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  • C++ enum in foreach

    - by Spencer
    I've have a card class for a blackjack game with the following enums: enum Rank { Ace, Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten, Jack, Queen, King }; enum Suit { Clubs, Diamonds, Hearts, Spades }; When I create the deck I want to write the code like this: // foreach Suit in Card::Suit // foreach Rank in Card::Rank // add new card(rank, suit) to deck I believe there is no foreach in c++. However, how do I traverse an enum? Thanks, Spencer

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  • Ranking - an Introduction

    - by PointsToShare
    © 2011 By: Dov Trietsch. All rights reserved Ranking Ranking is quite common in the internet. Readers are asked to rank their latest reading by clicking on one of 5 (sometimes 10) stars. The number of stars is then converted to a number and the average number of stars as selected by all the readers is proudly (or shamefully) displayed for future readers. SharePoint 2007 lacked this feature altogether. SharePoint 2010 allows the users to rank items in a list or documents in a library (the two are actually the same because a library is actually a list). But in SP2010 the computation of the average is done later on a timer rather than on-the-spot as it should be. I suspect that the reason for this shortcoming is that they did not involve a mathematician! Let me explain. Ranking is kept in a related list. When a user rates a document the rank-list is added an item with the item id, the user name, and his number of stars. The fact that a user already ranked an item prevents him from ranking it again. This prevents the creator of the item from asking his mother to rank it a 5 and do it 753 times, thus stacking the ballot. Some systems will allow a user to change his rating and this will be done by updating the rank-list item. Now, when the timer kicks off, the list is spanned and for each item the rank-list items containing this id are summed up and divided by the number of votes thus yielding the new average. This is obviously very time consuming and very server intensive. In the 18th century an early actuary named James Dodson used what the great Augustus De Morgan (of De Morgan’s law) later named Commutation tables. The labor involved in computing a life insurance premium was staggering and also very error prone. Clerks with pencil and paper would multiply and add mountains of numbers to do the task. The more steps the greater the probability of error and the more expensive the process. Commutation tables created a “summary” of many steps and reduced the work 100 fold. So had Microsoft taken a lesson in the history of computation, they would have developed a much faster way for rating that may be done in real-time and is also 100 times faster and less CPU intensive. How do we do this? We use a form of commutation. We always keep the number of votes and the total of stars. One simple division gives us the average. So we write an event receiver. When a vote is added, we just add the stars to the total-stars and 1 to the number of votes. We then recomputed the average. When a vote is updated, we reduce the total by the old vote, increase it by the new vote and leave the number of votes the same. Again we do the division to get the new average. When a vote is deleted (highly unlikely and maybe even prohibited), we reduce the total by that vote and reduce the number of votes by 1… Gone are the days of spanning lists, counting items, and tallying votes and we have no need for a timer process to run it all. This is the first of a few treatises on ranking. Even though I discussed the math and the history thereof, in here I am only going to solve the presentation issue. I wanted to create the CSS and Jscript needed to display the stars, create the various effects like hovering and clicking (onmouseover, onmouseout, onclick, etc.) and I wanted to create a general solution with any number of stars. When I had it all done, I created the ranking game so that I could test it. The game is interesting in and on itself, so here it is (or go to the games page and select “rank the stars”). BTW, when you play it, look at the source code and see how it was all done.  Next, how the 5 stars are displayed in the New and Update forms. When the whole set of articles will be done, you’ll be able to create the complete solution. That’s all folks!

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  • Java App Engine - ranked counter

    - by Richard
    I understand the sharded counter, here: http://code.google.com/appengine/articles/sharding_counters.html The problem is that a simple counter will not work in my application. I am sorting my entities by a particular variable so I am returned not so much a count, but more of a rank. My current method is: SELECT COUNT(this) FROM Entity.class WHERE value <= ? Result + 1 is then the rank of the parameter in relation to the value variable in the persistent Entity objects. The limitation of this is the highest rank being returned is 1001 because count() can give a maximum of 1000. The reason I cannot store the rank on the Entity object is that the ranks are updated very often, and re-setting this rank variable would be much too costly. Any ideas on the best way to accomplish this?

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  • Counting distinct and duplicate attribute values in an array

    - by keruilin
    I have an array of users that's sorted in descending order based on total_points. I need to find the rank of each user in that array. The issue is that more than one user can have the same total points and, thus, the same rank. For example, three users could be in 3rd place with 200 Points. Here's my current code: class Leader < ActiveRecord::Base def self.points_leaders all_leaders = all_points_leaders # returns array of users sorted by total_points in desc order all_leaders_with_rank = [] all_leaders.each do |user| rank = all_leaders.index(user)+1 all_leaders_with_rank << Ldr.new(rank, user) # Ldr is a Struct end return all_leaders_with_rank end end How must I modify the code so that the correct rank is returned, and not just the value of the index position?

