Search Results

Search found 4640 results on 186 pages for 'unique'.

Page 84/186 | < Previous Page | 80 81 82 83 84 85 86 87 88 89 90 91  | Next Page >

  • Eager/Lazy loaded member always empty with JPA one-to-many relationship

    - by Kaleb Pederson
    I have two entities, a User and Role with a one-to-many relationship from user to role. Here's what the tables look like: mysql> select * from User; +----+-------+----------+ | id | name | password | +----+-------+----------+ | 1 | admin | admin | +----+-------+----------+ 1 row in set (0.00 sec) mysql> select * from Role; +----+----------------------+---------------+----------------+ | id | description | name | summary | +----+----------------------+---------------+----------------+ | 1 | administrator's role | administrator | Administration | | 2 | editor's role | editor | Editing | +----+----------------------+---------------+----------------+ 2 rows in set (0.00 sec) And here's the join table that was created: mysql> select * from User_Role; +---------+----------+ | User_id | roles_id | +---------+----------+ | 1 | 1 | | 1 | 2 | +---------+----------+ 2 rows in set (0.00 sec) And here's the subset of orm.xml that defines the tables and relationships: <entity class="User" name="User"> <table name="User" /> <attributes> <id name="id"> <generated-value strategy="AUTO" /> </id> <basic name="name"> <column name="name" length="100" unique="true" nullable="false"/> </basic> <basic name="password"> <column length="255" nullable="false" /> </basic> <one-to-many name="roles" fetch="EAGER" target-entity="Role" /> </attributes> </entity> <entity class="Role" name="Role"> <table name="Role" /> <attributes> <id name="id"> <generated-value strategy="AUTO"/> </id> <basic name="name"> <column name="name" length="40" unique="true" nullable="false"/> </basic> <basic name="summary"> <column name="summary" length="100" nullable="false"/> </basic> <basic name="description"> <column name="description" length="255"/> </basic> </attributes> </entity> Yet, despite that, when I retrieve the admin user, I get back an empty collection. I'm using Hibernate as my JPA provider and it shows the following debug SQL: select user0_.id as id8_, user0_.name as name8_, user0_.password as password8_ from User user0_ where user0_.name=? limit ? When the one-to-many mapping is lazy loaded, that's the only query that's made. This correctly retrieves the one admin user. I changed the relationship to use eager loading and then the following query is made in addition to the above: select roles0_.User_id as User1_1_, roles0_.roles_id as roles2_1_, role1_.id as id9_0_, role1_.description as descript2_9_0_, role1_.name as name9_0_, role1_.summary as summary9_0_ from User_Role roles0_ left outer join Role role1_ on roles0_.roles_id=role1_.id where roles0_.User_id=? Which results in the following results: +----------+-----------+--------+----------------------+---------------+----------------+ | User1_1_ | roles2_1_ | id9_0_ | descript2_9_0_ | name9_0_ | summary9_0_ | +----------+-----------+--------+----------------------+---------------+----------------+ | 1 | 1 | 1 | administrator's role | administrator | Administration | | 1 | 2 | 2 | editor's role | editor | Editing | +----------+-----------+--------+----------------------+---------------+----------------+ 2 rows in set (0.00 sec) Hibernate obviously knows about the roles, yet getRoles() still returns an empty collection. Hibernate also recognized the relationship sufficiently to put the data in the first place. What problems can cause these symptoms?

