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  • Blackberry - Can't change theme after lwuit was installed

    - by Bel
    I've used lwuit in my j2me application and it works well. When I've converted .jar file to .cod file and install it on BB emulator, I've faced runtime error 104. Then I got the blackberry demo and lwuit.jar file included with it and when install it on BB it works well. But after I edit the theme.res file application doesn't open any more. Please can you help me - how to apply my theme on bb app which using lwuit? Thanks in advance.

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  • Why a variable is seen in the loop and is not seen outside the loop?

    - by Roman
    I have the following code: String serviceType; ServiceBrowser tmpBrowser; for (String playerName: players) { serviceType = "_" + playerName + "._tcp"; tmpBrowser = BrowsersGenerator.getBrowser(serviceType); tmpBrowser.browse(); System.out.println(tmpBrowser.getStatus()); } System.out.println(tmpBrowser.getStatus()); The compiler complains about the last line. It writes "variable tmpBrowser might not been initialized". If I comment the last line the compile does not complain.

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  • Call the method of base Class which was over ridden

    - by Abhijith Venkata
    I have illustrated my question in this example class Car { public void start(){ System.out.println("Car Started!!!"); } } class Mercedes extends Car { public void start(){ System.out.println("Mercedes Started!!!"); } } Now, in my main program, I write Mercedes m = new Mercedes(); m.start(); It prints: Mercedes Started!!! How do I call the start() method of Car class using the same object so that the output can be Car Started!!!. Edit: Actually It was asked in an interview I attended. I gave the super keyword answer. But the interviewer denied it. He said he'd give me a hint and said Virtual Function. I have no idea how to use that hint.

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  • Using ControllerClassNameHandlerMapping with @Controller and extending AbstractController

    - by whiskerz
    Hey there, actually I thought I was trying something really simple. ControllerClassNameHandlerMapping sounded great to produce a small spring webapp using a very lean configuration. Just annotate the Controller with @Controller, have it extend AbstractController and the configuration shouldn't need more than this <context:component-scan base-package="test.mypackage.controller" /> <bean id="urlMapping" class="org.springframework.web.servlet.mvc.support.ControllerClassNameHandlerMapping" /> to resolve my requests and map them to my controllers. I've mapped the servlet to "*.spring", and calling <approot>/hello.spring All I ever get is an error stating that no mapping was found. If however I extend the MultiActionController, and do something like <approot>/hello/hello.spring it works. Which somehow irritates me, as I would have thought that if that is working, why didn't my first try? Does anyone have any idea? The two controllers I used looked like this @Controller public class HelloController extends AbstractController { @Override protected ModelAndView handleRequestInternal(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView modelAndView = new ModelAndView("hello"); modelAndView.addObject("message", "Hello World!"); return modelAndView; } } and @Controller public class HelloController extends MultiActionController { public ModelAndView hello(HttpServletRequest request, HttpServletResponse response) throws Exception { ModelAndView modelAndView = new ModelAndView("hello"); modelAndView.addObject("message", "Hello World!"); return modelAndView; } }

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  • Why might RvdProxy.getServices() incorrectly return an empty Array?

    - by butterchicken
    The following code snippet attempts to create a Tib DaemonManager connecting to a particular rvd, and then query for that rvd's services. public static void main(String[] args) throws RuntimeException { DaemonManager daemonManager = new DaemonManager("http://foo.com:7580"); if(daemonManager.getDaemonType() == DaemonManager.RVD) { DaemonProxy daemonProxy = daemonManager.getDaemonProxy(); final RvdProxy rvdProxy = (RvdProxy) daemonProxy; Service[] services = rvdProxy.getServices(); System.out.println(services.length); //prints 0 for (Service service : services) { System.out.println(service.getNetwork()); } } } This prints zero, even though the web interface for this rvd lists multiple available services. Why might this happen? The daemon I am connecting to is running v 7.5.1 of the software, and the rvconfig.jar that I am using is from v 7.5.1 as well. Is there a gotcha when using Tibco's DaemonManager that is causing me to come unstuck?

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  • Websphere 6.1, Datasource, two apps

    - by asrijaal
    Hi, I've got a webapp running on a Websphere 6.1 Server which JNDI lookups for a datasource. This webapp runs fine, the Websphere server recognizes the datasource ref in the web.xml etc.. Now we added a second webapp which should use this datasource with same configuration but I only getting a NULL Object when I invoke my JNDI lookup and a ClassCastException is thrown (which is correct). Maybe one of you has some suggestions?

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  • Variable length Blob in hibernate?

    - by Seth
    I have a byte[] member in one of my persistable classes. Normally, I'd just annotate it with @Lob and @Column(name="foo", size=). In this particular case, however, the length of the byte[] can vary a lot (from ~10KB all the way up to ~100MB). If I annotate the column with a size of 128MB, I feel like I'll be wasting a lot of space for the small and mid-sized objects. Is there a variable length blob type I can use? Will hibernate take care of all of this for me behind the scenes without wasting space? What's the best way to go about this? Thanks!

