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  • one to many jpa relationship

    - by user309944
    Hai I have created two table first table as student package com.crimson.rship; import javax.persistence.Basic; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.Id; import javax.persistence.OneToMany; @Entity(name="student") public class student { @Id private String stumailid; @Basic private String fathername; @Basic private String mothername; @Basic private String doa; @Basic private String dob; public student(String stumailid,String fathername,String mothername,String doa,String dob) { // TODO Auto-generated constructor stub this.stumailid=stumailid; this.fathername=fathername; this.mothername=mothername; this.doa=doa; this.dob=dob; } public void setStumailid(String stumailid) { this.stumailid = stumailid; } public String getStumailid() { return stumailid; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } public void setMothername(String mothername) { this.mothername = mothername; } public String getMothername() { return mothername; } public void setDoa(String doa) { this.doa = doa; } public String getDoa() { return doa; } public void setDob(String dob) { this.dob = dob; } public String getDob() { return dob; } } Second table as mark package com.crimson.rship; import java.util.Collection; import javax.persistence.Basic; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.OneToMany; @Entity(name="mark") public class mark { @Id private String stumailid; @Basic private String fathername; @Basic private String mothername; @OneToMany(mappedBy="mark",targetEntity=student.class,fetch=FetchType.EAGER) private Collection orders; public mark(String stumailid,String fathername,String mothername) { // TODO Auto-generated constructor stub this.stumailid=stumailid; this.fathername=fathername; this.mothername=mothername; } public void setStumailid(String stumailid) { this.stumailid = stumailid; } public String getStumailid() { return stumailid; } public void setFathername(String fathername) { this.fathername = fathername; } public String getFathername() { return fathername; } public void setMothername(String mothername) { this.mothername = mothername; } public String getMothername() { return mothername; } public void setOrders(Collection orders) { this.orders = orders; } public Collection getOrders() { return orders; } } But this above coding working is not working correctly.can any one help me Thanks in advance

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  • Will this ever result in a stack overflow error?

    - by David
    Will incrementing the instance variables of an object ever lead to a stack overflow error? For example: This method (java) will cause a stack overflow error: class StackOverflow { public static void StackOverflow (int x) { System.out.println (x) ; StackOverflow(x+1) ; } public static void main (String[]arg) { StackOverflow (0) ; } but will this?: (..... is a gap that i've put in to shorten the code. its long enough as it is.) import java.util.*; class Dice { String name ; int x ; int[] sum ; .... public Dice (String name) { this.name = name ; this.x = 0 ; this.sum = new int[7] ; } .... public static void main (String[] arg) { Dice a1 = new Dice ("a1") ; for (int i = 0; i<6000000; i++) { a1.roll () ; printDice(a1) ; } } .... public void roll () { this.x = randNum(1, this.sum.length) ; this.sum[x] ++ ; } public static int randNum (int a, int b) { Random random = new Random() ; int c = (b-a) ; int randomNumber = ((random.nextInt(c)) + a) ; return randomNumber ; } public static void printDice (Dice Dice) { System.out.println (Dice.name) ; System.out.println ("value: "+Dice.x) ; printValues (Dice) ; } public static void printValues (Dice Dice) { for (int i = 0; i<Dice.sum.length; i++) System.out.println ("#of "+i+"'s: "+Dice.sum[i]) ; } } The above doesn't currently cause a stack overflow error but could i get it too if i changed this line in main: for (int i = 0; i<6000000; i++) so that instead of 6 million something sufficiently high were there?

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  • how get xml responce using JAX-WS SOAP handler

    - by khris
    I have implemented web service: @WebServiceClient(//parameters//) @HandlerChain(file = "handlers.xml") public class MyWebServiceImpl {...} Also I have implemented ObjectFactory with list of classes for creating my requests and responses. For Example class Test. I need to get xml of response. I try to use JAX-WS SOAP handler, so I add this @HandlerChain(file = "handlers.xml") anotation. My handlers.xml looks like: <?xml version="1.0" encoding="UTF-8"?> <handler-chains xmlns="http://java.sun.com/xml/ns/javaee"> <handler-chain> <handler> <handler-class>java.com.db.crds.ws.service.LoggingHandler</handler-class> </handler> </handler-chain> </handler-chains> My LoggingHandler class is: import java.io.PrintWriter; import java.util.Set; import javax.xml.namespace.QName; import javax.xml.soap.SOAPMessage; import javax.xml.ws.handler.MessageContext; import javax.xml.ws.handler.soap.SOAPMessageContext; public class LoggingHandler implements javax.xml.ws.handler.soap.SOAPHandler<SOAPMessageContext> { public void close(MessageContext messagecontext) { } public Set<QName> getHeaders() { return null; } public boolean handleFault(SOAPMessageContext messagecontext) { return true; } public boolean handleMessage(SOAPMessageContext smc) { Boolean outboundProperty = (Boolean) smc.get (MessageContext.MESSAGE_OUTBOUND_PROPERTY); if (outboundProperty.booleanValue()) { System.out.println("\nOutbound message:"); } else { System.out.println("\nInbound message:"); } SOAPMessage message = smc.getMessage(); try { PrintWriter writer = new PrintWriter("soap_responce" + System.currentTimeMillis(), "UTF-8"); writer.println(message); writer.close(); message.writeTo(System.out); System.out.println(""); // just to add a newline } catch (Exception e) { System.out.println("Exception in handler: " + e); } return outboundProperty; } } I have test class which creates request, here are part of code: MyWebServiceImpl impl = new MyWebServiceImpl(url, qName); ws = impl.getMyWebServicePort(); Test req = new Test(); I suppose to get xml response in file "soap_responce" + System.currentTimeMillis(). But such file isn't even created. Please suggest how to get xml response, I'm new to web services and may do something wrong. Thanks

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  • Help with listView in Android

