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  • Windows 7, file properties - Is "date accessed" ALWAYS 100% accurate?

    - by Robert
    Hello, Here's the situation: I went on vacation for a couple of weeks, but before I left, I took the harddrive out of my computer and hid it in a different location. Upon coming back on Monday and putting the harddrive back in my computer, I right-clicked on different files to see their properties. Interestingly enough, several files had been accessed during the time I was gone! I right-clicked different files in various locations on the harddrive, and all of these suspect files had been accessed within a certain time range (Sunday, ?January ?09, ?2011, approximately ??between 6:52:16 PM - 7:16:25 PM). Some of them had been accessed at the exact same time--down to the very second. This makes me think that someone must have done a search on my harddrive for certain types of files and then copied all those files to some other medium. The Windows 7 installation on this harddrive is password protected, but NOT encrypted, so they could have easily put the harddrive into an enclosure/toaster to access it from a different computer. Of course I did not right-click every single file on my computer, but did so in different folders. For instance, one of the folders I went through has different types of files: .mp3, ,prproj, .3gp, .mpg, .wmv, .xmp, .txt with file-sizes ranging from 2 KB to 29.7 MB (there is also a sub-folder in this folder which contains only .jpg files); however, of all these different types of files in this folder and its subfolder, all of them had been accessed (including the .jpg files from the sub-folder) EXCEPT the .mp3 files (if it makes any difference, the .mp3 files in this folder range in size from 187 KB to 4881 KB). Additionally, this sub-folder which contained only .jpg files (48 .jpg files to be exact) was not accessed during this time--only the .jpg files within it were accessed-- (between 6:57:03 PM - 6:57:08 PM). I thought that perhaps this was some kind of Windows glitch that was displaying the wrong access date, but then I looked at the "date created" and "date modified" for all of these files in question, and their created/modified dates and times were spot on correct. My first thought was that someone put the harddrive into an enclosure/toaster and viewed the files; but then I realized that this was impossible because several of the files had been accessed at the same exact time down to the second. So this made me think that the only other way the "date accessed" could have changed would have been if someone copied the files. Is there any chance at all whatsoever that this is some kind of Windows glitch or something, or is it a fact that someone was indeed accessing my files (and if someone was accessing my files, am I right about the files in question having been copied)? Is there any other possibility for what could have happened? Do I need to use any kinds of forensics tools to further investigate this matter (and if so, which tools), or is there any other way in which I can be certain of what took place in that timeframe the day before I got back? Or is what I see with Windows 7 good enough (i.e. accurate and truthful)? Thanks in advance, and please let me know if any other details are required on my part.

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  • How would I add an if statement into MSQLI query?

    - by Josh
    Okay so I'm just learning mysqli and I'm having a little trouble putting this code together. I've posted the mysqli query below and then below that is the code I'm trying to combine with the mysqli query and I can't seem to get it to work. Maybe what I'm doing isn't possible, but the third section below is how I had the query written for mysql and it's working fine. Answers in code are appreciated! Thanks! MYSQLI QUERY: <?php require("../config.php"); if ($stmt = $mysqli->prepare("SELECT firstname,lastname,spousefirst,phonecell,email,date,contacttype,status FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') ORDER BY date DESC")) { $stmt->execute(); $stmt->bind_results($firstname,$lastname,$spousefirst,$phonecell,$email,$date,$contacttype,$status); while ($stmt->fetch()) { echo ''.$firstname.' '." ".' '.$lastname.' '.",".' '.$spousefirst.' '.",".' '.$phonecell.' '.",".' '.$email.' '.",".' '.$date.' '.",".' '.$contacttype.' '.",".' '.$status.'</br>'; } $stmt->close(); } $mysqli->close(); ?> WHAT I'M TRYING TO COMBINE THE ABOVE WITH: if (($_GET['date'] == 'today')) { $sql = "SELECT * FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') AND date = DATE(NOW()) ORDER BY date DESC"; } WHAT I HAD BEFORE WITH MYSQL THAT WORKS: <?php require("../config.php"); $sql = "SELECT * FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') AND status = 'New' ORDER BY date DESC"; if (($_GET['date'] == 'today')) { $sql = "SELECT * FROM contacts WHERE contacttype IN ('Buyer','Seller','Buyer / Seller','Investor') AND date = DATE(NOW()) ORDER BY date DESC"; } ?>

