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  • send email to list of users with different timezones?

    - by ylazez
    i use the following method to send email to list of users i want the (To) in each email to be for just the user only not all users i.e appears to the users that the email is sent to only him my guess is to loop on: message.addRecipients(Message.RecipientType.TO, address); then send the message right? , but this is a heavy process sending an email many times any ideas ? suppose that i have the timezone for each user and i want to send each user the message in his timzone, the same issue i guess setting sent date for each user in his timezone then sending the message, right ? the method is: try { Properties props = System.getProperties(); props.put("mail.smtp.host", "localhost"); // Get a mail session Session session = Session.getDefaultInstance(props, null); // Define a new mail message Message message = new MimeMessage(session); InternetAddress ia = new InternetAddress(); ia.setPersonal("MySite"); ia.setAddress(from); message.setFrom(ia); Address[] address = new Address[recievers.size()]; for (int i = 0; i < recievers.size(); i++) { address[i] = new InternetAddress(recievers.get(i)); } message.addRecipients(Message.RecipientType.TO, address); message.setSubject(subject); // Create a message part to represent the body text BodyPart messageBodyPart = new MimeBodyPart(); messageBodyPart.setContent(body, "text/html"); // use a MimeMultipart as we need to handle the file attachments Multipart multipart = new MimeMultipart(); // add the message body to the mime message multipart.addBodyPart(messageBodyPart); // Put all message parts in the message message.setContent(multipart); message.setSentDate(getCurrentDate()); // Send the message Transport.send(message); } catch (Exception ex) {}

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  • How to lowercase every element of a collection efficiently?

    - by Chris
    Whats the most efficient way to lower case every element of a list or set? My idea for a List: final List<String> strings = new ArrayList<String>(); strings.add("HELLO"); strings.add("WORLD"); for(int i=0,l=strings.size();i<l;++i) { strings.add(strings.remove(0).toLowerCase()); } is there a better, faster way? How would this exmaple look like for a set? As there is currently no method for applying an operation to each element of a set (or list) can it be done without creating an additional temporary set? Something like this would be nice: Set<String> strings = new HashSet<String>(); strings.apply( function (element) { this.replace(element, element.toLowerCase();) } ); Thanks,

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  • How to create updateable panel using AjaxLink of Wicket?

    - by Arne
    I try to realize a link (in fact many links) that update a table in an website using an AjaxLink of Wicket. But I fail, the table is never updated (I have "setOutputMarkupId(true)" and call "addComponent", but there must be something other thats wrong). How can I realize a panel with a number of links and a table that displays dynamic data, dependent on the link clicked? Can someone give an example (Maybe two links, when the first one is clicked the table displays two random numbers from 1-10, when the second is clicked the table displays random numbers from 1-100)? Without reloading the entire page, but only the html for the table?

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  • how to share a variable between two threads

    - by prmatta
    I just inherited some code, two threads within this code need to perform a system task. One thread should do the system task before the other thread. They should not be performing the system task together. The two threads do not have references to each other. Now, I know I can use some sort of a semaphore to achieve this. But my question is what is the right way to get both threads to access this semaphore. I could create a static variable/method a new class : public class SharedSemaphore { private static Semaphore s = new Semaphore (1, true); public static void performSystemTask () { s.acquire(); } public static void donePerformingSystemTask() { s.release(); } } This would work (right?) but this doesn't seem like the right thing to do. Because, the threads now have access to a semaphore, without ever having a reference to it. This sort of thing doesn't seem like a good programming practice. Am I wrong?

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  • How to center elements in the BoxLayout using center of the element?

    - by Roman
    I use outputPanel.setLayout(new BoxLayout(outputPanel, BoxLayout.Y_AXIS)); and then I add elements (for example JLabels, JButtons) to the outputPanel. For example: outputPanel.add(submitButton);. I see that all added elements are "centered". It is good, because I do want my elements to be in the center. When I write "center" I mean "equal distance from left and right". But the problem is that the left part of the element is put into the center. And I want to have center of elements to be put into the center. How can I get this behavior?