    - by jul
    Hi, I'm just starting with Android and can't find how to display a list in my activity. I get some restaurant data from a web service and I'd like to show the results in a list. The activity, the restaurant class and the layout main.xml are shown below. How can I display, for instance, the list of the restaurant names in the ListView 'list' of my layout? thank you Jul public class Atable extends ListActivity { RestaurantList restaurantList; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); //Here I set restaurantList //Now how can I display, for example, the list of the names of the restaurants } main.xml <LinearLayout android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content"> <TextView android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/search" /> <EditText android:id="@+id/search" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_weight="1"/> </LinearLayout> <LinearLayout android:orientation="vertical" android:layout_width="wrap_content" android:layout_height="wrap_content"> <ListView android:id="@+id/android:list" android:layout_width="wrap_content" android:layout_height="wrap_content"/> <TextView android:id="@+id/android:empty" android:layout_width="wrap_content" android:layout_height="wrap_content" android:text="@string/noresults"/> </LinearLayout> </LinearLayout> Restaurant list class package org.digitalfarm.atable; import java.util.List; public class RestaurantList { private List<Restaurant> restaurants; public List<Restaurant> getRestaurants() { return restaurants; } public void setRestaurants(List<Restaurant> restaurants) { this.restaurants = restaurants; } } Restaurant class package org.digitalfarm.atable; public class Restaurant { private String name; private float latitude; private float longitude; public String getName() { return name; } public void setName(String name) { this.name = name; } public float getLatitude() { return latitude; } public void setLatitude(float latitude) { this.latitude = latitude; } public float getLongitude() { return longitude; } public void setLongitude(float longitude) { this.longitude = longitude; } }

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  • propertyplaceholderconfigurer class name substitution problem

    - by Alex
    The following example works for "class name substitution using the PropertyPlaceHolderConfigurer": http://forum.springsource.org/showpost.php?p=228136&postcount=2 HOWEVER, when porting this code over (messages.properties, com.spring.ioc.TestClass, and spring-config.xml) to a web application, the class name substitution now fails! 1) I am running on the webapp on Tomcat through the Eclipse plugin. 2) In the web.xml I have the following: <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/spring-config.xml</param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> 3) The following is output in the log: 282 [main] DEBUG org.springframework.beans.factory.support.DefaultListableBeanFactory - Ignoring bean class loading failure for bean 'test' org.springframework.beans.factory.CannotLoadBeanClassException: Cannot find class [${test.class}] for bean with name 'test' defined in ServletContext resource [/WEB-INF/spring-config.xml]; nested exception is java.lang.ClassNotFoundException: ${test.class} at org.springframework.beans.factory.support.AbstractBeanFactory.resolveBeanClass(AbstractBeanFactory.java:1141) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.predictBeanType(AbstractAutowireCapableBeanFactory.java:524) at org.springframework.beans.factory.support.AbstractBeanFactory.isFactoryBean(AbstractBeanFactory.java:1177) at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBeanNamesForType(DefaultListableBeanFactory.java:222) at org.springframework.context.support.AbstractApplicationContext.invokeBeanFactoryPostProcessors(AbstractApplicationContext.java:505) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:362) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45) at org.apache.catalina.core.StandardContext.listenerStart(StandardContext.java:3795) at org.apache.catalina.core.StandardContext.start(StandardContext.java:4252) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1014) at org.apache.catalina.core.StandardHost.start(StandardHost.java:736) at org.apache.catalina.core.ContainerBase.start(ContainerBase.java:1014) at org.apache.catalina.core.StandardEngine.start(StandardEngine.java:443) at org.apache.catalina.core.StandardService.start(StandardService.java:448) at org.apache.catalina.core.StandardServer.start(StandardServer.java:700) at org.apache.catalina.startup.Catalina.start(Catalina.java:552) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.apache.catalina.startup.Bootstrap.start(Bootstrap.java:295) at org.apache.catalina.startup.Bootstrap.main(Bootstrap.java:433) Caused by: java.lang.ClassNotFoundException: ${test.class} at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1438) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1284) at org.springframework.util.ClassUtils.forName(ClassUtils.java:211) at org.springframework.beans.factory.support.AbstractBeanDefinition.resolveBeanClass(AbstractBeanDefinition.java:385) at org.springframework.beans.factory.support.AbstractBeanFactory.resolveBeanClass(AbstractBeanFactory.java:1138) ... 23 more Note: I haven't included it, but the PropertyPlaceHolderConfigurer is successfully locating the messages.properties file, but this seems to happen AFTER the above error is output?! DOES ANYBODY KNOW WHY THIS IS THE CASE AND HOW I CAN OVERCOME THIS PROBLEM?

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  • j2me bluetooth client. Function startInquiry nothing found.

    - by Hugi
    I develop simple j2me bluetooth client and have problem with bluetooth device search. Function startInquiry nothing found. Client : nokia 5220 Server : my pc with bluetooth adapter All bluetooth devices is on. /* * To change this template, choose Tools | Templates * and open the template in the editor. */ import javax.microedition.midlet.*; import javax.bluetooth.*; import java.util.Vector; import javax.microedition.lcdui.*; /** * @author ????????????? */ public class Midlet extends MIDlet implements DiscoveryListener { private static Vector vecDevices=new Vector(); private static String connectionURL=null; private LocalDevice localDevice; private DiscoveryAgent agent; private RemoteDevice remoteDevice; private RemoteDevice[] devList; private Display display; private Form form; public void startApp() { display = Display.getDisplay(this); form = new Form( "Client" ); try { localDevice = LocalDevice.getLocalDevice(); } catch( BluetoothStateException e ) { e.printStackTrace(); } form.append("Address: "+localDevice.getBluetoothAddress()+"\n\n"); form.append("Name: "+localDevice.getFriendlyName()+"\n\n"); try { agent = localDevice.getLocalDevice().getDiscoveryAgent(); form.append("Starting device inquiry... \n\n"); boolean si = agent.startInquiry(DiscoveryAgent.GIAC, this); if ( si ) { form.append("true"); } else { form.append("false"); } } catch( BluetoothStateException e ) { } int deviceCount = vecDevices.size(); if(deviceCount <= 0){ form.append("No Devices Found ."); } else{ //print bluetooth device addresses and names in the format [ No. address (name) ] form.append("Bluetooth Devices: "); for (int i = 0; i < deviceCount; i++) { remoteDevice=(RemoteDevice)vecDevices.elementAt(i); form.append( remoteDevice.getBluetoothAddress() ); } } display.setCurrent(form); } public void pauseApp() { } public void destroyApp(boolean unconditional) { } public void deviceDiscovered(RemoteDevice btDevice, DeviceClass cod) { //add the device to the vector if(!vecDevices.contains(btDevice)){ vecDevices.addElement(btDevice); } } public void inquiryCompleted(int discType) { } //implement this method since services are not being discovered public void servicesDiscovered(int transID, ServiceRecord[] servRecord) { if(servRecord!=null && servRecord.length>0){ connectionURL=servRecord[0].getConnectionURL(0,false); } } //implement this method since services are not being discovered public void serviceSearchCompleted(int transID, int respCode) { } }

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  • What to Expect in Rails 4

