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  • Oracle support note for Leap Second Hang problem that may result into 100% CPU utilization in Linux environment

    - by Anand Akela
    Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} On or around July 1, 2012, Oracle has become aware of an issue on Linux distributions resulting from the introduction of the leap second; this is causing problems for some customers.  Leap seconds may be introduced at the end of June or December in a calendar year, like 2012, as necessary to maintain time standards. Servers hosting Oracle products which are clients of an NTP server (Network Time Protocol) may be particularly susceptible to this issue as the NTP server is updated. Linux distributions which may be affected include Oracle Enterprise Linux, Red Hat Enterprise Linux, Oracle VM and Oracle Unbreakable Enterprise Kernel. Asianux 2 and 3, based on RHEL 4 and 5, may also be affected. One report of correction to high agent CPU using Note 1472421.1 on SLES11 has also been reported. Not all customers will be affected, but those, who are affected, may observe higher than normal CPU consumption on their Linux environments where JVM's are utilized.  In Oracle Enterprise Manager ( EM ) , this problem can manifest itself as high CPU consumption with the EM Agent process (which runs on a JVM in EM 12c, for instance).  It is possible that the OMS is also affected. We would advise customers to review the description of this problem in MOS Note 1472651.1 and take action if they observe that their environment is affected. Contributed by Andrew Bulloch , Director, Application Systems Management Products

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  • Computer science final year project ideas

    - by roul
    I'm a Computer Science undergraduate student in UK and should be deciding the subject of my final year project soon. The school is pretty flexible with the subject... "The topic can be any area of the subject which is of mutual interest to both the student and supervisor. Topics can range from purely theoretical studies to practical work building a system for some third party, although most projects aim to provide a balance between the theoretical and practical aspects of the subject." ...so I'm a bit lost since I want to do something in software engineering but have no idea what (subject) or with what (languages)! :) a) Languages: I've had experience with Java, C# and ASP.NET mostly but I would definitely be interested in learning new languages/frameworks. I'm kind of drawn by the idea of dynamic languages at the moment so IronPython seems likely. b) Subject: Anything that will keep me interested through the year and will give me the opportunity to learn a lot of stuff. Maybe something that has to do with music, or a fancy website, or a website about music :P anything really. Open to any thoughts/ideas, geeky or cool! Edit: Professors do usually supervise projects in their research areas but I currently have the choice to approach any of them according to my interest - whatever that is.

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  • MS Acess SQL - where clause to get year from date based on the year - data located in MS access form

    - by primus285
    OK, back again. I have a problem getting a drop down list to populate based on information in two fields. I have got the SQL correct as to Select just one year if I put DateValue('01/01/2001') in both places, but I am trying now to get it to grab the year data from the MS access form - another drop down named "cboYear". I'd hate to have to do something in VB, unless necessary. so far I have gotten this to pull up something (its always incorrect) SELECT DISTINCT Database_New.ASEC FROM Database_New WHERE Database_New.Date>=DateValue('01/01/' & [cboYear]) And Database_New.Date<=DateValue('12/31/' & [cboYear]); and SELECT DISTINCT Database_New.ASEC FROM Database_New WHERE Database_New.Date>=DateValue('01/01/' + [cboYear]) And Database_New.Date<=DateValue('12/31/' + [cboYear]); SELECT DISTINCT Database_New.ASEC FROM Database_New WHERE Database_New.Date>=DateValue('01/01/' AND [cboYear]) And Database_New.Date<=DateValue('12/31/' AND [cboYear]); both give errors saying that it is too complex to compute. Its probably something simple, but where do I go from here?

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  • In which year was the date the same as the original year?

