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  • this is my first time asking here, I wanted to create a linked list while sorting it thanks

    - by user2738718
    package practise; public class Node { // node contains data and next public int data; public Node next; //constructor public Node (int data, Node next){ this.data = data; this.next = next; } //list insert method public void insert(Node list, int s){ //case 1 if only one element in the list if(list.next == null && list.data > s) { Node T = new Node(s,list); } else if(list.next == null && list.data < s) { Node T = new Node(s,null); list.next = T; } //case 2 if more than 1 element in the list // 3 elements present I set prev to null and curr to list then performed while loop if(list.next.next != null) { Node curr = list; Node prev = null; while(curr != null) { prev = curr; curr = curr.next; if(curr.data > s && prev.data < s){ Node T = new Node(s,curr); prev.next = T; } } // case 3 at the end checks for the data if(prev.data < s){ Node T = new Node(s,null); prev.next = T; } } } } // this is a hw problem, i created the insert method so i can check and place it in the correct order so my list is sorted This is how far I got, please correct me if I am wrong, I keep inserting node in the main method, Node root = new Node(); and root.insert() to add.

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  • JPA Database strcture for internationalisation

    - by IrishDubGuy
    I am trying to get a JPA implementation of a simple approach to internationalisation. I want to have a table of translated strings that I can reference in multiple fields in multiple tables. So all text occurrences in all tables will be replaced by a reference to the translated strings table. In combination with a language id, this would give a unique row in the translated strings table for that particular field. For example, consider a schema that has entities Course and Module as follows :- Course int course_id, int name, int description Module int module_id, int name The course.name, course.description and module.name are all referencing the id field of the translated strings table :- TranslatedString int id, String lang, String content That all seems simple enough. I get one table for all strings that could be internationalised and that table is used across all the other tables. How might I do this in JPA, using eclipselink 2.4? I've looked at embedded ElementCollection, ala this... JPA 2.0: Mapping a Map - it isn't exactly what i'm after cos it looks like it is relating the translated strings table to the pk of the owning table. This means I can only have one translatable string field per entity (unless I add new join columns into the translatable strings table, which defeats the point, its the opposite of what I am trying to do). I'm also not clear on how this would work across entites, presumably the id of each entity would have to use a database wide sequence to ensure uniqueness of the translatable strings table. BTW, I tried the example as laid out in that link and it didn't work for me - as soon as the entity had a localizedString map added, persisting it caused the client side to bomb but no obvious error on the server side and nothing persisted in the DB :S I been around the houses on this about 9 hours so far, I've looked at this Internationalization with Hibernate which appears to be trying to do the same thing as the link above (without the table definitions it hard to see what he achieved). Any help would be gratefully achieved at this point... Edit 1 - re AMS anwser below, I'm not sure that really addresses the issue. In his example it leaves the storing of the description text to some other process. The idea of this type of approach is that the entity object takes the text and locale and this (somehow!) ends up in the translatable strings table. In the first link I gave, the guy is attempting to do this by using an embedded map, which I feel is the right approach. His way though has two issues - one it doesn't seem to work! and two if it did work, it is storing the FK in the embedded table instead of the other way round (I think, I can't get it to run so I can't see exactly how it persists). I suspect the correct approach ends up with a map reference in place of each text that needs translating (the map being locale-content), but I can't see how to do this in a way that allows for multiple maps in one entity (without having corresponding multiple columns in the translatable strings table)...

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  • getResourceAsStream returns HttpInputStream not of the entire file

    - by khue
    Hi, I am having a web application with an applet which will copy a file packed witht the applet to the client machine. When I deploy it to webserver and use: InputStream in = getClass().getResourceAsStream("filename") ; The in.available() always return a size of 8192 bytes for every file I tried, which means the file is corrupted when it is copied to the client computer. The InputStream is of type HttpInputStream (sun.net.protocol.http.HttpUrlConnection$httpInputStream). But while I test applet in applet viewer, the files are copied fine, with the InputStream returned is of type BufferedInputStream, which has the file's byte sizes. I guess that when getResourceStream in file system the BufferedInputStream will be used and when at http protocol, HttpInputStream will be used. How will I copy the file completely, is there a size limited for HttpInputStream? Thanks a lot.

