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  • JSF submit dataTable and openpopup window after? is this possible?

    - by raimun
    Is it possible to just submit a dataTable instead of the entire form and then open a popupwindow after the submit? My dataTable has textboxes in it and the popup window is actually dependent on the data/values found in these textboxes. Since the user can change the values of the textboxes, I am required to get the latest values from the dataTables before the popup is opened. the popup is opened through a button found in each row of the datatable. i am using JSF2. thanks.

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  • Why doesn't my form post when I disable the submit button to prevent double clicking?

    - by John MacIntyre
    Like every other web developer on the planet, I have an issue with users double clicking the submit button on my forms. My understanding is that the conventional way to handle this issue, is to disable the button immediately after the first click, however when I do this, it doesn't post. I did do some research on this, god knows there's enough information, but other questions like Disable button on form submission, disabling the button appears to work. The original poster of Disable button after submit appears to have had the same problem as me, but there is no mention on how/if he resolved it. Here's some code on how to repeat it (tested in IE8 Beta2, but had same problem in IE7) My aspx code <%@ Page Language="C#" CodeFile="Default.aspx.cs" Inherits="_Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <script language="javascript" type="text/javascript"> function btn_onClick() { var chk = document.getElementById("chk"); if(chk.checked) { var btn = document.getElementById("btn"); btn.disabled = true; } } </script> <body> <form id="form1" runat="server"> <asp:Literal ID="lit" Text="--:--:--" runat="server" /> <br /> <asp:Button ID="btn" Text="Submit" runat="server" /> <br /> <input type="checkbox" id="chk" />Disable button on first click </form> </body> </html> My cs code using System; public partial class _Default : System.Web.UI.Page { protected override void OnInit(EventArgs e) { base.OnInit(e); btn.Click += new EventHandler(btn_Click); btn.OnClientClick = "btn_onClick();"; } void btn_Click(object sender, EventArgs e) { lit.Text = DateTime.Now.ToString("HH:mm:ss"); } } Notice that when you click the button, a postback occurs, and the time is updated. But when you check the check box, the next time you click the button, the button is disabled (as expected), but never does the postback. WHAT THE HECK AM I MISSING HERE??? Thanks in advance.

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  • Is posible to submit multipart/form-data without refresh page in jQuery?

    - by bugbug
    I want to upload picture from "my_form" in jQuery, I tried submit() function it alway redirect to SavePicture.jsp. Is posible to sumbit this form without refresh any page? This is my html code <form action="SavePicture.jsp" method="post" id="my_form" enctype="multipart/form-data"> <input name="file" type="file" id="file" size="35"> <input type="button" onClick="upload()" value="upload"></input> </form> And my script function upload{ jQuery("form#my_form").submit(); }

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  • Checking form input data on submit with pure PHP [migrated]

    - by Leron
    I have some experience with PHP but I have never even try to do this wit pure PHP, but now a friend of mine asked me to help him with this task so I sat down and write some code. What I'm asking is for opinion if this is the right way to do this when you want to use only PHP and is there anything I can change to make the code better. Besides that I think the code is working at least with the few test I made with it. Here it is: <?php session_start(); // define variables and initialize with empty values $name = $address = $email = ""; $nameErr = $addrErr = $emailErr = ""; $_SESSION["name"] = $_SESSION["address"] = $_SESSION["email"] = ""; $_SESSION["first_page"] = false; if ($_SERVER["REQUEST_METHOD"] == "POST") { if (empty($_POST["name"])) { $nameErr = "Missing"; } else { $_SESSION["name"] = $_POST["name"]; $name = $_POST["name"]; } if (empty($_POST["address"])) { $addrErr = "Missing"; } else { $_SESSION["address"] = $_POST["address"]; $address = $_POST["address"]; } if (empty($_POST["email"])) { $emailErr = "Missing"; } else { $_SESSION["email"] = $_POST["email"]; $email = $_POST["email"]; } } if ($_SESSION["name"] != "" && $_SESSION["address"] != "" && $_SESSION["email"] != "") { $_SESSION["first_page"] = true; header('Location: http://localhost/formProcessing2.php'); //echo $_SESSION["name"]. " " .$_SESSION["address"]. " " .$_SESSION["email"]; } ?> <DCTYPE! html> <head> <style> .error { color: #FF0000; } </style> </head> <body> <form method="POST" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"> Name <input type="text" name="name" value="<?php echo htmlspecialchars($name);?>"> <span class="error"><?php echo $nameErr;?></span> <br /> Address <input type="text" name="address" value="<?php echo htmlspecialchars($address);?>"> <span class="error"><?php echo $addrErr;?></span> <br /> Email <input type="text" name="email" value="<?php echo htmlspecialchars($email);?>"> <span class="error"><?php echo $emailErr;?></span> <br /> <input type="submit" name="submit" value="Submit"> </form> </body> </html>