    Read the article

  • Fatal error on a non-object

    - by Chris Leah
    Hey, so I have created a function to check the DB for unique entries, but when I call the function it doesn't seem to work and gives me a fatal error any ideas ? Thanks :) //Check for unique entries function checkUnique($table, $field, $compared) { $query = $mysqli->query('SELECT '.$mysqli->real_escape_string($field).' FROM '.$mysqli->real_escape_string($table).' WHERE "'.$mysqli->real_escape_string($field).'" = "'.$mysqli->real_escape_string($compared).'"'); if(!$query){ return TRUE; } else { return FALSE; } } The page calling it..... //Start session session_start(); //Check if the session is already set, if so re-direct to the game if(isset($_SESSION['id'], $_SESSION['logged_in'])){ Header('Location: ../main/index.php'); }; //Require database connection require_once('../global/includes/db.php'); require_once('../global/functions/functions.php'); //Check if the form has been submitted if (isset($_POST['signup'])){ //Validate input if (!empty($_POST['username']) && !empty($_POST['password']) && $_POST['password']==$_POST['password_confirm'] && !empty($_POST['email']) && validateEmail($_POST['email']) == TRUE && checkUnique('users', 'email', $_POST['email']) == TRUE && checkUnique('users', 'username', $_POST['username']) == TRUE) { //Insert user to the database $insert_user = $mysqli->query('INSERT INTO (`username, `password`, `email`, `verification_key`) VALUES ("'.$mysqli->real_escape_string($_POST['username']).'", "'.$mysqli-real_escape_string(md5($_POST['password'])).'", "'.$mysqli->real_escape_string($_POST['email']).'", "'.randomString('alnum', 32). '"') or die($mysqli->error()); //Get user information $getUser = $mysqli->query('SELECT id, username, email, verification_key FROM users WHERE username = "'.$mysqli->real_escape_string($_POST['username']).'"' or die($mysqli->error())); //Check if the $getUser returns true if ($getUser->num_rows == 1) { //Fetch associated fields to this user $row = $getUser->fetch_assoc(); //Set mail() variables $headers = 'From: [email protected]'."\r\n". 'Reply-To: [email protected]'."\r\n". 'X-Mailer: PHP/'.phpversion(); $subject = 'Activate your account (Music Battles.net)'; //Set verification email message $message = 'Dear '.$row['username'].', I would like to welcome you to Music Battles. Although in order to enjoy the gmae you must first activate your account. \n\n Click the following link: http://www.musicbattles.net/home/confirm.php?id='.$row['id'].'key='.$row['verification_key'].'\n Thanks for signing up, enjoy the game! \n Music Battles Team'; //Attempts to send the email if (mail($row['email'], $subject, $message, $headers)) { $msg = '<p class="success">Accound has been created, please go activate it from your email.</p>'; } else { $error = '<p class="error">The account was created but your email was not sent.</p>'; } } else { $error = '<p class="error">Your account was not created.</p>'; } } else { $error = '<p class="error">One or more fields contain non or invalid data.</p>'; } } Erorr.... Fatal error: Call to a member function query() on a non-object in /home/mbattles/public_html/global/functions/functions.php on line 5

    Read the article

  • Vlookup to retrieve an ID from table using text match

    - by Federico Giust
    I've got an excel spreadsheet where I would normally use a VLOOKUP. In this case I need to find the ID of the record when comparing email addresses, so the email address is the unique id here. For example on sheet 1 A B C D Person Id | Family Name | First Name | Email #N/A | Doe | John | [email protected] On Sheet 2 A B C D Person Id | Family Name | First Name | Email 12345 | Doe | John | [email protected] Basically on sheet 1 I've got 800 records, on sheet 2 450. I know the 450 are in Sheet 1, so I need to find the ids of those, and put them on sheet 1 where I've got lots more data for each person. What I've tried so far is a VLOOKUP, but I keep getting an error. I'd like to do it with some sort of formula and not using any copy paste and remove duplicates. Any ideas?

    Read the article

  • Having many subdomains with SSL--best practices?

    - by jnunn
    I have a site that has many subdomains (one for each client). The content for each subdomain will be different, pulling different data, different layouts etc, so I don't think I can just alias one directory to many different sub domains. My question is, what's the best practice for doing this? Each subdomain will need SSL. My setup is Amazon EC2 (ubuntu) Wildcard SSL for my domain (*.mydomain.com) Apache 2 PHP (LAMP) Currently, I'm just creating a new entry into "/etc/hosts" and an appropriate spot in the web root (ie /var/www/abc.mydomain.com, /var/www/def.mydomain.com, etc). I've just discovered that I'll need a unique IP for each subdomain, and that's tricky with EC2 as they limit you to the number you can have (unless you jump through some hoops). Right now I have about 10 subdomains, which is manageable, but theoretically I could have thousands. Am I doing it the only way possible or is there a better way I should investigate?

    Read the article

  • Setting up DNS in WHM/cPanel

    - by Jon Furmanski
    I don't understand what I'm doing wrong, but I'm sure this is a simple fix. I setup WHM/cPanel for the first time on my VPS and understand how DNS works for the most part (or so I thought). I created under the main domain name 2 nameservers (ns1.maindomain.com & ns2.maindomain.com). I have 2 IP address for my sever so each one points to a unique IP: ns1.maindomain.com => 198.x.x.204 ns2.maindomain.com => 198.x.x.205 I also set up reverse DNS with my hosting provider. When I put in my two nameservers under another domain (secondary domain), GoDaddy states that the nameservers are invalid. Any ideas on why this is or any configurations in cPanel that need to be made?

