Search Results

Search found 3804 results on 153 pages for 'regex'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 97/153 | < Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >

  • With PHP preg_match_all, get value of href

    - by Jeremy Dicaire
    Hi, I don'T really understabd how regular expressions works even after I read this tutorial http://www.webcheatsheet.com/php/regular_expressions.php Here is what I need to find: And it should return: http://link Here is what I tried: $find = preg_match_all('/<link type="text/html" rel="alternate" href=".*',$file,$patterns2); You can laught :) Thanks in advance for your help and your time :)

    Read the article

  • Mod rewrite with multiple query strings

    - by Boris
    Hi, I'm a complete n00b when it comes to regular expressions. I need these redirects: (1) www.mysite.com/products.php?id=001&product=Product-Name&source=Source-Name should become -> www.mysite.com/Source-Name/001-Product-Name (2) www.mysite.com/stores.php?id=002&name=Store-Name should become -> www.mysite.com/002-Store-Name Any help much appreciated :)

    Read the article

  • replacing text within quotes until next quote

    - by Jordan Trainor
    String input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; This is my current code that works but iv added some code that has to run before this which makes some '"' split onto another line thus making the code below obsolute unless under certain cirumstances the '"' is not put onto the next line. firstQuote = input.IndexOf("\""); lastQuote = input.LastIndexOf("\""); input = input.Substring(0, firstQuote) + "<span>quote" + input.Substring(firstQuote + 1, lastQuote - (firstQuote + 1) + "quote</span>" + input.Substring(lastQuote + 1, lines.Length - (lastQuote + 1); How could I change the input string from input = "helloj\"iojgeio\r\ngsk\\"jopri\"gj\r\negjoijisgoe\"joijsofeij\"\"\"ojgsoij\""; to input = "helloj(<span>quoteiojgeio\r\ngsk\\"jopriquote</span>gj\r\negjoijisgoe<span>quotejoijsofeijquote</span>quote<span>quote</span>ojgsoij<span>quote</span>";

    Read the article

  • [Python] OR in regular expression?

    - by www.yegorov-p.ru
    Hello. I have text file with several thousands lines. I want to parse this file into database and decided to write a regexp. Here's part of file: blablabla checked=12 unchecked=1 blablabla unchecked=13 blablabla checked=14 As a result, I would like to get something like (12,1) (0,13) (14,0) Is it possible?

    Read the article

  • How to use PHP preg_replace regular expression to find and replace text

    - by Roger
    I wrote this PHP code to make some substitutions: function cambio($txt){ $from=array( '/\+\>([^\+\>]+)\<\+/', //finds +>text<+ '/\%([^\%]+)\%/', //finds %text% ); $to=array( '<span class="P">\1</span>', '<span>\1</span>', ); return preg_replace($from,$to,$txt); } echo cambio('The fruit I most like is: +> %apple% %banna% %orange% <+.'); Resulting into this: The fruit I most like is: <span class="P"> <span>apple</span> <span>banna</span> <span>orange</span> </span>. however I needed to identify the fruit's span tags, like this: The fruit I most like is: <span class="P"> <span class="a">apple</span> <span class="b">banna</span> <span class="c">coco</span> </span>. I'd buy a fruit to whom discover a regular expression to accomplish this :-)

    Read the article

  • jquery sortable with regexp

    - by Chris Lively
    I am trying to figure out the right regexp to match on list item id's. For example: <ul id="MyList" class="connectedSortable"> <li id="id=1-32">Item 1</li> <li id="id=2_23">Item 2</li> <li id="id=3">Item 3</li> <li id="id=4">Item 4</li> <li id="id=5">Item 5</li> <li id="id=6">Item 6</li> </ul> On the serialize method, I want it to pull everything after the equal sign (=) $(function () { $("#MyList, #OtherList").sortable({ connectWith: '.connectedSortable', update: function () { $("#MyListOrder").val($("#MyList").sortable('serialize', { regexp: '/(.+)[=](.+)/)' })); } }).disableSelection(); }); I tried the above, but that didn't quite work. My regexp expression is wrong and I don't know what it should be. Ideas?

