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• How to do a join of 3 files with awk by first Column?

  - by noinflection

  i have three similar files, they are all like this: ID1 Value1a ID2 Value2a . . . IDN Value2n and i want an output like this ID1 Value1a Value1b Value1c ID2 Value2a Value2b Value2c ..... IDN ValueNa ValueNb ValueNc Looking to the first line i want value1A to be the value of id1 in fileA, value1B the value of id1 in fileB, etc, i think of it like a nice sql join. I've tried several things but none of them where even close.

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• bruteforce script

  - by oshirowanen

  I have forgotten my passphrase for my gpg key on linux. Can someone please help me write a simple script to use bruteforce to crack the key? I remember show of the words which MIGHT be in the passphrase, so hopefully, it will not take long for my computer to bruteforce it. All is not lost of I can't recover the passphrase, it just means I will not be able to work on my project for the next 10 days until I get back to work to get another copy of the files, but this time with a new key for which I will remember to passphrase.

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• sed to insert on first match only

  - by SS.

  UPDATED: Using sed, how can I insert (NOT SUBSTITUTE) a new line on only the first match of keyword for each file. Currently I have the following but this inserts for every line containing Matched Keyword and I want it to only insert the New Inserted Line for only the first match found in the file: sed -ie '/Matched Keyword/ i\New Inserted Line' *.* For example: Myfile.txt: Line 1 Line 2 Line 3 This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6 changed to: Line 1 Line 2 Line 3 New Inserted Line This line contains the Matched Keyword and other stuff Line 4 This line contains the Matched Keyword and other stuff Line 6

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• Uninstall Git completely on Ubuntu?

  - by Millisami

  I installed Git on Ubuntu Lucid (latest) manually as following. cd ~/tmp wget http://kernel.org/pub/software/scm/git/git-1.7.0.6.tar.gz tar -xzvf git-1.7.0.6.tar.gz cd git-1.7.0.6.tar.gz ./configure sudo make sudo make install Now, how can I completely uninstall it?

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• How to create program that can be run by: #service myservice start

  - by Saif Bechan

  I am new to Linux and want to know what kind of programs can be run by using. #service myservice start And the programs stays on until stopped. Are they normal c++ programs or are they different. In some tutorials i have seen that they use ./myprogram to start a program. Another thing I have seen is the usage of .sh files. One last type of program i see is executed by the command: #/usr/bin/myprogramm Can someone explain the difference between these or point me to a basic tutorial/guide.

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• select fields with sed

  - by Samantha

  Hey, Using only grep and sed, is there a way I can tranform the output of ls -l * into this : -rw-r--r-- agenda.txt -rw-r--r-- annuaire.txt Thanks!

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• I write barely functional scripts that tend to not be resuable and make the baby jesus cry. Please h

  - by maxxpower

  I received a request to add around 100 users to a linux box the users are already in ldap so I can't just use newusers and point it at a text file. Another admin is taking care of the ldap piece so all I have to do is create all the home directories and chown them to the correct user once he adds the users to the box. creating the directories isn't a problem, but I'd like a more elegant script for chowning them to the correct user. what I have currently basically looks like chown -R testuser1 testgroup1 /home/tetsuser1; chown -R testuser2 testgroup2 /home/testgroup2; chown -R testsuser3 testgroup1 /home/testuser3 bascially I took the request that the user name and group name popped it into excel added a column of "chown -R" to the front, then added a column of "/", copied and pasted the username column after it and then added a column of ";" and dragged it down to the second to last row. Popped it into notepad ran some quick find and replaces and in less than a minute I have a completed request and a sad empty feeling. I know this was a really ghetto method and I'm trying to get away from using excel to avoid learning new scripting techniques so here's my real question. tl;dr I made 100 home directories and chowned them to the correct users, but it was ugly. Actual question below. You have a file named idlist that looks like this (only with say 1000 users and real usernames and groups) testuser1 testgroup1 testuser2 testgroup2 testuser3 testgroup1 write a script that creates home directories for all the users and chowns the created directories to the correct user and group. To make the directories I used the following(feel free to flame/correct me on this as well. ) var= 'cut -f1 -d" " idlist' (I used backticks not apostrophes around the cut command) mkdir $var

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• Replace delimited block of text in file with the contents of another file

