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  • phpDocumentor to wiki?

    - by Mike
    My company is working on end user/developer docs using mediawiki. I'd like to take a lot of the API docs that phpdoc spit out (for specific functions/methods) and have it in wiki markup for easy transfer. Any solutions out there for getting wiki markup or wiki output from phpDoc? I've looked around and found nothing.

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  • TV Guide script - getting current date programmes to show

    - by whitstone86
    This is part of my TV guide script: //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, episode, airdate, expiration, setreminder FROM mediumonair where airdate >= now()"); The episodes show up, so there are no issues there. However, it's getting the database to find data that's the issue. If I add a record for a programme that airs today this should show: Medium showing on TV4 8:30pm "Episode" Set Reminder Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder but this shows instead: Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder I almost have the SQL working; just not sure what the right code is here, to avoid the second mistake showing - as the record (which indicates a show currently airing) does not seem to work at present. Please can anyone help me with this? Thanks

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  • lightbox dynamic image retrieval

    - by GSTAR
    I am constructing a lighbox gallery, currently experimenting with FancyBox (http://fancybox.net) and ColorBox (http://colorpowered.com/colorbox). By default you have to include a link to the large version of the image so that the Lightbox can display it. However, I am wanting to have the image link URLs pointing to a script rather than directly to the image file. So for example, instead of: <a href="mysite/images/myimage.jpg"> I want to do: <a href="mysite/photos/view/abc123"> The above URL points to a function: public function actionPhotos($view) { $photo=Photo::model()->find('name=:name', array(':name'=>$view)); if(!empty($photo)) { $user=$photo->user; $this->renderPartial('_photo', array('user'=>$user, 'photo'=>$photo, true)); } } At some point in the future the function will also update the view count of the image. Now this approach is working to an extent - most images load up but some do not load up (the lightbox gets displayed in a malformed state). I think the reason for this is because it is not processing the function quick enough. For example when I click the "next" button it needs to go to the URL, process the function and retreive/output the response. Does anybody know how I can get this working properly?

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  • All numbers that are NOT in an array under 1000

    - by baklap
    Hi, I've got this programming problem. I have number for example 1000. Now I have a number in an array, like 999. Now I need to display all numbers that are NOT in the array but are 1 to 1000; The next requirement is essential: It has to be displayed in a way that it's easy to oversee. So I was thinking, lets show: 100 200 300 400 500 600 700 800 900 910 920 930 940 950 960 970 980 990 991 992 993 994 995 996 997 998 1000 What is the best way to start programming this?

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  • Username correct, password incorrect?

    - by jonnnnnnnnnie
    In a login system, how can you tell if the user has entered the password incorrectly? Do you perform two SQL queries, one to find the username, and then one to find the username and matching (salted+hashed etc) password? I'm asking this because If the user entered the password incorrectly, I want to update the failed_login_attempts column I have. If you perform two queries wouldn't that increase overhead? If you did a query like this, how would you tell if the password entered was correct or not, or whether the username doesn't exist: SELECT * FROM author WHERE username = '$username' AND password = '$password' LIMIT 1 ( ^ NB: I'm keeping it simple, will use hash and salt, and will sanitize input in real one.) Something like this: $user = perform_Query() // get username and password? if ($user['username'] == $username && $user['password'] == $password) { return $user; } elseif($user['username'] == $username && $user['password'] !== $password) { // here the password doesn't match // update failed_login_attemps += 1 }

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  • How to find intersect rows when condition depend on some columns in one table

    - by user3695637
    Table subscribe subscriber | subscribeto (columns) 1 | 5 1 | 6 1 | 7 1 | 8 1 | 9 1 | 10 2 | 5 2 | 6 2 | 7 There are two users that have id 1 and 2. They subscribe to various user and I inserted these data to table subscribe. Column subscriber indicates who is subscriber and column subscribeto indicates who they've subscribe to. From the above table can conclude that; user id=1 subscribed to 6 users user id=2 subscribed to 3 users I want to find manual of subscription (like Facebook is manual friends) user 1 subscribe to user 5,6,7,8,9,10 user 2 subscribe to user 5,6,7 So, Manual subscription of user 1 and 2 are: 5,6,7 And I'm trying to create SQL statement.. I give you user table for my SQL statement and I think we can use only subscribe table but I can't figure out. Table user userid (columns) 1 2 3 ... ... SQL "select * from user where (select count( 1 ) from subscribe where subscriber = '1' and subscribeto = user.userid) and (select count( 1 ) from subscribe where subscriber = '2' and subscribeto = user.userid);" This SQL can work correctly, but it very slow for thousands of columns. Please provide better SQL for me, Thanks.

