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  • Efficient representation of Hierarchies in Hibernate.

    - by Alison G
    I'm having some trouble representing an object hierarchy in Hibernate. I've searched around, and haven't managed to find any examples doing this or similar - you have my apologies if this is a common question. I have two types which I'd like to persist using Hibernate: Groups and Items. * Groups are identified uniquely by a combination of their name and their parent. * The groups are arranged in a number of trees, such that every Group has zero or one parent Group. * Each Item can be a member of zero or more Groups. Ideally, I'd like a bi-directional relationship allowing me to get: * all Groups that an Item is a member of * all Items that are a member of a particular Group or its descendants. I also need to be able to traverse the Group tree from the top in order to display it on the UI. The basic object structure would ideally look like this: class Group { ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { ... } /** @return all direct children of this group */ Set<Group> getChildren() { ... } ... } class Item { ... /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { ... } ... } Originally, I had just made a simple bi-directional many-to-many relationship between Items and Groups, such that fetching all items in a group hierarchy required recursion down the tree, and fetching groups for an Item was a simple getter, i.e.: class Group { ... private Set<Item> items; private Set<Group> children; ... /** @return all items in this group and its descendants */ Set<Item> getAllItems() { Set<Item> allItems = new HashSet<Item>(); allItems.addAll(this.items); for(Group child : this.getChildren()) { allItems.addAll(child.getAllItems()); } return allItems; } /** @return all direct children of this group */ Set<Group> getChildren() { return this.children; } ... } class Item { ... private Set<Group> groups; /** @return all groups that this Item is a direct member of */ Set<Group> getGroups() { return this.groups; } ... } However, this resulted in multiple database requests to fetch the Items in a Group with many descendants, or for retrieving the entire Group tree to display in the UI. This seems very inefficient, especially with deeper, larger group trees. Is there a better or standard way of representing this relationship in Hibernate? Am I doing anything obviously wrong or stupid? My only other thought so far was this: Replace the group's id, parent and name fields with a unique "path" String which specifies the whole ancestry of a group, e.g.: /rootGroup /rootGroup/aChild /rootGroup/aChild/aGrandChild The join table between Groups and Items would then contain group_path and item_id. This immediately solves the two issues I was suffering previously: 1. The entire group hierarchy can be fetched from the database in a single query and reconstructed in-memory. 2. To retrieve all Items in a group or its descendants, we can select from group_item where group_path='N' or group_path like 'N/%' However, this seems to defeat the point of using Hibernate. All thoughts welcome!

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  • Mockito upgrade causes null pointer problems

    - by Ann Addicks
    We upgraded from mockito-all-1.8.5.jar to mockito-all-1.9.0.jar and now see null pointers when using annotations for the classes being mocked. Here is an example: @Mock private static IAccountManager accountManager; @Mock private static IBusinessUnitManager businessUnitManager; private static Gson parser; @InjectMocks private static DownloadController downloadController; @BeforeClass public static void setUpBeforeClass() throws Exception { parser = new Gson(); downloadController = new DownloadController(accountManager, businessUnitManager, parser); } @Before public void setUp() throws Exception { MockitoAnnotations.initMocks(this); Mockito.reset(accountManager, businessUnitManager); } As soon as accountManager is referenced in the download controller, it throws a npe. This worked in 1.8.5.

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  • Eclipse RCP and JFace: Problems with Images in Context menu and TreeViewer

    - by Juri
    I'm working on an Eclipse RCP application. Today I experienced some troubles when displaying images in the context menu. What I wanted to do is to add a column to my table containing images of stars for representing a user rating. On Windows, this causes some problems, since the star images are squeezed up on the left corner of the table cell instead of expanding on the whole cell, but I'll solve that somehow. In addition I have a context menu on the table, with an entry called "rate" where again the different stars from 1 to 5 (representing the rating level) are shown, such that the user can click on it for choosing different ratings. That works fine on Windows. Now I switched to Linux (Ubuntu) to see how it works out there, and strangely, the stars in the table cell are layed out perfectly, while the stars on the context menu don't even show up. On the context menu I'm using an action class where I'm setting the image descriptor for the star images: public class RateAction extends Action { private final int fRating; private IStructuredSelection fSelection; public RateAction(int rating, IStructuredSelection selection) { super("", AS_CHECK_BOX); fRating = rating; fSelection = selection; setImageDescriptor(createImageDescriptor()); } /** * Creates the correct ImageDescriptor depending on the given rating * @return */ private ImageDescriptor createImageDescriptor() { ImageDescriptor imgDescriptor = null; switch (fRating) { case 0: return OwlUI.NEWS_STARON_0; case 1: return OwlUI.NEWS_STARON_1; case 2: return OwlUI.NEWS_STARON_2; case 3: return OwlUI.NEWS_STARON_3; case 4: return OwlUI.NEWS_STARON_4; case 5: return OwlUI.NEWS_STARON_5; default: break; } return imgDescriptor; } /* * @see org.eclipse.jface.action.Action#getText() */ @Override public String getText() { //return no text, since the images of the stars will be displayed return ""; } ... } Does somebody know why this strange behaviour appears? Thanks a lot. (For some strange reason, the images don't appear. Here are the direct URLs: http://img187.imageshack.us/img187/4427/starsratingho4.png http://img514.imageshack.us/img514/8673/contextmenuproblemgt1.png) //Edit: I did some tries and it seems as if the images just don't appear when using a Checkbox style for the context menu (see constructor of the RateAction). When I switched to a PushButton style, the images appeared, although not correctly scaled, but at least they were shown.

