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  • Anyone have a good solution for scraping the HTML source of a page with content (in this case, HTML

    - by phpwns
    Anyone have a good solution for scraping the HTML source of a page with content (in this case, HTML tables) generated with Javascript? An embarrassingly simple, though workable solution using Crowbar: <?php function get_html($url) // $url must be urlencode(d) { $context = stream_context_create(array( 'http' => array('timeout' => 120) // HTTP timeout in seconds )); $html = substr(file_get_contents('http://127.0.0.1:10000/?url=' . $url . '&delay=3000&view=browser', 0, $context), 730, -32); // substr removes HTML from the Crowbar web service, returning only the $url HTML return $html; } ?> The advantage to using Crowbar is that the tables will be rendered (and accessible) thanks to the headless mozilla-based browser. The problem, of course, is being dependent on on an external web service, especially given that SIMILE seems to undergo regular server maintenance. :( A pure php solution would be nice, but any functional (and reliable) alternatives would be great.

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  • Check if table exists

    - by Dmitry
    I have a desktop application with a database embedded in it. When I execute my program I need to check that specific table exists, or create it if not. Given a Connection object named conn for my database, how could I check this?

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  • about Sorting Algorithms

    - by matin1234
    Hi I want to know that we always use Sorting algorithm like (Insertion Sort or Merge Sort,...) just for lists and arrays?? and we do not use these algorithms for stack or queue ??? thanks

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  • How do I retain a requested url with parameters after redirecting to a login page?

    - by Brent Parker
    I have been asked to set up some authentication for some content on our website using JSP. What I would like to do seems simple to me but I can't quite figure out how to do it in JSP. What I would like to do is this: When a user requests a page that you must be logged in to see, I have a tag that checks their cookies for an authentication token. If it is not there, they are redirected to a login page. After they log in, I want to redirect them back to the page they first requested along with any parameters they were sending. Now, I have the tag that is checking their authentication and redirecting them to the login page. That part is working just fine. But I'm not sure how to maintain the first requested url and parameters so they can be redirected after they login. How might I accomplish this?

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  • Arrays not matching correctly

    - by Nick Gibson
    userAnswer[] holds the string of the answer the user types in and is comparing it to answers[] to see if they match up and then spits out correct or wrong. j is equal to the question number. So if j was question 6, answers[j] should refer to answers[6] right? Then userAnswer[6] should compare to answers[6] and match if its correct. But its giving me wrong answers and displaying the answer I typed as correct. int abc, loopCount = 100; int j = quesNum, overValue, forLoop = 100; for (int loop = 1; loop < loopCount; loop++) { aa = r.nextInt(10+1); abc = (int) aa; String[] userAnswer = new String[x]; JOptionPane.showMessageDialog(null,abc); if(abc < x) { userAnswer[j] = JOptionPane.showInputDialog(null,"Question "+quesNum+"\n"+questions[abc]+"\n\nA: "+a[abc]+"\nB: "+b[abc]+"\nC: "+c[abc]+"\nD: "+d[abc]); if(userAnswer[j].equals(answers[j])) { JOptionPane.showMessageDialog(null,"Correct. \nThe Correct Answer is "+answers[abc]); } else { JOptionPane.showMessageDialog(null,"Wrong. \n The Correct Answer is "+answers[abc]); }//else }//if }//for

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  • checking boolean property in XML(Spring)

    - by Abhishek Bhandari
    I am using Spring Framework . While writing coustum SQL queries , i am unable check a parameter of boolean value. For example this is not working .. do some SQl cods The above checking is not working , it is evaluating as equal in both the cases when booleanVariable is true and false . i tried to replace compareValue ="tree" and "false". As that is a monkey work i do sometimes . is it possible to check the boolean property in XML like above .