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  • Why can't i create a RESTful web service in ejb module?

    - by Nitesh Panchal
    Hello, I am using Netbeans 6.8. I can see an option to create a web service in my independent ejb module but i can't seem to find an option to create a RESTful based web service in my ejb module. Is there any kind of restriction in ejb module that i can only create SOAP based web service and not RESTful? or is it the bug of Netbeans 6.8?

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  • Binary search in rotated sorted list

    - by Algorist
    I am having a sorted list which is rotated and I would like to do a binary search on that list to find the minimum element. Lets suppose initial list is {1,2,3,4,5,6,7,8} rotated list can be like {5,6,7,8,1,2,3,4} Normal binary search doesn't work in this case. Any idea how to do this.

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  • Best way to get a Web Service to return a database result as XML?

    - by John
    I am building a webservice using jax-rs and querying a DB2 z/OS database with SQLJ and getting the result set as an arraylist. I would like to return this list as XML, but not sure how to do it. Does anyone have an example of returning a result set as XML and is using an Arraylist the best way to do this? Should I use JAXB? if so how?

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  • view is not rendered when returning ModelAndView

    - by adancu
    Hi, I have the following problem. I need to export a PDF in a controller The code below, where I return a View, works as expected. @RequestMapping(method = RequestMethod.GET) public View exportReport( @RequestParam(value = "userName", required = true) String userName, @RequestParam(value = "startDate", required = true) Date startDate, @RequestParam(value = "endDate", required = true) Date endDate) { /////////////////////////////////////////// return new TimeSheetReportPdfView(); } The problem occurs if I change the method to return a ModelAndView: @RequestMapping(method = RequestMethod.GET) public ModelAndView exportReport( @RequestParam(value = "userName", required = true) String userName, @RequestParam(value = "startDate", required = true) Date startDate, @RequestParam(value = "endDate", required = true) Date endDate) { /////////////////////////////////////////// return new ModelAndView(new TimeSheetReportPdfView(), model); } Now, the PDF is not exported, all I get is a blank page and nothing in the logs. Any help appreciated. Thanks.

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  • Servlet Security question about j_security_check, j_username and j_password

    - by Nitesh Panchal
    Hello, I used jdbcRealm in my web application and it's working fine. I defined all constraints also in my web.xml. Like all pages of url pattern /Admin/* should be accessed by only admin. I have a login form with uses standard j_security_check, j_username and j_password. Now, when i type Admin/home.jsf it rightly redirects me login.jsf and there when i type the password i am redirected to home.jsf. This works alright but problem comes i directly go to login.jsf and then type password and username. This time it again redirects me to login.jsf. Is there any way through which i can specify which page to go when successful login is there? I need to specify different different pages for different roles. For Admin, it is /Admin/home.jsf for general users it is /General/home.jsf because login form is shared between different type of users. Where do i specify all these things? Secondly, i want to have a remember me checkbox at the end of login form. How do i do this? By default, it is submitted to j_security_check servlet and i have no control over its execution. Please help. This doesn't seem so hard but looks like i am missing something.

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  • Overriding a method in statically created objects

    - by I82Much
    All, Due to a bug in a library I'm using, I need to override the dispose() method on all objects extending a certain class and make it a NO-OP. I know that if I'm making new instances of the classes directly, this is easy to do: layerManager = new LayerManagerLayer(wwd) { @Override public void dispose() {} }; The problem is that a lot of the object instances I get are not directly constructed by my client code, but instead are created via static library method calls. // Here I want to override the dispose method, but I cannot. Layer l = ShapefileLoader.makeShapefileLayer(this.getClass().getResource("polylines10.shp")); Is there a way I can inject my dispose method into that statically created object without modifying the original sourcecode?