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  • Native functions throw UnsatisfiedLinkError in custom view, despite working in main activity

    - by Mark Ingram
    For some reason I can only call native functions from my main activity and not any custom views that I've created. Here is an example file (I followed a tutorial, but renamed the classes http://mindtherobot.com/blog/452/android-beginners-ndk-setup-step-by-step/) See the usage of the native function "getNewString". package com.example.native; import android.app.Activity; import android.app.AlertDialog; import android.content.Context; import android.graphics.Bitmap; import android.graphics.Canvas; import android.os.Bundle; import android.view.View; public class NativeTestActivity extends Activity { static { System.loadLibrary("nativeTest"); } private native String getNewString(); @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); this.setContentView(new BitmapView(this)); String hello = getNewString(); // This line works fine new AlertDialog.Builder(this).setMessage(hello).show(); } } class BitmapView extends View { static { System.loadLibrary("nativeTest"); } private native String getNewString(); public BitmapView(Context context) { super(context); String hello = getNewString(); // This line throws the UnsatisfiedLinkError new AlertDialog.Builder(this.getContext()).setMessage(hello).show(); } } How can I call native functions in my custom views? I've built the application as an Android 2.2 app. I'm running the application on my HTC Desire. I have the latest SDK (9) and latest NDK (r5).

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  • How to get path to wallpaper

    - by kentcdodds
    My Question: How do you get the filepath to the current wallpaper? Expansion: I'm writing an app that will let you change the wallpaper easily between different presets. I want to store the filepath of the available wallpapers in my database. What I've tried: WallpaperManger.getWallpaperInfo() or WallpaperManger.getDrawable(). Neither seem to contain the actual location of the file. Any help would be appreciated! :D Thanks! Also, I'm including live-wallpapers. Thanks!

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  • Access JBOSS Tomcat Web Application from Remote Computer

    - by Rod
    Hi, I just deployed a web application on JBOSS 4.2. It can be accessed locally only (http://localhost:8080/myApp). I cant access it from remote computer by typing its domain: (www.hostname.com:8080/myApp). I added Port 8080 as Exception in Windows Firewall. Note that the host (www.hostname.com) is reachable from remote computers via IIS on port 80. Thanks, Rod

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  • Can a user-chosen image be inserted directly into a JEditorPane?

    - by JIM
    What I am trying to do is open up a JFilechooser that filters jpeg,gif and png images, then gets the user's selection and inserts it into the JEditorPane. Can this be done? or am i attempting something impossible? Here is a sample of my program.(insert is a JMenuItem and mainText is a JEditorPane) insert.addActionListener(new ActionListener(){ public void actionPerformed(ActionEvent e){ JFileChooser imageChooser = new JFileChooser(); imageChooser.setFileFilter(new FileNameExtensionFilter("Image Format","jpg","jpeg","gif","png")); int choice = imageChooser.showOpenDialog(mainText); if (choice == JFileChooser.APPROVE_OPTION) { mainText.add(imageChooser.getSelectedFile()); } } }); What i tried to do is use the add method, i know it's wrong but just to give you an idea of what i'm trying to do. Before you complain, i'm sorry about the code formatting, i don't really know all the conventions of what is considered good or bad style. Thank you very much.

