Search Results

Search found 3977 results on 160 pages for 'filename'.

Page 91/160 | < Previous Page | 87 88 89 90 91 92 93 94 95 96 97 98  | Next Page >

  • Nginx proxy to s3 bucket gets 400 Invalid Argument

    - by elssar
    I have a Django app in which I serve media files through an nginx proxy to s3. The relevant python code response = HttpResponse() response['X-Accel-Redirect'] = '/s3_redirect/%s' % filefield.url.replace('http://', '') response['Content-Disposition'] = 'attachment; filename=%s' % filefield.name return response The nginx block for the internal redirect is location ~* ^/s3_redirect/(.*) { internal; set $full_url http://$1; proxy_pass $full_url; And the request logged by s3 is. REST.GET.OBJECT <media file> "GET <media file>" 400 InvalidArgument 354 - 4 - "http://<referer>" "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_8_3) AppleWebKit/537.1 (KHTML, like Gecko) Chrome/21.0.1180.89 Safari/537.1" - I, for the life of me, can't figure out what's wrong. The url send to nginx by the app is valid, it works in the browser. And nginx is sending a request to s3.

    Read the article

  • How do I run a beanshell script on my Mac?

    - by jonalv
    My Ubuntu-friend told me to testrun a Beanshell script by doing: bsh #filename# and when I told him that I don't know what bsh is nor have it he told me: sudo apt-get install bsh Being on a Mac I instead ran: sudo port install beanshell But still no bsh command available. A listing of the package content revealed a jar file named: /opt/local/share/java/bsh.jar but when I try to run that with my script file a complete Window manager written in Java starts up (and does not run the script file btw). Now, clearly I am doing something wrong, I am sure there must be a way of running beanshell scripts on a mac terminal although it does seem more natural for the linux users. What am I doing wrong and what should I do to run that script?

    Read the article

  • How to block own rpcap traffic where tshark is running?

    - by Pankaj Goyal
    Platform :- Fedora 13 32-bit machine RemoteMachine$ ./rpcapd -n ClientMachine$ tshark -w "filename" -i "any interface name" As soon as capture starts without any capture filter, thousands of packets get captured. Rpcapd binds to 2002 port by default and while establishing the connection it sends a randomly chosen port number to the client for further communication. Both client and server machines exchange tcp packets through randomly chosen ports. So, I cannot even specify the capture filter to block this rpcap related tcp traffic. Wireshark & tshark for Windows have an option "Do not capture own Rpcap Traffic" in Remote Settings in Edit Interface Dialog box. But there is no such option in tshark for linux. It will be also better if anyone can tell me how wireshark blocks rpcap traffic....

    Read the article

  • apc.stat causes 500 internal server error

    - by Legit
    When I turn off apc.stat it causes a 500 internal server error. I checked the apache error_log and it's something about: [Tue Jun 26 10:02:59 2012] [error] [client 127.0.0.1] PHP Warning: require(): Filename cannot be empty in /var/www/site1/public/index.php on line 17 [Tue Jun 26 10:02:59 2012] [error] [client 127.0.0.1] PHP Fatal error: require(): Failed opening required '' (include_path='.:/usr/share/pear:/usr/share/php') in /var/www/site1/public/index.php on line 17 I checked that line and here's what it contains: require('./wp-blog-header.php'); I don't see anything wrong with it. Here's my current APC config: APC version: 3.1.10 PHP Version: 5.4.4 How do I resolve this error when i disable apc.stat?

    Read the article

  • Mass renaming, *nix version

    - by Paolo B.
    I was looking for a way to rename a huge number of similarly-named files, much like this one (a Windows-related question) except that I'm using *nix (Ubuntu and FreeBSD, separately). Just to sum up, while using the shell (Bash, CSH, etc.) how do I mass-rename a number of files such that, for example, the following files: Beethoven - Fur Elise.mp3 Beethoven - Moonlight Sonata.mp3 Beethoven - Ode to Joy.mp3 Beethoven - Rage Over the Lost Penny.mp3 will be renamed like these? Fur Elise.mp3 Moonlight Sonata.mp3 Ode to Joy.mp3 Rage Over the Lost Penny.mp3 The reason I want to do this is that these collection of files will go under a directory named "Beethoven" (i.e. the filenames' prefix), and having this information on the filename itself will be redundant.

