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  • Call function based off of a string in Lisp

    - by powerj1984
    I am passing in command line arguments to my Lisp program and they are formatted like this when they hit my main function: ("1 1 1" "dot" "2 2 2") I have a dot function and would like to call it directly from the argument, but this isn't possible because something like (funcall (second args)...) receives "dot" and not dot as the function name. I tried variations of this function: (defun remove-quotes (s) (setf (aref s 0) '"")) to no avail, before realizing that the quotes were not really a part of the string. Is there a simple way to do this, or should I just check each string and then call the appropriate function? Thanks!

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  • Return multiple results using dynamic sql (postgresql 8.2)

    - by precose
    I want to loop through schemas and get a result set that looks like this: Count 5 834 345 34 984 However, I can't get it to return anything using dynamic sql...I've tried everything but 8.2 is being a real pain. Here is my function: CREATE OR REPLACE FUNCTION dwh.adam_test4() RETURNS void LANGUAGE plpgsql AS $function$ DECLARE myschema text; rec RECORD; BEGIN FOR myschema IN select distinct c.table_schema, d.p_id from information_schema.tables t inner join information_schema.columns c on (t.table_schema = t.table_schema and t.table_name = c.table_name) join dwh.sgmt_clients d on c.table_schema = lower(d.userid) where c.table_name = 'fact_members' and c.column_name = 'debit_card' and t.table_schema NOT LIKE 'pg_%' and t.table_schema NOT IN ('information_schema', 'ad_delivery', 'dwh', 'users', 'wand', 'ttd') order by table_schema LOOP EXECUTE 'select count(ucic) from '|| myschema || '.' ||'fact_members where debit_card = ''yes''' into rec; RETURN rec; END LOOP; END $function$

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  • How to make a copy of a char and not a reference in C++

    - by Phenom
    If I declare a function like this: string hash (char* key) then any change I make to key will also change it's value when the function exits, correct? I want to make a copy of it in the function so that I can safely change it without changing the original value. I tried this, but it doesn't work. string temp = key; How can it be done?

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  • How to implement XXTEA in MySQL?

    - by user339229
    Anyone knows how to implement XXTEA in MySQL? For example - SELECT xxtea_encrypt('text here', 'key here'); possible implementation is by creating a FUNCTION in MySQL using CREATE FUNCTION statement, e.g. CREATE FUNCTION xxtea_encrypt XXTEA Procedures here... RETURN encrypted string Thanks & Best regards

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  • When using out parameters in a function, is it good practice to initialize them in the function?

    - by adambox
    I have a function that uses out parameters to return multiple values to the caller. I would like to initialize them in the function, but I wasn't sure if that's a bad idea since you don't know when you call the function that it's going to change the values right away. The caller might assume that after the function returns, if whatever it was doing didn't work, the values would be whatever they were initialized to in the caller. Is it ok / good for me to initialize in the function? Example: public static void SomeFunction(int ixID, out string sSomething) { sSomething = ""; sSomething = something(ixID); if (sSomething = "") { somethingelse(); sSomething = "bar" } }

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  • Php inside javascript function

    - by jasminder
    What i am trying to do is inside script tags run javascript inside the php loops. For example: <script> $('#mydiv').mouseover(function(){ time(); function time(){ <?php $secs = 45; $secs--; if($secs <= 25){ ?>//javascript code here } }); </script> My main purpose is when the user mouseover a div, a javascript function runs and inside that javascript function there is php if conitions. If the time is less then 25 then do a specified javascript code. then another condition if the time is less that 10 then do another javascript function.Any type of help will be appreciated. THanks

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  • apply function using expand.grid in R

    - by kolonel
    I have two vectors x and y. I create a grid using the following function: v = expand.grid(x, y) I have a function defined as follows N <- function(a, b , dat){ m = ncol(Filter(function(z) a*max(z)*min(z) < b , dat[1:ncol(dat)])) return(m) } and then I need to maximize N over a grid of x,y: Maximize <- function(x , y ,dat){ v = as.matrix(expand.grid(x,y)) # Here is where I want to map the values of v and get the maximum element and # get the tuple in v that maximized N temp1 <- max(apply(v , 1 , N(v[[1]] , v[[2]] , dat))) } Thanks