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  • Table not created by Hibernate

    - by User1
    I annotated a bunch of POJO's so JPA can use them to create tables in Hibernate. It appears that all of the tables are created except one very central table called "Revision". The Revision class has an @Entity(name="RevisionT") annotation so it will be renamed to RevisionT so there is not a conflict with any reserved words in MySQL (the target database). I delete the entire database, recreate it and basically open and close a JPA session. All the tables seem to get recreated without a problem. Why would a single table be missing from the created schema? What instrumentation can be used to see what Hibernate is producing and which errors? Thanks. UPDATE: I tried to create as a Derby DB and it was successful. However, one of the fields has a a name of "index". I use @org.hibernate.annotations.IndexColumn to specify the name to something other than a reserved word. However, the column is always called "index" when it is created. Here's a sample of the suspect annotations. @ManyToOne @JoinColumn(name="MasterTopID") @IndexColumn(name="Cx3tHApe") protected MasterTop masterTop; Instead of creating MasterTop.Cx3tHApe as a field, it creates MasterTop.Index. Why is the name ignored?

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  • send email to list of users with different timezones?

    - by ylazez
    i use the following method to send email to list of users i want the (To) in each email to be for just the user only not all users i.e appears to the users that the email is sent to only him my guess is to loop on: message.addRecipients(Message.RecipientType.TO, address); then send the message right? , but this is a heavy process sending an email many times any ideas ? suppose that i have the timezone for each user and i want to send each user the message in his timzone, the same issue i guess setting sent date for each user in his timezone then sending the message, right ? the method is: try { Properties props = System.getProperties(); props.put("mail.smtp.host", "localhost"); // Get a mail session Session session = Session.getDefaultInstance(props, null); // Define a new mail message Message message = new MimeMessage(session); InternetAddress ia = new InternetAddress(); ia.setPersonal("MySite"); ia.setAddress(from); message.setFrom(ia); Address[] address = new Address[recievers.size()]; for (int i = 0; i < recievers.size(); i++) { address[i] = new InternetAddress(recievers.get(i)); } message.addRecipients(Message.RecipientType.TO, address); message.setSubject(subject); // Create a message part to represent the body text BodyPart messageBodyPart = new MimeBodyPart(); messageBodyPart.setContent(body, "text/html"); // use a MimeMultipart as we need to handle the file attachments Multipart multipart = new MimeMultipart(); // add the message body to the mime message multipart.addBodyPart(messageBodyPart); // Put all message parts in the message message.setContent(multipart); message.setSentDate(getCurrentDate()); // Send the message Transport.send(message); } catch (Exception ex) {}

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  • Android Multithreading, creating new thread not executing rest of OnCreate

    - by Aidan
    Hi Guys, Basically I'm trying to run 2 threads within the same class at the same time. The code runs but only executes whats in run() and doesnt finish the onCreate method... anyone know why? public Camera1(){ t = new Thread(this, "My Thread"); t.start(); } public void run(){ bearing(); } @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); new Camera1(); makeview(); tracking(); } Thanks!

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  • What is annotations and how do it actually works for frameworks like Spring ?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • Binary search in rotated sorted list

    - by Algorist
    I am having a sorted list which is rotated and I would like to do a binary search on that list to find the minimum element. Lets suppose initial list is {1,2,3,4,5,6,7,8} rotated list can be like {5,6,7,8,1,2,3,4} Normal binary search doesn't work in this case. Any idea how to do this.

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  • In which layer should I join 2 entities together?

    - by William
    I use Spring MVC and a regular JDBC. I've just learned that I should separate business process into layers which are presentation layer, controller layer, service layer, and repository/DAO layer. Now suppose that I have an Entity called Person that can have multiple Jobs. Job itself is another entity which have its own properties. From what I gathered, the repository layer only manages one entity. Now I have one entity that contains another entity. Where do I "join" them? The service layer? Suppose I want to get a person whose job isn't known yet (lazy loading). But the system might ask what the job of that particular person is later on. What is the role of each layer in this case? Please let me know if I need to add any detail into this question.

