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• Regular expression using + problem in js

  - by Karthik

  I am using regular expression. In phone validation, i have to use the "+" sign in that. How to provide the + sign in regular expression. Because + sign indicates one or more of preceding character(s). Whether i will provide like this + ?

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• How to install Snow Leopard Server over Regular Snow Leopard

  - by SeniorShizzle

  I'm in the ADC so I have legitimate access to a free copy of Snow Leopard Server and licence key which I need to use to test my Push Notifications. I downloaded the software, and when I opened the .dmg I saw "Click to install Snow Leopard Server" which I did, and then it prompted me to restart the computer to begin installation. When the computer restarted, however, it just booted into my regular OS X partition. I kept trying to no avail. Obviously I'm missing something stupid here but I'm not a server admin so I don't know what to do :) The dmg is almost 6GB so I can't burn a DVD of it. I really need your help! Thanks guys!

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• 12.04 ext4 - cannot create regular file/No space left - with a lot of space and inodes

  - by user1434058

  This seems similar: EXT4 "No space left on device (28)" incorrect but there is no explanation I created an ext4 filesystem on a RAID 1 array with: mke2fs -t ext4 -T small /dev/md0 Copying a single directory with many tiny files I get: cp: cannot create regular file `/mnt/raid1_new/pics/pic3412.jpg': No space left on device space used 5% inodes used 1% I manually tried: cp /source/test1.jpg /mnt/raid1_new/pics/test1.jpg --- error cp /source/test1.jpg /mnt/raid1_new/pics/test2.jpg --- ERROR cp /source/test1.jpg /mnt/raid1_new/pics/test3.jpg --- no error Notes: RAID 1 disks are error free. I tried mv instead of cp and got the same thing. I tried omitting -T small with no effect Can somebody help me understand this magic?

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• How to add in in appendix page numbers separately from the regular heading page numbers

  - by O_O

  I had regular page numbers on my Microsoft Word 2007 document at the bottom center of my page, starting from 1 from Insert tab Page Number Bottom of page Plain Number 2. I added an appendix with Heading 6 and followed the instructions from http://support.microsoft.com/kb/290953 to create separate page numbers just for the appendix, i.e. A-1, A-2, B-1, B-2, etc. The Page Number Format configuration I did is here: ]When I try to set this however, it changes all of the page numbers to this format, even the ones that aren't from heading 6 (meaning it changes the non-appendix content to this page number format). Here's another example: 1 Heading1 has page number A-4 (note it starts at A-1 at the title page) ... Appendix A has page number A-12 I would like to change it so that 1 Heading1 has page number 4 (note it starts at 1 at the title page) ... Appendix A has page number A-1 Anyone know why this is happening? Thank you!!

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• Create Google Maps screenshots at regular intervals

  - by Dave Jarvis

  Background People are concerned that building a pipeline to the West Coast of Canada will increase the number of oil tankers, thus increasing the probability of a major oil spill, thereby creating an environmental catastrophe. The AIS Live Ships Map website captures real-time Marine Traffic updates using a Google Maps interface. While it is possible to obtain data from an AIS data feed, often the feeds are either pay-for-use, or otherwise encumbered with license restrictions. Problem The AIS Live Ships website presents a map in the browser: The map above has had its location interactively changed to focus on the area in question: the northern straight of Vancouver Island. Question How would you create a service that captures the map every 30 minutes and that could run, with neither user-intervention nor a significant memory footprint, for a few years? Idea #1 Create a virtual machine. Install and run a light-weight browser. Use Shutter to take captures at regular intervals. Idea #2 Use Python's Ghost Webkit to automate the captures. Thank you!

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• Cannot run java as regular linux user.

