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  • Strange behavior: Dynamic expressions with RegExp Object in RegExp.match (Javascript)

    - by NeDark
    I have detect a strange behavior in regexps created with the RegExp object: With this code: var exp1 = /./; var exp2 = new RegExp('.'); ? var test1 = exp1.test('large\n\ntext..etc.'); var test2 = exp2.test('large\n\ntext..etc.'); ? var match1 = 'large\n\ntext..etc.'.match(exp1); var match2 = 'large\n\ntext..etc.'.match(exp2); ...the result is: test1 = true test2 = true ? match1 = 'l' (first match) match2 = null With the regexp maked with the regexp object from a string it finds nothing... Why does this happends? Thanks!!

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  • Issue with my regular expression?

    - by Rubans
    I'm trying to locate the number matches in a relative path for directory up references("..\"). So I have the following pattern : "(..\)" which works as expected for the path "....\a\b" where it will give me 2 successfull groups ("..\") but when I try the path "..\a\b" it will also return 2 when it should be 1. I tried this in a reg ex tool such Expresso and it seems to work as expected in there but not in in .net, any ideas?

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  • Regular expression only for website

    - by Katie
    HI, I'm new to Regular Expression. I need to find just website in some text and I'm looking for a regular expression able to find out strings like: www.my.home, http://my.site.it But this regular expression should not find strings like: [email protected] or if the website is already inside html tag <a href="http://www.my.site.com/"><span style="font-style: normal;">www.mambo-test.org</span></a> I tried with this one: \b((https?://[^ ])|(www.[^ ])) but it also finds the website in the href and between the tag: <a href="http://www.my.site.com/"><span style="font-style: normal;">www.mambo-test.org</span></a> and I don't know how except this case.

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  • Replace underscore between words (reg.exp)

    - by lasseespeholt
    Hey, I need a regular expression to solve the following problem (links to similar problems is also appreciated, related tutorials etc.): __some_words_a_b___ => __some words a b___ ____ => ____ So I want underscores between words to be replaced with space and keep leading and trailing underscores. I found this: ^[ \t]+|[ \t]+$ and I guess it most be something like that. I will use it in jQuery, Java (stdlibs) and maybe XSLT. Addition: The sentences do not necessarily start with underscores or ends with underscores. It is also possible that a sentence ain't containing underscores at all. Best regards Lasse Espeholt

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  • Regular Expression find a phrase not inside an HTML tag

    - by James Buckingham
    Hi there, I'm struggling a bit with this regular expression and wondered if anyone was about to help me please? What I need to do is isolate the 1st phrase inside a string which is NOT inside an HTML tag. So the examples I have at the moment are: This is some test text about ITS for the ITS department. Also worth mentioning ABS as well I guess.ITS, ... and ... This is some ITS test text about ITS for the ITS department. Also worth mentioning ABS as well I guess So in the first example I want it to ignore the wrapped ITS and give me the ITS at the end of the 1st sentence. In the second example I want it to return the ITS at the start of the 2nd sentence. The aim is to replace these with my own custom wrapped acronym tags in a ColdFusion application I'm writing. Thanks a lot, James

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  • Python regular expressions assigning to named groups

    - by None
    When you use variables (is that the correct word?) in python regular expressions like this: "blah (?P\w+)" ("value" would be the variable), how could you make the variable's value be the text after "blah " to the end of the line or to a certain character not paying any attention to the actual content of the variable. For example, this is pseudo-code for what I want: >>> import re >>> p = re.compile("say (?P<value>continue_until_text_after_assignment_is_recognized) endsay") >>> m = p.match("say Hello hi yo endsay") >>> m.group('value') 'Hello hi yo' Note: The title is probably not understandable. That is because I didn't know how to say it. Sorry if I caused any confusion.

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  • Filter string in C

    - by Paul Tarjan
    How can I filter a string in c? I want to remove anything that isn't [a-z0-9_]. int main(int argc, char ** argv) { char* name = argv[1]; // remove anything that isn't [a-z0-9_] printf("%s", name); }

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  • php replace regular expression

    - by Enkay
    I need to use php to add a space between a period and the next word/letter when there's none. For example, "This is a sentence.This is the next one." needs to become "This is a sentence. This is the next one." Notice the added space after the first period. My problem is that even if I'm able to make a regular expression that finds every dot followed by a letter, how do I then replace that dot with a "dot + space" and keep the letter? Also it needs to keep the case of the letter, lower or upper. Thanks for your input.

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  • get city, state or zip from a string in python

    - by Joe
    I'd like to be able to parse out the city, state or zip from a string in python. So, if I entered Boulder, Co 80303 Boulder, Colorado Boulder, Co 80303 ... any variation of these it would return the city, state or zip. This is all going to be user inputted data and inputted in one text field.

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  • PHP, what is the better choice for removing a known string?

    - by Brook Julias
    I am looking to search for and replace a known string from within another string. Should I use str_replace() or ereg_replace()? The string to be replaced would be something similar to [+qStr+], [+bqID+], or [+aID+] and it would be being searched for in a code chunk similar to this: <li> [+qStr+] <ol class="mcAlpha"> <li><input type="radio" name="[+bqID+]" id="[+bqID+]_[+aID+]" value="[+aID+]" /><label for="[+bqID+]_[+aID+]">[+aStr+]</label></li> </ol> </li> I would be replacing the strings with the results from a MySQL query, and be performing this action or similar up to 200 times at a time. Which function str_replace() or ereg_replace() would be the easiest and/or quickest method to take.

