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  • How can i Update /Get values in windows form while moving one form to other form(like cookies)?

    - by Jeyavel
    Hi, How can i Update /Get values in windows form while moving one form to other form(like cookies)? i need to update the values to some variable and again i am going to refer stored values and need to do some calculations. i have used Cookies in ASP.Net but i am not able to find out same concept in C#.net Windows forms . can any one help me for resolve this issues? Regards, Jeyavel N

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  • Want to build simple SQL admin interface to change a few values in a table.

    - by Adam McC
    i am currently building a system in MSSQL 2K5. i have a table that holds information about certain insurance schemes such as overheads and other things. these values will change occasionally and currently i administer the database straight through the management Studio. i would like to build a simple interface that will allow my colleagues to change these values by selecting the company in a dropdown and the current values will populate. they can then edit these values and submit them to the database. is this possible in the current Visual Studio supplied with MSSQL server 2K5 or do i need to get another product. i am confident that with the help of stack overflow and google i can build this myself, but i need pointed in the right direction as to which environment would be easiest and best to start building it. Many thanks, adam

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  • what is the difference between latitude, longitude and their delat values.

    - by Mas
    Hi! I'm new to the MKMapView (iPhone). I want to add several annotations to the map of Copenhagen (Denmark). I have the latitude and longitude values of different locations of the city. But I don't know how to get the longitudeDelta and latitudeDelta of these locations. I'm using the Google Map API's to calculate the latitude and longitude values (By web services) of each location in the city map. I need help on how to calculate delta values Thanks

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  • Getting all selected checkboxes values using ajax and jsp/servlets?

    - by A.S al-shammari
    Hi.. I'm developing a jsp/serlvet application. I have a page with a list of inputs as checkboxes . I want to send values of selected buttons to a servlet using ajax/jquery. In the servlet , I want to extract these values and use them . for example: The user checks some checkboxes , for example, list of messages. He/She presses Delete Link to delete selected messages. I searched and found something like this : $("#inboxDeleteSelected").click(function(){ var data = { 'checkBoxList[]' : []}; var list=$(":input:checkbox:checked"); // getting all selected checkboxes. $(list.each(function() { data['checkBoxList[]'].push($(this).val()); })); $.post("servlet?do=deleteSelected",data,function(d){ // do something here }); }); My questions: How can I send selected checkboxes values to a servlet ? How can I extract these values in the servlet ? Note: I don't use submit button to submit the selected checkboxes,Indeed I use link/anchor to send those values .

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  • Quickest way to compare a bunch of array or list of values.

    - by zapping
    Can you please let me know on the quickest and efficient way to compare a large set of values. Its like there are a list of parent codes(string) and each code has a series of child values(string). The child lists have to be compared with each other and find out duplicates and count how many times they repeat. code1(code1_value1, code1_value2, code3_value3, ..., code1_valueN); code2(code2_value1, code1_value2, code2_value3, ..., code2_valueN); code3(code2_value1, code3_value2, code3_value3, ..., code3_valueN); . . . codeN(codeN_value1, codeN_value2, codeN_value3, ..., codeN_valueN); The lists are huge say like there are 100 parent codes and each has about 250 values in them. There will not be duplicates within a code list. Doing it in java and the solution i could figure out is. Store the values of first set of code in as codeMap.put(codeValue, duplicateCount). The count initialized to 0. Then compare the rest of the values with this. If its in the map then increment the count otherwise append it to the map. The downfall of this is to get the duplicates. Another iteration needs to be performed on a very large list. An alternative is to maintain another hashmap for duplicates like duplicateCodeMap.put(codeValue, duplicateCount) and change the initial hashmap to codeMap.put(codeValue, codeValue). Speed is what is requirement. Hope one of you can help me with it.

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  • How do I add values in an array when there is a null entry?

    - by Angela
    I want to create a real time-series array. Currently, I am using the statistics gem to pull out values for each 'day': define_statistic :sent_count, :count => :all, :group => 'DATE(date_sent)', :filter_on => {:email_id => 'email_id > = ?'}, :order => 'DATE(date_sent) ASC' What this does is create an array where there are values for a date, for example [["12-20-2010",1], ["12-24-2010",3]] But I need it to fill in the null values, so it looks more like: [["12-20-2010",1], ["12-21-2010",0], ["12-22-2010",0], ["12-23-2010",0], ["12-24-2010",3]] Notice how the second example has "0" values for the days that were missing from the first array.

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  • How do I use an enum with custom values for a Sharepoint Web part?