    - by Marta
    It's my first question on this site, but I always found this site really useful. What I mean with my question is: you ask the person to give a date (eg. Fill in a date [dd-mm-yyyy]: 16-10-2013) you than have to ask an interval between 2 years (eg. Give an interval [yyyy-yyyy]:1800-2000) When the program runs, it has to show what day of the week the given date is. In this case it was a Wednesday. Than the program has to look in which year, in between the interval, the date 16 October also fell on a Wednesday. So in the end it has to look something like this: Fill in a date: [dd-mm-yyyy]: 16-10-2013 Give an interval [yyyy-yyyy]: 1900-2000 16 October was a wednesday in the following years: 1905 1911 1916 1922 1933 1939 1944 1950 1961 1967 1972 1978 1989 1995 2000 The full date is Wednesday 16 October, 2013 The small (or biggest) problem is, I am not allowed to use the DATE.function in java. If someone can help me with the second part I would be really really happy, cause I have no idea how I am supposed to do this To find out what day of the week the given date falls, I use the Zeller Congruence class Day { Date date; //To grab the month and year form the Date class int day; final static String[] DAYS_OF_WEEK = { "Saturday", "Sunday", "Monday", "Tuesday", "Wednesday", "Thursday", "Friday" }; public void dayWeekInterval{ //code to grab the interval from interval Class, and doing stuff here } public void dayOfTheWeek { int m = date.getMonth(); int y = date.getYear(); if (m < 3) { m += 12; y -= 1; } int k = y % 100; int j = y / 100; int day = ((q + (((m + 1) * 26) / 10) + k + (k / 4) + (j / 4)) + (5 * j)) % 7; return day; } public string ToString(){ return "" + DAYS_OF_WEEK[day] + day; } }

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  • How do I get a new license for gDEBugger after the 1 free year?

    - by Byte56
    I downloaded the gDEBugger from gremedy over a year ago, with their one year free license. The license has since expired and their site says that I'll be presented with the option for 1 year free license the first time I run it after install. This doesn't happen when re-installing, it just tells me the license has expired. How do I get a new license? I use this regularly for debugging shader problems and performance testing my game.

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  • Julian day of the year in Java

    - by Mark
    I have seen the "solution" at http://www.rgagnon.com/javadetails/java-0506.html, but it doesn't work correctly. E.g. yesterday (June 8) should have been 159, but it said it was 245. So, does someone have a solution in Java for getting the current date's three digit Julian day (not Julian date - I need the day this year)? Thanks! Mark

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  • AJAX Calendar extender select month and year

    - by nCdy
    Is it real and how can I think about it. To make so the user will select only the month and year, not date, because he need a period on full month, not some date. here is simple control ... <asp:TextBox ID="TextBox3" runat="server" /> <asp:CalendarExtender ID="TextBox3_CalendarExtender" runat="server" Enabled="True" TargetControlID="TextBox3" />

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  • How to set system time, day and year in registry

    - by sijith
    i created new registry entry using RegCreateKeyEx(HKEY_LOCAL_MACHINE, TEXT("Software\XXXXXX\Test"), 0, NULL, 0, 0, NULL, &hkey, &dwDisposition) Now i want to save current system time data and year to the newly created registry for later retrival How can i implement it in VC++ using RegSetKeyValue. I tried but faile dto implement.

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  • topic for final year project

    - by Mrinal Shrivastava
    i am a computer science student and have just entered in my final year. i wanna do a project on something new and exciting in the field of networking dbms os or ai. i am proficient in java c, oracle and am improving my linux skills.. please give me some suggestions for hot topics..

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  • SQL SERVER – Function: Is Function – SQL in Sixty Seconds #004 – Video