    - by mikhailov
    Rails 4 is nearly there, we should be ready before it released. Most developers are trying hard to keep their application on the edge. Must see resources: 1) @sikachu talk: What to Expect in Rails 4.0 - YouTube 2) Rails Guides release notes: http://edgeguides.rubyonrails.org/4_0_release_notes.html There is a mix of all major changes down here: ActionMailer changes excerpt: Asynchronously send messages via the Rails Raise an ActionView::MissingTemplate exception when no implicit template could be found ActionPack changes excerpt Added controller-level etag additions that will be part of the action etag computation Add automatic template digests to all CacheHelper#cache calls (originally spiked in the cache_digests plugin) Add Routing Concerns to declare common routes that can be reused inside others resources and routes Added ActionController::Live. Mix it in to your controller and you can stream data to the client live truncate now always returns an escaped HTML-safe string. The option :escape can be used as false to not escape the result Added ActionDispatch::SSL middleware that when included force all the requests to be under HTTPS protocol ActiveModel changes excerpt AM::Validation#validates ability to pass custom exception to :strict option Changed `AM::Serializers::JSON.include_root_in_json' default value to false. Now, AM Serializers and AR objects have the same default behaviour Added ActiveModel::Model, a mixin to make Ruby objects work with AP out of box Trim down Active Model API by removing valid? and errors.full_messages ActiveRecord changes excerpt Use native mysqldump command instead of structure_dump method when dumping the database structure to a sql file. Attribute predicate methods, such as article.title?, will now raise ActiveModel::MissingAttributeError if the attribute being queried for truthiness was not read from the database, instead of just returning false ActiveRecord::SessionStore has been extracted from Active Record as activerecord-session_store gem. Please read the README.md file on the gem for the usage Fix reset_counters when there are multiple belongs_to association with the same foreign key and one of them have a counter cache Raise ArgumentError if list of attributes to change is empty in update_all Add Relation#load. This method explicitly loads the records and then returns self Deprecated most of the 'dynamic finder' methods. All dynamic methods except for find_by_... and find_by_...! are deprecated Added ability to ActiveRecord::Relation#from to accept other ActiveRecord::Relation objects Remove IdentityMap ActiveSupport changes excerpt ERB::Util.html_escape now escapes single quotes ActiveSupport::Callbacks: deprecate monkey patch of object callbacks Replace deprecated memcache-client gem with dalli in ActiveSupport::Cache::MemCacheStore Object#try will now return nil instead of raise a NoMethodError if the receiving object does not implement the method, but you can still get the old behavior by using the new Object#try! Object#try can't call private methods Add ActiveSupport::Deprecations.behavior = :silence to completely ignore Rails runtime deprecations What are the most important changes for you?

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  • Trouble using South with Django and Heroku

    - by Dan
    I had an existing Django project that I've just added South to. I ran syncdb locally. I ran manage.py schemamigration app_name locally I ran manage.py migrate app_name --fake locally I commit and pushed to heroku master I ran syncdb on heroku I ran manage.py schemamigration app_name on heroku I ran manage.py migrate app_name on heroku I then receive this: $ heroku run python notecard/manage.py migrate notecards Running python notecard/manage.py migrate notecards attached to terminal... up, run.1 Running migrations for notecards: - Migrating forwards to 0005_initial. > notecards:0003_initial Traceback (most recent call last): File "notecard/manage.py", line 14, in <module> execute_manager(settings) File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 438, in execute_manager utility.execute() File "/app/lib/python2.7/site-packages/django/core/management/__init__.py", line 379, in execute self.fetch_command(subcommand).run_from_argv(self.argv) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 191, in run_from_argv self.execute(*args, **options.__dict__) File "/app/lib/python2.7/site-packages/django/core/management/base.py", line 220, in execute output = self.handle(*args, **options) File "/app/lib/python2.7/site-packages/south/management/commands/migrate.py", line 105, in handle ignore_ghosts = ignore_ghosts, File "/app/lib/python2.7/site-packages/south/migration/__init__.py", line 191, in migrate_app success = migrator.migrate_many(target, workplan, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 221, in migrate_many result = migrator.__class__.migrate_many(migrator, target, migrations, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 292, in migrate_many result = self.migrate(migration, database) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 125, in migrate result = self.run(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 99, in run return self.run_migration(migration) File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 81, in run_migration migration_function() File "/app/lib/python2.7/site-packages/south/migration/migrators.py", line 57, in <lambda> return (lambda: direction(orm)) File "/app/notecard/notecards/migrations/0003_initial.py", line 15, in forwards ('user', self.gf('django.db.models.fields.related.ForeignKey')(to=orm['auth.User'])), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 226, in create_table ', '.join([col for col in columns if col]), File "/app/lib/python2.7/site-packages/south/db/generic.py", line 150, in execute cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/util.py", line 34, in execute return self.cursor.execute(sql, params) File "/app/lib/python2.7/site-packages/django/db/backends/postgresql_psycopg2/base.py", line 44, in execute return self.cursor.execute(query, args) django.db.utils.DatabaseError: relation "notecards_semester" already exists I have 3 models. Section, Semester, and Notecards. I've added one field to the Notecards model and I cannot get it added on Heroku. Thank you.

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  • how to update an Android ListActivity on changing data of the connected SimpleCursorAdapter

    - by 4485670
    I have the following code. What I want to achieve is to update the shown list when I click an entry so I can traverse through the list. I found the two uncommented ways to do it here on stackoverflow, but neither works. I also got the advice to create a new ListActivity on the data update, but that sounds like wasting resources? EDIT: I found the solution myself. All you need to do is call "SimpleCursorAdapter.changeCursor(new Cursor);". No notifying, no things in UI-Thread or whatever. import android.app.ListActivity; import android.database.Cursor; import android.os.Bundle; import android.util.Log; import android.view.View; import android.widget.ListView; import android.widget.SimpleCursorAdapter; public class MyActivity extends ListActivity { private DepartmentDbAdapter mDbHelper; private Cursor cursor; private String[] from = new String[] { DepartmentDbAdapter.KEY_NAME }; private int[] to = new int[] { R.id.text1 }; private SimpleCursorAdapter notes; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.departments_list); mDbHelper = new DepartmentDbAdapter(this); mDbHelper.open(); // Get all of the departments from the database and create the item list cursor = mDbHelper.fetchSubItemByParentId(1); this.startManagingCursor(cursor); // Now create an array adapter and set it to display using our row notes = new SimpleCursorAdapter(this, R.layout.department_row, cursor, from, to); this.setListAdapter(notes); } @Override protected void onListItemClick(ListView l, View v, int position, long id) { super.onListItemClick(l, v, position, id); // get new data and update the list this.updateData(safeLongToInt(id)); } /** * update data for the list * * @param int departmentId id of the parent department */ private void updateData(int departmentId) { // close the old one, get a new one cursor.close(); cursor = mDbHelper.fetchSubItemByParentId(departmentId); // change the cursor of the adapter to the new one notes.changeCursor(cursor); } /** * safely convert long to in to save memory * * @param long l the long variable * * @return integer */ public static int safeLongToInt(long l) { if (l < Integer.MIN_VALUE || l > Integer.MAX_VALUE) { throw new IllegalArgumentException (l + " cannot be cast to int without changing its value."); } return (int) l; } }

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  • Import? Initialize? what do to?

