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  • Dynamically class creating by using Java Reflection, java.lang.ClassNotFoundException

    - by rubby
    Hi all; i want to use reflection in java, i want to do that third class will read the name of the class as String from console. Upon reading the name of the class, it will automatically and dynamically (!) generate that class and call its writeout method. If that class is not read from input, it will not be initialized. I wrote that codes but i am always taking to "java.lang.Class.Not.Found.Exception", and i don't know how i can fix it. Can anyone help me? class class3 { public Object dynamicsinif(String className, String fieldName, String value) throws Exception { Class cls = Class.forName(className,true,null); Object obj = cls.newInstance(); Field fld = cls.getField(fieldName); fld.set(obj, value); return obj; } public void writeout3() { System.out.println("class3"); } } public class Main { public static void main(String[] args) throws Exception { System.out.println("enter the class name : "); BufferedReader reader= new BufferedReader(new InputStreamReader(System.in)); String line=reader.readLine(); String x="Text1"; try{ class3 trycls=new class3(); Object gelen=trycls.dynamicsinif(line, x, "rubby"); Class yeni=(Class)gelen; System.out.println(yeni); }catch(ClassNotFoundException ex){ System.out.print(ex.toString()); } } }

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  • Java InputStream encoding/charset

    - by Tobbe
    Running the following (example) code import java.io.*; public class test { public static void main(String[] args) throws Exception { byte[] buf = {-27}; InputStream is = new ByteArrayInputStream(buf); BufferedReader r = new BufferedReader(new InputStreamReader(is, "ISO-8859-1")); String s = r.readLine(); System.out.println("test.java:9 [byte] (char)" + (char)s.getBytes()[0] + " (int)" + (int)s.getBytes()[0]); System.out.println("test.java:10 [char] (char)" + (char)s.charAt(0) + " (int)" + (int)s.charAt(0)); System.out.println("test.java:11 string below"); System.out.println(s); System.out.println("test.java:13 string above"); } } gives me this output test.java:9 [byte] (char)? (int)63 test.java:10 [char] (char)? (int)229 test.java:11 string below ? test.java:13 string above How do I retain the correct byte value (-27) in the line-9 printout? And consequently receive the expected output of the System.out.println(s) command (å).

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  • Java: How to make this main thread wait for the new thread to terminate

    - by Jeff Bullard
    I have a java class that creates a process, called child, using ProcessBuilder. The child process generates a lot of output that I am draining on a separate thread to keep the main thread from getting blocked. However, a little later on I need to wait for the output thread to complete/terminate before going on, and I'm not sure how to do that. I think that join() is the usual way to do this but I'm not sure how to do that in this case. Here is the relevant part of the java code. // Capture output from process called child on a separate thread final StringBuffer outtext = new StringBuffer(""); new Thread(new Runnable() { public void run() { InputStream in = null; in = child.getInputStream(); try { if (in != null) { BufferedReader reader = new BufferedReader(new InputStreamReader(in)); String line = reader.readLine(); while ((line != null)) { outtext.append(line).append("\n"); ServerFile.appendUserOpTextFile(userName, opname, outfile, line+"\n"); line = reader.readLine(); } } } catch (IOException iox) { throw new RuntimeException(iox); } } }).start(); // Write input to for the child process on this main thread // String intext = ServerFile.readUserOpTextFile(userName, opname, infile); OutputStream out = child.getOutputStream(); try { out.write(intext.getBytes()); out.close(); } catch (IOException iox) { throw new RuntimeException(iox); } // ***HERE IS WHERE I NEED TO WAIT FOR THE THREAD TO FINISH *** // Other code goes here that needs to wait for outtext to get all // of the output from the process // Then, finally, when all the remaining code is finished, I return // the contents of outtext return outtext.toString();

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  • Displaying NON-ASCII Characters using HttpClient