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  • How to prevent jQuery FancyBox from closing immediately after submit?

    - by Dimitri
    Hi! I'm loading an inline registration form in a FancyBox from jQuery. However after submitting the form, the box immediately closes while there is some feedback that I want to show the user in the FancyBox itself. This feedback is generated on the server side and is printed in the FancyBox. How can I make the box only closing when their is no feedback anymore? I was thinking about using ajax to just refresh the FancyBox itself and not the whole page after refreshing. But I just can't figure out how this ajax $.ajax({type, cache, url, data, success}); works... Also it seems like there's no reaction from the 'submit bind' in the javascript. I hope someone can help me with this problem. I paste my code below. If any questions, plz ask.. Thx in advance! This is the javascript: <script type="text/javascript"> $(document).ready(function() { $("#various1").fancybox({ 'transitionIn' : 'none', 'transitionOut' : 'none', 'scrolling' : 'no', 'titleShow' : false, 'onClosed' : function() { $("#registration_error").hide(); } }); }); $("#registration_form").bind("submit", function() { if ($("#registration_error").val() != "Registration succeeded!") { $("#registration_error").show(); $.fancybox.resize(); return false; } $.fancybox.showActivity(); $.ajax({ type : "POST", cache : false, url : "/data/login.php", data : $(this).serializeArray(), success : function(data) { $.fancybox(data); } }); return false; }); This is the inline form that I show in the FancyBox: <div style="display: none;"> <div id="registration" style="width:227px;height:250px;overflow:auto;padding:7px;"> <?php echo "<p id=\"registration_error\">".$feed."</p>"; ?> <form id="registration_form" action="<?php echo $_SERVER['PHP_SELF'] ?>" method="post"> <p> <label for="username">Username: </label> <input type="text" id="login_name" name="username" size="30" /> </p> <p> <label for="password">Password: </label> <input type="password" id="pass" name="pw" size="30" /> </p> <p> <label for="repeat_password">Repeat password: </label> <input type="password" id="rep_pass" name="rep_pw" size="30" /> </p> <p> <input type="submit" value="Register" name="register" id="reg" /> </p> <p> <em></em> </p> </form> </div> </div>

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  • jQuery append breaks my HTML form (with submit button)

    - by JimFing
    I'm trying to create a form with a submit button via jQuery using append(). So the following: out.append('<form name="input" action="/createuser" method="get">'); out.append('Username: <input type="text" name="user" />'); out.append('<input type="submit" value="Submit" />'); out.append('</form>'); However, clicking on submit, nothing happens! However if I do the following: var s = '<form name="input" action="/createuser" method="get">' + 'Username: <input type="text" name="user" />' + '<input type="submit" value="Submit" />' + '</form>'; out.html(s); Then the submit button works fine! I'm happy to use the 2nd method, but would rather know what the problem is here. Thanks

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  • jQuery.Form wont submit

    - by kim
    Im´trying to submit a form without refreshing the page, but I´m having a problem. When I click submit the page refreshes and anothing gets posted. Here is the code, what am I doing wrong? (I´m a newbie) jQuery 1.4.2 and the jQuery Form Plugin 2.43 is present. tnx $(document).ready(function() { var options = { target: '#output2', url: https://graph.facebook.com/<%=fbUid%>/feed, type: post, clearForm: true // clear all form fields after successful submit //dataType: null // 'xml', 'script', or 'json' (expected server response type) //resetForm: true // reset the form after successful submit // $.ajax options can be used here too, for example: //timeout: 3000 }; // bind to the form's submit event $('#fbPostStatus').submit(function() { // inside event callbacks 'this' is the DOM element so we first // wrap it in a jQuery object and then invoke ajaxSubmit $(this).ajaxSubmit(options); // !!! Important !!! // always return false to prevent standard browser submit and page navigation return false; }); });

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  • What to use instead of if(isset($_POST['submit'])) for this.form.submit()?

