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  • How to store sorted records in csv file ?

    - by Harikrishna
    I sort the records of the datatable datewise with the column TradingDate which is type of datetime. TableWithOnlyFixedColumns.DefaultView.Sort = "TradingDate asc"; Now I want to display these sorted records into csv file but it does not display records sorted by date. TableWithOnlyFixedColumns.DefaultView.Sort = "TradingDate asc";TableWithOnlyFixedColumns.Columns["TradingDate"].ColumnName + "] asc"; DataTable newTable = TableWithOnlyFixedColumns.Clone(); newTable.DefaultView.Sort = TableWithOnlyFixedColumns.DefaultView.Sort; foreach (DataRow oldRow in TableWithOnlyFixedColumns.Rows) { newTable.ImportRow(oldRow); } // we'll use these to check for rows with nulls var columns = newTable.DefaultView.Table.Columns.Cast<DataColumn>(); using (var writer = new StreamWriter(@"C:\Documents and Settings\Administrator\Desktop\New Text Document (3).csv")) { for (int i = 0; i < newTable.DefaultView.Table.Rows.Count; i++) { DataRow row = newTable.DefaultView.Table.Rows[i]; // check for any null cells if (columns.Any(column => row.IsNull(column))) continue; string[] textCells = row.ItemArray .Select(cell => cell.ToString()) // may need to pick a text qualifier here .ToArray(); // check for non-null but EMPTY cells if (textCells.Any(text => string.IsNullOrEmpty(text))) continue; writer.WriteLine(string.Join(",", textCells)); } } So how to store sorted records in csv file ?

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  • How to Store and Retrieve Images Using SQL Server (Server Management Studio)

    - by Joe Majewski
    I am having difficulties when trying to insert files into a SQL Server database. I'll try to break this down as best as I can: What data type should I be using to store image files (jpeg/png/gif/etc)? Right now my table is using the image data type, but I am curious if varbinary would be a better option. How would I go about inserting the image into the database? Does Microsoft SQL Server Management Studio have any built in functions that allow insertions of files into tables? If so, how is that done? Also, how could this be done through the use of an HTML form with PHP handling the input data and placing it into the table? How would I fetch the image from the table and display it on the page? I understand how to SELECT the cell's contents, but how would I go about translating that into a picture. Would I have to have a header(Content type: image/jpeg)? I have no problem doing any of these things with MySQL, but the SQL Server environment is still new to me, and I am working on a project for my job that requires the use of stored procedures to grab various data. Any and all help is appreciated.

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  • How to store a captured image into MySQL database using JavaScript

    - by R J.
    I am capturing image using canvas and i want to store a captured image in MySQL Database using Javascript. This is my code: <html> <head> <meta charset="utf-8"> <meta name="viewport" content="width=device-width, maximum-scale=1.0"> <style> body {width: 100%;} canvas {display: none;} </style> <title>Instant Camera - Remote</title> <script> var video, canvas, msg; var load = function () { video = document.getElementById('video'); canvas = document.getElementById('canvas'); msg = document.getElementById('error'); if( navigator.getUserMedia ) { video.onclick = function () { var context = canvas.getContext("2d"); context.drawImage(video, 0, 0, 240, 320); var image1 = canvas.toDataURL("image/png"); document.write('<img src="' + image1 + '" />'); }; } else { msg.innerHTML = "Native web camera not supported :("; } }; window.addEventListener('DOMContentLoaded', load, false); </script> </head> <body> <video id="video" width="240" height="320" autoplay> </video> <p id="error">Click on the video to send a snapshot to the receiving screen</p> <canvas id="canvas" width="240" height="320"> </canvas> </body> </html>

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  • PHP session corrupt

    - by Baversjo
    Using symfony framework 1.4 I have created a website. I'm using sfguard for authentication. Now, this is working great on WAMP (windows). I can login to several accounts on different browsers and use the website. I have ubuntu server 9.10 running apache (everything up to date and default configuration). On my server, when I login to the website in one browser it works great. When I on my other computer login with another user account on the public website, the login is successful. But when I refresh/go to another page the first user is shown as logged in instead! Also, when I press logout, It's not showing that I'm logged out after page load. When I press f5 again I'm logged out. As mentioned, all this works as expected on my local installation. I'm thinking there something wrong with my PHP session configuration on my ubuntu server, but I've never touched it.. Please help me. This is a school project and I'm presenting it today :(

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  • Best way to store this data?