    Read the article

  • Send one invalid email response to sender

    - by Kafuka
    I discovered that my postfix/dovecot configuration isn't rejecting emails. If a person sends an email to an invalid email-address, it just drops it. I am fine with this behavior since I think it discourages spammers from mining emails (I have had some success). Recently a person I did not want to talk to emailed an address I cut off and didn't receive a response back. It would have saved me some problems if they knew to call me instead of sending 50+ emails. How would I configure Dovecot/postfix to send a message back to a sender of an email address and then limit this 1 per domain or unique email. Debian Stable Linux 3.6.5-linode47 Dovecot 1.2.15 Postfix 2.7.1 PSQL - backend if that matters

    Read the article

  • Debian Harddrive Fdisk - Same ID's and changing letters

    - by James Willson
    I am trying to create and install a debain NAS and ive been having a hard time because I am new to all of this. I used ntfs-3g in order to automount my 4 NTFS drives. I also have a partitioned harddrive which is for the OS. When I was working on it and I ran this command I got this: fdisk -l /dev/sdae1 fdisk -l | grep NTFS /dev/sda1 /dev/sdb1 /dev/sdc1 /dev/sdd1 The weird thing is, all of the NTFS harddrives listed had an ID of 7. The next time I boot up my machine, I get an error about mounting /dev/sda1 and I run this command, and get the following results: fdisk -l | grep NTFS /dev/sdb1 /dev/sdc1 /dev/sdd1 /dev/sde1 I havent plugged in any drives, so whats going on? How to I make sure that my drives are mounted with the same sdXX name every time, and is the reason for this because they dont have unique ID numbers, if so, how do I solve this?

    Read the article

  • Debian Harddrive Fdisk - Same ID's and changing letters

    - by James Willson
    I am trying to create and install a debain NAS and ive been having a hard time because I am new to all of this. I used ntfs-3g in order to automount my 4 NTFS drives. I also have a partitioned harddrive which is for the OS. When I was working on it and I ran this command I got this: fdisk -l /dev/sdae1 fdisk -l | grep NTFS /dev/sda1 /dev/sdb1 /dev/sdc1 /dev/sdd1 The weird thing is, all of the NTFS harddrives listed had an ID of 7. The next time I boot up my machine, I get an error about mounting /dev/sda1 and I run this command, and get the following results: fdisk -l | grep NTFS /dev/sdb1 /dev/sdc1 /dev/sdd1 /dev/sde1 I havent plugged in any drives, so whats going on? How to I make sure that my drives are mounted with the same sdXX name every time, and is the reason for this because they dont have unique ID numbers, if so, how do I solve this?

    Read the article

  • setting up an access point from laptop to provide internet

    - by Avo
    i am trying to connect my wireless router as an access point from my laptop. the scenario is as follows: i have a wireless broadband connection at home, which i connect to using a username and a password. this username and password is unique, and can be used by one computer at a time!.. my sister and i can't have internet both at the same time! so im trying to connect my wireless router to my laptop with a physical cable so that i can provide internet via WiFi... first off, is this possible?!.. if not, what are my options? if it is possible, how do i set it up? a link to the appropriate steps would do as well, but i need it :(... thank you in advance, /av

    Read the article

  • Wordpress multisite and redirect

    - by Dr I
    I come to you because I'm facing a really strange effect on my hosting. I currently manage a server contening a NGINX/PHP-CGI and a wordpress multisite in it. My sites are created using subsite.domaine.tld, for now, my three subsites are correctly accessibles through the url: subsite.domain.tld. My goal is to allow my subsite on the host domain to be access through their respective unique domain. For exemple: www.domainA.com would redirect to subsite1.host.domain.tld. If I do that using the following setting on the domainA Public DNS: www 10800 IN CNAME subsite1.host.domain.tld. When I try to access www.domainA.com I don't go to subsite1.host.domain.tld but instead I'm redirect to the Wordpress ROOT site where I create my Network (host.domain.tld). Is there a trick to deal with?

    Read the article

  • What RSS Reader can handle item-updating (JIRA search) feeds?