    - by Jeff
    I'm trying to design a Web Part that has a drop-down list for the user to choose from. Eventually, these values will be automatically generated based on some kind of outside data source, so they're going to have somewhat arbitrary numeric values associated with them. This is the code I have now: public enum filterChoice { All=0, BOCC=12, Sustainability=15, Clerk=4, DA=13, Emergency=7, Highlights=3, POS=6, PR=1, PH=5, SHPR=2, Test=8, Transportation=14, Volunteer=16 }; These are different categories I want the user to choose from. When I choose one and save the settings for my Web Part, Sharepoint is only saving the values in numeric order; that is, All=0, BOCC=1, Sustainability=3 [...] so my Web Part then thinks the user chose the value with the corresponding number (PR when they chose BOCC, Highlights when they chose Sustainability, etc.) How can I make Sharepoint honor my custom values?

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  • Quickest way to compare a buch of array or list of values.

    - by zapping
    Can you please let me know on the quickest and efficient way to compare a large set of values. Its like there are a list of parent codes(string) and each code has a series of child values(string). The child lists have to be compared with each other and find out duplicates and count how many times they repeat. code1(code1_value1, code1_value2, code3_value3, ..., code1_valueN); code2(code2_value1, code1_value2, code2_value3, ..., code2_valueN); code3(code2_value1, code3_value2, code3_value3, ..., code3_valueN); . . . codeN(codeN_value1, codeN_value2, codeN_value3, ..., codeN_valueN); The lists are huge say like there are 100 parent codes and each has about 250 values in them. There will not be duplicates within a code list. Doing it in java and the solution i could figure out is. Store the values of first set of code in as codeMap.put(codeValue, duplicateCount). The count initialized to 0. Then compare the rest of the values with this. If its in the map then increment the count otherwise append it to the map. The downfall of this is to get the duplicates. Another iteration needs to be performed on a very large list. An alternative is to maintain another hashmap for duplicates like duplicateCodeMap.put(codeValue, duplicateCount) and change the initial hashmap to codeMap.put(codeValue, codeValue). Speed is what is requirement. Hope one of you can help me with it.

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  • How to add values accordingly of the first indices of a dictionary of tuples of a list of strings? Python 3x

    - by TheStruggler
    I'm stuck on how to formulate this problem properly and the following is: What if we had the following values: {('A','B','C','D'):3, ('A','C','B','D'):2, ('B','D','C','A'):4, ('D','C','B','A'):3, ('C','B','A','D'):1, ('C','D','A','B'):1} When we sum up the first place values: [5,4,2,3] (5 people picked for A first, 4 people picked for B first, and so on like A = 5, B = 4, C = 2, D = 3) The maximum values for any alphabet is 5, which isn't a majority (5/14 is less than half), where 14 is the sum of total values. So we remove the alphabet with the fewest first place picks. Which in this case is C. I want to return a dictionary where {'A':5, 'B':4, 'C':2, 'D':3} without importing anything. This is my work: def popular(letter): '''(dict of {tuple of (str, str, str, str): int}) -> dict of {str:int} ''' my_dictionary = {} counter = 0 for (alphabet, picks) in letter.items(): if (alphabet[0]): my_dictionary[alphabet[0]] = picks else: my_dictionary[alphabet[0]] = counter return my_dictionary This returns duplicate of keys which I cannot get rid of. Thanks.

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  • updating the values in detail view from another view....

    - by praseed
    Hi friends, i am building one app almost similar to contact management system...in which i have a detail view .. on pressing one of the table cells, a new view will be shown were the user can enter the new values and on pressing the save button the values will be updated in the database. On going back to the detail view the user should be able to see the updated values in the table cells.. or how can i update the values in detail view from another view...? i came to know that this can be acheived through Appdelegate objects ... but i couldnt understand wat is it or how it is done.... may be bcuz i am new to iPhone apps development... Pls can anyone explain me the process..

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  • How can I find columns which have non-null values?

    - by aartist
    I have many columns in oracle database and some new are added with values. I like to find out which columns have values other than 0 or null. So I am looking for column names for which some sort of useful values exists at least in one row. How do I do this? Update: This sounds very close. How do I modify this to suit my needs? select column_name, nullable, num_distinct, num_nulls from all_tab_columns where table_name = 'SOME_TABLE'

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  • C#/.NET Little Wonders: Using &lsquo;default&rsquo; to Get Default Values

