Search Results

Search found 39497 results on 1580 pages for 'two shoes'.

Page 94/1580 | < Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101  | Next Page >

  • adding two variables together

    - by James Trusler
    I have been trying for... about 4 hours now lmao. currentCalc returns 50 currentSum returns 0 when i alert them. Yet I cannot add them together with parseInt???? what am i doing wrong :'( var identRow = $('tr.identRow'); identRow.each( function(){ var getIdentClass = $(this).attr('class').split(' ').slice(1); $('tr.ohp' + getIdentClass + ' td.EURm').each( function(index){ var currentCalc = parseInt($(this).text().replace('.',''), 10); var currentSum = $('tr.' + getIdentClass + ' td.totalEURm', this).text().replace('.',''); total = parseInt(currentCalc, 10) + parseInt(currentSum, 10); $('tr.' + getIdentClass + ' td.totalEURm').text(total); if (index==6){ alert(total); } } ); } );

    Read the article

  • how to POST two strings?

    - by Garrith
    Im trying to create a POST method for my AddTagtoGroup which looks like this (altho still confused as string group never seems to be used): List<Group> Groups = new List<Group>(); List<Tag> tags = new List<Tag>(); public void AddTagtoGroup(string group, string tag) { var result = Groups.Where(n => String.Equals(n.GroupName, tag)).FirstOrDefault(); if (result != null) { result.Tags.Add(new Tag() { TagName = tag }); } } My data contracts looks like this: [DataContract(Name = "Group")] public class Group { public Group() // not sure if this has to have a datamember { Tags = new List<Tag>(); } [DataMember(Name = "GroupName")] public string GroupName { get; set; } public List<Tag> Tags { get; set; } // datamember or not? } [DataContract(Name = "Tag")] public class Tag { [DataMember(Name = "TagName")] public string TagName { get; set; } } And my post method looks like this but im unsure what to put in the uri template? [OperationContract] [WebInvoke(Method = "POST", BodyStyle = WebMessageBodyStyle.Bare, RequestFormat = WebMessageFormat.Xml, ResponseFormat = WebMessageFormat.Xml, UriTemplate = "/AddTagtoGroup{group}{tag}")] void AddTagtoGroup(string group, string tag);

    Read the article

  • Returning two or more values from a function

    - by cf_PhillipSenn
    I need to return multiple values from a ColdFusion function in an ajax callback function. Here's what I've got: $('input[name="StateName"]').live('change', function() { var StateID = $(this).parents('tr').attr('id'); var StateName = $(this).val(); $.ajax({ url: 'Remote/State.cfc' ,type: "POST" ,data: { 'method': 'UpdateStateName' ,'StateID': StateID ,'StateName': StateName } ,success: function(result){ if (isNaN(result)) { $('#msg').text(result).addClass('err'); } else { $('#' + result + ' input[name="StateName"]').addClass('changed'); }; } ,error: function(msg){ $('#msg').text('Connection error').addClass('err'); } }); }); If I trap a database error, then the success callback is fired, and the result is Not a Number (It is in fact, the text of the error message). I need the function to also pass back other values. One might be the primary key of the row that caused the error. Another might be the old StateName, so that I can refresh the old value on the screen so that the client will know absolutely for sure that their change did not take effect. I guess I'm breaking the rule of atomicity here and need to fix that, because I'm using result as both the primary key of the row that was updated, or it's the error message if the update fails. I need to return both the primary key and the error message.

    Read the article

  • Command button requires two clicks (sometimes)

    - by Shelly
    i am using icefaces 1.8.2. For some command buttons, sometimes i need to click the button twice. previously whole applivcation was working fine with single click. after upgrade to 1.8.2,i am facing this problem......Any suggestion,what could be the reason??? Thanks

    Read the article

  • How to synchronize two DataBase Schemas Oracle 10G?

