Search Results

Search found 46178 results on 1848 pages for 'java home'.

Page 906/1848 | < Previous Page | 902 903 904 905 906 907 908 909 910 911 912 913  | Next Page >

  • Test param value using EasyMock

    - by fmpdmb
    I'm attempting to write some unit tests using EasyMock and TestNG and have run into a question. Given the following: void execute(Foo f) { Bar b = new Bar() b.setId(123); f.setBar(b); } I'm trying to test that the Id of the Bar gets set accordingly in the following fashion: @Test void test_execute() { Foo f = EasyMock.createMock(Foo.class); execute(f); Bar b = ?; // not sure what to do here f.setBar(b); f.expectLastCall(); } In my test, I can't just call f.getBar() and inspect it's Id because f is a mock object. Any thoughts? Is this where I'd want to look at the EasyMock v2.5 additions andDelegateTo() and andStubDelegateTo()?

    Read the article

  • Simple question about the lunarlander example.

    - by Smills
    I am basing my game off the lunarlander example. This is the run loop I am using (very similar to what is used in lunarlander). I am getting considerable performance issues associated with my drawing, even if I draw almost nothing. I noticed the below method. Why is the canvas being created and set to null each cycle? @Override public void run() { while (mRun) { Canvas c = null; try { c = mSurfaceHolder.lockCanvas();//null synchronized (mSurfaceHolder) { updatePhysics(); doDraw(c); } } finally { // do this in a finally so that if an exception is thrown // during the above, we don't leave the Surface in an // inconsistent state if (c != null) { mSurfaceHolder.unlockCanvasAndPost(c); } } } } Most of the times I have read anything about canvases it is more along the lines of: mField = new Bitmap(...dimensions...); Canvas c = new Canvas(mField); My question is: why is Google's example done that way (null canvas), what are the benefits of this, and is there a faster way to do it?

    Read the article

  • Android Multithreading, creating new thread not executing rest of OnCreate

    - by Aidan
    Hi Guys, Basically I'm trying to run 2 threads within the same class at the same time. The code runs but only executes whats in run() and doesnt finish the onCreate method... anyone know why? public Camera1(){ t = new Thread(this, "My Thread"); t.start(); } public void run(){ bearing(); } @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); new Camera1(); makeview(); tracking(); } Thanks!

    Read the article

  • Playing .swf file in MediaPlayer?

    - by Omar
    I'm having some issues in playing .swf files on my application. On my PC, using Media Player Classic, they work normally, but on my phone they dont, all I hear is weird sounds.. the code I use to play: mediaplayer = MediaPlayer.create(getBaseContext(), Uri.parse(CurrentAyaSoundPath)); Can anyone tell me why I cant play .swf files normally? Is there another way to play them? Edit1: the .swf are sound only.. no video

    Read the article

  • String doesn't match regex when read from keyboard.

    - by athspk
    public static void main(String[] args) throws IOException { String str1 = "??123456"; System.out.println(str1+"-"+str1.matches("^\\p{InGreek}{2}\\d{6}")); //??123456-true BufferedReader br = new BufferedReader(new InputStreamReader(System.in)); String str2 = br.readLine(); //??123456 same as str1. System.out.println(str2+"-"+str2.matches("^\\p{InGreek}{2}\\d{6}")); //?”??123456-false System.out.println(str1.equals(str2)); //false } The same String doesn't match regex when read from keyboard. What causes this problem, and how can we solve this? Thanks in advance. EDIT: I used System.console() for input and output. public static void main(String[] args) throws IOException { PrintWriter pr = System.console().writer(); String str1 = "??123456"; pr.println(str1+"-"+str1.matches("^\\p{InGreek}{2}\\d{6}")+"-"+str1.length()); String str2 = System.console().readLine(); pr.println(str2+"-"+str2.matches("^\\p{InGreek}{2}\\d{6}")+"-"+str2.length()); pr.println("str1.equals(str2)="+str1.equals(str2)); } Output: ??123456-true-8 ??123456 ??123456-true-8 str1.equals(str2)=true