  - by rmarimon

  I need to write a simple script to replace a block of text in a configuration file with the contents of another file. Let's assume with have the following simplified files: server.xml <?xml version='1.0' encoding='UTF-8'?> <Server port="8005" shutdown="SHUTDOWN"> <Service name="Catalina"> <Connector port="80" protocol="HTTP/1.1"/> <Engine name="Catalina" defaultHost="localhost"> <!-- BEGIN realm --> <sometags/> <sometags/> <!-- END realm --> <Host name="localhost" appBase="webapps"/> </Engine> </Service> </Server> realm.xml <Realm className="org.apache.catalina.realm.UserDatabaseRealm" resourceName="UserDatabase"/> I want to run a script and have realm.xml replace the contents between the <!-- BEGIN realm --> and <!-- END realm --> lines. If realm.xml changes then whenever the script is run again it will replace the lines again with the new contents of realm.xml. This is intended to be run in /etc/init.d/tomcat on startup of the service on multiple installations on which the realm is going to be different. I'm not so sure how can I do this simply with awk or sed.

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• Using a dictionary file with sed

  - by Winston

  I have a blacklist.txt file that contains keywords I want to remove using sed. Here's what the blacklist.txt file contain winston@linux ] $ cat blacklist.txt obscure keywords here ... And here's what I have so far, but currently doesn't work. blacklist=$(cat blacklist.txt); output="filtered_file.txt" for i in $blacklist; do cat $input | sed 's/$i//g' >> $output done

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• grep 5 seconds of input from the serial port inside a shell-script

  - by pica

  I've got a device that I'm operating next to my PC and as it runs it's spitting log lines out it's serial port. I have this wired to my PC and I can see the log lines fine if I'm using either minicom or something like: ttylog -b 115200 -d /dev/ttyS0 I want to write 5 seconds of the device serial output to a temp file (or assign it to a variable) and then later grep that file for keywords that will let me know how the device is operating. I've already tried redirecting the output to a file while running the command in the background, and then sleeping 5 seconds and killing the process, but the log lines never get written to my temp file. Example: touch tempFile ttylog -b 115200 -d /dev/ttyS0 >> tempFile & serialPID=$! sleep 5 #kill ${serialPID} #does not work, gets wrong PID killall ttylog cat tempFile The file gets created but never filled with any data. I can also replace the ttylog line with: ttylog -b 115200 -d /dev/ttyS0 |tee -a tempFile & In neither case do I ever see any log lines logged to stdout or the log file unless I have multiple versions of ttylog running by mistake (see commented out line, D'oh). I have no idea what's going on here. It seems to be a failure of redirection within my script. Am I on the right track? Is there a better way to sample 5 seconds of the serial port?

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• Dymanic if statement evaluation problem with string comparison

  - by Mani

  I tried the example given in http://forums.sun.com/thread.jspa?threadID=780576&tstart=67605 to create if statement dynamically. But it is not working fine. Instead of using "age" variable as integer, i have used string in the below example. I am getting "fail" as answer instead of "success". Can anyone help me? / To change this template, choose Tools | Templates and open the template in the editor. / import java.lang.reflect.*; import bsh.Interpreter; public class Main { public static String d; public static void main(String args[]) { try { String age = "30"; String cond = "age==30"; Interpreter i = new Interpreter(); i.set("age", age); System.out.println(" sss" + i.get("age")); if((Boolean)i.eval(cond)) { System.out.println("success"); } else { System.out.println("fail"); } } catch (Throwable e) { System.err.println(e); } } } Thanks, Mani

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• Parsing the first column of a csv file to a new file.

  - by S1syphus

  Operating System: OSX Method: From the command line, so using sed, cut, gawk, although preferably no installing modules. Essentially I am trying to take the first column of a csv file and parse it to a new file. Example input file EXAMPLEfoo,60,6 EXAMPLEbar,30,6 EXAMPLE1,60,3 EXAMPLE2,120,6 EXAMPLE3,60,6 EXAMPLE4,30,6 Desire output EXAMPLEfoo EXAMPLEbar EXAMPLE1 EXAMPLE2 EXAMPLE3 EXAMPLE4 So I want the first column. Here is what I have tried so far: awk -F"," '{print $1}' in.csv > out.txt awk -F"," '{for (i=2;i<=NF;i++)}' in.csv > out.txt awk -F"," 'BEGIN { OFS="," }' '{print $1}' in.csv > out.txt cat in.csv | cut -d \, -f 1 > out.txt None seem to work, either they just print the first line or nothing at all, so I would assume it's failing to read line by line.

