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  • ASP.NET MVC - Form Post always redirect when I just want to bind json result to a div

    - by Saxman
    Hi all, I'm having a little problem with json result. I'm submitting a contact form, and after the submission, I just want to return some json data (indicating either a success or failed and displays a message) back to the view, without causing a redirect, but it kept redirecting me to the action, here are the codes: HTML <div id="contactForm2" class="grid_6"> <div id="contactFormContainer"> @using (Html.BeginForm(MVC.Home.ActionNames.ContactForm, MVC.Home.Name, FormMethod.Post, new { id = "contactForm" })) { <p> <input type="text" tabindex="1" size="22" value="" id="contactName" class="text_input required" name="contactName" /> <label for="contactName"> <strong class="leftSpace">Your Name (required)</strong></label></p> <p> <input type="text" tabindex="2" size="22" value="" id="contactEmail" class="text_input required" name="contactEmail" /> <label for="contactEmail"> <strong class="leftSpace">Email (required)</strong></label></p> <p> <input type="text" tabindex="2" size="22" value="" id="contactPhone" class="text_input" name="contactPhone" /> <label for="contactPhone"> <strong class="leftSpace">Phone</strong></label></p> <p> <label> <strong class="leftSpace n">Message (required)</strong></label> <textarea tabindex="4" rows="4" cols="56" id="contactMessage" class="text_area required" name="contactMessage"></textarea></p> <p> <input type="submit" value="Send" tabindex="5" id="contactSubmit" class="button submit" name="contactSubmit" /></p> } </div> <div id="contactFormStatus"> </div> </div> Controller [HttpPost] public virtual JsonResult ContactForm(FormCollection formCollection) { var name = formCollection["contactName"]; var email = formCollection["contactEmail"]; var phone = formCollection["contactPhone"]; var message = formCollection["contactMessage"]; if (string.IsNullOrEmpty(name) || string.IsNullOrEmpty(email) || string.IsNullOrEmpty(message)) { return Json(new { success = false, message = "Please complete all the required fields so that I can get back to you. Thanks." }); } // Insert contact form data here... return Json(new { success = true, message = "Your inquery has been sent. Thank you." }); } javascript $(document).ready(function () { $('#contactSubmit').live('click', function () { var form = $('#contactForm'); var formData = form.serialize(); $.post('/Home/ContactForm', formData, function (result) { var status = $('#contactFormStatus'); if (result.success) { $('#contactForm')[0].reset; } status.append(result.message); }, 'json' ); return false; }); }); I've also tried this javascript, but also got a redirect $(document).ready(function () { $('#contactSubmit').live('click', function () { var form = $('#contactForm'); var formData = form.serialize(); $.ajax({ type: 'POST', url: '/Home/ContactForm', data: formData, success: function (result) { SubmitContactResult(result); }, cache: false }); }); function SubmitContactResult(result) { var status = $('#contactFormStatus'); if (result.success) { $('#contactForm')[0].reset; } status.append(result.message); } }); Any idea what's going on with my code? Thank you very much.

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  • Can I add a portrait layout on top of a landscape Camera SurfaceView?

    - by Uwe Krass
    My application should hold a camera preview surface. The camera is fixed to landscape view via AndroidMainfest.xml <application android:icon="@drawable/icon" android:label="Camera"> <uses-library android:name="com.google.android.maps" /> <uses-feature android:name="android.hardware.camera" /> <uses-feature android:name="android.hardware.camera.autofocus" /> <activity android:name=".CameraPreview" android:label="Camera" android:screenOrientation="landscape"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> If there is another way to get the camera preview itself to behave correctly, please let me know. Now I need to have an overlay that holds a bunch of buttons. Due to usability, the user interface should be set to portrait view (or even better orientation aware). Is there a way to have a transparent layout (for buttons and other GUI elements) in portrait orientation? I tried to write a special rotated layout by extending a RelativeLayout, but the onDraw method isn't called at anytime. public class RotatedOverlay extends RelativeLayout { private static final String TAG = "RotatedOverlay"; public RotatedOverlay(Context context, AttributeSet attrs ) { super(context, attrs); } @Override protected void onDraw(Canvas canvas) { canvas.rotate(90); super.onDraw(canvas); } I am quite new to the Android plattform programming. Of course I dont know much about the programming tricks and workarounds yet. I did a lot of research over the last two weeks (even studied the native Camera implementation), but couldnt find a good solution so far. Maybe it works with two seperate Activities, but I dont think, that this can the right solution.

