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  • How to speed up SSH login using a public key and PuTTY?

    - by BarsMonster
    Hi! I am using PuTTY to log into my local server, but it takes about 1.5 seconds to log in (from the click on 'Connect' to working command prompt, most of time is spend on "Authenticating with public key..."). I know many see even slower speeds, but I would like to have not more than 0.1 sec. login time. I already set UseDNS=no, allowed only IPv4 in the PuTTY client, and reduced key length from 4k down to 1k. Any other suggestions to speed it up even further?

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  • what is file verification system for php project or licence checking the configuration files

    - by Jayapal Chandran
    Hi, My colleague asked me a question like "license check to config file". when i searched i got this http://www.google.com/search?q=file+verification+system&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a and in the result i got this http://integrit.sourceforge.net/texinfo/integrit.html but could not grasp much of its idea. Here is my thoughts... Our project is written in codeigniter. The project owner is providing it to their customer. The owner is a business partner with that concept. Besides, the owner needs control of the project code so that the customer will not break rules with him like changing the code or moving it go another server or validity. So the owner needs a system to enable disable the site. Let me give an example... owner.com will have an admin panel where he can either disable or enable the client.com. when he disables the client.com should display a custom message instead of loading the files. client.com is written i a way that i will process requests from owner.com and also the other way round. so, here i want a list of the concepts with which we can implement the ownership and control over client.com any suggestions, links, references, answers will be helpful. If i am missing something in my question i will update my question according to your comments if any so that the users can give in their idea without confusing of what i had asked. THX

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  • Access the next button event android

    - by Sephy
    I don't know if it's very clear, but i'm trying to do something when the "next" (bottom right corner of the keyboard) is pressed, and i can't find its keycode. I have tried to look for "next" or "enter" in the keycodes but nothing really relevant... does anyone know? (actually, i've found the enter keycode to be precise, but it does not do anything)

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  • Assigning hotkeys to custom buttons in Sage CRM

    - by CodeGeek
    Hi All, I'm trying to assign a hotkey to a custom buttom in Sage CRM. I'm able to do so for one keypress. However, it doesn't seem to work if I try to use a combination of keys, for example, 'Alt+C' Please refer my code below: document.onkeypress = onKeyPress; var flag = false; function onKeyPress() { if(window.event.keyCode == 18) { flag = true; } if(window.event.keyCode == 67 && flag) { alert("Successful!!!"); } }

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  • How do I install Ubuntu to a USB key?

    - by badp
    If you are hurrying to reply, System ? Administration ? StartUp Disk Creator -- no, that's not what I'm talking about. I want to try Ubuntu 11.04's Unity without touching my existing Ubuntu install. To do this, I need to install the nVidia drivers first (sigh). To do this, I need changes to persist a reboot. To do this, I need to really install Ubuntu on a USB key. How do you do that? What I tried I tried to make a USB key from Testdrive, then boot from it, then choose "Install Ubuntu." The installer refused to install to the installation media itself. I tried, from my installed copy of Ubuntu: sudo kvm /dev/sdb --cdrom .cache/testdrive/iso/ubuntu_natty-desktop-i386.iso ...but the installer didn't detect the disk properly.

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  • django model relation definition

    - by Laurent Luce
    Hello, Let say I have 3 models: A, B and C with the following relations. A can have many B and many C. B can have many C Is the following correct: class A(models.Model): ... class B(models.Model): ... a = ForeignKey(A) class C(models.Model): ... a = ForeignKey(A) b = ForeignKey(B)

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  • Encoding license file for privacy

    - by Swingline Rage
    Hi, We're using XML Digital Signatures for signing and verifying our license keys. The signing works fine and has been running smoothly. The XML license file contains a few (plaintext) details about the license, along with a binary signature. We'd like to encode (I don't say encrypt) those plaintext details (license duration, user name, etc, etc.) so they're not immediately visible to prying eyes. Is there a standard (eg, base 64 or something else) that people use in this situation? It doesn't need to be secure or particularly clever, just enough to conceal the information in Notepad. Thanks : )

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  • Non-normalized association with legacy tables in Rails and ActiveRecord

