Search Results

Search found 33297 results on 1332 pages for 'java java ee'.

Page 785/1332 | < Previous Page | 781 782 783 784 785 786 787 788 789 790 791 792  | Next Page >

  • Move 3 rectangles up in their X but keep order of rectangles

    - by Nicolas Martel
    I have 3 rectangles being rendered here. Let's say i wanted to move them all above the line yet keep their order, how would i go about that? I tried subtracting the Y and height rather than adding the Y it but as expected, the lower rectangle goes at the top, middle stays in the middle and top goes to the bottom before: after: So is there any simple solution to render them just above rather than having to change all values ?

    Read the article

  • Killing Mysql prcoesses staying in sleep command.

    - by Shino88
    Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

    Read the article

  • How to handle large dataset with JPA (or at least with Hibernate)?

    - by Roman
    I need to make my web-app work with really huge datasets. At the moment I get either OutOfMemoryException or output which is being generated 1-2 minutes. Let's put it simple and suppose that we have 2 tables in DB: Worker and WorkLog with about 1000 rows in the first one and 10 000 000 rows in the second one. Latter table has several fields including 'workerId' and 'hoursWorked' fields among others. What we need is: count total hours worked by each user; list of work periods for each user. The most straightforward approach (IMO) for each task in plain SQL is: 1) select Worker.name, sum(hoursWorked) from Worker, WorkLog where Worker.id = WorkLog.workerId group by Worker.name; //results of this query should be transformed to Multimap<Worker, Long> 2) select Worker.name, WorkLog.start, WorkLog.hoursWorked from Worker, WorkLog where Worker.id = WorkLog.workerId; //results of this query should be transformed to Multimap<Worker, Period> //if it was JDBC then it would be vitally //to set resultSet.setFetchSize (someSmallNumber), ~100 So, I have two questions: how to implement each of my approaches with JPA (or at least with Hibernate); how would you handle this problem (with JPA or Hibernate of course)?

    Read the article

  • Android file-creation fails.

    - by Alxandr
    I use the following code to create a folder "mymir" and a file ".nomedia" (in the mymir-folder) on the sdcard of an android unit. However, somehow it fails with the exception that the folder the ".nomedia"-file is to be placed in dosn't exist. Here's the code: private String EnsureRootDir() throws IOException { File sdcard = Environment.getExternalStorageDirectory(); File mymirFolder = new File(sdcard.getAbsolutePath() + "/mymir/"); if(!mymirFolder.exists()) { File noMedia = new File(mymirFolder.getAbsolutePath() + "/.nomedia"); noMedia.mkdirs(); noMedia.createNewFile(); } return mymirFolder.getAbsolutePath(); }

    Read the article

  • Logging a specific package in log4j programmatically

    - by VinTem
    Hi there, here is the thing, I have to deploy a web app and the the log4j.properties file is created by the client so I dont have control over it. Their properties file is like this: log4j.rootCategory= FILE !-----------FILE--------------! log4j.category.FILE=DEBUG log4j.appender.FILE=org.apache.log4j.RollingFileAppender log4j.appender.FILE.File=${catalina.base}/logs/rcweb.log log4j.appender.FILE.MaxFileSize=1024KB log4j.appender.FILE.MaxBackupIndex=10 log4j.appender.FILE.layout=org.apache.log4j.PatternLayout log4j.appender.FILE.layout.ConversionPattern=%-2d{dd/MM/yyyy HH:mm:ss} [%t] %5p %c:%L - %m%n And in my classes I do something like this: private static final Logger LOG = Logger.getLogger(MaterialController.class); LOG.info("my log"); But the log file has never been created. I did the test and changed the log4j.properties file and deployed in my computer adding the following line: log4j.logger.br.com.golive.requisicaoCompras=DEBUG This works, but I cant use the file like this. Is there any ideas? Thanks

    Read the article

  • Efficient representation of Hierarchies in Hibernate.