  - by Roger

  I am having problems trying to run java as a normal user on linux. It runs fine as root user but not as a regular user. Any help would be apreciated. Thanks root@pro1 [~]# which java /usr/local/jdk/bin/java root@pro1 [~]# java -version java version "1.6.0_22" Java(TM) SE Runtime Environment (build 1.6.0_22-b04) Java HotSpot(TM) 64-Bit Server VM (build 17.1-b03, mixed mode) root@pro1 [~]# su istream istream@xxxxxxxxx [/root]# which java /usr/local/jdk/bin/java istream@xxxxxxxxx [/root]# java -version Error occurred during initialization of VM Could not reserve enough space for object heap Could not create the Java virtual machine. istream@xxxxxxxxx [/root]#

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• Pixelated PDF in Apple Preview slideshow mode, but not in regular window

  - by Zack

  I have a PDF which is a presentation exported from OpenOffice. Two of the slides in this presentation have embedded .eps graphs. When I run the presentation using Preview's slideshow mode, the graphs are severely aliased and the axes are illegible. But when I just view the PDF in regular windowed mode, the graphs are properly antialiased and legible. Is there any way to get Preview to do the same display that it does in windowed mode, but in fullscreen (no window title, no menu bar)? (I don't want to just run the presentation from OpenOffice, because OpenOffice shows the same horrible aliasing effects plus it takes about 30 seconds to show the slide. I don't have, and don't want, Acrobat or MS Office. However, please do feel free to suggest other programs for doing PDF-based slideshows.)

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• Regular Expression to replace part of URL in XML file

  - by Richie086

  I need a regular expression in Notepad++ to search/replace a string. My document (xml) has serveral thousand lines that look similar to this: <Url Source="Output/username/project/Content/Volume1VolumeName/TopicFileName.htm" /> I need to replace everything starting from Volume1 to .htm" / to replaced with X's or some other character to mask the actual file names in this file. So the resulting string would look like this after the search/replace was performed: <Url Source="Output/username/project/Content/Volume1XxxxxxXxxx/XxxxxXxxxXxxx.htm" /> I am working with confidential information that I cannot release to people outside of my company, but i need to send an example log file to a 3rd party for troubleshooting purposes. FYI the X's do not need to follow the upper/lower case after the replacement, i was just using different case X's for the hell of it :)

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• latency, regular alternations. Pfsense, network

  - by Tillebeck

  Any idea why grapgh is a shown? It i two pfsense boxes and I have not looked into where they ping to and if it is related to the server they ping. Trafic graphs are following a normal 24 hour cycle and not related to either of the latency graphs Img1: High frequent ulteration in latency. Just started a few days back. Peaks are not perfectly regular but varies from 40min to 1hour Img2: This is a different router on another internet connection. Most of our routers shown this kind of latency graphs - so for our setup it is "normal". Please note that second graph is for a whole week and not just some hours

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• Help updating cron entry using regular expressions

  - by Uday

  hi I am trying to update a cron entry NOT by using crontab -e but by shell commands. For example the cron entry is like this: 10 * * * * /home/localuser/foo.sh -b 1 -h 4 > foo_output.sh 2>&1 No i need edit the command line parameters part ONLY i.e -b 1 -h 4 to something else which will be coming in from the user. First thing would be to write the crontab to a tmp file and then manipulate that temp file. Now, is there an easy way to edit that line using SED or something? The crude way wud be to delete that entire line, write a new line with the entire expression and then load that into the cron. I am not very good with regular expressions. My system supports sed -i so was thinking this could be done in a single line command. Thanks in advance

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• Misbehavior in regular expression in VIM

  - by poissonbreaker

  I am having a problem with a regular expression on vim. I have a pattern as follows: http:\/\/\(\w\+\.\?\)\+ [matches http://(AS MANY WORDS FOLLOWED BY DOT OR NOT ENCOUNTERS) e.g. http://wd1.wd2.com] I have a text as follows: http://wd1.wd2.com/wd3 I am trying to make this substitution on it: s/\(http:\/\/\)\(\w\+\.\?\)\+/\1wd4.wd5.com and the result is http://wd4.wd5.com /wd3 (Notice the white space inserted at the end of the replacement) How can I avoid having this inserted space? I am afraid is a bug in the regexp engine but I am not sure.