    - by Malfist
    I have just been assigned to renovate an old website, and I get to move it from some old archaic system to drupal. The only problem is that it's a real-estate system and a lot of data is stored. Currently all the information is stored in a single table, an id represents the house and then everything else is key/value pairs. There are a possible 243 keys per estate, there are 23840 estates in the system. As you can imagine the system is slow and difficult to query. I don't think a table with 243 rows would be a very good idea, and probably worse than the current situation. I've done some investigating and here's what I've found out: Missing data does not indicate a 0 value, data is merged from two, unique sources/formats. Some guessing is involved. I have no control over the source of the data. There are 4 keys that are common to all estates, all values look like something that is commonly searched for and could be indexed There are 10 keys that are in the [90-100)% range 8 of these are information like who's selling it, and it's address. The other two seem to belong with the below range There are 80 keys that are in the [80-90)% range This range seems to mostly just list room types and how many the house has (e.g. bedrooms_possible, bathrooms, family_room_3rd, etc) This range also includes some minor information like school districts, one or two more pieces of data on the address. The 179 keys that are in the [0-80)% range include all sorts of miscellaneous information about the estate My best idea was a hybrid approach, create a table that stores important, common information and keep a smaller key/value table. How would you store this information?

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  • Facebook API - Detect if session is active OR NOT active

    - by Tom Doe
    I'm sure I'm simply overlooking something in the Facebook API docs. Basically, after I've loaded the FB Graph, I need to know if the session is active... I cannot simply assume they're logged out and simply re-render if they're logged in once the 'auth.statusChange' event is triggered. I need to know right off the bat. Below is the code that I've used. Most importantly the FB.getLoginStatus/getAuthResponse/getAccessToken don't work like I'd expect; essentially where it indicates, when invoked, whether they're logged in or out. (function(d) { // Create fb-root var fb_root = document.createElement('div'); fb_root.id = "fb-root"; document.getElementsByTagName('body')[0].appendChild( fb_root ); // Load FB Async var js, id = 'facebook-jssdk', ref = d.getElementsByTagName('script')[0]; if (d.getElementById(id)) {return;} js = d.createElement('script'); js.id = id; js.async = true; js.src = "//connect.facebook.net/en_US/all.js"; ref.parentNode.insertBefore(js, ref); // App config-data var config = { appId : XXXX, cookie: true, status: true, frictionlessRequests: true }; window.fbAsyncInit = function() { // This won't work. // I can't assume they're logged out and rely on this to tell me they're logged in. FB.Event.subscribe('auth.statusChange', function(response) {}); // Init FB.init(config); // These do not inidicate if the user is logged out :( FB.getLoginStatus(function(response) { }); FB.getAuthResponse(function(response) { }); FB.getAccessToken(function(response) { }); }; }(document)); Any help is much appreciated. :)

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  • Best way to store data in database when you don't know the type

    - by stiank81
    I have a table in my database that represents datafields in a custom form. The DataField gives some representation of what kind of control it should be represented with, and what value type it should take. Simplified you can say that I have 2 entities in this table - Textbox taking any string and Textbox only taking numbers. Now I have the different values stored in a separate table, referencing the datafield definition. What is the best way to store the data value here, when the type differs? One possible solution is to have the FieldValue table hold one field per possible value type. Now this would certainly be redundant, but at least I would get the value stored in its correct form - simplifying queries later. FieldValue ---------- Id DataFieldId IntValue DoubleValue BoolValue DataValue .. Another possibility is just storing everything as String, and casting this in the queries. I am using .Net with NHibernate, and I see that at least here there is a Projections.Cast that can be used to cast e.g. string to int in the query. Either way in these two solutions I need to know which type to use when doing the query, but I will know that from the DataField, so that won't be a problem. Anyway; I don't think any of these solutions sounds good. Are they? Or is there a better way?