    - by pinaldave
    Today is February 29th. An unique date which we only get to observe once every four year. Year 2012 is leap year and SQL Server 2012 is also releasing this year. Yesterday I wrote an article where we have seen observed how using four different function we can create another function which can accurately validate if any year is leap year or not. We will use three functions newly introduced in SQL Server 2012 and demonstrate how we can find if any year is leap year or not. This function uses three of the SQL Server 2012 functions - IIF, EOMONTH and CONCAT. When I wrote this function, this is the sortest function I ever wrote to find out leap year. Please watch the video and let me know if any shorter function can be written to find leap year. More on Leap Yer: Detecting Leap Year in T-SQL using SQL Server 2012 – IIF, EOMONTH and CONCAT Function Date and Time Functions – EOMONTH() – A Quick Introduction Script/Function to Find Last Day of Month  I encourage you to submit your ideas for SQL in Sixty Seconds. We will try to accommodate as many as we can. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Database, Pinal Dave, PostADay, SQL, SQL Authority, SQL in Sixty Seconds, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Video

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  • NSDateFormatterFullStyle without year (NSDateFormatter)

    - by Brian Halpin
    Using the user's currentLocale from the device, I want to have a date format exactly like the one generated for NSDateFormatterFullStyle minus the year: [dateFormatter setDateStyle:NSDateFormatterFullStyle]; Friday, 21 September (2012) I've noticed the iPhone app, Living Earth does this and works for all locales, so does the iPhone lock screen. A custom formatter such as, [dateFormatter setDateFormat:@"EEEE, MMMM"]; won't change with localisation. Can anyone shed some light on how to accomplish this? None of the options for date style seem to do this. Thanks

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  • PHP/MYSQL Year Month table for news archive

    - by ee12csvt
    Hi all, I am creating a news archive for my site and want to create an overview page from the following DB table id - Unique identifier newsDate - in a format XXXX-XX-XX title - News Item title details - News item photo - News Item Photo caption - News Item Photo caption update - Timestamp for record The news on the site is current but I hope to add some data from years gone by over the next few months and years. What I want to do is create a new line for each year and highlight the month which corresponds to a record in the DB table, similar to that below. 2002 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2004 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2005 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2008 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC Any help or advice would be much appreciated Cheers

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  • Display relative time in hour, day, month and year

    - by JohnJohnGa
    I wrote a function toBeautyString(epoch) : String which given a epoch, return a string which will display the relative time from now in hour and minute For instance: // epoch: 1346140800 -> Tue, 28 Aug 2012 05:00:00 GMT // and now: 1346313600 -> Thu, 30 Aug 2012 08:00:00 GMT toBeautyString(1346140800) -> "2 days and 3 hours ago" I want now to extend this function to month and year, so it will be able to print: 2 years, 1 month, 3 days and 1 hour ago Only with epoch without any external libraries. The purpose of this function is to give to the user a better way to visualize the time in the past. I found this: Calculating relative time but the granularity is not enough.

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  • Finding begin and end of year/month/day/hour

    - by reto
    I'm using the following snipped to find the begin and end of several time periods in Joda. The little devil on my left shoulder says thats the way to go... but I dont believe him. Could anybody with some joda experience take a brief look and tell me that the little guy is right? (It will be only used for UTC datetime objects) Thank you! /* Year */ private static DateTime endOfYear(DateTime dateTime) { return endOfDay(dateTime).withMonthOfYear(12).withDayOfMonth(31); } private static DateTime beginningOfYear(DateTime dateTime) { return beginningOfMonth(dateTime).withMonthOfYear(1); } /* Month */ private static DateTime endOfMonth(DateTime dateTime) { return endOfDay(dateTime).withDayOfMonth(dateTime.dayOfMonth().getMaximumValue()); } private static DateTime beginningOfMonth(DateTime dateTime) { return beginningOfday(dateTime).withDayOfMonth(1); } /* Day */ private static DateTime endOfDay(DateTime dateTime) { return endOfHour(dateTime).withHourOfDay(23); } private static DateTime beginningOfday(DateTime dateTime) { return beginningOfHour(dateTime).withHourOfDay(0); } /* Hour */ private static DateTime beginningOfHour(DateTime dateTime) { return dateTime.withMillisOfSecond(0).withSecondOfMinute(0).withMinuteOfHour(0); } private static DateTime endOfHour(DateTime dateTime) { return dateTime.withMillisOfSecond(999).withSecondOfMinute(59).withMinuteOfHour(59); }