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• Objects with permissions assigned by django-guardian not visible in admin

  - by jul

  I'm using django-guardian in order to manage per object permission. For a given user I give permission all permission on one object: joe = User.objects.get(username="joe") mytask = Task.objects.get(pk=1) assign('add_task', joe, mytask) assign('change_task', joe, mytask) assign('delete_task', joe, mytask) and I get, as expected: In [57]: joe.has_perm("add_task", mytask) Out[57]: True In [58]: joe.has_perm("change_task", mytask) Out[58]: True In [59]: joe.has_perm("delete_task", mytask) Out[59]: True In admin.py I also make TaskAdmin inherit from GuardedModelAdmin instead of admin.ModelAdmin Now when I connect to my site with joe, on the admin I get: You don't have permission to edit anything Am I not supposed to be able to edit the object mytask? Do I have to set some permissions using the built-in model-based permission system? Am I missing anything? Thank you

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• Apache MatchRedirect exception regex

  - by Arash Mousavi

  I want to redirect any URL that is Https and hasn't start with "system_" to the same URL with http. for exapmle for this url : https://exsite.tld/some/thing/that/not/start/with/pattern to : http://exsite.tld/some/thing/that/not/start/with/pattern but this url: https://exsite.tld/system_aas3f4 Shouldn't redirect. I try: RedirectMatch ^/?((?!(system_)).*) http://exsite.tld/$1 but it won't work. I don't know what's the problem.

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• Apache mod_proxy_html Substitute: how to re-use part of regex match? (regex variables?)

  - by goober

  Hi all, Have a unique URL-rewriting situation in Apache. I need to be able to take a URL that starts with "\u002f[X]" or '\u002f[X]" Where X is the rest of some URL, and substitute the text "\u002fmeis2\u002f[X] I'm not sure how the Regex works in Apache -- I think it's the same as Perl 5? -- but even then I'm a little unsure how this would be done. My hunch is that it has to do with Regex grouping and then using $1 to pull the variable out, but I'm entirely unfamiliar with this process in Apache. Hoping someone can help -- thanks!

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• non greedy grep command on ubuntu?

  - by ChrisRamakers

  Hi all, I'm building a script which filters out all our translatables from our template system. the problem i'm facing is the occasion where 2 translatables are on one line. These are 2 example lines from a template file which both hold one or more translatables <img src="/captcha/generate.jpg" alt="[#Captcha#]" /> <span>[#Velden met een * zijn verplicht in te vullen#]</span> <button type="submit" name="frm_submit" class="right">[#Verzend#] And when i set loose the following regexp egrep "\[#(.*)#\]" . -Rohis I get this output [#Captcha#]" [#Velden met een * zijn verplicht in te vullen#]</span> <button type="submit" name="frm_submit" class="right">[#Verzend#] While the desired output is [#Captcha#] [#Velden met een * zijn verplicht in te vullen#] [#Verzend#]

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• I am trying to write an htaccess file performs authentication and redirects authenticated users to a

  - by racl101

  This is what I have so far but I can't get the RewriteCond and RewriteRule properly. RewriteEngine On RewriteCond %{LA-U:REMOTE_USER} (\d{3})$ RewriteRule !^%1 http://subdomain.mydomain.com/%1 [R,L]. AuthName "My Domain Protected Area" AuthType Basic AuthUserFile /path/to/my/.htpasswd Require valid-user This is what I mean the ReWriteCond and RewriteRule to say: "If the REMOTE_USER has a username ending in 3 digits then capture the three digits that match and for whatever url they are trying to access if it does not start with the 3 digits captured then redirect them to the sub directory with the name equal to those captured three digits." In other words, if a user named 'johnny202' is authenticated then if he's requesting any directory other than http://subdomain.mydomain.com/202/ then he should be redirected to http://subdomain.mydomain.com/202/ The only thing I can think of that is wrong is the first instance of '%1'.

