Search Results

Search found 103781 results on 4152 pages for 'am'.

Page 8/4152 | < Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >

  • Can't find this.Controls - what am I missing?

    - by Adam S
    Sorry for a potentially dumb question, I am still new at this. I really appreciate your help. Referring to http://stackoverflow.com/questions/1536739/c-get-control-by-name/1536756#1536756 But I don't have a "this.Controls" available. Is there something I am missing here? In other words, when I type "this." and visual studio populates a list of option, there is no "Controls" option.

    Read the article

  • Why I am getting a Heap Corruption Error?

    - by vaidya.atul
    I am new to C++. I am getting HEAP CORRUPTION ERROR. Any help will be highly appreciated. Below is my code class CEntity { //some member variables CEntity(string section1,string section2); CEntity(); virtual ~CEntity(); //pure virtual function .. virtual CEntity* create()const =0; }; I derive CLine from CEntity as below class CLine:public CEntity { // Again some variables ... // Constructor and destructor CLine(string section1,string section2); CLine(); ~CLine(); CLine* Create() const; } // CLine Implementation CLine::CLine(string section1,string section2):CEntity(section1,section2){}; CLine::CLine(); CLine* CLine::create()const{return new CLine();} I have another class CReader which uses CLine object and populates it in a multimap as below class CReader { public: CReader(); ~CReader(); multimap<int,CEntity*>m_data_vs_entity; }; //CReader Implementation CReader::CReader() { m_data_vs_entity.clear(); }; CReader::~CReader() { multimap<int,CEntity*>::iterator iter; for(iter = m_data_vs_entity.begin();iter!=m_data_vs_entity.end();iter++) { CEntity* current_entity = iter->second; if(current_entity) delete current_entity; } m_data_vs_entity.clear(); } I am reading the data from a file and then populating the CLine Class.The map gets populated in a function of CReader class. Since CEntity has a virtual destructor, I hope the piece of code in CReader's destructor should work. In fact, it does work for small files but I get HEAP CORRUPTION ERROR while working with bigger files. If there is something fundamentally wrong, then, please help me find it, as I have been scratching my head for quit some time now. Thanks in advance and awaiting reply, Regards, Atul

    Read the article

  • What am I missing in IIS7?

    - by faded19
    Hello All, Ok here is my dilemma, I have been developing on a shared host at discountasp.net (IIS 6)for some time now. All was going well, however now that app is complete we are moving it to its own dedicated server which is now server 2008 and IIS 7. I am currently using asp forms authentication (which again seems to work just fine on IIS6) The issue seems to occur after I click login, it pops the "Signing In" box..an error then arises in the JavaScript of Membership.js "Object Does not Support Membership.js" I verified that the code was making it to: membership.BeginLogin(uid, pwd, rememberme); and was in fact passing the correct variables. Another odd thing I noticed when setting the forms permissions is that when I went to select Users or Roles within the IIS 7 management console it would take forever, and then time out with the following error: A Network related or instance specific error occurred while establishing a connection to SQL Server. The server was not or was not accessible, verify that the instance name is correct and that SQL Server is configured to allow remote connections (provider - named pipes provider: error 40 - could not open a connection to SQL Server.) I am rather weak on the hardware/configure side of the house so I am not really sure what the issue is, it’s almost as if IIS7 cannot see the DB. They both reside on the same server however. If anyone could help point me in the right direction as to how to resolve this I would be eternally grateful! Thanks in advance Bryan

