Search Results

Search found 2560 results on 103 pages for 'vitor py'.

Page 86/103 | < Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >

• How do I modify gitstats to only utilize a specified file extension for it's statistics?

  - by Fake Code Monkey Rashid

  Hello good people! The website of the statistics generator in question is: http://gitstats.sourceforge.net/ It's git repo can be cloned from: git clone git://repo.or.cz/gitstats.git What I want to do is something like: ./gitstatus --ext=".py" /input/foo /output/bar Failing being able to easily pass the above option without heavy modification, I'd just hardcore the file extentsion I want to be included. However, I'm unsure of the relevant section of code to modify and even if I did no, I'm unsure of how to start such modifications. It's seems like it'd be rather simple but alas...

  Read the article

• Can you change/redirect a django form's function by passing in your own function?

  - by Derek

  I'm dealing with django-paypal and want to change the button src images. So I went the the conf.py file in the source and edited the src destination. However, I really want to leave the source alone, and I noticed that the class PayPalPaymentsForm(forms.Form): has def get_image(self): return { (True, self.SUBSCRIBE): SUBSCRIPTION_SANDBOX_IMAGE, (True, self.BUY): SANDBOX_IMAGE, (True, self.DONATE): DONATION_SANDBOX_IMAGE, (False, self.SUBSCRIBE): SUBSCRIPTION_IMAGE, (False, self.BUY): IMAGE, (False, self.DONATE): DONATION_IMAGE, }[TEST, self.button_type] which handles all the image src destinations. Since changing this def in the source is worse than changing conf, I was wondering if there was a way to pass in customized defs you make like passing in initial arguments in forms? This way no source code is changed, and I can customize the get_image def as much as I need. passing in def something like this? def get_image(self): .... .... paypal = { 'amount': 10, 'item_name': 'test1', 'item_number': 'test1_slug', # PayPal wants a unique invoice ID 'invoice': str(uuid.uuid4()), } form = PayPalPaymentsForm(initial=paypal, get_image) Thanks!

  Read the article

• Why is django.test.client.Client not keeping me logged in.

  - by Mystic

  I'm using django.test.client.Client to test whether some text shows up when a user is logged in. However, I the Client object doesn't seem to be keeping me logged in. This test passes if done manually with Firefox but not when done with the Client object. class Test(TestCase): def test_view(self): user.set_password(password) user.save() client = self.client # I thought a more manual way would work, but no luck # client.post('/login', {'username':user.username, 'password':password}) login_successful = client.login(username=user.username, password=password) # this assert passes self.assertTrue(login_successful) response = client.get("/path", follow=True) #whether follow=True or not doesn't seem to work self.assertContains(response, "needle" ) When I print response it returns the login form that is hidden by: {% if not request.user.is_authenticated %} ... form ... {% endif %} This is confirmed when I run ipython manage.py shell. The problem seems to be that the Client object is not keeping the session authenticated.