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  • Does Hibernate always need a setter when there is a getter?

    - by Marcus
    We have some Hibernate getter methods annotated with both @Column and @Basic. We get an exception if we don't have the corresponding setter. Why is this? In our case we are deriving the value returned from the getter (to get stored in the DB) and the setter has no functional purpose. So we just have an empty method to get around the error condition..

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  • jQuery rotator not rotating properly - too much recursion

    - by Matt Nathanson
    I've built a custom jQuery rotator using just basic animation to rotate the 3 Divs (images). I've built the function and then reinitiate the function using it as a call back. Here's the code: function ImageRotate() { var CurrentFeature = "#container" + featureNumber; $(CurrentFeature).stop(false, true).delay(4500).animate({'top' : '330px'}, 3000); var featureNumber2 = featureNumber-1; if ( featureNumber == 1) {featureNumber2=3} var CurrentFeature2 = "#container" + featureNumber2; $(CurrentFeature2).stop(false, true).delay(4500).animate({'top' : '0px'}, 3000); $('#container2').stop(false, true).delay(4500).animate({'top' : '-330px'}, 25); var featureNumber3 = featureNumber+1; if ( featureNumber == 3){featureNumber3=1} var CurrentFeature3 = "#container" + featureNumber3; $(CurrentFeature3).stop(false, true).delay(7500).animate({'top' : '0px'}, 3000); $(CurrentFeature2).stop(false, true).delay(4500).animate({'top' : '330px'}, 3000); $(CurrentFeature).stop(false, true).delay(4500).animate({'top' : '-330px'}, 25); if (featureNumber ==1) {featureNumber=3} else{featureNumber--}; $(CurrentFeature).stop(false, true).delay(7500).animate({'top' : '0px'}, 3000); $(CurrentFeature3).stop(false, true).delay(4500).animate({'top' : '330px'}, 3000); $(CurrentFeature2).stop(false, false).delay(4500).animate({'top' : '-330px'}, 25,ImageRotate()); }; It's worth noting that when calling the function again I also tried making another function called ImageRotate2(); and it did the same thing. It loops, but i get all sorts of funkiness. Edit: I've also tried some answers in the replies and they both leave me with recursion errors each second.

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  • Adding a div layer on top of a jquery carousel. Tough one.

    - by wilwaldon
    Hey everyone, I have a tough one, well it's tough for me because I'm kinda new to the whole jQuery carousel thing, never built one before this project. Here's my problem. If you go to the TEST SITE you will see a scroller with a blue background about half way down the page. If you mouse onto the "data analytics" slide you should see a black box fade in. Here is my dilemma. I want that black box to be a menu that's connected to the data analytics slide. I've done a mock up for you so you can see what I'm talking about. Here is my scroller code. I'm using jCarousel. <div class="carousel"> <ul> <li> <div id="homeslide1"> testers sdfasdfasdfas asdftjhs iasndkad kasdnf <a href="#" id="#homeslide1-toggle">Close this</a> </div> <a href="#" id="homeslide1-show"><img src="<?php bloginfo('template_url'); ?>/images/home_data_analytics.jpg" width="200" height="94" /></a> </li> <li><img src="<?php bloginfo('template_url'); ?>/images/home_oem_partnerships.jpg" width="200" height="94" /></li> <li><img src="<?php bloginfo('template_url'); ?>/images/home_reporting.jpg" width="200" height="92" /></li> <li><img src="<?php bloginfo('template_url'); ?>/images/home_returning_lost_customers.jpg" width="200" height="92" /></li> <li><img src="<?php bloginfo('template_url'); ?>/images/home_sales.jpg" width="200" height="92" /></li> <li><img src="<?php bloginfo('template_url'); ?>/images/home_service_retention.jpg" width="200" height="92" /></li> </ul> Here is my scroller css /*HOMEPAGE SCROLLER*/ .carousel {!important padding:10px; width: 890px; margin: 0px 0px 0px 26px;} .carousel ul li element.style{height: 94px;} .carousel ul{width: 200px; padding: 5px;} .carouselitem{height: 94px;} .prev{background: url(images/home_left_scroll.png); height: 94px; width: 16px; text-indent: -999px; outline: none; cursor:pointer; float: left;} .next{background: url(images/home_right_scroll.png); height: 94px; width: 16px; text-indent: -999px; outline: none; cursor:pointer; float: right;} .carousel ul li{ padding: 0px 3px 0px 3px; margin: 0px; height:!important 94px; } .home_right_arrow{ width: 16px; float: right;} .home_left_arrow{ width: 16px; float: left;} .homeslide1{ width: 200px; height: 94px;} I've tried all sorts of z-index tricks but can't seem to figure it out on my own. If you solve this riddle I'll buy you a beer if we ever meet up. I'll also give you a high five through the internet. Is there a simple way to do this via jQuery? If so could you point me in the right direction? Thanks so much.