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  • Parse Nested XML tags with the same name

    - by footose
    Let's take a simple XML document: <x> <e> <e> <e>Whatever 1</e> </e> </e> <e> <e> <e>Whatever 2</e> </e> </e> <e> <e> <e>Whatever 3</e> </e> </e> </x> Using the standard org.w3c.dom, I can get the nodes in X by doing.. NodeList fullnodelist = doc.getElementsByTagName("x"); But if I want to return the next set of "e" I try to use something like .. Element element = (Element) fullnodelist.item(0); NodeList nodes = pelement.getElementsByTagName("e"); Expecting it to return "3" nodes (because there are 3 sets of "e"), but instead, it returns "9" - becuase it gets all entries with "e" apperently. This would be fine in the above case, because I could probably iterate through and find what I'm looking for. The problem I'm having is that when the XML file looks like the following: <x> <e> <pattern>whatever</pattern> <blanks> <e>Something Else</e> </blanks> </e> <e> <pattern>whatever</pattern> <blanks> <e>Something Else</e> </blanks> </e> </x> When I request the "e" value, it returns 4, instead of (what i expect) 2. Am I just not understanding how the DOM parsing works? Typically in the past I have used my own XML documents so I would never name the items like this, but unfortunately this is not my XML file and I have no choice to work like this. What I thought I would do is write a loop that "drills down" nodes so that I could group each node together... public static NodeList getNodeList(Element pelement, String find) { String[] nodesfind = Utilities.Split(find, "/"); NodeList nodeList = null; for (int i = 0 ; i <= nodesfind.length - 1; i++ ) { nodeList = pelement.getElementsByTagName( nodesfind[i] ); pelement = (Element)nodeList.item(i); } // value of the nod we are looking for return nodeList; } .. So that if you passed "s/e" into the function, it would return the 2 nodes that I'm looking for (or elements, maybe I'm using the terminology incorrect?). instead it returns all of the "e" nodes within that node. I'm using J2SE for this, so options are rather limited. I can't use any third party XML Parsers. Anyway, if anyone is still with me and has a suggestion, it would be appreciated.

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  • Timer Service in ejb 3.1 - schedule calling timeout problem

    - by Greg
    Hi Guys, I have created simple example with @Singleton, @Schedule and @Timeout annotations to try if they would solve my problem. The scenario is this: EJB calls 'check' function every 5 secconds, and if certain conditions are met it will create single action timer that would invoke some long running process in asynchronous fashion. (it's sort of queue implementation type of thing). It then continues to check, but as long as long running process is there it won't start another one. Below is the code I came up with, but this solution does not work, because it looks like asynchronous call I'm making is in fact blocking my @Schedule method. @Singleton @Startup public class GenerationQueue { private Logger logger = Logger.getLogger(GenerationQueue.class.getName()); private List<String> queue = new ArrayList<String>(); private boolean available = true; @Resource TimerService timerService; @Schedule(persistent=true, minute="*", second="*/5", hour="*") public void checkQueueState() { logger.log(Level.INFO,"Queue state check: "+available+" size: "+queue.size()+", "+new Date()); if (available) { timerService.createSingleActionTimer(new Date(), new TimerConfig(null, false)); } } @Timeout private void generateReport(Timer timer) { logger.info("!!--timeout invoked here "+new Date()); available = false; try { Thread.sleep(1000*60*2); // something that lasts for a bit } catch (Exception e) {} available = true; logger.info("New report generation complete"); } What am I missing here or should I try different aproach? Any ideas most welcome :) Testing with Glassfish 3.0.1 latest build - forgot to mention

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  • Trying to create spring project with maven

    - by Gandalf StormCrow
    Hello everyone I was just going trough http://static.springsource.org/docs/Spring-MVC-step-by-step/part1.html spring tutorial, and I thought its old I'll think something better on my own. For starters how do I start spring project with maven, which archtype should I choose? I wanna create simple spring app, write class which I will deploy to jboss, spring will instansiate it at startup .. that is what have in mind for now .. for now I need to start it first

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  • JSF - <h:outputText> making some of words Bold

    - by karansardana
    How can we go about making some of the words in a sentence appear in BOLD for example - I'm trying to put one of the words of a sentence in BOLD i.e. sentence is "please select the amount" amount should be in BOLD, and now, when I use message = "please select the amount " This doesn't work. It simply shows please select the amount . How can I get this to work?

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  • I am confused -- Will this code always work?