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  • how to sort xml data in jQuery

    - by pixeltocode
    how can i sort all officers based on their ranks jQuery $.get('officers.xml', function(grade){ $(grade).find('officer').each(function(){ var $rank = $(this).attr('rank'); }); }); XML (officer.xml) <grade> <officer rank="2"></student> <officer rank="3"></student> <officer rank="1"></student> </grade> thanks.

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  • Zend Framework Db Select Join table help

    - by tester2001
    I have this query: SELECT g.title, g.asin, g.platform_id, r.rank FROM games g INNER JOIN ranks r ON ( g.id = r.game_id ) ORDER BY r.rank DESC LIMIT 5` Now, this is my JOIN using Zend_Db_Select but it gives me array error $query = $this-select(); $query-from(array('g' = 'games'), array()); $query-join(array('r' = 'ranks'), 'g.id = r.game_id', array('g.title', 'g.asin', 'g.platform_id', 'r.rank')); $query-order('r.rank DESC'); $query-limit($top); $resultRows = $this-fetchAll($query); return $resultRows; Anyone know what I could be doing wrong? I want to get all the columns in 'games' to show and the 'rank' column in the ranks table.

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  • Optimise & improve performance of this MYSQL query

    - by David
    SELECT u.id, u.honour, COUNT(*) + 1 AS rank FROM user_info u INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id = '$id' AND u2.status = 'Alive' AND u2.rank != '14' This query is currently utterly raping my server. It works out based on your honour what rank you are within the 'user_info' table which stores it out of all our users. Screenshot for explain. http://cl.ly/370z0v2Y3v2X1t1r1k2A SELECT u.id, u.honour, COUNT(*)+1 as rank FROM user_info u USE INDEX (prestigeOptimiser) INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id='3' AND u2.status='Alive' AND u2.rank!='14'

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  • How to ORDER BY non-column field?

    - by Phil Bolduc
    I am trying to create an Entity SQL that is a union of two sub-queries. (SELECT VALUE DISTINCT ROW(e.ColumnA, e.ColumnB, 1 AS Rank) FROM Context.Entity AS E WHERE ...) UNION ALL (SELECT VALUE DISTINCT ROW(e.ColumnA, e.ColumnB, 2 AS Rank) FROM Context.Entity AS E WHERE ...) ORDER BY *??* LIMIT 50 I have tried: ORDER BY Rank and ORDER BY e.Rank but I keep getting: System.Data.EntitySqlException: The query syntax is not valid. Near keyword 'ORDER' I do not think it is a problem with the Rank column. I do think it is how I am trying to apply an order by to two different esql statements joined by union all. Could someone suggest: How to apply a ORDER BY to this kind of UNION/UNION ALL statment How to order by the non-entity column expression. Thanks.

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  • How can I remove an "ALMOST" Duplicate using LINQ? ( OR SQL? )

    - by Atomiton
    This should be and easy one for the LINQ gurus out there. I'm doing a complex Query using UNIONS and CONTAINSTABLE in my database to return ranked results to my application. I'm getting duplicates in my returned data. This is expected. I'm using CONTAINSTABLE and CONTAINS to get all the results I need. CONTAINSTABLE is ranked by SQL and CONTAINS (which is run only on the Keywords field ) is hard-code-ranked by me. ( Sorry if that doesn't make sense ) Anyway, because the tuples aren't identical ( their rank is different ) a duplicate is returned. I figure the best way to deal with this is use LINQ. I know I'll be using the Distinct() extension method, but do I have to implement the IEqualityComparer interface? I'm a little fuzzy on how to do this. For argument's sake, say my resultset is structured like this class: class Content { ContentID int //KEY Rank int Description String } If I have a List<Content> how would I write the Distinct() method to exclude Rank? Ideally I'd like to keep the Content's highest Rank. SO, if one Content's RAnk is 112 and the other is 76. I'd like to keep the 112 rank. Hopefully I've given enough information.

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  • How do I return an array from a method?