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  • Is Work Stealing always the most appropriate user-level thread scheduling algorithm?

    - by Il-Bhima
    I've been investigating different scheduling algorithms for a thread pool I am implementing. Due to the nature of the problem I am solving I can assume that the tasks being run in parallel are independent and do not spawn any new tasks. The tasks can be of varying sizes. I went immediately for the most popular scheduling algorithm "work stealing" using lock-free deques for the local job queues, and I am relatively happy with this approach. However I'm wondering whether there are any common cases where work-stealing is not the best approach. For this particular problem I have a good estimate of the size of each individual task. Work-stealing does not make use of this information and I'm wondering if there is any scheduler which will give better load-balancing than work-stealing with this information (obviously with the same efficiency). NB. This question ties up with a previous question.

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  • Can I Always debug multiple instances of a same object that is of type thread with GDB?

    - by yan bellavance
    program runs fine. When I put a breakpoint a segmentation fault is generated. Is it me or GDB? At run time this never happens and if I instantiate only one object then no problems. Im using QtCreator on ubuntu x86_64 karmic koala. UPDATE1: I have made a small program containing a simplified version of that class. You can download it at: example program simply put a breakpoint on the first line of the function called drawChart() and step into to see the segfault happen UPDATE2: This is another small program but it is practically the same as the mandlebrot example and it is still happening. You can diff it with mandlebrot to see the small difference. almost the same as mandlebrot example program

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  • Did we always have to register to download the Java 5 JDK, or is this new Oracle fun?

    - by Ukko
    I could swear that just a couple of months ago I downloaded a copy of the Java 1.5 SE JDK and I did not have to give them information on my first born. Today, I had to go through the register-and-we-will-send-you-a-link-someday dance. I have not received the link yet, so I thought I would ask about it here. What is special about the Java 5 JDK? I can get 6 just by clicking, is this a stick to get us to migrate to Java 6? Am I just not remembering doing this before? What marketing genius thought this would be a value add for Java? "If we make them sweat for the JDK they won't just delete it willy-nilly the next time?" Does everyone picture the people designing systems like this as mustache twirling Snidely Whiplash clones like I do? Did I just miss the link for the Secret Squirrel route to the download page? Finally, I am in the U.S. so I should not have to worry about export restrictions. Any thoughts?

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  • how to develop domain specific language on top of another language ?

    - by sofreakinghigh
    say i found a good open source software/library written in python. i want to wrap some of the functions or methods that i have created into easy to understand language of my own. do porter_stemm(DOC) (the DSL) would be equivalent to the function or series of methods written in python. i want to create a DSL that is easy to learn, but need this DSL translated into the original open source software software. im not sure if i am clear here but my intention is: create an easy to learn code language that users can use to solve a problem in a certain niche. this simple language needs to be translated or compiled or interpretated via some middleware into the original open source software's language (python).

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  • Are Java GUIs always slow to update or is it just me?

    - by ChrisD
    I've just started making my first GUI application in Java and I decided to use the NetBeans IDE to do it. I think its working fine so far, except for one problem; it seems to be slow updating the content of a window. Even in very simple windows with few controls I find that when - for example - closing or resizing a window, I get the normal window border working properly but the inside is completely see through for a second. It's not the biggest deal in the world, I just find it mildly annoying.

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  • Why increased pipeline depth does not always mean increased throughput?

    - by worlds-apart89
    This is perhaps more of a discussion question, but I thought stackoverflow could be the right place to ask it. I am studying the concept of instruction pipelining. I have been taught that a pipeline's instruction throughput is increased once the number of pipeline stages is increased, but in some cases, throughput might not change. Under what conditions, does this happen? I am thinking stalling and branching could be the answer to the question, but I wonder if I am missing something crucial.