    Read the article

  • non-interactively upload file to sftp server, using password

    - by matt
    Hello Guys, I know, this is not the recommended way to do this. But, I do not have another choice: I've got to set up a cron job that will regularly upload a file to an external SFTP Server (no FTP available, and I do only have a username/password for it but no key.) Still, I need to set up a cron that will regularly connect to that sftp and upload a file. sftp <<EOF put filename exit EOF therefore will not work, because sftp asks for the password, before STDIN is evaluated. What can I do, to pass the Password to sftp? Again: I am aware of the potential security risk, but I really do not have any choice here, and the server from which the file is uploaded is protected rather well.

    Read the article

  • error LNK2019 for ZLib sample code compiling.

    - by Nano HE
    Hello. I created win32 console application in vs2010 (without select the option of precompiled header). And I inserted the code below. but *.obj link failed. Could you provide me more information about the error. I searched MSDN, but still can't understand it. #include <stdio.h> #include "zlib.h" // Demonstration of zlib utility functions unsigned long file_size(char *filename) { FILE *pFile = fopen(filename, "rb"); fseek (pFile, 0, SEEK_END); unsigned long size = ftell(pFile); fclose (pFile); return size; } int decompress_one_file(char *infilename, char *outfilename) { gzFile infile = gzopen(infilename, "rb"); FILE *outfile = fopen(outfilename, "wb"); if (!infile || !outfile) return -1; char buffer[128]; int num_read = 0; while ((num_read = gzread(infile, buffer, sizeof(buffer))) > 0) { fwrite(buffer, 1, num_read, outfile); } gzclose(infile); fclose(outfile); } int compress_one_file(char *infilename, char *outfilename) { FILE *infile = fopen(infilename, "rb"); gzFile outfile = gzopen(outfilename, "wb"); if (!infile || !outfile) return -1; char inbuffer[128]; int num_read = 0; unsigned long total_read = 0, total_wrote = 0; while ((num_read = fread(inbuffer, 1, sizeof(inbuffer), infile)) > 0) { total_read += num_read; gzwrite(outfile, inbuffer, num_read); } fclose(infile); gzclose(outfile); printf("Read %ld bytes, Wrote %ld bytes, Compression factor %4.2f%%\n", total_read, file_size(outfilename), (1.0-file_size(outfilename)*1.0/total_read)*100.0); } int main(int argc, char **argv) { compress_one_file(argv[1],argv[2]); decompress_one_file(argv[2],argv[3]);} Output: 1>------ Build started: Project: zlibApp, Configuration: Debug Win32 ------ 1> zlibApp.cpp 1>d:\learning\cpp\cppvs2010\zlibapp\zlibapp\zlibapp.cpp(15): warning C4996: 'fopen': This function or variable may be unsafe. Consider using fopen_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS. See online help for details. 1> c:\program files\microsoft visual studio 10.0\vc\include\stdio.h(234) : see declaration of 'fopen' 1>d:\learning\cpp\cppvs2010\zlibapp\zlibapp\zlibapp.cpp(25): warning C4996: 'fopen': This function or variable may be unsafe. Consider using fopen_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS. See online help for details. 1> c:\program files\microsoft visual studio 10.0\vc\include\stdio.h(234) : see declaration of 'fopen' 1>d:\learning\cpp\cppvs2010\zlibapp\zlibapp\zlibapp.cpp(40): warning C4996: 'fopen': This function or variable may be unsafe. Consider using fopen_s instead. To disable deprecation, use _CRT_SECURE_NO_WARNINGS. See online help for details. 1> c:\program files\microsoft visual studio 10.0\vc\include\stdio.h(234) : see declaration of 'fopen' 1>d:\learning\cpp\cppvs2010\zlibapp\zlibapp\zlibapp.cpp(36): warning C4715: 'decompress_one_file' : not all control paths return a value 1>d:\learning\cpp\cppvs2010\zlibapp\zlibapp\zlibapp.cpp(57): warning C4715: 'compress_one_file' : not all control paths return a value 1>zlibApp.obj : error LNK2019: unresolved external symbol _gzclose referenced in function "int __cdecl decompress_one_file(char *,char *)" (?decompress_one_file@@YAHPAD0@Z) 1>zlibApp.obj : error LNK2019: unresolved external symbol _gzread referenced in function "int __cdecl decompress_one_file(char *,char *)" (?decompress_one_file@@YAHPAD0@Z) 1>zlibApp.obj : error LNK2019: unresolved external symbol _gzopen referenced in function "int __cdecl decompress_one_file(char *,char *)" (?decompress_one_file@@YAHPAD0@Z) 1>zlibApp.obj : error LNK2019: unresolved external symbol _gzwrite referenced in function "int __cdecl compress_one_file(char *,char *)" (?compress_one_file@@YAHPAD0@Z) 1>D:\learning\cpp\cppVS2010\zlibApp\Debug\zlibApp.exe : fatal error LNK1120: 4 unresolved externals ========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========