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  • Long running method causing race condition

    - by keeleyt83
    Hi, I'm relatively new with hibernate so please be gentle. I'm having an issue with a long running method (~2 min long) and changing the value of a status field on an object stored in the DB. The pseudo-code below should help explain my issue. public foo(thing) { if (thing.getStatus() == "ready") { thing.setStatus("finished"); doSomethingAndTakeALongTime(); } else { // Thing already has a status of finished. Send the user back a message. } } The pseudo-code shouldn't take much explanation. I want doSomethingAndTakeALongTime() to run, but only if it has a status of "ready". My issue arises whenever it takes 2 minutes for doSomethingAndTakeALongTime() to finish and the change to thing's status field doesn't get persisted to the database until it leaves foo(). So another user can put in a request during those 2 minutes and the if statement will evaluate to true. I've already tried updating the field and flushing the session manually, but it didn't seem to work. I'm not sure what to do from here and would appreciate any help. PS: My hibernate session is managed by spring.

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  • How to add chain of certificate in spring ws client request

    - by hudi
    I have simply spring ws client which sending request to some url: @SuppressWarnings("unchecked") private JAXBElement<O> sendSyncSoapRequest(final JAXBElement<I> req, final String iszrUrl) { if (iszrUrl != null) { return (JAXBElement<O>) this.wsTemplate.marshalSendAndReceive(iszrUrl, req); } else { return (JAXBElement<O>) this.wsTemplate.marshalSendAndReceive(req); } } Now I need attach chain of certificate to the soap request. How should I do this ? Please help

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  • Strange IP addresses in tomcat

    - by mdev
    Some where I have this in some generic class. public static String getRequestIp (HttpServletRequest request){ String ipaddr = request.getHeader("X-FORWARDED-FOR"); if (ipaddr == null)ipaddr = request.getRemoteAddr(); return ipaddr; } For every request i call that method and in a certain moment i insert a record in a mysql database. In most cases it works normally and i can see a record for every request with a valid ip address in the right field. But sometimes where the IP should be there is something like this. "unknown, 93.186.30.120" or "10.0.1.169, 186.38.84.3" Apache is at the front listening at port 80 and used as proxy to Tomcat that listens at port 8081. My router config would not allow to pass any conection that come by any port other than 80. Any Help? Thanks in advance.

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  • Encrypt/ Secure communication Android app <-> REST webservice

    - by Ascorbin
    I want to create a backend for my android app with Tapestry5 and this http://code.google.com/p/t5-restful-webservices/ plugin. The app will communicate with the server by calling REST methods both for registered users (that would be easy to secure I guess) as well as unregistered users. Now of course I don't want people to just call that webservice from a browser. How can I make sure that only my app can make calls to this backend?

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  • Why is it not saying I won?

    - by Itachi
    This is my if statement... The buttons show up like this: This is my if statement if((buttons[3].getName()=="x" && buttons[6].getName()=="x" && buttons[9].getText()=="x")||(buttons[2].getName()=="x" && buttons[5].getName()=="x" && buttons[8].getName()=="x")|| ((buttons[1].getName()=="x") && (buttons[4].getName()=="x") && (buttons[7].getName()=="x"))){ JOptionPane.showMessageDialog(null,"X Wins"); } So if I select the 1st, 4th and 7th buttons (the left most 3 buttons) why does it not say "X Wins"? As a sidenote, yes the buttons should have the name "x"

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  • Weird behaviour of Calendar and DateFormat

    - by Nejc
    I encountered really strange behaviour when constructing a Calendar object and then formating it in a particular style. Let the code do the talking: public class Test { public static void main(String[] args) { SimpleDateFormat frmt = new SimpleDateFormat(); frmt.applyPattern("yyyy-MM-dd"); GregorianCalendar date = new GregorianCalendar(2012,1,1); System.out.println(frmt.format(date.getTime())); } } The output is: 2012-02-01 The expected output is of course: 2012-01-01 What am I doing wrong?