    - by dwwilson66
    I'm trying to create a deck of cards for my homework. Code is posted below. I need to create four sets of cards (the four suits) and am create a multidimensional array. When I print the results instead of trying to pass the array, I can see that the data in the array is as expected. However, when I try to pass the array card, I get an error cannot find symbol. I've got this modeled after texbook and Java tutorial examples, and I need some help figuring out what I'm missing. I've over-documented to give an idea of how I'm thinking this SHOULD work...please let me know where I've gone horribly wrong in my understanding. import java.util.*; import java.lang.*; // public class CardGame { public static int[][] main(String[] args) { int[][] startDeck = deckOfCards(); /* cast new deck as int[][], calling method deckOfCards System.out.println(" /// from array: " + Arrays.deepToString(startDeck)); } public static int[][] deckOfCards() /* method to return a multi-dimensional array */ { int rank; int suit; for(rank=1;rank<14;rank++) /* cards 1 - 13 .... */ { for(suit=1;suit<5;suit++) /* suits 1 - 4 .... */ { int[][] card = new int[][] /* define a new card... */ { {rank,suit} /* with rank/suit from for... loops */ }; System.out.println(" /// from array: " + Arrays.deepToString(card)); } } return card; /* Error: cannot find symbol } }

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  • jQuery: AJAX call isn't updating page

    - by Cortopasta
    Thought I had a simple AJAX call using $.POST(), but apparently my function isn't firing, and nothing is updating :-/ Here is the call: $(".answerVerse ul li").click(function(){ var rank = $(this).removeClass("star_empty star_full star_highlight").attr("class"); var verse_id = $(this).parent().parent().find(".verseId").html(); var answer_id = $(this).parent().parent().find(".answerId").html(); var place = this; $.post("rank.php", { rank: rank, verse_id: verse_id, answer_id: answer_id },function(data){ $(place).parent().removeClass().addClass(data.newVerseRank); for (i=0;i<=5;i++) { $(".answerVerse ul."+i).each(function(){ $(".answerVerse ul."+i+" li."+i).prevAll().andSelf().removeClass("star_empty").addClass("star_full"); }); } }, "json"); }); And here is the PHP (rank.php) that it calls: require_once("dbcon.php"); $user = new user(); $user->updateVerseRank($_POST['verse_id'], $_POST['rank']); $user->getVerse($_POST['verse_id']); $user->getAnswer($_POST['answer_id']; $arr = array ('newVerseRank'=>htmlspecialchars(round($user->verse[3])),'newVerseVotes'=>htmlspecialchars(round($user->verse[4])),'newAnswerRank'=>htmlspecialchars($user->answer[3])); echo json_encode($arr); Why am I not updating the page? I know it's something dumb I'm doing seeing as how this is my first attempt at AJAX and JSON :-/ Just trying to learn

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  • Retrieving a unique result set with Core Data

    - by randombits
    I have a core data based app that manages a bunch of entities. I'm looking to be able to do the following. I have an entity "SomeEntity" with the attributes: name, type, rank, foo1, foo2. Now, SomeEntity has several rows if when we're speaking strictly in SQL terms. What I'm trying to accomplish is to retrieve only available types, even though each instance can have duplicate types. I also need them returned in order according to rank. So in SQL, what I'm looking for is the following: SELECT DISTINCT(type) ORDER BY rank ASC Here is the code I have so far that's breaking: NSError *error = NULL; NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; [fetchRequest setReturnsDistinctResults:YES]; [fetchRequest setPropertiesToFetch:[NSArray arrayWithObjects:@"type", @"rank", nil]]; NSEntityDescription *entity = [NSEntityDescription entityForName:@"SomeEntity" inManagedObjectContext:managedObjectContext]; [fetchRequest setEntity:entity]; // sort by rank NSSortDescriptor *rankDescriptor = [[NSSortDescriptor alloc] initWithKey:@"rank" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:rankDescriptor,nil]; [fetchRequest setSortDescriptors:sortDescriptors]; [sortDescriptors release]; [rankDescriptor release]; NSArray *fetchResults = [managedObjectContext executeFetchRequest:fetchRequest error:&error]; [fetchRequest release]; return fetchResults; Right now that is crashing with the following: Invalid keypath section passed to setPropertiesToFetch:

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  • How to distribute ranking using MySQL Query and PHP

    - by nkp
    I have to distribute ranking to the 5000 students in an exam. Ranking is based on the score and the time taken (in seconds) to obtain that score. For example is 5 students have same score, then taken will be the criteria to calculate their ranks otherwise score should be the criteria to calculate their ranks. Following is my table tbRank ID StudID Score Time Date Rank 1 11 8 60 09-11-2013 2 22 6 45 09-11-2013 3 33 4 76 09-11-2013 4 44 6 67 09-11-2013 5 55 8 35 09-11-2013 6 66 8 35 08-11-2013 7 77 8 39 08-11-2013 Now rank column in above table should be updated as: ID StudID Score Time Date Rank 1 11 8 60 09-11-2013 2 2 22 6 45 09-11-2013 3 3 33 4 76 09-11-2013 5 4 44 6 67 09-11-2013 4 5 55 8 35 09-11-2013 1 6 66 8 35 08-11-2013 1 7 77 8 39 08-11-2013 2 I want to make a MySQL Query to do this business. Similarly there can be more than 10000 records in the table. So I need an optimized query for this functionality. Note: I am using PHP and MYSQL. Update: Everyday almost 5000 new entries will be created in the table and after all insertions are made, rank column will be updated once in a day. Now please suggest me the best way to do this. If I update rank column in the table, then only once I will have to do it, otherwise everytime while fetching the rank of the student, I will have to make calculations.