    - by Stephen
    Thunderbird is a good rss reader in terms of being able to connect successfully to jira authenticated search feeds (where evolution-rss and Liferea can't), but really sucks when it comes to updating. A Jira search feed will give a link id to http://jira/browse/[ticket no], and if that ticket/feed-item is updated, thunderbird refuses to update it - it already has it! (even though the item date does not match). Also, if you delete the ticket update, it will never show up again for that news account. Has anybody found an RSS reader that can work with JIRA/updating RSS items? Note: this is not the same as Jira activity feeds - those work great, as each update has a unique item id To replicate: Grab a search (any search) Get it into your rss reader Read an item, modify the linked ticket Update rss and see if the ticket bumps to most recent and unread or, generically: Get an rss feed (from your hard drive?) Modify an item in the middle changing the content, the date, and moving it to the top Update rss and see if the ticket bumps to most recent and unread

    Read the article

  • Multiple SSL domains on the same IP address and same port?

    - by johnlai2004
    I set up an ubuntu 9.10 - apache2 - php5 server. I was under the impression that each valid SSL certificate (no domain wild cards) required it's own unique IP address and port number combination. But the answer to a previous question I posted is at odds with this claim: http://serverfault.com/questions/109766/ssl-site-not-using-the-correct-ip-in-apache-and-ubuntu Using the accepted answer, I was able to get multiple domains, each with it's own valid SSL to work on the same IP address and on port 443. I am very confused as to why the above answer works, especially after hearing from others that each SSL domain website on the same server requires its own IP+port combination. I am suspicious that I did something wrong. Can someone clear up the confusion? Websites currently using different SSL but on the same IP and Port are: https://www.yummyskin.com/ https://staging.bossystem.org/

    Read the article

  • Help needed with Flash AS2 to AS3 conversion, having major problems...

    - by Mat
    Hi all, I have a project i need to update form AS2 to AS3 as i need some of the new functions available for vertical centering of text. My current AS2 code on the time line is as follows. var dataField = _root.dataField; var dataType = _root.dataType; var dataPage = _root.dataPage; var dataVar = _root.dataVar; _root.mc.onRelease = function() { getURL("index.php?page="+dataPage+"&num="+dataNum+"&"+dataType+"="+dataVar, "_self"); }; And my external AS file is as follows. import mx.transitions.Tween; /** * * StandardKey is attached to a movieclip in the library. * It handles the basic button behavior of the keyboard keys. * When each button is placed on the stage, it's instance name * will be the unique ID of the key. * */ class StandardKey extends MovieClip { /////////////////////////////////////// //Stage Elements var highlight:MovieClip; //End Stage Elements var highlightTween:Tween; function StandardKey(Void) { //Repaint the key with 0 alpha highlight._alpha = 0; } function onPress(Void):Void { //Do the highlight animation highlightTween.stop(); highlightTween = new Tween(highlight, "_alpha", mx.transitions.easing.Regular.easeInOut, 100, 0, 10, false); } } Here is my attempt at moving timeline and external AS2 to AS3 Timeline i now have : var dataField = this.dataField; var dataType = this.dataType; var dataPage = this.dataPage; var dataVar = this.dataVar; var dataNum = this.dataNum; _root.mc.onRelease = function() { navigateToURL(new URLRequest("index.php?page="+dataPage+"&num="+dataNum+"&"+dataType+"="+dataVar, "_self")); }; External AS3 i have package { import fl.transitions.Tween; import fl.transitions.easing.*; import flash.display.MovieClip; /** * * StandardKey is attached to a movieclip in the library. * It handles the basic button behavior of the keyboard keys. * When each button is placed on the stage, it's instance name * will be the unique ID of the key. * */ public class StandardKey extends MovieClip { /////////////////////////////////////// //Stage Elements var highlight:MovieClip; //End Stage Elements var highlightTween:Tween; public function StandardKey(Void) { //Repaint the key with 0 alpha highlight._alpha = 0; } public function onPress(Void):void { //Do the highlight animation highlightTween.stop(); highlightTween = new Tween(highlight, "_alpha", fl.transitions.easing.Regular.easeInOut, 100, 0, 10, false); } } } The errors i am currently getting are : Scene 1, Layer 'Label', Frame 1, Line 6 1120: Access of undefined property _root. Scene 1, Layer 'Label', Frame 1, Line 7 1137: Incorrect number of arguments. Expected no more than 1. If any one could help me work this out i would appreciate it very much. Kind regards Mat.