    - by Abdullah Gheith
    So, i am using this code to get the whole HTML of a website. But i dont seem to get non-ascii characters with me. all i get is diamonds with question mark. characters like this: å, appears like this: ? I doubt its because of the charset, what could it then be? Log.e("HTML", "henter htmlen.."); String url = "http://beep.tv2.dk"; HttpClient client = new DefaultHttpClient(); client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); client.getParams().setParameter(CoreProtocolPNames.HTTP_ELEMENT_CHARSET, "UTF-8"); HttpGet request = new HttpGet(url); HttpResponse response = client.execute(request); Header h = HeaderValueFormatter response.addHeader(header) String html = ""; InputStream in = response.getEntity().getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); StringBuilder str = new StringBuilder(); String line = null; while((line = reader.readLine()) != null) { str.append(line); } in.close(); //b = false; html = str.toString();

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  • Reading from txt ruins formatting

    - by Sorin Grecu
    I'm saving some values to a txt file and after that i want to be able to show it in a dialog.All good,done that but though the values in the txt file are formated nicely,like this : Aaaaaaaa 0.55 1 Bbbbb 1 2.2 CCCCCCCCC 3 0.22 When reading and setting them to a textview they get all messy like this : Aaaaaaaa 0.55 1 Bbbbb 1 2.2 CCCCCCCCC 3 0.22 My writting method : FileOutputStream f = new FileOutputStream(file); PrintWriter pw = new PrintWriter(f); for (int n = 0; n < allpret.size() - 1; n++) { if (cant[n] != Float.toString(0) && pret[n] != Float.toString(0)) { String myFormat = "%-20s %-5s %-5s%n"; pw.println(String.format(myFormat, prod[n], cant[n], pret[n])); My reading method : StringBuilder text = new StringBuilder(); try { BufferedReader br = new BufferedReader(new FileReader(file)); String line; while ((line = br.readLine()) != null) { text.append(line); text.append('\n'); } } catch (IOException e) { } Why does it ruin the amount of spaces and how can i fix this ? Thanks and have a good night !

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  • Search a string in a file and write the matched lines to another file in Java

    - by Geeta
    For searching a string in a file and writing the lines with matched string to another file it takes 15 - 20 mins for a single zip file of 70MB(compressed state). Is there any ways to minimise it. my source code: getting Zip file entries zipFile = new ZipFile(source_file_name); entries = zipFile.entries(); while (entries.hasMoreElements()) { ZipEntry entry = (ZipEntry)entries.nextElement(); if (entry.isDirectory()) { continue; } searchString(Thread.currentThread(),entry.getName(), new BufferedInputStream (zipFile.getInputStream(entry)), Out_File, search_string, stats); } zipFile.close(); Searching String public void searchString(Thread CThread, String Source_File, BufferedInputStream in, File outfile, String search, String stats) throws IOException { int count = 0; int countw = 0; int countl = 0; String s; String[] str; BufferedReader br2 = new BufferedReader(new InputStreamReader(in)); System.out.println(CThread.currentThread()); while ((s = br2.readLine()) != null) { str = s.split(search); count = str.length - 1; countw += count; //word count if (s.contains(search)) { countl++; //line count WriteFile(CThread,s, outfile.toString(), search); } } br2.close(); in.close(); } -------------------------------------------------------------------------------- public void WriteFile(Thread CThread,String line, String out, String search) throws IOException { BufferedWriter bufferedWriter = null; System.out.println("writre thread"+CThread.currentThread()); bufferedWriter = new BufferedWriter(new FileWriter(out, true)); bufferedWriter.write(line); bufferedWriter.newLine(); bufferedWriter.flush(); } Please help me. Its really taking 40 mins for 10 files using threads and 15 - 20 mins for a single file of 70MB after being compressed. Any ways to minimise the time.