    Read the article

  • parse youtube video id using preg_match

    - by Webbo
    Hi, I am attempting to parse the video ID of a youtube URL using preg_match. I found a regular expression on this site that appears to work; (?<=v=)[a-zA-Z0-9-]+(?=&)|(?<=[0-9]/)[^&\n]+|(?<=v=)[^&\n]+ As shown in this pic; http://i.imgur.com/SQJW2.jpg My PHP is as follows, but it doesn't work (gives Unknown modifier '[' error)... <? $subject = "http://www.youtube.com/watch?v=z_AbfPXTKms&NR=1"; preg_match("(?<=v=)[a-zA-Z0-9-]+(?=&)|(?<=[0-9]/)[^&\n]+|(?<=v=)[^&\n]+", $subject, $matches); print "<pre>"; print_r($matches); print "</pre>"; ?> Cheers

    Read the article

  • Dreamweaver regular expression substitution followed by number

    - by mark
    Hi. I'm using Dreamweaver to update copyright dates across my site. I want to preserve the existing spacing (or lack thereof) between years. Examples: © 2002-2008 should update to © 2002-2009 © 2003 - 2008 should update to © 2003 - 2009 This is the regular expression I'm using to accomplish this in Dreamweaver's find & replace function Find: ©\s*(\d{4}\s*-\s*)\d{3}[^9] Replace: © $1 2009 Here's the PROBLEM: This expression works, but has that that extra space between the hyphen and 2009. If I write the replace expression without the space, as © $12009 then dreamweaver looks for the 12,009th substitution in the find expression, and, not finding one, prints $12009. Any ideas?

    Read the article

  • How to use regular expressions to pull a substring? (screen scraping)

    - by Diego
    Hey guys, i'm really trying to understand regular expressions while scraping a site, i've been using it in my code enough to pull the following, but am stuck here. I need to quickly grab this: http://www.example.com/online/store/TitleDetail?detail&sku=123456789 from this: ('<a href="javascript:if(handleDoubleClick(this.id)){window.location=\'http://www.example.com/online/store/TitleDetail?detail&sku=123456789\';}" id="getTitleDetails_123456789">\r\n\t\t\t \tcheck store inventory\r\n\t\t\t </a>', 1) This is where I got confused. any ideas?

    Read the article

  • Regexp look-behind to match internet speeds

    - by Sandman
    So the user may search for "10 mbit" after which I want to capture the "10" so I can use it in a speed-search rather than a string-search. This isn't a problem, the below regexp does this fine: if (preg_match("/(\d+)\smbit/", $string)){ ... } But, the user may search for something like "10/10 mbit" or "10-100 mbit". I don't want to match those with the above regexp - they should be handled in another fashion. So I would like a regexp that matches "10 mbit" if the number is all-numeric as a whole word (i.e. contained by whitespace, newline or lineend/linestart) Using lookbehind, I did this: if (preg_match("#(?<!/)(\d+)\s+mbit#i", $string)){ Just to catch those that doesn't have "/" before them, but this matched true for this string: "10/10 mbit" so I'm obviously doing something wrong here, but what?

    Read the article

  • How to export the matches only in a pattern search in vim?

    - by Mert Nuhoglu
    Is there a way to grab and export the match part only in a pattern search without changing the current file? For example, from a file containing: 57","0","37","","http://www.thisamericanlife.org/Radio_Episode.aspx?episode=175" 58","0","37","","http://www.thisamericanlife.org/Radio_Episode.aspx?episode=170" I want to export a new file containing: http://www.thisamericanlife.org/Radio_Episode.aspx?episode=175 http://www.thisamericanlife.org/Radio_Episode.aspx?episode=170 I can do this by using substitution like this: :s/.\{-}\(http:\/\/.\{-}\)".\{-}/\1/g :%w>>data But the substitution command changes the current file. Is there a way to do this without changing the current file?

    Read the article

  • Use Regular expression with fileinput

    - by chrissygormley
    Hello, I am trying to replace a variable stored in another file using regular expression. The code I have tried is: r = re.compile(r"self\.uid\s*=\s*('\w{12})'") for line in fileinput.input(['file.py'], inplace=True): print line.replace(r.match(line), sys.argv[1]), The format of the variable in the file is: self.uid = '027FC8EBC2D1' I am trying to pass in a parameter in this format and use regular expression to verify that the sys.argv[1] is correct format and to find the variable stored in this file and replace it with the new variable. Can anyone help. Thanks for the help.