    Read the article

  • Automatically detect faces in a picture

    - by abel
    At my work place, passport sized photographs are scanned together, then cut up into individual pictures and saved with unique file numbers. Currently we use Paint.net to manually select, cut and save the pictures. I have seen Sony's Cybershot Camera has face detection. Google also gives me something about iphoto when searching for face detection. Picasa has facedetection too. Are there any ways to autodetect the faces in a document, which would improve productivity at my workplace by reducing the time needed to cut up individual images. Sample Scanned Document(A real document has 5 rows of 4 images each=20 pics): (from: http://www.memorykeeperphoto.com/images/passport_photo.jpg, fairuse) For eg. In Picasa 3.8, On clicking View People, all the faces are shown and I am asked to name them, can I save these individual pictures automatically with the names as different pictures.

    Read the article

  • Lookup Active Directory entry by implicit UPN

    - by Michael-O
    In our company exists a forest-wide UPN suffix company.com and almost all user accounts have the explicit UPN set to [email protected]. This value is also set in the Active Directory userPrincipalName attribute. Now we have an application where users perform authentication through Kerberos. So we are given the Kerberos principal, i.e. implicit UPN. We'd like to look up that user and retrieve several LDAP attributes. Since iUPN and userPrincipalName do not match anymore, the lookup is not possible. Is there any "official" way to retrieve a mapping from the Active Direcory? My workaround is to perform a LDAP bind against the realm component and search for the sAMAccountName attribute which matches the user id component of the iUPN. Searching for the mere sAMAccountName in the forest is not possible because the value is unique in the domain only.

    Read the article

  • Varnish: User specific pages

    - by jchong0707
    I'm new to Varnish and am interested in using it to speed up my web application I wanted to know if Varnish can handle caching and serving user specific content. For example if I have a page say for example /welcome which is dynamically generated in the backend and is user specific So if User John Smith shows up to /welcome it'll show in the page itself 'Welcome John Smith' and if Bob Smith shows up to /welcome it'll show 'Welcome Bob Smith' Ideally both of those /welcome pages will be cached for each unique User, is this something Varnish can do? (is this even a good Use Case of Varnish?) Thanks!

    Read the article

  • How to populate the span tags for all text nodes between specific self closing tags.

    - by Rachel
    I want to populate span tags for all text nodes between the self closing tags s1 and s2 having the same id. Eg. For the input: <a> <b>Some <s1 id="1" />text here</b> <c>Some <s2 id="1"/>more text <s1 id="2"/> here<c/> <d>More data</d> <e>Some <s2 id="2" />more data</e> </a> In the above input i want to enclose every text node between <s1 id="1"/> and <s2 id="1" /> with span tags. Also all the text node between <s1 id="2" /> and <s2 id="2" /> Expected Output: <a> <b>Some <span class="spanClass" id="1a">text here</span></b> <c><span class="spanClass" id="1b">Some </span>more text <span class="spanClass" id="2a"> here</span></c> <d><span class="spanClass" id="2b">More data</span></d> <e><span class="spanClass" id="2c">Some </span>more data</e> </a> I am not concened about the pattern of the id tag populated for the span as along it is unique. If the transformation of the input to the output form requires the list of ids of the s1 , s2 tag pairs say 1, 2 etc i can assume that it in place in any form if required. Hope i am clear. How can this be achieved using XSL? EDIT: The input can have any structure and not exactly the same as seen in the sample input. It can have any number of s1, s2 tag pairs but each pair will have a unique id.Adding another sample input and output pattern for more information. Input: <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>This is my title</title> </head> <body> <h1 align="center">This <s1 id="1" />is my <s2 id="1" />heading</h1> <p> Sample content <s1 id="2" />Some text here. Some content here. </p> <p> Here you <s2 id="2" />go. </p> </body> </html> Desired output: <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>This is my title</title> </head> <body> <h1 align="center">This <span id="1">is my </span>heading</h1> <p> Sample content <span id="2">Some text here. Some content here.</span> </p> <p> <span id="2">Here you </span>go. </p> </body> </html>

    Read the article

  • How do I code this relationship in SQLAlchemy?

