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  • Need Help With Simple Regex

    - by npinti
    I have strings of this type: text (more text) What I would like to do is to have a regular expression that extracts the "more text" segment of the string, so far I have been using this regular expression: "^.*\\((.*)\\)$" Which although it works on many cases, it seems to fail if I have something of the sort: text (more text (even more text)) What I get is: even more text) What I would like to get instead is: more text (even more text) (basically the content of the outermost pair of brackets.) Thanks

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  • urgent..haskell mini interpreter

    - by mohamed elshikh
    i'm asked to implement this project and i have problems in part b which is the eval function this is the full describtion of the project You are required to implement an interpreter for mini-Haskell language. An interpreter is dened in Wikipedia as a computer program that executes, i.e. performs, instructions written in a programming language. The interpreter should be able to evaluate functions written in a special notation, which you will dene. A function is dened by: Function name Input Parameters : dened as a list of variables. The body of the function. The body of the function can be any of the following statements: a) Variable: The function may return any of the input variables. b) Arithmetic Expressions: The arithmetic expressions include input variables and addition, sub- traction, multiplication, division and modulus operations on arithmetic expressions. c) Boolean Expressions: The Boolean expressions include the ordering of arithmetic expressions (applying the relationships: <, =<, , = or =) and the anding, oring and negation of Boolean expressions. d) If-then-else statements: where the if keyword is followed by a Boolean expression. The then and else parts may be followed by any of the statements described here. e) Guarded expressions: where each case consists of a boolean expression and any of the statements described here. The expression consists of any number of cases. The rst case whose condition is true, its body should be evaluated. The guarded expression has to terminate with an otherwise case. f) Function calls: the body of the function may have a call to another function. Note that all inputs passed to the function will be of type Int. The output of the function can be of type Int or Bool. To implement the interpreter, you are required to implement the following: a) Dene a datatype for the following expressions: Variables Arithmetic expressions Boolean expressions If-then-else statements Guarded expressions Functions b) Implement the function eval which evaluates a function. It takes 3 inputs: The name of a function to be evaluated represented as a string. A list of inputs to that function. The arguments will always be of datatype Int. A list of functions. Each function is represented as instance of the datatype that you have created for functions. c) Implement the function get_type that returns the type of the function (as a string). The input to this function is the same as in part b. here is what i've done data Variable = v(char) data Arth= va Variable | Add Arth Arth | Sub Arth Arth | Times Arth Arth | Divide Arth Arth data Bol= Great Arth Arth | Small Arth Arth | Geq Arth Arth | Seq Arth Arth | And Bol Bol | Or Bol Bol | Neg Bol data Cond = data Guard = data Fun =cons String [Variable] Body data Body= bodycons(String) |Bol |Cond |Guard |Arth

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  • How to access class member from bison action

    - by yodhevauhe
    I am calling yyparse from a member function. How to access the member variables/function from the bison action. I am currently doing as %{ #include "myclass.h" #include "parse.tab.hh" MyClass *ptr=NULL; void MyClass::evaluate(string expression) { ptr=this; yy_scan_string(expression.c_str()); yyparse(); } %} %% EXPR : EXPR PLUS EXPR { $$ = ptr->memberFunction("+",$1,$3); }

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  • Is there a more modern regexp handler for Open Object Rexx

    - by Brent.Longborough
    The regular expression class (rxregexp.dll) that comes with ooRexx (I'm on 4.0.0) is relatively low on function compared, say, with Python's re module (even at 2.5.2). It appears to have no assertions, no facilities for group extraction, or for substitution. Greedy or lazy matching is a global pattern option, rather than flagged by an additional "?". Basically, a pre-PCRE regular expression engine. Does anyone know if anything with more up-to-date function is available?

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  • Specializing a template on a lambda in C++0x

    - by Tony A.
    I've written a traits class that lets me extract information about the arguments and type of a function or function object in C++0x (tested with gcc 4.5.0). The general case handles function objects: template <typename F> struct function_traits { template <typename R, typename... A> struct _internal { }; template <typename R, typename... A> struct _internal<R (F::*)(A...)> { // ... }; typedef typename _internal<decltype(&F::operator())>::<<nested types go here>>; }; Then I have a specialization for plain functions at global scope: template <typename R, typename... A> struct function_traits<R (*)(A...)> { // ... }; This works fine, I can pass a function into the template or a function object and it works properly: template <typename F> void foo(F f) { typename function_traits<F>::whatever ...; } int f(int x) { ... } foo(f); What if, instead of passing a function or function object into foo, I want to pass a lambda expression? foo([](int x) { ... }); The problem here is that neither specialization of function_traits<> applies. The C++0x draft says that the type of the expression is a "unique, unnamed, non-union class type". Demangling the result of calling typeid(...).name() on the expression gives me what appears to be gcc's internal naming convention for the lambda, main::{lambda(int)#1}, not something that syntactically represents a C++ typename. In short, is there anything I can put into the template here: template <typename R, typename... A> struct function_traits<????> { ... } that will allow this traits class to accept a lambda expression?