    Read the article

  • Calling web service from seems to hang

    - by anothershrubery
    I am trying to call an asmx web service from an Android app. Just literally started some Android development today. I've been following various solutions I have found on the net and on here and it seems it is more difficult than anticipated. I have tried various solutions and using KSoap2 seems to be the easiest way to implement this, well it would be if I could get it working. I have the following code which works up until a point: private class CallWebService extends AsyncTask<Void, Void, Void> { private static final String SOAP_ACTION = "http://tempuri.org/GetUser"; private static final String METHOD_NAME = "GetUser"; private static final String NAMESPACE = "http://tempuri.org/"; private static final String URL = "http://160.10.1.79:59315/Service1.asmx"; TextView tv; @Override protected Void doInBackground(Void... params) { tv=(TextView)findViewById(R.id.txtMessage); try { SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet=true; envelope.setOutputSoapObject(request); HttpTransportSE androidHttpTransport = new HttpTransportSE(URL); androidHttpTransport.call(SOAP_ACTION, envelope); Object result = (Object)envelope.getResponse(); tv.setText(result.toString()); } catch (Exception e) { tv.setText(e.getMessage()); } return null; } } It seems to hang at the line androidHttpTransport.call(SOAP_ACTION, envelope); Any ideas why? Is this the correct approach? Should I be looking in another direction?

    Read the article

  • Google Data Api returning an invalid access token

    - by kingdavies
    I'm trying to pull a list of contacts from a google account. But Google returns a 401. The url used for requesting an authorization code: String codeUrl = 'https://accounts.google.com/o/oauth2/auth' + '?' + 'client_id=' + EncodingUtil.urlEncode(CLIENT_ID, 'UTF-8') + '&redirect_uri=' + EncodingUtil.urlEncode(MY_URL, 'UTF-8') + '&scope=' + EncodingUtil.urlEncode('https://www.google.com/m8/feeds/', 'UTF-8') + '&access_type=' + 'offline' + '&response_type=' + EncodingUtil.urlEncode('code', 'UTF-8') + '&approval_prompt=' + EncodingUtil.urlEncode('force', 'UTF-8'); Exchanging the returned authorization code for an access token (and refresh token): String params = 'code=' + EncodingUtil.urlEncode(authCode, 'UTF-8') + '&client_id=' + EncodingUtil.urlEncode(CLIENT_ID, 'UTF-8') + '&client_secret=' + EncodingUtil.urlEncode(CLIENT_SECRET, 'UTF-8') + '&redirect_uri=' + EncodingUtil.urlEncode(MY_URL, 'UTF-8') + '&grant_type=' + EncodingUtil.urlEncode('authorization_code', 'UTF-8'); Http con = new Http(); Httprequest req = new Httprequest(); req.setEndpoint('https://accounts.google.com/o/oauth2/token'); req.setHeader('Content-Type', 'application/x-www-form-urlencoded'); req.setBody(params); req.setMethod('POST'); Httpresponse reply = con.send(req); Which returns a JSON array with what looks like a valid access token: { "access_token" : "{access_token}", "token_type" : "Bearer", "expires_in" : 3600, "refresh_token" : "{refresh_token}" } However when I try and use the access token (either in code or curl) Google returns a 401: curl -H "Authorization: Bearer {access_token}" https://www.google.com/m8/feeds/contacts/default/full/ Incidentally the same curl command but with an access token acquired via https://code.google.com/oauthplayground/ works. Which leads me to believe there is something wrong with the exchanging authorization code for access token request as the returned access token does not work. I should add this is all within the expires_in time frame so its not that the access_token has expired

    Read the article

  • Determining if a coordinate is on a line

    - by TGCBraun
    I´m coding a little app that allows the user to draw multiple shapes and then remove or resize them. It´s working perfectly on rectangles and ovals, but I´m having issues with lines. Here´s a method that I wrote to find if the clicked spot on the screen is part of a specific line: public boolean containsLocation(int x, int y) { int m = (getY2() - getY()) / (getX2() - getX()); int b = getY() - (m * getX()); if (y == (m * x) + b) { return true; } return false; I´m using the famous y = mx + b formula and replacing y and x to find if the clicked spot is part of the line. The problem is when I click on the screen to remove the line, it only works if I click on the very fist coordinate (x,y) where the line starts. Nothing happens when I click anywhere else along the line. Can anyone shed a light on what I´m doing wrong? Thanks a lot.