    - by paracaudex
    I want to run a particular block of PHP if the user submits a form. It works if I use a submit button with name="submit" and: <?php if(isset($_POST['submit'])) { code to run } ?> I don't know anything about javascript, and I want the code to run if the user changes a dropdown menu. If I make the first line of the dropdown <select name="dropdownname" onchange="this.form.submit()"> the form appears (I haven't tested it) to submit if the user changes the dropdown choice. However, if I do this, the if(isset($_POST['submit'])) PHP code doesn't run. Is there a PHP if statement I can write that will respond to the form being submitted even though it's being submitted by a change in the dropdown and not a submit button?

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  • For what purpose does java have a float primitive type?

    - by Roman
    I heard plenty times different claims about float type in java. The most popular issues typicaly regard to converting float value to double and vice versa. I read (rather long time ago and not sure that it's actual now with new JVM) that float gives much worse performance then double. And it's also not recommended to use float in scientific applications which should have certain accuracy. I also remember that when I worked with AWT and Swing I had some problems with using float or double (like using Point2D.Float or Point2D.Double). So, I see only 2 advantages of float over double: it needs only 4 bytes while double needs 8 bytes JMM garantees that assignment operation is atomic with float variables while it's not atomic with double's. Are there any other cases where float is better then double? Do you use float's in your applications? It seems to me that the only valuable reason java has float is backward compatibility.

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  • Preoblem with Precision floating point operation in C

    - by Microkernel
    Hi Guys, For one of my course project I started implementing "Naive Bayesian classifier" in C. My project is to implement a document classifier application (especially Spam) using huge training data. Now I have problem implementing the algorithm because of the limitations in the C's datatype. ( Algorithm I am using is given here, http://en.wikipedia.org/wiki/Bayesian_spam_filtering ) PROBLEM STATEMENT: The algorithm involves taking each word in a document and calculating probability of it being spam word. If p1, p2 p3 .... pn are probabilities of word-1, 2, 3 ... n. The probability of doc being spam or not is calculated using Here, probability value can be very easily around 0.01. So even if I use datatype "double" my calculation will go for a toss. To confirm this I wrote a sample code given below. #define PROBABILITY_OF_UNLIKELY_SPAM_WORD (0.01) #define PROBABILITY_OF_MOSTLY_SPAM_WORD (0.99) int main() { int index; long double numerator = 1.0; long double denom1 = 1.0, denom2 = 1.0; long double doc_spam_prob; /* Simulating FEW unlikely spam words */ for(index = 0; index < 162; index++) { numerator = numerator*(long double)PROBABILITY_OF_UNLIKELY_SPAM_WORD; denom2 = denom2*(long double)PROBABILITY_OF_UNLIKELY_SPAM_WORD; denom1 = denom1*(long double)(1 - PROBABILITY_OF_UNLIKELY_SPAM_WORD); } /* Simulating lot of mostly definite spam words */ for (index = 0; index < 1000; index++) { numerator = numerator*(long double)PROBABILITY_OF_MOSTLY_SPAM_WORD; denom2 = denom2*(long double)PROBABILITY_OF_MOSTLY_SPAM_WORD; denom1 = denom1*(long double)(1- PROBABILITY_OF_MOSTLY_SPAM_WORD); } doc_spam_prob= (numerator/(denom1+denom2)); return 0; } I tried Float, double and even long double datatypes but still same problem. Hence, say in a 100K words document I am analyzing, if just 162 words are having 1% spam probability and remaining 99838 are conspicuously spam words, then still my app will say it as Not Spam doc because of Precision error (as numerator easily goes to ZERO)!!!. This is the first time I am hitting such issue. So how exactly should this problem be tackled?