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• Invoking shell from java, it complaints "stty: standard input: Invalid argument"

  - by solotim

  Hi, everybody. I invoked shell command by Process class of java and it gave "stty: standard input: Invalid argument" no matter the command is right or wrong (normal output of shell command is shown too). If I run the shell command in shell, no such error message shows. I can't figure out why. Thanks

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• Trouble with piping through sed

  - by Joel

  I am having trouble piping through sed. Once I have piped output to sed, I cannot pipe the output of sed elsewhere. wget -r -nv http://127.0.0.1:3000/test.html Outputs: 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/test.html [99/99] -> "127.0.0.1:3000/test.html" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/robots.txt [83/83] -> "127.0.0.1:3000/robots.txt" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/shop [22818/22818] -> "127.0.0.1:3000/shop.29" [1] I pipe the output through sed to get a clean list of URLs: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' Outputs: http://127.0.0.1:3000/test.html http://127.0.0.1:3000/robots.txt http://127.0.0.1:3000/shop I would like to then dump the output to file, so I do this: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' > /tmp/DUMP_FILE I interrupt the process after a few seconds and check the file, yet it is empty. Interesting, the following yields no output (same as above, but piping sed output through cat): wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' | cat Why can I not pipe the output of sed to another program like cat?

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• Script telnet on webserver

  - by Kami

  Hi I would like to script telnet to test my website inputs handling. I can do it manually : telnet localhost 8888 ... GET / HTTP/1.1\n Host: localhost ...html response But I can pass command to telnet in my shell script ! I've tried : (echo "GET / HTTP/1.1\n"; echo "Host: localhost \n\n"; sleep 1) | telnet localhost 8888 It produces no results at all !

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• Is there an API for calling system scripts/programs?

  - by Zeratul

  Hi, is there something like API built atop the standard ProcessBuilder for calling system programs? I won't argue that scripts can be ported to Java but utilities like arping and netstat are good-to-go in Linux.

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• strange behavior

  - by lego69

  I wrote simple script test echo hello <-- inside test if I press one time enter after hello, my script will run, if I don't press - it will not, if two times I'll receive my hello and + command was not found, can somebody please explain me this behavior thanks in advance

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• cmake source and out-of-source navigation

  - by idimba

  Hi, cmake advises to use out-of-source builds. While in general I like the idea I find it not comfortable to navigate from out-of-source sub directory to the corresponding source directory. I frequently need the code to perform some actions with code (e.g. grep, svn command etc.). Is there an easy way in shell to navigate from out-of-source sub directory to the corresponding source directory? Thanks Dima

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• How can I prevent default_environment variables from getting set by Capistrano's sudo action?

  - by Logan Koester

  My deploy.rb sets some environment variables to use the regular user's local Ruby rather than the system-wide one. set :default_environment, { :PATH => '/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games', :RUBY_VERSION => 'ruby-1.9.1-p378', :GEM_HOME => '/home/myapp/.rvm/gems/ruby-1.9.1-p378', :GEM_PATH => '/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global' } Naturally, when a task is using sudo, I would expect the system-wide ruby to be used instead. But it seems the environment variables are being set anyway, which is obviously invalid for the root user and returns an error: executing "sudo -p 'sudo password: ' /etc/init.d/god stop" servers: ["myapp.com"] [myapp.com] executing command command finished failed: "env PATH=/home/myapp/.rvm/bin:/home/myapp/.rvm/bin:/home/myapp/.rvm/rubies/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378/bin:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global/bin:/home/myapp/bin:/usr/bin:/opt/local/bin:/opt/local/sbin:/usr/local/bin:/usr/local/sbin:/usr/sbin:/sbin:/bin:/usr/games RUBY_VERSION=ruby-1.9.1-p378 GEM_HOME=/home/myapp/.rvm/gems/ruby-1.9.1-p378 GEM_PATH=/home/myapp/.rvm/gems/ruby-1.9.1-p378:/home/myapp/.rvm/gems/ruby-1.9.1-p378%global sh -c 'sudo -p '\\''sudo password: '\\'' /etc/init.d/god stop'" on myapp.com It makes no difference whether I use capistrano's sudo "system call" or the regular run "sudo system call". How can I avoid this?