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  • Can someone tell me what this Java class does? I/O related

    - by anon
    I am relatively new to Java and trying to learn the I/O syntax. Could someone give me a general overview of what this code does? Thanks!! import java.io.*; public class FileReader { private String openFile=""; private String saveFile=""; FileReader(openFile, saveFile) { this.openFile=openFile; this.saveFile=saveFile; } public String process(){ System.out.println(this.openFile); System.out.println(this.saveFile); BufferedReader open=null; FileReader openFR=null; FileWriter save=null; int counter=0; String output=""; if(openFile.equals("")){ return "No open file specifified\n"; } if(this.saveFile.equals("")){ return "No save file specified\n"; } try { openFR = new FileReader(this.openFile); open = new BufferedReader(openFR); } catch (FileNotFoundException e) { return ("Open file no longer exists\n"); } try { save = new FileWriter(saveFile); } catch (IOException e){ return ("Error saving the file\n"); } try{ String temp = open.readLine(); while(temp != null){ temp = open.readLine(); counter++; save.write(output + "\n"); } } catch (IOException e){ e.getStackTrace(); return ("Error reading open file"); } try { save.flush(); } catch (IOException e) { e.printStackTrace(); return ("Error writing save file"); } return "Operation completed successfully"; } }

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  • Uva's 3n+1 problem

    - by dmindreader
    I'm solving Uva's 3n+1 problem and I don't get why the judge is rejecting my answer. The time limit hasn't been exceeded and the all test cases I've tried have run correctly so far. import java.io.*; public class NewClass{ /** * @param args the command line arguments */ public static void main(String[] args) throws IOException { int maxCounter= 0; int input; int lowerBound; int upperBound; int counter; int numberOfCycles; int maxCycles= 0; int lowerInt; BufferedReader consoleInput = new BufferedReader(new InputStreamReader(System.in)); String line = consoleInput.readLine(); String [] splitted = line.split(" "); lowerBound = Integer.parseInt(splitted[0]); upperBound = Integer.parseInt(splitted[1]); int [] recentlyused = new int[1000001]; if (lowerBound > upperBound ) { int h = upperBound; upperBound = lowerBound; lowerBound = h; } lowerInt = lowerBound; while (lowerBound <= upperBound) { counter = lowerBound; numberOfCycles = 0; if (recentlyused[counter] == 0) { while ( counter != 1 ) { if (recentlyused[counter] != 0) { numberOfCycles = recentlyused[counter] + numberOfCycles; counter = 1; } else { if (counter % 2 == 0) { counter = counter /2; } else { counter = 3*counter + 1; } numberOfCycles++; } } } else { numberOfCycles = recentlyused[counter] + numberOfCycles; counter = 1; } recentlyused[lowerBound] = numberOfCycles; if (numberOfCycles > maxCycles) { maxCycles = numberOfCycles; } lowerBound++; } System.out.println(lowerInt +" "+ upperBound+ " "+ (maxCycles+1)); } }

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  • Java Trying to get a line of source from a website

    - by dsta
    I'm trying to get one line of source from a website and then I'm returning that line back to main. I keep on getting an error at the line where I define InputStream in. Why am I getting an error at this line? public class MP3LinkRetriever { private static String line; public static void main(String[] args) { String link = "www.google.com"; String line = ""; while (link != "") { link = JOptionPane.showInputDialog("Please enter the link"); try { line = Connect(link); } catch(Exception e) { } JOptionPane.showMessageDialog(null, "MP3 Link: " + parseLine(line)); String text = line; Toolkit.getDefaultToolkit( ).getSystemClipboard() .setContents(new StringSelection(text), new ClipboardOwner() { public void lostOwnership(Clipboard c, Transferable t) { } }); JOptionPane.showMessageDialog(null, "Link copied to your clipboard"); } } public static String Connect(String link) throws Exception { String strLine = null; InputStream in = null; try { URL url = new URL(link); HttpURLConnection uc = (HttpURLConnection) url.openConnection(); in = new BufferedInputStream(uc.getInputStream()); Reader re = new InputStreamReader(in); BufferedReader r = new BufferedReader(re); int index = -1; while ((strLine = r.readLine()) != null && index == -1) { index = strLine.indexOf("<source src"); } } finally { try { in.close(); } catch (Exception e) { } } return strLine; } public static String parseLine(String line) { line = line.replace("<source", ""); line = line.replace(" src=", ""); line = line.replace("\"", ""); line = line.replace("type=", ""); line = line.replace("audio/mpeg", ""); line = line.replace(">", ""); return line; } }