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  • 2010's Most Popular Articles

    The end of the year is upon us, 2010 is about to be in the books. When closing out a year I like to take a look back at the articles I wrote over the year and see which ones resonated the most with readers. Which ones generated the most reader emails? Which ones were read the most? Such a retrospective analysis highlights what content was of most interest to developers in the trenches, and this data is used to guide article topics in the new year. I ended last year with a "Best Of" article - see 2009's Most Popular Articles - and decided to continue this tradition. Such "Best Of" articles give both regular and new readers a chance to discover (or rediscover) the most favored content from the year. So here it is - a list and synopsis of the 2010's most popular articles on 4GuysFromRolla.com. Read More >

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  • Oracle Excellence Awards 2012

    - by A&C Redaktion
    Spezialisierte Partner können sich ab sofort bis 29. Juni als „Specialized Partner of the Year“ bewerben. Damit honoriert Oracle diejenigen OPN Partner in EMEA, die sich mithilfe der Spezialisierung besonders ausgezeichnet haben, sei es durch einen hohen Mehrwert für deren Endkunden oder innovativen Lösungen und Services. Voraussetzung für eine Bewerbung ist mindestens eine abgeschlossene Spezialisierung in diesen sieben Kategorien: Specialized Partner of the Year: Database Specialized Partner of the Year: Applications Specialized Partner of the Year: Middleware Specialized Partner of the Year: Industry Specialized Partner of the Year: Oracle Accelerate Specialized Partner of the Year: Servers and Storage Systems Specialized Partner of the Year: Oracle on Oracle Der Gewinner eines “Specialized Partner of the Year” EMEA Awards erhält 5.000 US-Dollar MDF und vielfältige Möglichkeiten, sich in Szene zu setzen. Wie auch im letzten Jahr wird der Award wieder auf der Oracle OpenWorld in San Francisco überreicht. Interviews, Videos, Werbung, Berichte im Oracle Magazine und ein kostenloser Konferenzpass sind natürlich inklusive. Wie immer, gilt die Bewerbung für den EMEA-Award gleichzeitig als Bewerbung für den deutschen Partner-Award 2012, der auf dem Oracle Partner Day (im Herbst nach der OpenWorld) verliehen wird. Normal 0 21 false false false DE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Die Nominierung Ihres erfolgreichen Projektes muss diesmal hier auf Englisch eingereicht werden, da eine internationale Jury entscheidet. Beschreiben Sie Ihr Projekt so ausführlich wie möglich, damit sich die Juroren ein gutes Bild Ihrer Leistungen und Services machen können. Wenn Sie hierbei Unterstützung benötigen, fragen Sie einfach Ihren Channel Manager. Denn: Je aussagekräftiger Ihre Unterlagen sind, desto höher ist Ihre Chance zu gewinnen! Alle Informationen zu den diesjährigen Awards finden Sie auf der Oracle Excellence Awards Website. Wir drücken Ihnen die Daumen!

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  • Oracle Excellence Awards 2012