    Read the article

  • Add a record to relational XML with C#

    - by Megawolt
    I have a XML and XSD I want to add a record to trck table with Dataset i'm also write that code but need trackListrow... how can i handle that? playListDS rec = new playListDS(); if(File.Exists(Server.MapPath("~/playlist.xml"))) rec.ReadXml(Server.MapPath("~/playlist.xml")); int id = int.Parse(rec.track.Rows[rec.track.Rows.Count - 1][0].ToString()) + 1; if (ViewState["Filename"] != null && ViewState["Cover"] != null) { playListDS.trackListRow row = new playListDS.trackListRow(); rec.track.AddtrackRow(id.ToString(), "mp3/" + ViewState["Filename"].ToString(), txtartist.Text, txtalbum.Text, txttitle.Text, txtannotation.Text, txtduration.Text, "mp3/cover" + ViewState["Cover"].ToString(), txtinfo.Text, txtlink.Text); <?xml version="1.0"?> <!-- Generated using Flame-Ware Solutions XML-2-XSD v2.0 at http://www.flame-ware.com/Products/XML-2-XSD/ --> <xs:schema id="playListDS" targetNamespace="http://tempuri.org/playListDS.xsd" xmlns:mstns="http://tempuri.org/playListDS.xsd" xmlns="http://tempuri.org/playListDS.xsd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" attributeFormDefault="qualified" elementFormDefault="qualified"> <xs:element name="playListDS" msdata:IsDataSet="true" msdata:UseCurrentLocale="true"> <xs:complexType> <xs:choice minOccurs="0" maxOccurs="1"> <xs:element name="trackList"> <xs:complexType> <xs:sequence> <xs:element name="track" minOccurs="0" maxOccurs="unbounded"> <xs:complexType> <xs:sequence> <xs:element name="FileID" type="xs:string" minOccurs="0" /> <xs:element name="location" type="xs:string" minOccurs="0" /> <xs:element name="creator" type="xs:string" minOccurs="0" /> <xs:element name="album" type="xs:string" minOccurs="0" /> <xs:element name="title" type="xs:string" minOccurs="0" /> <xs:element name="annotation" type="xs:string" minOccurs="0" /> <xs:element name="duration" type="xs:string" minOccurs="0" /> <xs:element name="image" type="xs:string" minOccurs="0" /> <xs:element name="info" type="xs:string" minOccurs="0" /> <xs:element name="link" type="xs:string" minOccurs="0" /> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:choice> </xs:complexType> </xs:element> </xs:schema> <?xml version="1.0" standalone="yes"?> <playListDS xmlns="http://tempuri.org/playListDS.xsd"> <trackList> <track> <FileID>6</FileID> <location>mp3/Gomez - See The World-1.mp3</location> <creator>Gomez</creator> <album>How We Operate</album> <title>See the World</title> <annotation>Buraya kendi yorumun gelicek bos kalabilir</annotation> <duration>243670</duration> <image>mp3/coverChrysanthemum.jpg</image> <info /> <link>Grubun bi sitesi fln varsa buraya yazabilisin yoksa beni sil</link> </track> </trackList> </playListDS>