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  • Execute the function automatically in 30 seconds, if the button is not pressed

    - by You Kuper
    I want to add the following functionality to my web page: if a user has not pressed the 'Accept' button during 30 seconds, then $('#popupBoxAccept').click( function() {..} is executed automatically. $(document).ready(function() { loadPopupBox(); }); function loadPopupBox() { // to load the Popupbox $('#popup_box').fadeIn("slow"); } $('#popupBoxAccept').click( function() { //... }); $('#popupBoxDecline').click( function() { //... }); <div id="popup_box"> <a id="popupBoxAccept">Accept</a> <a id="popupBoxDecline">Decline</a> </div>

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  • Calling function from an object with event listener

    - by Mirat Can Bayrak
    i have a view model something like this: CANVAS = getElementById... RemixView = function(attrs) { this.model = attrs.model; this.dragging = false; this.init(); }; RemixView.prototype = { init: function() { CANVAS.addEventListener("click", this.handleClick); }, handleClick: function(ev) { var obj = this.getHoveredObject(ev); }, getHoveredObject: function(ev) {} ... ... } rv = new RemixView() the problem is my when clickHandler event fired, this object is being equal to CANVAS object, not RemixView. So i get error that says: this.getHoveredObject is not a function What is correct approach at that stuation?

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  • What does reorder() function do in Joomla?

    - by Parth
    What does reorder() function do in Joomla? I have a statement for a function of menu "copy" in administrator code for menu as: $curr->reorder( 'menutype = '.$this->_db->Quote($curr->menutype).' AND parent = '.(int) $curr->parent ); as i Have executed this code it has reordered my id to any other position.. I just need to know is this reorder() function a inbuilt function of joomla? If yes, WHat and how does it do what he has done it to my ids ? :( I am Newbie to Joomla PLs help EDIT How can i get the the reordered output just after calling the function?

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  • Query "where clause" fails when calling a function

    - by guest1
    Hi All, I have a function in Access VBA that takes four parameters.The fourth parameter is a "where clause" that I use in an SQL statement inside the function. The function fails when I include the fourth parameter (where clause). When I remove this fourth parameter, the function just works fine. I am not sure if there is anything wrong with the syntax of the fourth parameter ? Please help. here is the function as called in the Query FunctionA('Table1','Field1',0.3,'Field2=#' & [Field2] & '# and Value3="' & [Value3] & '"') AS Duration_Field

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  • why Haskell can deduce [] type in this function

    - by Sili
    rho x = map (((flip mod) x).(\a -> a^2-1)) (rho x) This function will generate an infinite list. And I tested in GHCi, the function type is *Main> :t rho rho :: Integral b => b -> [b] If I define a function like this fun x = ((flip mod) x).(\a -> a^2-1) The type is *Main> :t fun fun :: Integral c => c -> c -> c My question is, how can Haskell deduce the function type to b - [b]? We don't have any [] type data in this function. Thanks!

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  • difficulty with deleting a function from jquery snippet

    - by user1691389
    I'm trying to get rid of a function that appends a loading gif while the script is busy ajax'ing in new content, but I keep breaking the script so I'm posting it here hoping someone can just kindly edit it for me correctly. (I'd like to get rid of everything that has to do with #load and keep everything else intact.) $('#header_nav_content_container a, a.scroll_to_top, a.clear_banner, a.desire').not('.exception').click(function(){ var toLoad = $(this).attr('href')+' #content'; $('#content').hide(1555,'easeInOutQuint',loadContent); $('#load').remove(); $('body').append('<span id="load">LOADING...</span>'); $('#load').fadeIn(888); window.location.hash = $(this).attr('href').substr(0,$(this).attr('href').length-0); function loadContent() { $('#content').load(toLoad,'',showNewContent); } function showNewContent() { $('#content').show(777,'',hideLoader); } function hideLoader() { $('#load').fadeOut(888); } return false; }); Thanks for your help.