    Read the article

  • I am Unable to Post Xml to Linkedin Share API

    - by Vijesh V.Nair
    I am using Delphi 2010, with Indy 10.5.8(svn version) and oAuth.pas from chuckbeasley. I am able to collect token with app key and App secret, authorize token with a web page and Access the final token. Now I have to post a status with Linkedin’s Share API. I am getting a unauthorized response. My request and responses are giving bellow. Request, POST /v1/people/~/shares HTTP/1.0 Content-Encoding: utf-8 Content-Type: text/xml; charset=us-ascii Content-Length: 999 Authorization: OAuth oauth_consumer_key="xxx",oauth_signature_method="HMAC-SHA1",oauth_timestamp="1340438599",oauth_nonce="BB4C78E0A6EB452BEE0FAA2C3F921FC4",oauth_version="1.0",oauth_token="xxx",oauth_signature="Pz8%2FPz8%2FPz9ePzkxPyc%2FDD82Pz8%3D" Host: api.linkedin.com Accept: text/html, */* Accept-Encoding: identity User-Agent: Mozilla/3.0 (compatible; Indy Library) %3C%3Fxml+version=%25221.0%2522%2520encoding%253D%2522UTF-8%2522%253F%253E%253Cshare%253E%253Ccomment%253E83%2525%2520of%2520employers%2520will%2520use%2520social%2520media%2520to%2520hire%253A%252078%2525%2520LinkedIn%252C%252055%2525%2520Facebook%252C%252045%2525%2520Twitter%2520%255BSF%2520Biz%2520Times%255D%2520http%253A%252F%252Fbit.ly%252FcCpeOD%253C%252Fcomment%253E%253Ccontent%253E%253Ctitle%253ESurvey%253A%2520Social%2520networks%2520top%2520hiring%2520tool%2520-%2520San%2520Francisco%2520Business%2520Times%253C%252Ftitle%253E%253Csubmitted-url%253Ehttp%253A%252F%252Fsanfrancisco.bizjournals.com%252Fsanfrancisco%252Fstories%252F2010%252F06%252F28%252Fdaily34.html%253C%252Fsubmitted-url%253E%253Csubmitted-image-url%253Ehttp%253A%252F%252Fimages.bizjournals.com%252Ftravel%252Fcityscapes%252Fthumbs%252Fsm_sanfrancisco.jpg%253C%252Fsubmitted-image-url%253E%253C%252Fcontent%253E%253Cvisibility%253E%253Ccode%253Eanyone%253C%252Fcode%253E%253C%252Fvisibility%253E%253C%252Fshare%253E Response, HTTP/1.1 401 Unauthorized Server: Apache-Coyote/1.1 x-li-request-id: K14SWRPEPL Date: Sat, 23 Jun 2012 08:07:17 GMT Vary: * x-li-format: xml Content-Type: text/xml;charset=UTF-8 Content-Length: 341 Connection: keep-alive <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <error> <status>401</status> <timestamp>1340438838344</timestamp> <request-id>K14SWRPEPL</request-id> <error-code>0</error-code> <message>[unauthorized]. OAU:xxx|nnnnn|*01|*01:1340438599:Pz8/Pz8/Pz9ePzkxPyc/DD82Pz8=</message> </error> Please help. Regards, Vijesh Nair

    Read the article

  • I am not able to update form data to MySQL using PHP and jQuery

    - by Jimson Jose
    My problem is that I am unable to update the values entered in the form. I have attached all the files. I'm using MYSQL database to fetch data. What happens is that I'm able to add and delete records from form using jQuery and PHP scripts to MYSQL database, but I am not able to update data which was retrieved from the database. The file structure is as follows: index.php is a file with jQuery functions where it displays form for adding new data to MYSQL using save.php file and list of all records are view without refreshing page (calling load-list.php to view all records from index.php works fine, and save.php to save data from form) - Delete is an function called from index.php to delete record from MySQL database (function calling delete.php works fine) - Update is an function called from index.php to update data using update-form.php by retriving specific record from MySQL table, (works fine) Problem lies in updating data from update-form.php to update.php (in which update query is written for MySQL) I have tried in many ways - at last I had figured out that data is not being transferred from update-form.php to update.php; there is a small problem in jQuery AJAX function where it is not transferring data to update.php page. Something is missing in calling update.php page it is not entering into that page. I am new bee in programming. I had collected this script from many forums and made this one. So I was limited in solving this problem. I came to know that this is good platform for me and many where we get a help to create new things. Please find the link below to download all files which is of 35kb (virus free assurance): download mysmallform files in ZIPped format, including mysql query

    Read the article

  • Basic SQL Query, I am newbie

    - by user3530547
    I just started my database and query class on Monday. We met on Monday and just went over the syllabus, and on Wednesday the network at school was down so we couldn't even do the power point lecture. Right now I am working on my first homework assignment and I am almost finished but I am having trouble on one question. Here is is... Write a SELECT statement that returns one column from the Customers table named FullName that joins the LastName and FirstName columns. Format the columns with the last name, a comma, a space, and the first name like this: Doe, John Sort the result set by last name in ascending sequence. Return only the contacts whose last name begins with letters from M to Z. Here is what I have so far... USE md0577283 SELECT FirstName,LastName FROM Customers ORDER BY LastName,FirstName My question is how do I format is Lastname, FirstName like the professor wants and how do I only select names M-Z? If someone could point me in the right direction I would greatly appreciate it. Thank you. PS With all do respect, I didn't ask for the answer I asked for a nudge in the right direction so why the down vote guys?