    - by Jeremy B
    I'm working on homework and I'm close but I am having an issue. I just learned how to work with packages in eclipse so I have a class that is importing another class from a package (I think I said that right) The main prompts the user to enter an integer between -100 and 100 and I am having an issue with validating it. I know the issue is where I'm importing I'm just unsure the direction I need to go to fix it. This is a section of my main code. (my issue starts with the last couple lines if you want to skip ahead) import myUtils.util.Console; public class ConsoleTestApp { public static void main(String args[]) { // create the Console object Console c = new Console(); // display a welcome message c.println("Welcome to the Console Tester application"); c.println(); // int c.println("Int Test"); int i = c.getIntWithinRange("Enter an integer between -100 and 100: ", -101, 101); c.println(); I have a class called Console that is located in another package that I believe I have properly imported. here is the code I am stuck on in my console class. public int getIntWithinRange(String prompt, int min, int max) { int i = 0; boolean isValid = false; while (isValid == false) { System.out.println(prompt); if (sc.hasNextInt()) { //if user chooses menu option less than 1 the program will print an error message i = sc.nextInt(); if (i < min) { System.out.println("Error! Please enter an int greater than -100"); } else if (i > max) { System.out.println("Error! Please enter an int less than 100"); } else isValid = true; } else System.out.println("Error! Invalid number value"); sc.nextLine(); } // return the int return i; } when I run this I keep getting my last print which is an invalid number value. am I not importing the code from the main method in the other console properly?

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  • JSP to Bean to Java class Validation

    - by littlevahn
    I have a rather simple form in JSP that looks like this: <form action="response.jsp" method="POST"> <label>First Name:</label><input type="text" name="firstName" /><br> <label>Last Name:</label><input type="text" name="lastName" /><br> <label>Email:</label><input type="text" name="email" /><br> <label>Re-enter Email:</label><input type="text" name="emailRe" /><br> <label>Address:</label><input type="text" name="address" /><br> <label>Address 2:</label><input type="text" name="address2" /><br> <label>City:</label><input type="text" name="city" /><br> <label>Country:</label> <select name="country"> <option value="0">--Country--</option> <option value="1">United States</option> <option value="2">Canada</option> <option value="3">Mexico</option> </select><br> <label>Phone:</label><input type="text" name="phone" /><br> <label>Alt Phone:</label><input type="text" name="phoneAlt" /><br> <input type="submit" value="submit" /> </form> But when I try and access the value of the select box in my Java class I get null. Ive tried reading it in as a String and an Array of strings neither though seems to be grabbing the right value. The response.jsp looks like this: <%@ page language="java" %> <%@ page import="java.util.*" %> <%@page contentType="text/html" pageEncoding="UTF-8"%> <%! %> <jsp:useBean id="formHandler" class="validation.RegHandler" scope="request"> <jsp:setProperty name="formHandler" property="*" /> </jsp:useBean> <% if (formHandler.validate()) { %> <jsp:forward page="success.jsp"/> <% } else { %> <jsp:forward page="retryReg.jsp"/> <% } %> I already have Java script validation in place but I wanted to make sure I covered validation and checking for non-JS users. The RegHandler just uses the name field to refer to the value in the form. Any Idea how I could access the select box's value?

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  • due at midnight - program compiles but has logic error(s)

    - by Leslie Laraia
    not sure why this program isn't working. it compiles, but doesn't provide the expected output. the input file is basically just this: Smith 80000 Jones 100000 Scott 75000 Washington 110000 Duffy 125000 Jacobs 67000 Here is the program: import java.io.File; import java.io.FileNotFoundException; import java.util.Scanner; /** * * @author Leslie */ public class Election { /** * @param args the command line arguments */ public static void main(String[] args) throws FileNotFoundException { // TODO code application logic here File inputFile = new File("C:\\Users\\Leslie\\Desktop\\votes.txt"); Scanner in = new Scanner(inputFile); int x = 0; String line = ""; Scanner lineScanner = new Scanner(line); line = in.nextLine(); while (in.hasNextLine()) { line = in.nextLine(); x++; } String[] senatorName = new String[x]; int[] votenumber = new int[x]; double[] votepercent = new double[x]; System.out.printf("%44s", "Election Results for State Senator"); System.out.println(); System.out.printf("%-22s", "Candidate"); //Prints the column headings to the screen System.out.printf("%22s", "Votes Received"); System.out.printf("%22s", "%of Total Votes"); int i; for(i=0; i<x; i++) { while(in.hasNextLine()) { line = in.nextLine(); String candidateName = lineScanner.next(); String candidate = candidateName.trim(); senatorName[i] = candidate; int votevalue = lineScanner.nextInt(); votenumber[i] = votevalue; } } votepercent = percentages(votenumber, x); for (i = 0; i < x; i++) { System.out.println(); System.out.printf("%-22s", senatorName[i]); System.out.printf("%22d", votenumber[i]); System.out.printf("%22.2f", votepercent[i]); System.out.println(); } } public static double [] percentages(int[] votenumber, int z) { double [] percentage = new double [z]; double total = 0; for (double element : votenumber) { total = total + element; } for(int i=0; i < votenumber.length; i++) { int y = votenumber[i]; percentage[i] = (y/total) * 100; } return percentage; } }

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  • sending and receiving with sockets in java?