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  • Maintaining Revision Levels

    - by kyle.hatlestad
    A question that came up on an earlier blog post was how to limit the number of revisions on a piece of content. UCM does not inherently enforce any sort of limit on how many revisions you can have. It's unlimited. In some cases, there may be content that goes through lots of changes, but there just simply isn't a need to keep all of its revisions around. Deleting those revisions through the content information screen can be very cumbersome. And going through the Repository Manager applet can take time as well to filter and find the revisions to get rid of. But there is an easier way through the Archiver. The Export Query criteria in Archiver includes a very handy field called 'Revision Rank'. With revision labels, they typically go up as new revisions come in (e.g. 1, 2, 3, 4, etc...). But you can't really use this field to tell it to keep the top 5 revisions. Those top 5 revision numbers are always going up. But revision rank goes the opposite direction. The very latest revision is always 0. The previous revision to that is 1. Previous revision to that is 2. And so on and so forth. With revision rank, you can set your query to look for any Revision Rank greater or equal to 5. Now as older revisions move down the line, their revision rank gets higher and higher until they reach that threshold. Then when you run that archive export, you can choose to delete and remove those revisions. Running that export in Archiver is normally a manual process. But with Idc Command, you can script the process and have it run automatically from the server. Idc Command is a utility that allows you to run any of the content server services via the command line. You basically feed it a text file with the services and parameters defined along with the user to run it as. The Idc Command executable is located within the \bin\ directory: $ ./IdcCommand -f DeleteOlderRevisions.txt -u sysadmin -l delete_revisions.log In this example, our IdcCommand file to run the export and do the deletions would look like: IdcService=EXPORT_ARCHIVE aArchiveName=DeleteOlderRevisions aDoDelete=1 IDC_Name=idc dataSource=RevisionIDs <<EOD>> You can then use automated scheduling routines in the OS to run the command and command file at the frequency needed. Remember that you are deleting the revisions from within UCM, but they are still getting placed within the archive. So you will need to delete those batches to have them fully removed (or re-import if you need to recover them). For more information about Idc Command, you can find that in the Idc Command Reference Guide.

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  • C++ match string in file and get line number

    - by Corey
    I have a file with the top 1000 baby names. I want to ask the user for a name...search the file...and tell the user what rank that name is for boy names and what rank for girl names. If it isn't in boy names or girl names, it tells the user it's not among the popular names for that gender. The file is laid out like this: Rank Boy-Names Girl-Names 1 Jacob Emily 2 Michael Emma . . . Desired output for input Michael would be: Michael is 2nd most popular among boy names. If Michael is not in girl names it should say: Michael is not among the most popular girl names Though if it was, it would say: Micheal is (rank) among girl names The code I have so far is below.. I can't seem to figure it out. Thanks for any help. #include <iostream> #include <fstream> #include <string> #include <cctype> using namespace std; void find_name(string name); int main(int argc, char **argv) { string name; cout << "Please enter a baby name to search for:\n"; cin >> name; /*while(!(cin>>name)) { cout << "Please enter a baby name to search for:\n"; cin >> name; }*/ find_name(name); cin.get(); cin.get(); return 0; } void find_name(string name) { ifstream input; int line = 0; string line1 = " "; int rank; string boy_name = ""; string girl_name = ""; input.open("/<path>/babynames2004.rtf"); if (!input) { cout << "Unable to open file\n"; exit(1); } while(input.good()) { while(getline(input,line1)) { input >> rank >> boy_name >> girl_name; if (boy_name == name) { cout << name << " is ranked " << rank << " among boy names\n"; } else { cout << name << " is not among the popular boy names\n"; } if (girl_name == name) { cout << name << " is ranked " << rank << " among girl names\n"; } else { cout << name << " is not among the popular girl names\n"; } } } input.close(); }

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  • Blackjack game reshuffling problem-edited