    - by Martin Del Vecchio
    I am new to SQLAlchemy (and SQL, for that matter). I can't figure out how to code the idea I have in my head. I am creating a database of performance-test results. A test run consists of a test type and a number (this is class TestRun below) A test suite consists the version string of the software being tested, and one or more TestRun objects (this is class TestSuite below). A test version consists of all test suites with the given version name. Here is my code, as simple as I can make it: from sqlalchemy import * from sqlalchemy.ext.declarative import declarative_base from sqlalchemy.orm import relationship, backref, sessionmaker Base = declarative_base() class TestVersion (Base): __tablename__ = 'versions' id = Column (Integer, primary_key=True) version_name = Column (String) def __init__ (self, version_name): self.version_name = version_name class TestRun (Base): __tablename__ = 'runs' id = Column (Integer, primary_key=True) suite_directory = Column (String, ForeignKey ('suites.directory')) suite = relationship ('TestSuite', backref=backref ('runs', order_by=id)) test_type = Column (String) rate = Column (Integer) def __init__ (self, test_type, rate): self.test_type = test_type self.rate = rate class TestSuite (Base): __tablename__ = 'suites' directory = Column (String, primary_key=True) version_id = Column (Integer, ForeignKey ('versions.id')) version_ref = relationship ('TestVersion', backref=backref ('suites', order_by=directory)) version_name = Column (String) def __init__ (self, directory, version_name): self.directory = directory self.version_name = version_name # Create a v1.0 suite suite1 = TestSuite ('dir1', 'v1.0') suite1.runs.append (TestRun ('test1', 100)) suite1.runs.append (TestRun ('test2', 200)) # Create a another v1.0 suite suite2 = TestSuite ('dir2', 'v1.0') suite2.runs.append (TestRun ('test1', 101)) suite2.runs.append (TestRun ('test2', 201)) # Create another suite suite3 = TestSuite ('dir3', 'v2.0') suite3.runs.append (TestRun ('test1', 102)) suite3.runs.append (TestRun ('test2', 202)) # Create the in-memory database engine = create_engine ('sqlite://') Session = sessionmaker (bind=engine) session = Session() Base.metadata.create_all (engine) # Add the suites in version1 = TestVersion (suite1.version_name) version1.suites.append (suite1) session.add (suite1) version2 = TestVersion (suite2.version_name) version2.suites.append (suite2) session.add (suite2) version3 = TestVersion (suite3.version_name) version3.suites.append (suite3) session.add (suite3) session.commit() # Query the suites for suite in session.query (TestSuite).order_by (TestSuite.directory): print "\nSuite directory %s, version %s has %d test runs:" % (suite.directory, suite.version_name, len (suite.runs)) for run in suite.runs: print " Test '%s', result %d" % (run.test_type, run.rate) # Query the versions for version in session.query (TestVersion).order_by (TestVersion.version_name): print "\nVersion %s has %d test suites:" % (version.version_name, len (version.suites)) for suite in version.suites: print " Suite directory %s, version %s has %d test runs:" % (suite.directory, suite.version_name, len (suite.runs)) for run in suite.runs: print " Test '%s', result %d" % (run.test_type, run.rate) The output of this program: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 Version v1.0 has 1 test suites: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Version v1.0 has 1 test suites: Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Version v2.0 has 1 test suites: Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 This is not correct, since there are two TestVersion objects with the name 'v1.0'. I hacked my way around this by adding a private list of TestVersion objects, and a function to find a matching one: versions = [] def find_or_create_version (version_name): # Find existing for version in versions: if version.version_name == version_name: return (version) # Create new version = TestVersion (version_name) versions.append (version) return (version) Then I modified my code that adds the records to use it: # Add the suites in version1 = find_or_create_version (suite1.version_name) version1.suites.append (suite1) session.add (suite1) version2 = find_or_create_version (suite2.version_name) version2.suites.append (suite2) session.add (suite2) version3 = find_or_create_version (suite3.version_name) version3.suites.append (suite3) session.add (suite3) Now the output is what I want: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 Version v1.0 has 2 test suites: Suite directory dir1, version v1.0 has 2 test runs: Test 'test1', result 100 Test 'test2', result 200 Suite directory dir2, version v1.0 has 2 test runs: Test 'test1', result 101 Test 'test2', result 201 Version v2.0 has 1 test suites: Suite directory dir3, version v2.0 has 2 test runs: Test 'test1', result 102 Test 'test2', result 202 This feels wrong to me; it doesn't feel right that I am manually keeping track of the unique version names, and manually adding the suites to the appropriate TestVersion objects. Is this code even close to being correct? And what happens when I'm not building the entire database from scratch, as in this example. If the database already exists, do I have to query the database's TestVersion table to discover the unique version names? Thanks in advance. I know this is a lot of code to wade through, and I appreciate the help.

