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  • Python regular expressions assigning to named groups

    - by None
    When you use variables (is that the correct word?) in python regular expressions like this: "blah (?P\w+)" ("value" would be the variable), how could you make the variable's value be the text after "blah " to the end of the line or to a certain character not paying any attention to the actual content of the variable. For example, this is pseudo-code for what I want: >>> import re >>> p = re.compile("say (?P<value>continue_until_text_after_assignment_is_recognized) endsay") >>> m = p.match("say Hello hi yo endsay") >>> m.group('value') 'Hello hi yo' Note: The title is probably not understandable. That is because I didn't know how to say it. Sorry if I caused any confusion.

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  • PHP regular expression

    - by Ferol
    such text: $text = ' href="http://yahoo.com" target="_blank"> link text </a> text... text... <br> text...'; // $text = ' text... <a href="http://yahoo.com" target="_blank"> link text </a> text... text... <br> text...'; and such regular expression: preg_match_all('/^(.*)(<.+>)(.*)(<\/.+>)(.*)$/',$text,$matches); what I want, - to check if text matches the regular expression. If yes, then $matches should contain parts of string above, if not (as I guess) it should contain four zero-length arrays. something is wrong, but I can't find, what actually is?

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  • get city, state or zip from a string in python

    - by Joe
    I'd like to be able to parse out the city, state or zip from a string in python. So, if I entered Boulder, Co 80303 Boulder, Colorado Boulder, Co 80303 ... any variation of these it would return the city, state or zip. This is all going to be user inputted data and inputted in one text field.

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  • Regular Expression for CSV with numbers

    - by Bernie Perez
    I'm looking for some regular expression to help parse my CSV file. The file has lines of number,number number,number Comment I want to skip number,number number,number Ex: 319,5446 564425,87 Text to skip 27,765564 I read each line into a string and I wanted to use some regular express to make sure the line matches the pattern of (number,number). If not then don't use the line.

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  • php replace regular expression

    - by Enkay
    I need to use php to add a space between a period and the next word/letter when there's none. For example, "This is a sentence.This is the next one." needs to become "This is a sentence. This is the next one." Notice the added space after the first period. My problem is that even if I'm able to make a regular expression that finds every dot followed by a letter, how do I then replace that dot with a "dot + space" and keep the letter? Also it needs to keep the case of the letter, lower or upper. Thanks for your input.

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  • What's the fastest way to check if a word from one string is in another string?

    - by Mike Trpcic
    I have a string of words; let's call them bad: bad = "foo bar baz" I can keep this string as a whitespace separated string, or as a list: bad = bad.split(" "); If I have another string, like so: str = "This is my first foo string" What's the fasted way to check if any word from the bad string is within my comparison string, and what's the fastest way to remove said word if it's found? #Find if a word is there bad.split(" ").each do |word| found = str.include?(word) end #Remove the word bad.split(" ").each do |word| str.gsub!(/#{word}/, "") end

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  • Regular Expression: back references

    - by sixtyfootersdude
    sed 's/^\(\h*\)\(.*\)$/\1<!-- \2 -->/' web.xml I think that this should take this xml: <a> <d> bla </d> </a> And turn it into: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> --> But what is doing is this: <!-- <a> --> <!-- <d> --> <!-- bla --> <!-- </d> --> <!-- </a> -->

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  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

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  • Automatically hyper-link URL's and Email's using C#, whilst leaving bespoke tags in place