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• Redirect PHP-Shell-Script output

  - by Corelgott

  Hi Folks, i have got a php-script foo.php #!/usr/bin/php -c /etc/php5/cli/php.ini -q <?php echo 'hello'; // & do some stuff ?> I call this script not wrapped by a sh-script but using it directly in a cron job. To get rid of it's output i normally would just create a sh-file which calls /usr/bin/php -c /etc/php5/cli/php.ini -q foo.php > /dev/null 2 > /dev/null now i'd like to do this in the interpreter-declaration of the php file it self... so i am looking for the syntax for: #!/usr/bin/php -args [file's content] > /redirect 2 > /redirect i have kind of a hard time googleing for it... so if anybody could point me into the right direction i would really appreciate it! Thx in advance Corelgott

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• What happened to the TMP environment variable?

  - by Mark0978

  I always heard that the proper way to find the temporary folder on a UNIX machine was to look at the TMP environment variable. When writing code that worked on Windows as well as Linux, I would check for TEMP and TMP. Today, I discovered that my Ubuntu install does not have that environment variable at all. I know it seems you can always count on /tmp being there to put your temporary files in, but I understood that TMP was the way the user could tell you to put the temporary files someplace else. Is that still the case?

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• Getting ssh to execute a command in the background on target machine

  - by dagorym

  This is a follow-on question to the How do you use ssh in a shell script? question. If I want to execute a command on the remote machine that runs in the background on that machine, how do I get the ssh command to return? When I try to just include the ampersand (&) at the end of the command it just hangs. The exact form of the command looks like this: ssh user@target "cd /some/directory; program-to-execute &" Any ideas? One thing to note is that logins to the the target machine always produce a text banner and I have ssh keys set up so no password is required.

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• Shell - Run additional command on failure

  - by Shawn

  I have this script that I am currently running that works great for all instances but one: #!/bin/sh pdfopt test.pdf test.opt.pdf &>/dev/null pdf2swf test.opt.pdf test.swf [ "$?" -ne 0 ] && exit 2 More lines to execute follow the above code ... How would I go about changing this script to run "pdf2swf test.pdf test.swf" if "pdf2swf test.opt.pdf test.swf" fails? If the second attempt fails, then I would "exit 2". Thanks

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• Escaping Code for Different Shells

  - by Jon Purdy

  Question: What characters do I need to escape in a user-entered string to securely pass it into shells on Windows and Unix? What shell differences and version differences should be taken into account? Can I use printf "%q" somehow, and is that reliable across shells? Backstory (a.k.a. Shameless Self-Promotion): I made a little DSL, the Vision Web Template Language, which allows the user to create templates for X(HT)ML documents and fragments, then automatically fill them in with content. It's designed to separate template logic from dynamic content generation, in the same way that CSS is used to separate markup from presentation. In order to generate dynamic content, a Vision script must defer to a program written in a language that can handle the generation logic, such as Perl or Python. (Aside: using PHP is also possible, but Vision is intended to solve some of the very problems that PHP perpetuates.) In order to do this, the script makes use of the @system directive, which executes a shell command and expands to its output. (Platform-specific generation can be handled using @unix or @windows, which only expand on the proper platform.) The problem is obvious, I should think: test.htm: <!-- ... --> <form action="login.vis" method="POST"> <input type="text" name="USERNAME"/> <input type="password" name="PASSWORD"/> </form> <!-- ... --> login.vis: #!/usr/bin/vision # Think USERNAME = ";rm -f;" @system './login.pl' { USERNAME; PASSWORD } One way to safeguard against this kind of attack is to set proper permissions on scripts and directories, but Web developers may not always set things up correctly, and the naive developer should get just as much security as the experienced one. The solution, logically, is to include a @quote directive that produces a properly escaped string for the current platform. @system './login.pl' { @quote : USERNAME; @quote : PASSWORD } But what should @quote actually do? It needs to be both cross-platform and secure, and I don't want to create terrible problems with a naive implementation. Any thoughts?

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• How do I create a Launcher in Ubuntu 9.1 that runs a shell script?

  - by mkelley33

  Here's my situation: New to Ubuntu (just nstalled 9.10 Karmic Koala 64 bit) Purpose: to easily run PyCharm without too much typing (ie. cd... ./pycharm.sh) Want to create desktop Launcher instead of terminal & typing (without resorting to the "Run in Terminal" option) Tried to create Launcher to executes .sh script in Document directory Right-clicked Desktop Create Launcher a. Type == Application; Browse [insert absolute path to .sh script]; no luck b. Type == Application in Terminal; Browse ...ditto I'm open to any other alternatives that involve as little typing as possible. I would like to just start Ubuntu, click Launcher icons, and have terminals spring to life, running the intended scripts. Crazy? No. Lazy? Probably. Productive? Hopefully :)

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