    - by Alison G
    I'm having some trouble representing an object hierarchy in Hibernate. I've searched around, and haven't managed to find any examples doing this or similar - you have my apologies if this is a common question. I have two types which I'd like to persist using Hibernate: Groups and Items. * Groups are identified uniquely by a combination of their name and their parent. * The groups are arranged in a number of trees, such that every Group has zero or one parent Group. * Each Item can be a member of zero or more Groups. Ideally, I'd like a bi-directional relationship allowing me to get: * all Groups that an Item is a member of * all Items that are a member of a particular Group or its descendants. I also need to be able to traverse the Group tree from the top in order to display it on the UI. The basic object structure would ideally look like this: class Group { ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { ... } /** @return all direct children of this group */ Set<Group> getChildren() { ... } ... } class Item { ... /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { ... } ... } Originally, I had just made a simple bi-directional many-to-many relationship between Items and Groups, such that fetching all items in a group hierarchy required recursion down the tree, and fetching groups for an Item was a simple getter, i.e.: class Group { ... private Set<Item> items; private Set<Group> children; ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { Set<Item> allItems = new HashSet<Item>(); allItems.addAll(this.items); for(Group child : this.getChildren()) { allItems.addAll(child.getAllItems()); } return allItems; } /** @return all direct children of this group */ Set<Group> getChildren() { return this.children; } ... } class Item { ... private Set<Group> groups; /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { return this.groups; } ... } However, this resulted in multiple database requests to fetch the Items in a Group with many descendants, or for retrieving the entire Group tree to display in the UI. This seems very inefficient, especially with deeper, larger group trees. Is there a better or standard way of representing this relationship in Hibernate? Am I doing anything obviously wrong or stupid? My only other thought so far was this: Replace the group's id, parent and name fields with a unique "path" String which specifies the whole ancestry of a group, e.g.: /rootGroup /rootGroup/aChild /rootGroup/aChild/aGrandChild The join table between Groups and Items would then contain group_path and item_id. This immediately solves the two issues I was suffering previously: 1. The entire group hierarchy can be fetched from the database in a single query and reconstructed in-memory. 2. To retrieve all Items in a group or its descendants, we can select from group_item where group_path='N' or group_path like 'N/%' However, this seems to defeat the point of using Hibernate. All thoughts welcome!

    Read the article

  • Eclipse won't believe I have Maven 2.2.1

    - by Andrew Clegg
    I have a project (built from an AppFuse template) that requires Maven 2.2.1. So I upgraded to this (from 2.1.0) and set my path and my M2_HOME and MAVEN_HOME env variables. Then I ran mvn eclipse:eclipse and imported the project into Eclipse (Galileo). However, in the problems list for the project (and at the top of the pom.xml GUI editor) it says: Unable to build project '/export/people/clegg/data/GanymedeWorkspace/funcserve/pom.xml; it requires Maven version 2.2.1 (Please ignore 'GanymedeWorkspace', I really am using Galileo!) This persists whether I set Eclipse to use its Embedded Maven implementation, or the external 2.2.1 installation, in the Preferences - Maven - Installations dialog. I've tried closing and reopening the project, reindexing the repository, cleaning the project, restarting the IDE, logging out and back in again, everything I can think of! But Eclipse still won't believe I have Maven 2.2.1. I just did a plugin update so I have the latest version of Maven Integration for Eclipse -- 0.9.8.200905041414. Does anyone know how to convince Eclipse I really do have the right version of Maven? It's like it's recorded the previous version somewhere else and won't pay any attention to my changes :-( Many thanks! Andrew.

    Read the article

  • How to specify a parameter as part of every web service call?

    - by LES2
    Currently, each web service for our application has a user parameter that is added for every method. For example: @WebService public interface FooWebService { @WebMethod public Foo getFoo(@WebParam(name="alwaysHere",header=true,partName="alwaysHere") String user, @WebParam(name="fooId") Long fooId); @WebMethod public Result deletetFoo(@WebParam(name="alwaysHere",header=true,partName="alwaysHere") String user, @WebParam(name="fooId") Long fooId); // ... } There could be twenty methods in a service, each with the first parameter as user. And there could be twenty web services. We don't actually use the 'user' argument in the implementations - in fact, I don't know why it's there - but I wasn't involved in the design, and the person that put it there had a reason (I hope). Anyway, I'm trying to straighten out this Big Ball of Mud. I have already come a long way by wrapping the web services by a Spring proxy, which allows me to do some before-and-after processing in an interceptor (before there were at least 20 lines of copy-pasted boiler plate per method). I'm wondering if there's some kind of "message header" I can apply to the method or package and that can be accessed by some type of handler or something outside of each web service method. Thanks in advance for the advice, LES

    Read the article

  • Application Server or Lightweight Container?

