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  • Given a program's source code, what is a simple way to calculate the function points?

    - by user354822
    For class, I was told to give a function point count for Mozilla Thunderbird, however I am absolutely stumped as to how to approach this. Some methods I saw online suggested analyzing the interface of the program itself, however they used very simple methods. Thunderbird has a very complex interface and has so many FPs, I'm not sure if I could do it by hand. Some help would be very much appreciated. Thanks!

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  • c++ i need help with this program. everytime i try to run it, i got a problem

    - by FOXMULDERIZE
    1-the program must read numeric data from a file. 2-only one line per number 3-half way between those numbers is a negative number. 4-the program must sum those who are above the negative number in a acumulator an those below the negative number in another acumulator. 5-the black screen shall print both results and determined who is grater or equal. include include using namespace std; void showvalues(int,int,int[]); void showvalues2(int,int); void sumtotal(int,int); int main() { int total1=0; int total2=0; const int SIZE_A= 9; int arreglo[SIZE_A]; int suma,total,a,b,c,d,e,f; ifstream archivo_de_entrada; archivo_de_entrada.open("numeros.txt"); //lee/// for(int count =0 ;count < SIZE_A;count++) archivo_de_entrada>>arreglo[count] ; archivo_de_entrada.close(); showvalues(0,3,arreglo); showvalues2(5,8); sumtotal(total1,total2); system("pause"); return 0; } void showvalues(int a,int b,int arreglos) { int total1=0; //muestra//////////////////////// cout<< "los num son "; for(int count = a ;count <= b;count++) total1 += arreglos[count]; cout < } void showvalues2(int c,int d) { ////////////////////////////// int total2=0; cout<< "los num 2 son "; for(count =5 ;count <=8;count++) total2 = total2 + arreglo[count]; cout < void sumtotal(int e,int f) { ///////////////////////////////// cout<<"la suma de t1 y t2 es "; total= total1 + total2; cout< }

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  • Having another static method as the entry point of the java program?

    - by GK
    As we all know java program will start executing from the main method of the class. So was curious to know that is there any other way by which we can make another static method as the entry point, that is can we override this property of the JVM to start with some other method than main? many of you will ask why do you want to do this? so want to make it clear that its just a curiosity to know about. And if it is there then it might help in many ways

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  • How to give focus to default program of shell-opened file, from Java ?

    - by Rabarberski
    From within Java, I am opening an Excel file with the default file handler (MS Excel, in this case :-) ) using the method described in this stackoverflow question: Desktop dt = Desktop.getDesktop(); dt.open(new File(filename)); However, the Excel program doesn't get the focus. Is there any easy way to do so? Edit: There is a related stackoverflow question for C#, but I didn't find any similar Java method.

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  • easy, straightforward way to package a python program for debian?

    - by Jeremiah Rose
    i'm having trouble navigating the maze of distribution tools for python and debian; cdbs, debhelper, python-support, python-central, blah blah blah .. my application is a fairly straightforward one - a single python package (directory containing modules and a __init__.py), a script for running the program (script.py) and some icons and menu items (.desktop files). is there a simple straightforward way to make a .deb file out of these, or should i brave the nonsensical tools listed above?

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  • How can a C/C++ program put itself into background?

    - by Larry Gritz
    What's the best way for a running C or C++ program that's been launched from the command line to put itself into the background, equivalent to if the user had launched from the unix shell with '&' at the end of the command? (But the user didn't.) It's a GUI app and doesn't need any shell I/O, so there's no reason to tie up the shell after launch. But I want a shell command launch to be auto-backgrounded without the '&' (or on Windows). Ideally, I want a solution that would work on any of Linux, OS X, and Windows. (Or separate solutions that I can select with #ifdef.) It's ok to assume that this should be done right at the beginning of execution, as opposed to somewhere in the middle. One solution is to have the main program be a script that launches the real binary, carefully putting it into the background. But it seems unsatisfying to need these coupled shell/binary pairs. Another solution is to immediately launch another executed version (with 'system' or CreateProcess), with the same command line arguments, but putting the child in the background and then having the parent exit. But this seems clunky compared to the process putting itself into background. Edited after a few answers: Yes, a fork() (or system(), or CreateProcess on Windows) is one way to sort of do this, that I hinted at in my original question. But all of these solutions make a SECOND process that is backgrounded, and then terminate the original process. I was wondering if there was a way to put the EXISTING process into the background. One difference is that if the app was launched from a script that recorded its process id (perhaps for later killing or other purpose), the newly forked or created process will have a different id and so will not be controllable by any launching script, if you see what I'm getting at. Edit #2: fork() isn't a good solution for OS X, where the man page for 'fork' says that it's unsafe if certain frameworks or libraries are being used. I tried it, and my app complains loudly at runtime: "The process has forked and you cannot use this CoreFoundation functionality safely. You MUST exec()." I was intrigued by daemon(), but when I tried it on OS X, it gave the same error message, so I assume that it's just a fancy wrapper for fork() and has the same restrictions. Excuse the OS X centrism, it just happens to be the system in front of me at the moment. But I am indeed looking for a solution to all three platforms.

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