    - by Thomas Holmström
    I am building a Rails application accessing a legacy system. The data model contains Customers which can have one or more Subscriptions. A Subscription always belong to one and only one Customer. Though not needed, this association is represented through a join table "subscribes", which do not have an id column: Column | Type | Modifiers -----------------+---------+----------- customer_id | integer | not null subscription_id | integer | not null I have this coded as a has_and_belongs_to_many declarations in both Customer and Subscription class Customer < Activerecord::Base has_and_belongs_to_many :subscriptions, :join_table => "subscribes", :foreign_key => "customer_id", :association_foreign_key => "subscription_id" end class Subscription < Activerecord::Base has_and_belongs_to_many :customers, :join_table => "subscribes", :foreign_key => "subscription_id", :association_foreign_key => "customer_id" end The problem I have is that there can only ever be one customer for each subscription, not many, and the join table will always contain at most one row with a certain customer_id. And thus, I don't want the association "customers" on a Subscription which returns an array of (at most one) Customer, I really do want the relation "customer" which returns the Customer associated. Is there any way to force ActiveRecord to make this a 1-to-N relation even though the join table itself seems to make it an N-to-M relation? --Thomas

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  • Couchbase (ex. membase) solution to dump all keys in a bucket

    - by j99
    I was googling around and found various python + tap solutions that should enable me to dump all keys from a bucket but none of them worked for me. I have a bucket at port 11230 and I need to get a dump of all keys in order to fill them into sphinx search engine. If I execute: # python /opt/couchbase/lib/python/tap_example.py 127.0.0.1:11230 I get the following output: info: New bin connection from None error: uncaptured python exception, closing channel <tap.TapConnection connected at 0x7f5d287184d0> (<type 'exceptions.AssertionError'>: [/usr/lib/python2.6/asyncore.py|read|78] [/usr/lib/python2.6/asyncore.py|handle_read_event|428] [/opt/couchbase/lib/python/mc_bin_server.py|handle_read|325]) this error is the same even if I try some other host or port. I also tried many other python scripts that I found on forums and groups but all of them produced the same error. My primary development environment includes PHP & Perl on Debian linux box but I will take any solution that would just dump all the keys into plain text file. Thank you for any help!

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  • Help needed with Linq To Sql Query

    - by fearofawhackplanet
    I have the concept of valid/ordered transitions. So for example, it's not possible to move to status In progress from status Complete. Current and Next in table StatusTransition are FK (StatusType.Id). The Linq generator has created the following relations: Child Property Name: StatusTransitions1 Parent Property Name: StatusType1 Participating Properties: StatusType.Id -> StatusTransition.Next Child Property Name: StatusTransitions Parent Property Name: StatusType Participating Properties: StatusType.Id -> StatusTransition.Current I'm normally ok with Linq but I'm having difficulty getting the list of valid Next StatusTypes from the Current status. public List<StatusType> GetValidStatusTransitions(int statusId) { // trying to write something like the following // (obviously not correct) return _statusRepository .Where(s => s.Id == statusId) .Next.StatusTypes; }

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  • Multiple has_many's of the same model

    - by Koning Baard
    I have these models: Person has_many :messages_form_person, :foreign_key => :from_user_id, :class_name => :messages has_many :messages_to_person, :foreign_key => :to_user_id, :class_name => :messages Message belongs_to :to_person, :foreign_key => :to_user_id, :class_name => :person belongs_to :from_person, :foreign_key => :to_user_id, :class_name => :person And this view: person#show <% @person.messages_to_person.each do |message| %> <%=h message.title %> <% end %> But I get this error: TypeError in People#show Showing app/views/people/show.html.erb where line #26 raised: can't convert Symbol into String Extracted source (around line #26): 23: <%=h @person.biography %> 24: </p> 25: 26: <% @person.messages_to_person.each do |message| %> 27: 28: <% end %> 29: I basicly want that people can send eachother messages. Can anyone help me? Thanks.

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  • How does CouchDB perform for a regularly updated dataset?

    - by Ritesh M Nayak
    I am planning on using CouchDB on a project. But as the querying mechanism involves writing views (which are a lot like indexes on regular RDMBMS's) I was wondering, if the document database keeps getting updated a lot ( a write heavy database) would CouchDB perform well compared to a regular RDBMS? Or do we have to compact/re-index the system occasionally to make it perform faster?

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  • How to write a custom predicate for multi_index_containder with composite_key?