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• apache virtualhost: Auto subdomain with exception

  - by Ineentho

  I've been searching for a way to automatically redirect domains to a specific folder, and fond a good answer here on serverfault: Apache2 VirtualHost auto subdomain. (The accepted answer) So far everything works good, however now I need to add an exception to this. The result I want is this: http://localhost/ --> E:/websites/ http://specialDomain2/ --> E:/websites/ http://normal1.com/ --> E:/websites/normal1.com/ http://normalDomain.com/ --> E:/websites/normal2.com/ I get the expceted result for the two last domains, but the localhost doesn't work. I copied the script from the question aboved, and tried to add something like <VirtualHost *:80> RewriteEngine On RewriteMap lowercase int:tolower # if already rewitten and we have the right path, stop right here RewriteRule ^(E:/websites/[^/]+/.*)$ $1 [L] RewriteRule ^localhost/(.*)$ E:/websites/$1 [L] # <-- Added this row RewriteRule ^(.+) ${lowercase:%{SERVER_NAME}}$1 [C] RewriteRule ^(www\.)?([^/]+)/(.*)$ E:/websites/$2/$3 [L,E=VHOST_ROOT:E:/websites/$2/] </VirtualHost> I thought this would make sense, since I would translate this to if URL = localhost/* Do nothing (because of the [L] flag), and use the default document root specified earlier else continue What's wrong with this? Thanks for any help!

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• Zabbix doesn't update value from file neither with log[] nor with vfs.file.regexp[] item

  - by tymik

  I am using Zabbix 2.2. I have a very specific environment, where I have to generate desired data to file via script, then upload that file to ftp from host and download it to Zabbix server from ftp. After file is downloaded, I check it with log[] and vfs.file.regexp[] items. I use these items as below: log[/path/to/file.txt,"C.*\s([0-9]+\.[0-9])$",Windows-1250,,"all",\1] vfs.file.regexp[/path/to/file.txt,"C.*\s([0-9]+\.[0-9])$",Windows-1250,,,\1] The line I am parsing looks like below: C: 8195Mb 5879Mb 2316Mb 28.2 The value I want to extract is 28.2 at the end of file. The problem I am currently trying to solve is that when I update the file (upload from host to ftp, then download from ftp to Zabbix server), the value does not update. I was trying only log[] at start, but I suspect, that log[] treat the file as real log file and doesn't check the same lines (althought, following the documentation, it should with "all" value), so I added vfs.file.regexp[] item too. The log[] has received a value in past, but it doesn't update. The vfs.file.regexp[] hasn't received any value so far. file.txt has got reuploaded and redownloaded several times and situation doesn't change. It seems that log[] reads only new lines in the file, it doesn't check lines already caught if there are any changes. The zabbix_agentd.log file doesn't report any problem with access to file, nor with regexp construction (it did report "unsupported" for log[] key, when I had something set up wrong). I use debug logging level for agent - I haven't found any interesting info about that problem. I have no idea what I might be doing wrong or what I do not know about how Zabbix is performing these checks. I see 2 solutions for that: adding more lines to the file instead of making new one or making new files and check them with logrt[], but those doesn't satisfy my desires. Any help is greatly appreciated. Of course I will provide additional information, if requested - for now I don't know what else might be useful.

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• RegularExpression Validator doesn't display error message.

  - by Rudi Ramey

  I have a regular expression validation control initialized to validate a textbox control. I want users to be able to enter U.S. Currency values ($12,115.85 or 1500.22 etc.). I found a regular expression off of regexlib website that does the trick. The validation control seems to be working except for one crucial thing. If invalid data is entered, the validation text dispalys (a red "*" next to the textbox), but the page will still submit and the error message won't pop up... I thought that the error message is supposed to display and the page won't submit if the validation control detects invalid data. Isn't this automatic with ASP .NET? I have searched extensively on how to create validation controls, but haven't found anything different than what I am already doing. Can anyone tell me what I am doing wrong here? <asp:TextBox ID="txtActualCost" runat="server" Width="120px" CausesValidation="true"></asp:TextBox> <asp:RegularExpressionValidator ID="regExValActualCost" ControlToValidate="txtActualCost" Text="*" ValidationExpression="^\$?(\d{1,3}(\,\d{3})*|(\d+))(\.\d{2})?$" ErrorMessage="Please enter a valid currency value for 'Actual Cost'" Display="Dynamic" EnableClientScript="true" runat="server" />

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• java phone number validation....