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  • Accept All Cookies via HttpClient

    - by Vinay
    So this is currently how my app is set up: 1.) Login Activity. 2.) Once logged in, other activities may be fired up that use PHP scripts that require the cookies sent from logging in. I am using one HttpClient across my app to ensure that the same cookies are used, but my problem is that I am getting 2 of the 3 cookies rejected. I do not care about the validity of the cookies, but I do need them to be accepted. I tried setting the CookiePolicy, but that hasn't worked either. This is what logcat is saying: 11-26 10:33:57.613: WARN/ResponseProcessCookies(271): Cookie rejected: "[version: 0] [name: cookie_user_id][value: 1][domain: www.trackallthethings.com][path: trackallthethings][expiry: Sun Nov 25 11:33:00 CST 2012]". Illegal path attribute "trackallthethings". Path of origin: "/mobile-api/login.php" 11-26 10:33:57.593: WARN/ResponseProcessCookies(271): Cookie rejected: "[version: 0][name: cookie_session_id][value: 1985208971][domain: www.trackallthethings.com][path: trackallthethings][expiry: Sun Nov 25 11:33:00 CST 2012]". Illegal path attribute "trackallthethings". Path of origin: "/mobile-api/login.php" I am sure that my actual code is correct (my app still logs in correctly, just doesn't accept the aforementioned cookies), but here it is anyway: HttpGet httpget = new HttpGet(//MY URL); HttpResponse response; response = Main.httpclient.execute(httpget); HttpEntity entity = response.getEntity(); InputStream in = entity.getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); StringBuilder sb = new StringBuilder(); From here I use the StringBuilder to simply get the String of the response. Nothing fancy. I understand that the reason my cookies are being rejected is because of an "Illegal path attribute" (I am running a script at /mobile-api/login.php whereas the cookie will return with a path of just "/" for trackallthethings), but I would like to accept the cookies anyhow. Is there a way to do this?

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  • android httpurlconnection [closed]

    - by user620451
    hi im new android developer i am trying to login to my asterisk server passing my username and password it works good but when i am trying to request anther url to the server after login i get access denied and i now the problem because the login connection has disconnected so i want a way to request to urls the first one is login to the server and the second is to do something else after login please help and thx anyway this is a part of my code i want to request this 2 url url1="http://192.168.1.7:8088/rawman?action=login&username=admin&secret=admin" url2="http://192.168.1.5:8088/rawman?action=updateconfig&reload=yes&srcfilename=users.conf&dstfilename=users.conf&Action-000000=newcat&Cat-000000=6001&Var-000000=&Value-000000=" public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); tv1 = (TextView) this.findViewById(R.id.display); ed1 = (EditText) this.findViewById(R.id.editText); bt1 = (Button) this.findViewById(R.id.submit); bt1.setOnClickListener(new OnClickListener() { public void onClick(View view) { { try{ ServerRequest(url1); ServerRequest(url2); } catch(Exception e) { Log.v("Exception", "Exception:"+e.getMessage()); } } } }); } public String ServerRequest(String serverString) throws MalformedURLException, IOException { String newFeed=serverString; StringBuilder response = new StringBuilder(); Log.v("server","server url:"+newFeed); URL url = new URL(newFeed); HttpURLConnection httpconn = (HttpURLConnection) url.openConnection(); if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK) { BufferedReader input = new BufferedReader( new InputStreamReader(httpconn.getInputStream()), 8192); String strLine = null; while ((strLine = input.readLine()) != null) { response.append(strLine); } input.close(); } tv1.settext(response); return response.toString(); }

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  • Longer execution through Java shell than console?