    Read the article

  • Regular expression to retrieve everything before first slash

    - by alex
    I need a regular expression to basically get the first part of a string, before the first slash (). For example in the following: C:\MyFolder\MyFile.zip The part I need is "C:" Another example: somebucketname\MyFolder\MyFile.zip I would need "somebucketname" I also need a regular expression to retrieve the "right hand" part of it, so everything after the first slash (excluding the slash.) For example somebucketname\MyFolder\MyFile.zip would return MyFolder\MyFile.zip.

    Read the article

  • Remove newlines and spaces

    - by Cosmin
    How can I remove newline between <table> .... </table> and add \n after each ex: <table border="0" cellspacing="0" cellpadding="0" width="450" class="descriptiontable"><tr> <td width="50%" valign="top"> <span class="displayb">Model Procesor:</span> Intel Celeron<br><span class="displayb">Frecventa procesor (MHz):</span> 2660<br><span class="displayb">Placa Video:</span> Intel Extreme Graphics 2<br><span class="displayb">Retea integrata:</span> 10/100Mbps, RJ-45<br><span class="displayb">Chipset:</span> Intel 845G<br> </td> <td width="50%" valign="top"> <span class="displayb">Capacitate RAM (MB):</span> 512<br><span class="displayb">Tip RAM:</span> DDR<br> </td> </tr></table> and become : <table border="0" cellspacing="0" cellpadding="0" width="450" class="descriptiontable"><tr><td width="50%" valign="top"><span class="displayb">Model Procesor:</span> Intel Celeron<br><span class="displayb">Frecventa procesor (MHz):</span> 2660<br><span class="displayb">Placa Video:</span> Intel Extreme Graphics 2<br><span class="displayb">Retea integrata:</span> 10/100Mbps, RJ-45<br><span class="displayb">Chipset:</span> Intel 845G<br></td><td width="50%" valign="top"><span class="displayb">Capacitate RAM (MB):</span> 512<br><span class="displayb">Tip RAM:</span> DDR<br></td></tr></table>\n s.

    Read the article

  • Regular expression to match any table tag

    - by keeg
    I'm trying to write a regular expression to see if a string contains any of the typical table tags: <table></table> <td></td> <th></th> <tr></tr> <thead></thead> <tfoot></tfoot> <tbody></tbody> Along with tags that may contain other attributes e.g: <table border="1"> I've come up with this so far, however, it matches <br /> tag and I'm not sure why: /<\/?[table|td|th|tr|tfoot|thead|tbody]{1,}>?/ http://www.rexfiddle.net/20Xtqka

    Read the article

  • How do I write this URL in Django?

    - by alex
    (r'^/(?P<the_param>[a-zA-z0-9_-]+)/$','myproject.myapp.views.myview'), How can I change this so that "the_param" accepts a URL(encoded) as a parameter? So, I want to pass a URL to it. mydomain.com/http%3A//google.com

    Read the article

  • How Do I Remove The First 4 Characters From A String If It Matches A Pattern In Ruby

    - by James
    I have the following string: "h3. My Title Goes Here" I basically want to remove the first 4 characters from the string so that I just get back: "My Title Goes Here". The thing is I am iterating over an array of strings and not all have the h3. part in front so I can't just ditch the first 4 characters blindly. I have checked the docs and the closest think I could find was chomp, but that only works for the end of a string. Right now I am doing this: "h3. My Title Goes Here".reverse.chomp(" .3h").reverse This gives me my desired output, but there has to be a better way right? I mean I don't want to reverse a string twice for no reason. I am new to programming so I might have missed something obvious, but I didn't see the opposite of chomp anywhere in the docs. Is there another method that will work? Thanks!

    Read the article

  • Find and Replace with Notepad++

    - by Levi
    I have a document that was converted from PDF to HTML for use on a company website to be referenced and indexed for search. I'm attempting to format the converted document to meet my needs and in doing so I am attempting to clean up some of the junk that was pulled over from when it was a PDF such as page numbers, headers, and footers. luckily all of these lines that need to be removed are in blocks of 4 lines unfortunately they are not exactly the same therefore cannot be removed with a simple literal replace. The lines contain numbers which are incremental as they correlate with the pages. How can I remove the following example from my html file. Title<br> 10<br> <hr> <A name=11></a>Footer<br> I've tried many different regular expression attempts but as my skill in that area is limited I can't find the proper syntax. I'm sure i'm missing something fairly easy as it would seem all I need is a wildcard replace for the two numbers in the code and the rest is literal. any help is apprciated

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 93 94 95 96 97 98 99 100 101 102 103 104  | Next Page >