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  • JPA Database strcture for internationalisation

    - by IrishDubGuy
    I am trying to get a JPA implementation of a simple approach to internationalisation. I want to have a table of translated strings that I can reference in multiple fields in multiple tables. So all text occurrences in all tables will be replaced by a reference to the translated strings table. In combination with a language id, this would give a unique row in the translated strings table for that particular field. For example, consider a schema that has entities Course and Module as follows :- Course int course_id, int name, int description Module int module_id, int name The course.name, course.description and module.name are all referencing the id field of the translated strings table :- TranslatedString int id, String lang, String content That all seems simple enough. I get one table for all strings that could be internationalised and that table is used across all the other tables. How might I do this in JPA, using eclipselink 2.4? I've looked at embedded ElementCollection, ala this... JPA 2.0: Mapping a Map - it isn't exactly what i'm after cos it looks like it is relating the translated strings table to the pk of the owning table. This means I can only have one translatable string field per entity (unless I add new join columns into the translatable strings table, which defeats the point, its the opposite of what I am trying to do). I'm also not clear on how this would work across entites, presumably the id of each entity would have to use a database wide sequence to ensure uniqueness of the translatable strings table. BTW, I tried the example as laid out in that link and it didn't work for me - as soon as the entity had a localizedString map added, persisting it caused the client side to bomb but no obvious error on the server side and nothing persisted in the DB :S I been around the houses on this about 9 hours so far, I've looked at this Internationalization with Hibernate which appears to be trying to do the same thing as the link above (without the table definitions it hard to see what he achieved). Any help would be gratefully achieved at this point... Edit 1 - re AMS anwser below, I'm not sure that really addresses the issue. In his example it leaves the storing of the description text to some other process. The idea of this type of approach is that the entity object takes the text and locale and this (somehow!) ends up in the translatable strings table. In the first link I gave, the guy is attempting to do this by using an embedded map, which I feel is the right approach. His way though has two issues - one it doesn't seem to work! and two if it did work, it is storing the FK in the embedded table instead of the other way round (I think, I can't get it to run so I can't see exactly how it persists). I suspect the correct approach ends up with a map reference in place of each text that needs translating (the map being locale-content), but I can't see how to do this in a way that allows for multiple maps in one entity (without having corresponding multiple columns in the translatable strings table)...

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  • BFS Shortest Path: Edge weight either 1 or 2

    - by Hackster
    I am trying to implement a shortest path algorithm using BFS. That is I am trying to find the shortest path from a specified vertex to every other vertex. However, its a special case where all edge weights are either 1 or 2. I know it could be done with Dijkstra's algorithm but I must use Breadth First Search. So far I have a working version of BFS that searches first for a vertex connected with an edge of weight 1. If it cannot find it, then returns a vertex connected with an edge of weight 2. After thinking about it, this is not the correct way to find the shortest path. The problem is I cannot think of any reasoning why BFS would work with weights 1 or 2, as opposed to any weight. Here is the code: public void addEdge(int start, int end, int weight) { adjMat[start][end] = 1; adjMat[end][start] = 1; edge_weight[start][end] = weight; edge_weight[end][start] = weight; } // ------------------------------------------------------------- public void bfs() // breadth-first search { // begin at vertex 0 vertexList[0].wasVisited = true; // mark it displayVertex(0); // display it theQueue.insert(0); // insert at tail int v2; while( !theQueue.isEmpty() ) // until queue empty, { int v1 = theQueue.remove(); // remove vertex at head // until it has no unvisited neighbors while( (v2=getAdjUnvisitedVertex(v1)) != -1 ){// get one, vertexList[v2].wasVisited = true; // mark it displayVertex(v2); // display it theQueue.insert(v2); // insert it } } // end while(queue not empty) // queue is empty, so we're done for(int j=0; j<nVerts; j++) // reset flags vertexList[j].wasVisited = false; } // end bfs() // ------------------------------------------------------------- // returns an unvisited vertex adj to v -- ****WITH WEIGHT 1**** public int getAdjUnvisitedVertex(int v) { for (int j = 0; j < nVerts; j++) if (adjMat[v][j] == 1 && vertexList[j].wasVisited == false && edge_weight[v][j] == 1){ //System.out.println("Vertex found with 1:"+ vertexList[j].label); return j; } for (int k = 0; k < nVerts; k++) if (adjMat[v][k] == 1 && vertexList[k].wasVisited == false && edge_weight[v][k] == 2){ //System.out.println("Vertex found with 2:"+vertexList[k].label); return k; } return -1; } // end getAdjUnvisitedVertex() // ------------------------------------------------------------- } //////////////////////////////////////////////////////////////// public class BFS{ public static void main(String[] args) { Graph theGraph = new Graph(); theGraph.addVertex('A'); // 0 (start for bfs) theGraph.addVertex('B'); // 1 theGraph.addVertex('C'); // 2 theGraph.addEdge(0, 1,2); // AB theGraph.addEdge(1, 2,1); // BC theGraph.addEdge(2, 0,1); // AD System.out.print("Visits: "); theGraph.bfs(); // breadth-first search System.out.println(); } // end main() } The problem then is, that I don't know why BFS can work for the shortest path problem with edges of weight 1 or 2 as opposed to any edges of any weight. Any help is appreciated. Thanks!