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  • child objects in rdlc (Studio 2010RC)

    - by Jim
    Hi, I am attempting to reference a sub-object in a field expression in a studio 2010 report. This used to work in prior versions. When account references another object with properties the following used to work. =Fields!Account.Value.Name (Name is a property of the child object, Account is the parent object) The same expression syntax no longer works. How do I reference the properties of a sub-object in reporting services in an rdlc in studio 2010. Thanks

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  • In Java, is it possible for a super constructor invocation actually invoke a constructor in the calling class?

    - by John Assymptoth
    Super constructor invocation definition: [Primary.] [NonWildTypeArguments] super ( ArgumentListopt ) ; A super constructor call can be prefixed by an Primary expression. Example (taken from JLS): class Outer { class Inner{ } } class ChildOfInner extends Outer.Inner { ChildOfInner() { (new Outer()).super(); // (new Outer()) is the Primary } } Does a Primary expression exist that makes the call to super() the invocation of a constructor of the calling class? Or Java prevents that?

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  • Regex for Password Must be contain at least 8 characters, least 1 number and both lower and uppercase letters and special characters

    - by user2442653
    I want a regular expression to check that Password Must be contain at least 8 characters, including at least 1 number and includes both lower and uppercase letters and special characters (e.g., #, ?, !) Cannot be your old password or contain your username, "password", or "websitename" And here is my validation expression which is for 8 characters including 1 uppercase letter, 1 lowercase letter, 1 number or special character. (?=^.{8,}$)((?=.*\d)|(?=.*\W+))(?![.\n])(?=.*[A-Z])(?=.*[a-z]).*$" How I can write it for password must be 8 characters including 1 uppercase letter, 1 special character and alphanumeric characters?

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  • Why doesn't Java warn about a == "something"?

    - by Marius
    This might sound stupid, but why doesn't the Java compiler warn about the expression in the following if statement: String a = "something"; if(a == "something"){ System.out.println("a is equal to something"); }else{ System.out.println("a is not equal to something"); } I realize why the expression is untrue, but AFAIK, a can never be equal to the String literal "something". The compiler should realize this and at least warn me that I'm an idiot who is coding way to late at night.

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  • uncaught exception: Syntax error after jQuery upgrade

    - by wham12
    I am trying to upgrade an existing application from jQuery 1.3.2 to jQuery 1.4.2. When I do this, the page fails to load correctly and firefox's error console displays the error message "uncaught exception: Syntax error, unrecognized expression: Syntax error, unrecognized expression: search". How can I determine what is causing this exception?

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  • HtmlHelperExtensions are not visible in view mvc3 asp.net

    - by user1299372
    I've added a class for the HTML Custom Extensions: using System; using System.Linq.Expressions; using System.Text; using System.Web.Mvc; using System.Web.Mvc.Html; namespace App.MvcHtmlHelpers { public static class HtmlHelperExtensions { public static MvcHtmlString ComboBox(HtmlHelper html, string name, SelectList items, string selectedValue) { var sb = new StringBuilder(); sb.Append(html.DropDownList(name + "_hidden", items, new { @style = "width: 200px;", @onchange = "$('input#" + name + "').val($(this).val());" })); sb.Append(html.TextBox(name, selectedValue, new { @style = "margin-left: -199px; width: 179px; height: 1.2em; border: 0;" })); return MvcHtmlString.Create(sb.ToString()); } public static MvcHtmlString ComboBoxFor<TModel, TProperty>(HtmlHelper<TModel> html, Expression<Func<TModel, TProperty>> expression, SelectList items) { var me = (MemberExpression)expression.Body; var name = me.Member.Name; var sb = new StringBuilder(); sb.Append(html.DropDownList(name + "_hidden", items, new { @style = "width: 200px;", @onchange = "$('input#" + name + "').val($(this).val());" })); sb.Append(html.TextBoxFor(expression, new { @style = "margin-left: -199px; width: 179px; height: 1.2em; border: 0;" })); return MvcHtmlString.Create(sb.ToString()); } I've also registered it in my site web config: <namespaces> <add namespace="System.Web.Helpers" /> <add namespace="System.Web.Mvc" /> <add namespace="System.Web.Mvc.Ajax" /> <add namespace="System.Web.Mvc.Html" /> <add namespace="System.Web.Routing" /> <add namespace="System.Web.WebPages" /> <add namespace="App.MvcHtmlHelpers"/> </namespaces> In my view, I import the namespace: <%@ Import Namespace="RSPWebApp.MvcHtmlHelpers" %> But when I go to call it in the view, it doesn't recognize the custom extension. Can someone help me by telling me what I might have missed? Thanks so much in advance! <%:Html.ComboBoxFor(a => a.Street2, streetAddressListItems) %

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  • How to create dynamic number of output files with SSIS?