    - by James Michael Hare
    Once again, in this series of posts I look at the parts of the .NET Framework that may seem trivial, but can help improve your code by making it easier to write and maintain. The index of all my past little wonders posts can be found here. Today’s little wonder is another of those small items that can help a lot in certain situations, especially when writing generics.  In particular, it is useful in determining what the default value of a given type would be. The Problem: what’s the default value for a generic type? There comes a time when you’re writing generic code where you may want to set an item of a given generic type.  Seems simple enough, right?  We’ll let’s see! Let’s say we want to query a Dictionary<TKey, TValue> for a given key and get back the value, but if the key doesn’t exist, we’d like a default value instead of throwing an exception. So, for example, we might have a the following dictionary defined: 1: var lookup = new Dictionary<int, string> 2: { 3: { 1, "Apple" }, 4: { 2, "Orange" }, 5: { 3, "Banana" }, 6: { 4, "Pear" }, 7: { 9, "Peach" } 8: }; And using those definitions, perhaps we want to do something like this: 1: // assume a default 2: string value = "Unknown"; 3:  4: // if the item exists in dictionary, get its value 5: if (lookup.ContainsKey(5)) 6: { 7: value = lookup[5]; 8: } But that’s inefficient, because then we’re double-hashing (once for ContainsKey() and once for the indexer).  Well, to avoid the double-hashing, we could use TryGetValue() instead: 1: string value; 2:  3: // if key exists, value will be put in value, if not default it 4: if (!lookup.TryGetValue(5, out value)) 5: { 6: value = "Unknown"; 7: } But the “flow” of using of TryGetValue() can get clunky at times when you just want to assign either the value or a default to a variable.  Essentially it’s 3-ish lines (depending on formatting) for 1 assignment.  So perhaps instead we’d like to write an extension method to support a cleaner interface that will return a default if the item isn’t found: 1: public static class DictionaryExtensions 2: { 3: public static TValue GetValueOrDefault<TKey, TValue>(this Dictionary<TKey, TValue> dict, 4: TKey key, TValue defaultIfNotFound) 5: { 6: TValue value; 7:  8: // value will be the result or the default for TValue 9: if (!dict.TryGetValue(key, out value)) 10: { 11: value = defaultIfNotFound; 12: } 13:  14: return value; 15: } 16: } 17:  So this creates an extension method on Dictionary<TKey, TValue> that will attempt to get a value using the given key, and will return the defaultIfNotFound as a stand-in if the key does not exist. This code compiles, fine, but what if we would like to go one step further and allow them to specify a default if not found, or accept the default for the type?  Obviously, we could overload the method to take the default or not, but that would be duplicated code and a bit heavy for just specifying a default.  It seems reasonable that we could set the not found value to be either the default for the type, or the specified value. So what if we defaulted the type to null? 1: public static TValue GetValueOrDefault<TKey, TValue>(this Dictionary<TKey, TValue> dict, 2: TKey key, TValue defaultIfNotFound = null) // ... No, this won’t work, because only reference types (and Nullable<T> wrapped types due to syntactical sugar) can be assigned to null.  So what about a calling parameterless constructor? 1: public static TValue GetValueOrDefault<TKey, TValue>(this Dictionary<TKey, TValue> dict, 2: TKey key, TValue defaultIfNotFound = new TValue()) // ... No, this won’t work either for several reasons.  First, we’d expect a reference type to return null, not an “empty” instance.  Secondly, not all reference types have a parameter-less constructor (string for example does not).  And finally, a constructor cannot be determined at compile-time, while default values can. The Solution: default(T) – returns the default value for type T Many of us know the default keyword for its uses in switch statements as the default case.  But it has another use as well: it can return us the default value for a given type.  And since it generates the same defaults that default field initialization uses, it can be determined at compile-time as well. For example: 1: var x = default(int); // x is 0 2:  3: var y = default(bool); // y is false 4:  5: var z = default(string); // z is null 6:  7: var t = default(TimeSpan); // t is a TimeSpan with Ticks == 0 8:  9: var n = default(int?); // n is a Nullable<int> with HasValue == false Notice that for numeric types the default is 0, and for reference types the default is null.  In addition, for struct types, the value is a default-constructed struct – which simply means a struct where every field has their default value (hence 0 Ticks for TimeSpan, etc.). So using this, we could modify our code to this: 1: public static class DictionaryExtensions 2: { 3: public static TValue GetValueOrDefault<TKey, TValue>(this Dictionary<TKey, TValue> dict, 4: TKey key, TValue defaultIfNotFound = default(TValue)) 5: { 6: TValue value; 7:  8: // value will be the result or the default for TValue 9: if (!dict.TryGetValue(key, out value)) 10: { 11: value = defaultIfNotFound; 12: } 13:  14: return value; 15: } 16: } Now, if defaultIfNotFound is unspecified, it will use default(TValue) which will be the default value for whatever value type the dictionary holds.  So let’s consider how we could use this: 1: lookup.GetValueOrDefault(1); // returns “Apple” 2:  3: lookup.GetValueOrDefault(5); // returns null 4:  5: lookup.GetValueOrDefault(5, “Unknown”); // returns “Unknown” 6:  Again, do not confuse a parameter-less constructor with the default value for a type.  Remember that the default value for any type is the compile-time default for any instance of that type (0 for numeric, false for bool, null for reference types, and struct will all default fields for struct).  Consider the difference: 1: // both zero 2: int i1 = default(int); 3: int i2 = new int(); 4:  5: // both “zeroed” structs 6: var dt1 = default(DateTime); 7: var dt2 = new DateTime(); 8:  9: // sb1 is null, sb2 is an “empty” string builder 10: var sb1 = default(StringBuilder()); 11: var sb2 = new StringBuilder(); So in the above code, notice that the value types all resolve the same whether using default or parameter-less construction.  This is because a value type is never null (even Nullable<T> wrapped types are never “null” in a reference sense), they will just by default contain fields with all default values. However, for reference types, the default is null and not a constructed instance.  Also it should be noted that not all classes have parameter-less constructors (string, for instance, doesn’t have one – and doesn’t need one). Summary Whenever you need to get the default value for a type, especially a generic type, consider using the default keyword.  This handy word will give you the default value for the given type at compile-time, which can then be used for initialization, optional parameters, etc. Technorati Tags: C#,CSharp,.NET,Little Wonders,default