    - by Titan
    I googled and searched in the boost's man, but didn't find any examples. May be it's a stupid question...anyway. So we have the famous phonebook from the man: typedef multi_index_container< phonebook_entry, indexed_by< ordered_non_unique< composite_key< phonebook_entry, member<phonebook_entry,std::string,&phonebook_entry::family_name>, member<phonebook_entry,std::string,&phonebook_entry::given_name> >, composite_key_compare< std::less<std::string>, // family names sorted as by default std::greater<std::string> // given names reversed > >, ordered_unique< member<phonebook_entry,std::string,&phonebook_entry::phone_number> > > > phonebook; phonebook pb; ... // look for all Whites std::pair<phonebook::iterator,phonebook::iterator> p= pb.equal_range(boost::make_tuple("White"), my_custom_comp()); How should my_custom_comp() look like? I mean it's clear for me then it takes boost::multi_index::composite_key_result<CompositeKey> as an argumen (due to compilation errors :) ), but what is CompositeKey in that particular case? struct my_custom_comp { bool operator()( ?? boost::multi_index::composite_key_result<CompositeKey> ?? ) const { return blah_blah_blah; } }; Thanks in advance.

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  • I Can't update 12.04 to 12.10 ERROR:"gpg: WARNING: This key is not certified with a trusted signature!"

    - by jason328
    I'm trying to update to 12.10 from a 12.04 machine. When I ran the code sudo do-release-upgrade -d in my terminal and verified my password it checked for a new upgrade. I was then returned with this: gpg: Good signature from "Ubuntu Archive Automatic Signing Key <[email protected]>" gpg: WARNING: This key is not certified with a trusted signature! gpg: There is no indication that the signature belongs to the owner.` There of course is more but it looks like it may or may not be showing private information with it. What's causing this and how do I fix this.

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  • How do I specify a null relation in SQLAlchemy?

    - by Jesse
    Not sure what the correct title for this question should be. I have the following schema: Matters have a one-many relationship to WorkItems. WorkItems have a one-one (or one-zero) relationship to LineItems. I am trying to create the following relation between Matters and WorkItems Matter.unbilled_work_items = orm.relation(WorkItem, primaryjoin = (Matter.id == WorkItem.matter_id) and (WorkItem.line_item_id == None), foreign_keys = [WorkItem.matter_id, WorkItem.line_item_id], viewonly=True ) This throws: AttributeError: '_Null' object has no attribute 'table' That seems to be saying that the second clause in the primaryjoin returns an object of type _Null, but it seems to be expecting something with a "table" attribute. This seems like it should be pretty straightforward to me, am I missing something obvious?

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  • How to 'insert if not exists' in MySQL?

    - by warren
    I started by googling, and found this article which talks about mutex tables. I have a table with ~14 million records. If I want to add more data in the same format, is there a way to ensure the record I want to insert does not already exist without using a pair of queries (ie, one query to check and one to insert is the result set is empty)? Does a unique constraint on a field guarantee the insert will fail if it's already there? It seems that with merely a constraint, when I issue the insert via php, the script croaks.

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  • Cannot access NSDictionary

    - by michael blaize
    I created a JSON using a PHP script. I am reading the JSON and can see that the data has been correctly read. However, when it comes to access the objects I get unrecognized selector sent to instance... Cannot seem to find why that is after too many hours !!!! Any help would be great ! My code looks like that: `NSDictionary *json = [[NSDictionary alloc] init]; json = [NSJSONSerialization JSONObjectWithData:receivedData options:kNilOptions error:&error]; NSLog(@"raw json = %@,%@",json,error); NSMutableArray *name = [[NSMutableArray alloc] init]; [name addObjectsFromArray: [json objectForKey:@"name"]];` The code crashes when reaching the last line above. The output like this: raw json = ( { category = vacancies; link = "http://blablabla.com"; name = "name 111111"; tagline = "tagline 111111"; }, { category = vacancies; link = "http://blobloblo.com"; name = "name 222222222"; tagline = "tagline 222222222"; } ),(null) 2012-06-23 21:46:57.539 Wind expert[4302:15203] -[__NSCFArray objectForKey:]: unrecognized selector sent to instance 0xdcfb970 HELP !!!

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  • JavaScript Keycode 46 is DEL Function key or (.) period sign?