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  • PHP session token can be used multipletimes?

    - by kornesh
    I got page A which is a normal HTML page and page which is an AJAX response page. And I want to prevent CSRF attacks by tokens. Lets say I use this method for an autocomplete form, is it possible to use same token multiple times (of course the session is only set one time) because i tired this method but the validation keep failing after the first suggestion (obviously the token has changed, somehow) page A <?php session_start(); $token = md5(uniqid(rand(), TRUE)); $_SESSION['token'] = $token; ?> <input id="token" value="<?php echo $token; ?>" type="hidden"></input> <input id="autocomplete" placeholder="Type something"></input> .... The form is autosubmitted every time theres a change using Jquery. page B <?php session_start(); if($_REQUEST['token'] == $_SESSION['token']){ echo 'Im working fine'; } ?>

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  • login script in php using session variables

    - by kracekumar
    ? username: '; } else { $user=$_POST['user']; $query="select name from login where name='$user'"; $result=mysql_query($query) or die(mysql_error()); $rows=mysql_num_rows($result)or die(mysql_error()); session_start(); //echo "results"; $username=mysql_fetch_array($result) or die(mysql_error()); $fields=mysql_num_fields($result) or die(mysql_error()); echo "username:$username[0]"; $_SESSION['username']=$username[0]; $sesion_username=$_SESSION['username']; //echo "rows:$rows"." "."fields:$fields"; echo""."username:$sesion_username"; } ? i wanted to create a site where user can login and upload their details depending on their user name have stored their details in a database,the problem i am facing is two people 'a' and 'b' login one after other session_variable $_SESSION['username'] will have 'b's' username ,so i can't display 'a's' details now. . . . what i want to achieve is when a user logins in i want to store his name and other details in session variable and navigate him according and display his details

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  • Javascript/ajax/php question: sending from server to client works, sending from client to server fai

    - by Jeroen Willemsen
    Hey All, Sorry for reposting(Admins, please delete the other one!). since you guys have been a great help, I was kinda hoping that you could help me once again while having the following question: I am currently trying to work with AJAX by allowing a managerclass in PHP to communicate via an XmlHttpobject with the javascript on the clientside. However, I can send something to the client via JSON, but I cannot read it at the clientside. In fact I am getting the error that the "time" is an undefined index in Session. So I was wondering: what am I doing wrong? The javascriptcode for Ajax: <script type="text/javascript"> var sendReq = GetXmlHttpObject(); var receiveReq = GetXmlHttpObject(); var JSONIn = 0; var JSONOut= 0; //var mTimer; //function to retreive xmlHTTp object for AJAX calls (correct) function GetXmlHttpObject() { var xmlHttp=null; try { // Firefox, Opera 8.0+, Safari xmlHttp=new XMLHttpRequest(); } catch (e) { // Internet Explorer try { xmlHttp=new ActiveXObject("Msxml2.XMLHTTP"); } catch (e) { xmlHttp=new ActiveXObject("Microsoft.XMLHTTP"); } } return xmlHttp; } //Gets the new info from the server function getUpdate() { if (receiveReq.readyState == 4 || receiveReq.readyState == 0) { receiveReq.open("GET", "index.php?json="+JSONIn+"&sid=$this->session", true); receiveReq.onreadystatechange = updateState; receiveReq.send(null); } } //send a message to the server. function sendUpdate(JSONstringsend) { JSONOut=JSONstringsend; if (sendReq.readyState == 4 || sendReq.readyState == 0) { sendReq.open("POST", "index.php?json="+JSONstringsend+"&sid=$this->session", true); sendReq.setRequestHeader('Content-Type','application/x-www-form-urlencoded'); alert(JSONstringsend); sendReq.onreadystatechange = updateCycle; sendReq.send(JSONstringsend); } } //When data has been send, update the page. function updateCycle() { getUpdate(); } function updateState() { if (receiveReq.readyState == 4) { // JSONANSWER gets here (correct): var JSONtext = sendReq.responseText; // convert received string to JavaScript object (correct) alert(JSONtext); var JSONobject = JSON.parse(JSONtext); // updates date from the JSONanswer (correct): document.getElementById("dateview").innerHTML= JSONobject.date; } //mTimer = setTimeout('getUpdate();',2000); //Refresh our chat in 2 seconds } </script> The function that actually uses the ajax code: //datepickerdata $(document).ready(function(){ $("#datepicker").datepicker({ onSelect: function(dateText){ var JSONObject = {"date": dateText}; var JSONstring = JSON.stringify(JSONObject); sendUpdate(JSONstring); }, dateFormat: 'dd-mm-yy' }); }); </script> And the PHP code: private function handleReceivedJSon($json){ $this->jsonLocal=array(); $json=$_POST["json"]; $this->jsonDecoded= json_decode($json, true); if(isset($this->jsonDecoded["date"])){ $_SESSION["date"]=$this->jsonDecoded["date"]; $this->useddate=$this->jsonDecoded; } if(isset($this->jsonDecoded["logout"])){ session_destroy(); exit("logout"); } header("Last-Modified: " . gmdate( "D, d M Y H:i:s" ) . "GMT" ); header("Cache-Control: no-cache, must-revalidate" ); header("Pragma: no-cache" ); header("Content-Type: text/xml; charset=utf-8"); exit($json); }