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  • Why don't %MEM values add up to mem in top?

    - by ben
    I'm currently debugging performance issues with my VPS and for that I'm trying to understand which of the processes eat the most memory. Reading top, here's what I get: Mem: 366544k total, 321396k used, 45148k free, 380k buffers Swap: 1048572k total, 592388k used, 456184k free, 7756k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 12339 ruby 20 0 844m 74m 2440 S 0 20.8 0:24.84 ruby 12363 ruby 20 0 844m 73m 1576 S 0 20.6 0:00.26 ruby 21117 ruby 20 0 171m 33m 1792 S 0 9.3 2:03.98 ruby 11846 ruby 20 0 858m 21m 1820 S 0 6.0 0:09.15 ruby 21277 ruby 20 0 219m 11m 1648 S 0 3.2 2:00.98 ruby 792 root 20 0 266m 10m 1024 S 0 3.0 1:40.06 ruby 532 mysql 20 0 234m 4760 1040 S 0 1.3 0:41.58 mysqld 793 root 20 0 250m 4616 984 S 0 1.3 1:20.55 ruby 586 root 20 0 156m 4532 848 S 0 1.2 6:17.10 god 12315 ruby 20 0 175m 2412 1900 S 0 0.7 0:07.55 ruby 3844 root 20 0 44036 2132 1028 S 0 0.6 1:08.22 ruby 10939 ruby 20 0 179m 1884 1724 S 0 0.5 0:08.33 ruby 4660 ruby 20 0 229m 1592 1440 S 0 0.4 2:55.46 ruby 3879 nobody 20 0 37428 964 520 S 0 0.3 0:01.99 nginx As you can see my memory is about 90% used (which is my issue) but when you add up the %MEM values, it goes to about 50-60% only. Same thing, RES doesn't add up to ~350mb. Why? Am I misunderstanding their meaning? Thanks

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  • sed: replace only the first range of numbers

    - by Marit Hoen
    Imagine I have an input file like this: INSERT INTO video_item_theme VALUES('9', '29'); INSERT INTO video_item_theme VALUES('19', '312'); INSERT INTO video_item_theme VALUES('414', '1'); And I wish to add 10000 to only the first range of numbers, so I end up with something like this: INSERT INTO video_item_theme VALUES('10009', '29'); INSERT INTO video_item_theme VALUES('10019', '312'); INSERT INTO video_item_theme VALUES('10414', '1'); My approach would be to prefix "1000" to one digit numbers, "100" Something like...: sed 's/[0-9]\{2\}/10&/g' ... isn't very helpful, since it changes each occurance of two numbers, not only in the first occurance of numbers: INSERT INTO video_item_theme VALUES('9', '10029'); INSERT INTO video_item_theme VALUES('10019', '100312'); INSERT INTO video_item_theme VALUES('100414', '1');

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  • Problem running oracle script from command line using sqlplus