    - by Jeff Storey
    Let me preface this by saying this is not an actual situation of mine but I'm asking this question more for my own knowledge and to get other people's inputs here. I've used both Spring and EJB3/JBoss, and for the smaller types of applications I've built, Spring (+Tomcat when needed) has been much simpler to use. However, when scaling up to larger applications that require things like load balancing and clustering, is Spring still a viable solution? Or is it time to turn to a solution like EJB3/JBoss when you start to get big enough to need that? I'm not sure if I've scoped the problem well enough to get a good answer, so please let me know. Thanks, Jeff

    Read the article

  • log4j/log4cxx : exclusive 1 to 1 relation between logger and appender

    - by Omry
    Using the xml configuration of log4cxx (which is identical in configuration to log4j). I want to have a certain logger output exclusively to a specific appender (have it the only logger which outputs to that appender). I found that it's possible to bind a logger to a specific appender like this: <logger name="LoggerName"> <level value="info"/> <appender-ref ref="AppenderName"/> </logger> but it that logger still outputs to the root appender because I have this standard piece in the conf file: <root> <priority value="DEBUG"/> <appender-ref ref="OtherAppender"/> </root> How can I exclude that logger from the root logger? in other words, how do I configure the log such that all loggers inherit the appenders of the root logger except a specific logger?

    Read the article

  • Using Quartz with Spring

    - by Anurag
    In my application there is a requirement to be able to create Scheduled Job(s) depending on the type of Request that comes in (Dynamically). Can I still use Spring to create and trigger Jobs? If Yes, how? Any help would be useful.

    Read the article

  • NoSuchMessageException: No message found

    - by adisembiring
    Hi .... I try to learn Spring MVC 3.0 validation. but I got NoSuchMessageException: No message found under code 'name.required' for locale 'en_US' error message when form submted. I have create message.properties in src/message.properties and the content of that file is: name.required = User Name is required password.required = Password is required gender.required = Gender is required I have set ResourceBundleMessageSource in my app-servlet.xml <bean id="messageSource" class="org.springframework.context.support.ResourceBundleMessageSource" p:basename="messages" /> My validator code is: @Component("registrationValidator") public class RegistrationValidator implements Validator { @Override public boolean supports(Class<?> clazz) { return RegistrationCommand.class.isAssignableFrom(clazz); } @Override public void validate(Object target, Errors errors) { RegistrationCommand registrationCommand = (RegistrationCommand) target; ValidationUtils.rejectIfEmptyOrWhitespace(errors, "name", "name.required"); ValidationUtils.rejectIfEmptyOrWhitespace(errors, "password", "password.required"); ValidationUtils.rejectIfEmpty(errors, "gender", "gender.required"); ValidationUtils.rejectIfEmpty(errors, "country", "country.required"); //ValidationUtils.rejectIfEmpty(errors, "community", "community.required"); ValidationUtils.rejectIfEmptyOrWhitespace(errors, "description", "description.required"); if (registrationCommand.getCommunity().length == 0) { errors.rejectValue("community", "community.required"); } } } and JSP Page is: <form:form commandName="registrationCommand"> <p class="name"> <label for="name">Name</label> <form:input path="name" /> <form:errors path="name" cssClass="error"></form:errors> </p> <p class="password"> <label for="password">Password</label> <form:password path="password" /> <form:errors path="password" cssClass="error"></form:errors> </p> <p class="gender"> <label>Gender</label> <form:radiobutton path="gender" value="M" label="M" /> <form:radiobutton path="gender" value="F" label="F" /> <form:errors path="gender" cssClass="error"></form:errors> </p> <p class="submit"> <input type="submit" value="Submit" /> </p> </form:form>

    Read the article

  • How do I determine whether I am going "forward" or "backward" through my History in GWT?

    - by Stephen Cagle
    I am looking at History and History JavaDocs in GWT and I notice that there is no way to tell whether the forward or backward button was pressed (either pragmatically or by the user). The "button press" is handled by your registered addValueChangeHandler, but the only thing passed to the handler is a string on your history stack. There is no indication as to whether the "History" is moving "back" (using the back arrow button) or "forward" (using the right arrow button). Is there any way to determine this?