    - by Shekhar
    Hello, I have written this piece of code public class Test{ public static void main(String[] args) { List<Integer> list = new ArrayList<Integer>(); for(int i = 1;i<= 4;i++){ new Thread(new TestTask(i, list)).start(); } while(list.size() != 4){ // this while loop required so that all threads complete their work } System.out.println("List "+list); } } class TestTask implements Runnable{ private int sequence; private List<Integer> list; public TestTask(int sequence, List<Integer> list) { this.sequence = sequence; this.list = list; } @Override public void run() { list.add(sequence); } } This code works and prints all the four elements of list on my machine. My question is that will this code always work. I think there might be a issue in this code when two/or more threads add element to this list at the same point. In that case it while loop will never end and code will fail. Can anybody suggest a better way to do this? I am not very good at multithreading and don't know which concurrent collection i can use? Thanks Shekhar

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  • richfaces keepAlive not working

    - by Jurgen H
    I have a mediaOutput tag which, in its createContent attribute, requires the backing bean to be in a certain state. A list of values, which is filled in an init method, must be available. I therefore added a keepAlive tag for the whole backing bean. I now indeed see the backingBean in stead of some (richfaces) proxy bean, but the filled list is null again. How to make this possible? I checked that the init method was called and that the list is filled in in the init method. <a4j:keepAlive beanName="myBean" /> <a4j:mediaOutput createContent="#{myBean.writeChart}" ... /> The backing bean public class MyBean implements Serializable { public List list; public void init(ActionEvent event) { // call some resource to fill the list list = service.getItems(); } public void writeChart(final OutputStream out, final Object data) throws IOException { // list is null } // getters & setters }

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  • Getting fewer columns with hibernate

    - by Gandalf StormCrow
    I have a table with 11 columns, but I need to get only 2 of them in my application, I'm using spring/hibernate/DAO combination. For now I have a domain class which includes all 11 fields, and mapping file which maps all 11 columns in table. How do I use get just 2 of them not all?

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  • ORM framework that extends base class with database-implementation.

    - by aioobe
    I have a game consisting of a client / server + a webpage. A central notion in both client and game-/webserver is an Account. Accounts are stored in a database thus I'm in need of some ORM and recently had a look at Hibernate and Cayenne. My understanding however, is that both frameworks provide an "DatabaseBackedAccount"-class which I extend with my other Account methods. My problem is that the Account class is reused heavily on the client side, and I would obviously not want to include database-related code on the client implementation. My current solution is to have an Account class (shared by server and client) and extend this with a DatabaseBackedAccount (overriding setter-methods and providing a commit method) on the server side. I find this quite natural and nice, however I've had to implement all gory sql-details and ORM myself. Is there any way to "turn the table" in any existing ORM framework, so that the generated classes extend my existing class?

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  • Using Comparable to compare objects and sorting them in a TreeMap

    - by arjacsoh
    II cannot understand how should the natural ordering of class be "consistent with equals" when implementing the Comparable interface. I deteted a flaw in my program and therefore I deteced that in the documentantion of the interface Comparable. My problem is that although two Objects are considered as distinct on the base of equals method, the TreeMap structure treats them as equal and consequently does not accept the second insert. The sample code is: public class Car implements Comparable<Car> { int weight; String name; public Car(int w, String n) { weight=w; name=n; } public boolean equals(Object o){ if(o instanceof Car){ Car d = (Car)o; return ((d.name.equals(name)) && (d.weight==weight)); } return false; } public int hashCode(){ return weight/2 + 17; } public String toString(){ return "I am " +name+ " !!!"; } public int compareTo(Car d){ if(this.weight>d.weight) return 1; else if(this.weight<d.weight) return -1; else return 0; } /*public int compareTo(Car d){ return this.name.compareTo(d.name); }*/ } public static void main(String[] args) { Car d1 = new Car(100, "a"); Car d2 = new Car(110, "b"); Car d3 = new Car(110, "c"); Car d4 = new Car(100, "a"); Map<Car, Integer> m = new HashMap<Car, Integer>(); m.put(d1, 1); m.put(d2, 2); m.put(d3, 3); m.put(d4, 16); for(Map.Entry<Car, Integer> me : m.entrySet()) System.out.println(me.getKey().toString() + " " +me.getValue()); TreeMap<Car, Integer> tm = new TreeMap<Car, Integer>(m); System.out.println("After Sorting: "); for(Map.Entry<Car, Integer> me : tm.entrySet()) System.out.println(me.getKey().toString() + " " +me.getValue()); } The output is : I am a !!! 16 I am c !!! 3 I am b !!! 2 After Sorting: I am a !!! 16 I am c !!! 2 That is, that the object c has replaced (somewhat) object b. If I comment the original equals method and uncomment the second equals method, which compares the objects according name, the output is the expected: I am a !!! 16 I am c !!! 3 I am b !!! 2 After Sorting: I am a !!! 16 I am b !!! 2 I am c !!! 3 Why does it come around in this way and what should I alter in order to insert and sort different objects with some attributes of equal value in a TreeMap?