    - by Charlie
    I'm having a problem trying to run my sql script into oracle using sqlplus. The script just populates some dummy data: DECLARE role1Id NUMBER; user1Id NUMBER; role2Id NUMBER; user2Id NUMBER; role3Id NUMBER; user3Id NUMBER; perm1Id NUMBER; perm2Id NUMBER; perm3Id NUMBER; perm4Id NUMBER; perm5Id NUMBER; BEGIN INSERT INTO PB_USER(USER_ID,USER_NAME, USER_EMAIL, USER_ACTIVEYN) VALUES(PB_USER_ID_SEQ.nextval, 'RoleDataManagerTests_Username', '[email protected]',' '); INSERT INTO ROLES(ROLE_ID, ROLE_NAME) VALUES(PB_ROLE_ID_SEQ.nextval, 'Test role 1'); INSERT INTO ROLES(ROLE_ID, ROLE_NAME) VALUES(PB_ROLE_ID_SEQ.nextval, 'Test role 2'); INSERT INTO ROLES(ROLE_ID, ROLE_NAME) VALUES(PB_ROLE_ID_SEQ.nextval, 'Test role 3'); SELECT ROLE_ID INTO role1Id FROM ROLES WHERE ROLE_NAME = 'Test role 1'; SELECT USER_ID INTO user1Id FROM PB_USER WHERE USER_NAME = 'RoleDataManagerTests_Username'; INSERT INTO USERS_ROLES(USER_ID, ROLE_ID) VALUES(user1Id, role1Id); SELECT ROLE_ID INTO role2Id FROM ROLES WHERE ROLE_NAME = 'Test role 2'; SELECT USER_ID INTO user2Id FROM PB_USER WHERE USER_NAME = 'RoleDataManagerTests_Username'; INSERT INTO USERS_ROLES(USER_ID, ROLE_ID) VALUES(user2Id, role2Id); SELECT ROLE_ID INTO role3Id FROM ROLES WHERE ROLE_NAME = 'Test role 3'; SELECT USER_ID INTO user3Id FROM PB_USER WHERE USER_NAME = 'RoleDataManagerTests_Username'; INSERT INTO USERS_ROLES(USER_ID, ROLE_ID) VALUES(user3Id, role3Id); INSERT INTO PERMISSIONS(PERMISSION_ID, KEY, DESCRIPTION) VALUES (PB_PERMISSION_ID_SEQ.nextval, 'perm1', 'permission 1'); INSERT INTO PERMISSIONS(PERMISSION_ID, KEY, DESCRIPTION) VALUES (PB_PERMISSION_ID_SEQ.nextval, 'perm2', 'permission 2'); INSERT INTO PERMISSIONS(PERMISSION_ID, KEY, DESCRIPTION) VALUES (PB_PERMISSION_ID_SEQ.nextval, 'perm3', 'permission 3'); INSERT INTO PERMISSIONS(PERMISSION_ID, KEY, DESCRIPTION) VALUES (PB_PERMISSION_ID_SEQ.nextval, 'perm4', 'permission 4'); INSERT INTO PERMISSIONS(PERMISSION_ID, KEY, DESCRIPTION) VALUES (PB_PERMISSION_ID_SEQ.nextval, 'perm5', 'permission 5'); SELECT PERMISSION_ID INTO perm1Id FROM PERMISSIONS WHERE KEY = 'perm1'; SELECT PERMISSION_ID INTO perm2Id FROM PERMISSIONS WHERE KEY = 'perm2'; SELECT PERMISSION_ID INTO perm3Id FROM PERMISSIONS WHERE KEY = 'perm3'; SELECT PERMISSION_ID INTO perm4Id FROM PERMISSIONS WHERE KEY = 'perm4'; SELECT PERMISSION_ID INTO perm5Id FROM PERMISSIONS WHERE KEY = 'perm5'; INSERT INTO ROLES_PERMISSIONS(ROLE_ID, PERMISSION_ID) VALUES(role1Id, perm1Id); INSERT INTO ROLES_PERMISSIONS(ROLE_ID, PERMISSION_ID) VALUES(role1Id, perm2Id); INSERT INTO ROLES_PERMISSIONS(ROLE_ID, PERMISSION_ID) VALUES(role1Id, perm3Id); INSERT INTO ROLES_PERMISSIONS(ROLE_ID, PERMISSION_ID) VALUES(role2Id, perm3Id); INSERT INTO ROLES_PERMISSIONS(ROLE_ID, PERMISSION_ID) VALUES(role3Id, perm4Id); INSERT INTO ROLES_PERMISSIONS(ROLE_ID, PERMISSION_ID) VALUES(role3Id, perm5Id); END; / My script works fine when I run it using Oracle SQL Developer but when I use the sqlplus command line tool this is what's outputted and then it just hangs: SQL*Plus: Release 11.1.0.7.0 - Production on Tue May 11 09:49:34 2010 Copyright (c) 1982, 2008, Oracle. All rights reserved. Connected to: Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bit Production With the Partitioning, Oracle Label Security, OLAP, Data Mining Scoring Engine and Real Application Testing options I'm running the tool using this command line, which works fine for other scripts: sqlplus username/password@server/dbname @Setup.sql Any ideas? Thanks.

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  • Oracle Database 12 c New Partition Maintenance Features by Gwen Lazenby