    Read the article

  • How to log all sql going through JBoss datasource with log4j

    - by Ichorus
    I've looked at log4jdbc (which does not support datasources), p6spy which seems to be what I am looking for but it has not been updated since 2003 which makes me nervous and lists only JBoss 3.x (we use JBoss 5), and JAMon which seems heavyweight for what I am trying to accomplish (a simple log of all SQL statements running through a JBoss application server). I was hoping that JBoss itself would have a switch to log all the sql (as Websphere does) but I cannot find any documentation for it so that functionality might not exist.

    Read the article

  • Update database settings in properties file in Spring

    - by mvg
    Hi all, I am trying to create a Database Manager page which shows the database details on page load and updates the database settings when the user press submit I followed this tutorial and set the database settings in properties file. I managed to update the database settings in properties file programmatically. When I retrieved the database settings using the following code DriverManagerDataSource databaseSource = (DriverManagerDataSource)context.getBean("dataSource"); databaseSource.getUsername(); I managed to get the old value and unable to get the new value This is the mapping in applicationContext.xml file <bean class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer"> <property name="location"> <value>classpath:/bundle/database.properties</value> </property> </bean> <bean id="dataSource" class="org.springframework.jdbc.datasource.DriverManagerDataSource"> <property name="driverClassName" value="${jdbc.driverClassName}" /> <property name="url" value="${jdbc.url}" /> <property name="username" value="${jdbc.username}" /> <property name="password" value="${jdbc.password}" /> </bean> I checked the properties file and found it to be updated with the latest input. What am I missing? Thanks in advance P.S I am using JSF1.2 with Spring 3 Update Just making my requirement simple. I am creating a setparate dbsettings page, so that when user wishes to connect to different database he/she can just enter the details in dbsettings page and connect

    Read the article

  • Creating 3DES key from bytes

    - by AO
    I create a triple DES key from the a byte array ("skBytes") but when calling getEncoded on the triple DES key ("sk") and comparing it to the byte array, they differ! They are almost the same if you look at the console output, though. How would I create a triple DES key that is exactly as "skBytes"? byte[] skBytes = {(byte) 0x41, (byte) 0x0B, (byte) 0xF0, (byte) 0x9B, (byte) 0xBC, (byte) 0x0E, (byte) 0xC9, (byte) 0x4A, (byte) 0xB5, (byte) 0xCE, (byte) 0x0B, (byte) 0xEA, (byte) 0x05, (byte) 0xEF, (byte) 0x52, (byte) 0x31, (byte) 0xD7, (byte) 0xEC, (byte) 0x2E, (byte) 0x75, (byte) 0xC3, (byte) 0x1D, (byte) 0x3E, (byte) 0x61}; DESedeKeySpec keySpec = new DESedeKeySpec(skBytes); SecretKeyFactory keyFactory = SecretKeyFactory.getInstance("DESede"); SecretKey sk = keyFactory.generateSecret(keySpec); for(int i = 0; i < skBytes.length; i++) { System.out.println("(sk.getEncoded()[i], skBytes[i]) = (" + sk.getEncoded()[i] +", " + skBytes[i] + ")"); } Console output: (sk.getEncoded()[i], skBytes[i]) = (64, 65) (sk.getEncoded()[i], skBytes[i]) = (11, 11) (sk.getEncoded()[i], skBytes[i]) = (-15, -16) (sk.getEncoded()[i], skBytes[i]) = (-101, -101) (sk.getEncoded()[i], skBytes[i]) = (-68, -68) (sk.getEncoded()[i], skBytes[i]) = (14, 14) (sk.getEncoded()[i], skBytes[i]) = (-56, -55) (sk.getEncoded()[i], skBytes[i]) = (74, 74) (sk.getEncoded()[i], skBytes[i]) = (-75, -75) (sk.getEncoded()[i], skBytes[i]) = (-50, -50) (sk.getEncoded()[i], skBytes[i]) = (11, 11) (sk.getEncoded()[i], skBytes[i]) = (-22, -22) (sk.getEncoded()[i], skBytes[i]) = (4, 5) (sk.getEncoded()[i], skBytes[i]) = (-17, -17) (sk.getEncoded()[i], skBytes[i]) = (82, 82) (sk.getEncoded()[i], skBytes[i]) = (49, 49) (sk.getEncoded()[i], skBytes[i]) = (-42, -41) (sk.getEncoded()[i], skBytes[i]) = (-20, -20) (sk.getEncoded()[i], skBytes[i]) = (47, 46) (sk.getEncoded()[i], skBytes[i]) = (117, 117) (sk.getEncoded()[i], skBytes[i]) = (-62, -61) (sk.getEncoded()[i], skBytes[i]) = (28, 29) (sk.getEncoded()[i], skBytes[i]) = (62, 62) (sk.getEncoded()[i], skBytes[i]) = (97, 97)

