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  • How to get a list of users for all instance's databases

    - by stee1rat
    I guess the procedure should be something like this: declare @db varchar(100) declare @user varchar(100) declare c cursor for select name from sys.sysdatabases open c fetch next from c into @db while @@fetch_status = 0 begin print @db exec ('use ' + @db) declare u cursor for select name from sys.sysusers where issqlrole <> 1 and hasdbaccess <> 0 and isntname <> 1 open u fetch next from u into @user while @@fetch_status = 0 begin print @user fetch next from u into @user end print '--------------------------------------------------' close u deallocate u fetch next from c into @db end close c deallocate c But the problem is that exec ('use ' + @db) doesn't work. And i always get user list of currently chosen database. How should i fix that? P.S.: I want this code to work on both 2000 and 2005 sql servers.

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  • Javascript: why I cannot load my external js page in Drupal ?

    - by Patrick
    hi, when I add the tag script to load an external javascript file, my page is not longer displayed. There are not error in Firebug, there are not errors such as "File not found" or "Not enough permissions", the browser just displays a blank page for some reason. <?php print $head; ?> <?php print $styles; ?> <?php print $scripts; ?> <script type="text/JavaScript" src="main.js" /> If I remove the last line everything works perfectly. The previous php lines are the standard Drupal head lines. This is the content of my js file: $(document).ready( function() { alert("hello"); }); thanks

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  • Loop through collections

    - by ScG
    I have two classes class A { public string something { get; set; } public IList<B> b= new List<B>(); } class B { public string else { get; set; } public string elseelse { get; set; } } I have populated an object of class A called obj. How can I loop through this object and print values. Do I have to use two foreach's like the one show here or is there a better way? foreach (var z in obj) { // print z.something; foreach (var x in z.b) { // print x.elseelse; } }

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  • Why is the value of __name__ changing after assignment to sys.modules[__name__]?

    - by martineau
    While trying to do something similar to what's in the ActiveState recipe titled Constants in Python by Alex Martelli, I ran into an unexpected side-effect that assigning a class instance to an entry in sys.modules apparently has in Python 2.7 -- namely that doing so apparent changes the value of __name__ to None as illustrated in the following code fragment: class _test(object): pass import sys print '__name__: %r' % __name__ # __name__: '__main__' sys.modules[__name__] = _test() print '__name__: %r' % __name__ # __name__: None if __name__ == '__main__': # never executes... import test print "done" I'd like to understand why this is happening. I don't believe it was that way in Python 2.6 and earlier versions since I have some older code where apparently the if __name__ == '__main__': conditional worked as expected following the assignment (but no longer does). FWIW, I also noticed that the name _class is getting rebound from a class object to None, too, after the assignment. Also seems odd to me that they're being rebound to 'None' rather than disappearing altogether... Update: I'd like to add that any workarounds for achieving the effect of if __name__ == '__main__':, given what happens would be greatly appreciated. TIA!

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  • Deferred printing in Java

    - by Bober02
    I have a specific issue with general console printing and I was wondering whether anyone has a solution for it. I am trying to print a dataTable which would look like sth like this: Table ---------------------- Name |Surname | ---------------------- Mike |Mikhailowish| Rafaello|Mirena | and so on. In order to print the border of the bar I need to know what the maximum length of each column value is. I don't want to go through the whole database to find that out and then again to print it. I would rather like to do sth like: System.out.printLater(s); //herejust leave a pointer to a StringBuilder you will build ... s.append("--------"); ... System.out.printAllDeferred(); I understand the above is probably in 99.99999% chances impossible, but perhaps you guys have a clever way of achieving the above?

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  • How to get "printer ready bytes" from a source in c#?

    - by luis_villase
    Hey everyone! I'm in a bit of trouble here, hoping you can help a fellow programmer out. I have an application that receives a pointer to raw bytes (plus length and stuff) and sends said raw data to a printer. This is important, I have no choice but to use this method to get any printing done. If I send a raw string, it will print with no problem. However, I need to be able to print formatted text, images, etc. So the thing is... I would like to be able to get printer ready bytes from a given source (maybe a pdf, or html, does not matter as long as it contains formatted text and/or images). It would be like "splitting" the print command like so: a) Open file and read data b) Load printer data into memory c) Send bytes to printer Obviously, I've got a) and c) covered, it's b) the one that's breaking my head. Any thoughts? Thanks in advance for your help.