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  • how to change picture using drop down list ?

    - by garcon1986
    Hello, I want to use a drop down list, every time i click the content in it, different pictures will show up. But i don't want to use the property 'value', because i want to use the values for other use. Example: <select name='test'> <option value='1'>1</option> <option value='2'>2</option> <option value='3'>3</option> <option value='4'>4</option> </select> How do i accomplish that? Thanks.

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  • How can I get the count of orders placed from my database?

    - by user1360564
    I am preparing a chart which will display the number of orders placed for a particular day in the current month and year. I wanted the count of orders placed for each day. I am showing the count of orders on the y-axis and the day on the x-axis. In my database, there is table called "order" in which order data is placed: order date, user_id, order_price, etc. For example, if on 4 July, 10 orders are placed, on 5 july, 20 orders are placed, and so on. How can I get the count of orders placed for day of the current month?

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  • Generating a zend form with dynamic data?

    - by meder
    I need to access my session and based on the session property I need to grab stuff from the database to use as options in my dropdown. $_SESSION is: [sess_name] => Array( [properties] => Array( 1=> Hotel A, 2=> Hotel B ), [selected] => 1 ) I need to grab Hotel A from selected, and then access all accounts under Hotel A from the database: id title hotel_id ------------------------------ 1 Hotel A Twitter Account 1 2 Hotel B Facebook Account 2 3 Hotel A Facebook Account 1 I need ids 1 and 3 because my hotel_id is 1 in the context of: $this->addElement( 'select', 'account', array( 'multioptions' => $NEED_IT_HERE )); Here's my query / session grabbing code: $cs = new Zend_Session_Namespace( SESS_NAME ); $model = new Model_DbTable_Social; $s = " SELECT social_accounts.* FROM social_accounts LEFT JOIN social_media_outlets ON social_media_outlets.id = social_accounts.property WHERE social_accounts.property=".(int)$cs->selectedclient; I have this code in my form page, but I need to move it into my model now.

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  • Why my mysql DISTINCT doesn't work ?

    - by belaz
    Hello, Why the two query below return duplicate member_id and not the third ? i need the second query to work with distinct. Anytime i run a GROUP BY, this query is incredibly slow and the resultset doesn't return the same value as distinct (the value is wrong). SELECT member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+ | member_id | +-----------+ | 11333 | | 141831 | | 12013 | | 60821 | | 64980 | +-----------+ my table sample CREATE TABLE `table1` ( `id` int(11) NOT NULL AUTO_INCREMENT, `member_id` int(11) NOT NULL, `s_type_id` int(11) NOT NULL, `created_at` datetime DEFAULT NULL, PRIMARY KEY (`id`), KEY `s_FI_1` (`member_id`), KEY `s_FI_2` (`s_type_id`) ) ENGINE=InnoDB AUTO_INCREMENT=313096 DEFAULT CHARSET=utf8;

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  • update entire table with pdo

    - by MephDaddy
    I am working on a simple gaming ladder script. I am having little to no luck trying to find an effective way to reset my ladder information while leaving my table id and name fields intact. I am trying to get create a loop to update my entire table, similar to the way I draw my table. Shown below. ...... //Start displaying ladder with with team with most wins at the top echo "<TABLE border=1 width=500 align=center><TR>"; foreach($db->query('SELECT * FROM test ORDER BY win DESC , name ASC') as $row) { echo "<TR><TD>" . $row['name'] . "</TD><TD>" . $row['win'] . "</TD><TD>"; echo $row['loss'] . "</TD><TD>" . $row['battles'] . "</TD><TD>"; echo $row['score'] . "</TD></TR>"; } ...... I currently have a table with 6 fields(id,name,win,loss,battles,score). I want to reset the values of win,loss,battles, and score back to 0. While leaving id and name alone. Effective reseting my ladder for a new season to begin. The only way I have been able to complete this is to find out how many rows there are and run a for loop. It seems vary inefficient. Was hoping I could get some better insight as to how to go about this.

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  • Match a word with similar words using Solr?