    Read the article

  • How To Edit XML File

    - by thebourneid
    I have a movie collection catalogue with local links to folders and files for an easy access. Recently I reorganaized my entire hard disk space and I need to update the links and I'm trying to do that automatically with perl. I can export the data in a xml file and import it again. I can extract the new filepaths with the use of File::Find but I'm stuck with two problems. I have no idea how to connect the $title from the new filepath with the corresponding $title from the xml file. I'm dealing with such files for the first time and I don't know how to proceed with the replacement process. Here is what I've done till now use strict; use warnings; use File::Basename; use File::Find; use File::Spec; use XML::Simple; use Data::Dumper; my $dir_target = 'somepath'; find(\&a, $dir_target); sub a { /\.iso$/ or return; my $fn = $File::Find::name; $fn =~ s/\//\\/g; $fn =~ /(.*\\)(.*)/; my $path = $1; my $filename = $2; my $title = (File::Spec->splitdir($fn))[2]; $title =~ s/(.*?)\s\(\d+\)$/$1/; $title =~ s/~/:/; $title =~ s/`/?/; my $link_local = '<link><description>Folder</description><url>'.$path.'</url><urltype>Movie</urltype></link><link><description>'.$filename.'</description><url>'.$fn.'</url><urltype>Movie</urltype></link>' unless $title eq ''; my $txt = 'somepath/log.txt'; my $xml_in = XMLin('somepath/test.xml', ForceArray => 1, KeepRoot => 1); my $xml_out = XMLout($xml_in, OutputFile => 'somepath/test_out.xml', KeepRoot=>1); open F, ">>", $txt; print F $link_local."\n\n"; close F; } And here is a snippet of the data I need to edit. If found imdb and dvdempire link - do not touch. if found local links replace, otherwise insert. I'm willing to complete the code myself but need some directions how to proceed further. Thanks. <title>$title</title> ....... <links> <link> <description>IMDB</description> <url>http://www.imdb.com/title/VARIABLE</url> <urltype>URL</urltype> </link> <link> <description>DVD Empire</description> <url>http://www.dvdempire.com/VARIABLE</url> <urltype>URL</urltype> </link> <link> <description>Folder</description> <url>OLD_FOLDERPATH</url> <urltype>Movie</urltype> </link> <link> <description>OLD_FILENAME</description> <url>OLD_FILENAMEPATH</url> <urltype>Movie</urltype> </link> </links>

    Read the article

  • Syntax of mac2vlan file in freeradius?

    - by Edik Mkoyan
    below is the content of mac2vlan file in freeradius When I uncomment this 00:01:02:03:04:05,VLAN1 it logs parsing error including configuration file /etc/raddb/modules/mac2vlan /etc/raddb/modules/mac2vlan[10]: Parse error after "00:01:02:03:04:05" Errors reading /etc/raddb/radiusd.conf what is the correct syntax? # -*- text -*- # # $Id$ # A simple file to map a MAC address to a VLAN. # # The file should be in the format MAC,VLAN # the VLAN name cannot have spaces in it, for example: # 00:01:02:03:04:05,VLAN1 # 03:04:05:06:07:08,VLAN2 # ... passwd mac2vlan { filename = ${confdir}/mac2vlan format = "*VMPS-Mac:=VMPS-VLAN-Name" delimiter = "," #}

    Read the article

  • What is AddType application/x-httpd-php-source

    - by egor
    I have the apache2.0, PHP5.2.4 and the directive in the httpd.conf: AddType application/x-httpd-php-source .php .php3 .php4 .php5 .php6 AddType directive is used to maps the given filename extensions onto the specified content type. This is the only meaning of this directive. But why does this method switch off PHP handler, that assigned .php extensions, and I can view source code of scripts in my browser? And another: AddType application/x-httpd-php5 .php Why does this method switch on PHP handler? This simply must send header "Content-Type: application/x-httpd-php5" to my browser and this must be only meaning of directive AddType from mod_mime. I'm confused. Thanks for your replies.