    Read the article

  • JSF SelectOneMenuItem onselect attribute

    - by William
    I have created selectOneMenuItem(JSF).I placed my events on valueChangeListener / onchange like that <h:selectOneMenu id="ddl" value="#{Foo.attr}" onchange="submit()" valueChangeListener="#{Foo.renderFoo}"> When I select one vlaue from selectOneMenuItem then event fires.Now when I reselect that value ,then event doesn't fire (because this is the valueChangeListener event) so it doesn't fire.I want that event should fire on every selection even on again the same selection.I found onselect but unable to find that is it right and how can i use this onselect.Anyu help would be greatly appreciable

    Read the article

  • This code is not submitting to a form? Why

    - by Ankur
    Since I am using get I expect to see the submitted values appended to the queryString but instead all I see is the URL of the servlet being called with nothing added at the end. <form id="editClassList" name="editClassList" method="get" action="EditClassList"> <% HashMap<Integer,String> classes = new HashMap<Integer,String>(); classes = (HashMap<Integer,String>) request.getAttribute("classes"); %> <% if(classes.size()==0){ %> <label><input class="small-link" type="text" id="add-this-class" size="42" value="" /></label> <% } %> <% Set<Integer> classIds = new HashSet<Integer>(); classIds = classes.keySet(); Iterator<Integer> itr = classIds.iterator(); while(itr.hasNext()){ int nextId = (Integer)itr.next(); %> <label><input class="small-link" type="text" id="<% out.print(nextId); %>" size="42" value="<% out.print(classes.get(nextId)); %>" /> </label> <img id="add-class" src="images/add.png" width="16" height="16" /><br /> <label><input class="small-link" type="text" id="class-to-add" size="42" value="" /></label> <% } %> <label><input type="submit" id="save-class-btn" value="Save Class(es)" /></label> </form>

    Read the article

  • Loading child entities with JPA on Google App Engine

    - by Phil H
    I am not able to get child entities to load once they are persisted on Google App Engine. I am certain that they are saving because I can see them in the datastore. For example if I have the following two entities. public class Parent implements Serializable{ @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String key; @OneToMany(cascade=CascadeType.ALL) private List<Child> children = new ArrayList<Child>(); //getters and setters } public class Child implements Serializable{ @Id @GeneratedValue(strategy = GenerationType.IDENTITY) @Extension(vendorName="datanucleus", key="gae.encoded-pk", value="true") private String key; private String name; @ManyToOne private Parent parent; //getters and setters } I can save the parent and a child just fine using the following: Parent parent = new Parent(); Child child = new Child(); child.setName("Child Object"); parent.getChildren().add(child); em.persist(parent); However when I try to load the parent and then try to access the children (I know GAE lazy loads) I do not get the child records. //parent already successfully loaded parent.getChildren.size(); // this returns 0 I've looked at tutorial after tutorial and nothing has worked so far. I'm using version 1.3.3.1 of the SDK. I've seen the problem mentioned on various blogs and even the App Engine forums but the answer is always JDO related. Am I doing something wrong or has anyone else had this problem and solved it for JPA?

    Read the article

  • Error in my web.xml

    - by Mercer
    Why i have an error in my web.xml when i want add servlet..? <servlet> <servlet-name>ClientServlet</servlet-name> <servlet-class>org.task.ClientServlet</servlet-class> <servlet-name>FactoryServlet</servlet-name> <servlet-class>org.task.FactoryServlet</servlet-class> <servlet-name>TraderServlet</servlet-name> <servlet-class>org.task.TraderServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>ClientServlet</servlet-name> <url-pattern>/ClientServlet</url-pattern> <servlet-name>FactoryServlet</servlet-name> <url-pattern>/FactoryServlet</url-pattern> <servlet-name>TraderServlet</servlet-name> <url-pattern>/TraderServlet</url-pattern> </servlet-mapping>

    Read the article

  • Can Tomcat provide seperate (or HTTPS only) sessions for HTTPS requests?