    - by hamsun
    One of my favourite new features in Oracle Database 12c is the ability to perform partition maintenance operations on multiple partitions. This means we can now add, drop, truncate and merge multiple partitions in one operation, and can split a single partition into more than two partitions also in just one command. This would certainly have made my life slightly easier had it been available when I administered a data warehouse at Oracle 9i. To demonstrate this new functionality and syntax, I am going to create two tables, ORDERS and ORDERS_ITEMS which have a parent-child relationship. ORDERS is to be partitioned using range partitioning on the ORDER_DATE column, and ORDER_ITEMS is going to partitioned using reference partitioning and its foreign key relationship with the ORDERS table. This form of partitioning was a new feature in 11g and means that any partition maintenance operations performed on the ORDERS table will also take place on the ORDER_ITEMS table as well. First create the ORDERS table - SQL CREATE TABLE orders ( order_id NUMBER(12), order_date TIMESTAMP, order_mode VARCHAR2(8), customer_id NUMBER(6), order_status NUMBER(2), order_total NUMBER(8,2), sales_rep_id NUMBER(6), promotion_id NUMBER(6), CONSTRAINT orders_pk PRIMARY KEY(order_id) ) PARTITION BY RANGE(order_date) (PARTITION Q1_2007 VALUES LESS THAN (TO_DATE('01-APR-2007','DD-MON-YYYY')), PARTITION Q2_2007 VALUES LESS THAN (TO_DATE('01-JUL-2007','DD-MON-YYYY')), PARTITION Q3_2007 VALUES LESS THAN (TO_DATE('01-OCT-2007','DD-MON-YYYY')), PARTITION Q4_2007 VALUES LESS THAN (TO_DATE('01-JAN-2008','DD-MON-YYYY')) ); Table created. Now the ORDER_ITEMS table SQL CREATE TABLE order_items ( order_id NUMBER(12) NOT NULL, line_item_id NUMBER(3) NOT NULL, product_id NUMBER(6) NOT NULL, unit_price NUMBER(8,2), quantity NUMBER(8), CONSTRAINT order_items_fk FOREIGN KEY(order_id) REFERENCES orders(order_id) on delete cascade) PARTITION BY REFERENCE(order_items_fk) tablespace example; Table created. Now look at DBA_TAB_PARTITIONS to get details of what partitions we have in the two tables – SQL select table_name,partition_name, partition_position position, high_value from dba_tab_partitions where table_owner='SH' and table_name like 'ORDER_%' order by partition_position, table_name; TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 Just as an aside it is also now possible in 12c to use interval partitioning on reference partitioned tables. In 11g it was not possible to combine these two new partitioning features. For our first example of the new 12cfunctionality, let us add all the partitions necessary for 2008 to the tables using one command. Notice that the partition specification part of the add command is identical in format to the partition specification part of the create command as shown above - SQL alter table orders add PARTITION Q1_2008 VALUES LESS THAN (TO_DATE('01-APR-2008','DD-MON-YYYY')), PARTITION Q2_2008 VALUES LESS THAN (TO_DATE('01-JUL-2008','DD-MON-YYYY')), PARTITION Q3_2008 VALUES LESS THAN (TO_DATE('01-OCT-2008','DD-MON-YYYY')), PARTITION Q4_2008 VALUES LESS THAN (TO_DATE('01-JAN-2009','DD-MON-YYYY')); Table altered. Now look at DBA_TAB_PARTITIONS and we can see that the 4 new partitions have been added to both tables – SQL select table_name,partition_name, partition_position position, high_value from dba_tab_partitions where table_owner='SH' and table_name like 'ORDER_%' order by partition_position, table_name; TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q1_2008 5 TIMESTAMP' 2008-04-01 00:00:00' ORDER_ITEMS Q1_2008 5 ORDERS Q2_2008 6 TIMESTAMP' 2008-07-01 00:00:00' ORDER_ITEM Q2_2008 6 ORDERS Q3_2008 7 TIMESTAMP' 2008-10-01 00:00:00' ORDER_ITEMS Q3_2008 7 ORDERS Q4_2008 8 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 8 Next, we can drop or truncate multiple partitions by giving a comma separated list in the alter table command. Note the use of the plural ‘partitions’ in the command as opposed to the singular ‘partition’ prior to 12c– SQL alter table orders drop partitions Q3_2008,Q2_2008,Q1_2008; Table altered. Now look at DBA_TAB_PARTITIONS and we can see that the 3 partitions have been dropped in both the two tables – TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q4_2008 5 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 5 Now let us merge all the 2007 partitions together to form one single partition – SQL alter table orders merge partitions Q1_2005, Q2_2005, Q3_2005, Q4_2005 into partition Y_2007; Table altered. TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Y_2007 1 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Y_2007 1 ORDERS Q4_2008 2 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 2 Splitting partitions is a slightly more involved. In the case of range partitioning one of the new partitions must have no high value defined, and in list partitioning one of the new partitions must have no list of values defined. I call these partitions the ‘everything else’ partitions, and will contain any rows contained in the original partition that are not contained in the any of the other new partitions. For example, let us split the Y_2007 partition back into 4 quarterly partitions – SQL alter table orders split partition Y_2007 into (PARTITION Q1_2007 VALUES LESS THAN (TO_DATE('01-APR-2007','DD-MON-YYYY')), PARTITION Q2_2007 VALUES LESS THAN (TO_DATE('01-JUL-2007','DD-MON-YYYY')), PARTITION Q3_2007 VALUES LESS THAN (TO_DATE('01-OCT-2007','DD-MON-YYYY')), PARTITION Q4_2007); Now look at DBA_TAB_PARTITIONS to get details of the new partitions – TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q4_2008 5 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 5 Partition Q4_2007 has a high value equal to the high value of the original Y_2007 partition, and so has inherited its upper boundary from the partition that was split. As for a list partitioning example let look at the following another table, SALES_PAR_LIST, which has 2 partitions, Americas and Europe and a partitioning key of country_name. SQL select table_name,partition_name, high_value from dba_tab_partitions where table_owner='SH' and table_name = 'SALES_PAR_LIST'; TABLE_NAME PARTITION_NAME HIGH_VALUE -------------- --------------- ----------------------------- SALES_PAR_LIST AMERICAS 'Argentina', 'Canada', 'Peru', 'USA', 'Honduras', 'Brazil', 'Nicaragua' SALES_PAR_LIST EUROPE 'France', 'Spain', 'Ireland', 'Germany', 'Belgium', 'Portugal', 'Denmark' Now split the Americas partition into 3 partitions – SQL alter table sales_par_list split partition americas into (partition south_america values ('Argentina','Peru','Brazil'), partition north_america values('Canada','USA'), partition central_america); Table altered. Note that no list of values was given for the ‘Central America’ partition. However it should have inherited any values in the original ‘Americas’ partition that were not assigned to either the ‘North America’ or ‘South America’ partitions. We can confirm this by looking at the DBA_TAB_PARTITIONS view. SQL select table_name,partition_name, high_value from dba_tab_partitions where table_owner='SH' and table_name = 'SALES_PAR_LIST'; TABLE_NAME PARTITION_NAME HIGH_VALUE --------------- --------------- -------------------------------- SALES_PAR_LIST SOUTH_AMERICA 'Argentina', 'Peru', 'Brazil' SALES_PAR_LIST NORTH_AMERICA 'Canada', 'USA' SALES_PAR_LIST CENTRAL_AMERICA 'Honduras', 'Nicaragua' SALES_PAR_LIST EUROPE 'France', 'Spain', 'Ireland', 'Germany', 'Belgium', 'Portugal', 'Denmark' In conclusion, I hope that DBA’s whose work involves maintaining partitions will find the operations a bit more straight forward to carry out once they have upgraded to Oracle Database 12c. Gwen Lazenby is a Principal Training Consultant at Oracle. She is part of Oracle University's Core Technology delivery team based in the UK, teaching Database Administration and Linux courses. Her specialist topics include using Oracle Partitioning and Parallelism in Data Warehouse environments, as well as Oracle Spatial and RMAN.