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  • What could cause a returning function to crash? C++

    - by JeanOTF
    So I have been debugging this error for hours now. I writing a program using Ogre3d relevant only because it doesn't load symbols so it doesn't let me stack trace which made finding the location of the crash even harder. So, write before I call a specific function I print out "Starting" then I call the function and immediately after I print "Stopping". Throughout the function I print out letters A-F where F is printed right before the function returns (one line above the last '}') The weird thing is when the crash occurs it is after the 'F' is printed but there is no 'Stopping'. Does this mean that the crash is happening in between somewhere? The only thing I can think of is something going wrong during the deallocation of some of the memory allocated during the function. I've never had anything happen like this, I will keep checking to make sure it's going wrong where I think it is.

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  • Flattening hash into string in Ruby

    - by fahadsadah
    Is there a way to flatten a hash into a string, with optional delimiters between keys and values, and key/value pairs? For example, print {:a => :b, :c => :d}.flatten('=','&') should print a=b&c=d I wrote some code to do this, but I was wondering if there was a neater way: class Hash def flatten(keyvaldelimiter, entrydelimiter) string = "" self.each do |key, value| key = "#{entrydelimiter}#{key}" if string != "" #nasty hack string += "#{key}#{keyvaldelimiter}#{value}" end return string end end print {:a => :b, :c => :d}.flatten('=','&') #=> 'c=d&a=b' Thanks

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  • How to convert ms access data into pdf in vb.net

    - by user225269
    I want to convert the ms access data into a document so that the print function in vb.net will read it. Where do I start from here? Here is my form: http://screencast.com/t/MGU4N2UyNmY And here is the code for print preview. Try PrintPreviewDialog1.ShowDialog() Catch es As Exception MessageBox.Show(es.Message) End Try How do I incorporate the above code, to the code below so that there is something that can be seen when I hit the print button? Dim cn As New OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=C:\search.mdb") Dim cmd As OleDbCommand = New OleDbCommand("Select * from GH where NAME= '" & TextBox6.Text & "' ", cn) cn.Open() Dim rdr As OleDbDataReader rdr = cmd.ExecuteReader If rdr.HasRows Then rdr.Read() NoAcc = rdr("NAME") If (TextBox6.Text = NoAcc) Then TextBox1.Text = rdr("IDNUMBER") If (TextBox6.Text = NoAcc) Then TextBox7.Text = rdr("DEPARTMENT") If (TextBox6.Text = NoAcc) Then TextBox8.Text = rdr("COURSE") End If Please help,thanks

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  • Output custom messages based on row value

    - by decimal
    I've made a simple guestbook mysql/php page. An entry is displayed if the approve column has a value of 1. For the adminstrator, I want to display either "message approved" or "not approved". Here's my code: while ($row = mysql_fetch_array ($r)) { print "<p>Guest:" .$row['name']. "</p> <p>Date:" .$row['date']. "</p> <p>Comment:". $row['comment']. "</p>"; if ($row['approve'] = '1') { print '<p>YES, the message has been approved</p>'; } else { print '<p>NO, it hasn\'t been approved</p>'; } Whatever value the if statement checks approve is equal to, all approve values are output as that value.

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  • How do I tell gdb how long my zero-length array is?

    - by Joe
    Slightly oxymoronic title! Bonus points for Xcode answer but it's a gdb question. If I have a standard, statically sized array gdb will print all its elements [and Xcode will let me browse through it] but if I have a zero length array, it won't, because it doesn't know. Obviously I can print the array indexes one by one, but I'd like a dump of the whole thing. How do I tell gdb how much space I have allocated for the array to allow it to print the array (or to allow Xcode to view the array). Is it even possible?

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  • how to make this piece of code work in C++?

    - by cambr
    #include<stdio.h> void print(int *arr[], int s1, int s2) { int i, j; printf("\n"); for(i = 0; i<s1; i++) { for(j = 0; j<s2; j++) { printf("%d, ", *((arr+i)+j)); } } printf("\n"); } int main() { int a[4][4] = {{0}}; print(a,4,4); } This works in C, but not in C++. error: cannot convert `int (*)[4]' to `int**' for argument `1' to `void print(int**, int, int)' Why does it not work in C++? What change is needed to be made?