    - by czuk
    I have a script in Python which do some computations. When I run this script in console it takes about 7 minutes to complete but when I run it thought Java shell it takes three times longer. I use following code to execute the script in Java: this.p = Runtime.getRuntime().exec("script.py --batch", envp); this.input = new BufferedReader(new InputStreamReader(p.getInputStream())); this.output = new BufferedWriter(new OutputStreamWriter(p.getOutputStream())); this.error = new BufferedReader(new InputStreamReader(p.getErrorStream())); Do you have any suggestion why the Python script runs three time longer in Java than in a console? update The computation goes as follow: Java sends data to the Python. Python reads the data. Python generates a decision tree --- this is a long operation. Python sends a confirmation that the tree is ready. Java receives the confirmation. Later there is a series of communications between Java and Python but it takes only several second.

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  • Java - Reading a csv file line by line - stuck with weird non-existent characters being read!

    - by rockit
    hello fellow java developers. I'm having a very strange issue. I'm trying to read a csv file line by line. Im at the point where Im just testing out the reading of the lines. ONly each time that I read a line, the line contains square characters between each character of text. I even saved the file as a txt file in wordpad and notepad with no change. Thus I must be doing something stupid... I have a csv file, standard csv file, yes a text file with commas in it. I try to read a line of text, but the text is all f-ed up and cannot find the phrase within the text. Any advice? code below. //open csv File filReadMe = new File(strRoot + "data2.csv"); BufferedReader brReadMe = new BufferedReader(new InputStreamReader(new FileInputStream(filReadMe))); String strLine = brReadMe.readLine(); //for all lines while (strLine != null){ //if line contains "(see also" if (strLine.toLowerCase().contains("(see also")){ //write line from "(see also" to ")" int iBegin = strLine.toLowerCase().indexOf("(see also"); String strTemp = strLine.substring(iBegin); int iLittleEnd = strTemp.indexOf(")"); System.out.println(strLine.substring(iBegin, iBegin + iLittleEnd)); } //update line strLine = brReadMe.readLine(); } //end for brReadMe.close();

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  • N3WB Question: passing objects in java?

    - by Adam Outler
    Hello, I am new at java. I am doing the following: Read from file, then put data into a variable. checkToken = lineToken.nextToken(); processlinetoken() } But then when I try to process it... public static void readFile(String fromFile) throws IOException { BufferedReader reader = new BufferedReader(new FileReader(fromFile)); String line = null; while ((line=reader.readLine()) != null ) { if (line.length() >= 2) { StringTokenizer lineToken = new StringTokenizer (line); checkToken = lineToken.nextToken(); ...... But here's where I come into a problem. public static void processlinetoken() checkToken=lineToken.nextToken(); } it fails out. Exception in thread "main" java.lang.Error: Unresolved compilation problem: The method nextToken() is undefined for the type String at testread.getEngineLoad(testread.java:243) at testread.readFile(testread.java:149) at testread.main(testread.java:119) so how do I get this to work? It seems to pass the variable, but nothing after the . works.

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  • how to add data to ARRAYLIST

    - by Chamal
    try { ArrayList ar=new ArrayList(); PRIvariable pri=new PRIvariable(); BufferedReader reader = new BufferedReader(new InputStreamReader(new FileInputStream("C:/cdr2.csv"))); while (reader.ready()) { String line = reader.readLine(); String[] values = line.split(","); pri.dateText=values[2]+" "+values[4]; pri.count=pri.count+1; pri.sum = pri.sum+Integer.parseInt(values[7]); System.out.println(pri.dateText+" "+pri.sum+" "+pri.count); ar.add(pri); } String[] columnNames={"Date","TOTAL","COUNTS"}; String[][] cells=new String[ar.size()][3]; for(int i=0;i<ar.size();i++){ cells[i][0]=((PRIvariable)ar.get(i)).dateText; cells[i][1]=""+((PRIvariable)ar.get(i)).sum; cells[i][2]=""+((PRIvariable)ar.get(i)).count; } table = new JTable(cells,columnNames); table.setSize(400,400); table.setVisible(true); JScrollPane js=new JScrollPane(); js.setViewportView(table); js.setSize(400,400); js.setVisible(true); add(js,java.awt.BorderLayout.CENTER); } catch (Exception e) { System.out.println(e); } This is my code. Here i want to Read text file and put that data to Jtable. But in this code it shows every row of the Jtable filled with same data that contain in arraylist(ar) last row. ( i think there is problem in my arraylist). How can i solve this......

