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  • Looping through a SimpleXML object, or turning the whole thing into an array.

    - by Coffee Cup
    I'm trying to work out how to iterate though a returned SimpleXML object. I'm using a toolkit called Tarzan AWS, which connects to Amazon Web Services (SimpleDB, S3, EC2, etc). I'm specifically using SimpleDB. I can put data into the Amazon SimpleDB service, and I can get it back. I just don't know how to handle the SimpleXML object that is returned. The Tarzan AWS documentation says this: Look at the response to navigate through the headers and body of the response. Note that this is an object, not an array, and that the body is a SimpleXML object. Here's a sample of the returned SimpleXML object: [body] = SimpleXMLElement Object ( [QueryWithAttributesResult] = SimpleXMLElement Object ( [Item] = Array ( [0] = SimpleXMLElement Object ( [Name] = message12413344443260 [Attribute] = Array ( [0] = SimpleXMLElement Object ( [Name] = active [Value] = 1 ) [1] = SimpleXMLElement Object ( [Name] = user [Value] = john ) [2] = SimpleXMLElement Object ( [Name] = message [Value] = This is a message. ) [3] = SimpleXMLElement Object ( [Name] = time [Value] = 1241334444 ) [4] = SimpleXMLElement Object ( [Name] = id [Value] = 12413344443260 ) [5] = SimpleXMLElement Object ( [Name] = ip [Value] = 10.10.10.1 ) ) ) [1] = SimpleXMLElement Object ( [Name] = message12413346907303 [Attribute] = Array ( [0] = SimpleXMLElement Object ( [Name] = active [Value] = 1 ) [1] = SimpleXMLElement Object ( [Name] = user [Value] = fred ) [2] = SimpleXMLElement Object ( [Name] = message [Value] = This is another message ) [3] = SimpleXMLElement Object ( [Name] = time [Value] = 1241334690 ) [4] = SimpleXMLElement Object ( [Name] = id [Value] = 12413346907303 ) [5] = SimpleXMLElement Object ( [Name] = ip [Value] = 10.10.10.2 ) ) ) ) So what code do I need to get through each of the object items? I'd like to loop through each of them and handle it like a returned mySQL query. For example, I can query SimpleDB and then loop though the SimpleXML so I can display the results on the page. Alternatively, how do you turn the whole shebang into an array? I'm new to SimpleXML, so I apologise if my questions aren't specific enough.

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  • Extracting table rows with a particular attribute from an HTML File, using HTMLAgilityPack

    - by Soham
    Consider this html snippet: <tr> <td valign=top class="tim_new"><a href="/stocks/company_info/pricechart.php?sc_did=MI42" class="tim_new">3M India</a></td> <td class="tim_new" valign=top><a href='/stocks/marketstats/indcomp.php?optex=NSE&indcode=Diversified' class=tim>Diversified</a></td> <td class="tim_new" align=right valign=top>2,487.25</td> <td class="tim_new" align=right valign=top><font color=#16a903>187.25</font></td> <td class="tim_new" align=right valign=top><font color=#16a903>8.14</font></td> <td class="tim_new" align=right valign=top>2,801.90</td> <td class="tim_new" align=right valign=top>0.06</td> </tr> Realize these three things: The HTML file from which this snippet has been taken, contains multiple number of HTML tables. The table from which this snippet has been extracted doesnt contain only rows of the shown format, but also of other formats like this, for example: <tr><td colspan=7><img src="http://img1.moneycontrol.com/images/blank.gif"height="5"></td></tr>` This same table contains multiple rows of the format which I need to extract. So given this scenario, is it possible to run a code, which extracts, the link with the class name = "tim_new"? Help Appreciated, Soham

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  • Mixing a4 and a3 in one Latex file

    - by jorgusch
    Hello, I am finishing my thesis and have a large appendix. Some tables only look good, if first done on a3 and then (paper)printed on a4. Anyhow, working all the files seperalty is fine, but I struggle to compile all in one. I use the geometry package and start the document with: \usepackage[a4paper,left=30mm,right=20mm,top=20mm, bottom=20mm]{geometry} For the appendix, I want to include the table and use \newgeometry{a3paper,left=25mm,right=15mm, top=15mm, bottom=15mm} However, the command is completely ignored and I can read "a3paper,left=25mm,right=15mm, top=15mm, bottom=15mm" above the table. What did I miss? Is it even possible? If not, how do I get the numbers right, if I have to include it as a pdf (which works)? Thanks!

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  • How to create a web-based Email Client in .NET?

    - by Blankman
    I am creating a web based email client in .NET using a 3rd party component. I just want to make sure I have the right idea: I will first pull the emails in using POP I will then parse each individual message that I got from POP using the MIME component right? My choices for 3rd party are: Nsoftware, Quiksoft or Dart. I am looking at Nsoftware right now though.