    - by A&C Redaktion
    Spezialisierte Partner können sich ab sofort bis 29. Juni als „Specialized Partner of the Year“ bewerben. Damit honoriert Oracle diejenigen OPN Partner in EMEA, die sich mithilfe der Spezialisierung besonders ausgezeichnet haben, sei es durch einen hohen Mehrwert für deren Endkunden oder innovativen Lösungen und Services. Voraussetzung für eine Bewerbung ist mindestens eine abgeschlossene Spezialisierung in diesen sieben Kategorien: Specialized Partner of the Year: Database Specialized Partner of the Year: Applications Specialized Partner of the Year: Middleware Specialized Partner of the Year: Industry Specialized Partner of the Year: Oracle Accelerate Specialized Partner of the Year: Servers and Storage Systems Specialized Partner of the Year: Oracle on Oracle Der Gewinner eines “Specialized Partner of the Year” EMEA Awards erhält 5.000 US-Dollar MDF und vielfältige Möglichkeiten, sich in Szene zu setzen. Wie auch im letzten Jahr wird der Award wieder auf der Oracle OpenWorld in San Francisco überreicht. Interviews, Videos, Werbung, Berichte im Oracle Magazine und ein kostenloser Konferenzpass sind natürlich inklusive. Wie immer, gilt die Bewerbung für den EMEA-Award gleichzeitig als Bewerbung für den deutschen Partner-Award 2012, der auf dem Oracle Partner Day (im Herbst nach der OpenWorld) verliehen wird. Normal 0 21 false false false DE X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0cm 5.4pt 0cm 5.4pt; mso-para-margin:0cm; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} Die Nominierung Ihres erfolgreichen Projektes muss diesmal hier auf Englisch eingereicht werden, da eine internationale Jury entscheidet. Beschreiben Sie Ihr Projekt so ausführlich wie möglich, damit sich die Juroren ein gutes Bild Ihrer Leistungen und Services machen können. Wenn Sie hierbei Unterstützung benötigen, fragen Sie einfach Ihren Channel Manager. Denn: Je aussagekräftiger Ihre Unterlagen sind, desto höher ist Ihre Chance zu gewinnen! Alle Informationen zu den diesjährigen Awards finden Sie auf der Oracle Excellence Awards Website. Wir drücken Ihnen die Daumen!

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  • using java Calendar

    - by owca
    I have a simple task. There are two classes : Ticket and Date. Ticket contains event, event place and event date which is a Date object. I also need to provide a move() method for Date object, so I used Calendar and Calendar's add(). Everything looks fine apart of the output. I constantly get 5,2,1 as the date's day,month,year. Lines with asterix return proper date. The code : Ticket class : public class Ticket { private String what; private String where; private Date when; public Ticket(String s1, String s2, Data d){ this.what = s1; this.where = s2; this.when = d; } *public Date giveDate(){ System.out.println("when in giveDate() "+this.when); return this.when; } public String toString(){ return "what: "+this.what+"\n"+"where: "+this.where+"\n"+"when: "+this.when; } } Date class: import java.util.Calendar; import java.util.GregorianCalendar; public class Date { public int day; public int month; public int year; public Date(int x, int y, int z){ *System.out.println("x: "+x); *System.out.println("y: "+y); *System.out.println("z: "+z); this.day = x; this.month = y; this.year = z; *System.out.println("this.day: "+this.day); *System.out.println("this.month: "+this.month); *System.out.println("this.year: "+this.year); } public Date move(int p){ *System.out.println("before_change: "+this.day+","+this.month+","+this.year); Calendar gc = new GregorianCalendar(this.year, this.month, this.day); System.out.println("before_adding: "+gc.DAY_OF_MONTH+","+gc.MONTH+","+gc.YEAR); gc.add(Calendar.DAY_OF_YEAR, p); System.out.println("after_adding: "+gc.DAY_OF_MONTH+","+gc.MONTH+","+gc.YEAR); this.year = gc.YEAR; this.day = gc.DAY_OF_MONTH; this.month = gc.MONTH; return this; } @Override public String toString(){ return this.day+","+this.month+","+this.year; } } Main for testing : public class Main { public static void main(String[] args) { Date date1=new Date(30,4,2002); Ticket event1=new Ticket("Peter Gabriel's gig", "London",date1 ); Ticket event2=new Ticket("Diana Kroll's concert", "Glasgow",date1 ); Date date2=event2.giveDate(); date2.move(30); Ticket event3=new Ticket("X's B-day", "some place",date2 ); System.out.println(date1); System.out.println(event1); System.out.println(event2); System.out.println(event3); } } And here's my output. I just can't get it where 5,2,1 come from :/ x: 30 y: 4 z: 2002 this.day: 30 this.month: 4 this.year: 2002 when in giveDate() 6,12,2004 before_change: 6,12,2004 before_adding: 5,2,1 after_adding: 5,2,1 5,2,1 what: Peter Gabriel's gig where: London when: 5,2,1 (...)