    Read the article

  • Options for PCI-DSS on AWS - file integrity monitoring and intrusion detection

    - by Brill Pappin
    I need to deploy some file integrity monitoring and intrusion detections software on AWS instances. I really wanted to use OSSEC, however it does not work well in an environment where servers can auto deploy and shut down based on load, because it requires server managed keys to be generated. Including the agent in the AMI will not allow monitoring as soon as it comes up because of that. There are many options out there, and several are listed in other posts on this site, however none that I've seen so far deal with the unique problems inherent in AWS or cloud based deployments in general. Can anyone point me at some products, preferably open source, that we might use to cover those portions of PCI DSS that require this software? Has anyone else achieved this on AWS?

    Read the article

  • Mysql optimization question - How to apply AND logic in search and limit on results in one query?

    - by sandeepan-nath
    This is a little long but I have provided all the database structures and queries so that you can run it immediately and help me. Run the following queries:- CREATE TABLE IF NOT EXISTS `Tutor_Details` ( `id_tutor` int(10) NOT NULL auto_increment, `firstname` varchar(100) NOT NULL default '', `surname` varchar(155) NOT NULL default '', PRIMARY KEY (`id_tutor`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=41 ; INSERT INTO `Tutor_Details` (`id_tutor`,`firstname`, `surname`) VALUES (1, 'Sandeepan', 'Nath'), (2, 'Bob', 'Cratchit'); CREATE TABLE IF NOT EXISTS `Classes` ( `id_class` int(10) unsigned NOT NULL auto_increment, `id_tutor` int(10) unsigned NOT NULL default '0', `class_name` varchar(255) default NULL, PRIMARY KEY (`id_class`) ) ENGINE=InnoDB DEFAULT CHARSET=utf8 AUTO_INCREMENT=229 ; INSERT INTO `Classes` (`id_class`,`class_name`, `id_tutor`) VALUES (1, 'My Class', 1), (2, 'Sandeepan Class', 2); CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=18 ; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (1, 'Bob'), (6, 'Class'), (2, 'Cratchit'), (4, 'Nath'), (3, 'Sandeepan'), (5, 'My'); CREATE TABLE IF NOT EXISTS `Tutors_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) default NULL, KEY `Tutors_Tag_Relations` (`id_tag`), KEY `id_tutor` (`id_tutor`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tutors_Tag_Relations` (`id_tag`, `id_tutor`) VALUES (3, 1), (4, 1), (1, 2), (2, 2); CREATE TABLE IF NOT EXISTS `Class_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_class` int(10) default NULL, `id_tutor` int(10) NOT NULL, KEY `Class_Tag_Relations` (`id_tag`), KEY `id_class` (`id_class`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Class_Tag_Relations` (`id_tag`, `id_class`, `id_tutor`) VALUES (5, 1, 1), (6, 1, 1), (3, 2, 2), (6, 2, 2); Following is about the tables:- There are tutors who create classes. Tutor_Details - Stores tutors Classes - Stores classes created by tutors And for searching we are using a tags based approach. All the keywords are stored in tags table (while classes/tutors are created) and tag relations are entered in Tutor_Tag_Relations and Class_Tag_Relations tables (for tutors and classes respectively)like this:- Tags - id_tag tag (this is a a unique field) Tutors_Tag_Relations - Stores tag relations while the tutors are created. Class_Tag_Relations - Stores tag relations while any tutor creates a class In the present data in database, tutor "Sandeepan Nath" has has created class "My Class" and "Bob Cratchit" has created "Sandeepan Class". 3.Requirement The requirement is to return tutor records from Tutor_Details table such that all the search terms (AND logic) are present in the union of these two sets - 1. Tutor_Details table 2. classes created by a tutor in Classes table) Example search and expected results:- Search Term Result "Sandeepan Class" Tutor Sandeepan Nath's record from Tutor Details table "Class" Both the tutors from ... Most importantly, there should be only one mysql query and a LIMIT applicable on the number of results. Following is a working query which I have so far written (It just applies OR logic of search key words instead of the desired AND logic). SELECT td . * FROM Tutor_Details AS td LEFT JOIN Tutors_Tag_Relations AS ttagrels ON td.id_tutor = ttagrels.id_tutor LEFT JOIN Classes AS wc ON td.id_tutor = wc.id_tutor INNER JOIN Class_Tag_Relations AS wtagrels ON td.id_tutor = wtagrels.id_tutor LEFT JOIN Tags AS t ON t.id_tag = ttagrels.id_tag OR t.id_tag = wtagrels.id_tag WHERE t.tag LIKE '%Sandeepan%' OR t.tag LIKE '%Nath%' GROUP BY td.id_tutor LIMIT 20 Please help me with anything you can. Thanks