    - by Darksole
    I am working on sending and receiving from clients and servers in java, and am stumped at the moment. the client socket is to contact a server at “localhost” port 4321. The client will receive a string from the server and alternate spelling the contents of this string with the server. For example, given the string “Bye Bye”, the client (which always begins sending the first letter) sends “B”, receives “y”, sends “e”, receives “ ”, sends “B”, receives “y”, sends “e”, and receives “done!”, which is the string that either client or server will send after the last letter from the original string is received. After “done!” is transmitted, both client and server close their communications. How would i go about getting the first string and then going back and forth sending and reciving letters that make the string, and when finished either send or get done!? import java.io.IOException; import java.io.InputStream; import java.io.OutputStream; import java.io.PrintWriter; import java.net.Socket; import java.net.UnknownHostException; import java.util.Scanner; public class Program2 { public static void goClient() throws UnknownHostException, IOException{ String server = "localhost"; int port = 4321; Socket socket = new Socket(server, port); InputStream inStream = socket.getInputStream(); OutputStream outStream = socket.getOutputStream(); Scanner in = new Scanner(inStream); PrintWriter out = new PrintWriter(outStream, true); String rec = ""; if(in.hasNext()){ rec = in.nextLine(); } char[] array = new char[rec.length()]; for(int i = 0; i < rec.length(); i++){ array[i] = rec.charAt(i); } while(in.hasNext()){ for(int x = 0; x < array.length + 1; x+=2){ String str = in.nextLine(); str = Character.toString(array[x]); out.println(str); } in.close(); socket.close(); } } }

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  • Losing session after Login - Java

    - by Patrick Villela
    I'm building an application that needs to login to a certain page and make a navigation. I can login, provided that the response contains a string that identifies it. But, when I navigate to the second page, I can't see the page as a logged user, only as anonymous. I'll provide my code. import java.net.*; import java.security.*; import java.security.cert.*; import javax.net.ssl.*; import java.io.*; import java.util.*; public class PostTest { static HttpsURLConnection conn = null; private static class DefaultTrustManager implements X509TrustManager { @Override public void checkClientTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public void checkServerTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public X509Certificate[] getAcceptedIssuers() { return null; } } public static void main(String[] args) { try { SSLContext ctx = SSLContext.getInstance("TLS"); ctx.init(new KeyManager[0], new TrustManager[] {new DefaultTrustManager()}, new SecureRandom()); SSLContext.setDefault(ctx); String data = URLEncoder.encode("txtUserName", "UTF-8") + "=" + URLEncoder.encode(/*username*/, "UTF-8"); data += "&" + URLEncoder.encode("txtPassword", "UTF-8") + "=" + URLEncoder.encode(/*password*/", "UTF-8"); data += "&" + URLEncoder.encode("envia", "UTF-8") + "=" + URLEncoder.encode("1", "UTF-8"); connectToSSL(/*login url*/); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; String resposta = ""; while((line = rd.readLine()) != null) { resposta += line + "\n"; } System.out.println("valid login -> " + resposta.contains(/*string that assures me I'm looged in*/)); connectToSSL(/*first navigation page*/); rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); while((line = rd.readLine()) != null) { System.out.println(line); } } catch(Exception e) { e.printStackTrace(); } } private static void connectToSSL(String address) { try { URL url = new URL(address); conn = (HttpsURLConnection) url.openConnection(); conn.setHostnameVerifier(new HostnameVerifier() { @Override public boolean verify(String arg0, SSLSession arg1) { return true; } }); } catch(Exception ex) { ex.printStackTrace(); } } } Any further information, just ask. Thanks in advance.

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  • Can I take the voice data (f.e. in mp3 format) from speech recognition? [closed]

    - by Ersin Gulbahar
    Possible Duplicate: Android: Voice Recording and saving audio I mean ; I use voice recognition classes on android and I succeed voice recognition. But I want to real voice data not words instead of it. For example I said 'teacher' and android get you said teacher.Oh ok its good but I want to my voice which include 'teacher'.Where is it ? Can I take it and save another location? I use this class to speech to text : package net.viralpatel.android.speechtotextdemo; import java.util.ArrayList; import android.app.Activity; import android.content.ActivityNotFoundException; import android.content.Intent; import android.os.Bundle; import android.speech.RecognizerIntent; import android.view.Menu; import android.view.View; import android.widget.ImageButton; import android.widget.TextView; import android.widget.Toast; public class MainActivity extends Activity { protected static final int RESULT_SPEECH = 1; private ImageButton btnSpeak; private TextView txtText; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); txtText = (TextView) findViewById(R.id.txtText); btnSpeak = (ImageButton) findViewById(R.id.btnSpeak); btnSpeak.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View v) { Intent intent = new Intent( RecognizerIntent.ACTION_RECOGNIZE_SPEECH); intent.putExtra(RecognizerIntent.EXTRA_LANGUAGE_MODEL, "en-US"); try { startActivityForResult(intent, RESULT_SPEECH); txtText.setText(""); } catch (ActivityNotFoundException a) { Toast t = Toast.makeText(getApplicationContext(), "Ops! Your device doesn't support Speech to Text", Toast.LENGTH_SHORT); t.show(); } } }); } @Override public boolean onCreateOptionsMenu(Menu menu) { getMenuInflater().inflate(R.menu.activity_main, menu); return true; } @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); switch (requestCode) { case RESULT_SPEECH: { if (resultCode == RESULT_OK && null != data) { ArrayList<String> text = data .getStringArrayListExtra(RecognizerIntent.EXTRA_RESULTS); txtText.setText(text.get(0)); } break; } } } } Thanks.

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  • Error with connection in my database servlet

    - by Zerobu
    Hello, I am writing a Database servlet, all seems well except that there seems to be an error in my connection import java.io.IOException; import java.sql.Connection; import java.sql.DriverManager; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; import java.sql.Statement; import java.util.ArrayList; import javax.servlet.RequestDispatcher; import javax.servlet.ServletContext; import javax.servlet.ServletException; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; public class DBServlet3 extends HttpServlet { private static final long serialVersionUID = 1L; @Override public void init() throws ServletException { super.init(); try { String jdbcDriverClass= getServletContext().getInitParameter( "jdbcDriverClass" ); if (jdbcDriverClass == null) throw new ServletException( "Could not find jdbcDriverClass initialization parameter" ); Class.forName( jdbcDriverClass ); } catch (ClassNotFoundException e) { throw new ServletException( "Could not load JDBC driver class", e ); } } @Override protected void doGet( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { RequestDispatcher dispatcher= request.getRequestDispatcher( "/db.jsp" ); ServletContext application= getServletContext(); ArrayList<String> names= new ArrayList<String>(); try { Connection connection= null; Statement statement= null; ResultSet results= null; try { String jdbcUrl= application.getInitParameter( "jdbcUrl" ); String jdbcUser= application.getInitParameter( "jdbcUser" ); String jdbcPassword= application.getInitParameter( "jdbcPassword" ); connection= DriverManager.getConnection( jdbcUrl, jdbcUser, jdbcPassword ); statement= connection.createStatement(); results= statement.executeQuery( "SELECT * FROM students" ); while (results.next()) { String name= results.getString( "name" ); names.add( name ); } } finally { if (results != null) results.close(); if (statement != null) statement.close(); if (connection != null) connection.close(); } } catch (SQLException e) { throw new ServletException( e ); } request.setAttribute( "names", names ); dispatcher.forward( request, response ); } @Override protected void doPost( HttpServletRequest request, HttpServletResponse response ) throws ServletException, IOException { String sql= "INSERT INTO students VALUES (" + request.getParameter( "id" ) + ", '" + request.getParameter( "name" ) + "')"; sql= "INSERT INTO students VALUES (?, ?, ?, ?)"; PreparedStatement statement= connection.prepareStatement( sql ); //error on this line statement.setString( 1, request.getParameter( "id" ) ); statement.setString( 2, request.getParameter( "name" ) ); } }