    - by fayer
    I want to search for threads in my mysql database with Solr. But i want it to not just search the thread words, but for similar words. Eg. if a thread title is "dog for sale" and if the user searches for dogs the title will be in the result. and also if a user searches for "mac os x" the word "snow leopard" will appear. and the ability to link words the application thinks is related eg. house and apartment. how is this kind of logic done? i know that you can with solr look up words in a dictionary file you create/add, so solr will look for dogs and see what related words there are (eg. dog). but where do you find such a dictionary? i have no idea about this kind of implementation. please point me into right direction. thanks

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  • regular expression for validation not working

    - by Camran
    I have a "description textarea" inside a form where user may enter a description for an item. This is validated with javascript before the form beeing submitted. One of the validation-steps is this: else if (!fld.value.match(desExp)){ And desExp: var desExp = /^\s*(\w[^\w]*){3}.*$/gm; Now my problem, this works fine on all cases except for descriptions where the description BEGINS with a special character of the swedish language (å, ä, ö). This wont work: åäö hello world But this will: hello world åäö Any fixes? Thanks

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  • keeping single-quotes in http_build_query()?

    - by user151841
    I'm wanting to use http_build_query to change an array to html tag properties. Problem is, it's changing my single-quoted values into %27. So if I have http_build_query( array("type"=>"'hidden'", ... ), '', ' ' ); I get <input type=%27hidden%27 ...> How can I get around this?

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  • how to verify that an old session is really destroyed?

    - by jodeci
    Um, this might sound a bit weird. We were having some problems with a specific browser under a very specific condition, and finally narrowed down the problem to the fact that we were not properly destroying the old sessions after doing session_regenerate_id(). I believe I have solved this problem by doing session_regenerate_id(true) now, but how does one verify that the previous sessions really do not exist any more? Someone suggested cURL but I cannot find my way around their docs. Sadly(?) the boss does not take 'it just works' for an answer so I'd really appreciate any advice!

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  • Force memcached to write to all servers in pool

    - by Industrial
    Hi everyone, I have thought a bit on how to make sure that a particular key is distributed to ALL memcached servers in a pool. My current, untested solution is to make another instance of memcached, something like this: $cluster['local'] = array('host' => '192.168.1.1', 'port' => '11211', 'weight' => 50); foreach ($this->cluster() as $cluster) { @$this->tempMemcache = new Memcache; @$this->tempMemcache->connect($cluster['host'], $cluster['port']); @$this->tempMemcache->set($key, $value, $this->compress, $expireTime); @$this->tempMemcache->close(); } What is common sense to do in this case, when certain keys need to be stored on ALL servers for reliability?

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  • MVC Model architecture

    - by ATT
    I'm getting into CodeIgniter and trying to figure out the good architecture for my models. What kind of models would you create for the following simple example: list page of blog entries: shows part of the entry data, number of comments blog entry page: shows all the entry data, comment list (with part of the comment data) comment page: shows all the comment data I'm trying to get this right so that it's simple and effective. I don't want to load too much information (from the db) on the pages where I don't need them. E.g. should the same entry model handle both multiple entries as well as a single entry? And how should the comments be loaded? I only need the number of comments on the multiple entries (list) page but some of the comment data on the single entry page. How would you handle this?

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  • assigning values to variables within foreach loop

    - by Patrick
    Im working on a script to tear into a csv file and ive got the rows separated, but im not sure how to assign variables to the fields within the row, so that i can perform functions with them. my code: <? ini_set('auto_detect_line_endings', true); $csvraw = file_get_contents("file.csv"); $csv = explode("\n", $csvraw); $i=0; foreach($csv AS $key=>$value){ $rowsplit = explode(",", $value); // This is where i get my headers if($i == 0){ $col0 = $rowsplit[0]; $col1 = $rowsplit[1]; $col2 = $rowsplit[2]; $col3 = $rowsplit[3]; $col4 = $rowsplit[4]; $col5 = $rowsplit[5]; $col6 = $rowsplit[6]; $col7 = $rowsplit[7]; } $i++; //This is where i loop through each row's fields foreach($rowsplit AS $key2=>$value2){ if(empty($value2)){ echo ""; }else{ echo "$value2 <br>"; } // This is where i need to assign $variable0 through $variable7 so i can perform a function with the field values. } echo "<br><br><br>"; } ?>

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  • Am I underestimating MySQL ?

    - by user281434
    Hi I'm about to implement a feature on my website that recommends content to users based on the content they already have in their library (a la Last.fm). A single table holds all the records of the content they have added, so a row might look something like: -------------------- | userid | content | -------------------- | 28 | a | -------------------- When I want to recommend some content for a user, I use a query to get all the user id's that have content a added in their library. Then, out of those user id's, I make another query that finds the next most common content among those users (fx. 'b'), and show that to the user. My problem is when I'm thinking about the big picture here. Say that eventually my site will hold something like 500.000 rows in the table, will this make the MySQL response very slow or am I underestimating MySQL here?

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