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  • Problem with Precision floating point operation in C

    - by Microkernel
    Hi Guys, For one of my course project I started implementing "Naive Bayesian classifier" in C. My project is to implement a document classifier application (especially Spam) using huge training data. Now I have problem implementing the algorithm because of the limitations in the C's datatype. ( Algorithm I am using is given here, http://en.wikipedia.org/wiki/Bayesian_spam_filtering ) PROBLEM STATEMENT: The algorithm involves taking each word in a document and calculating probability of it being spam word. If p1, p2 p3 .... pn are probabilities of word-1, 2, 3 ... n. The probability of doc being spam or not is calculated using Here, probability value can be very easily around 0.01. So even if I use datatype "double" my calculation will go for a toss. To confirm this I wrote a sample code given below. #define PROBABILITY_OF_UNLIKELY_SPAM_WORD (0.01) #define PROBABILITY_OF_MOSTLY_SPAM_WORD (0.99) int main() { int index; long double numerator = 1.0; long double denom1 = 1.0, denom2 = 1.0; long double doc_spam_prob; /* Simulating FEW unlikely spam words */ for(index = 0; index < 162; index++) { numerator = numerator*(long double)PROBABILITY_OF_UNLIKELY_SPAM_WORD; denom2 = denom2*(long double)PROBABILITY_OF_UNLIKELY_SPAM_WORD; denom1 = denom1*(long double)(1 - PROBABILITY_OF_UNLIKELY_SPAM_WORD); } /* Simulating lot of mostly definite spam words */ for (index = 0; index < 1000; index++) { numerator = numerator*(long double)PROBABILITY_OF_MOSTLY_SPAM_WORD; denom2 = denom2*(long double)PROBABILITY_OF_MOSTLY_SPAM_WORD; denom1 = denom1*(long double)(1- PROBABILITY_OF_MOSTLY_SPAM_WORD); } doc_spam_prob= (numerator/(denom1+denom2)); return 0; } I tried Float, double and even long double datatypes but still same problem. Hence, say in a 100K words document I am analyzing, if just 162 words are having 1% spam probability and remaining 99838 are conspicuously spam words, then still my app will say it as Not Spam doc because of Precision error (as numerator easily goes to ZERO)!!!. This is the first time I am hitting such issue. So how exactly should this problem be tackled?

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  • Array loading with doubles in C

    - by user2892120
    I am trying to load a 3x8 array of doubles but my code keeps outputting 0.00 for all of the values. The code should be outputting the array (same as the input) under the Read#1 Read#2 Read#3 lines, with the average under average. Here is my code: #include <stdio.h> double getAvg(double num1, double num2, double num3); int main() { int numJ,month,day,year,i,j; double arr[3][8]; scanf("%d %d %d %d",&numJ,&month,&day,&year); for (i = 0; i < 8; i++) { scanf("%f %f %f",&arr[i][0], &arr[i][1], &arr[i][2]); } printf("\nJob %d Date: %d/%d/%d",numJ,month,day,year); printf("\n\nLocation Read#1 Read#2 Read#3 Average"); for (j = 0; j < 8; j++) { printf("\n %d %.2f %.2f %.2f %.2f",j+1,arr[j][0],arr[j] [1],arr[j][2],getAvg(arr[j][0],arr[j][1],arr[j][2])); } return 0; } double getAvg(double num1, double num2, double num3) { double avg = (num1 + num2 + num3) / 3; return avg; } Input example: 157932 09 01 2013 0.00 0.00 0.00 0.36 0.27 0.23 0.18 0.16 0.26 0.27 0.00 0.34 0.24 0.00 0.31 0.16 0.33 0.36 0.29 0.36 0.00 0.21 0.36 0.00

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  • Which of these design patterns is superior?