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  • RightBarButtonItem in iphone

    - by venkat
    hello all. i am using navigation control with left and right bar buttons.my right side bar button contains length of 10 chars. And my title contains 12 chars. when i press the right bar button my title is moving.how can i stop moving the title when clicking button.

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  • HTTPSConnection module missing in Python 2.6 on CentOS 5.2

    - by d2kagw
    Hi guys, I'm playing around with a Python application on CentOS 5.2. It uses the Boto module to communicate with Amazon Web Services, which requires communication through a HTTPS connection. When I try running my application I get an error regarding HTTPSConnection being missing: "AttributeError: 'module' object has no attribute 'HTTPSConnection'" Google doesn't really return anything relevant, I've tried most of the solutions but none of them solve the problem. Has anyone come across anything like it? Here's the traceback: Traceback (most recent call last): File "./chatter.py", line 114, in <module> sys.exit(main()) File "./chatter.py", line 92, in main chatter.status( ) File "/mnt/application/chatter/__init__.py", line 161, in status cQueue.connect() File "/mnt/application/chatter/tools.py", line 42, in connect self.connection = SQSConnection(cConfig.get("AWS", "KeyId"), cConfig.get("AWS", "AccessKey")); File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/sqs/connection.py", line 54, in __init__ self.region.endpoint, debug, https_connection_factory) File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/connection.py", line 418, in __init__ debug, https_connection_factory) File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/connection.py", line 189, in __init__ self.refresh_http_connection(self.server, self.is_secure) File "/usr/local/lib/python2.6/site-packages/boto-1.7a-py2.6.egg/boto/connection.py", line 247, in refresh_http_connection connection = httplib.HTTPSConnection(host) AttributeError: 'module' object has no attribute 'HTTPSConnection'

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  • Gradient a Parallelogram

    - by nuclearpenguin
    I'm working in JavaScript drawing on a canvas, and have four coordinates to draw a parallelogram, called A, B, C, and D starting from the top-left, top-right, bottom-left, and bottom right, respectively. An example of some coordinates might be: A: (3, 3) B: (4, 3) C: (1, 0) D: (2, 0) I can draw the parallelogram just fine, but I would like to fill it in with a gradient. I want the gradient to fill in from left to right, but matching the angle of the shape. The library I use (CAKE) requires a start and stop coordinate for the gradient. My stop and start would be somewhere half way between A and C, and end somewhere half way between B and D. Of course, it is not simply EXACTLY half way because the angles at A, B, C, and D are not right angles. So given this information (the coordinates), how to I find the point on the line A - C to start, and the point on the line B - D to stop? Remember, I'm doing this in JavaScript, so I have some good Math tools at my disposal for calculation.

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  • Most efficient way to combine two objects in C#

    - by Dested
    I have two objects that can be represented as an int, float, bool, or string. I need to perform an addition on these two objects with the results being the same thing c# would produce as a result. For instance 1+"Foo" would equal the string "1Foo", 2+2.5 would equal the float 5.5, and 3+3 would equal the int 6 . Currently I am using the code below but it seems like incredible overkill. Can anyone simplify or point me to some way to do this efficiently? private object Combine(object o, object o1) { float left = 0; float right = 0; bool isInt = false; string l = null; string r = null; if (o is int) { left = (int)o; isInt = true; } else if (o is float) { left = (float)o; } else if (o is bool) { l = o.ToString(); } else { l = (string)o; } if (o1 is int) { right = (int)o1; } else if (o is float) { right = (float)o1; isInt = false; } else if (o1 is bool) { r = o1.ToString(); isInt = false; } else { r = (string)o1; isInt = false; } object rr; if (l == null) { if (r == null) { rr = left + right; } else { rr = left + r; } } else { if (r == null) { rr = l + right; } else { rr = l + r; } } if (isInt) { return Convert.ToInt32(rr); } return rr; }

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  • java.bigDecimal divide in ruby environment

    - by Eyal
    I right script in Ruby that include java classes require 'java' include_class 'java.math.BigDecimal' include_class 'java.math.RoundingMode' during the script I need to divide 2 java.bigDecimal one = BigDecimal.new("1") number1 = BigDecimal.new("3") number1 = one.divide(number1,RoundingMode.new(HALF_EVEN)) since I don't have intellisense in this IDE I'm not sure the syntax is right and the runtime error is: uninitialized constant::HALF_EVEN do I combine java object in the ruby scrpit in the right way? how should I divide two java.bigDecimal object in ruby env?