  - by user69514

  Here is my problem: Create a constructor for a telephone number given a string in the form xxx-xxx-xxxx or xxx-xxxx for a local number. Throw an exception if the format is not valid. So I was thinking to validate it using a regular expression, but I don't know if I'm doing it correctly. Also what kind of exception would I have to throw? Do I need to create my own exception? public TelephoneNumber(String aString){ if(isPhoneNumberValid(aString)==true){ StringTokenizer tokens = new StringTokenizer("-"); if(tokens.countTokens()==3){ areaCode = Integer.parseInt(tokens.nextToken()); exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else if(tokens.countTokens()==2){ exchangeCode = Integer.parseInt(tokens.nextToken()); number = Integer.parseInt(tokens.nextToken()); } else{ //throw an excemption here } } } public static boolean isPhoneNumberValid(String phoneNumber){ boolean isValid = false; //Initialize reg ex for phone number. String expression = "(\\d{3})(\\[-])(\\d{4})$"; CharSequence inputStr = phoneNumber; Pattern pattern = Pattern.compile(expression); Matcher matcher = pattern.matcher(inputStr); if(matcher.matches()){ isValid = true; } return isValid; } Hi sorry, yes this is homework. For this assignments the only valid format are xxx-xxx-xxxx and xxx-xxxx, all other formats (xxx)xxx-xxxx or xxxxxxxxxx are invalid in this case. I would like to know if my regular expression is correct

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• Convert Javascript Regular Expression to PHP (PCRE) Expression

  - by Matt

  Hi all, I am up to my neck in regular expressions, and I have this regular expression that works in javascript (and flash) that I just can't get working in PHP Here it is: var number = '(?:-?\\b(?:0|[1-9][0-9]*)(?:\\.[0-9]+)?(?:[eE][+-]?[0-9]+)?\\b)'; var oneChar = '(?:[^\\0-\\x08\\x0a-\\x1f\"\\\\]' + '|\\\\(?:[\"/\\\\bfnrt]|u[0-9A-Fa-f]{4}))'; var str = '(?:\"' + oneChar + '*\")'; var varName = '\\$(?:' + oneChar + '[^ ,]*)'; var func = '(?:{[ ]*' + oneChar + '[^ ]*)'; // Will match a value in a well-formed JSON file. // If the input is not well-formed, may match strangely, but not in an unsafe // way. // Since this only matches value tokens, it does not match whitespace, colons, // or commas. var jsonToken = new RegExp( '(?:false|true|null' +'|[\\}]' + '|' + varName + '|' + func + '|' + number + '|' + str + ')', 'g'); If you want it fully assembled here it is: /(?:false|true|null|[\}]|\$(?:(?:[^\0-\x08\x0a-\x1f"\\]|\\(?:["/\\bfnrt]|u[0-9A-Fa-f]{4}))[^ ,]*)|(?:{[ ]*(?:[^\0-\x08\x0a-\x1f"\\]|\\(?:["/\\bfnrt]|u[0-9A-Fa-f]{4}))[^ ]*)|(?:-?\b(?:0|[1-9][0-9]*)(?:\.[0-9]+)?(?:[eE][+-]?[0-9]+)?\b)|(?:"(?:[^\0-\x08\x0a-\x1f"\\]|\\(?:["/\\bfnrt]|u[0-9A-Fa-f]{4}))*"))/g Interestingly enough, its very similar to JSON. I need this regular expression to work in PHP... Here's what I have in PHP: $number = '(?:-?\\b(?:0|[1-9][0-9]*)(?:\\.[0-9]+)?(?:[eE][+-]?[0-9]+)?\\b)'; $oneChar = '(?:[^\\0-\\x08\\x0a-\\x1f\"\\\\]|\\\\(?:[\"/\\\\bfnrt]|u[0-9A-Fa-f]{4}))'; $string = '(?:\"'.$oneChar.'*\")'; $varName = '\\$(?:'.$oneChar.'[^ ,]*)'; $func = '(?:{[ ]*'.$oneChar.'[^ ]*)'; $jsonToken = '(?:false|true|null' .'|[\\}]' .'|'.$varName .'|'.$func .'|'.$number .'|'.$string .')'; echo $jsonToken; preg_match_all($jsonToken, $content, $out); return $out; Here's what happens if I try using preg_match_all(): Warning: preg_match_all() [function.preg-match-all]: Compilation failed: nothing to repeat at offset 0 in /Users/Matt/Sites/Templating/json/Jeeves.php on line 88 Any help would be much appreciated! Thanks, Matt

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• Mathematica regular expressions on unicode strings.