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  • Year split in Quarters using basic jQuery

    - by Alexander Corotchi
    Hi, I have a interesting question: I want to split the year into 4 quarters. What is the idea, A quarter can be different: The HTML Code: <div class="quarterBody"> <span>04-29-2010</span> <span>06-29-2010</span> <span>08-29-2010</span> </div> jQuery (javascript) is total wrong, I hope that w: $(document).ready(function(){ var quarter1 = to make interval (01-01-2010 to 03-31-2010); var quarter2 = to make interval (03-01-2010 to 06-31-2010); var quarter3 = to make interval (06-01-2010 to 09-31-2010); var quarter4 = to make interval (09-01-2010 to 12-31-2010); ... $(".quarterBody span").each(function(){ var date = Date.parse($(this).text()); //to apply some magic code $(this).addClass(quarterNumber); }); }); OUTPUT: <div class="quarterBody"> <span class="Quarter1">02-29-2010</span> <span class="Quarter2">04-29-2010</span> <span class="Quarter3">08-29-2010</span> ... </div> I know right now it is a stupid way, but I hope that somebody can help me, or suggest an idea how to do that in a better way!! Thanks!

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  • Oracle Date Format Convert Hour-Minute to Interval and Disregard Year-Month-Day

    - by dlite922
    I need to compare an event's half-way midpoint between a start and stop time of day. Right now i'm converting the dates you see on the right, to HH:MM and the comparison works until midnight. the query says: WHERE half BETWEEN pStart and pStop. As you can see below, pStart and pStap have January 1st 2000 dates, this is because the year month day are not important to me... Valid Data: +-------+--------+-------+---------------------+---------------------+---------------------+ | half | pStart | pStop | half2 | pStart2 | pStop2 | +-------+--------+-------+---------------------+---------------------+---------------------+ | 19:00 | 19:00 | 23:00 | 2012-11-04 19:00:00 | 2000-01-01 19:00:00 | 2000-01-01 23:00:00 | | 20:00 | 19:00 | 23:00 | 2012-11-04 20:00:00 | 2000-01-01 19:00:00 | 2000-01-01 23:00:00 | | 21:00 | 19:00 | 23:00 | 2012-11-04 21:00:00 | 2000-01-01 19:00:00 | 2000-01-01 23:00:00 | | 23:00 | 20:00 | 23:00 | 2012-11-05 23:00:00 | 2000-01-01 20:00:00 | 2000-01-01 23:00:00 | +-------+--------+-------+---------------------+---------------------+---------------------+ Now observe what happens when pStop is midnight or later... Valid Data that breaks it: +-------+--------+-------+---------------------+---------------------+---------------------+ | half | pStart | pStop | half2 | pStart2 | pStop2 | +-------+--------+-------+---------------------+---------------------+---------------------+ | 23:00 | 22:00 | 00:00 | 2012-11-04 23:00:00 | 2000-01-01 22:00:00 | 2000-01-01 00:00:00 | | 23:30 | 23:00 | 02:00 | 2012-11-05 23:30:00 | 2000-01-01 23:00:00 | 2000-01-01 02:00:00 | +-------+--------+-------+---------------------+---------------------+---------------------+ Thus my where clause translates to: WHERE 19:00 BETWEEN 22:00 AND 00:00 ...which returns false and I miss those two correct rows above. Question: Is there a way to show those dates as integer interval so that saying half BETWEEN pStart and pStop are correct? I thought about adding 24 when pStop is less than pStart to make 00:00 into 24:00 but don't know an easy way to do that without long string concatenations and number conversions. This would solve the problem because pStart pStop difference will never be longer than 6 hours. Note: (The Query is much more complex. It has other irrelevant date calculations, but the result are show above. DATE_FORMAT(%H:%i) is applied to the first three columns and no formatting to the last three) Thanks for your help:

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