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  • Combo box in a scrollable panel causing problems

    - by Dennis
    I have a panel with AutoScroll set to true. In it, I am programmatically adding ComboBox controls. If I add enough controls to exceed the viewable size of the panel a scroll bar appears (so far so good). However, if I open one of the combo boxes near the bottom of the viewable area the combo list isn't properly displayed and the scrollable area seems to be expanded. This results in all of the controls being "pulled" to the new bottom of the panel with some new blank space at the top. If I continue to tap on the drop down at the bottom of the panel the scrollable area will continue to expand indefinitely. I'm anchoring the controls to the left, right and top so I don't think anchoring is involved. Is there something obvious that could be causing this? Update: It looks like the problem lies with anchoring the controls to the right. If I don't anchor to the right then I don't get the strange behavior. However, without right anchoring the control gets cut off by the scroll bar. Here's a simplified test case I built that shows the issue: public Form1() { InitializeComponent(); Panel panel = new Panel(); panel.Size = new Size(80, 200); panel.AutoScroll = true; for (int i = 0; i < 10; ++i) { ComboBox cb = new ComboBox(); cb.Anchor = AnchorStyles.Left | AnchorStyles.Right | AnchorStyles.Top; cb.Items.Add("Option 1"); cb.Items.Add("Option 2"); cb.Items.Add("Option 3"); cb.Items.Add("Option 4"); cb.Location = new Point(0, i * 24); panel.Controls.Add(cb); } Controls.Add(panel); } If you scroll the bottom of the panel and tap on the combo boxes near the bottom you'll notice the strange behavior.

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  • BST insert operation. don't insert a node if a duplicate exists already

    - by jeev
    the following code reads an input array, and constructs a BST from it. if the current arr[i] is a duplicate, of a node in the tree, then arr[i] is discarded. count in the struct node refers to the number of times a number appears in the array. fi refers to the first index of the element found in the array. after the insertion, i am doing a post-order traversal of the tree and printing the data, count and index (in this order). the output i am getting when i run this code is: 0 0 7 0 0 6 thank you for your help. Jeev struct node{ int data; struct node *left; struct node *right; int fi; int count; }; struct node* binSearchTree(int arr[], int size); int setdata(struct node**node, int data, int index); void insert(int data, struct node **root, int index); void sortOnCount(struct node* root); void main(){ int arr[] = {2,5,2,8,5,6,8,8}; int size = sizeof(arr)/sizeof(arr[0]); struct node* temp = binSearchTree(arr, size); sortOnCount(temp); } struct node* binSearchTree(int arr[], int size){ struct node* root = (struct node*)malloc(sizeof(struct node)); if(!setdata(&root, arr[0], 0)) fprintf(stderr, "root couldn't be initialized"); int i = 1; for(;i<size;i++){ insert(arr[i], &root, i); } return root; } int setdata(struct node** nod, int data, int index){ if(*nod!=NULL){ (*nod)->fi = index; (*nod)->left = NULL; (*nod)->right = NULL; return 1; } return 0; } void insert(int data, struct node **root, int index){ struct node* new = (struct node*)malloc(sizeof(struct node)); setdata(&new, data, index); struct node** temp = root; while(1){ if(data<=(*temp)->data){ if((*temp)->left!=NULL) *temp=(*temp)->left; else{ (*temp)->left = new; break; } } else if(data>(*temp)->data){ if((*temp)->right!=NULL) *temp=(*temp)->right; else{ (*temp)->right = new; break; } } else{ (*temp)->count++; free(new); break; } } } void sortOnCount(struct node* root){ if(root!=NULL){ sortOnCount(root->left); sortOnCount(root->right); printf("%d %d %d\n", (root)->data, (root)->count, (root)->fi); } }

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  • How to make an equation span the whole page / line in LaTeX?

    - by Reed Richards
    I have this equation and it's quite big (basically a FDM one) but it aligns with the text and then continues out on the right side to the nothingness. I've tried stuff like \begin{center} and \hspace*{-2.5cm} but to no avail. I want it to use the whole line not just from the left-margin and out to the right. How do I do it and do I need to install some special package for it? I use the \[ instead of the displaymath like this \[ Equation arrays here \] The code \[ \left( \begin{array}{cccccc} -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots & 0 \\ -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots \\ 0 & -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) & 0 & \cdots \\ \vdots & 0 & \ddots & \vdots \\ \vdots & \vdots & \vdots & -\kappa & -(2\kappa+\frac{hV\rho}{2}) & (\frac{hV\rho}{2}-\kappa) \\ 0 & \vdots & \vdots & 0 & \kappa - \frac{2h\kappa_{v}}{\kappa}(\frac{hv\rho}{2} - \kappa) & -2\kappa \\ \end{array} \right) \left( \begin{array}{c} T_{1} \\ T_{2} \\ \vdots \\ T_{n} \\ \end{array} \right) = \left( \begin{array}{c} Q(0) + \kappa T_{0} \\ Q(h) \\ Q(2h) \\ \vdots \\ Q((n-1)h) \\ 2\frac{\kappa_{v}}{\kappa_{v}}T_{out} \\ \end{array} \right) \]

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  • Prolog: Not executing code as expected.