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  • Reason for unintuitive UnboundLocalError behaviour 2

    - by Jonathan
    Following up on Reason for unintuitive UnboundLocalError behaviour (I will assume you've read it). Consider the following Python script: def f(): # a+=1 # 1 aa=a aa+=1 # b+='b' # 2 bb=b bb+='b' c[0]+='c' # 3 c.append('c') cc=c cc.append('c') # 4 a=1 b='b' c=['c'] f() print a print b print c The result of the script is: 1 b ['cc', 'c', 'c'] The commented out lines (marked 1,2) are lines that would through an UnboundLocalError and the SO question I referenced explains why. However, the line marked 3 works! By default, lists are copied by reference in Python, therefore it's understandable that c changes when cc changes. But why should Python allow c to change in the first place, if it didn't allow changes to a and b directly from the method's scope? I don't see how the fact that by default lists are copied by reference in Python should make this design decision inconsistent. What am I missing folks?

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  • SqlAlchemy hangs after adding record in MS SQL

    - by Patrick
    I'm running SQLAlchemy on Jython and trying to connect to a MS SQL database using jTDS with windows authentication. I can query and delete just fine but when I try to insert new values it will hang when I commit. int 'before add' session.add(newVal) print 'after add' session.commit() print 'after commit' I see the first two print statements but not the last. My CPU maxes out and I can't even query the table directly using the MS SQL Management Studio. When I kill the Jython java process I can query again but the new values haven't been added. Strangely enough I can insert values directly using an SQL command: insert_sql = "INSERT INTO my_table (my_value) VALUES ('test_value')" session.execute(insert_sql) session.commit() Any ideas what I'm doing wrong?

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  • How to get variable value from inside a stored procedure in DB2?

    - by Sylvia
    This seems like it should be very easy...anyway, it is in MS SQL Server In a DB2 stored procedure, how can I just get the value of a variable? Say I have the following stored procedure: CREATE PROCEDURE etl.TestABC( ) LANGUAGE SQL BEGIN declare Stmt varchar(2048); set Stmt = 'this is a test'; -- print Stmt; -- select Stmt; return 0; END @ I'd like to print out the value of Stmt after I set it. Print doesn't work, select doesn't work. Somebody said I have to insert it to a table first, and then get it after I run the stored procedure. Is this really necessary? Thanks, Sylvia EDIT: I should have made clearer that I want to see the value of Stmt each time after I set it, and I may need to set it multiple times within the same stored procedure.

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  • Perl Matching ,Extracting , and printing emails

    - by user3448790
    How do I match an email using the The Official Standard: RFC 5322 in a html source code, after that i will extract the strings that are matched ONLY, and print out inly the emails, and not the whole source code? Is there any examples and output to illustrate this? Thnaks! elsif ($_ eq '-dDATA' or $_ eq '-ft') { opendir(DIR,'DATA'); my(@dir) = grep /\.htm/, readdir (DIR); closedir(DIR); my $value = join(@dir); print "$value\n"; foreach my $movies (@dir) { open (my $FHD, "<", "DATA/$movies") || die $!; print <$FHD>; } } }

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  • Crystal Report | Printing | Default Printer

    - by Akshay J
    I am making one application where user will print invoices which I am displaying using Crystal Report. The user showed me his current application made using ForPro. In that application, under Printer Options form, one can see all the printers currently installed and the user could select default printer. When the invoice is made, the user presses the print button, then there is one dialog asking for no. of copies. When it's entered, the invoice gets printed directly, without any Print Dialog Box. If the user wants to change the printer again he/she will change it in the Printer Option form. I want to know if similar thing is possible in Crystal Report and need guidance on how to approach for it.

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  • How to get a variable name as a string in Python?

    - by e-satis
    I would like to be able to get the name of a variable as a string but I don't know if Python has that much introspection capabilities. Something like: >>> print(my_var.__name__) 'my_var' I want to do that because I have a bunch of vars I'd like to turn into a dictionary like : bar=True foo=False >>> my_dict=dict(bar=bar, foo=foo) >>> print mydict >>> print my_dict {'foo': False, 'bar': True} But I'd like something more automatic than that. Python have locals() and vars(), so I guess there is a way.