    - by Jam
    I am trying to make a blackjack game where before each new round, the program checks to make sure that the deck has 7 cards per player. And if it doesn't, the deck clears, repopulates, and reshuffles. I have most of the problem down, but for some reason at the start of every deal it reshuffles the deck more than once, and I can't figure out why. Help, please. Here's what I have so far: (P.S. the imported cards and games modules aren't part of the problem, I'm fairly sure my problem lies in the deal() function of my BJ_Deck class.) import cards, games class BJ_Card(cards.Card): """ A Blackjack Card. """ ACE_VALUE = 1 def get_value(self): if self.is_face_up: value = BJ_Card.RANKS.index(self.rank) + 1 if value > 10: value = 10 else: value = None return value value = property(get_value) class BJ_Deck(cards.Deck): """ A Blackjack Deck. """ def populate(self): for suit in BJ_Card.SUITS: for rank in BJ_Card.RANKS: self.cards.append(BJ_Card(rank, suit)) def deal(self, hands, per_hand=1): for rounds in range(per_hand): if len(self.cards)>=7*(len(hands)): print "Reshuffling the deck." self.cards=[] self.populate() self.shuffle() for hand in hands: top_card=self.cards[0] self.give(top_card, hand) class BJ_Hand(cards.Hand): """ A Blackjack Hand. """ def __init__(self, name): super(BJ_Hand, self).__init__() self.name = name def __str__(self): rep = self.name + ":\t" + super(BJ_Hand, self).__str__() if self.total: rep += "(" + str(self.total) + ")" return rep def get_total(self): # if a card in the hand has value of None, then total is None for card in self.cards: if not card.value: return None # add up card values, treat each Ace as 1 total = 0 for card in self.cards: total += card.value # determine if hand contains an Ace contains_ace = False for card in self.cards: if card.value == BJ_Card.ACE_VALUE: contains_ace = True # if hand contains Ace and total is low enough, treat Ace as 11 if contains_ace and total <= 11: # add only 10 since we've already added 1 for the Ace total += 10 return total total = property(get_total) def is_busted(self): return self.total > 21 class BJ_Player(BJ_Hand): """ A Blackjack Player. """ def is_hitting(self): response = games.ask_yes_no("\n" + self.name + ", do you want a hit? (Y/N): ") return response == "y" def bust(self): print self.name, "busts." self.lose() def lose(self): print self.name, "loses." def win(self): print self.name, "wins." def push(self): print self.name, "pushes." class BJ_Dealer(BJ_Hand): """ A Blackjack Dealer. """ def is_hitting(self): return self.total < 17 def bust(self): print self.name, "busts." def flip_first_card(self): first_card = self.cards[0] first_card.flip() class BJ_Game(object): """ A Blackjack Game. """ def __init__(self, names): self.players = [] for name in names: player = BJ_Player(name) self.players.append(player) self.dealer = BJ_Dealer("Dealer") self.deck = BJ_Deck() self.deck.populate() self.deck.shuffle() def get_still_playing(self): remaining = [] for player in self.players: if not player.is_busted(): remaining.append(player) return remaining # list of players still playing (not busted) this round still_playing = property(get_still_playing) def __additional_cards(self, player): while not player.is_busted() and player.is_hitting(): self.deck.deal([player]) print player if player.is_busted(): player.bust() def play(self): # deal initial 2 cards to everyone self.deck.deal(self.players + [self.dealer], per_hand = 2) self.dealer.flip_first_card() # hide dealer's first card for player in self.players: print player print self.dealer # deal additional cards to players for player in self.players: self.__additional_cards(player) self.dealer.flip_first_card() # reveal dealer's first if not self.still_playing: # since all players have busted, just show the dealer's hand print self.dealer else: # deal additional cards to dealer print self.dealer self.__additional_cards(self.dealer) if self.dealer.is_busted(): # everyone still playing wins for player in self.still_playing: player.win() else: # compare each player still playing to dealer for player in self.still_playing: if player.total > self.dealer.total: player.win() elif player.total < self.dealer.total: player.lose() else: player.push() # remove everyone's cards for player in self.players: player.clear() self.dealer.clear() def main(): print "\t\tWelcome to Blackjack!\n" names = [] number = games.ask_number("How many players? (1 - 7): ", low = 1, high = 8) for i in range(number): name = raw_input("Enter player name: ") names.append(name) print game = BJ_Game(names) again = None while again != "n": game.play() again = games.ask_yes_no("\nDo you want to play again?: ") main() raw_input("\n\nPress the enter key to exit.") Since someone decided to call this 'psychic-debugging', I'll go ahead and tell you what the modules are then. Here's the cards module: class Card(object): """ A playing card. """ RANKS = ["A", "2", "3", "4", "5", "6", "7", "8", "9", "10", "J", "Q", "K"] SUITS = ["c", "d", "h", "s"] def __init__(self, rank, suit, face_up = True): self.rank = rank self.suit = suit self.is_face_up = face_up def __str__(self): if self.is_face_up: rep = self.rank + self.suit else: rep = "XX" return rep def flip(self): self.is_face_up = not self.is_face_up class Hand(object): """ A hand of playing cards. """ def init(self): self.cards = [] def __str__(self): if self.cards: rep = "" for card in self.cards: rep += str(card) + "\t" else: rep = "<empty>" return rep def clear(self): self.cards = [] def add(self, card): self.cards.append(card) def give(self, card, other_hand): self.cards.remove(card) other_hand.add(card) class Deck(Hand): """ A deck of playing cards. """ def populate(self): for suit in Card.SUITS: for rank in Card.RANKS: self.add(Card(rank, suit)) def shuffle(self): import random random.shuffle(self.cards) def deal(self, hands, per_hand = 1): for rounds in range(per_hand): for hand in hands: if self.cards: top_card = self.cards[0] self.give(top_card, hand) else: print "Can't continue deal. Out of cards!" if name == "main": print "This is a module with classes for playing cards." raw_input("\n\nPress the enter key to exit.") And here's the games module: class Player(object): """ A player for a game. """ def __init__(self, name, score = 0): self.name = name self.score = score def __str__(self): rep = self.name + ":\t" + str(self.score) return rep def ask_yes_no(question): """Ask a yes or no question.""" response = None while response not in ("y", "n"): response = raw_input(question).lower() return response def ask_number(question, low, high): """Ask for a number within a range.""" response = None while response not in range(low, high): response = int(raw_input(question)) return response if name == "main": print "You ran this module directly (and did not 'import' it)." raw_input("\n\nPress the enter key to exit.")