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  • What is the recommended way to output values to FBO targets? (OpenGL 3.3 + GLSL 330)

    - by datSilencer
    I'll begin by apologizing for any dumb assumptions you might find in the code below since I'm still pretty much green when it comes to OpenGL programming. I'm currently trying to implement deferred shading by using FBO's and their associated targets (textures in my case). I have a simple (I think :P) geometry+fragment shader program and I'd like to write its Fragment Shader stage output to three different render targets (previously bound by a call to glDrawBuffers()), like so: #version 330 in vec3 WorldPos0; in vec2 TexCoord0; in vec3 Normal0; in vec3 Tangent0; layout(location = 0) out vec3 WorldPos; layout(location = 1) out vec3 Diffuse; layout(location = 2) out vec3 Normal; uniform sampler2D gColorMap; uniform sampler2D gNormalMap; vec3 CalcBumpedNormal() { vec3 Normal = normalize(Normal0); vec3 Tangent = normalize(Tangent0); Tangent = normalize(Tangent - dot(Tangent, Normal) * Normal); vec3 Bitangent = cross(Tangent, Normal); vec3 BumpMapNormal = texture(gNormalMap, TexCoord0).xyz; BumpMapNormal = 2 * BumpMapNormal - vec3(1.0, 1.0, -1.0); vec3 NewNormal; mat3 TBN = mat3(Tangent, Bitangent, Normal); NewNormal = TBN * BumpMapNormal; NewNormal = normalize(NewNormal); return NewNormal; } void main() { WorldPos = WorldPos0; Diffuse = texture(gColorMap, TexCoord0).xyz; Normal = CalcBumpedNormal(); } If my render target textures are configured as: RT1:(GL_RGB32F, GL_RGB, GL_FLOAT, GL_TEXTURE0, GL_COLOR_ATTACHMENT0) RT2:(GL_RGB32F, GL_RGB, GL_FLOAT, GL_TEXTURE1, GL_COLOR_ATTACHMENT1) RT3:(GL_RGB32F, GL_RGB, GL_FLOAT, GL_TEXTURE2, GL_COLOR_ATTACHMENT2) And assuming that each texture has an internal format capable of contaning the incoming data, will the fragment shader write the corresponding values to the expected texture targets? On a related note, do the textures need to be bound to the OpenGL context when they are Multiple Render Targets? From some Googling, I think there are two other ways to output to MRTs: 1: Output each component to gl_FragData[n]. Some forum posts say this method is deprecated. However, looking at the latest OpenGL 3.3 and 4.0 specifications at opengl.org, the core profiles still mention this approach. 2: Use a typed output array variable for the expected type. In this case, I think it would be something like this: out vec3 [3] output; void main() { output[0] = WorldPos0; output[1] = texture(gColorMap, TexCoord0).xyz; output[2] = CalcBumpedNormal(); } So which is then the recommended approach? Is there a recommended approach at all if I plan to code on top of OpenGL 3.3? Thanks for your time and help!