    Read the article

  • Youtube API upload - Incomplete Multipart body error

    - by Blerim J
    Hello, I'm trying to upload videos in Youtube through HttpWebRequest. Everything seems to be fine when uploading following the example given in API documentation. I see that request is being formed correctly, with content and token sent but I receive "Incomplete multipart body" as response. Thanks Blerim public bool YouTubeUpload() { string newLine = "\r\n"; //token and url are retrieved from YouTube at runtime. string token = string.Empty; string url = string.Empty; // construct the command url url = url + "?nexturl=http://www.mywebsite.com/"; // get a unique string to use for the data boundary string boundary = Guid.NewGuid().ToString().Replace("-", string.Empty); foreach (string file in Request.Files) { HttpPostedFileBase hpf = Request.Files[file] as HttpPostedFileBase; if (hpf.ContentLength == 0) continue; // get info about the file and open it for reading Stream fs = hpf.InputStream; HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url); webRequest.ContentType = "multipart/form-data; boundary=" + boundary; webRequest.Method = "POST"; webRequest.KeepAlive = true; webRequest.Credentials = System.Net.CredentialCache.DefaultCredentials; MemoryStream memoryStream = new MemoryStream(); StreamWriter writer = new StreamWriter(memoryStream); //token writer.Write("--" + boundary + newLine); writer.Write("Content-Disposition: form-data; name=\"{0}\"{1}{2}", "token", newLine, newLine); writer.Write(token); writer.Write(newLine); //Video writer.Write("--" + boundary + newLine); writer.Write("Content-Disposition: form-data; name=\"{0}\"; filename=\"{1}\"{2}", "File1", hpf.FileName, newLine); writer.Write("Content-Type: {0}" + newLine + newLine, hpf.ContentType); writer.Flush(); byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes(string.Format("--{0}--{1}", boundary, newLine)); webRequest.ContentLength = memoryStream.Length + fs.Length + boundarybytes.Length; Stream webStream = webRequest.GetRequestStream(); // write the form data to the web stream memoryStream.Position = 0; byte[] tempBuffer = new byte[memoryStream.Length]; memoryStream.Read(tempBuffer, 0, tempBuffer.Length); memoryStream.Close(); webStream.Write(tempBuffer, 0, tempBuffer.Length); // write the file to the stream int size; byte[] buf = new byte[1024 * 10]; do { size = fs.Read(buf, 0, buf.Length); if (size > 0) webStream.Write(buf, 0, size); } while (size > 0); // write the trailer to the stream webStream.Write(boundarybytes, 0, boundarybytes.Length); webStream.Close(); fs.Close(); //fails here. Error - Incomplete multipart body. WebResponse webResponse = webRequest.GetResponse(); } return true; }

    Read the article

  • Break a class in twain, or impose an interface for restricted access?

    - by bedwyr
    What's the best way of partitioning a class when its functionality needs to be externally accessed in different ways by different classes? Hopefully the following example will make the question clear :) I have a Java class which accesses a single location in a directory allowing external classes to perform read/write operations to it. Read operations return usage stats on the directory (e.g. available disk space, number of writes, etc.); write operations, obviously, allow external classes to write data to the disk. These methods always work on the same location, and receive their configuration (e.g. which directory to use, min disk space, etc.) from an external source (passed to the constructor). This class looks something like this: public class DiskHandler { public DiskHandler(String dir, int minSpace) { ... } public void writeToDisk(String contents, String filename) { int space = getAvailableSpace(); ... } public void getAvailableSpace() { ... } } There's quite a bit more going on, but this will do to suffice. This class needs to be accessed differently by two external classes. One class needs access to the read operations; the other needs access to both read and write operations. public class DiskWriter { DiskHandler diskHandler; public DiskWriter() { diskHandler = new DiskHandler(...); } public void doSomething() { diskHandler.writeToDisk(...); } } public class DiskReader { DiskHandler diskHandler; public DiskReader() { diskHandler = new DiskHandler(...); } public void doSomething() { int space = diskHandler.getAvailableSpace(...); } } At this point, both classes share the same class, but the class which should only read has access to the write methods. Solution 1 I could break this class into two. One class would handle read operations, and the other would handle writes: // NEW "UTILITY" CLASSES public class WriterUtil { private ReaderUtil diskReader; public WriterUtil(String dir, int minSpace) { ... diskReader = new ReaderUtil(dir, minSpace); } public void writeToDisk(String contents, String filename) { int = diskReader.getAvailableSpace(); ... } } public class ReaderUtil { public ReaderUtil(String dir, int minSpace) { ... } public void getAvailableSpace() { ... } } // MODIFIED EXTERNALLY-ACCESSING CLASSES public class DiskWriter { WriterUtil diskWriter; public DiskWriter() { diskWriter = new WriterUtil(...); } public void doSomething() { diskWriter.writeToDisk(...); } } public class DiskReader { ReaderUtil diskReader; public DiskReader() { diskReader = new ReaderUtil(...); } public void doSomething() { int space = diskReader.getAvailableSpace(...); } } This solution prevents classes from having access to methods they should not, but it also breaks encapsulation. The original DiskHandler class was completely self-contained and only needed config parameters via a single constructor. By breaking apart the functionality into read/write classes, they both are concerned with the directory and both need to be instantiated with their respective values. In essence, I don't really care to duplicate the concerns. Solution 2 I could implement an interface which only provisions read operations, and use this when a class only needs access to those methods. The interface might look something like this: public interface Readable { int getAvailableSpace(); } The Reader class would instantiate the object like this: Readable diskReader; public DiskReader() { diskReader = new DiskHandler(...); } This solution seems brittle, and prone to confusion in the future. It doesn't guarantee developers will use the correct interface in the future. Any changes to the implementation of the DiskHandler could also need to update the interface as well as the accessing classes. I like it better than the previous solution, but not by much. Frankly, neither of these solutions seems perfect, but I'm not sure if one should be preferred over the other. I really don't want to break the original class up, but I also don't know if the interface buys me much in the long run. Are there other solutions I'm missing?