    - by gnash-85
    Hi Masters, Good Day, I am new and very naive to Oracle DB. I am using Oracle 10G. Let me explain to you. I have one source database named ( DB1) and Target Database named (DB2). I have 2 schema's named dbs1 and dbs2 in the source database (DB1). I have exported both the database schemas in Source Database (DB1) and imported it successfully into the Target Database (DB2). Now I face a challenge in synchronizing these database schemas every time from Source DB (DB1) to Target DB (DB2). Can anyone please help in letting me know how can achieve this synchronization? It would a great help. Thanks Nash

    Read the article

  • How can I split the suckerfish Menu into two pieces so that I can put it in two frame?

    - by Kai
    I found a tutorial for developing multi-level drop down menu here.Its demo can be checked at www.kriesi.at/wp-content/extra_data/suckerfish_tutorial/step4.html#. I would like to enhance it to support cross-frames . It means, the horizontal part of the whole menu (html,css,javascript etc..in demo page) will exist in the upper frame and the rest will be put in the lower frame. Edit: There will be only one menu item in the horizontal part. It will be still ok if I can click that menu_item rather than mouse-hovering to show the lower part of the menu . Any idea will be appreciated. Thanks.

    Read the article

  • For improving the join of two wave files

    - by kaki
    i want to get the values of the last 30 frames of the first wav file and first thirty frames of the second wave file in integer format and stored in a list or array. i have written the code for joining but during this manupalation i am getting in byte format and tried to convert it to integer but couldn't. as told before i want to get the frame detail of 1st 30 and last 30 in integer format,and by performing other operations join can be more successful looking for your help in this,please... thanking you, import wave m=['C:/begpython/S0001_0002.wav', 'C:/begpython/S0001_0001.wav'] i=1 a=m[i] infiles = [a] outfile = "C:/begpython/S0001_00367.wav" data= [] data1=[] for infile in infiles: w = wave.open(infile, 'rb') data1=[w.getnframes] #print w.readframes(100) data.append( [w.getparams(), w.readframes(w.getnframes())] ) #print w.readframes(1) #data1 = [ord(character) for character in data1] #print data1 #data1 = ''.join(chr(character) for character in data1) w.close() print data output = wave.open(outfile, 'wb') output.setparams(data[0][0]) output.writeframes(data[0][1]) output.writeframes(data[1][1]) output.writeframes(data[2][1]) output.close()

    Read the article

  • Switch two items in associative array PHP

    - by user280381
    Example: $arr = array('apple'='sweet','grapefruit'='bitter','pear'='tasty','banana'='yellow'); I want to switch the positions of grapefruit and pear, so the array will become 'apple'='sweet','pear'='tasty','grapefruit'='bitter','banana'='yellow') I know the keys and values of the elements I want to switch, is there an easy way to do this? Or will it require a loop + creating a new array? Thanks

    Read the article

  • Having two sets of input combined on hadoop

    - by aeolist
    I have a rather simple hadoop question which i'll try to present with an example say you have a list of strings and a large file and you want each mapper to process a piece of the file and one of the strings in a grep like program. how are you supposed to do that? I am under the impression that the number of mappers is a result of the inputsplits produced. I could run subsequent jobs, one for each string, but it seems kinda... messy?

    Read the article

  • mysql join on two indexes takes long time!!

    - by Alaa
    Hi All I have a custom query in dripal, this query is: select count(distinct B.src) from node A, url_alias B where concat('node/',A.nid)= B.src; now, nid in node is primary key and i have made src as an index in url_alias table. after waiting for more than a minute i got this: +-----------------------+ | count(distinct B.src) | +-----------------------+ | 325715 | +-----------------------+ 1 row in set (1 min 24.37 sec) now my question is: why did this query take this long, and how to optimize it?? Thanks for your help

    Read the article

  • AlertDialog not showing two buttons.