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  • Django save_m2m() and excluded field

    - by jul
    hi, in a ModelForm I replaced a field by excluding it and adding a new one with the same name, as shown below in AddRestaurantForm. When saving the form with the code shown below, I get an error in form.save_m2m() ("Truncated incorrect DOUBLE value"), which seems to be due to the function to attempt to save the tag field, while it is excluded. Is the save_m2m() function supposed to save excluded fields? Is there anything wrong in my code? Thanks Jul (...) new_restaurant = form.save(commit=False) new_restaurant.city = city new_restaurant.save() tags = form.cleaned_data['tag'] if(tags!=''): tags=tags.split(',') for t in tags: tag, created = Tag.objects.get_or_create(name = t.strip()) tag.save() new_restaurant.tag.add(tag) new_restaurant.save() form.save_m2m() models.py class Tag(models.Model): name = models.CharField(max_length=100, unique=True) class Restaurant(models.Model): name = models.CharField(max_length=50) city=models.ForeignKey(City) category=models.ManyToManyField(Category) tag=models.ManyToManyField(Tag, blank=True, null=True) forms.py class AddRestaurantForm(ModelForm): name = forms.CharField(widget=forms.TextInput(attrs=classtext)) city = forms.CharField(widget=forms.TextInput(attrs=classtext), max_length=100) tag = forms.CharField(widget=forms.TextInput(attrs=classtext), required=False) class Meta: model = Restaurant exclude = ('city','tag') Traceback: File "/var/lib/python-support/python2.5/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/jul/atable/../atable/resto/views.py" in addRestaurant 498. form.save_m2m() File "/var/lib/python-support/python2.5/django/forms/models.py" in save_m2m 75. f.save_form_data(instance, cleaned_data[f.name]) File "/var/lib/python-support/python2.5/django/db/models/fields/ related.py" in save_form_data 967. setattr(instance, self.attname, data) File "/var/lib/python-support/python2.5/django/db/models/fields/ related.py" in set 627. manager.add(*value) File "/var/lib/python-support/python2.5/django/db/models/fields/ related.py" in add 430. self._add_items(self.source_col_name, self.target_col_name, *objs) File "/var/lib/python-support/python2.5/django/db/models/fields/ related.py" in _add_items 497. [self._pk_val] + list(new_ids)) File "/var/lib/python-support/python2.5/django/db/backends/util.py" in execute 19. return self.cursor.execute(sql, params) File "/var/lib/python-support/python2.5/django/db/backends/mysql/ base.py" in execute 84. return self.cursor.execute(query, args) File "/var/lib/python-support/python2.5/MySQLdb/cursors.py" in execute 168. if not self._defer_warnings: self._warning_check() File "/var/lib/python-support/python2.5/MySQLdb/cursors.py" in _warning_check 82. warn(w[-1], self.Warning, 3) File "/usr/lib/python2.5/warnings.py" in warn 62. globals) File "/usr/lib/python2.5/warnings.py" in warn_explicit 102. raise message Exception Type: Warning at /restaurant/add/ Exception Value: Truncated incorrect DOUBLE value: 'a'

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  • Reading three words and sorting them in lexicographic order

    - by Derrick
    I am trying to create a program that asks the User to type three words and sort them in lexicographic order. EXAMPLE; Enter three words separated by spaces: Pear Orange Apple Apple Orange Pear The program is working fine (if I attempt the above example) except for one type of combination example that I will show below. EXAMPLE; Enter three words separated by spaces: Orange Apple Pear Apple Pear Pear The program is skipping the first word (Orange) if it is supposed to appear in the middle of the three words. I believe that this line of code is affecting the program because it says that "this assigned value is never used" but I'm not sure how to fix it since I'm still an entry Java learner. middle = firstWord; Because of that line being unused, it's why Pear appeared twice. import java.util.*; public static void main(String[] args) { Scanner wordInput = new Scanner(System.in); String firstWord; String secondWord; String thirdWord; System.out.println("Enter three words separated by spaces: "); firstWord = wordInput.next(); secondWord = wordInput.next(); thirdWord = wordInput.next(); String top = firstWord; String bottom = firstWord; if( top.compareTo(secondWord) > 0) { top = secondWord; } if( top.compareTo(thirdWord) > 0) { top = thirdWord; } if( bottom.compareTo(secondWord) < 0) { bottom = secondWord; } if( bottom.compareTo(thirdWord) < 0) { bottom = thirdWord; } String middle; if( !firstWord.equals(bottom) && !firstWord.equals(top) ) { middle = firstWord; } if( !secondWord.equals(bottom) && !secondWord.equals(top) ) { middle = secondWord; } else { middle = thirdWord; } System.out.println( top ); System.out.println( middle ); System.out.println( bottom ); } } Does anyone what I am missing or doing wrong? :( Please and thank you for any help!

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  • Why is this statement treated as a string instead of its result?