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  • VBA Solution to VLOOKUP with Hyperlinks

    - by Emily2
    I am looking for some help with a VBA solution for preserving hyperlinks when using VLOOKUP on Excel (2010). I have a load of data on Sheet 1 for internal use only, and a cut-down version of this on Sheet 2. Instead of recreating Sheet 2 everytime, I am looking to have a working version which updates everytime Sheet1 is updated. Thus, I have used VLOOKUP on Sheet 2 so that only the desired info is returned on sheet 2. However, the problem was that sheet 1 contained in many cells Hyperlinks to external websites, and this would not pull through to Sheet2 using VLOOKUP. With some help, however, using the following VBA solution the hyperlinks now pull through: Function GetHyperLink(r As Range) As String If r.Hyperlinks.Count Then GetHyperLink = r.Hyperlinks(1).Address End If End Function And I am using the following formula in the relevant cell(s) in Sheet2: =HYPERLINK(GetHyperLink(INDEX('Sheet 1'!$B$1:$B$10001,MATCH(A4,'Sheet 1'!$A$1:$A$10001,0))),(VLOOKUP(A4,'Sheet 1'!$A$1:$B$10001,2,FALSE))) However, the problem is with formatting: every cell on Sheet2 is formatted blue and underlined, even although some of them do not contain a hyperlink! Is someone able to help with a VBA solution/formula to fix this last piece of the puzzle? Many thanks, in anticipation.

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  • Hibernate without primary keys generated by db?

    - by Michael Jones
    I'm building a data warehouse and want to use InfiniDB as the storage engine. However, it doesn't allow primary keys or foreign key constraints (or any constraints for that matter). Hibernate complains "The database returned no natively generated identity value" when I perform an insert. Each table is relational, and contains a unique integer column that was previously used as the primary key - I want to keep that, but just not have the constraint in the db that the column is the primary key. I'm assuming the problem is that Hibernate expects the db to return a generated key. Is it possible to override this behaviour so I can set the primary key field's value myself and keep Hibernate happy? -- edit -- Two of the mappings are as follows: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Jun 1, 2010 2:49:51 PM by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="com.example.project.Visitor" table="visitor" catalog="orwell"> <id name="id" type="java.lang.Long"> <column name="id" /> <generator class="identity" /> </id> <property name="firstSeen" type="timestamp"> <column name="first_seen" length="19" /> </property> <property name="lastSeen" type="timestamp"> <column name="last_seen" length="19" /> </property> <property name="sessionId" type="string"> <column name="session_id" length="26" unique="true" /> </property> <property name="userId" type="java.lang.Long"> <column name="user_id" /> </property> <set name="visits" inverse="true"> <key> <column name="visitor_id" /> </key> <one-to-many class="com.example.project.Visit" /> </set> </class> </hibernate-mapping> and: <?xml version="1.0"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <!-- Generated Jun 1, 2010 2:49:51 PM by Hibernate Tools 3.2.1.GA --> <hibernate-mapping> <class name="com.example.project.Visit" table="visit" catalog="orwell"> <id name="id" type="java.lang.Long"> <column name="id" /> <generator class="identity" /> </id> <many-to-one name="visitor" class="com.example.project.Visitor" fetch="join" cascade="all"> <column name="visitor_id" /> </many-to-one> <property name="visitId" type="string"> <column name="visit_id" length="20" unique="true" /> </property> <property name="startTime" type="timestamp"> <column name="start_time" length="19" /> </property> <property name="endTime" type="timestamp"> <column name="end_time" length="19" /> </property> <property name="userAgent" type="string"> <column name="user_agent" length="65535" /> </property> <set name="pageViews" inverse="true"> <key> <column name="visit_id" /> </key> <one-to-many class="com.example.project.PageView" /> </set> </class> </hibernate-mapping>

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  • ssh key error - Permission denied (publickey,gssapi-keyex,gssapi-with-mic)