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  • Core Data migration failing with error: Failed to save new store after first pass of migration

    - by unforgiven
    In the past I had already implemented successfully automatic migration from version 1 of my data model to version 2. Now, using SDK 3.1.3, migrating from version 2 to version 3 fails with the following error: Unresolved error Error Domain=NSCocoaErrorDomain Code=134110 UserInfo=0x5363360 "Operation could not be completed. (Cocoa error 134110.)", { NSUnderlyingError = Error Domain=NSCocoaErrorDomain Code=256 UserInfo=0x53622b0 "Operation could not be completed. (Cocoa error 256.)"; reason = "Failed to save new store after first pass of migration."; } I have tried automatic migration using NSMigratePersistentStoresAutomaticallyOption and NSInferMappingModelAutomaticallyOption and also migration using only NSMigratePersistentStoresAutomaticallyOption, providing a mapping model from v2 to v3. I see the above error logged, and no object is available in the application. However, if I quit the application and reopen it, everything is in place and working. The Core Data methods I am using are the following ones - (NSManagedObjectModel *)managedObjectModel { if (managedObjectModel != nil) { return managedObjectModel; } NSString *path = [[NSBundle mainBundle] pathForResource:@"MYAPP" ofType:@"momd"]; NSURL *momURL = [NSURL fileURLWithPath:path]; managedObjectModel = [[NSManagedObjectModel alloc] initWithContentsOfURL:momURL]; return managedObjectModel; } - (NSManagedObjectContext *) managedObjectContext { if (managedObjectContext != nil) { return managedObjectContext; } NSPersistentStoreCoordinator *coordinator = [self persistentStoreCoordinator]; if (coordinator != nil) { managedObjectContext = [[NSManagedObjectContext alloc] init]; [managedObjectContext setPersistentStoreCoordinator: coordinator]; } return managedObjectContext; } - (NSPersistentStoreCoordinator *)persistentStoreCoordinator { if (persistentStoreCoordinator != nil) { return persistentStoreCoordinator; } NSURL *storeUrl = [NSURL fileURLWithPath: [[self applicationDocumentsDirectory] stringByAppendingPathComponent: @"MYAPP.sqlite"]]; NSDictionary *options = [NSDictionary dictionaryWithObjectsAndKeys: [NSNumber numberWithBool:YES], NSMigratePersistentStoresAutomaticallyOption, [NSNumber numberWithBool:YES], NSInferMappingModelAutomaticallyOption, nil]; NSError *error = nil; persistentStoreCoordinator = [[NSPersistentStoreCoordinator alloc] initWithManagedObjectModel: [self managedObjectModel]]; if (![persistentStoreCoordinator addPersistentStoreWithType:NSSQLiteStoreType configuration:nil URL:storeUrl options:options error:&error]) { // Handle error NSLog(@"Unresolved error %@, %@", error, [error userInfo]); } return persistentStoreCoordinator; } In the simulator, I see that this generates a MYAPP~.sqlite files and a MYAPP.sqlite file. I tried to remove the MYAPP~.sqlite file, but BOOL oldExists = [[NSFileManager defaultManager] fileExistsAtPath: [[self applicationDocumentsDirectory] stringByAppendingPathComponent: @"MYAPP~.sqlite"]]; always returns NO. Any clue? Am I doing something wrong? Thank you in advance.