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  • Why do I need to set up Autologon values in registry twice before it works and can i fix this?

    - by jJack
    Background: As part an automated testing suite I am building, I need to set up Autologon on my virtual machines 'on demand'. By on demand, I mean that I don't want to necessarily pre-configure my VM or any snapshot to have Autologon set up already, for security reasons and also a huge business case. My solution so far: I'm copying a script to the guest machine and then using Sysinternals PsExec to execute it. The script is: reg add "hklm\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon" /f /v DefaultUserName /t REG_SZ /d myusername reg add "hklm\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon" /f /v DefaultPassword /t REG_SZ /d myfakepassword reg add "hklm\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon" /f /v DefaultDomainName /t REG_SZ /d mydomain reg add "hklm\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon" /f /v ForceAutoLogon /t REG_SZ /d 1 reg add "hklm\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon" /f /v AutoAdminLogon /t REG_SZ /d 1 reg add "hklm\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Winlogon\AutoLogonChecked" /f /ve /d 1 Note: I don't believe AutoLogonChecked is required for machines post Windows 2000 but I'm doing it just in case for now. Maybe ForceAutoLogon isn't either, not sure yet. The Problem: I see PsExec executes this properly and all the values are in the registry, however when I restart the machine, the user isn't automatically logged on...When I run this a second time then restart the machine, the user is finally logged on. A diff between the registry states shows that the first time I run this, it is missing both the "1" for AutoAdminLogon, and also the DefaultPassword key. The second time I execute it, these values are correctly intact as I intended. So, what is going on here? Is this expected? This post claims in the end that it really all just works (the problem was that a logoff script was setting off the values). Doesn't seem to work for me however.

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  • How to implement best matching logic in TSQL (SQL Server 2000)

    - by sanjay-kumar1911
    I have two tables X and Y: Table X C1 C2 C3 1 A 13 2 B 16 3 C 8 Table Y C1 C2 C3 C4 1 A 2 N 2 A 8 N 3 A 12 N 4 A 5 N 5 B 7 N 6 B 16 N 7 B 9 N 8 B 5 N 9 C 8 N 10 C 2 N 11 C 8 N 12 C 6 N Records in Table Y can be n number CREATE TABLE X(C1 INT, C2 CHAR(1), C3 INT); CREATE TABLE Y(C1 INT, C2 CHAR(1), C3 INT, C4 CHAR(1)); with following data: INSERT INTO X VALUES (1 'A',13 ); INSERT INTO X VALUES (2 'B',16 ); INSERT INTO X VALUES (3 'C',8 ); INSERT INTO Y VALUES (1,'A', 2,'N'); INSERT INTO Y VALUES (2,'A', 8,'N'); INSERT INTO Y VALUES (3,'A', 12,'N'); INSERT INTO Y VALUES (4,'A', 5,'N'); INSERT INTO Y VALUES (5,'B', 7,'N'); INSERT INTO Y VALUES (6,'B', 16,'N'); INSERT INTO Y VALUES (7,'B', 9,'N'); INSERT INTO Y VALUES (8,'B', 5,'N'); INSERT INTO Y VALUES (9,'C', 8,'N'); INSERT INTO Y VALUES (10,'C', 2,'N'); INSERT INTO Y VALUES (11,'C', 8,'N'); INSERT INTO Y VALUES (12,'C', 6,'N'); EXPECTED RESULT Table Y C1 C2 C3 C4 1 A 2 N 2 A 8 Y 3 A 12 N 4 A 5 Y 5 B 7 N 6 B 16 Y 7 B 9 N 8 B 5 N 9 C 8 Y 10 C 2 N 11 C 8 N 12 C 6 N How do I compare value of column C3 in Table X with all possible matches of column C3 of Table Y and to mark records as matched and unmatched in column C4 of Table Y? Possible matches for A (i.e. value of column C2 in Table X) would be (where R is row number i.e. value of column C1 in Table Y): R1, R2, R3, R4, R1+R2, R1+R3, R1+R4, R2+R3, R2+R4, R3+R4, R4+R5, R1+R2+R3, R1+R2+R4, R2+R3+R4, R1+R2+R3+R4

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