    - by user1963938
    Amazon Ec2 :: Redhat 6. 64 Bit I'm trying to follow the socks5 guidelines (http://www.catonmat.net/blog/linux-socks5-proxy/ ) to open a socks on one of our servers but unfortunately I got suck at step 1 . ssh -N -D 0.0.0.0:1080 localhost I get error Permission denied (publickey,gssapi-keyex,gssapi-with-mic). How do I fix it ? More debug info ssh -v -f -N -D 0.0.0.0:1080 localhost OpenSSH_5.3p1, OpenSSL 1.0.0-fips 29 Mar 2010 debug1: Reading configuration data /etc/ssh/ssh_config debug1: Applying options for * debug1: Connecting to localhost [127.0.0.1] port 22. debug1: Connection established. debug1: permanently_set_uid: 0/0 debug1: identity file /root/.ssh/identity type -1 debug1: identity file /root/.ssh/id_rsa type -1 debug1: identity file /root/.ssh/id_dsa type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3 debug1: match: OpenSSH_5.3 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.3 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'localhost' is known and matches the RSA host key. debug1: Found key in /root/.ssh/known_hosts:1 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey,gssapi-keyex,gssapi-with-mic debug1: Next authentication method: gssapi-keyex debug1: No valid Key exchange context debug1: Next authentication method: gssapi-with-mic debug1: Unspecified GSS failure. Minor code may provide more information Credentials cache file '/tmp/krb5cc_0' not found debug1: Unspecified GSS failure. Minor code may provide more information Credentials cache file '/tmp/krb5cc_0' not found debug1: Unspecified GSS failure. Minor code may provide more information debug1: Unspecified GSS failure. Minor code may provide more information debug1: Next authentication method: publickey debug1: Trying private key: /root/.ssh/identity debug1: Trying private key: /root/.ssh/id_rsa debug1: Trying private key: /root/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey,gssapi-keyex,gssapi-with-mic).

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  • Cannot connect to my EC2 instance because of "Permission denied (publickey)"

    - by Burak
    In AWS console, I saw that my key pair was deleted. I created a new one with the same name. Then I tried to connect with ssh -v -i sohoKey.pem ec2-user@******.compute-1.amazonaws.com Here's the output: macs-MacBook-Air:~ mac$ ssh -v -i sohoKey.pem ec2-user@******.compute-1.amazonaws.com OpenSSH_5.6p1, OpenSSL 0.9.8r 8 Feb 2011 debug1: Reading configuration data /etc/ssh_config debug1: Applying options for * debug1: Connecting to ********.compute-1.amazonaws.com [*****] port 22. debug1: Connection established. debug1: identity file sohoKey.pem type -1 debug1: identity file sohoKey.pem-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3 debug1: match: OpenSSH_5.3 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.6 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host '*******.compute-1.amazonaws.com' is known and matches the RSA host key. debug1: Found key in /Users/mac/.ssh/known_hosts:3 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Offering RSA public key: sohoKey.pem debug1: Authentications that can continue: publickey debug1: Trying private key: sohoKey.pem debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey debug1: No more authentication methods to try. Permission denied (publickey). Update: I detached my old EBS and attached to the new instance. Now, how can I mount it?

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  • ssh-agent on ubuntu rapidly restarts

    - by Santa Claus
    I am attempting to use ssh-agent on Ubuntu 13.10 so that I will not have to enter my passphrase to unlock a key every time I want to use ssh or git. As you can see below, ssh-agent appears to be restarting for some reason. These commends were executed within a period of less than 5 seconds: andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-pqm5J0s70NxG/agent.2820; export SSH_AUTH_SOCK; SSH_AGENT_PID=2821; export SSH_AGENT_PID; echo Agent pid 2821; andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-VpkOH2WKjT1M/agent.2822; export SSH_AUTH_SOCK; SSH_AGENT_PID=2823; export SSH_AGENT_PID; echo Agent pid 2823; andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-EQ6X9JHNiBOO/agent.2824; export SSH_AUTH_SOCK; SSH_AGENT_PID=2825; export SSH_AGENT_PID; echo Agent pid 2825; andrew@zaphod:~$ ssh-agent SSH_AUTH_SOCK=/tmp/ssh-8Iij8kFkaapz/agent.2826; export SSH_AUTH_SOCK; SSH_AGENT_PID=2827; export SSH_AGENT_PID; echo Agent pid 2827; andrew@zaphod:~$ My guess is that ssh-agent is crashing, but how would I know? What log file would it log to?