  Read the article

• SWIG & C/C++ Python API connected - SEGFAULT

  - by user289637

  Hello, my task is to create dual program. At the beginning I start C program that calls throught C/C++ API of Python some Python method. The called method after that call a function that is created with SWIG. I show you my sample also with backtrace from gdb after I am given Segmentation fault. main.c: #include <Python.h> #include <stdio.h> #include "utils.h" int main(int argc, char** argv) { printf("Calling from C !\n"); increment(); int i; for(i = 0; i < 11; ++i) { Py_Initialize(); PyObject *pname = PyString_FromString("py_function"); PyObject *module = PyImport_Import(pname); PyObject *dict = PyModule_GetDict(module); PyObject *func = PyDict_GetItemString(dict, "ink"); PyObject_CallObject(func, NULL); Py_DECREF(module); Py_DECREF(pname); printf("\tbefore finalize\n"); Py_Finalize(); printf("\tafter finalize\n"); } return 0; } utils.c #include <stdio.h> #include "utils.h" void increment(void) { printf("Incremention counter to: %u\n", ++counter); } py_function.py #!/usr/bin/python2.6 '''py_function.py - Python source designed to demonstrate the use of python embedding''' import utils def ink(): print 'I am gonna increment !' utils.increment() and last think is my Makefile & SWIG configure file Makefile: CC=gcc CFLAGS=-c -g -Wall -std=c99 all: main main: main.o utils.o utils_wrap.o $(CC) main.o utils.o -lpython2.6 -o sample swig -Wall -python -o utils_wrap.c utils.i $(CC) utils.o utils_wrap.o -shared -o _utils.so main.o: main.c $(CC) $(CFLAGS) main.c -I/usr/include/python2.6 -o main.o utils.o: utils.c utils.h $(CC) $(CFLAGS) -fPIC utils.c -o $@ utils_wrap.o: utils_wrap.c $(CC) -c -fPIC utils_wrap.c -I/usr/include/python2.6 -o $@ clean: rm -rf *.o The program is called by ./main and there is output: (gdb) run Starting program: /home/marxin/Programming/python2/sample [Thread debugging using libthread_db enabled] Calling from C ! Incremention counter to: 1 I am gonna increment ! Incremention counter to: 2 before finalize after finalize I am gonna increment ! Incremention counter to: 3 before finalize after finalize I am gonna increment ! Incremention counter to: 4 before finalize after finalize Program received signal SIGSEGV, Segmentation fault. 0xb7ed3e4e in PyObject_Malloc () from /usr/lib/libpython2.6.so.1.0 Backtrace: (gdb) backtrace #0 0xb7ed3e4e in PyObject_Malloc () from /usr/lib/libpython2.6.so.1.0 #1 0xb7ca2b2c in ?? () #2 0xb7f8dd40 in ?? () from /usr/lib/libpython2.6.so.1.0 #3 0xb7eb014c in ?? () from /usr/lib/libpython2.6.so.1.0 #4 0xb7f86ff4 in ?? () from /usr/lib/libpython2.6.so.1.0 #5 0xb7f99820 in ?? () from /usr/lib/libpython2.6.so.1.0 #6 0x00000001 in ?? () #7 0xb7f8dd40 in ?? () from /usr/lib/libpython2.6.so.1.0 #8 0xb7f4f014 in _PyObject_GC_Malloc () from /usr/lib/libpython2.6.so.1.0 #9 0xb7f99820 in ?? () from /usr/lib/libpython2.6.so.1.0 #10 0xb7f4f104 in _PyObject_GC_NewVar () from /usr/lib/libpython2.6.so.1.0 #11 0xb7ee8760 in _PyType_Lookup () from /usr/lib/libpython2.6.so.1.0 #12 0xb7f99820 in ?? () from /usr/lib/libpython2.6.so.1.0 #13 0x00000001 in ?? () #14 0xb7f8dd40 in ?? () from /usr/lib/libpython2.6.so.1.0 #15 0xb7ef13ed in ?? () from /usr/lib/libpython2.6.so.1.0 #16 0xb7f86ff4 in ?? () from /usr/lib/libpython2.6.so.1.0 #17 0x00000001 in ?? () #18 0xbfff0c34 in ?? () #19 0xb7e993c3 in ?? () from /usr/lib/libpython2.6.so.1.0 #20 0x00000001 in ?? () #21 0xbfff0c70 in ?? () #22 0xb7f99da0 in ?? () from /usr/lib/libpython2.6.so.1.0 #23 0xb7f86ff4 in ?? () from /usr/lib/libpython2.6.so.1.0 #24 0xb7f86ff4 in ?? () from /usr/lib/libpython2.6.so.1.0 #25 0x080a6b0c in ?? () #26 0x080a6b0c in ?? () #27 0xb7e99420 in PyObject_CallFunctionObjArgs () from /usr/lib/libpython2.6.so.1.0 #28 0xb7f86ff4 in ?? () from /usr/lib/libpython2.6.so.1.0 #29 0xb7f86ff4 in ?? () from /usr/lib/libpython2.6.so.1.0 #30 0x800e55eb in ?? () #31 0x080a6b0c in ?? () #32 0xb7e9958c in PyObject_IsSubclass () from /usr/lib/libpython2.6.so.1.0 #33 0xb7f8dd40 in ?? () from /usr/lib/libpython2.6.so.1.0 #34 0x080a9020 in ?? () #35 0xb7fb78f0 in PyFPE_counter () from /usr/lib/libpython2.6.so.1.0 #36 0xb7f86ff4 in ?? () from /usr/lib/libpython2.6.so.1.0 #37 0x00000000 in ?? () Thanks for your help and advices, marxin