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  • oracle connectivity

    - by jayprakash
    String serverName = "127.0.0.1"; String portNumber = "1521"; String sid = "database"; String url = "jdbc:oracle:thin:@" + serverName + ":" + portNumber + ":" + sid; String username = "scott"; String password = "tiger"; connection = DriverManager.getConnection(url, username, password); Could not connect to the database

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  • Weird behaviour of Calendar and DateFormat

    - by Nejc
    I encountered really strange behaviour when constructing a Calendar object and then formating it in a particular style. Let the code do the talking: public class Test { public static void main(String[] args) { SimpleDateFormat frmt = new SimpleDateFormat(); frmt.applyPattern("yyyy-MM-dd"); GregorianCalendar date = new GregorianCalendar(2012,1,1); System.out.println(frmt.format(date.getTime())); } } The output is: 2012-02-01 The expected output is of course: 2012-01-01 What am I doing wrong?

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  • Database connection via Hibernate in servlets

    - by blackliteon
    What is the best place in servlet for Hibernate code that returns HibernateSessionFactory ? I saw many examples: ones put db connection in service methods. Others - use smth like HibernateUtil (Singleton) that returns HibernateSessionFactory. I don't know is it safe to use HibernateUtil in multithreaded Servlets ?

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  • JPA: what is the proper pattern for iterating over large result sets?

    - by Caffeine Coma
    Let's say I have a table with millions of rows. Using JPA, what's the proper way to iterate over a query against that table, such that I don't have all an in-memory List with millions of objects? I suspect that the following will blow up if the table is large: List<Model> models = entityManager().createQuery("from Model m", Model.class).getResultList(); for (Model model : models) { // do something with model } Is pagination (looping and manually updating setFirstResult()/setMaxResult()) really the best solution?

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  • why toString method does not work here??

    - by user329820
    Hi this is my whole class ,I have added number 2 to the doubly linked list and then I want it to be be print in the concole but it will show this "datastructureproject.Node@f62373" thanks! package datastructureproject; public class DoublyLinkedList { private Node head = new Node(0); private Node tail = new Node(0); private int length = 0; public DoublyLinkedList() { head.setPrev(null); head.setNext(tail); tail.setPrev(head); tail.setNext(null); } public void add(int index, int value) throws IndexOutOfBoundsException { Node cursor = get(index); Node temp = new Node(value); temp.setPrev(cursor); temp.setNext(cursor.getNext()); cursor.getNext().setPrev(temp); cursor.setNext(temp); length++; } private Node get(int index) throws IndexOutOfBoundsException { if (index < 0 || index > length) { throw new IndexOutOfBoundsException(); } else { Node cursor = head; for (int i = 0; i < index; i++) { cursor = cursor.getNext(); } return cursor; } } public long size() { return length; } public boolean isEmpty() { return length == 0; } @Override public String toString() { StringBuffer result = new StringBuffer(); result.append("(head) - "); Node temp = head; while (temp.getNext() != tail) { temp = temp.getNext(); result.append(temp.getValue() + " - "); } result.append("(tail)"); return result.toString(); } public static void main(String[] args){ DoublyLinkedList list = new DoublyLinkedList(); list.add(0,2 ); System.out.println(list.get(0).toString()); } }

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  • Overriding a method in statically created objects

    - by I82Much
    All, Due to a bug in a library I'm using, I need to override the dispose() method on all objects extending a certain class and make it a NO-OP. I know that if I'm making new instances of the classes directly, this is easy to do: layerManager = new LayerManagerLayer(wwd) { @Override public void dispose() {} }; The problem is that a lot of the object instances I get are not directly constructed by my client code, but instead are created via static library method calls. // Here I want to override the dispose method, but I cannot. Layer l = ShapefileLoader.makeShapefileLayer(this.getClass().getResource("polylines10.shp")); Is there a way I can inject my dispose method into that statically created object without modifying the original sourcecode?

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  • When calling CRUD check if "parent" exists with read or join?

    - by Trick
    All my entities can not be deleted - only deactivated, so they don't appear in any read methods (SELECT ... WHERE active=TRUE). Now I have some 1:M tables on this entities on which all CRUD operations can be executed. What is more efficient or has better performance? My first solution: To add to all CRUD operations: UPDATE ... JOIN entity e ... WHERE e.active=TRUE My second solution: Before all CRUD operations check if entity is active: if (getEntity(someId) != null) { //do some CRUD } In getEntity there's just SELECT * FROM entity WHERE id=? AND active=TRUE. Or any other solution, recommendation,...?