    - by marcusstarnes
    I have a site that enables users to post messages to a forum. At present, if a user types a web address or email address and posts it, it's treated the same as any other piece of text. There are tools that enable the user to supply hyper-linked web and email addresses (via some bespoke tags/markup) - these are sometimes used, but not always. In addition, a bespoke 'Image' tag can also be used to reference images that are hosted on the web. My objective is to both cater for those that use these existing tools to generate hyper-linked addresses, but to also cater for those that simply type a web or email address in, and to then automatically convert this to a hyper-linked address for them (as soon as they submit their post). I've found one or two regular expressions that convert a plain string web or email address, however, I obviously don't want to perform any manipulation on addresses that are already being handled via the sites bespoke tagging, and that's where I'm stuck - how to EXCLUDE any web or email addresses that are already catered for via the bespoke tagging - I wan't to leave them as is. Here are some examples of bespoke tagging for the variations that I need to be left alone: [URL=www.msn.com]www.msn.com[/URL] [URL=http://www.msn.com]http://www.msn.com[/URL] [[email protected]][email protected][/EMAIL] [IMG]www.msn.com/images/test.jpg[/IMG] [IMG]http://www.msn.com/images/test.jpg[/IMG] The following examples would however ideally need to be automatically converted into web & email links respectively: www.msn.com http://www.msn.com [email protected] Ideally, the 'converted' links would just have the appropriate bespoke tags applied to them as per the initial examples earlier in this post, so rather than: <a href="..." etc. they'd become: [URL=http://www.. etc.) Unfortunately, we have a LOT of historic data stored with this bespoke tagging throughout, so for now, we'd like to retain that rather than implementing an entirely new way of storing our users posts. Any help would be much appreciated. Thanks.

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  • Filter string in C

    - by Paul Tarjan
    How can I filter a string in c? I want to remove anything that isn't [a-z0-9_]. int main(int argc, char ** argv) { char* name = argv[1]; // remove anything that isn't [a-z0-9_] printf("%s", name); }

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  • Python regex on list

    - by Peter Nielsen
    Hi there I am trying to build a parser and save the results as an xml file but i have problems.. For instance i get a TypeError: expected string or buffer when i try to run the code.. Would you experts please have a look at my code ? import urllib2, re from xml.dom.minidom import Document from BeautifulSoup import BeautifulSoup as bs osc = open('OSCTEST.html','r') oscread = osc.read() soup=bs(oscread) doc = Document() root = doc.createElement('root') doc.appendChild(root) countries = doc.createElement('countries') root.appendChild(countries) findtags1 = re.compile ('<h1 class="title metadata_title content_perceived_text(.*?)</h1>', re.DOTALL | re.IGNORECASE).findall(soup) findtags2 = re.compile ('<span class="content_text">(.*?)</span>', re.DOTALL | re.IGNORECASE).findall(soup) for header in findtags1: title_elem = doc.createElement('title') countries.appendChild(title_elem) header_elem = doc.createTextNode(header) title_elem.appendChild(header_elem) for item in findtags2: art_elem = doc.createElement('artikel') countries.appendChild(art_elem) s = item.replace('<P>','') t = s.replace('</P>','') text_elem = doc.createTextNode(t) art_elem.appendChild(text_elem) print doc.toprettyxml()

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  • How to get a Clean String in Javascript?

    - by streetparade
    i have a long String. With some German characters and lots of new lines tabs ect.. In a Selectbox user can select a text, on change i do document.getElementById('text').value=this.value; But this fails. I just get a "unterminated string literal" as error in JavaScript. I think i should clean the string. How can i do it in JavaScript?

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  • Removing text within parentheses (parentheses within parentheses prob)

    - by TenJack
    Hi, I am trying to remove text that is within parentheses (along with the parentheses themselves) but am having trouble with the scenario where there are parentheses within parentheses. This is the method I am using (in Ruby): sentence.gsub(/\(.*?\)/, "") and that works fine until I have a sentence such as: "This is (a test (string))" Then the above chokes. Anyone have any idea how to do this? I am completely stumped.

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  • Replace underscore between words (reg.exp)

    - by lasseespeholt
    Hey, I need a regular expression to solve the following problem (links to similar problems is also appreciated, related tutorials etc.): __some_words_a_b___ => __some words a b___ ____ => ____ So I want underscores between words to be replaced with space and keep leading and trailing underscores. I found this: ^[ \t]+|[ \t]+$ and I guess it most be something like that. I will use it in jQuery, Java (stdlibs) and maybe XSLT. Addition: The sentences do not necessarily start with underscores or ends with underscores. It is also possible that a sentence ain't containing underscores at all. Best regards Lasse Espeholt

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  • Search for a String and replace it with a variable