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  • Country specific SEO

    - by John
    I have a wordpress site which is located at a .com address. The site is a simple 4 page personal site with my academic credentials, publications and a health blog that I started. I have done quite a bit of seo and I rank pretty high for the keywords i want on google.co.uk. However, I do not rank at all on google.com.mt which is the Malta specific search. I have therefore just bought the .com.mt domain and pointed the DNS nameservers to my current host provider and redirected it to the .com address. My goal is to make sure I don't screw up my google.co.uk search ranking, while starting to rank on google.com.mt I'm I doing the right thing or do you have any suggestions??

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  • Services - Separate Sites or One Site - Impact on SEO

    - by Lynda
    I have a client who is a lawyer that specializes in Criminal Defense and DUI, however, he does not show up well in Google. In researching the sites that rank better have much more content for those specialties than his site does and my thought it that he needs to add more quality content to rank better for those searches. On his site he mentions his specialties, but also he has various personal things on his sites that reflect his interest. These are clearly separated from the business portion. My questions are should he 1) separate his personal information into a new domain and 2) should he have a separate URL for each of his specialties? OR would one URL work as long as everything is clearly separated? I read once that for legal services to rank well you should make a separate site for each specialty and have that site focus solely on that service.

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  • Google Places seo?

    - by sam
    Im familiar with seo and getting higher google listings but for allot of services google has recently been making there search results (were applicable) much more location orientated.. for instance searching for a "accountant in london" or "accountancy firm london" will through return the first half of page 1 as google places listings, then under about 6 of these you will get your normal search results so somone who used to rank #1 on page 1 now will rank effectily #7. What i was wandering is that i cant see any reasons as to why the company that rank high in the places results get there, often they are not high up in the search results. Is there a way to optimise on or offsite to rise up the google places listings in your city ?

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  • Problems with Ranking when Using Sourcing Rules And ASLs From Blanket Agreements?

    - by LisaO
    Are you using Sourcing Rules and Approved Supplier List with Blanket Purchase Agreements (BPA) and it seems like Ranking is not working correctly? For example:  The Sourcing Rule being used, has effective dates from 01-APR to 31-MAR for 2013, 2014 and 2015. One BPA is defined for Supplier A, which was originally set to Rank 1 with 100% allocation. A new BPA was created for the same item and with same effective dates as the current BPA. The BPA is for a different Supplier. When Generate Sourcing Rules is run it adds the new BPA/Supplier to the Sourcing rule, but its added as Rank 1, with the old rule changed to Rank 2. For complete information refer to  Doc ID 1678447.1 Generate Sourcing Rules And ASLs From Blanket Agreements Ranking not Behaving As Expected. Still have Questions? Access the Procurement Community and, using the 'Start a Discussion' link, post your question.