    - by Omar
    Im writing some logic in JavaScript using jquery, where i must check the input content against a REGEX pattern ex: "^[a-zA-Z0-9_]*$" //Alpha-numeric and _ The logic is almost done, i just have a little problem filtering the function key DEL, my logic goes like this: var FunctionsKey = new Array(8, 9, 13, 16, 35, 36, 37, 39, 46); function keypressValidation(key) { if (config.regexExp != null) { if ($.inArray(key, FunctionsKey) != -1) { return true; } else { var keyChar = String.fromCharCode(key); return RegexCheck(keyChar); } } return true; } If the KeyCode is one of those in the array, i let it pass, if not i get the char and compare it against the REGEX. The problem is: in some Browsers the DEL and '.' (period sign) have the same key Code 46. So is there a better logic to filter the function keys or must i write a condition for that case, maybe removing the 46 from the array and try to convert it to char and if is (.) let it go to the Regex function if not let it pass? The other question will be are there more shared Key Codes in some browsers? EDIT: My suggested solution wont work because it doesn't matter which key the user pressed (DEL or period) i always get (.) as CHAR at least on OPERA and FF =(.

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  • How to debug KVO

    - by user8472
    In my program I use KVO manually to observe changes to values of object properties. I receive an EXC_BAD_ACCESS signal at the following line of code inside a custom setter: [self willChangeValueForKey:@"mykey"]; The weird thing is that this happens when a factory method calls the custom setter and there should not be any observers around. I do not know how to debug this situation. Update: The way to list all registered observers is observationInfo. It turned out that there was indeed an object listed that points to an invalid address. However, I have no idea at all how it got there. Update 2: Apparently, the same object and method callback can be registered several times for a given object - resulting in identical entries in the observed object's observationInfo. When removing the registration only one of these entries is removed. This behavior is a little counter-intuitive (and it certainly is a bug in my program to add multiple entries at all), but this does not explain how spurious observers can mysteriously show up in freshly allocated objects (unless there is some caching/reuse going on that I am unaware of). Modified question: How can I figure out WHERE and WHEN an object got registered as an observer? Update 3: Specific sample code. ContentObj is a class that has a dictionary as a property named mykey. It overrides: + (BOOL)automaticallyNotifiesObserversForKey:(NSString *)theKey { BOOL automatic = NO; if ([theKey isEqualToString:@"mykey"]) { automatic = NO; } else { automatic=[super automaticallyNotifiesObserversForKey:theKey]; } return automatic; } A couple of properties have getters and setters as follows: - (CGFloat)value { return [[[self mykey] objectForKey:@"value"] floatValue]; } - (void)setValue:(CGFloat)aValue { [self willChangeValueForKey:@"mykey"]; [[self mykey] setObject:[NSNumber numberWithFloat:aValue] forKey:@"value"]; [self didChangeValueForKey:@"mykey"]; } The container class has a property contents of class NSMutableArray which holds instances of class ContentObj. It has a couple of methods that manually handle registrations: + (BOOL)automaticallyNotifiesObserversForKey:(NSString *)theKey { BOOL automatic = NO; if ([theKey isEqualToString:@"contents"]) { automatic = NO; } else { automatic=[super automaticallyNotifiesObserversForKey:theKey]; } return automatic; } - (void)observeContent:(ContentObj *)cObj { [cObj addObserver:self forKeyPath:@"mykey" options:0 context:NULL]; } - (void)removeObserveContent:(ContentObj *)cObj { [cObj removeObserver:self forKeyPath:@"mykey"]; } - (void)observeValueForKeyPath:(NSString *)keyPath ofObject:(id)object change:(NSDictionary *)change context:(void *)context { if (([keyPath isEqualToString:@"mykey"]) && ([object isKindOfClass:[ContentObj class]])) { [self willChangeValueForKey:@"contents"]; [self didChangeValueForKey:@"contents"]; } } There are several methods in the container class that modify contents. They look as follows: - (void)addContent:(ContentObj *)cObj { [self willChangeValueForKey:@"contents"]; [self observeDatum:cObj]; [[self contents] addObject:cObj]; [self didChangeValueForKey:@"contents"]; } And a couple of others that provide similar functionality to the array. They all work by adding/removing themselves as observers. Obviously, anything that results in multiple registrations is a bug and could sit somewhere hidden in these methods. My question targets strategies on how to debug this kind of situation. Alternatively, please feel free to provide an alternative strategy for implementing this kind of notification/observer pattern.

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