    - by reve_etrange
    I am trying to perform some composition-based filtering on a large collection of strings (protein sequences). I wrote a group of three subroutines in order to take care of it, but I'm running into trouble in two ways - one minor, one major. The minor trouble is that when I use List::MoreUtils 'pairwise' I get warnings about using $a and $b only once and them being uninitialized. But I believe I'm calling this method properly (based on CPAN's entry for it and some examples from the web). The major trouble is an error "Can't use string ("17/32") as HASH ref while "strict refs" in use..." It seems like this can only happen if the foreach loop in &comp is giving the hash values as a string instead of evaluating the division operation. I'm sure I've made a rookie mistake, but can't find the answer on the web. The first time I even looked at perl code was last Wednesday... use List::Util; use List::MoreUtils; my @alphabet = ( 'A', 'R', 'N', 'D', 'C', 'Q', 'E', 'G', 'H', 'I', 'L', 'K', 'M', 'F', 'P', 'S', 'T', 'W', 'Y', 'V' ); my $gapchr = '-'; # Takes a sequence and returns letter = occurrence count pairs as hash. sub getcounts { my %counts = (); foreach my $chr (@alphabet) { $counts{$chr} = ( $[0] =~ tr/$chr/$chr/ ); } $counts{'gap'} = ( $[0] =~ tr/$gapchr/$gapchr/ ); return %counts; } # Takes a sequence and returns letter = fractional composition pairs as a hash. sub comp { my %comp = getcounts( $[0] ); foreach my $chr (@alphabet) { $comp{$chr} = $comp{$chr} / ( length( $[0] ) - $comp{'gap'} ); } return %comp; } # Takes two sequences and returns a measure of the composition difference between them, as a scalar. # Originally all on one line but it was unreadable. sub dcomp { my @dcomp = pairwise { $a - $b } @{ values( %{ comp( $[0] ) } ) }, @{ values( %{ comp( $[1] ) } ) }; @dcomp = apply { $_ ** 2 } @dcomp; my $dcomp = sqrt( sum( 0, @dcomp ) ) / 20; return $dcomp; } Much appreciation for any answers or advice!

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  • How can i maintain last cookie value in flex with jsp?

    - by praveen
    Hi All, my login form in flex when I login I have created a cookie in jsp like this name setValueCookie.jsp <%@ page language="java" import="java.util.* , javax.net.*" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <% String username = request.getParameter("value"); System.out.println("Email got in cookieSet = " + username); if(username==null) username=""; Date now = new Date(); String timestamp = now.toString(); Cookie cookie = new Cookie("username",username); cookie.setMaxAge(365 * 24 * 60 * 60); response.addCookie(cookie); %> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>DashBoard-Cookie</title> </head> <body> </body> </html> now using Http service request parameter i am passing username 'Value' to this jsp. and i am reading cookie value from getValueCookie.jsp like this <% String cookieName = "username"; Cookie cookies [] = request.getCookies (); Cookie myCookie = null; String result; if (cookies != null) { for (int i = 0; i < cookies.length; i++) { if (cookies [i].getName().equals (cookieName)) { myCookie = cookies[i]; break; } } } %> <data> <status><%=myCookie.getValue().toString()%></status> </data> through the httpservice value i am getting but if i open a new window or any new tab cookie value is not getting how can i solve this? Thanks in advance.

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  • PHP apache_request_headers() diagrees with reality (as confirmed by Firebug): why?

    - by Peter Howe
    I have written a web app in PHP which makes use of Ajax requests (made using YUI.util.Connect.asyncRequest). Most of the time, this works fine. The request is sent with an X-Requested-With value of XMLHttpRequest. My PHP controller code uses apache_request_headers() to check whether an incoming request is Ajax or not and all works well. But not always. Intermittently, I'm getting a situation where the Ajax request is sent (and Firebug confirms for me that the headers on the request include an X-Requested-With of XMLHttpRequest) but apache_request_headers() is not returning that header in its list. The output from when I var_dump the apache_request_headers() is as follows (note the lack of X- 'Host' => string 'peterh.labs.example.com' (length=26) 'User-Agent' => string 'Mozilla/5.0 (X11; U; Linux i686; en-GB; rv:1.9.0.3) Gecko/2008101315 Ubuntu/8.10 (intrepid) Firefox/3.0.3' (length=105) 'Accept' => string 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8' (length=63) 'Accept-Language' => string 'en-gb,en;q=0.5' (length=14) 'Accept-Encoding' => string 'gzip,deflate' (length=12) 'Accept-Charset' => string 'ISO-8859-1,utf-8;q=0.7,*;q=0.7' (length=30) 'Keep-Alive' => string '300' (length=3) 'Connection' => string 'keep-alive' (length=10) 'Referer' => string 'http://peterh.labs.example.com/qmail/' (length=40) 'Cookie' => string 'WORKFLOW_SESSION=55f9aff2051746851de453c1f776ad10745354f6' (length=57) 'Pragma' => string 'no-cache' (length=8) 'Cache-Control' => string 'no-cache' (length=8) But Firebug tells me: Request Headers: Host peterh.labs.example.com User-Agent Mozilla/5.0 (X11; U; Linux i686; en-GB; rv:1.9.0.3) Gecko/2008101315 Ubuntu/8.10 (intrepid) Firefox/3.0.3 Accept text/html,application/xhtml+xml,application/xml;q=0.9,**;q=0.8 Accept-Language en-gb,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive X-Requested-With XMLHttpRequest Referer http://peterh.labs.example.com/qmail/ Cookie WORKFLOW_SESSION=55f9aff2051746851de453c1f776ad10745354f6 This mismatch is (apparently) intermittent when executing the same code. But I don't believe in "intermittent" when it comes to software! Help!

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  • StaX: Content not allowed in prolog

    - by RalfB
    I have the following (test) XML file below and Java code that uses StaX. I want to apply this code to a file that is about 30 GB large but with fairly small elements, so I thought StaX is a good choice. I am getting the following error: Exception in thread "main" javax.xml.stream.XMLStreamException: ParseError at [row,col]:[1,1] Message: Content is not allowed in prolog at com.sun.org.apache.xerces.internal.impl.XMLStreamReaderImpl.next(XMLStreamReaderImpl.java:598) at at.tuwien.mucke.util.xml.staxtest.StaXTest.main(StaXTest.java:18) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43) at java.lang.reflect.Method.invoke(Method.java:601) at com.intellij.rt.execution.application.AppMain.main(AppMain.java:120) <?xml version='1.0' encoding='utf-8'?> <catalog> <book id="bk101"> <author>Gambardella, Matthew</author> <title>XML Developer's Guide</title> <price>44.95</price> <description>An in-depth look at creating applications with XML.</description> </book> <book id="bk102"> <author>Ralls, Kim</author> <title>Midnight Rain</title> <price>5.95</price> <description>A former architect battles corporate zombies, an evil sorceress, and her own childhood to become queen of the world.</description> </book> </catalog> Here the code: package xml.staxtest; import java.io.*; import javax.xml.stream.*; public class StaXTest { public static void main(String[] args) throws Exception { XMLInputFactory xif = XMLInputFactory.newInstance(); XMLStreamReader streamReader = xif.createXMLStreamReader(new FileReader("D:/Data/testFile.xml")); while(streamReader.hasNext()){ int eventType = streamReader.next(); if(eventType == XMLStreamReader.START_ELEMENT){ System.out.println(streamReader.getLocalName()); } //... more to come here later ... } } }

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  • What am I encrypting wrong here?