    Read the article

  • I am trying to access the individual bytes in a floating point number and I am getting unexpected results

    - by oweinh
    So I have this so far: #include <iostream> #include <string> #include <typeinfo> using namespace std; int main () { float f = 3.45; // just an example fp# char* ptr = (char*)&f; // a character pointer to the first byte of the fp#? cout << int(ptr[0]) << endl; // these lines are just to see if I get what I cout << int(ptr[1]) << endl; // am looking for... I want ints that I can cout << int(ptr[2]) << endl; // otherwise manipulate. cout << int(ptr[3]) << endl; } the result is: -51 -52 92 64 so obviously -51 and -52 are not in the byte range that I would expect for a char... I have taken information from similar questions to arrive at this code and from all discussions, a conversion from char to int is straightforward. So why negative values? I am trying to look at a four-byte number, therefore I would expect 4 integers, each in the range 0-255. I am using Codeblocks 13.12 with gcc 4.8.1 with option -std=C++11 on a Windows 8.1 device.

    Read the article

  • Expression Studio 4 Premium & SketchFlow: Am I screwed?

    - by Refracted Paladin
    Through work I have an Visual Studio Premium with MSDN subscription that I love. However, my biggest disappointment of the last 12 months was discovering that our 2nd from the top level subscription was not enough to get me Sketchflow! This sucks and I am borderline distraught! What are my options? Upgrading to an Ultimate subscription for Sketchflow is out of the question. Am I forced, then, to stay with Blend 3 or Purchase Blend 4 seperately? If this is not a question I should ask here please inform and I'll delete. I just tend to default to SO for all questions that Google can't answer and Google did not answer this one.

    Read the article

  • How safe am I singing into Google Spreadsheets with yeroon.net/ggplot2

    - by Farrel
    I am impressed by what I have seen of yeroon.net/ggplot2 which is a web interface for Hadley Wickham's R package ggplot2. I want to try it out on my own data. The part that has me very excited is that one can use data stored in one's own Google spreadsheet as the data. One just signs into their Google Account so that yeroon.net/ggplot2 can access the spreadsheet list. I have been hesitant to do it. If I sign in whilst on yeroon.net am I handing over my username and password to a third party? It would not be wise of me to divulge my google password to third parties since Google is fast becoming my repository of everything. How do I know if Jeroon's application is using ClientLogin or OAuth? My understanding is very basic and may be wrong but nevertheless here it is. OAuth would be better since it does not actually pass the password onto the third party application.

    Read the article

  • Defining where on the page the flowdocument I am printing will 'start' and 'end'

    - by Sagi1981
    Dear community. I am almost done with implementing a printing functionality, but I am having trouble getting the last hurdle done with. My problem is, that I am printing some reports, consisting of a header (with information about the person the report is about), a footer (with a page number) and the content in the middle, which is a FlowDocument. Since the flowdocuments can be fairly long, It is very possible that they will span multiple pages. My approach is to make a custom FlowDocumentPaginator which derives from DocumentPaginator. In there i define my header and my footer. However, when I print my page, the flowdocument and my header and footer are on top of eachother. So my question is plain and simple - how do I define from where and to where the flowdocument part on the pages will be placed? here is the code from my custommade Paginator: public class HeaderedFlowDocumentPaginator : DocumentPaginator { private DocumentPaginator flowDocumentpaginator; public HeaderedFlowDocumentPaginator(FlowDocument document) { flowDocumentpaginator = ((IDocumentPaginatorSource) document).DocumentPaginator; } public override bool IsPageCountValid { get { return flowDocumentpaginator.IsPageCountValid; } } public override int PageCount { get { return flowDocumentpaginator.PageCount; } } public override Size PageSize { get { return flowDocumentpaginator.PageSize; } set { flowDocumentpaginator.PageSize = value; } } public override IDocumentPaginatorSource Source { get { return flowDocumentpaginator.Source; } } public override DocumentPage GetPage(int pageNumber) { DocumentPage page = flowDocumentpaginator.GetPage(pageNumber); ContainerVisual newVisual = new ContainerVisual(); newVisual.Children.Add(page.Visual); DrawingVisual header = new DrawingVisual(); using (DrawingContext dc = header.RenderOpen()) { //Header data } newVisual.Children.Add(header); DrawingVisual footer = new DrawingVisual(); using (DrawingContext dc = footer.RenderOpen()) { Typeface typeface = new Typeface("Trebuchet MS"); FormattedText text = new FormattedText("Page " + (pageNumber + 1).ToString(), CultureInfo.CurrentCulture, FlowDirection.LeftToRight, typeface, 14, Brushes.Black); dc.DrawText(text, new Point(page.Size.Width - 100, page.Size.Height-30)); } newVisual.Children.Add(footer); DocumentPage newPage = new DocumentPage(newVisual); return newPage; } } And here is the printdialogue call: private void btnPrint_Click(object sender, RoutedEventArgs e) { try { PrintDialog printDialog = new PrintDialog(); if (printDialog.ShowDialog() == true) { FlowDocument fd = new FlowDocument(); MemoryStream stream = new MemoryStream(ASCIIEncoding.Default.GetBytes(<My string of text - RTF formatted>)); TextRange tr = new TextRange(fd.ContentStart, fd.ContentEnd); tr.Load(stream, DataFormats.Rtf); stream.Close(); fd.ColumnWidth = printDialog.PrintableAreaWidth; HeaderedFlowDocumentPaginator paginator = new HeaderedFlowDocumentPaginator(fd); printDialog.PrintDocument(paginator, "myReport"); } } catch (Exception ex) { //Handle } }