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  • How to disable a checkbox based on date using php?

    - by udaya
    I have iterated a table based on my query result... I have a column lastDate it contains a date value like 01/24/2010... Now i have to check the date value with the current date if currentdate is less than or equal to lastDate i have to enable the checkbox else disable it..... Any suggestion how it can be done in php... Here is my code <? if(isset($comment)) { echo '<tr><td class=table_label colspan=5>'.$comment.'</td></tr>'; } ?> <td align="center" class="table_label" id="txtsubdat"> <? $dd=$row['dDate']; if($dd=='') { } else { $str = $dd; $dd = strtotime ( $str ); echo date ( 'm/d/Y' , $dd ); } ?> </td> <td align="center"> <input type="checkbox" name="group" id="group" value="<?=$row['dAssignment_id']?>" onclick="checkdisplay(this);"> </td> <? } ?>

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  • In CakePHP, how do I create a form to list models withing a date range?

    - by anonymous coward
    I have a very simple model that includes the auto-filled field much like 'created'. (DateTime format). I'd like to use the Form helpers if possible, to validate the date fields and whatnot. I'd like a simple form with a "Begin Date" (YMD, 12 hours), and an "End Date" (same format). There is already a controller action set up as follows: function view_between($start_date = null, $end_date = null) { // ... stuff that works correctly when the URL is manually entered. } Have I defined the controller wrong, or how can I pass these values into that function? The reason I'm stuck is because I tried adding a $form->input('my_datetime_field' ...) twice, but obviously the name/id were the same on the respective elements. I have also tried using $form->dateTime(...) with similar results. I'm not sure how to uniquely identify a Begin and End date selection, when it should interact with a single field. Am I going about this wrong? A kind shove in the right direction should suffice.

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  • Is it possible to pass Calendar new date in the bean without listener?

    - by isabsent
    I am trying to pass new date from PrimeFaces p:calendar (placed in p:dataTable column) to the backing bean: <p:column > <p:calendar value="#{bean.date}">` <p:ajax /> </p:calendar> </p:column> It does not update bean.date. Variants with <p:ajax update="@this" event="change"/> <p:ajax update="@this" event="select"/> do not update bean.date too. The only way I have found is using of listener. However, I suppose, there should be a way without listener implementation like for simple facelets: <p:column> <h:inputText value="#{bean.note}" > <f:ajax/> </h:inputText> </p:column> that works fine for me. Does anybody know how to get it working!?

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  • Inserting Records in Ascending Order function- C homework assignment