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  • How to override j_security_check in glassfish?

    - by Alex B
    I'm currently using FORM based authentication in glassfish v2.1 to log users in and it works fine. I want to switch to ProgrammaticLogin and I want to be able to get the initially requested URL (i.e. before redirecting to login page) and use it in my programmatic login code so that the user is redirected back to the requested page after authentication. I've seen the source code for j_security_check - in my case that's FormAuthenticator (catalina codebase) and it saves the initial request in a SavedRequest object in the session but that session is a StandardSession rather than HttpSession so there's no direct way to access it. Or should I change the authentication mechanism from FORM to something else? Thanks!

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  • Hibernate: deletes not cascading for self-referencing entities

    - by jwaddell
    I have the following (simplified) Hibernate entities: @Entity @Table(name = "package") public abstract class Package { protected Content content; @ManyToOne(cascade = {javax.persistence.CascadeType.ALL}) @JoinColumn(name = "content_id") @Fetch(value = FetchMode.JOIN) public Content getContent() { return content; } public void setContent(Content content) { this.content = content; } } @Entity @Table(name = "content") public class Content { private Set<Content> subContents = new HashSet<Content>(); @ManyToMany(fetch = FetchType.EAGER) @JoinTable(name = "subcontents", joinColumns = {@JoinColumn(name = "content_id")}, inverseJoinColumns = {@JoinColumn(name = "elt")}) @Cascade(value = {org.hibernate.annotations.CascadeType.DELETE, org.hibernate.annotations.CascadeType.REPLICATE}) @Fetch(value = FetchMode.SUBSELECT) public Set<Content> getSubContents() { return subContents; } public void setSubContents(Set<Content> subContents) { this.subContents = subContents; } } So a Package has a Content, and a Content is self-referencing in that it has many sub-Contents (which may contain sub-Contents of their own etc). The relationships are required to be ManyToOne (Package to Content) and ManyToMany (Content to sub-Contents) but for the case I am currently testing each sub-Content only relates to one Package or Content. The problem is that when I delete a Package and flush the session, I get a Hibernate error stating that I'm violating a foreign key constraint on table subcontents, with a particular content_id still referenced from table subcontents. I've tried specifically (recursively) deleting the Contents before deleting the Package but I get the same error. Is there a reason why this entity tree is not being deleted properly?

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  • Annoying struts 2 problem

    - by Parhs
    Hello... I am using this code to include some menus to my code... <s:action namespace="/" name="get_header" executeResult="true" /> <jsp:include page="/get_menu" > <jsp:param name="menuKey" value="configuration"></jsp:param> <jsp:param name="subMenuKey" value="user.add"></jsp:param> </jsp:include> THe problem is that the menus are generated dynamically... So suppose that we have 2 Actions ActionA and get_menu Action The jsp page for the result of ActionA calls get_menu to generate the menus. So suppose that ActionA sets a variable groups and get_menu also uses a groups variable... ActionA's variable will overtake get_menu's variable. I tried many solutions and even jsp:inculde doesnt help:(...

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  • Modelling a manyToMany relationship with attributes

    - by Javi
    Hello, I have a ManyToMany relationship between two classes, for instance class Customer and class Item. A customer can buy several items and an item can be bought by different customers. I need to store extra information in this relationship, for example the day when the item was bought. I wonder how is this usually modelled in JPA, cause I'm not sure how to express this in code. Do I have to create a new class to model all the attributes of the relationship and make a manyToMany relationship between the other classes or is a better way to do this? Thanks

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  • storage service with google app engine.

    - by Bunny Rabbit
    i've been assigned a project to create a filestorage service on google applet engine.but i am really doubtful wheather it's possible or not given the 30 sec limit to process the response and moreover its the bigtable is just a database system not a storage server .am i correct ?

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  • ResultSet in JTable

    - by Merin Treesa Joseph
    Sir, How display ResultSet in JTable. i using this code /*String [] record= new String[ColCount]; for (i=0; i } cell[i] = rset1.getString("loginname"); cell[i] = rset1.getString( "role"); System.out.println(cell[i][0]); //ItemGroup = rset1.getString( "Status"); } System.out.println(ItemCode); JTable jt = new JTable( cell[i], headers);*/ but i get only one row that lastly inserted to database.