    - by Joe
    I have a web application which contains both secure (SSL) and non-secure pages. A user can login to the site and must appear logged-in in both the SSL and non-SSL areas. (NB. SSL isn't implemented via Tomcat, but via Apache HTTPD servers which sit in front of Tomcat - so Tomcat has no SSL configuration.) The logged-in state is currently maintained via a servlet session (using Tomcat's vanilla session management). The obvious issue with this approach is that the JSESSIONID cookie is transported over both HTTP and HTTPS connections, meaning that it's potentially possible to intercept it and hijack the session. Are there any solutions to this without rolling our own session management (i.e. does Tomcat cater for this situation)? I'm prepared to implement our own session management, but don't want to reinvent something that may already be supported.

    Read the article

  • Why does the android emulator camera stop unexpectedly?

    - by user490074
    I am using Android 2.2 (API Level 8). The camera is enabled in the manifest. When I try the camera icon provided by the emulator model, it runs for a few seconds showing a gray box moving around a black and white checkerboard, then dies with the error message: Sorry! The application Camera (process com.android.camera) has stopped unexpectedly. Please try again. Trying again, of course, doesn't help. I am using the provided emulator camera to compare behavior with a camera application I am working on. Why does the android emulator camera stop unexpectedly?

    Read the article

  • Call HashMap from jsp EL ?

    - by Parhs
    Here is my Entity Class public enum UnitType { HOSPITAL, HEALTHCENTER } public static LinkedHashMap<UnitType, String> unitType = new LinkedHashMap<UnitType, String>() { { put(UnitType.HEALTHCENTER, "???t?? ??e?a?"); put(UnitType.HOSPITAL, "??s???µe??"); } }; @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Long id; private String name; private String address; @Column(columnDefinition = "TEXT") private String info; @Enumerated(EnumType.STRING) private UnitType type; At my jsp <c:forEach var="unit" items="${requestScope.units}"> <tr> <td>${unit.id}</td> <td>${unit.name}</td> <td>${unit.address}</td> <td>??!?</td> <td><a href="#">?e??ss?te?a</a></td> </tr> </c:forEach> How can i place the text value of the enum at ??!? .. Any idea? Tried some ways but nothing worked..

    Read the article

  • prefix and postfix increments while comparing variables

    - by miatech
    could someone explain why this code output is not equals not equals 2 in the first if statement it seems that a = 0 b/c is a postfix increment; therefore a will not increase untile next line; however, the two a's are not equal why? and in the second if when I run the debugger the value of a is 2, but the test is false, why? public static void main (String[] args) { int a = 0; if (a++ == a++) { System.out.println("equals"); } else { System.out.println("not equals"); } if (++a == 2) { System.out.println("equals 2"); } else { System.out.println("not equals 2"); } }

    Read the article

  • delete everything before last comma

    - by clankill3r
    I want to delete everything before the last tab (or comma). For example, in this sentence: Hoe treedt een gevestigd instituut als het Nederlands Openluchtmuseum, alom geassocieerd met ambacht en traditie, buiten zijn grenzen op zoek naar vernieuwing? should be naar vernieuwing? Ik heb ruim 6 weken geleden een boek besteld en ik wacht nog steeds,enig idee hoe lang dit wachten nog gaat duren? should be enig idee hoe lang dit wachten nog gaat duren? I tried this, "^(.*\t+)+" but that doesn't work.

    Read the article

  • Is ArrayList.size() method cached?

    - by Peterdk
    I was wondering, is the size() method that you can call on a existing ArrayList<T> cached? Or is it preferable in performance critical code that I just store the size() in a local int? I would expect that it is indeed cached, when you don't add/remove items between calls to size(). Am I right?

    Read the article

  • Redeclaration of parameters

    - by Scott
    While looking through the Selenium source code I noticed the following in the PageFactory: public static <T> T initElements(WebDriver driver, Class<T> pageClassToProxy) { T page = instantiatePage(driver, pageClassToProxy); initElements(driver, page); return page; } public static void initElements(WebDriver driver, Object page) { final WebDriver driverRef = driver; initElements(new DefaultElementLocatorFactory(driverRef), page); } What is the benefit of having the following line? final WebDriver driverRef = driver; Wouldn't it have made sense to just make the parameter final, and then passing that along to the next method without declaring the new reference?

    Read the article

< Previous Page | 902 903 904 905 906 907 908 909 910 911 912 913  | Next Page >