    - by Louis
    Basically I am attempting to have an AI agent navigate a world based on given percepts. My issue is handling how the agent moves. Basically, I have created find_action/4 such that we pass in the percepts, action, current cell, and the direction the agent is facing. As it stands the entire code looks like: http://wesnoth.pastebin.com/kdNvzZ6Y My issue is mainly with lines 102 to 106. Basically, in it's current form the code does not work and the find_action is skipped even when the agent is in fact facing right (I have verified this). This broken code is as follows: % If we are headed right, take a left turn find_action([_, _, _, _, _], Action, _, right) :- retractall(facing(_)), assert(facing(up)), Action = turnleft . However, after some experimentation I have concluded that the following works: % If we are headed right, take a left turn find_action([_, _, _, _, _], Action, _, _) :- facing(right), retractall(facing(_)), assert(facing(up)), Action = turnleft . I am not entire sure why this is. I've attempted to create several identical find_action's as well, each checking a different direction using the facing(_) format, however swipl does not like this and throws an error. Any help would be greatly appreciated.

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  • Rails CSS not Loading using Heroku

    - by eWizardII
    I have the following site set up here on Heroku - http://www.peerinstruction.net/users/sign_up the issue is that I have updated the css yet it is not being actively reflected on the site, it just shows a textbox, with some edited/custom fonts. I have attached the css file in the following gist - https://gist.github.com/f74b626c54ecbb60bbde The signup page controller: !!! Strict %html %head %title= yield(:title) || "Untitled" = stylesheet_link_tag 'application', 'web-app-theme/base', 'web-app-theme/themes/activo/style', 'web-app-theme/override' = javascript_include_tag :defaults = csrf_meta_tag = yield(:head) %body #container #header %h1 %a{:href => "/"} Peer Instruction Network #user-navigation %ul.wat-cf %li .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => session_path(resource_name), :html => { :class => "form login" }) do |f| .group.wat-cf .left= f.label :email, :class => "label right" .right= f.text_field :email, :class => "text_field" .group.wat-cf .left= f.label :password, :class => "label right" .right= f.password_field :password, :class => "text_field" .group.wat-cf .right %button.button{ :type => "submit" } Login /= link_to "Sign In", destroy_user_session_path #box = yield The signup pages haml file: %h2 .block .content.login .flash - flash.each do |type, message| %div{ :class => "message #{type}" } %p= message = form_for(resource, :as => resource_name, :url => registration_path(resource_name)) do |f| = devise_error_messages! %div = f.label :firstname %br/ = f.text_field :firstname %div = f.label :middlename %br/ = f.text_field :middlename %div = f.label :lastname %br/ = f.text_field :lastname %div = f.label :email %br/ = f.email_field :email %div = f.label :password %br/ = f.password_field :password %div = f.label :academic %br/ = f.text_field :academic %div= f.submit "Continue" = render :partial => "devise/shared/links" I used web-app-theme to create an activo theme and then modify it.

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  • Windows store apps: ScrollViewer with dinamic content