    - by Aaron McRuer
    Good day, Stack Overflow. I have a homework assignment that I'm working on this weekend that I'm having a bit of a problem with. We have a struct "Record" (which contains information about cars for a dealership) that gets placed in a particular spot in a linked list according to 1) its make and 2) according to its model year. This is done when initially building the list, when a "int insertRecordInAscendingOrder" function is called in Main. In "insertRecordInAscendingOrder", a third function, "createRecord" is called, where the linked list is created. The function then goes to the function "compareCars" to determine what elements get put where. Depending on the value returned by this function, insertRecordInAscendingOrder then places the record where it belongs. The list is then printed out. There's more to the assignment, but I'll cross that bridge when I come to it. Ideally, and for the assignment to be considered correct, the linked list must be ordered as: Chevrolet 2012 25 Chevrolet 2013 10 Ford 2010 5 Ford 2011 3 Ford 2012 15 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2013 20 from the a text file that has the data ordered the following way: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Notice that the alphabetical order of the "make" field takes precedence, then, the model year is arranged from oldest to newest. However, the program produces this as the final list: Chevrolet 2012 25 Chevrolet 2013 10 Honda 2011 9 Honda 2012 3 Honda 2013 12 Toyota 2009 2 Toyota 2011 7 Toyota 2012 20 Ford 2010 5 Ford 2011 3 Ford 2012 15 I sat down with a grad student and tried to work out all of this yesterday, but we just couldn't figure out why it was kicking the Ford nodes down to the end of the list. Here's the code. As you'll notice, I included a printList call at each instance of the insertion of a node. This way, you can see just what is happening when the nodes are being put in "order". It is in ANSI C99. All function calls must be made as they are specified, so unfortunately, there's no real way of getting around this problem by creating a more efficient algorithm. #include <stdio.h> #include <stdlib.h> #include <string.h> #define MAX_LINE 50 #define MAX_MAKE 20 typedef struct record { char *make; int year; int stock; struct record *next; } Record; int compareCars(Record *car1, Record *car2); void printList(Record *head); Record* createRecord(char *make, int year, int stock); int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock); int main(int argc, char **argv) { FILE *inFile = NULL; char line[MAX_LINE + 1]; char *make, *yearStr, *stockStr; int year, stock, len; Record* headRecord = NULL; /*Input and file diagnostics*/ if (argc!=2) { printf ("Filename not provided.\n"); return 1; } if((inFile=fopen(argv[1], "r"))==NULL) { printf("Can't open the file\n"); return 2; } /*obtain values for linked list*/ while (fgets(line, MAX_LINE, inFile)) { make = strtok(line, " "); yearStr = strtok(NULL, " "); stockStr = strtok(NULL, " "); year = atoi(yearStr); stock = atoi(stockStr); insertRecordInAscendingOrder(&headRecord,make, year, stock); } printf("The original list in ascending order: \n"); printList(headRecord); } /*use strcmp to compare two makes*/ int compareCars(Record *car1, Record *car2) { int compStrResult; compStrResult = strcmp(car1->make, car2->make); int compYearResult = 0; if(car1->year > car2->year) { compYearResult = 1; } else if(car1->year == car2->year) { compYearResult = 0; } else { compYearResult = -1; } if(compStrResult == 0 ) { if(compYearResult == 1) { return 1; } else if(compYearResult == -1) { return -1; } else { return compStrResult; } } else if(compStrResult == 1) { return 1; } else { return -1; } } int insertRecordInAscendingOrder(Record **head, char *make, int year, int stock) { Record *previous = *head; Record *newRecord = createRecord(make, year, stock); Record *current = *head; int compResult; if(*head == NULL) { *head = newRecord; printf("Head is null, list was empty\n"); printList(*head); return 1; } else if ( compareCars(newRecord, *head)==-1) { *head = newRecord; (*head)->next = current; printf("New record was less than the head, replacing\n"); printList(*head); return 1; } else { printf("standard case, searching and inserting\n"); previous = *head; while ( current != NULL &&(compareCars(newRecord, current)==1)) { printList(*head); previous = current; current = current->next; } printList(*head); previous->next = newRecord; previous->next->next = current; } return 1; } /*creates records from info passed in from main via insertRecordInAscendingOrder.*/ Record* createRecord(char *make, int year, int stock) { printf("CreateRecord\n"); Record *theRecord; int len; if(!make) { return NULL; } theRecord = malloc(sizeof(Record)); if(!theRecord) { printf("Unable to allocate memory for the structure.\n"); return NULL; } theRecord->year = year; theRecord->stock = stock; len = strlen(make); theRecord->make = malloc(len + 1); strncpy(theRecord->make, make, len); theRecord->make[len] = '\0'; theRecord->next=NULL; return theRecord; } /*prints list. lists print.*/ void printList(Record *head) { int i; int j = 50; Record *aRecord; aRecord = head; for(i = 0; i < j; i++) { printf("-"); } printf("\n"); printf("%20s%20s%10s\n", "Make", "Year", "Stock"); for(i = 0; i < j; i++) { printf("-"); } printf("\n"); while(aRecord != NULL) { printf("%20s%20d%10d\n", aRecord->make, aRecord->year, aRecord->stock); aRecord = aRecord->next; } printf("\n"); } The text file you'll need for a command line argument can be saved under any name you like; here are the contents you'll need: Ford 2012 15 Ford 2011 3 Ford 2010 5 Toyota 2011 7 Toyota 2012 20 Toyota 2009 2 Honda 2011 9 Honda 2012 3 Honda 2013 12 Chevrolet 2013 10 Chevrolet 2012 25 Thanks in advance for your help. I shall continue to plow away at it myself.