    - by chrissygormley
    Hello, I am trying to use regular expression to search a document fo a UUID number and replace the end of it with a new number. The code I have so far is: read_file = open('test.txt', 'r+') write_file = open('test.txt', 'w') r = re.compile(r'(self.uid\s*=\s*5EFF837F-EFC2-4c32-A3D4\s*)(\S+)') for l in read_file: m1 = r.match(l) if m1: new=(str,m1.group(2)) new?????? This where I get stuck. The file test.txt has the below UUID stored in it: self.uid = '5EFF837F-EFC2-4c32-A3D4-D15C7F9E1F22' I want to replace the part D15C7F9E1F22. I have also tried this: r = re.compile(r'(self.uid\s*=\s*)(\S+)') for l in fp: m1 = r.match(l) new=map(int,m1.group(2).split("-") new[4]='RHUI5345JO' But I cannot seem to match the string. Thanks in advance for any help.

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  • Strange JavaScript Regular Expression Behavior

    - by Kiwi
    I'm getting different behavior from a regular expression in JavaScript depending on whether or not I declare it using literal syntax. Using a extremely simple test HTML file: <html> <head> <script type="text/javascript"> var s = '3'; var regex1 = /\d/; var regex2 = new RegExp('\d'); alert(s.search(regex1)); // 0 (matches) alert(s.search(regex2)); // -1 (does not match) </script> </head> <body></body> </html> The regular expression declared with literal syntax (/\d/) works correctly, while the other (new RegExp('\d')) does not. Why on earth is this happening? I'm using Google Chrome 5.0.375.70 on Windows Vista Home Premium, if that's at all helpful.

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  • How to Practically Split Values from CSV File into MySQL Database

    - by Ryan
    Let's suppose I have the following line in a CSV file (I removed the header row in this example): "500,000",2,50,2,90000 I have a PHP script read the CSV file, break the file into individual lines, and store each line in an array called $linearray. Then, I use a foreach loop to look at each line individually. Within the foreach loop, I break the line into separate variables using the following function: $line = str_replace("'","\'",$line); From here, I insert the values into separate columns within a MySQL database. The script works. The values are inserted into a database, but I run into a problem. I want: "500,000" | 2 | 50 | 2 | 90000 But I get this: "500 | 000" | 2 | 50 | 2 | 90000 The script isn't smart enough to understand it should skip commas within quotation marks. Do you know how I can alter my script to make sure I get the output I'm looking for? Thanks.

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  • Is the JavaScript RegExp implicit method deprecated?

    - by Eric
    So everyone knows what I mean by "implicit methods"? They're like those default properties from the Windows COM days of yore, where you could type something like val = obj(arguments) and it would be interpreted as val = obj.defaultMethod(arguments) I just found out JavaScript has the same thing: the default method of a RegExp object appears to be 'exec', as in /(\w{4})/('yip jump man')[1] ==> jump This even works when the RegExp object is assigned to a variable, and even when it's created with the RegExp constructor, instead of /.../, which is good news to us fans of referential transparency. Where is this documented, and/or is it deprecated?

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  • Help me to split string with Regular Expression

    - by Lu Lu
    Hello, I have a string: CriteriaCondition={FieldName={*EPS}*$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)} Help me to get the first word which ends with the first word "={" & get the next following word which ends with "}". The result must be: Word1 = "CriteriaCondition" Word2 = "FieldName={EPS}$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)" And with the string "FieldName=(EPS)$MinValue=(-201)$MaxValue=(304)$TradingPeriod=(-1)", help me to split to pairs: FieldName EPS MinValue -201 MaxValue 304 TradingPeriod -1 Thanks.

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  • regular expression for indian vehicle number in javascript and php

    - by I Like PHP
    i need regular expression in java script as well as in PHP for Indian vehicle NUMBER here are conditions list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

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  • preg_replace pass match through function before replacing

    - by Martin
    This is what i want to do: $line = 'blabla translate("test") blabla'; $line = preg_replace("/(.*?)translate\((.*?)\)(.*?)/","$1".translate("$2")."$3",$line); So the result should be that translate("test") is replaced with the translation of "test". The problem is that translate("$2") passes the string "$2" to the translate function. So translate() tries to translate "$2" instead of "test". Is there some way to pass the value of the match to a function before replacing?

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