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  • Using custom detectors with FindBugs Maven plugin

    - by Lóránt Pintér
    I have a nice JAR of some custom FindBugs detectors I'd like to use with the FindBugs Maven plugin. There is a way to do this with the plugin via the <pluginList> configuration parameter, but that only accepts local files, URLs, or resources. The only way I found for doing so is to somehow copy my JAR to a local file (maybe via the Dependency plugin) and then configure the FindBugs plugin something like this: <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>findbugs-maven-plugin</artifactId> <version>2.3.1</version> <configuration> <pluginList>${project.build.directory}/my-detectors.jar</pluginList> </configuration> </plugin> But this is not very flexible. Is there a way to use Maven's dependency management features together with FindBugs' plugins? I'd like to use something like this: <plugin> <groupId>org.codehaus.mojo</groupId> <artifactId>findbugs-maven-plugin</artifactId> <dependencies> <dependency> <groupId>com.lptr.findbugs</groupId> <artifactId>my-detectors</artifactId> <version>1.0</version> </dependency> </dependencies> </plugin> ...but this simply overrides the core FindBugs detectors.

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  • Where to handle fatal exceptions

    - by Stephen Swensen
    I am considering a design where all fatal exceptions will be handled using a custom UncaughtExceptionHandler in a Swing application. This will include unanticipated RuntimeExceptions but also custom exceptions which are thrown when critical resources are unavailable or otherwise fail (e.g. a settings file not found, or a server communication error). The UncaughtExceptionHandler will do different things depending on the specific custom exception (and one thing for all the unanticipated), but in all cases the application will show the user an error message and exit. The alternative would be to keep the UncaughtExceptionHandler for all unanticipated exceptions, but handle all other fatal scenarios close to their origin. Is the design I'm considering sound, or should I use the alternative?

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  • Strange behavior while returning csv file from spring controller

    - by Fanooos
    I working in a spring application which have an action method that returns a CSV file. This action works fine but in some cases it throws a predefined exception (MyAppException). I have another method that is annotated @ExceptionHandler(MyAppException.class) In the exception handler method I return another csv file but with different contents. The code that returns the csv file is almost the same in the two methods. List<String[]> list= new ArrayList<String[]>(); list.add(new String[]{ integrationRequestErrorLog.getErrorMessage(), Long.toString(integrationRequestErrorLog.getId()), Integer.toString(integrationRequestErrorLog.getErrorCode()) }); CSVWriter writer = new CSVWriter(response.getWriter(), ','); writer.writeAll(list); writer.close(); the difference between the two method is the list of contents. In the first method the file is returned normally while in the exception handler method I have a strange behavior. The exception handler method works fine with Opera browser while it gives me a 404 with FireFox. Opera browser give me 404 also but it download the file while firefox does not? Really I do not understand what is the difference here.

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  • regular expression and escaping

    - by pstanton
    Sorry if this has been asked, my search brought up many off topic posts. I'm trying to convert wildcards from a user defined search string (wildcard is "*") to postgresql like wildcard "%". I'd like to handle escaping so that "%" => "\%" and "\*" => "*" I know i could replace \* with something else prior to replacing * and then swap it back, but i'd prefer not to and instead only convert * using a pattern that selects it when not proceeded by \. String convertWildcard(String like) { like = like.replaceAll("%", "\\%"); like = like.replaceAll("\\*", "%"); return like; } Assert.assertEquals("%", convertWildcard("*")); Assert.assertEquals("\%", convertWildcard("%")); Assert.assertEquals("*", convertWildcard("\*")); // FAIL Assert.assertEquals("a%b", convertWildcard("a*b")); Assert.assertEquals("a\%b", convertWildcard("a%b")); Assert.assertEquals("a*b", convertWildcard("a\*b")); // FAIL ideas welcome.

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  • Revalidate JPanel's parent frame

    - by Tom Brito
    I need show/hide some fields of my panel, and I want the panel to fit the frame. How could I notify to the parent frame to revalidate? I think in pass the frame to my panel's constructor, but I think may have a way this is already done. I remember that there was a protected attribute in JPanel, but there isn't.. maybe i remembering the wrong component.

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  • How can I get the name of all tables in a JavaDB database?

    - by Jonas
    How can i programmatically get the names of all tables in a JavaDB database? Is there any specific SQL-statement over JDBC I can use for this or any built in function in JDBC? I will use it for exporting the tables to XML, and would like to do it this way so I don't miss any tables from the database when exporting.

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  • Return type value if RunTimeException has been thrown and not catched.