    - by jfalexvijay
    Hi AlertDialog not showing send button. Below is the code. Please tell me what mistake I have made in my code. protected Dialog onCreateDialog(int id) { final AlertDialog.Builder dialog = new AlertDialog.Builder(this); dialog.setMessage("Enter Holla message"); EditText hollaMessage = new EditText(this); dialog.setView(hollaMessage); dialog.setCancelable(false); dialog.setPositiveButton("Send", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int id) { List result = new ArrayList(); } }); dialog.setPositiveButton("Cancel", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int which) { dismissDialog(0); } }); AlertDialog alert = dialog.create(); return alert; }

    Read the article

  • Printing Two Dimensional Array in Special Format

    - by user554313
    Hello everybody, I am working in a small task that allow the user to enter the regions of any country and store them in one array. Also, each time he enters a region, the system will ask him to enter the neighbours of that entered region and store these neighbours. I did the whole task but I have a small problem: I could not be able to print each region and its neighbours like the following format: Region A: neighbour1 neighbour2 Region B: neighbour1 neighbour2 For example, let us take USA map. I want to print the result as following: Washington D.C: Texas, Florida, Oregon and so on. My code is: import java.io.*; import java.util.Arrays; import java.util.Scanner; public class Test7{public static void main(String[] args) { Scanner kb = new Scanner(System.in); System.out.print("Please enter the number of regions: "); int REGION_COUNT = kb.nextInt(); String[] regionNames = new String[REGION_COUNT]; String[][] regions = new String[REGION_COUNT][2]; for (int r = 0; r < regions.length; r++) { System.out.print("Please enter the name of region #" + (r + 1) + ": "); regionNames[r] = kb.next(); System.out .print("How many neighbors for region #" + (r + 1) + ": "); if (kb.hasNextInt()) { int size = kb.nextInt(); regions[r] = new String[size]; for (int n = 0; n < size; n++) { System.out.print("Please enter the neighbour #" + (n) + ": "); regions[r][n] = kb.next(); } } else System.exit(0); } for (int i = 0; i < REGION_COUNT; i++) { System.out.print(regionNames[i] +": "); for (int k = 0; k < 2; k++) { System.out.print(regions[i][k]+", "); } System.out.println(); } } }

    Read the article

  • Is it possible to add two nodes at a time dynamically to a treeview

    - by Dorababu
    I am having a tree-view on my main form with initially some nodes as follows ACH |-> some.txt |->FileHeader |->BatchHeader Now at this point i will have to add 2 child nodes at a time to BatchHeader. This nodes i will pass as strings from child forms My sample code that i added some nodes is as follows public void loadingDatafrom(string filename, bool str) { if (Append.oldbatchcontrol != filename) { if (tvwACH.SelectedNode.Text == "FileHeader") { tvwACH.SelectedNode.Nodes.Add(filename); } if (tvwACH.SelectedNode.Text == "BatchHeader" && filecontrolvariables.m_gridclick == false) { tvwACH.SelectedNode.Nodes.Add(filename); **I got this idea tvwach.SelectedNode.Lastnode.Nodes.Add("Node");** } } } Can any one give an idea to add 2 nodes as child to the existing node ..

    Read the article

  • Specifying $(this).val() for two different elements (by class)