    Read the article

  • Drupal + Lighttpd: enabling clean urls (rewriting)

    - by Patrick
    I'm emulating Ubuntu on my mac, and I use it as a server. I've installed lighttpd + Drupal and the following configuration section requires a domain name in order to make clean urls to work. Since I'm using a local server I don't have a domain name and I was wondering how to make it work given the fact the ip of the local machine is usually changing. thanks $HTTP["host"] =~ "(^|\.)mywebsite\.com" { server.document-root = "/var/www/sites/mywebsite" server.errorlog = "/var/log/lighttpd/mywebsite/error.log" server.name = "mywebsite.com" accesslog.filename = "/var/log/lighttpd/mywebsite/access.log" include_shell "./drupal-lua-conf.sh mywebsite.com" url.access-deny += ( "~", ".inc", ".engine", ".install", ".info", ".module", ".sh", "sql", ".theme", ".tpl.php", ".xtmpl", "Entries", "Repository", "Root" ) # "Fix" for Drupal SA-2006-006, requires lighttpd 1.4.13 or above # Only serve .php files of the drupal base directory $HTTP["url"] =~ "^/.*/.*\.php$" { fastcgi.server = () url.access-deny = ("") } magnet.attract-physical-path-to = ("/etc/lighttpd/drupal-lua-scripts/p-.lua") }

    Read the article

  • FTP "PUT" fails from Virtual Machine, but not host PC: 504 Command not implemented for that paramete

    - by BrianH
    I have an FTP Script I'm using to automate a file transfer. The transfer works fine on my PC (XP SP2), but when I try and run it on a VM on my PC (XP SP2), the "put" commands gives off: 504 Command not implemented for that parameter. FTP File: open [ftp site] [username] [password] cd [directory on FTP server] binary hash put ..\[subfolder1]\[Subfolder2]\[subfolder3]\[filename] bye The FTP site/server is around the world, and not under my control. From what I understand of a 504, that means the command should NEVER work, but since the same script DOES work on my PC (hosting the VM), that eliminates syntax, file naming, etc. The put command when triggered from the VM, actually creates a 0 length file on the target FTP server, but doesn't populate the file.