    Read the article

  • How do I write a analyzable thread dump format

    - by gamue
    I'm creating a global exception handling which collects some information before shutting down in some cases. One of this information is the current thread dump. i do this with following code: ManagementFactory.getThreadMXBean().dumpAllThreads(true, true); The problem is to write the information into a analyzable format for TDA. Is there a "simple" way to format the information instead of writing the format on my own?

    Read the article

  • What design pattern will you choose ?

    - by MemoryLeak
    I want to design a class, which contains a procedure to achieve a goal. And it must follow some order to make sure the last method, let's say "ExecuteIt", to behave correctly. in such a case, what design patter will you use ? which can make sure that the user must call the public method according some ordering. If you really don't know what I am saying, then can you share me some concept of choosing a design patter, or what will you consider while design a class?

    Read the article

  • Smack API - How to display loop jxTaskpane for expand and collapse roster list

    - by MYE
    Hello everybody ! i have problem to display Taskpane for loop. i have a code to get the groups of roster (Groups : Friends - Business - Company, so on) my code is : Roster rost = xmppcon.getRoster(); Collection<RosterGroup> groups = rost.getGroups(); for(RosterGroup group : groups){ DefaultListModel model = new DefaultListModel(); model.addElement(group.getEntries()); String GroupNameCount = group.getName() + "("+group.getEntryCount()+")"; jXTaskPane1.setTitle(GroupNameCount); jXList1.setModel(model); } but jxTaskpane not loop, but when i print group name it print 2 line (because in database user A have two group is Friends and NIIT) sample print System.out.println(group.getName()); result: Friends NIIT

    Read the article

  • How can I improve the performance of this double-for print?

    - by Florenc
    I have the following static method that prints the data imported from a 40.000 lines .xls spreadsheet. Now, it takes about 27 seconds to print the data in the console and the memory consumption is huge. import org.apache.poi.hssf.usermodel.*; import org.apache.poi.ss.usermodel.*; public static void printSheetData(List<List<HSSFCell>> sheetData) { for (int i = 0; i < sheetData.size(); i++) { List<HSSFCell> list = (List<HSSFCell>) sheetData.get(i); for (int j = 0; j < list.size(); j++) { HSSFCell cell = (HSSFCell) list.get(j); System.out.print(cell.toString()); if (j < list.size() - 1) { System.out.print(", "); } } System.out.println(""); } } Disclaimer: I know, I know large data belong to a database, don't print output in the console, premature optimization is the root of all evils...

    Read the article

  • JPA getSingleResult() or null

    - by Eugene Ramirez
    Hi. I have an insertOrUpdate method which inserts an Entity when it doesn't exist or update it if it does. To enable this, I have to findByIdAndForeignKey, if it returned null insert if not then update. The problem is how do I check if it exists? So I tried getSingleResult. But it throws an exception if the public Profile findByUserNameAndPropertyName(String userName, String propertyName) { String namedQuery = Profile.class.getSimpleName() + ".findByUserNameAndPropertyName"; Query query = entityManager.createNamedQuery(namedQuery); query.setParameter("name", userName); query.setParameter("propName", propertyName); Object result = query.getSingleResult(); if(result==null)return null; return (Profile)result; } but "getSingleResult" throws an exception. Thanks

    Read the article

  • Ant: foreach loop

    - by user305801
    I'm trying to use the foreach loop in an Ant script but I get the message: Problem: failed to create task or type foreach Cause: The name is undefined. I don't understand why this doesn't work. It is not a 3rd party library. It is a standard task that would be part of the latest version of Ant (1.8). <target name="parse"> <echo message="The first five letters of the alphabet are:"/> <foreach param="instance" list="a,b,c,d,e"> </foreach> </target>

    Read the article

< Previous Page | 781 782 783 784 785 786 787 788 789 790 791 792  | Next Page >