    - by JSacksteder
    I will be creating flatfiles and based on the data in the batch, it might be necessary to split the data into an undetermined number of files. I can make the connection string dynamic with an expression, but that is only evaluated when the package starts. I'd like to change that expression to include a '-a' or '-b' in the filename. Alternately, if I have to create new connection manager objects at run time on demand, how do I go about that?

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  • help with regex needed

    - by user268375
    I need a regular expression with the following needs: the string is alphanumeric and have exactly 6 characters in the first half followed by hyphen(optional) followed by optional 4 characters:(cannot have more than 4 characters in the second half) so any of the following is valid 11111A 111111-1 111111-yy yyyyy-989 yyyyyy-9090 i thought this expression /[a-zA-Z0-9]([-])?[a-zA-Z0-9]{5,10}$/; should work but i m unable to get it working correctly. Any help will be appreciated,

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  • DataColumn expressions

    - by Kumar
    What is the most complex expression you've seen/used ? and what's the limit on the length of the expression that can be used ? I seem to recall something to that effect a while back but can't locate it now !!

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  • How can you remove a Criterion from a criteria?

    - by ChuckM
    Hello, For instance if I do something like: Criteria c = session.createCriteria(Book.class) .add(Expression.ge("release",reDate); .add(Expression.ge("price",price); .addOrder( Order.asc("date") ) .setFirstResult(0) .setMaxResults(10); c.list(); How can I use the same criteria instance, but remove (for example) the second criterion? I'm trying to build a dynamic query in which I'd like to let the user remove a filter, without the backend having to reconstruct the criteria from scratch. Thank you

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  • Does this e-mail-regex exclude valid addresses?

    - by neo
    I tried to create a regular expression which catches all RFC-valid addresses but it's ok if some false-positives come through (though hopefully not so many). This is waht I came up so far: /^\b\S+@\S+\.[^\s@]{2,}\b$/ Is there any RFC-valid address which doesn't match against this expression or do you have any suggestions to improve it? I don't mind the false positives but I would be glad if you show me a few, too.

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  • Haskell "Source reduction"

    - by Martin
    I'm revising for an upcoming Haskell exam and I don't understand one of the questions on a past paper. Google turns up nothing useful fst(x, y) = x square i = i * i i) Source reduce, using Haskells lazy evaluation, the expression: fst(square(3+4), square 8) ii) Source reduce, using strict evaluation, the same expression iii) State one advantage of lazy evaluation and one advantage of strict evaluation

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  • Javascript regular expressions: how to match ONLY the given characters?

    - by Dfowj
    I'm trying to use a regex like /[computer]{3,8}/ to get any words containing only the letters in computer ranging from 3 to 8 letters long. That regex instead captures all words containing ANY of the letters in [computer]. I've been looking at regular expression examples, but i can't quite figure it out... How do i modifiy this regular expression to capture words containing ONLY the letters in computer (with a length of 3 to 8)?

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  • Copying an entire table with Postgres

    - by NudeCanalTroll
    Hello, I'm trying to copy the contents of one table into another in Postgres, however it appears some rows aren't being copied correctly: ActiveRecord::StatementInvalid: PGError: ERROR: column "email_date" is of type timestamp without time zone but expression is of type character varying HINT: You will need to rewrite or cast the expression. Is there any way I can have it automatically skip (or ignore) invalid rows? Here's the query I'm using: SET statement_timeout = 0; INSERT INTO emails3 SELECT * FROM emails

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  • Handling a colon in an element ID in a CSS selector

    - by sblundy
    JSF is setting the ID of an input field to search_form:expression. I need to specify some styling on that element, but that colon looks like the beginning of a pseudo-element to the browser so it gets marked invalid and ignored. Is there anyway to escape the colon or something? input#search_form:expression { ///... }

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  • Doubt in Conditional inclusion

    - by Philando Gullible
    This is actually extracted from my module (Pre-processor in C) The conditional expression could contain any C operator except for the assignment operators,increment, and decrement operators. I am not sure if I am getting this statement or not since I tried using this and it worked.Also for other manipulation a probable work around would be to simply declare macro or function inside the conditional expression,something like this to be precise. Also I don't understand what is the rationale behind this rule. Could somebody explain? Thanks

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  • Passing template into boost function

    - by Ockonal
    template <class EventType> class IEvent; class IEventable; typedef boost::function<void (IEventable&, IEvent&)> behaviorRef; What is the right way for passing template class IEvent into boost function? With this code I get: error: functional cast expression list treated as compound expression error: template argument 1 is invalid error: invalid type in declaration before ‘;’ token

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  • NHibernate, could not load an entity when column exists in the database.