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  • undefined index mode, which is the variable that case statement is looking for

    - by Brad
    receiving error: PHP Notice: Undefined index: mode in /web/ee_web/include/form-modal.php on line 51 line 51 switch($_GET["mode"]) { block of code it is in: switch($_GET["mode"]) { case "login": login_user(); break; case "logout": session_destroy(); print "<p>You are now logged out.</p>"; print "<p><input type=\"submit\" id=\"closeButton\" name=\"closeButton\" value=\"Close\" onclick=\"self.parent.tb_remove(); parent.location.reload(1);\" /></p>"; break; default: login_user(); //print "<p>How'd you end up here?</p>"; break; } The URL for the page is index.php?mode=logout, that is how I am passing the value into mode. Any way I could resolve this error message?

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  • Help me with Php session vs Header redirect?

    - by python
    I have the following pages: *page1.php <?php if (isset($_GET['link'])) { session_start(); $_session['myvariable'] = 'Hello World'; header('Location: http://' . $_SERVER['SERVER_NAME'] . dirname($_SERVER['REQUEST_URI']) . '/page2.php'); exit; } ?> <a href="<?php print $_SERVER['REQUEST_URI'] . '?link=yes';?>">Click Here</a> *page2.php <?php print 'Here is page two, and my session variable: '; session_start(); print $_session['myvariable']; //This line could not output. exit; ?> When I try output $_session['myvariable'] I did not get the result hello world message. I could not find out the solution to fix it .?

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  • Java input Letter

    - by xyvyre
    I'm doing an java activity that if Name start with letter A-G and Ends with Letter H-z the output is invalid heres my code: System.out.print("Enter your name: "); String str = in.readLine(); if(str.startsWith("a" )){ System.out.print("INVALID!"); } if(str.endsWith("h")){ System.out.print("INVALID!"); } This works but how can i implement letter a to g and h to z i already try this [a-g] and it not WORK!

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  • C++ template specialization

    - by user231536
    I have a class template <typename T> class C { static const int K=1; static ostream& print(ostream& os, const T& t) { return os << t;} }; I would like to specialize C for int. //specialization for int template <> C<int>{ static const int K=2; } I want the default print method that works for int to remain and just change the constant. For some specializations, I want to keep K=1 and change the print method because there is no << operator. How do I do this?

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  • Can Perl detect arrays?

    - by Sandra Schlichting
    I have this script #!/usr/bin/perl use warnings; use strict; use Data::Dumper; my %x1 = (); $x1{"a"} = "e"; my %x2 = (); $x2{"a"} = ["b","c"]; p(\%x1); p(\%x2); sub p { my $x = shift @_; print $x->{a}; print "\n"; } which outputs e ARRAY(0x2603fa0) The problem is I don't know when the input is an array or a scalar, and when it is an array I would like to print those values as well. Can p be modified to do this?

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  • Number guessing game (3+- guessed result)

    - by Nick Waring
    I've been assigned a task to create a game that generates 4 digits and the user has to guess the digits one at a time to get the correct result. If the number is correct a Y is displayed and if not, a N. This was easy, now the next step was to implement another two responses. If the answer is too high, a H is displayed and too low, an N. Again, was easy - now the third is to use the same design as game 2 but if the number is 3 higher than a H is displayed and same if it's 3 lower than a L is displayed - otherwise an X is displayed. I can't figure out how to do this. Here's my test code for game 2 for just one of the digits - any help is appreciated. (5 was used just for a test.) def guess(): x = 5 g= int(input("Guess the number: ")) if g == x: print("Y") elif g < x: print("L") else: print("H")

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  • list within a list

    - by atm atm
    I'm working on this problem, but I cannot figure out the second part. I tried using reverse list but it did not work out how I planned it. Given a list L (e.g. [1,2,3,4]), write a program that generates the following nested lists: L1 = [[1],[1,2],[1,2,3],[1,2,3,4]], L2 = [[4],[3,4],[2,3,4],[1,2,3,4]]. My code that I have so far: mylist=[,1,2,3,4] print("Orginal list L=",mylist) n=len(mylist) l1=[] l2=[] for x in range(1,n+1,1): l1.append(mylist[0:x]) print("L1=",l1) #prints final product of l1 mylist.reverse() #this is where i get messed up for x in range(1,n+1,1): l2.append(mylist[0:x]) print("L2=",l2)

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