    Read the article

  • Memory over-release problem when I am animating UIView

    - by Sheehan Alam
    I have enabled NSZombie's and I am getting the following message in my console when I am running my application: *** -[UIViewAnimationState release]: message sent to deallocated instance 0xf96d7e0 Here is the method that is performing the animation -(void)loadAvatar:(STObject*)st { NSAutoreleasePool * pool = [[NSAutoreleasePool alloc] init]; avatar.alpha = 0; avatar.frame = avatarRectSmall; avatar.image = [ImageCache getMemoryCachedImageAtUrl:st.avatar_url]; [UIView beginAnimations:nil context:nil]; [UIView setAnimationDuration:.50]; avatar.frame = avatarRectNormal; [avatar setAlpha:1]; [UIView commitAnimations]; [pool release]; pool = nil; } I don't always get a crash, only sometimes. I'm wondering what is getting released?

    Read the article

  • How safe am I signing into Google Spreadsheets with yeroon.net/ggplot2

    - by Farrel
    I am impressed by what I have seen of yeroon.net/ggplot2 which is a web interface for Hadley Wickham's R package ggplot2. I want to try it out on my own data. The part that has me very excited is that one can use data stored in one's own Google spreadsheet as the data. One just signs into their Google Account so that yeroon.net/ggplot2 can access the spreadsheet list. I have been hesitant to do it. If I sign in whilst on yeroon.net am I handing over my username and password to a third party? It would not be wise of me to divulge my google password to third parties since Google is fast becoming my repository of everything. How do I know if Jeroon's application is using ClientLogin or OAuth? My understanding is very basic and may be wrong but nevertheless here it is. OAuth would be better since it does not actually pass the password onto the third party application.

    Read the article

  • Drag and Drop text - What am I missing?

    - by Harvey
    I am trying to add drag-and-drop text to my Doc-View App. I added the COleDropTarget variable to the view class, registered it in OnCreate(). I added OnDragEnter(), OnDragOver(), OnDragLeave() and OnDrop() to that class as virtual overrides, but none of them are ever called. I previously had added m_pMainWnd-DragAcceptFiles(TRUE); to my App class. I tried commenting out that statement, but no affect. I tried using Spy++ to see where the messages go while I do a drag, but it logs nothing at all while I am dragging the text around in the App. What do I need? Or what else can I try, to narrow down the problem? TIA, Harvey

    Read the article

  • Where i am doing wrong in this?