    Read the article

  • Webdriver PageObject Implementation using PageFactory in Java

    - by kamal
    here is what i have so far: A working Webdriver based Java class, which logs-in to the application and goes to a Home page: import java.io.File; import java.io.IOException; import java.util.concurrent.TimeUnit; import org.apache.commons.io.FileUtils; import org.openqa.selenium.By; import org.openqa.selenium.OutputType; import org.openqa.selenium.TakesScreenshot; import org.openqa.selenium.WebDriver; import org.openqa.selenium.firefox.FirefoxDriver; import org.openqa.selenium.firefox.FirefoxProfile; import org.testng.AssertJUnit; import org.testng.annotations.AfterMethod; import org.testng.annotations.BeforeMethod; import org.testng.annotations.Test; public class MLoginFFTest { private WebDriver driver; private String baseUrl; private String fileName = "screenshot.png"; @BeforeMethod public void setUp() throws Exception { FirefoxProfile profile = new FirefoxProfile(); profile.setPreference("network.http.phishy-userpass-length", 255); profile.setAssumeUntrustedCertificateIssuer(false); driver = new FirefoxDriver(profile); baseUrl = "https://a.b.c.d/"; driver.manage().timeouts().implicitlyWait(30, TimeUnit.SECONDS); } @Test public void testAccountLogin() throws Exception { driver.get(baseUrl + "web/certLogon.jsp"); driver.findElement(By.name("logonName")).clear(); AssertJUnit.assertEquals(driver.findElement(By.name("logonName")) .getTagName(), "input"); AssertJUnit.assertEquals(driver.getTitle(), "DA Logon"); driver.findElement(By.name("logonName")).sendKeys("username"); driver.findElement(By.name("password")).clear(); driver.findElement(By.name("password")).sendKeys("password"); driver.findElement(By.name("submit")).click(); driver.findElement(By.linkText("Account")).click(); AssertJUnit.assertEquals(driver.getTitle(), "View Account"); } @AfterMethod public void tearDown() throws Exception { File screenshot = ((TakesScreenshot) driver) .getScreenshotAs(OutputType.FILE); try { FileUtils.copyFile(screenshot, new File(fileName)); } catch (IOException e) { e.printStackTrace(); } driver.quit(); } } Now as we see there are 2 pages: 1. Login page, where i have to enter username and password, and homepage, where i would be taken, once the authentication succeeds. Now i want to implement this as PageObjects using Pagefactory: so i have : package com.example.pageobjects; import static com.example.setup.SeleniumDriver.getDriver; import java.util.concurrent.TimeUnit; import org.openqa.selenium.support.PageFactory; import org.openqa.selenium.support.ui.ExpectedCondition; import org.openqa.selenium.support.ui.FluentWait; import org.openqa.selenium.support.ui.Wait; public abstract class MPage<T> { private static final String BASE_URL = "https://a.b.c.d/"; private static final int LOAD_TIMEOUT = 30; private static final int REFRESH_RATE = 2; public T openPage(Class<T> clazz) { T page = PageFactory.initElements(getDriver(), clazz); getDriver().get(BASE_URL + getPageUrl()); ExpectedCondition pageLoadCondition = ((MPage) page).getPageLoadCondition(); waitForPageToLoad(pageLoadCondition); return page; } private void waitForPageToLoad(ExpectedCondition pageLoadCondition) { Wait wait = new FluentWait(getDriver()) .withTimeout(LOAD_TIMEOUT, TimeUnit.SECONDS) .pollingEvery(REFRESH_RATE, TimeUnit.SECONDS); wait.until(pageLoadCondition); } /** * Provides condition when page can be considered as fully loaded. * * @return */ protected abstract ExpectedCondition getPageLoadCondition(); /** * Provides page relative URL/ * * @return */ public abstract String getPageUrl(); } And for login Page not sure how i would implement that, as well as the Test, which would call these pages.

    Read the article

  • pure-ftpd: one readonly/non-deletable file in home directory

    - by Bram Schoenmakers
    Is there a way to have a file in the user's FTP home directory without the ability to modify/remove it from that directory over FTP? So the user has write permissions on his own home folder, thus the ability to remove files. An exception should be made for a single file, which has the same filename and contents for each account. The solution I'm thinking of right now to run a periodic script to check the presence of that file, and if not, put it back. But I wonder whether there's a better solution than this.

    Read the article

  • Varnish doesn't seem to be caching

    - by Charlie Somerville
    I've setup a Varnish cache mirror to sit in front of a file server, but it seems to be endlessly re-downloading data from my file server. There's about 100GB of data in total, but so far Varnish has downloaded 800GB from my file server. I'm using the default VCL file that comes with Varnish and the response headers for files served by the file server are similar to the following: HTTP/1.1 200 OK Cache-Control: max-age=290304000, public Content-Type: image/jpeg Expires: Wed, 29 Dec 2010 21:38:33 GMT Server: Microsoft-IIS/7.0 E-Tag: "8b4723296ab697530768f18b1378b269" Content-Disposition: inline; filename=image046.jpg; X-AspNet-Version: 4.0.30319 X-Powered-By: ASP.NET Date: Thu, 23 Dec 2010 05:38:33 GMT Content-Length: 100592 I'm starting varnishd with the following options: varnish/sbin/varnishd -a 0.0.0.0:80 -f varnish/etc/varnish/default.vcl -s file,varnish/var/lib/varnish/varnish_storage.bin,100G

    Read the article

  • Unlock file on Windows Server 2003 by remote desktop without rebooting

    - by BalusC
    We've several Windows Server 2003 machines running, each with its own purposes. There are scheduled jobs which synchronizes some files over SFTP using WinSCP. Very sometimes a newly copied file is left locked in the "inbox" folder without any reason. The machine's own background task (programmed in Java) can't move it to the "processed" folder anymore after processing it. Manually moving it only yields the well known error message Cannot move [filename]: it is being used by another person or program. The only resort is to reboot the machine, but we would of course like to avoid that. Any suggestions? I tried Unlocker which works fine locally at WinXP, but doesn't work at those Win2K3 machines by remote desktop (unlock option doesn't show up in rightclick context menu). I tried Process Explorer as well as described in this blog article, but it caused the server to crash (not sure if that's because it's executed through remote desktop).