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  • Loading data from file to Vector structure

    - by owca
    I'm trying to parse through fixed-width formatted file extracting x,y values of points from it, and then storing them in int[] array inside a Vector. Text file looks as follows : 0006 0015 0125 0047 0250 0131 That's the code : Vector<int[]> vc = new Vector<int[]>(); try { BufferedReader file = new BufferedReader(new FileReader("myfile.txt")); String s; int[] vec = new int[2]; while ((s = file.readLine()) != null) { vec[0] = Integer.parseInt(s.substring(0, 4).trim()); vec[1] = Integer.parseInt(s.substring(5, 8).trim()); vc.add(vec); } file.close(); } catch (IOException e) { } for(int i=0; i<vc.size(); i++){ for(int j=0; j<2; j++){ System.out.println(vc.elementAt(i)[j]); } } But the output shows only last line. 250 131 250 131 250 131 Should I somehow use Vector.nextElement() here to get all my data ?

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  • Consume a JSON webservice and process data in Android

    - by user1783391
    I am trying to consume a the webservice below http://62.253.195.179/disaster/webservices/login.php?message=[{"email":"[email protected]","password":"welcome"}] This returns a JSON array [{"companyuserId":"2","name":"ben stein","superiorname":"Leon","departmentId":"26","departmentname":"Development","companyId":"23","UDID":"12345","isActive":"1","devicetoken":"12345","email":"[email protected]","phone":"5456465465654","userrole":"1","chngpwdStatus":"1"}] My code is below try{ String weblink = URLEncoder.encode("http://62.253.195.179/disaster/webservices/login.php?message=[{\"email\":\"[email protected]\",\"password\":\"welcome\"}]"); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 7500; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 7500; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient client = new DefaultHttpClient(httpParameters); HttpGet request = new HttpGet(); URI link = new URI(weblink); request.setURI(link); HttpResponse response = client.execute(request); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); result = rd.readLine(); JSONObject myData = new JSONObject(result); JSONArray jArray = myData.getJSONArray(""); JSONObject steps = jArray.getJSONObject(0); String name = steps.getString("name"); } catch (JSONException e) { e.printStackTrace(); } But its not working and I am not 100% sure this is the best way to do it. 11-10 10:49:55.489: E/AndroidRuntime(392): java.lang.IllegalStateException: Target host must not be null, or set in parameters.

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  • BufferedWriter overwriting itself

    - by Danson
    I want to read in a file and create a duplicate of the file but my code only write the last line in the file. How do I make so that whenever I call write(), it writes to a new line. I want to create a new file for the duplicate so I can't add true to FileWriter constructor. This is my code: //Create file reader BufferedReader iReader = new BufferedReader(new FileReader(args[1])); //Create file writer BufferedWriter oWriter = new BufferedWriter(new FileWriter(args[2], true)); String strLine; //reading file int iterate = 0; while((strLine = iReader.readLine()) != null) { instructions[iterate] = strLine; } //creating duplicate for(int i = 0; i < instructions.length; i++) { if(instructions[i] != null) { oWriter.write(instructions[i]); oWriter.newLine(); } else { break; } } try { iReader.close(); oWriter.close(); } catch (IOException e) { e.printStackTrace(); }

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  • String doesn't match regex when read from keyboard.