    - by Chaya Cooper
    What would be the correct syntax for specifying 2 elements by class to evaluate their values when they have different classes? This snippet adds and/or removes values from "increase_priority1" when the user has selected both a complaint and ranked the importance level of the issue, however when I added the 2nd element (".complaint select") to the If Statement it stopped working properly and only accepts input from the 2nd item (Waist) after the 1rst item (Shoulders) has been selected. I believe the problem is that it's unable to determine which ".complaint select" to use, but I haven't been able to figure out how to use (this) for the 2nd element, or another similar approach. The complete function includes apx. 20 similar pairs of If Statements to set & unset other elements, and a working example with 4 pairs is available at http://jsfiddle.net/chayacooper/vWLEn/168/ I'm trying to avoid using ID's because that becomes pretty cumbersome to do for 25 Select elements and each of their values (ID's were also problematic because it stopped working when I added a 2nd element to the If Statement for removing/unsetting a value) Javascript var $increase_priority1 = $(".increase_priority1"); // If value is "Shoulders", complaint was Shoulders too small (select name=Shoulders value=Too_small) and it was assigned a level 1 priority (select class="ranking shoulders" value=1). // var's for other issues and priority levels go here $(".ranking, .complaint select").change(function() { var name = $(this).data("name"); //get priority name if ($(".complaint select").val() === "Too_small" && $(this).val() == 1 && !$(this).data("increase_priority1")) { //rank is 1, and not yet added to priority list $("<option>", {text:name, val:name}).appendTo($increase_priority1); $(this).data("increase_priority1", true); //flag as a priority item } if ($(this).data("increase_priority1") && ($(this).val() != 1 || $(".complaint select").val() != "Too_small")) { //is in priority list, but now demoted $("option[value=" + name + "]", $increase_priority1).remove(); $(this).removeData("increase_priority1"); //no longer a priority item } // Similar If Statements to set & unset other elements go here }); HTML <div> <label>To Increase - 1rst Priority <select name="modify_increase_1rst[]" class="increase_priority1" multiple> </select></label> </div> <div> <span class="complaint"> <label>Shoulders</label> <select name=Shoulders> <option value="null">Select</option><option value="Too_small">Too Small</option><option value="Too_big">Too Big</option><option value="Too_expensive">Too expensive</option> </select> </span> <label>Ranking</label> <select name="importance_bother_shoulders" class="ranking shoulders" data-name="Shoulders"> <option value="Null">Select</option><option value="1">1</option><option value="2">2</option><option value="3">3</option><option value="4">4</option> <option value="5">5</option> </select> </div> <div> <span class="complaint"> <label>Waist</label> <select name=Waist> <option value="null">Select</option><option value="Too_small">Too Small</option><option value="Too_big">Too Big</option><option value="Too_expensive">Too expensive</option> </select> </span> <label>Ranking</label> <select name="importance_bother_waist" class="ranking waist" data-name="Waist"> <option value="Null">Select</option><option value="1">1</option><option value="2">2</option><option value="3">3</option><option value="4">4</option> <option value="5">5</option> </select> </div>

    Read the article

  • Rails - inheritance hierarchy of classes where an subtipe can play two roles

    - by Miquel
    I need to model Owners and Rentees in an application, so you have stuff that is always owned by someone and can be rented for someone else. I first approached this problem with Single Table Inheritance because both types of person will share all attributes, so you would have a model called Person associated to a table people with Owner and Rentee inheriting from Person. The problem is that Single type inheritance discerns subtypes using a field type and therefore a record in the table can represent either an Owner or a Rentee but not both at the same time, while in the real context you can have an Owner which is renting something from another Owner and therefore that person is at the same time an Owner and a Rentee. How would you approach this problem? Would you use separated tables fro owners and rentees? Is there any other type of table inheritance in Rails?

    Read the article

  • Sql Get months Name between two dates in a table

    - by user2219210
    My Table column (ID , startDate , EndDate ) I need to use this way with every row of the table : not with a specific value like : declare @start DATE = '2011-05-30' declare @end DATE = '2011-06-10' ;with months (date) AS ( SELECT @start UNION ALL SELECT DATEADD(month,1,date) from months where DATEADD(month,1,date)<= DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,@end)+1,0)) ) select Datename(month,date) from months it possible ??

    Read the article

  • help me to choose between two designs

    - by alex
    // stupid title, but I could not think anything smarter I have a code (see below, sorry for long code but it's very-very simple): namespace Option1 { class AuxClass1 { string _field1; public string Field1 { get { return _field1; } set { _field1 = value; } } // another fields. maybe many fields maybe several properties public void Method1() { // some action } public void Method2() { // some action 2 } } class MainClass { AuxClass1 _auxClass; public AuxClass1 AuxClass { get { return _auxClass; } set { _auxClass = value; } } public MainClass() { _auxClass = new AuxClass1(); } } } namespace Option2 { class AuxClass1 { string _field1; public string Field1 { get { return _field1; } set { _field1 = value; } } // another fields. maybe many fields maybe several properties public void Method1() { // some action } public void Method2() { // some action 2 } } class MainClass { AuxClass1 _auxClass; public string Field1 { get { return _auxClass.Field1; } set { _auxClass.Field1 = value; } } public void Method1() { _auxClass.Method1(); } public void Method2() { _auxClass.Method2(); } public MainClass() { _auxClass = new AuxClass1(); } } } class Program { static void Main(string[] args) { // Option1 Option1.MainClass mainClass1 = new Option1.MainClass(); mainClass1.AuxClass.Field1 = "string1"; mainClass1.AuxClass.Method1(); mainClass1.AuxClass.Method2(); // Option2 Option2.MainClass mainClass2 = new Option2.MainClass(); mainClass2.Field1 = "string2"; mainClass2.Method1(); mainClass2.Method2(); Console.ReadKey(); } } What option (option1 or option2) do you prefer ? In which cases should I use option1 or option2 ? Is there any special name for option1 or option2 (composition, aggregation) ?