    - by Katie Krueger
    So I have a wordplay project to do and I have to encrypt some characters. I am at the point where I am stuck, and when I run it and type 1 for encrypt it doesn't shift that many letters. It just prints the work over again. I am wondering what I could do to fix it where if I say "hello" it will print 1 character over and say "ifmmp" Thank you! import java.util.Scanner; public class WordPlayTester{ public static void main(String [] args){ String word, reverse=""; String original; int key= 0; String Menu= "1-Encrypt \n2-Decrypt \n3-Is Palindrome \n0-Quit \n-Select an option-"; Scanner in = new Scanner(System.in); System.out.println("-Type any word-"); word = in.nextLine(); System.out.println(Menu); int choice=in.nextInt(); if(choice==1) { System.out.println("Insert a Key number"); int select= in.nextInt(); for (int i=0; i < word.length(); i++) { char c = word.charAt(i); if (c >= 'A' && c <= 'Z') { c = (char)(c - 64); int n = c+1; n = n % 26; if (n < 0) { n = n + 26; } c = (char)(n + 65); } System.out.println(c); } } else if(choice==3) { int length = word.length(); for ( int i = length - 1 ; i >= 0 ; i-- ) reverse = reverse + word.charAt(i); if (word.equals(reverse)) System.out.println("Your word is a palindrome."); else System.out.println("Your word is not a palindrome."); } else if(choice==0) { System.exit(0); } else { System.out.println(Menu); } } }

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  • Java program grading

    - by pasito15
    I've been working on this program for hours and I can't figure out how to get the program to actually print the grades from the scores Text file public class Assign7{ private double finalScore; private double private_quiz1; private double private_quiz2; private double private_midTerm; private double private_final; private final char grade; public Assign7(double finalScore){ private_quiz1 = 1.25; private_quiz2 = 1.25; private_midTerm = 0.25; private_final = 0.50; if (finalScore >= 90) { grade = 'A'; } else if (finalScore >= 80) { grade = 'B'; } else if (finalScore >= 70) { grade = 'C'; } else if (finalScore>= 60) { grade = 'D'; } else { grade = 'F'; } } public String toString(){ return finalScore+":"+private_quiz1+":"+private_quiz2+":"+private_midTerm+":"+private_final; } } this code compiles as well as this one import java.util.*; import java.io.*; public class Assign7Test{ public static void main(String[] args)throws Exception{ int q1,q2; int m = 0; int f = 0; int Record ; String name; Scanner myIn = new Scanner( new File("scores.txt") ); System.out.println( myIn.nextLine() +" avg "+"letter"); while( myIn.hasNext() ){ name = myIn.next(); q1 = myIn.nextInt(); q2 = myIn.nextInt(); m = myIn.nextInt(); f = myIn.nextInt(); Record myR = new Record( name, q1,q2,m,f); System.out.println(myR); } } public static class Record { public Record() { } public Record(String name, int q1, int q2, int m, int f) { } } } once a compile the code i get this which dosent exactly compute the numbers I have in the scores.txt Name quiz1 quiz2 midterm final avg letter Assign7Test$Record@4bcc946b Assign7Test$Record@642423 Exception in thread "main" java.until.InputMismatchException at java.until.Scanner.throwFor(Unknown Source) at java.until.Scanner.next(Unknown Source) at java.until.Scanner.nextInt(Unknown Source) at java.until.Scanner.nextInt(Unknown Source) at Assign7Test.main(Assign7Test.java:25)

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  • How can I set an image for background of GUI interface?

    - by enriched
    hey everyone, im having some troubles displaying the background image for a GUI interface in java. Here is what i have at the moment, and with current stage of code it shows default(gray) background. import javax.swing.*; import java.awt.event.*; import java.util.Scanner; import java.awt.*; import java.io.File; import javax.imageio.ImageIO; import java.awt.image.BufferedImage; import java.io.IOException; ////////////////////////////////// // 3nriched Games Presents: // // MIPS The Mouse!! // ////////////////////////////////// public class mipsMouseGUI extends JFrame implements ActionListener { private static String ThePDub = ("mouse"); //the password JPasswordField pass; JPanel panel; JButton btnEnter; JLabel lblpdub; public mipsMouseGUI() { BufferedImage image = null; try { //attempts to read picture from the folder image = ImageIO.read(getClass().getResource("/mousepics/mousepic.png")); } catch (IOException e) { //catches exceptions e.printStackTrace(); } ImagePanel panel = new ImagePanel(new ImageIcon("/mousepics/neonglowOnwill.png").getImage()); setIconImage(image); //sets icon picture setTitle("Mips The Mouse Login"); setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); pass = new JPasswordField(5); //sets password length to 5 pass.setEchoChar('@'); //hide characters as @ symbol pass.addActionListener(this); //adds action listener add(panel); //adds panel to frame btnEnter = new JButton("Enter"); //creates a button btnEnter.addActionListener(this);// Register the action listener. lblpdub = new JLabel(" Your Password: "); // label that says enter password panel.add(lblpdub, BorderLayout.CENTER);// adds label and inputbox panel.add(pass, BorderLayout.CENTER); // to panel and sets location panel.add(btnEnter, BorderLayout.CENTER); //adds button to panel pack(); // packs controls and setLocationRelativeTo(null); // Implicit "this" if inside JFrame constructor. setVisible(true);// makes them visible (duh) } public void actionPerformed(ActionEvent a) { Object source = a.getSource(); //char array that holds password char[] passy = pass.getPassword(); //characters array to string String p = new String(passy); //determines if user entered correct password if(p.equals(ThePDub)) { JOptionPane.showMessageDialog(null, "Welcome beta user: USERNAME."); } else JOptionPane.showMessageDialog(null, "You have enter an incorrect password. Please try again."); } public class ImagePanel extends JPanel { private BufferedImage img; public ImagePanel(String img) { this(new ImageIcon(img).getImage()); } public ImagePanel(Image img) { Dimension size = new Dimension(img.getWidth(null), img.getHeight(null)); } public void paintComponent(Graphics g) { g.drawImage(img, 0, 0, null); } } }

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