  Read the article

• keep open windows console after a python syntax error

  - by basweber

  File associations on my machine (winxp home) are such that a python script is directly opened with the python interpreter. If I double click on a python script a console window runs and every thing is fine - as long as there is no syntax error in the script. In that case the console window opens up for a moment but it is closed immediately. Too fast to read the error message. Of course their would be the possibility to manually open a console window and to execute the script by typing python myscript.py but I am sure that there is a more convenient (i.e. "double click based") solution.

  Read the article

• Symbol not found: _curl_easy_cleanup

  - by Bharadwaj

  I am working on porting a python application to Mac OS X. The application makes use of pycurl and PyCDF. When I run my code, I get this error : > File > "/Library/Python/2.5/site-packages/pycdf/pycdfext.py", > line 5, in <module> > import _pycdfext ImportError: dlopen(/Library/Python/2.5/site-packages/pycdf/_pycdfext.so, > 2): Symbol not found: > _curl_easy_cleanup Referenced from: /Library/Python/2.5/site-packages/pycdf/_pycdfext.so > Expected in: dynamic lookup I tried installing different versions of curl, pycurl with different configs of libcurl. Still stuck Platform : 10.5.8 Curl : 7.19.4 [also tried 7.20.1] Pycurl : 7.19.0 How do I fix this error?

  Read the article

• Problem with sys.argv[1] when unittest module is in a script

  - by chrissygormley

  Hello, I have a script that does various things and access paramenters using sys.argv but when the script gets to the unittest part of the code it says there is no module for this. The script that I have is: class MyScript(): def __init__(self): self.value = sys.argv[1] def hello(self): print self.value def suite(self): modules_to_test = ('external_sanity_onvif', 'starttest') alltests = unittest.TestSuite() for module in map(__import__, modules_to_test): alltests.addTest(unittest.findTestCases(module)) return alltests if __name__ == '__main__': Run = MyScript() Run.hello() log_file = 'log_file.txt' test_file = open(log_file, "w") runner = unittest.TextTestRunner(test_file) unittest.main(defaultTest='Run.suite', testRunner=runner) Say I enter ./script.py Hello in the command line. The error I get is: AttributeError: 'module' object has no attribute 'Hello' If I remove the unittest module it works. Also if I remove the testrunner log and leave it at: unittest.main(defaultTest='Run.suite') This still doesn't work. Can anyone help. Thanks

  Read the article

• Not work variables in django templates

  - by ??????? ???????

  My context dictionary not sending to my templates. I have function from django.shortcuts import render_to_response def home(request): return render_to_response('home.html',{'test':'test'}) and i have simple template such as: <html> <body> my test == {{test}} </body> </html> When i open my site in browser, i have "my test == ". settings.py is default. I dont use something custom. What the problem? Server is apache with wsgi module.

  Read the article

• Mocking imported modules in Python

  - by Evgenyt

  I'm trying to implement unit tests for function that uses imported external objects. For example helpers.py is: import os import pylons def some_func(arg): ... var1 = os.path.exist(...) var2 = os.path.getmtime(...) var3 = pylons.request.environ['HTTP_HOST'] ... So when I'm creating unit test for it I do some mocking (minimock in my case) and replacing references to pylons.request and os.path: import helpers def test_some_func(): helpers.pylons.request = minimock.Mock("pylons.request") helpers.pylons.request.environ = { 'HTTP_HOST': "localhost" } helpers.os.path = minimock.Mock(....) ... some_func(...) # assert ... This does not look good for me. Is there any other better way or strategy to substitute imported function/objects in Python?