    - by Alexandru Circus
    I have a scrollViewer with an ItemsControl (which holds rows with data) as content. The data from these rows is grabbed from the server so I want to display a ProgressRing with a text until the data arrives. Basically I want the content of the ScrollViewer to be a grid with progress ring and a text and after the data arrives the content to be changed with my ItemsControl. The problem is that the ScrollViewer does not accept more than 1 element as content. Please tell me how can I solve this problem. (I'm a C# beginner) <FlipView x:Name="OptionPagesFlipView" Grid.Row="1" TabNavigation="Cycle" SelectionChanged="OptionPagesFlipView_SelectionChanged" ItemsSource="{Binding OptionsPageItems}"> <FlipView.ItemTemplate> <DataTemplate x:Name="OptionMonthPageTemplate"> <ScrollViewer x:Name="OptionsScrollViewer" HorizontalScrollMode="Disabled" HorizontalAlignment="Stretch" VerticalScrollBarVisibility="Auto"> <ItemsControl x:Name="OptionItemsControl" ItemsSource="{Binding OptionItems, Mode=OneWay}" Visibility="Collapsed"> <ItemsControl.ItemTemplate> <DataTemplate x:Name="OptionsChainItemTemplate"> <Grid x:Name="OptionItemGrid" Background="#FF9DBDF7" HorizontalAlignment="Stretch"> <Grid.RowDefinitions> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> <RowDefinition Height="Auto"/> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> <ColumnDefinition Width="*" /> </Grid.ColumnDefinitions> <!-- CALL BID --> <TextBlock Text="Bid" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="0" Grid.Column="0" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallBidTextBlock" Text="{Binding CallBid}" Foreground="Blue" HorizontalAlignment="Left" Grid.Row="1" Grid.Column="0" Margin="5,0,5,5" FontSize="18"/> <!-- CALL ASK --> <TextBlock Text="Ask" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="2" Grid.Column="0" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallAskTextBlock" Text="{Binding CallAsk}" Foreground="Blue" HorizontalAlignment="Left" Grid.Row="3" Grid.Column="0" Margin="5,0,5,0" FontSize="18"/> <!-- CALL LAST --> <TextBlock Text="Last" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="0" Grid.Column="1" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallLastTextBlock" Text="{Binding CallLast}" Foreground="Blue" HorizontalAlignment="Left" Grid.Row="1" Grid.Column="1" Margin="5,0,5,5" FontSize="18"/> <!-- CALL NET CHANGE --> <TextBlock Text="Net Ch" Foreground="Gray" HorizontalAlignment="Left" Grid.Row="2" Grid.Column="1" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="CallNetChTextBlock" Text="{Binding CallNetChange}" Foreground="{Binding CallNetChangeForeground}" HorizontalAlignment="Left" Grid.Row="3" Grid.Column="1" Margin="5,0,5,5" FontSize="18"/> <!-- STRIKE --> <TextBlock Text="Strike" Foreground="Gray" HorizontalAlignment="Center" Grid.Row="1" Grid.Column="2" FontSize="18" Margin="5,0,5,0"/> <Border Background="{Binding StrikeBackground}" HorizontalAlignment="Center" Grid.Row="2" Grid.Column="2" Margin="5,0,5,5"> <TextBlock x:Name="StrikeTextBlock" Text="{Binding Strike}" Foreground="Blue" FontSize="18"/> </Border> <!-- PUT LAST --> <TextBlock Text="Last" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="0" Grid.Column="3" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="PutLastTextBlock" Text="{Binding PutLast}" Foreground="Blue" HorizontalAlignment="Right" Grid.Row="1" Grid.Column="3" Margin="5,0,5,5" FontSize="18"/> <!-- PUT NET CHANGE --> <TextBlock Text="Net Ch" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="2" Grid.Column="3" FontSize="18" Margin="5,0,5,0"/> <TextBlock x:Name="PutNetChangeTextBlock" Text="{Binding PutNetChange}" Foreground="{Binding PutNetChangeForeground}" HorizontalAlignment="Right" Grid.Row="3" Grid.Column="3" Margin="5,0,5,5" FontSize="18"/> <!-- PUT BID --> <TextBlock Text="Bid" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="0" Grid.Column="4" FontSize="18" Margin="5,0,15,0"/> <TextBlock x:Name="PutBidTextBlock" Text="{Binding PutBid}" Foreground="Blue" HorizontalAlignment="Right" Grid.Row="1" Grid.Column="4" Margin="5,0,15,5" FontSize="18"/> <!-- PUT ASK --> <TextBlock Text="Ask" Foreground="Gray" HorizontalAlignment="Right" Grid.Row="2" Grid.Column="4" FontSize="18" Margin="5,0,15,0"/> <TextBlock x:Name="PutAskTextBlock" Text="{Binding PutAsk}" Foreground="Blue" HorizontalAlignment="Right" Grid.Row="3" Grid.Column="4" Margin="5,0,15,5" FontSize="18"/> <!-- BOTTOM LINE SEPARATOR--> <Rectangle Fill="Black" Height="1" Grid.ColumnSpan="5" VerticalAlignment="Bottom" Grid.Row="3"/> </Grid> </DataTemplate> </ItemsControl.ItemTemplate> </ItemsControl> <!--<Grid> <Grid.RowDefinitions> <RowDefinition/> </Grid.RowDefinitions> <Grid.ColumnDefinitions> <ColumnDefinition/> <ColumnDefinition/> </Grid.ColumnDefinitions> <ProgressRing x:Name="CustomProgressRing" Height="40" Width="40" IsActive="true" Grid.Column="0" Margin="20" Foreground="White"/> <TextBlock x:Name="CustomTextBlock" Height="auto" Width="auto" FontSize="25" Grid.Column="1" Margin="20"/> <Border BorderBrush="#FFFFFF" BorderThickness="1" Grid.ColumnSpan="2"/> </Grid>--> </ScrollViewer> </DataTemplate> </FlipView.ItemTemplate>