    Read the article

  • Ctrl W s not splitting windows in vim

    - by rajan sthapit
    I am trying to use Ctrl+ws to split a window in vim. However it is not working in my case. I opened a file using vim filename. Then I pressed Ctrl+ws. But as soon as I press just Ctrl+w it clears the viewport and I could see my shell display before vim opened the file. I mean the view port is replaced by the content just before the file was opened. However, I am still editing the file with vim. Suggestions?

    Read the article

  • Target to browse in order to insert a file

    - by Abid
    I have created an application using PHP and HTML. I insert it in my Linux server. I open it from my windows machine using the browser. I should in this application insert a file. When i click "insert file", instead of i have a window that browse the Linux server , i get a window that browse my local machine. And when i click insert , nothing is copied to the server. The code to insert file is: Filename: <input type="file" name="file" id="file"> So what should i do to force this application to browse the Linux machine when i open it from my local machine?

    Read the article

  • nfs server on cygwin slow

    - by Weltenwanderer
    The setup: We run an instance of cygwin nfsd on a Windows 2008 Server (Xeon 3,2 GHz). There are several Sun Solaris and SunOS machines accessing the shares. This is the exports file: /disk3 (rw,all_squash) /disk2 (rw,all_squash) Those paths are soft linked to the relevant cygdrive/d/path/to/dir paths. Some of the folders contain up to 10k files. The Problem: ls -la on the mounted folder on the sun boxes takes 2 - 3 minutes and the general read performance is really bad. cat filename displays the file in slow bursts and this hurts performance on tasks that access those shared files heavily. Processor load is not the issue, the nfs server idles most of the time, the cygwin tasks never get over 1% load.

    Read the article

  • ASP.NET, URL Rewriting and threads on Linux?

    - by acidzombie24
    Right now converting my normal sql(ite) syntax into compatible MS Server syntax is driving me mad. My code seems to be mono compatible judging by MoMA. However in global.asax i start several threads in Application_Start to use as a service and excessive url rewrites in Application_BeginRequest (everything is rewriting into default.aspx which calls C# code/class baded on the url). The urls do not have extensions or my have false extentions ie mysite.com/username/page/title.lol - id I need it all to go to BeginRequest. I also need files to be downloadable. Usually the path will be rewritten as from /file/user/filename to /file/u/s/user/file. Would this be supported on linux+mono+a good webserver?

    Read the article

  • Server 2008 won't run executables from CMD prompt without .exe extension

    - by Dan
    On one of our production server 2008 boxes, I cannot run executables from a CMD prompt without supplying the full filename, including the '.exe' extension. For example, when running "java" produced the usual "is not recognized as an internal or external command" message, I assumed I had borked the path and/or java_home variables. However, even navigating to the %java_home%\bin directory and typing "java" produced the same error. If I type "java.exe" instead, all works perfectly. The problem does not only affect java.exe. Even Microsoft executables suffer the same problem -- ping fails, ping.exe works; ipconfig fails, ipconfig.exe works; manually created batch file 'test' only works when invoked explicitly as 'test.bat'. Any bright ideas?

    Read the article

  • inetmgr missing after vista iis7 install

    - by GHarping
    I have installed IIS7 on Vista with all options from Programs and Features->Turn on/off windows features. I have searched for inetmgr accross the whole system with no luck. It is also not present in C:\Windows\System32\inetsrv. The IIS Admin Service is shown as running in the list of all services. Might anyone know what the problem is? My initial problem before this was that after installing IIS and trying to view any arbitrary page via localhost/*filename*, i recieved the error HTTP Error 404.4 - Not Found The resource you are looking for does not have a handler associated with it.

    Read the article

< Previous Page | 87 88 89 90 91 92 93 94 95 96 97 98  | Next Page >