  Read the article

• Windows equivalent to this Makefile

  - by Sridhar Ratnakumar

  The advantage of writing a Makefile is that "make" is generally assumed to be present on the various Unices (Linux and Mac primarily). Now I have the following Makefile: PYTHON := python all: e installdeps e: virtualenv --distribute --python=${PYTHON} e installdeps: e/bin/python setup.py develop clean: rm -rf e As you can see this Makefile uses simple targets and variable substitution. Can this be achieved on Windows? By that mean - without having to install external tools (like cygwin make); perhaps make.cmd? Typing "make installdeps" for instance, should work both on Unix and Windows.

  Read the article

• Having my Python package install shortcuts in Start menu

  - by cool-RR

  I'm making a Python package that gets installed with a setup.py file using setuptools. The package includes a GUI, and when it's installed on a Windows machine, I want the installation to make a folder in "Programs" in the start menu, and make a shortcut there to a pyw script that will start the GUI. (The pyw think works on all platforms, right?) On Mac and Linux, I would like it to put this shortcut in whatever Mac and Linux have that is parallel to the start menu. How do I do this?

  Read the article

• libxml2 install error: command 'gcc' failed with exit status 1? What are the dependencies of libxml2

  - by SIA

  Hi everybody!! I am trying to install libxml2 on unbuntu 9.10 and getting errors: $ sudo python setup.py develop Its a very lengthy error message but the last error is Setup script exited with error: Command 'gcc' failed with exit status 1. Can anybody tell me why i am getting this error? What are the dependencies or libraries required to install this? scenario: I am trying to setup the reddit.com clone, and when i run develop command, its generating a huge error as stated above. Please help!! Thanks in advance And my many thanks to Stackoverflow team for having such a life saving site.

  Read the article

• Should I bundle C libraries with my Python application?

  - by oceanhug

  If I have a Python package that depends on some C libraries (like say the Gnu Scientific Library (GSL) for numerical computations), is it a good idea to bundle the library with my code? I'd like to make my package as easy to install as possible for users and I don't want them to have to download C libraries by hand and supply include-paths. Also I could always ensure that the version of the library that I ship is compatible with my code. However, is it possible that there are clashes if the user has the library installed already, or ar there any other reasons why I shouldn't do this? I know that I can make it easier for users by just providing a binary distribution, but I'd like to avoid having to maintain binary distributions for all possible OSs. So, I'd like to stick to a source distribution, but for the user (who proudly owns a C compiler) installation should be as easy as python setup.py install.

  Read the article

• How to find full module path of a class to import in other file

  - by Pooya

  I have method that returns module path of given class name def findModulePath(path, className): attributes = [] for root, dirs, files in os.walk(path): for source in (s for s in files if s.endswith(".py")): name = os.path.splitext(os.path.basename(source))[0] full_name = os.path.splitext(source)[0].replace(os.path.sep, '.') m = imp.load_module(full_name, *imp.find_module(name, [root])) try: attr = getattr(m, className) attributes.append(attr) except: pass if len(attributes) <= 0: raise Exception, "Class %s not found" % className for element in attributes: print "%s.%s" % (element.__module__, className) but it does not return the full path of the module, For example I have a python file named "objectmodel" in objects package,and it contains a Model class, So I call findModulePath(MyProjectPath,"Model"). it prints objectmodel.Model but I need objects.objectmodel.Model

  Read the article

• Django nose to run only project tests

  - by patroqueeet

  I added nose, django-nose, nose-exclude, coverage to my buildout.cfg and ran buildout. Furthermore I added the TEST_RUNNER and the NOSE_ARGS to my settings.py. In the last step I created a exclude_dirs.txt and included it into the NOSE_ARGS. That worked so far. Finally I ran bin/django testto run the tests of my project. I found out that every app inside INSTALLED_APP is run and that even parts of the django core models are run. How can I limit this to my project only without exernal packages?