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  • What regular expression do I need to check for some non-latin characters?

    - by zeckdude
    I am checking a field if it is Latin Characters or not. var foreignCharacters = $("#foreign_characters").val(); var rlatins = /[\u0000-\u007f]/; if (rlatins.test(foreignCharacters)) { alert("This is Latin Characters"); } else { alert("This is non-latin Characters"); } This works well, but I would like to change it so when I enter any non-latin characters, such as chinese characters, along with a space(which is within that range I am using currently) it will still say it is non-latin characters. How can I change the regular expression I have to do that?

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  • How would you parse the location text from Twitter to get the latitude/longitude in Objective-C?

    - by Brennan
    The location text from Twitter could be just about anything. Sometimes Twitter clients set the location with the user's latitude and longitude in the following format. "\U00dcT: 43.05948,-87.908409" Since there is no built-in support for Regular Expressions in Objective-C I am considering using the NSString functions like rangeOfString to pull the float values out of this string. For my current purpose I know the values with start with 43 and 87 so I can key off those values this time but I would prefer to do better than that. What would you do to parse the latitude/longitude from this string?

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  • Python regex on list

    - by Peter Nielsen
    Hi there I am trying to build a parser and save the results as an xml file but i have problems.. For instance i get a TypeError: expected string or buffer when i try to run the code.. Would you experts please have a look at my code ? import urllib2, re from xml.dom.minidom import Document from BeautifulSoup import BeautifulSoup as bs osc = open('OSCTEST.html','r') oscread = osc.read() soup=bs(oscread) doc = Document() root = doc.createElement('root') doc.appendChild(root) countries = doc.createElement('countries') root.appendChild(countries) findtags1 = re.compile ('<h1 class="title metadata_title content_perceived_text(.*?)</h1>', re.DOTALL | re.IGNORECASE).findall(soup) findtags2 = re.compile ('<span class="content_text">(.*?)</span>', re.DOTALL | re.IGNORECASE).findall(soup) for header in findtags1: title_elem = doc.createElement('title') countries.appendChild(title_elem) header_elem = doc.createTextNode(header) title_elem.appendChild(header_elem) for item in findtags2: art_elem = doc.createElement('artikel') countries.appendChild(art_elem) s = item.replace('<P>','') t = s.replace('</P>','') text_elem = doc.createTextNode(t) art_elem.appendChild(text_elem) print doc.toprettyxml()

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  • Removing text within parentheses (parentheses within parentheses prob)

    - by TenJack
    Hi, I am trying to remove text that is within parentheses (along with the parentheses themselves) but am having trouble with the scenario where there are parentheses within parentheses. This is the method I am using (in Ruby): sentence.gsub(/\(.*?\)/, "") and that works fine until I have a sentence such as: "This is (a test (string))" Then the above chokes. Anyone have any idea how to do this? I am completely stumped.

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  • How to get a Clean String in Javascript?

    - by streetparade
    i have a long String. With some German characters and lots of new lines tabs ect.. In a Selectbox user can select a text, on change i do document.getElementById('text').value=this.value; But this fails. I just get a "unterminated string literal" as error in JavaScript. I think i should clean the string. How can i do it in JavaScript?

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  • regular expression for indian vehicle number in javascript and php

    - by I Like PHP
    i need regular expression in java script as well as in PHP for Indian vehicle NUMBER here are conditions list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

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  • Redirect visitor with .htaccess

    - by Aaron
    Hi all, I've got an e-shop on a virtual server that's been used as a subdirectory for the last few years, but now I'm finally giving the VS it's own domain name. What I really need is visitors to the old URL to be transparently (and 301) redirected to the new URL with everything after /eshop/ maintained and apended to the new host. I.e. http://www.example.com/eshop/page.php - http://www.newdomain.com/page.php Any help would be greatly appreciated.

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  • questions on nfa and dfa..

    - by Loop
    Hi Guys... Hope you help me with this one.... I have a main question which is ''how to judge whether a regular expression will be accepted by NFA and/or DFA? For eg. My question says that which of the regular expressions are equivalent? explain... 1.(a+b)*b(a+b)*b(a+b)* 2.a*ba*ba* 3.a*ba*b(a+b)* do we have to draw the NFA and DFA and then find through minimisation algorithm? if we do then how do we come to know that which regular expression is accepted by NFA/DFA so that we can begin with the answer? its so confusing.... Second is a very similar one, the question asks me to show that the language (a^nb^n|n1} is not accepted by DFA...grrrrr...how do i know this? (BTW this is a set of all strings of where a number of a's is followed by the same number of b's).... I hope I explained clearly well....

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  • Strange JavaScript Regular Expression Behavior

    - by Kiwi
    I'm getting different behavior from a regular expression in JavaScript depending on whether or not I declare it using literal syntax. Using a extremely simple test HTML file: <html> <head> <script type="text/javascript"> var s = '3'; var regex1 = /\d/; var regex2 = new RegExp('\d'); alert(s.search(regex1)); // 0 (matches) alert(s.search(regex2)); // -1 (does not match) </script> </head> <body></body> </html> The regular expression declared with literal syntax (/\d/) works correctly, while the other (new RegExp('\d')) does not. Why on earth is this happening? I'm using Google Chrome 5.0.375.70 on Windows Vista Home Premium, if that's at all helpful.

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