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  • Sharing cookies/session from WebView to HttpClient doesn't work

    - by Toni Kanoni
    I know this question has been asked a hundred times, and I've read and tried for 2 hours now, but I can't find my error :-( I am trying to create a simple webbrowser and therefore have a webview, where I login on a site and get access to a picture area. With help of a DefaultHttpClient, I want to make it possible to download pictures in the secured area. Therefore I am trying to share the cookies from the webview and pass them on to the HttpClient, so that it is authenticated and able to download. But whatever I try and do, I always get a 403 response back... Basically the steps are the following: 1) Enter URL, webview loads website 2) Enter login details in a form 3) Navigate to picture and long hold for context menu 4) Retrieve the image URL and pass it on to AsynTask for downloading Here's the code of the AsyncTask with the Cookie stuff: protected String doInBackground(String... params) { //params[0] is the URL of the image try { CookieManager cookieManager = CookieManager.getInstance(); String c = cookieManager.getCookie(new URL(params[0]).getHost()); BasicCookieStore cookieStore = new BasicCookieStore(); BasicHttpContext localContext = new BasicHttpContext(); localContext.setAttribute(ClientContext.COOKIE_STORE, cookieStore); String[] cookieParts = null; String cookies[] = null; cookies = c.split(";"); for(int i=0;i<cookies.length;i++) { cookieParts = cookies[i].split("="); BasicClientCookie sessionCookie = new BasicClientCookie(cookieParts[0].trim(), cookieParts[1].trim()); sessionCookie.setDomain(new URL(params[0]).getHost()); cookieStore.addCookie(sessionCookie); } DefaultHttpClient httpClient = new DefaultHttpClient(); httpClient.setCookieStore(cookieStore); HttpGet pageGet = new HttpGet(new URL(params[0]).toURI()); HttpResponse response = httpClient.execute(pageGet, localContext); if(response.getStatusLine().getStatusCode() == HttpStatus.SC_OK) -- NEVER Happens, always get 403 .) One of the problems is that the webview saves some cookies for the host *www.*example.com, but the image-URL to download (params[0]) is *static.*example.com. The line cookieManager.getCookie(new URL(params[0]).getHost()); returns null, because there is no cookie for static.example.com, but only for www.example.com. .) When I manually say cookieManager.getCookie("www.example.com"); I get some cookies back, which I add to the HttpClient cookie store: There are 5 cookies added - testcookie = 0 - PHPSESSID = 320947238someGibberishSessionId - email = [email protected] - pass = 32423te32someEncodedPassGibberish - user = 345542 So although these cookies, a session ID and other stuff, get added to the HttpClient, it never get's through to download an image. Im totally lost... though I guess that it either has something to do with the cookies domains, or that Im still missing other cookies. But from where the heck should I know which cookies exist in the webview, when I have to specify a specific URL to get a cookie back?? :-( Any advice?

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  • How to store wiki sites (vcs)