    Read the article

  • getting the distance between two location on iphone

    - by Gani
    i am trying to calculate the distance between the statringpoint which hold the initial value of location and the newlocation using the following code but i am getting null in distance. can anyone help me out with this CLLocationDistance distance = [newLocation getDistanceFrom:startingPoint];

    Read the article

  • One value display two columns in data grid

    - by Nair
    I have a XML with 3 values, they are 'name', 'department', 'value'. I want to display a data grid with four columns like Name, department, credit and debit. When I have a value positive in 'value' column I want to enter the value in debit column and 0 in credit column and vice versa.

    Read the article

  • Compare two audio files of beat/tempo and rating in iphone

    - by Senthil Kumar
    Hello, I want to develop iPhone application should have the ability to count the number of phrases that are received when user sing on mic. This application should also have the ability to decipher whether the users phrases are in or out of cadence with a preset beat.When user sing on mic Instrumental music only play. So I have to merge the User Recorded voice with Instrumental music this is one Audio file.Already i have on original Song file.I have to compare both and give the Rating to users. [Note: Instrumental music is without vocal of Original Song file] Can you please help me?. Thanks Vadivelu

    Read the article

  • Determining two lines in MATLAB

    - by Sanyi
    Hi! I am making the game planarity in MATLAB, and i am stuck where the program have to determine that is there any lines that are in inscision with each other. Any ideas how could the program find the inscision points. Heres my source for the game: > clear; clc; a=1; b=10; x=floor(rand(5,1)*(b-a+1)+a); y=floor(rand(5,1)*(b-a+1)+a); fig1=figure; set(fig1,'Color','w','Position',[100 100 500 500]) plot(x,y,'o','MarkerSize',12,'MarkerFaceColor','r'); axis([0 11 0 11]); axis off grid on; hold on; FirstPlayerLines=[]; SecondPlayerLines=[]; for a1=1:+1:2 for a2=5:-1:2 plot([x(a1) x(a2)],[y(a1) y(a2)],'Color','black','LineWidth',3); end end waitforbuttonpress

    Read the article

  • Open two new tabs using Javascript

    - by Permana
    I have this situation: There are a login page with a login form (form action is $_SERVER['PHP_SELF']). When user login, it will check what application the user can access and open all the application that available for that user in new tab. If user can access application (for example) 'Docs' and 'Sites', it will open 2 tabs. I Open new tab using window.open('app1.html','_newhtml');, some people say that it only works in Firefox. It's OK, no big deal for me. The problem is, It only open 1 tab, although I write it 2 times window.open('app1.html','_newhtml'); window.open('app2.html','_newhtml'); How can I open 2 tabs? are there any hacks from server side or client side programming?

    Read the article

  • Two parameters in asp.net mvc route

    - by olst
    Hi. This is a modification to a question I've asked before on this forum. My controller action: public ActionResult SearchResults(string searchTerm, int page)... My view: <%= Html.PageLinks((int)ViewData["CurrentPage"], (int)ViewData["TotalPages"], i => Url.Action("SearchResults", new { page = i }))%>... The route entries: routes.MapRoute( null, "SearchResults", new { controller = "Search", action = "SearchResults", page = 1 } // Defaults ); routes.MapRoute( "Search", "SearchResults/Page{page}", new { controller = "Search", action = "SearchResults" }, new { page = @"\d+" } ); My goal is to have paging links for the search results. The problem is that when I click any page in the paging links, it gives me the search results of an empty serach term. How can I pass the search term parameter which is a string in addition to the page number parameter ? What should I put in the routing ?

    Read the article

< Previous Page | 90 91 92 93 94 95 96 97 98 99 100 101  | Next Page >