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  • Query to retrieve records by aplhabetic order, except for n predefined items which must be on top

    - by Ashraf Bashir
    I need to retrieve all records ordered alphabetically. Except for a predefined list of record's columns which their records should appear first in a given predefined order, then all other records should be sorted alphabetically based on the same column For instance, assume we have the following table which is called Names Lets assume the predefined list is ("Mathew", "Ashraf", "Jack"). I.e. these are the names of whom their records should be listed first as in the predefined order. So the desired query result should be: Which query could retrieve this custom order ? P.S, I'm using MySQL. Here's my trial based on comments' request: (SELECT * FROM Names WHERE Name in ('Mathew', 'Ashraf', 'Jack')) UNION (SELECT * FROM Names WHERE Name NOT IN ('Mathew', 'Ashraf', 'Jack') ORDER BY Name ASC); the first query result wasn't ordered as required.

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  • How to override inner class methods if the inner class is defined as a property of the top class

    - by Maddy
    I have a code snippet like this class A(object): class b: def print_hello(self): print "Hello world" b = property(b) And I want to override the inner class b (please dont worry about the lowercase name) behaviour. Say, I want to add a new method or I want to change an existing method, like: class C(A): class b(A.b): def print_hello(self): print "Inner Class: Hello world" b = property(b) Now if I create C's object as c = C(), and call c.b I get TypeError: 'property' object is not callable error. How would I get pass this and call print_hello of the extended inner class? Disclaimer: I dont want to change the code for A class.

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  • PPTP VPN connection always connects successfully in Mac OS X/windows but drops after 2 minute in iPad or it doesn't connect al all!

    - by Farshid
    Dear Users, I've a big problem with using iPad's VPN connection. When I use the same VPN connection (PPTP) configuration parameters in my Mac OS X Snow Leopard or my windows XP (Bootcamp), it works flawlessly but when I define the same connection in my iPad, connection drops in about 1 or 2 minutes (some times) and most of the time, it Doesn't Connect at all. I'm using iPad 3G with iOS 4.2.1 and my iPad is not jail-broken. I've tried so hard to make it work in an stable manner but not found any solution yet. (I should have put encryption level to No-Encryption in Mac and Windows otherwise it won't connect in my desktop operating systems. It is a host-related issue and I'm binding to that). I'm sure there is no technical problem in my iPad's hardware and this problem also exists in my friend's iPad too. Our devices work perfectly with 3G and Wifi connections. Your answers are really appreciated.

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  • How to sort a list so that managers are always ahead of their subordinates (How do I do a topologica

    - by James Black
    I am working on a project using Groovy, and I would like to take an array of employees, so that no manager follows their subordinates in the array. The reason being that I need to add people to a database and I would prefer not to do it in two passes. So, I basically have: <employees> <employee> <employeeid>12</employeeid> <manager>3</manager> </employee> <employee> <employeeid>1</employeeid> <manager></manager> </employee> <employee> <employeeid>3</employeeid> <manager>1</manager> </employee> </employees> So, it should be sorted as such: employeeid = 1 employeeid = 3 employeeid = 12 The first person should have a null for managers. I am thinking about a binary tree representation, but I expect it will be very unbalanced, and I am not certain the best way to do this using Groovy properly. Is there a way to do this that isn't going to involve using nested loops?

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  • Can a binary tree or tree be always represented in a Database table as 1 table and self-referencing?

    - by Jian Lin
    I didn't feel this rule before, but it seems that a binary tree or any tree (each node can have many children but children cannot point back to any parent), then this data structure can be represented as 1 table in a database, with each row having an ID for itself and a parentID that points back to the parent node. That is in fact the classical Employee - Manager diagram: one boss can have many people under him... and each person under him can have n people under him, etc. This is a tree structure and is represented in database books as a common example as a single table Employee.

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  • How to find out top links in a website?

    - by Anil
    I want to know what are the best links in a site are? It may be pagerank wise or popularity wise. For example http://www.pragprog.com is a site. I want to find out what are the most relevant links this site has. The links should not be external pointing links. It should be of the same site. Do google or any similar site can tell such information?

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  • How can a WPF StackPanel fill vertically from bottom to top?

    - by Stimul8d
    I need to be able to fill a stackpanel with buttons but the buttons must appear at the bottom of the stackpanel first and populate upwards. The buttons are created dynamically and there's an unknown number of them so visual hackery just won't work. I've tried experimenting with vertical alignments but to no avail. Thanks in advance.

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