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  • Read quicktime movie from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\\TEMP\\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using embed or object tag to read the media stream from the response? Here is my code in the servlet: public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getParameter("location"); uploadFile(response); } private void uploadFile(HttpServletResponse response) { File transferFile = new File("C:/TEMP/captured.mov"); FileInputStream in = null; try { in = new FileInputStream(transferFile); } catch (FileNotFoundException e) { System.out.println("File not found"); } try { System.out.println("in byes i s" + in.available()); } catch (IOException e) { } DataOutputStream responseStream = null; try { responseStream = new DataOutputStream(response.getOutputStream()); } catch (IOException e) { System.out.println("Io exception"); } try { Util.copyStream(in, responseStream); } catch (CopyStreamException e) { System.out.println("copy Stream exception"); } try { responseStream.flush(); } catch (IOException e) { } try { responseStream.close(); } catch (IOException e) { } } And here is html page as Ryan suggested: <embed SRC="http://localhost:7101/movies/transferservlet" WIDTH=100 HEIGHT=196 AUTOPLAY=true CONTROLLER=true LOOP=false PLUGINSPAGE="http://www.apple.com/quicktime/"> Any ideas?

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  • abstract class need acces to subclass atribute

    - by user1742980
    I have a problem with my code. public abstract class SimplePolygon implements Polygon { ... public String toString(){ String str = "Polygon: vertices ="; for(int i = 0;i<varray.length;i++){ str += " "; str += varray[i]; } return str; } } public class ArrayPolygon extends SimplePolygon { private Vertex2D[] varray; public ArrayPolygon(Vertex2D[] array){ varray = new Vertex2D[array.length]; if (array == null){} for(int i = 0;i<array.length;i++){ if (array[i] == null){} varray[i] = array[i]; } ... } Problem is, that i'm not allowed to add any atribute or method to abstract class SimplePolygon, so i'cant properly initialize varray. It could simply be solved with protected atrib in that class, but for some (stupid) reason i'cant do that. Has anybody an idea how to solve it without that? Thanks for all help.

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  • Problem inretrieving the name field in symbian using j2me

    - by learn
    I have added the firstname, middlename, lastname, suffix, prefix in symbian and now i want to retrieve each of this attributes of name. I am getting the firstname and lastname together by if(contactlist.isSupportedField(Contact.FORMATTED_NAME) && contact.countValues(Contact.FORMATTED_NAME)0) { mycontact.setName(contact.getString(Contact.FORMATTED_NAME, 0)); }

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