    Read the article

  • can't add sharepoint users from trusted domain

    - by user22215
    I have a very strange problem with our Sharepoint 2007 implementation. I went in today to grant access to a user and was greeted with "The user does not exist or is not unique." Let me start off by saying that this user is not on our domain we have a 2 way trust connecting to one of our subsidiaries. I can see the users in the people pick but can't add them into Sharepoint. This problem flared up after we had some trust issues last two days ago. So I must ask has anyone came across this error and if so what steps did you take to resolve it? This link further highlights my problem: http://social.technet.microsoft.com/forums/en-US/sharepointgeneral/thread/41265a91-191c-4952-9c8c-1e0129b9fd3a

    Read the article

  • Recursive Batch File

    - by MCZ
    I have a file that looks this: head1,head2,head3,head4,head5,head6 a11,a12,keyA,a14,a15,a16 a21,a22,keyB,a24,a25 a31,a32,keyC,a34 a41,a42,keyB,a44,a44 a51,a52,keyA,a54,a55,a56 a61,a62,keyA,a64,a65,a66 a71,a72,keyC,a74 some message Objective: Write list of unique keys to a text file. For example, the result for the file described above should be: keyA, keyB, keyC Here's the pseudocode I would like to implement in batch file recur.bat Read second line of inputfile If no key exist on second line, return else continue Append keyX to list FINDSTR /v keyX inputfile Pipe results to recur.bat I don't know if this is the most efficient way to do this without using actual programming language. Any suggestions for actual batch file code?

    Read the article

  • How can I set up VLANs in a way that won't put me at risk for VLAN hopping?

    - by hobodave
    We're planning to migrate our production network from a VLAN-less configuration to a tagged VLAN (802.1q) configuration. This diagram summarizes the planned configuration: One significant detail is that a large portion of these hosts will actually be VMs on a single bare-metal machine. In fact, the only physical machines will be DB01, DB02, the firewalls and the switches. All other machines will be virtualized on a single host. One concern that has been is that this approach is complicated (overcomplicated implied), and that the VLANs are only providing an illusion of security, because "VLAN hopping is easy". Is this a valid concern, given that multiple VLANs will be used for a single physical switch port due to virtualization? How would I setup my VLANs appropriately to prevent this risk? Also, I've heard that VMWare ESX has something called "virtual switches". Is this unique to the VMWare hypervisor? If not, is it available with KVM (my planned hypervisor of choice)?. How does that come into play?

    Read the article

  • How should I implement an email circuit test?

    - by lukecyca
    I want a high-level test that ensures that both incoming and outgoing email services are operating normally. I've achieved this by writing a python script which does this: Send a message with a unique hash through my mail server to [email protected] The gmail account is configured to auto-reply back to the same address and then delete the message. My script polls IMAP until it finds an email with the correct hash sitting in its inbox, or times out. It reports the elapsed time to my monitoring software (Zabbix) My question: Is gmail the best third-party to use? Should I add a couple others as well such as hotmail and yahoo? Is there anyone more official that will auto-reply to these sorts of "mail pings"? Any other recommendations for this type of test?

    Read the article

  • How to determine if a file has been backed up?

    - by Console
    I try to consolidate old drives to new ones of larger capacity. Sometimes files have been renamed, but are otherwise identical. Sometimes an old directory has just a few more files in it than a newer directory with the same name. Sometimes a file has the same name but the size differs. So I often find myself asking the question: Are there any files on this old drive or directory that I haven't already copied to the new drive? I just want to know that I have the files, I don't want to try and sync stuff automatically (Syncing tools tend to just sync, creating duplicate folder structures and other problems, so I prefer to do it by hand). Basically, if an old drive has a file called "foo.bar" ten directories deep, and my new big drive has an identical file called "oldstuff.zip" in the root, I just want a "yes you have it" or "no, unique files exist". Is there a free tool, a script or a quick and easy method (Mac/Unix or Windows) to get the answer?

    Read the article

< Previous Page | 80 81 82 83 84 85 86 87 88 89 90 91  | Next Page >