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  • create new subdomain or buy new domain? seo costs [closed]

    - by greek_no_money
    If I am targeting the same audience, but the new sub-site has different concept from the existing site, should I create a new sub-domain or create a new domain? What are the seo advantages and disadvantages of creating a new sub-domain? For example Stack Exchange with Alexa rank 1.474 right now, has sub-domains such as programmers.stackexchange.com and other domains such us serverfault.com with rank 3.515 and stackoverflow.com with rank 109. So why didn't Stack Exchange put, for example, Stack Overflow in a sub-domain to create a better ranking?

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  • FullText Search using multiple tables in SQL

    - by Caesar
    Hi there. I have 3 tables, tblBook(BookID, ISBN, Title, Summary) tblAuthor(AuthorID, FullName) tblBookAuthor(BookAuthorID, BookID, AuthorID) tblBookAuthor allows for a single book to have multiple authors and an author may have written any number of books. I am using full text search to search for ranking base on a word: SET @Word = 'FORMSOF(INFLECTIONAL, "' + @Word + '")' SELECT COALESCE(ISBNResults.[KEY], TitleResults.[KEY], SummaryResults.[KEY]) AS [KEY], ISNULL(ISBNResults.Rank, 0) * 3 + ISNULL(TitleResults.Rank, 0) * 2 + ISNULL(SummaryResults.Rank, 0) AS Rank FROM CONTAINSTABLE(tblBook, ISBN, @Word, LANGUAGE 'English') AS ISBNResults FULL OUTER JOIN CONTAINSTABLE(tblBook, Title, @Word, LANGUAGE 'English') AS TitleResults ON ISBNResults.[KEY] = TitleResults.[KEY] FULL OUTER JOIN CONTAINSTABLE(tblBook, Summary, @Word, LANGUAGE 'English') AS SummaryResults ON ISBNResults.[KEY] = SummaryResults.[KEY] The above code works fine for just searching tblBook table. But now I would like to search also the table tblAuthor based on key word searched. Can you help me with this?

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  • Allocation algorithm help, using Python.

    - by Az
    Hi there, I've been working on this general allocation algorithm for students. The pseudocode for it (a Python implementation) is: for a student in a dictionary of students: for student's preference in a set of preferences (ordered from 1 to 10): let temp_project be the first preferred project check if temp_project is available if so, allocate it to them and make the project UNavailable to others Quite simply this will try to allocate projects by starting from their most preferred. The way it works, out of a set of say 100 projects, you list 10 you would want to do. So the 10th project wouldn't be the "least preferred overall" but rather the least preferred in their chosen set, which isn't so bad. Obviously if it can't allocate a project, a student just reverts to the base case which is an allocation of None, with a rank of 11. What I'm doing is calculating the allocation "quality" based on a weighted sum of the ranks. So the lower the numbers (i.e. more highly preferred projects), the better the allocation quality (i.e. more students have highly preferred projects). That's basically what I've currently got. Simple and it works. Now I'm working on this algorithm that tries to minimise the allocation weight locally (this pseudocode is a bit messy, sorry). The only reason this will probably work is because my "search space" as it is, isn't particularly large (just a very general, anecdotal observation, mind you). Since the project is only specific to my Department, we have their own limits imposed. So the number of students can't exceed 100 and the number of preferences won't exceed 10. for student in a dictionary/list/whatever of students: where i = 0 take the (i)st student, (i+1)nd student for their ranks: allocate the projects and set local_weighting to be sum(student_i.alloc_proj_rank, student_i+1.alloc_proj_rank) these are the cases: if local_weighting is 2 (i.e. both ranks are 1): then i += 1 and and continue above if local weighting is = N>2 (i.e. one or more ranks are greater than 1): let temp_local_weighting be N: pick student with lowest rank and then move him to his next rank and pick the other student and reallocate his project after this if temp_local_weighting is < N: then allocate those projects to the students move student with lowest rank to the next rank and reallocate other if temp_local_weighting < previous_temp_allocation: let these be the new allocated projects try moving for the lowest rank and reallocate other else: if this weighting => previous_weighting let these be the allocated projects i += 1 and move on for the rest of the students So, questions: This is sort of a modification of simulated annealing, but any sort of comments on this would be appreciated. How would I keep track of which student is (i) and which student is (i+1) If my overall list of students is 100, then the thing would mess up on (i+1) = 101 since there is none. How can I circumvent that? Any immediate flaws that can be spotted? Extra info: My students dictionary is designed as such: students[student_id] = Student(student_id, student_name, alloc_proj, alloc_proj_rank, preferences) where preferences is in the form of a dictionary such that preferences[rank] = {project_id}