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  • DKIM passes everywhere apart from Yahoo!

    - by Ian
    Hi, I'm using dkim-milter, Postfix on Ubuntu (I think I used these instructions for setting up). Anyway, using the reflectors such as Port25, BlackOps and Altn.com I get passes for DKIM: X-DKIM: OpenDKIM Filter v2.0.1 medusa.blackops.org o2SGTMSg005616 Authentication-Results: medusa.blackops.org; dkim=pass (1024-bit key) [email protected]; dkim-adsp=pass dkim=pass header.d=example.com (b=miSIxi7TMX; 1:0:good); Authentication-Results: verifier.port25.com header.d=example.com; dkim=pass (matches From: [email protected]); Yahoo gives this: Authentication-Results: mta1031.mail.ukl.yahoo.com from=; domainkeys=neutral (no sig); from=example.com; dkim=permerror (key failed) Where, obviously, example.com is my site address. Is anyone aware of anything different with Yahoo! that would stop these from signing? TIA

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  • ForwardAgent in Jenkins

    - by r_2
    I'm trying to enable ForwardAgent in the "Publish over SSH" Jenkins Plugin. This would allow jenkins to execute deployments, rsyncs and svn+ssh checkouts on remote servers. But there's no option for this in the GUI. ForwardAgent is set to yes in /etc/ssh/ssh_config and in /var/lib/jenkins/.ssh/config, but when Jenkins jobs login over ssh, the remote session does not have the key loaded in agent. ("Could not open a connection to your authentication agent.") Is there a way to force ForwardAgent, or a better way to do this (via a Jenkins slave)? Thanks for any ideas, much appreciated!

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  • How can I get the root account to generate an acceptable ssh key?

    - by Jamie
    On an ubuntu machine I did the following: ~$ sudo su - [sudo] password for jamie: root@mydomain:~# ssh-keygen -t rsa Generating public/private rsa key pair. Enter file in which to save the key (/root/.ssh/id_rsa): Enter passphrase (empty for no passphrase): Enter same passphrase again: Your identification has been saved in /root/.ssh/id_rsa. Your public key has been saved in /root/.ssh/id_rsa.pub. The key fingerprint is: 12:34:56:78:9a:bc:de:f0:12:34:56:78:9a:bc:de:f0 [email protected] The key's randomart image is: +--[ RSA 2048]----+ | | | | | | | | | | | | | | | | | | +-----------------+ root@mydomain:~# cat /root/.ssh/id_rsa.pub | ssh -p 443 [email protected] 'cat > authorized_keys' [email protected]'s password: root@mydomain:~# ssh -p 443 [email protected] [email protected]'s password: It's asking me for a password. However, using a regular account, the following works: $ cd ; ssh-keygen -t rsa ; cat ~/.ssh/id_rsa.pub | ssh [email protected] 'cat >> ~/.ssh/authorized_keys' $ ssh [email protected] Last login: Thu Oct 24 14:48:41 2013 from 173.45.232.105 [[email protected] ~]$ Which leads me to believe it's not an issue of authorized_keys versus authorized_keys2 or permissions. Why does the 'root' account accessing the remote 'jamie' account not work? The remote machine is CentOS if that's relevant.