    - by kumar
    <script type="text/javascript"> $(document).ready(function() { $('#PbtnSubmit').attr('disabled', 'disabled'); $('#PbtnCancel').attr('disabled', 'disabled'); $('#PbtnSelectAll').click(function() { $('#PricingEditExceptions input[type=checkbox]').attr('checked', 'checked'); $('#PbtnSubmit').removeAttr('disabled'); $('#PbtnCancel').removeAttr('disabled'); $('fieldset').find("input,select,textarea").removeAttr('disabled'); }); $('#PbtnCancel').click(function() { $('#PricingEditExceptions input[name=PMchk]').attr('checked', false); $('#PbtnSubmit').attr('disabled', 'disabled'); $('#PbtnCancel').attr('disabled', 'disabled'); $('fieldset').find("input:not(:checkbox),select,textarea").attr('disabled', 'disabled'); $('#genericfieldset').find("input,select,textarea").removeAttr('disabled'); }); $('#PbtnSubmit').click(function() { $('#PricingEditExceptions input[name=PMchk]').each(function() { if ($("#PricingEditExceptions input:checkbox:checked").length > 0) { var checked = $('#PricingEditExceptions input[type=checkbox]:checked'); var PMstrIDs = checked.map(function() { return $(this).val(); }).get().join(','); $('#1_exceptiontypes').attr('value', exceptiontypes) $('#1_PMstrIDs').attr('value', PMstrIDs); } else { alert("Please select atleast one exception"); return false; } }); }); function validate_excpt(formData, jqForm, options) { var form = jqForm[0]; } // post-submit callback function showResponse(responseText, statusText, xhr, $form) { if (responseText[0].substring(0, 16) != "System.Exception") { $('#error-msg-ID span:last').html('<strong>Update successful.</strong>'); } else { $('#error-msg-ID span:last').html('<strong>Update failed.</strong> ' + responseText[0].substring(0, 48)); } $('#error-msg-ID').removeClass('hide'); } $('#exc-').ajaxForm({ target: '#error-msg-ID', beforeSubmit: validate_excpt, success: showResponse, dataType: 'json' }); $('.button').button(); }); </script> This is my button.. at very first when page load I am trying Make Disabled PbtnSubmit and PbtnCancel and when we click PbtnSelectAll I am enabling back again.. but its not doing with this code. is that something I am doing worng in this? thanks

    Read the article

  • Beginform is not working in Asp.net mvc control whenI am trying to send the values

    - by kumar
    Hello friends i have a beginform is soemthing like this, <% using (Html.BeginForm("edit", (Model.ExceptionCategoryID == "EXP") ? "expense" : "pricing", FormMethod.Post, new { @id="exc-" + Model.ExceptionID})) { %> <input type="hidden" id="Status" runat="server"/> <%= Html.ValidationSummary(true)%> input submit button <input id="bSubmit" type="submit" class="button" value="Save" /> <script type="text/javascript"> $(document).ready(function() { $('#bSubmit').click(function() { var Status = "<%=Model.ExceptionStatus.Trim()%>"; alert(Status); $('#1_Status').attr('value',Status); }); </script> on sbmit I am trying to send the Status value.. on controler var sta = Request.Form[0]; I am getting something like 3%24Status in the From key.. why its hapeening ? thanks

    Read the article

  • Coding issue in the 3D Buzz Hyperion tutorial.I am work

    - by Geno
    I'm following along with the tutorial. And we are currently coding the Item class. I am using the 2008 edition, while the tutorial uses 2005. The code I am having issue with is: public string Weight { get { return weight; } set { weight = value; } } earlier in the code, we had: private int Weight = 1; as you can see, they are both different variables, int, and string. I'm doing exactly as the tutorial shows, on mine, I get a conversion error, whereas in the tutorial, there are no errors, why is this? I'm doing exactly what the video shows.

    Read the article

  • What am I encrypting wrong here?

    - by Katie Krueger
    So I have a wordplay project to do and I have to encrypt some characters. I am at the point where I am stuck, and when I run it and type 1 for encrypt it doesn't shift that many letters. It just prints the work over again. I am wondering what I could do to fix it where if I say "hello" it will print 1 character over and say "ifmmp" Thank you! import java.util.Scanner; public class WordPlayTester{ public static void main(String [] args){ String word, reverse=""; String original; int key= 0; String Menu= "1-Encrypt \n2-Decrypt \n3-Is Palindrome \n0-Quit \n-Select an option-"; Scanner in = new Scanner(System.in); System.out.println("-Type any word-"); word = in.nextLine(); System.out.println(Menu); int choice=in.nextInt(); if(choice==1) { System.out.println("Insert a Key number"); int select= in.nextInt(); for (int i=0; i < word.length(); i++) { char c = word.charAt(i); if (c >= 'A' && c <= 'Z') { c = (char)(c - 64); int n = c+1; n = n % 26; if (n < 0) { n = n + 26; } c = (char)(n + 65); } System.out.println(c); } } else if(choice==3) { int length = word.length(); for ( int i = length - 1 ; i >= 0 ; i-- ) reverse = reverse + word.charAt(i); if (word.equals(reverse)) System.out.println("Your word is a palindrome."); else System.out.println("Your word is not a palindrome."); } else if(choice==0) { System.exit(0); } else { System.out.println(Menu); } } }