  Read the article

• zeromq installtion on mac os snow leopard

  - by Ashish

  I have installed zeromq 2.1.11 on mac os x using the steps given on http://www.zeromq.org/area:download Then i installed pyzmq (python bindings ) But i get the following error : import zmq Traceback (most recent call last): File "<pyshell#1>", line 1, in <module> import zmq File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/zmq/__init__.py", line 35, in <module> from zmq.utils import initthreads # initialize threads ImportError: dlopen(/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/zmq/utils/initthreads.so, 2): no suitable image found. Did find: /Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/zmq/utils/initthreads.so: no matching architecture in universal wrapper

  Read the article

• Can I turn off implicit Python unicode conversions to find my mixed-strings bugs?

  - by Tal Weiss

  When profiling our code I was surprised to find millions of calls to C:\Python26\lib\encodings\utf_8.py:15(decode) I started debugging and found that across our code base there are many small bugs, usually comparing a string to a unicode or adding a sting and a unicode. Python graciously decodes the strings and performs the following operations in unicode. How kind. But expensive! I am fluent in unicode, having read Joel Spolsky and Dive Into Python... I try to keep our code internals in unicode only. My question - can I turn off this pythonic nice-guy behavior? At least until I find all these bugs and fix them (usually by adding a u'u')? Some of them are extremely hard to find (a variable that is sometimes a string...). Python 2.6.5 (and I can't switch to 3.x).

  Read the article

• How to use traceit to report function input variables in stack trace

  - by reckoner

  Hi, I've been using the following code to trace the execution of my programs: import sys import linecache import random def traceit(frame, event, arg): if event == "line": lineno = frame.f_lineno filename = frame.f_globals["__file__"] if filename == "<stdin>": filename = "traceit.py" if (filename.endswith(".pyc") or filename.endswith(".pyo")): filename = filename[:-1] name = frame.f_globals["__name__"] line = linecache.getline(filename, lineno) print "%s:%s:%s: %s" % (name, lineno,frame.f_code.co_name , line.rstrip()) return traceit def main(): print "In main" for i in range(5): print i, random.randrange(0, 10) print "Done." sys.settrace(traceit) main() Using this code, or something like it, is it possible to report the values of certain function arguments? In other words, the above code tells me "which" functions were called and I would like to know "what" the corresponding values of the input variables for those function calls. Thanks in advance.

  Read the article

• How do I get the path of the current executed file in python?

  - by Sorin Sbarnea

  This may seam a newbie question but it is not. It looks that common approaches are not always working: Currently I know only two options but none of them looks to work an all cases. sys.argv[0] This means using path = os.path.abspath(os.path.dirname(sys.argv[0])) but this does not work if you are running from another python script from another directory, and this can really happen in real life. __file__ this means that path = os.path.abspath(os.path.dirname(__file__)) but I found that this doesn't work: py2exe that doesn't have a __file__ attribute but there is an workaround. when you run from IDLE with execute() there is no __file__ attribute OS X 10.6 where I get NameError: global name '__file__' is not defined Related questions with incomplete answers: http://stackoverflow.com/questions/1296501/python-find-path-to-file-being-run http://stackoverflow.com/questions/1483827/python-path-to-current-file-depends-on-how-i-execute-the-program http://stackoverflow.com/questions/2259503/how-to-know-the-path-of-the-running-script-in-python http://stackoverflow.com/questions/509742/python-chdir-to-dir-the-py-script-is-in

  Read the article

• urlopen error [errno 111] connection refused

  - by Ui-Gyun Jeong

  I am doing python exercise with a book 'headfirst python' and making android app by using python and sl4a my code is import android import json import time from urllib import urlencode from urllib2 import urlopen hello_msg = "Welcome to Coach Kelly's Timing App" list_title = 'Here is your list of athletes:' quit_msg = "Quitting Coach Kelly's App." web_server = 'http://127.0.0.1:8080' get_names_cgi = '/cgi-bin/generate_name.py' def send_to_server(url, post_data=None): if post_data: page = urlopen(url, urlencode(post_data)) else: page = urlopen(url) return(page.read().decode("utf8")) app = android.Android() def status_update(msg, how_long=2): app.makeToast(msg) time.sleep(how_long) status_update(hello_msg) athlete_names = sorted(json.loads(send_to_server(web_server + get_names_cgi))) app.dialogCreateAlert(list_title) app.dialogSetSingleChoiceItems(athlete_names) app.dialogSetPositiveButtonText('Select') app.dialogSetNegativeButtonText('Quit') app.dialogShow() resp = app.dialogGetResponse().result status_update(quit_msg) this is my code and the result is what is the problem??? I can not figure out what the problem is...