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  • Poor performance / speed of regex with lookahead

    - by Hugo Zaragoza
    I have been observing extremely slow execution times with expressions with several lookaheads. I suppose that this is due to underlying data structures, but it seems pretty extreme and I wonder if I do something wrong or if there are known work-arounds. The problem is determining if a set of words are present in a string, in any order. For example we want to find out if two terms "term1" AND "term2" are somewhere in a string. I do this with the expresion: (?=.*\bterm1\b)(?=.*\bterm2\b) But what I observe is that this is an order of magnitude slower than checking first just \bterm1\b and just then \bterm2\b This seems to indicate that I should use an array of patterns instead of a single pattern with lookaheads... is this right? it seems wrong... Here is an example test code and resulting times: public static void speedLookAhead() { Matcher m, m1, m2; boolean find; int its = 1000000; // create long non-matching string char[] str = new char[2000]; for (int i = 0; i < str.length; i++) { str[i] = 'x'; } String test = str.toString(); // First method: use one expression with lookaheads m = Pattern.compile("(?=.*\\bterm1\\b)(?=.*\\bterm2\\b)").matcher(test); long time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m.reset(test); find = m.find(); } time = System.currentTimeMillis() - time; System.out.println(time); // Second method: use two expressions and AND the results m1 = Pattern.compile("\\bterm1\\b").matcher(test); m2 = Pattern.compile("\\bterm2\\b").matcher(test); time = System.currentTimeMillis(); ; for (int i = 0; i < its; i++) { m1.reset(test); m2.reset(test); find = m1.find() && m2.find(); } time = System.currentTimeMillis() - time; System.out.println(time); } This outputs in my computer: 1754 150

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  • JSF SelectOneMenuItem onselect attribute

    - by William
    I have created selectOneMenuItem(JSF).I placed my events on valueChangeListener / onchange like that <h:selectOneMenu id="ddl" value="#{Foo.attr}" onchange="submit()" valueChangeListener="#{Foo.renderFoo}"> When I select one vlaue from selectOneMenuItem then event fires.Now when I reselect that value ,then event doesn't fire (because this is the valueChangeListener event) so it doesn't fire.I want that event should fire on every selection even on again the same selection.I found onselect but unable to find that is it right and how can i use this onselect.Anyu help would be greatly appreciable

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  • Does a HashSet make an internal copy of added Objects?

    - by praks5432
    Let's say I have a function that is recursive and is like this public void someRecur(List<Integer>someList){ if(someBreakCondition) Set.add(someList); for(int i = 0; i < someLen ; i++){ someList.add(someInt); someRecur(someList); someList.remove(someInt); } } Does the remove affect the list that has been put into the set? What should I do to give the set an actual copy of the list?

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  • Problem inretrieving the name field in symbian using j2me

    - by learn
    I have added the firstname, middlename, lastname, suffix, prefix in symbian and now i want to retrieve each of this attributes of name. I am getting the firstname and lastname together by if(contactlist.isSupportedField(Contact.FORMATTED_NAME) && contact.countValues(Contact.FORMATTED_NAME)0) { mycontact.setName(contact.getString(Contact.FORMATTED_NAME, 0)); }

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  • Error in my web.xml

    - by Mercer
    Why i have an error in my web.xml when i want add servlet..? <servlet> <servlet-name>ClientServlet</servlet-name> <servlet-class>org.task.ClientServlet</servlet-class> <servlet-name>FactoryServlet</servlet-name> <servlet-class>org.task.FactoryServlet</servlet-class> <servlet-name>TraderServlet</servlet-name> <servlet-class>org.task.TraderServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ClientServlet</servlet-name> <url-pattern>/ClientServlet</url-pattern> <servlet-name>FactoryServlet</servlet-name> <url-pattern>/FactoryServlet</url-pattern> <servlet-name>TraderServlet</servlet-name> <url-pattern>/TraderServlet</url-pattern> </servlet-mapping>

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