    Read the article

  • Can anyone tell me were I am making mistake in the snippet

    - by Solitaire
    public partial class Form1 : Form { [DllImport("coredll.dll")] static extern int SetWindowLong(IntPtr hWnd, int nIndex, int dwNewLong); const int GWL_WNDPROC = -4; public delegate int WindProc(IntPtr hWnd, uint msg, long Wparam, long lparam); public Form1() { InitializeComponent(); WindProc SampleProc = new WindProc (SubclassWndProc); SetWindowLong(this .Handle , GWL_WNDPROC, SampleProc.Method .MethodHandle.Value.ToInt32()); } public int SubclassWndProc(IntPtr hwnd, uint msg, long Wparam, long lparam) { return 1; } Here is the sample which i was trying to take the window procedure of a form, this is how i do in C++ i get the windwproc easlily if i try the same in C# .net 3.5 i am unable to get the window proc,, after calling SetWindowLong API application hangs and it pops up some dont send report... i have read this is the way to get the window proc.. please let me know were i am making mistake...

    Read the article

  • Why am I getting ClassNotFoundExpection when I have properly imported said class and am looking at it in its directory?

    - by Strider
    This is my Javac compiling statement: javac -cp "C:\java\code\j3D\j3dcore.jar;C:\java\code\j3D\j3dutils.jar;C:\java\code\j3D\vecmath.jar" Simple.java compiles with no problems. The three jar files (j3dcore, j3dutils, and vecmath) are the essential jar's for my program (or at least I am led to believe according to this official tutorial on J3D For the record I ripped this code almost line from line from this pdf file. jar files are correctly located in referenced locations When I run my Simple program, (java Simple) I am greeted with Exception in thread "main" java.lang.NoClassDefFoundError: javax/media/j3d/Cavas3d Caused by: java.lang.ClassNotFoundExpection: javax.media.j3d.Canvas3D Currently I am staring directly at this Canvas3D.class that is located within j3dcore.jar\javax\media\j3d\ wtfisthis.jpg Here is the source code: //First java3D Program import java.applet.Applet; import java.awt.BorderLayout; import java.awt.Frame; import java.awt.event.*; import com.sun.j3d.utils.applet.MainFrame; import com.sun.j3d.utils.universe.*; import com.sun.j3d.utils.geometry.ColorCube; import javax.media.j3d.*; import javax.vecmath.*; import java.awt.GraphicsConfiguration; public class Simple extends Applet { public Simple() { setLayout(new BorderLayout()); GraphicsConfiguration config = SimpleUniverse.getPreferredConfiguration(); Canvas3D canvas3D = new Canvas3D(config); add("Center", canvas3D); BranchGroup scene = createSceneGraph(); scene.compile(); // SimpleUniverse is a Convenience Utility class SimpleUniverse simpleU = new SimpleUniverse(canvas3D); // This moves the ViewPlatform back a bit so the // objects in the scene can be viewed. simpleU.getViewingPlatform().setNominalViewingTransform(); simpleU.addBranchGraph(scene); } // end of HelloJava3Da (constructor) public BranchGroup createSceneGraph() { // Create the root of the branch graph BranchGroup objRoot = new BranchGroup(); // Create a simple shape leaf node, add it to the scene graph. // ColorCube is a Convenience Utility class objRoot.addChild(new ColorCube(0.4)); return objRoot; } public static void main(String args[]){ Simple world = new Simple(); } }` Did I import correctly? Did I incorrectly reference my jar files in my Javac statement? If I clearly see Canvas3D within its correct directory why cant java find it? The first folder in both j3dcore.jar and vecmath.jar is "javax". Is the compiler getting confused? If the compiler is getting confused how do I specify where to find that exact class when referencing it within my source code?

    Read the article

  • why am i getting an error SyntaxError : invalid syntax for this code

    - by eragon1189
    This is a code in python which calculates f (x) =? ((-1)*x)/(x*x+n*n) n from 1 to infinite.... correct to 0.0001, for the range 1 < x < 100 in steps of 0.1.But i am getting an syntax error,as i am new to programming in python... from scipy import * from matplotlib.pyplot import * x=arange(0.1,100,0.1) f=zeros(len(x)) s=-1 for n in range (1,10000): t=s*x/(x*x+n*n) f +=t s =-s if max(abs(t))< 1e-4 break for xx in c_[x,f]: print "%f %f" % (xx[0],xx[1])

    Read the article

< Previous Page | 4 5 6 7 8 9 10 11 12 13 14 15  | Next Page >