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  • Unable to login to Amazon EC2 compute server

    - by MasterGaurav
    I am unable to login to the EC2 server. Here's the log of the connection-attempt: $ ssh -v -i ec2-key-incoleg-x002.pem [email protected] OpenSSH_5.6p1, OpenSSL 0.9.8p 16 Nov 2010 debug1: Reading configuration data /home/gvaish/.ssh/config debug1: Applying options for * debug1: Connecting to ec2-50-16-0-207.compute-1.amazonaws.com [50.16.0.207] port 22. debug1: Connection established. debug1: identity file ec2-key-incoleg-x002.pem type -1 debug1: identity file ec2-key-incoleg-x002.pem-cert type -1 debug1: identity file /home/gvaish/.ssh/id_rsa type -1 debug1: identity file /home/gvaish/.ssh/id_rsa-cert type -1 debug1: Remote protocol version 2.0, remote software version OpenSSH_5.3 debug1: match: OpenSSH_5.3 pat OpenSSH* debug1: Enabling compatibility mode for protocol 2.0 debug1: Local version string SSH-2.0-OpenSSH_5.6 debug1: SSH2_MSG_KEXINIT sent debug1: SSH2_MSG_KEXINIT received debug1: kex: server->client aes128-ctr hmac-md5 none debug1: kex: client->server aes128-ctr hmac-md5 none debug1: SSH2_MSG_KEX_DH_GEX_REQUEST(1024<1024<8192) sent debug1: expecting SSH2_MSG_KEX_DH_GEX_GROUP debug1: SSH2_MSG_KEX_DH_GEX_INIT sent debug1: expecting SSH2_MSG_KEX_DH_GEX_REPLY debug1: Host 'ec2-50-16-0-207.compute-1.amazonaws.com' is known and matches the RSA host key. debug1: Found key in /home/gvaish/.ssh/known_hosts:8 debug1: ssh_rsa_verify: signature correct debug1: SSH2_MSG_NEWKEYS sent debug1: expecting SSH2_MSG_NEWKEYS debug1: SSH2_MSG_NEWKEYS received debug1: Roaming not allowed by server debug1: SSH2_MSG_SERVICE_REQUEST sent debug1: SSH2_MSG_SERVICE_ACCEPT received debug1: Authentications that can continue: publickey debug1: Next authentication method: publickey debug1: Trying private key: ec2-key-incoleg-x002.pem debug1: read PEM private key done: type RSA debug1: Authentications that can continue: publickey debug1: Trying private key: /home/gvaish/.ssh/id_rsa debug1: No more authentication methods to try. Permission denied (publickey). What can be the possible reason? How do I fix the issue?

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  • Remap FN to another key

    - by MrValdez
    I got a keyboard (Logitech Wave, pictured below) which I'm very happy with. Unfortunately, the manufacturer has changed the button for right-click for a FN key. Is there any program to remap the FN key to something else?

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  • Validating GPG key signature authenticity

    - by Dor
    I'm trying to validate the integrity of my httpd-2.2.17.tar.gz image. I followed the steps written in the following pages: http://httpd.apache.org/download.cgi#verify http://httpd.apache.org/dev/verification.html#Validating But I got: WARNING: This key is not certified with a trusted signature! gpg: There is no indication that the signature belongs to the owner. What I need to do in order to verify the authenticity of the key?

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  • how to automatically mount ~/Private using ecryptfs when logging in via ssh pubkey

    - by andreash
    Raionale: I want to be able to automatically make backups to a remote machine, which will be encrypted with ecryptfs. The title says it all: I set up ecryptfs-utils on my Debian Squeeze box, and set up one user to use it via ecryptfs-setup-private. When I log in via SSH using password authentication, the ~/Private directory automatically gets mounted. How can I achieve that ~/Private also automatically gets mounted when logging in via SSH using public key authentication? Obviously, the best solution would be if ecryptfs could somehow 'use' the SSH public key to en/decrypt the data (I know that then using the user's password would not be able to en/decrypt the data any more; this would be acceptable). Probably, this will not work. So perhaps somehow call ecryptfs-mount-private via ssh before logging in via public key? Probably, then I would need to somehow pipe the passphrase through the SSH connection, right? So I would need to store it on the source machine's file system. Not nice either. Any other ideas?

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