  Read the article

• Django equivalent to paster for backend processes

  - by intractelicious

  I use pylons in my job, but I'm new to django. I'm making an rss filtering application, and so I'd like to have two backend processes that run on a schedule: one to crawl rss feeds for each user, and another to determine relevance of individual posts relative to users' past preferences. In pylons, I'd just write paster commands to update the db with that data. Is there an equivalent in django? EG is there a way to run the equivalent of python manage.py shell in a non-interactive mode?

  Read the article

• Running "source" from python

  - by R S

  Hello, I have a file a.txt with lines of commands I want to run, say: echo 1 echo 2 echo 3 If I was on csh (unix), I would have done source a.txt and it would run. From python I want to run os.execl with it, however I get: >>> os.execl("source", "a.txt") Traceback (most recent call last): File "<stdin>", line 1, in <module> File "/usr/lib/python2.5/os.py", line 322, in execl execv(file, args) OSError: [Errno 2] No such file or directory How to do it?

  Read the article

• Halting Django's dev server via page request?

  - by Ben Blank

  I'm looking at writing a portable, light-weight Python app. As the "GUI toolkit" I'm most familiar with — by a wide margin! — is HTML/CSS/JS, I thought to use Django as a framework for the project, using its built-in "development server" (manage.py runserver). I've been banging on a proof-of-concept for a couple hours and the only real problem I've encountered so far is shutting down the server once the user has finished using the app. Ideally, I'd like there to be a link on the app's pages which shuts down the server and closes the page, but nothing I see in the Django docs suggests this is possible. Can this be done? For that matter, is this a reasonable approach for writing a small, portable GUI tool?

  Read the article

• django url tag performance

  - by zxygentoo

  I was trying to integrate django-voting into my project following the RedditStyleVoting instruction. In my urls.py, i did something like this: url(r'^sections/(?P<object_id>\d+)/(?P<direction>up|down|clear)vote/?$', vote_on_object, dict( model=Section, template_object_name='section', template_name='script/section_confirm_vote.html', allow_xmlhttprequest=True ), name="section_vote", then, in my template: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} It takes over 1.3s to load the page, but by hard coding it like this: {% vote_by_user user on section as vote %} {% score_for_object section as score %} {{ score.score|default:0 }} I got 50ms. Just avoid the url tag resolving stuff I got a 20+ times performance improvement. Is there something I did wrong? If not, then what's the best practice here, should we do things the right way or the fast way?

  Read the article

• Django colon syntax in template tags: only in newer versions?

  - by Alan

  I just deployed an application to a new server, and although I'm using virtualenv, I had to install a new environment on the production server, which has a different architecture. Anyway, I received no TemplateSytaxErrors in development, but on the production server, I get: Exception Type: TemplateSyntaxError Exception Value: Caught SyntaxError while rendering: invalid syntax (views.py, line 25) The offending line is: {% url admin:password_change as password_change_url %} Upon removing that line, the TemplateSyntaxError hops to the next line that has a colon in it (and lets other template tags work fine). So my question is this: is there some discrepancy in versions of Python/Django that would allow or disallow the namespacing syntax? The template tags are in django-grappelli (http://code.google.com/p/django-grappelli/), so I'd rather not go through their code and rewrite all the template tags. Development server: 32-bit Debian Python 2.5.5 Django 1.2.1 Production server: 64-bit CentOS Python 2.4.3 Django 1.2.1 Any ideas?

  Read the article

< Previous Page | 82 83 84 85 86 87 88 89 90 91 92 93  | Next Page >