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  • How to tell if a freebsd jail is up to date?

    - by Martin Torhage
    I've set up a "Service Jail" in FreeBSD 8.0 according to the FreeBSD Handbook (http://www.freebsd.org/doc/en_US.ISO8859-1/books/handbook/jails-application.html). After upgrading the host to the latest patch level and then performed a jail-upgrade, freebsd-fetch still reports that there are files in need of an update in the jail. Is this expected? Then how do I know if a jail is up to date? This is what I've done in more detail: After the initial setup of the jail freebsd-update fetch reported that there were no updates available neither in the host system nor in the jail. This was expected. A while later freebsd-update fetch reported that the following files where in need of an update both in the host and in the jail. /usr/lib/libssl.a /usr/lib/libssl_p.a /usr/lib/libzpool.a /usr/lib32/libssl.a /usr/lib32/libssl_p.a /usr/lib32/libzpool.a I updated the host and followed the upgrade guide for the jail (http://www.freebsd.org/doc/en_US.ISO8859-1/books/handbook/jails-application.html#JAILS-SERVICE-JAILS-UPGRADING). freebsd-update fetch now reports that there are no updates available in the host but the following is the output from freebsd-update fetch in the jail: [root@bb /]# freebsd-update fetch Looking up update.FreeBSD.org mirrors... 3 mirrors found. Fetching metadata signature for 8.0-RELEASE from update5.FreeBSD.org... done. Fetching metadata index... done. Inspecting system... done. Preparing to download files... done. The following files are affected by updates, but no changes have been downloaded because the files have been modified locally: /var/db/mergemaster.mtree The following files will be updated as part of updating to 8.0-RELEASE-p2: /usr/lib/libssl.a /usr/lib/libssl_p.a /usr/lib/libzpool.a /usr/lib32/libssl.a /usr/lib32/libssl_p.a /usr/lib32/libzpool.a Shouldn't freebsd-update know that the jail is up to date or have I failed upgrading it? How am I supposed to know if a jail is up to date if freebsd-update can't tell? I'm sure I ran make cleandir twice before make buildworld. TIA

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  • How to sort by file's modified date on IIS web server in Windows 7?

    - by ????
    Apache has this built in since 1996 which is 17 years ago... for Microsoft's IIS Web server which is available on Windows 7, is there a way to make it be able to sort the file listing by file modification dates? For example, show the file listing with the label "Date", "Filename", and clicking it will sort the files by that attribute. The only info I could find is: http://technet.microsoft.com/en-us/library/cc732762(v=ws.10).aspx cd %windir%\system32\inetsrv appcmd set config /section:directoryBrowse /showFlags:Time|Size|Extension|Date|LongDate|None but it doesn't work.

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  • At what year in history was computers first used to store porn? [closed]

    - by Emil H
    Of course this sounds like a joke question, but it's meant seriously. I remember being told by an old system administrator back in the early nineties about people asking about good FTPs for porn, and that they would as a joke always tell them to connect to 127.0.0.1. They would come back saying that there was a lot of porn at that address, but that oddly enough it seemed like they already had it all. Point being, it seems like it's been around for quite a while. Anyway. Considering that a considerable portion of the internet is devoted to porn these days, it would be interesting to know if someone has any kind of idea as to when and where the phenomena first arose? There must be some mention of this in old hacker folk lore? (Changed to CW to emphasize that this isn't about rep, but about genuine curiousity. :)

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  • How to set expiration date for external files? [closed]

    - by garconcn
    I have a site included lots of external files, most of them are gif format. I have no control on the external files, but have to use them(with permission). When I check the site using Google Pagespeed, I got very low score(31) even though the page load is fast. One of the high priority suggestion is to leverage browser caching by setting an expiration date. However, all the files are on external links. I have already set the expiration date for local files.