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  • Div tags, how to create rows with them

    - by Daniel
    How to you define a row in div tags High level example in pseudo code: [DIV TAGS LEFT] [DIV TAGS CENTER] [DIV TAGS RIGHT] [WHAT GOES HERE?????] [DIV TAGS LEFT] [DIV TAGS CENTER] [DIV TAGS RIGHT] [WHAT GOES HERE?????] [DIV TAGS LEFT] [DIV TAGS CENTER] [DIV TAGS RIGHT]

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  • jQuery check offset

    - by Glister
    HTML: <ul class="clients"> <li> <div class="over left">Description</div> <div class="inner">Image</div> </li> </ul> CSS: .clients { margin-right: -20px; } .clients li { float: left; width: 128px; height: 120px; margin: 0 20px 20px 0; border: 1px solid #c2c2c2; } .clients .over { display: none; position: absolute; width: 250px; font-size: 11px; line-height: 16px; background: #ecf5fb; margin: 3px 0 0 3px; padding: 18px; z-index: 25; } .clients .right { margin: 3px 0 0 -161px; } .clients .inner { width: 128px; height: 120px; overflow: hidden; } So, we have a list of floated squares and a popup blocks in each, which have absolute position. JS: jQuery(function($) { $('input[title!=""]').hint(); $(".clients li").bind('mouseover mouseout',function(){$(this).find("div.over").toggle()}); }); If over - show, else - hide. Quite ok, but it must be more advanced, we should catch an offset and give a class to .over block: if offset from right (corner of browser window) less than 150px, then add class "right" for a .over block. if offset from right more than 150px - add class "left" for a .over block. How can we do it?

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  • Manipulating / Resizing / Scaling an image in vb.net

    - by Christian Payne
    Imagine I have a rectangle say 400px x 300px. Then let’s say I want to load an image in that. All of this is very easy using Sytem.Drawing.DrawImage. But then I want to leave the left hand side as 300px but change the right hand side to 250 px. I can draw the box using 4 DrawLines but I don’t know how to squash the image into the new shape. I want the right hand side of the shape to be 250, the left size 300 and the top and bottom 400px. I can’t use DrawImage as it expects the left and right sizes to be the same. Is there a way to manipulate the image into the new shape? I've looked at other questions, but they only apply where the left and right hand side is equal. Any thoughts on how to squash an image into a shape which did not have parallel sides? (If it helps, I'm happy to sacrifice image quality to fit the right shape.)

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  • background image disappears when position relative used in firefox

    - by toomanyairmiles
    So I'm trying to add a badge to the top right corner of a site I'm doing some work on. z-index works to float the object above the page content but each time i try to use position relative the background image disappears only position absolute shows the image. I don't really want to use absolute as the image needs to be positioned on the right hand side of the sites menu bar not the right hand side of the viewport. Any thoughts or advice appreciated <div class="badge-box"> <a href="http://www.google.com" class="badge">Book Now!</a> </div> <div id="header"> <a href="index.php"><img src="images/pixel.gif" width="378" height="31" alt="Welcome to Gwynfryn Farm Cottages" /></a> </div> <div id="main-menu"> <div> <a href="/">Home</a> <a href="/cottages.php">Our Cottages</a> <a href="/gwynfryn.php">Bed &amp; Breakfast</a> <a href="/rates.php">Price Guide</a> <a href="/llanbedr.php">Location &amp; Local Attractions</a> <a href="/news.php">News &amp; Special Offers</a> <a href="/contact.php">Contact Us</a> </div> </div> .badge-box { width: 1030px; margin-left: auto; margin-right: auto; border: 0px solid red; } .badge { background: url(../images/badge.png) 0px 0px no-repeat; width: 148px; height: 148px; text-indent: -10000px; position: relative; z-index: 999; } #header { width: 960px; height: 40px; margin-left:auto; margin-right:auto; margin-top:20px; padding: 20px 0px 0px 20px; background: #58564f url(../images/header-top-background.png); } #main-menu { width: 980px; margin-left: auto; margin-right: auto; height: 35px; /*background: red;*/ background: #58564f url(../images/header-bottom-background.png); font-family: Georgia, "Times New Roman", Times, serif; } #main-menu div { width: 776px; height: 35px; margin-left: auto; margin-right: auto; background: blue; } #main-menu div a { display: block; float: left; padding: 5px 10px 0px 10px; height: 30px; color: #FFFFFF; font-size: 1.2em; text-align: center; background: green; } #main-menu div a:hover { background-color: #333333; }

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  • How to make my robot move in a rectangular path along the black tape?