    - by athspk
    public static void main(String[] args) throws IOException { String str1 = "??123456"; System.out.println(str1+"-"+str1.matches("^\\p{InGreek}{2}\\d{6}")); //??123456-true BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String str2 = br.readLine(); //??123456 same as str1. System.out.println(str2+"-"+str2.matches("^\\p{InGreek}{2}\\d{6}")); //?”??123456-false System.out.println(str1.equals(str2)); //false } The same String doesn't match regex when read from keyboard. What causes this problem, and how can we solve this? Thanks in advance. EDIT: I used System.console() for input and output. public static void main(String[] args) throws IOException { PrintWriter pr = System.console().writer(); String str1 = "??123456"; pr.println(str1+"-"+str1.matches("^\\p{InGreek}{2}\\d{6}")+"-"+str1.length()); String str2 = System.console().readLine(); pr.println(str2+"-"+str2.matches("^\\p{InGreek}{2}\\d{6}")+"-"+str2.length()); pr.println("str1.equals(str2)="+str1.equals(str2)); } Output: ??123456-true-8 ??123456 ??123456-true-8 str1.equals(str2)=true

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  • Android: Having trouble getting html from webpage

    - by Kyle
    Hi, I'm writing an android application that is supposed to get the html from a php page and use the parsed data from thepage. I've searched for this issue on here, and ended up using some code from an example another poster put up. Here is my code so far: HttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(url); try { Log.d("first","first"); HttpResponse response = client.execute(request); String html = ""; Log.d("second","second"); InputStream in = response.getEntity().getContent(); Log.d("third","third"); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); Log.d("fourth","fourth"); StringBuilder str = new StringBuilder(); String line = null; Log.d("fifth","fifth"); while((line = reader.readLine()) != null) { Log.d("request line",line); } in.close(); } catch (ClientProtocolException e) { } catch (IOException e) { // TODO Auto-generated catch block Log.d("error", "error"); } Log.d("end","end"); } Like I said before, the url is a php page. Whenever I run this code, it prints out the first first message, but then prints out the error error message and then finally the end end message. I've tried modifying the headers, but I've had no luck with it. Any help would be greatly appreciated as I don't know what I'm doing wrong. Thanks!

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  • A question on webpage representation in Java

    - by Gemma
    Hello there. I've followed a tutorial and came up with the following method to read the webpage content into a CharSequence public static CharSequence getURLContent(URL url) throws IOException { URLConnection conn = url.openConnection(); String encoding = conn.getContentEncoding(); if (encoding == null) { encoding = "ISO-8859-1"; } BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream(),encoding)); StringBuilder sb = new StringBuilder(16384); try { String line; while ((line = br.readLine()) != null) { sb.append(line); sb.append('\n'); } } finally { br.close(); } return sb; } It will return a representation of the webpage specified by the url. However,this representation is hugely different from what I use "view page source" in my Firefox,and since I need to scrape data from the original webpage(some data segement in the original "view page source" file),it will always fail to find required text on this Java representation. Did I go wrong somewhere?I need your advice guys,thanks a lot for helping!

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  • java.net.BindException How can I clear the sockets or what ever is causing it?

    - by user2266067
    I need some help with, I guess a simple networking related problem I'm having. It will also help me better understand how all this works by knowing what isn't being .close()'ed. I'm sure this is pretty simple, but for me its all very new. This is the client program. I can most likely append the server then, if I can figure this out. Thanks public class Server { public static void main(String[] args) { start(); } static int start = 0; public static void start() { try { ServerSocket serverSocket = new ServerSocket(4567); Socket socket = serverSocket.accept(); //1) Take and echo input (In this case a message) BufferedReader bf = new BufferedReader(new InputStreamReader(socket.getInputStream())); String message = bf.readLine(); System.out.println("Message recieved from Client:" + message); //2) Response of client message PrintWriter printWriter = new PrintWriter(socket.getOutputStream(), true); printWriter.println("Server echoing back the message ' " + message + " ' from Client"); } catch (IOException e) { System.out.println("e " + e); System.exit(-1); } start++; clearUp(); if (start < 5) { System.out.println("Closing binds and Restarting" + start); start(); } } public void clearUp(){ //How would I clear the stuff that is left bound so I can restart via start() and avoid the java.net.BindException: Address already in use: JVM_Bind ? } } How would I clear the stuff that is left bound so I can restart via start() and avoid java.net.BindException: Address already in use: JVM_Bind ?