    - by Eitan
    This is probably a simple question to answer but I just can't figure it out. I have a "Company" class with a many-to-one to "Address" which has a many to one to a composite id in "City". When I load a "Company" it loads the "Address", but if I call any property of "Address" I get the error: {"could not load an entity: [IDI.Domain.Entities.Address#2213][SQL: SELECT address0_.AddressId as AddressId13_0_, address0_.Street as Street13_0_, address0_.floor as floor13_0_, address0_.room as room13_0_, address0_.postalcode as postalcode13_0_, address0_.CountryCode as CountryC6_13_0_, address0_.CityName as CityName13_0_ FROM Address address0_ WHERE address0_.AddressId=?]"} The inner exception is: {"Invalid column name 'CountryCode'.\r\nInvalid column name 'CityName'."} What I don't understand is that I can run the query in sql server 2005 and it works, furthermore both those columns exist in the address table. Here are my HBMs: <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="IDI.Domain" namespace="IDI.Domain.Entities" > <class name="IDI.Domain.Entities.Company,IDI.Domain" table="Companies"> <id column="CompanyId" name="CompanyId" unsaved-value="0"> <generator class="native"></generator> </id> <property column="Name" name="Name" not-null="true" type="String"></property> <property column="NameEng" name="NameEng" not-null="false" type="String"></property> <property column="Description" name="Description" not-null="false" type="String"></property> <property column="DescriptionEng" name="DescriptionEng" not-null="false" type="String"></property> <many-to-one name="Address" column="AddressId" not-null="false" cascade="save-update" class="IDI.Domain.Entities.Address,IDI.Domain"></many-to-one> <property column="Telephone" name="Telephone" not-null="false" type="String"></property> <property column="TelephoneTwo" name="TelephoneTwo" not-null="false" type="String"></property> <property column="Fax" name="Fax" not-null="false" type="String"></property> <property column="ContactMan" name="ContactMan" not-null="false" type="String"></property> <property column="ContactManEng" name="ContactManEng" not-null="false" type="String"></property> <property column="Email" name="Email" not-null="false" type="String"></property> </class> </hibernate-mapping> <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="IDI.Domain" namespace="IDI.Domain.Entities" > <class name="IDI.Domain.Entities.Address,IDI.Domain" table="Address"> <id name="AddressId" column="AddressId" type="Int32"> <generator class="native"></generator> </id> <property name="Street" column="Street" not-null="false" type="String"></property> <property name="Floor" column="floor" not-null="false" type="Int32"></property> <property name="Room" column="room" not-null="false" type="Int32"></property> <property name="PostalCode" column="postalcode" not-null="false" type="string"></property> <many-to-one class="IDI.Domain.Entities.City,IDI.Domain" name="City" update="false" insert="false"> <column name="CountryCode" sql-type="String" ></column> <column name="CityName" sql-type="String"></column> </many-to-one> </class> </hibernate-mapping> <?xml version="1.0" encoding="utf-8" ?> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2" assembly="IDI.Domain" namespace="IDI.Domain.Entities" > <class name="IDI.Domain.Entities.City,IDI.Domain" table="Cities"> <composite-id> <key-many-to-one class="IDI.Domain.Entities.Country,IDI.Domain" name="CountryCode" column="CountryCode"> </key-many-to-one> <key-property name="Name" column="Name" type="string"></key-property> </composite-id> </class> </hibernate-mapping> Here is my code that calls the Company: IList<BursaUser> user; if(String.IsNullOrEmpty(email) && String.IsNullOrEmpty(company)) return null; ICriteria criteria = Session.CreateCriteria(typeof (BursaUser), "user").CreateCriteria("Company", "comp"); if(String.IsNullOrEmpty(email) || String.IsNullOrEmpty(company) ) { user = String.IsNullOrEmpty(email) ? criteria.Add(Expression.Eq("comp.Name", company)).List<BursaUser>() : criteria.Add(Expression.Eq("user.Email", email)).List<BursaUser>(); } And finally here is where i get the error: "user" was already initialized with the code above: if (user.Company.Address.City == null) user.Company.Address.City = new City(); Thanks.

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