    - by Sahat
    I am working on a robot, it's part of the summer robotics workshop in our college. We are using C-STAMP micro controllers by A-WIT. I was able to make it move, turn left, turn right, move backward. I have even managed to make it go along the black tape using a contrast sensor. I send the robot at 30-45 degrees toward the black tape on the table and it aligns itself and starts to move along the black tape. It jerks a little, probably due to my programming logic below, it's running a while loop and constantly checking if statements, so it ends up trying to turn left and right every few milliseconds, which explains the jerking part. But it's okay, it works, not as smooth as I want it to work but it works! Problem is that I can't make my robot go into a rectangular path of the black tape. As soon as it reaches the corner it just keeps going straight instead of making a left/right turn. Here's my attempt. The following code is just part of the code. My 2 sensors are located right underneath the robot, next to the front wheel, almost at the floor level. It has "index" value ranging from 0 to 8. I believe it's 8 when you have a lot of light coming into the sensor , and 0 when it's nearly pitch black. So when the robot moves into the black-tape-zone, the index value drops, and based on that I have an if-statement telling my robot to either turn left or right. To avoid confusion I didn't post the entire source code, but only the logical part responsible for the movement of my robot along the black tape. while(1) { // don't worry about these. // 10 and 9 represent Sensor's PIN location on the motherboard V = ANALOGIN(10, 1, 0, 0, 0); V2 = ANALOGIN(9, 1, 0, 0, 0); // i got this "formula" from the example in my Manual. // V stands for voltage of the sensor. // it gives me the index value of the sensor. 0 = darkest, 8 = lightest. index = ((-(V - 5) / 5) * 8 + 0.5); index2 = ((-(V2 - 5) / 5) * 8 + 0.5); // i've tweaked the position of the sensors so index > 7 is just right number. // the robot will move anywhere on the table just fine with index > 7. // as soon as it drops to or below 7 (i.e. finds black tape), the robot will // either turn left or right and then go forward. // lp & rp represent left-wheel pin and right-wheel pin, 1 means run forever. // if i change it from 1 to 100, it will go forward for 100ms. if (index > 7 && index2 > 7) goForward(lp, rp, 1); if (index <= 7) { turnLeft(lp, rp, 1); goForward(lp, rp, 1); // this is the tricky part. i've added this code last minute // trying to make my robot turn, but i didn't work. if (index > 4) { turnLeft(lp, rp, 1); goForward(lp, rp, 1); } } else if (index2 <= 7) { turnRight(lp, rp, 1); goForward(lp, rp, 1); // this is also the last minute addition. it's same code as above // but it's for the 2nd sensor. if (index2 > 4) { turnRight(lp, rp, 1); goForward(lp, rp, 1); } } I've spent the entire day trying to figure it out. I've pretty much exhausted all avenues. Asking for the solution on stackoverflow is my very last option now. Thanks in advance! If you have any questions about the code, let me know, but comments should be self-explanatory.

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  • C++ find largest BST in a binary tree

    - by fonjibe
    what is your approach to have the largest BST in a binary tree? I refer to this post where a very good implementation for finding if a tree is BST or not is bool isBinarySearchTree(BinaryTree * n, int min=std::numeric_limits<int>::min(), int max=std::numeric_limits<int>::max()) { return !n || (min < n->value && n->value < max && isBinarySearchTree(n->l, min, n->value) && isBinarySearchTree(n->r, n->value, max)); } It is quite easy to implement a solution to find whether a tree contains a binary search tree. i think that the following method makes it: bool includeSomeBST(BinaryTree* n) { if(!isBinarySearchTree(n)) { if(!isBinarySearchTree(n->left)) return isBinarySearchTree(n->right); } else return true; else return true; } but what if i want the largest BST? this is my first idea, BinaryTree largestBST(BinaryTree* n) { if(isBinarySearchTree(n)) return n; if(!isBinarySearchTree(n->left)) { if(!isBinarySearchTree(n->right)) if(includeSomeBST(n->right)) return largestBST(n->right); else if(includeSomeBST(n->left)) return largestBST(n->left); else return NULL; else return n->right; } else return n->left; } but its not telling the largest actually. i struggle to make the comparison. how should it take place? thanks

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  • Using recursion to to trim a binary tree based on a given min and max value