  - by dreeves

  This was a fascinating debugging experience. Can you spot the difference between the following two lines? StringReplace["–", RegularExpression@"[\\s\\S]" -> "abc"] StringReplace["-", RegularExpression@"[\\s\\S]" -> "abc"] They do very different things when you evaluate them. It turns out it's because the string being replaced in the first line consists of a unicode en dash, as opposed to a plain old ascii dash in the second line. In the case of the unicode string, the regular expression doesn't match. I meant the regex "[\s\S]" to mean "match any character (including newline)" but Mathematica apparently treats it as "match any ascii character". How can I fix the regular expression so the first line above evaluates the same as the second? Alternatively, is there an asciify filter I can apply to the strings first? PS: The Mathematica documentation says that its string pattern matching is built on top of the Perl-Compatible Regular Expressions library (http://pcre.org) so the problem I'm having may not be specific to Mathematica.

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• .NET Regular Expression to find actual words in text

  - by Mehdi Anis

  I am using VB .NET to write a program that will get the words from a suplied text file and count how many times each word appears. I am using this regular expression:- parser As New Regex("\w+") It gives me almost 100% correct words. Except when I have words like "Ms Word App file name is word.exe." or "is this a c# statment If(ab?1,0) ?" In such cases I get [word & exe] AND [If, a, b, 1 and 0] as seperate words. it would be nice (for my purpose) that I received word.exe and (If(ab?1,0) as words. I guess \w+ looks for white space, sentence terminating punctuation mark and other punctuation marks to determine a word. I want a similar regular Expression that will not break a word by a punctuation mark, if the punctuation mark is not the end of the word. I think end-of-word can be defined by a trailing WhiteSpace, Sentence terminating Punctuation (you may think of others). if you can suggest some regular expression 9for VB .NET) that will be great help. Thanks.

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• Regular expression to match HTML table row ( <tr> ) NOT containing a specific value

  - by user1821136

  I'm using Notepad++ to clean up a long and messy HTML table. I'm trying to use regular expressions even if I'm a total noob. :) I need to remove all the table rows that doesn't contain a specific value (may I call that substring?). After having all the file contents unwrapped, I've been able to use the following regular expression to select, one by one, every table row with all its contents: <tr>.+?</tr> How can I improve the regular expression in order to select and replace only table rows containing, somewhere inside a part of them, that defined substring? I don't know if this does matter but the structure of every table row is the following (I've put there every HTML tag, the dots stand for standard content/values) <tr> <td> ... </td> <td> ... </td> <td> <a sfref="..." href="...">!! SUBSTRING I HAVE TO MATCH HERE !!</a> </td> <td> <img /> </td> <td> ... </td> <td> ... </td> <td> ... </td> <td> ... </td> </tr> Thanks in advance for your help!

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• Nullability (Regular Expressions)

  - by danportin

  In Brzozowski's "Derivatives of Regular Expressions" and elsewhere, the function d(R) returning ? if a R is nullable, and Ø otherwise, includes clauses such as the following: d(R1 + R2) = d(R1) + d(R2) d(R1 · R2) = d(R1) ? d(R2) Clearly, if both R1 and R2 are nullable then (R1 · R2) is nullable, and if either R1 or R2 is nullable then (R1 + R2) is nullable. It is unclear to me what the above clauses are supposed to mean, however. My first thought, mapping (+), (·), or the Boolean operations to regular sets is nonsensical, since in the base case, d(a) = Ø (for all a ? S) d(?) = ? d(Ø) = Ø and ? is not a set (nor is the return type of d, which is a regular expression). Furthermore, this mapping isn't indicated, and there is a separate notation for it. I understand nullability, but I'm lost on the definition of the sum, product, and Boolean operations in the definition of d: how are ? or Ø returned from d(R1) ? d(R2), for instance, in the definition off d(R1 · R2)?

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