    - by Alfred
    I am using Gson to parse Json. What I don't understand what the return type will be if you don't catch the Runtime Exception. I was expecting it to be null, but it is not null when evaluating with a simple if statement. My code looks something like this: public X x() { return gson.fromJson(jsonString, X.class); } then from another function I call the function: public void y() { final X x = x(); if (x == null) { System.out.println("x == null") } } I was expecting x to be null, but it isn't because the print statement is not called? What is the value of x? How can if them. I have my problem by using a catch block in the x() function and returning null. But I am just wondering what the value of function x() is(if any?)? Hopefully I make any sense at all.

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  • getResourceAsStream returns HttpInputStream not of the entire file

    - by khue
    Hi, I am having a web application with an applet which will copy a file packed witht the applet to the client machine. When I deploy it to webserver and use: InputStream in = getClass().getResourceAsStream("filename") ; The in.available() always return a size of 8192 bytes for every file I tried, which means the file is corrupted when it is copied to the client computer. The InputStream is of type HttpInputStream (sun.net.protocol.http.HttpUrlConnection$httpInputStream). But while I test applet in applet viewer, the files are copied fine, with the InputStream returned is of type BufferedInputStream, which has the file's byte sizes. I guess that when getResourceStream in file system the BufferedInputStream will be used and when at http protocol, HttpInputStream will be used. How will I copy the file completely, is there a size limited for HttpInputStream? Thanks a lot.

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  • Timeout Exceptions

    - by Raihan Jamal
    This is my below code, I am confuse why this thing is happening. In this code getLocationByIpTimeout is a method in which I am passing two things- one is the ip address and second is the timeout. So I will get the timeout exception if the response is not getting back in under 5 ms. So when I ran this below code, I am getting few timeout exceptions but the most important thing that I am confuse is if I am getting timeout exceptions (time taken to get the response is greater than 5 ms) then why the program is entering in that if loop in which I am having difference 5. What can be the possible reason for this? It is because of catch block?? Any suggestions will be appreciated. long runs =10000; long difference = 0; while(runs > 0) { String ipAddress = generateIPAddress(); long start_time = System.nanoTime(); try { resp = PersonalizationGeoLocationServiceClientHelper.getLocationByIpTimeout(ipAddress, 5); } catch (TimeoutException e) { System.out.println("Timeout Exception"); } long end_time = System.nanoTime(); if(resp == null || (resp.getLocation() == null)) { difference = 0; } else if(resp.getLocation() != null) { difference = (end_time - start_time)/1000000; } if(difference> 5) { System.out.println("Debug"); } }

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  • Exception handling in Iterable

    - by Maas
    Is there any way of handling -- and continuing from -- an exception in an iterator while maintaining the foreach syntactic sugar? I've got a parser that iterates over lines in a file, handing back a class-per-line. Occasionally lines will be syntactically bogus, but that doesn't necessarily mean that we shouldn't keep reading the file. My parser implements Iterable, but dealing with the potential exceptions means writing for (Iterator iter = myParser.iterator(); iter.hasNext(); ) { try { MyClass myClass = iter.next(); // .. do stuff .. } catch (Exception e) { // .. do exception stuff .. } } .. nothing wrong with that, but is there any way of getting exception handling on the implicit individual iter.next() calls in the foreach construct?

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  • oracle connectivity

    - by jayprakash
    String serverName = "127.0.0.1"; String portNumber = "1521"; String sid = "database"; String url = "jdbc:oracle:thin:@" + serverName + ":" + portNumber + ":" + sid; String username = "scott"; String password = "tiger"; connection = DriverManager.getConnection(url, username, password); Could not connect to the database

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  • Determining if a coordinate is on a line

    - by TGCBraun
    I´m coding a little app that allows the user to draw multiple shapes and then remove or resize them. It´s working perfectly on rectangles and ovals, but I´m having issues with lines. Here´s a method that I wrote to find if the clicked spot on the screen is part of a specific line: public boolean containsLocation(int x, int y) { int m = (getY2() - getY()) / (getX2() - getX()); int b = getY() - (m * getX()); if (y == (m * x) + b) { return true; } return false; I´m using the famous y = mx + b formula and replacing y and x to find if the clicked spot is part of the line. The problem is when I click on the screen to remove the line, it only works if I click on the very fist coordinate (x,y) where the line starts. Nothing happens when I click anywhere else along the line. Can anyone shed a light on what I´m doing wrong? Thanks a lot.

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