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  • Strange numbers in java socket output

    - by user293163
    I have small test app: Socket socket = new Socket("jeck.ru", 80); PrintWriter pw = new PrintWriter(socket.getOutputStream(), false); pw.println("GET /ip/ HTTP/1.1"); pw.println("Host: jeck.ru"); pw.println(); pw.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(socket.getInputStream())); String str; while ((str = rd.readLine()) != null) { System.out.println(str); } It`s output: HTTP/1.1 200 OK Date: Sat, 13 Mar 2010 22:06:51 GMT Content-Type: text/html;charset=utf-8 Transfer-Encoding: chunked Connection: keep-alive Keep-Alive: timeout=5 Server HTTP/1.1 200 OK Date: Sat, 13 Mar 2010 22:06:51 GMT Content-Type: text/html;charset=utf-8 Transfer-Encoding: chunked Connection: keep-alive Keep-Alive: timeout=5 Server: Apache Cache-Control: max-age=0 Expires: Sat, 13 Mar 2010 22:06:51 GMT 123 <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>??? IP</title> </head> <body> <div style='text-align: center; font: 32pt Verdana;margin-top: 300px'> ??? IP &#151; 94.103.87.153 </div> </body> </html> 0 Whence these numbers (123 an 0) takes?

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  • Java File Handling, what did I do wrong?

    - by Urda
    Wrote up a basic file handler for a Java Homework assignment, and when I got the assignment back I had some notes about failing to catch a few instances: Buffer from file could have been null. File was not found File stream wasn't closed Here is the block of code that is used for opening a file: /** * Create a Filestream, Buffer, and a String to store the Buffer. */ FileInputStream fin = null; BufferedReader buffRead = null; String loadedString = null; /** Try to open the file from user input */ try { fin = new FileInputStream(programPath + fileToParse); buffRead = new BufferedReader(new InputStreamReader(fin)); loadedString = buffRead.readLine(); fin.close(); } /** Catch the error if we can't open the file */ catch(IOException e) { System.err.println("CRITICAL: Unable to open text file!"); System.err.println("Exiting!"); System.exit(-1); } The one comment I had from him was that fin.close(); needed to be in a finally block, which I did not have at all. But I thought that the way I have created the try/catch it would have prevented an issue with the file not opening. Let me be clear on a few things: This is not for a current assignment (not trying to get someone to do my own work), I have already created my project and have been graded on it. I did not fully understand my Professor's reasoning myself. Finally, I do not have a lot of Java experience, so I was a little confused why my catch wasn't good enough.

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  • android populating gridivew from a url string

    - by user1685991
    I am building an android application in which i am trying to read data from a url and want to display the data in a gridview. But i have some problem or dont understand to how to display the array list on grdiview. Here is my code for reading data from php url ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); //http post try{ HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://sml.com.pk/a/smldb.php"); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); HttpEntity entity = response.getEntity(); is = entity.getContent(); }catch(Exception e){ Log.e("log_tag", "Error in http connection"+e.toString()); } //convert response to string try{ BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8); sb = new StringBuilder(); sb.append(reader.readLine() + "\n"); String line="0"; while ((line = reader.readLine()) != null) { sb.append(line + "\n"); } is.close(); result=sb.toString(); }catch(Exception e){ Log.e("log_tag", "Error converting result "+e.toString()); } //paring data double des; double value; try{ jArray = new JSONArray(result); JSONObject json_data=null; for(int i=0;i<jArray.length();i++){ json_data = jArray.getJSONObject(i); LAT=json_data.getDouble("TITLE"); LANG=json_data.getDouble("A"); } } catch(JSONException e1){ Toast.makeText(getBaseContext(), "No Vehicles Found" ,Toast.LENGTH_LONG).show(); } catch (ParseException e1) { e1.printStackTrace(); } Here TITLE and A are my two columns of DB Table and i want to display them on gridview please any one help me to do this according to my current code. Here is my live url for data string http://sml.com.pk/a/smldb.php

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