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  • select and jstl query

    - by sarah
    Hi All, I am displaying data in combo box using ${role} the requirement is on clcik of edit i want to show the preselected value in the drop down ,suppose i have cat,rat and i selected rat and i saved it in database ,now when i want to edit the details i want to show rat first in drop down as pre selected and then cat,how to od this ?

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  • mockito ArrayList<String> problem...

    - by Sardathrion
    I have a method that I am trying to unit test. This method takes a parameter as an ArrayList and does things with it. The mock I am trying to define is: ArrayList<String> mocked = mock(ArrayList.class); which gives a [unchecked] unchecked conversion" warning. ArrayList<String> mocked = mock(ArrayList<String>.class); gives me an error. Anyone care to enlighten me as to what I am doing wrong?

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  • MouseMotion Sensor Method Call

    - by user321894
    I have a soon-to-be due assignment due in computer science. I have encountered a problem, for which no matter how long I study the API's of the class and superclasses, I can not figure out. Suppose I wish to design a sort of "Breakout game" where the mouse motion controls the motion of a block that is used to bounce a ball, which then destroys multi colored bricks. How do you specifically make the block "listen" to the mouse? The below code is what I have attempted to achieve the desired results. /** Breakout Program*/ public class Breakout extends GraphicsProgram implements MouseMotionListener { ... /** The Paddle Itself */ private GRect paddle = new GRect(0, HEIGHT-PADDLEBOTTOM_OFFSET, PADDLEWIDTH, PADDLEHEIGHT); ... /** Run the Breakout program. */ public void run() { paddle.setFillColor(Color.BLACK); paddle.setFilled(true); add(paddle); paddle.addMouseListener(this); ... } /** Move the horizontal middle of the paddle to the x-coordinate of the mouse position - * -but keep the paddle completely on the board. */ public void mouseMoved(MouseEvent e) { GPoint p= new GPoint(e.getPoint()); double x = p.getX(); paddle.setLocation(x, HEIGHT-PADDLEBOTTOM_OFFSET); } } Any clarification on why/what I am doing incorrectly would be helpful, thanks.

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  • Convert InputStream to String with encoding given in stream data

    - by Quentin
    Hi, My input is a InputStream which contains an XML document. Encoding used in XML is unknown and it is defined in the first line of XML document. From this InputStream, I want to have all document in a String. To do this, I use a BufferedInputStream to mark the beginning of the file and start reading first line. I read this first line to get encoding and then I use an InputStreamReader to generate a String with the correct encoding. It seems that it is not the best way to achieve this goal because it produces an OutOfMemory error. Any idea, how to do it ? public static String streamToString(final InputStream is) { String result = null; if (is != null) { BufferedInputStream bis = new BufferedInputStream(is); bis.mark(Integer.MAX_VALUE); final StringBuilder stringBuilder = new StringBuilder(); try { // stream reader that handle encoding final InputStreamReader readerForEncoding = new InputStreamReader(bis, "UTF-8"); final BufferedReader bufferedReaderForEncoding = new BufferedReader(readerForEncoding); String encoding = extractEncodingFromStream(bufferedReaderForEncoding); if (encoding == null) { encoding = DEFAULT_ENCODING; } // stream reader that handle encoding bis.reset(); final InputStreamReader readerForContent = new InputStreamReader(bis, encoding); final BufferedReader bufferedReaderForContent = new BufferedReader(readerForContent); String line = bufferedReaderForContent.readLine(); while (line != null) { stringBuilder.append(line); line = bufferedReaderForContent.readLine(); } bufferedReaderForContent.close(); bufferedReaderForEncoding.close(); } catch (IOException e) { // reset string builder stringBuilder.delete(0, stringBuilder.length()); } result = stringBuilder.toString(); }else { result = null; } return result; } Regards, Quentin

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  • how to draw a line between two labels in a panel where labels are added during runtime

    - by vybhav
    A panel contains two labels which are generated by mouse clicks on the panel. I want to connect these two labels by drawing a line between them probably by dragging the mouse pointer from one label to another. There are two events here - one is clicking on the panel to generate the labels and the second is connecting these two labels (mouse pressed, mouse dragged and mouse released events). Both these event need to call the repaint() method but for different purposes. But there can be only one paint() method. The problem is when I connect these two labels, the line comes up but the rest of the components on the panel disappear.

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