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  • unknown error in shell

    - by lego69
    can somebody explain me what does this error mean: > ./rank lines.in 'nknown option: `- Usage: tcsh [ -bcdefilmnqstvVxX ] [ argument ... ]. this is my script rank: #! /bin/tcsh -f set line = `cat ${1}` echo $line I think that the problem I have is with first row #! /bin/tcsh -f I'm working on Windows! but after I wrote script on windows editor, I converted it using dos2unix rank, what can be the problem, thanks in advance for any help

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  • iPhone: Repeating Rows in Each Section of Grouped UITableview

    - by Rank Beginner
    I'm trying to learn how to use the UITableView in conjunction with a SQLite back end. My issue is that I've gotten the table to populate with the records from the database, however I'm having a problem with the section titles. I am not able to figure out the proper set up for this, and I'm repeating all tasks under each section. The table looks like this. The groups field is where I'm trying to pull the section title from. TaskID groups TaskName sched lastCompleted nextCompleted success 1 Household laundry 3 03/19/2010 03/22/2010 y 1 Automotive Change oil 3 03/20/2010 03/23/2010 y In my viewDidLoad Method, I create an array from each column in the table like below. //Create and initialize arrays from table columns //______________________________________________________________________________________ ids =[[NSMutableArray alloc] init]; tasks =[[NSMutableArray alloc] init]; sched =[[NSMutableArray alloc] init]; lastComplete =[[NSMutableArray alloc] init]; nextComplete =[[NSMutableArray alloc] init]; weight =[[NSMutableArray alloc] init]; success =[[NSMutableArray alloc] init]; group =[[NSMutableArray alloc] init]; // Bind them to the data //______________________________________________________________________________________ NSString *query = [NSString stringWithFormat:@"SELECT * FROM Tasks ORDER BY nextComplete "]; sqlite3_stmt *statement; if (sqlite3_prepare_v2( database, [query UTF8String], -1, &statement, nil) == SQLITE_OK) { while (sqlite3_step(statement) == SQLITE_ROW) { [ids addObject:[NSString stringWithFormat:@"%i",(int*) sqlite3_column_int(statement, 0)]]; [group addObject:[NSString stringWithFormat:@"%s",(char*) sqlite3_column_text(statement, 1)]]; [tasks addObject:[NSString stringWithFormat:@"%s",(char*) sqlite3_column_text(statement, 2)]]; [sched addObject:[NSString stringWithFormat:@"%i",(int*) sqlite3_column_int(statement, 3)]]; [lastComplete addObject:[NSString stringWithFormat:@"%s",(char*) sqlite3_column_text(statement, 4)]]; [nextComplete addObject:[NSString stringWithFormat:@"%s",(char*) sqlite3_column_text(statement, 5)]]; [success addObject:[NSString stringWithFormat:@"%s",(char*) sqlite3_column_text(statement, 6)]]; [weight addObject:[NSString stringWithFormat:@"%i",(int*) sqlite3_column_int(statement, 7)]]; } sqlite3_finalize(statement); } In the table method:cellForRowAtIndexPath, I create controls on the fly and set their text properties to objects in the array. Below is a sample, I can provide more but am already working on a book here... :) /create the task label NSString *tmpMessage; tmpMessage = [NSString stringWithFormat:@"%@ every %@ days, for %@ points",[tasks objectAtIndex:indexPath.row],[sched objectAtIndex:indexPath.row],[weight objectAtIndex:indexPath.row]]; CGRect schedLabelRect = CGRectMake(0, 0, 250, 15); UILabel *lblSched = [[UILabel alloc] initWithFrame:schedLabelRect]; lblSched.textAlignment = UITextAlignmentLeft; lblSched.text = tmpMessage; lblSched.font = [UIFont boldSystemFontOfSize:10]; [cell.contentView addSubview: lblSched]; [lblSched release]; My numberOfSectionsInTableView method looks like this // Figure out how many sections there are by a distinct count of the groups field // The groups are entered by user when creating tasks //______________________________________________________________________________________ NSString *groupquery = [NSString stringWithFormat:@"SELECT COUNT(DISTINCT groups) as Sum FROM Tasks"]; int sum; sqlite3_stmt *statement; if (sqlite3_prepare_v2( database, [groupquery UTF8String], -1, &statement, nil) == SQLITE_OK) { while (sqlite3_step(statement) == SQLITE_ROW) { sum = sqlite3_column_int(statement, 0); } sqlite3_finalize(statement); } if (sum=0) { return 1; } return 2; } I know I'm going wrong here but this is all that's in my numberOfRowsInSection method return [ids count];

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