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  • how to register a selectionProvider for the Viewer from a superclass

    - by Tom
    I have a View which extends a View provided by another plugin like this; public class View2 extends some.other.package.View1 { public void createPartControl(Composite parent) { super.createPartControl(parent); //I want to do this, but I can't because its private //getSite().setSelectionProvider(treeViewer); } } But I can't edit the super class, so I need to access the viewer from the Control. public class some.other.package.View1 extends ViewPart { private TreeViewer treeViewer; public void createPartControl(Composite parent) { treeViewer = new TreeViewer(parent, SWT.V_SCROLL); } } I tried using parent.getChildren(); to get a Tree object, but I can't see that it can be cooerced into an ISElectionProvider as required

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  • JAXB unmarshal exclude specific element

    - by zigomir
    Hi everyone! I know for @XmlTransient annotation, but sometimes I need this element and in other use cases I really have to prevent it from unmarshaling, because it contains base64 text. So I need to exclude it because performance problems. Is there any way to dynamicly exclude one element from unmarshaling with JAXB?

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  • Killing Mysql prcoesses staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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  • How do I sort an ArrayList lexicographically?

    - by Jake
    I am trying to sort an ArrayList of Strings that represent card values. So, some cards contain letters ("King") and some contain Strings containing only a number ("7"). I know to use Collections.sort, but it only sorts Strings that contain letters. How do I get the ArrayList to be sorted by number as well as alphabetically?

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  • Adding and removing elements efficiently from Collection object

    - by user569125
    Hi, Below coding is the working sample,but still i am not happy with this code with related to performancewise.Please have a look and let me know if any better approach is there.Thanks in advance. Adding items to the arraylist object String resultItems[] = paging.getMoveLeftArray().split(","); String fields[]={"id","name","name1"}; leftObj=new ArrayList(); for(int i=0;i<resultItems.length;i++){ //below line mea TestVO bean=new TestVO(); String resultItem = resultItems[i]; String idANDname[] = resultItem.split("@"); String id = idANDname[0]; // name or id should not contain "-" String name[] = idANDname[1].split("-"); //values and fileds are always having same length for(int j=0;j<name.length;j++) { PropertyUtils.setProperty(bean, fields[j], name[j]); } leftObj.add(bean); } Removing items from the arraylist object:availableList contains all the TestVO objects: String []removeArray=paging.getMoveRightArray().split(","); tempList=new CopyOnWriteArrayList(); newTempList=new CopyOnWriteArrayList(); for(int i=0;i<availableList.size();i++){ boolean flag = false; TestVO tempObj = (TestVO )availableList.get(i); int id =(Integer)tempObj.getId(); // System.out.println("id value"+id); // availableList.get(i).getClass().getField(name); for(int j=0;j<removeArray.length;j++){ String resultItem = removeArray[j]; String idandname[] = resultItem.split("@"); for(int k=0;k<idandname.length;k++){ String ids[]=idandname[0].split("-"); if(id==Integer.parseInt(ids[0])){ flag = true; break; } } } if(flag){ tempList.add(tempObj); } else{ newTempList.add(tempObj); }

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  • ListAdapters and WrapperListAdapter algorithm

    - by Matty F
    This logic is written in a function with signature private void showDialog(final AdapterView<? extends Adapter> parent, String title, String message, final Tag subject) Is there a better way of doing this? // refresh adapter SimpleCursorAdapter adapter; if (parent.getAdapter() instanceof WrapperListAdapter) { adapter = (SimpleCursorAdapter) ((WrapperListAdapter) parent.getAdapter()).getWrappedAdapter(); } else { adapter = (SimpleCursorAdapter) parent.getAdapter(); } adapter.getCursor().requery(); adapter.notifyDataSetChanged(); Also, is there any point in having AdapterView<? extends Adapter> in the signature and not just AdapterView<?>?

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  • How to programmly download image from website ?

    - by MemoryLeak
    I need to download images from a website, and I have the login name and password, but if i just use URL to download the image, it will throw a exception: there is no value in session. I think I need to login the website before I can programmingly download the image. Do you have any solutions ? Thanks in advance !

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  • Android file-creation fails.

    - by Alxandr
    I use the following code to create a folder "mymir" and a file ".nomedia" (in the mymir-folder) on the sdcard of an android unit. However, somehow it fails with the exception that the folder the ".nomedia"-file is to be placed in dosn't exist. Here's the code: private String EnsureRootDir() throws IOException { File sdcard = Environment.getExternalStorageDirectory(); File mymirFolder = new File(sdcard.getAbsolutePath() + "/mymir/"); if(!mymirFolder.exists()) { File noMedia = new File(mymirFolder.getAbsolutePath() + "/.nomedia"); noMedia.mkdirs(); noMedia.createNewFile(); } return mymirFolder.getAbsolutePath(); }

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  • JTwitter OAuth with callback authorisation

    - by RenegadeAndy
    Hey guys. I am writing an App using JTwitter however I need to authenticate in order to not have the 150 requests per minute on the public api. Jtwitter seems to support OAuth however I have some questions. My app will be running behind a company firewall - so the URL wont be accessible outside of the company's network - will callback authorisation work, and does anybody have an example of using callback authorisation using OAuth in JTwitter - because I cannot work it out in order to try it. Cheers, Andy

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