    - by durron597
    I find I tend to design class structures where several subclasses have nearly identical functionality, but one piece of it is different. So I write nearly all the code in the abstract class, and then create several subclasses to do the one different thing. Does this pattern have a name? Is this the best way for this sort of scenario? Option 1: public interface TaxCalc { String calcTaxes(); } public abstract class AbstractTaxCalc implements TaxCalc { // most constructors and fields are here public double calcTaxes(UserFinancials data) { // code double diffNumber = getNumber(data); // more code } abstract protected double getNumber(UserFinancials data); protected double initialTaxes(double grossIncome) { // code return initialNumber; } } public class SimpleTaxCalc extends AbstractCalc { protected double getNumber(UserFinancials data) { double temp = intialCalc(data.getGrossIncome()); // do other stuff return temp; } } public class FancyTaxCalc extends AbstractTaxCalc { protected double getNumber(UserFinancials data) { int temp = initialCalc(data.getGrossIncome()); // Do fancier math return temp; } } Option 2: This version is more like the Strategy pattern, and should be able to do essentially the same sorts of tasks. public class TaxCalcImpl implements TaxCalc { private final TaxMath worker; public DummyImpl(TaxMath worker) { this.worker = worker; } public double calcTaxes(UserFinancials data) { // code double analyzedDouble = initialNumber; int diffNumber = worker.getNumber(data, initialNumber); // more code } protected int initialTaxes(double grossIncome) { // code return initialNumber; } } public interface TaxMath { double getNumber(UserFinancials data, double initial); } Then I could do: TaxCalc dum = new TaxCalcImpl(new TaxMath() { @Override public double getNumber(UserFinancials data, double initial) { double temp = data.getGrossIncome(); // do math return temp; }); And I could make specific implementations of TaxMath for things I use a lot, or I could make a stateless singleton for certain kinds of workers I use a lot. So the question I'm asking is: Which of these patterns is superior, when, and why? Or, alternately, is there an even better third option?

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  • how do I set up a double domain?

    - by kdavis8
    I would like to set up a server similar to Google's. Their domain acts like a double domain, like you can use these URLS, "play.Google.com" or "apps.Google.com", to go to different sites.. For example, my domain would now be "my_domain.com" but i would like another one to be "domain2.my_domain.com". My question is,what is this officially called and how do i set it up? I'm not sure if you need two servers or just 1;

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  • Opera double ses téléchargements en Europe depuis l'arrivée du "Ballot Screen" sur Windows : réelle

    Opera double ses téléchargements En Europe depuis l'arrivée du "Ballot Screen" sur Windows : réelle envolée ou effet passager ? Opera Software, l'éditeur du navigateur Norvégien, était à l'origine de la procédure européenne pour imposer le ballot-screen à Microsoft. Et c'est son produit, Opera qui semble bien tirer les bénéfices de cet écran de choix du navigateur par défaut à installer lors du premier démarrage de Windows. En Europe, depuis l'arrivée du ballot-screen, Opera aurait connu une pr...

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  • Must double-tap Windows key to open Dash

    - by Bart van Heukelom
    I'm experiencing some strange behaviour of the Unity Dash and the Windows/Super keyboard key. As far as I know, normal behaviour is: Tap: Open Dash Hold: Show keyboard shortcut overlay However, the behaviour I'm experiencing is: Tap: Show keyboard shortcut overlay (after a short delay) Double Tap: Open Dash Hold: Show keyboard shortcut overlay What could cause this, and how do I fix it? I'm on a fresh 12.10 (Quantal) installation.

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  • Avoid double compression of resources

    - by user1095108
    I am using .pngs for my textures and am using a virtual file system in a .zip file for my game project. This means my textures are compressed and decompressed twice. What are the solutions to this double compression problem? One solution I've heard about is to use .tgas for textures, but it seems ages ago, since I've heard that. Another solution is to implement decompression on the GPU and, since that is fast, forget about the overhead.

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  • Single quotes vs double quotes

    - by Eric Hydrick
    I just started a job where I'm writing Python after coming from a Java background, and I'm noticing that other developers tend to quote strings using single quotes ('') instead of double quotes (""). For example: line1 = 'This is how strings typically look.' line2 = "Not like this." Is there a particular reason for this other than personal preference? Is this the proper way to be quoting strings?

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  • Double Buffering in Panda3D (C++)

    - by jsvcycling
    How would I go about using Double Buffering (to create a loading screen) in Panda3D using C++? I've searched Google and found some forums that talk about the concept of swapping buffers, but I haven't seen any that show any type of source code (specifically Panda3D/C++). I'd like to try and stay away from using pure OpenGL code and work it through Panda3D, but if I have no other choice, then I'll have to go with OpenGL coding.

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  • xfce4 - 'Run Program' dialogue box does not appear when double clicking script

    - by Ron Paulfan
    Ubuntu 12.04 Xfce4 On my previous Ubuntu distro, when I double clicked scripts I got a little dialogue window that asked me if I wanted to run the script as a program or run it in terminal. Similar to this window: Since upgrading, I have never seen that window. I have ensured that the option to 'Allow executing as a program is enabled' and the script works if I run it through terminal. I simply just don't get the prompt. Any ideas?

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