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  • File property information (last write time and file size) in explorer out of date by hours over netw

    - by David L Morris
    An application is running on a windows XP prof machine picking up file from a network share from another windows machine. It detects that the file has been updated (by date and time or optionally file size) and reads it for any new data. Most of the time the last write time and file size, seems to be up to date. Occasionally, this information stops being updated, even though the file is growing (intermittently during the day) with appended content, so that the last write time and file size remain fixed at some arbitrary moment. This is visible in explorer, where it shows a fixed last write time on the reading machine. Just opening the file to edit it in notepad, immediately refreshes the file properties, and the other application picks up where it left of. The file location can't be changed, nor the location of the relevant applications. Any solutions to resolve this problem?

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  • Expire windows user (license) after some time according to first login instead of a solid expiration date

    - by smhnaji
    In a project, we have lots of Windows user that have bought licenses for 1 month, 2 month,... 1 year and so... CURRENT SITUATION (WHAT I DON'T WANT): When users are created and added to the OS, a solid expiration date is given. WHAT I WANT: Users' expiration date should be calculated automatically after first login. The user might not need his account right when purchases the license. In another words: When a license is purchased at Jan 1, he should use the license until Feb 1. No matter whether he really logs in or not. He cannot come Feb 5 and begin using his license because that has expired then. What I want is that when he comes at Feb 5 and begins using, the license update until March 5. Environment: Windows Server 2012

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  • In Excel, how to group data by date, and then do operations on the data?

    - by Bicou
    Hi, I have Excel 2003. My data is like this: 01/10/2010 0.99 02/10/2010 1.49 02/10/2010 0.99 02/10/2010 0.99 02/10/2010 0.99 03/10/2010 1.49 03/10/2010 1.49 03/10/2010 0.99 etc. In fact it is a list of sales every day. I want to have something like this: 01/10/2010 0.99 02/10/2010 4.46 03/10/2010 3.97 I want to group by date, and sum the column B. I'd like to see the evolution of the sales over time, and display a nice graph about that. I have managed to create pivot tables that almost do the job: they list the number of 0.99 and 1.49 each day, but I can't find a way to simply sum everything and group by date. Thanks for reading.

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  • In OpenOffice Spreadsheet, how can I set the default Date format?

    - by Joe Casadonte
    I'm using OO 3.1.1 on Ubuntu 9.10 (in case that matters to the answer). I like my dates to appear as YYYY-MM-DD. I can't think of a time when I want to see a date in any other format, so I'm constantly changing how dates look. That's manageable, though annoying. What's gotten me to the point of posting is that when I edit a cell with a date value, I have to edit it in the format MM/DD/YYYY, which is really, really annoying, as I'm usually mucking with the day (or possibly the month), and very seldom the year. So there's lots of cursor or mouse use, wasting my time. So is there a way that I can change how dates are edited, or at least the default display format? Thanks!

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  • Have optical drive connectors changed in the last year?

    - by Zippityboomba
    In early 2010 my motherboard freaked out, and I was able to drop in a new board and connect my two DVD drives that were initially bought in 2005. Tonight my new components arrived to build my next system, and I figured I'd just reuse the old DVD drives. Surprise, the long flat connector cable has no mate on the new motherboard. Reckon I'll just pick up a new DVD drive for $25, but what gives? Thanks!

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  • Like to Upgrade My PC (7 year old) - for animation and hardcore gaming ! - help me [closed]

    - by sri
    I like to buy a new computer for my studies and as well as gaming. My old pc has 1.5 GB RAM with 512MB Graphics card. And it is very old to run Adobe CS5 version and other high end animation software. My budget will be INR 20k-25k. I have 500GB hard disk, keyboard and mouse new. So apart from this, I like to buy : Intel or AMD is good ? My idea is : Corei5 or Corei7 = which is best and economy ? Which mother board. 4 GB RAM with upto 8 GB RAM slot for future upgrade. 1 GB or 2 GB Graphic card - which one ? If I am wrong - please suggest me

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