    - by Justin
    As the title says, I have to trim a binary tree based on a given min and max value. Each node stores a value, and a left/right node. I may define private helper methods to solve this problem, but otherwise I may not call any other methods of the class nor create any data structures such as arrays, lists, etc. An example would look like this: overallRoot _____[50]____________________ / \ __________[38] _______________[90] / \ / _[14] [42] [54]_____ / \ \ [8] [20] [72] \ / \ [26] [61] [83] trim(52, 65); should return: overallRoot [54] \ [61] My attempted solution has three methods: public void trim(int min, int max) { rootFinder(overallRoot, min, max); } First recursive method finds the new root perfectly. private void rootFinder(IntTreeNode node, int min, int max) { if (node == null) return; if (overallRoot.data < min) { node = overallRoot = node.right; rootFinder(node, min, max); } else if (overallRoot.data > max) { node = overallRoot = node.left; rootFinder(node, min, max); } else cutter(overallRoot, min, max); } This second method should eliminate any further nodes not within the min/max, but it doesn't work as I would hope. private void cutter(IntTreeNode node, int min, int max) { if (node == null) return; if (node.data <= min) { node.left = null; } if (node.data >= max) { node.right = null; } if (node.data < min) { node = node.right; } if (node.data > max) { node = node.left; } cutter(node.left, min, max); cutter(node.right, min, max); } This returns: overallRoot [54]_____ \ [72] / [61] Any help is appreciated. Feel free to ask for further explanation as needed.

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  • How to make a control invisible?

    - by Nakilon
    I've made several TextCtrls and Button, but currently users of my application don't want to see them. So I have to hide them temporary (for current build). Here they are: class MainFrame < Wx::Frame def initialize (parent = nil) super nil,:title=>"sometitle",:size=>[600,600] set_sizer Wx::BoxSizer.new Wx::VERTICAL @tag1 = Wx::TextCtrl.new self sizer.add_item @tag1,:flag=>Wx::RIGHT|Wx::EXPAND @tag1.set_value 'property' @tag1title = Wx::TextCtrl.new self sizer.add_item @tag1title,:flag=>Wx::RIGHT|Wx::EXPAND @tag1title.set_value 'title' @tag2 = Wx::TextCtrl.new self sizer.add_item @tag2,:flag=>Wx::RIGHT|Wx::EXPAND @tag2.set_value 'description' @tag2title = Wx::TextCtrl.new self sizer.add_item @tag2title,:flag=>Wx::RIGHT|Wx::EXPAND @tag2title.set_value '' @button_parse = Wx::Button.new self sizer.add_item @button_parse @button_parse.label = "Parse XML" evt_button @button_parse, :click_parse # ...... end # ...... end I see nothing about it in docs and Google is also not a friend for me today.

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  • Improve performance of searching JSON object with jQuery

    - by cale_b
    Please forgive me if this is answered on SO somewhere already. I've searched, and it seems as though this is a fairly specific case. Here's an example of the JSON (NOTE: this is very stripped down - this is dynamically loaded, and currently there are 126 records): var layout = { "2":[{"id":"40","attribute_id":"2","option_id":null,"design_attribute_id":"4","design_option_id":"131","width":"10","height":"10", "repeat":"0","top":"0","left":"0","bottom":"0","right":"0","use_right":"0","use_bottom":"0","apply_to_options":"0"}, {"id":"41","attribute_id":"2","option_id":"115","design_attribute_id":"4","design_option_id":"131","width":"2","height":"1", "repeat":"0","top":"0","left":"0","bottom":"4","right":"2","use_right":"0","use_bottom":"0","apply_to_options":"0"}, {"id":"44","attribute_id":"2","option_id":"118","design_attribute_id":"4","design_option_id":"131","width":"10","height":"10", "repeat":"0","top":"0","left":"0","bottom":"0","right":"0","use_right":"0","use_bottom":"0","apply_to_options":"0"}], "5":[{"id":"326","attribute_id":"5","option_id":null,"design_attribute_id":"4","design_option_id":"154","width":"5","height":"5", "repeat":"0","top":"0","left":"0","bottom":"0","right":"0","use_right":"0","use_bottom":"0","apply_to_options":"0"}] }; I need to match the right combination of values. Here's the function I currently use: function drawOption(attid, optid) { var attlayout = layout[attid]; $.each(attlayout, function(k, v) { // d_opt_id and d_opt_id are global scoped variable set elsewhere if (v.design_attribute_id == d_att_id && v.design_option_id == d_opt_id && v.attribute_id == attid && ((v.apply_to_options == 1 || (v.option_id === optid)))) { // Do stuff here } }); } The issue is that I might iterate through 10-15 layouts (unique attid's), and any given layout (attid) might have as many as 50 possibilities, which means that this loop is being run A LOT. Given the multiple criteria that have to be matched, would an AJAX call work better? (This JSON is dynamically created via PHP, so I could craft a PHP function that could possibly do this more efficently), or am I completely missing something about how to find items in a JSON object? As always, any suggestions for improving the code are welcome! EDIT: I apologize for not making this clear, but the purpose of this question is to find a way to improve the performance. The page has a lot of javascript, and this is a location where I know that performance is lower than it could be.

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