    - by Eugen
    Hello, as a personal project I am trying to write a wiki with the help of django. I'm a beginner when it comes to web development. I am at the (early) point where I need to decide how to store the wiki sites. I have three approaches in mind and would like to know your suggestion. Flat files I considered a flat file approach with a version control system like git or mercurial. Firstly, I would have some example wikis to look at like http://hatta.sheep.art.pl/. Secondly, the vcs would probably deal with editing conflicts and keeping the edit history, so I would not have to reinvent the wheel. And thirdly, I could probably easily clone the wiki repository, so I (or for that matter others) can have an offline copy of the wiki. On the other hand, as far as I know, I can not use django models with flat files. Then, if I wanted to add fields to a wiki site, like a category, I would need to somehow keep a reference to that flat file in order to associate the fields in the database with the flat file. Besides, I don't know if it is a good idea to have all the wiki sites in one repository. I imagine it is more natural to have kind of like a repository per wiki site resp. file. Last but not least, I'm not sure, but I think using flat files would limit my deploying capabilities because web hosts maybe don't allow creating files (I'm thinking, for example, of Google App Engine) Storing in a database By storing the wiki sites in the database I can utilize django models and associate arbitrary fields with the wiki site. I probably would also have an easier life deploying the wiki. But I would not get vcs features like history and conflict resolving per se. I searched for django-extensions to help me and I found django-reversion. However, I do not fully understand if it fit my needs. Does it track model changes like for example if I change the django model file, or does it track the content of the models (which would fit my need). Plus, I do not see if django reversion would help me with edit conflicts. Storing a vcs repository in a database field This would be my ideal solution. It would combine the advantages of both previous approaches without the disadvantages. That is; I would have vcs features but I would save the wiki sites in a database. The problem is: I have no idea how feasible that is. I just imagine saving a wiki site/source together with a git/mercurial repository in a database field. Yet, I somehow doubt database fields work like that. So, I'm open for any other approaches but this is what I came up with. Also, if you're interested, you can find the crappy early test I'm working on here http://github.com/eugenkiss/instantwiki-test

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  • Custom Class to store the properties and passing the class object across the pages - ASP.NEt

    - by NLV
    Hello I've a requirement where i need to pass some objects across the pages. So i created a custom class with all the properties required and created a instance of it and assigned all the properties appropriately. I then put that object in the session and took it the other page. The problem is that even when i set the properties values to the class it is coming as null. I set a breakpoint in the getter-setter and saw that the value itself is coming as null. Code - public class GetDataSetForReports { private Table m_aspTable; private int m_reportID; private string m_accountKey; private string m_siteKey; private string m_imUserName; /// <summary> /// Asp Table containing the filters /// </summary> public Table aspTable { get { return m_aspTable; } set { m_aspTable = aspTable; } } /// <summary> /// Report ID /// </summary> public int reportID { get { return m_reportID; } set { m_reportID = reportID; } } /// <summary> /// All the accounts selected /// </summary> public string accountKey { get { return m_accountKey; } set { m_accountKey = accountKey; } } /// <summary> /// All the sites selected /// </summary> public string siteKey { get { return m_siteKey; } set { m_siteKey = siteKey; } } /// <summary> /// Current User Name /// </summary> public string imUserName { get { return m_imUserName; } set { m_imUserName = imUserName; } } } This is how i'm creating an instance in the page1 and trying to get it in the page2. Page1 Code //Add the objects to the GetDataSetForReports Class GetDataSetForReports oGetDSForReports = new GetDataSetForReports(); oGetDSForReports.aspTable = aspTable; oGetDSForReports.reportID = iReportID; oGetDSForReports.accountKey = AccountKey; oGetDSForReports.siteKey = Sitekey; oGetDSForReports.imUserName = this.imUserName.ToString(); But the values are not getting set at all. The values are not passing to the class (to the setter) at all. Am i making any OOPS blunder? Any ideas? NLV

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  • Can i store a Queue in viewstate? only will store the first item i add to queue

    - by Mausimo
    Hey, as the question states i am trying to store a Queue in a viewstate (to track postbacks and refreshes to stop a form from resubmitting). Here is just the viewstate code: private Queue<string> p_tempQue { set { ViewState["sTemp"] = value; } get { return (Queue<string>)ViewState["sTemp"]; } } //BasePage constructor public BasePage() { //create a Queue of string //sTemp = new Queue(); this.Load += new EventHandler(this.Page_Load); this.Init += new EventHandler(this.Page_Init); } //In the 'page_Init' event we have created a simple hidden field by name 'hdnGuid' which is attached to the page on the first hit itself. protected void Page_Init(object sender, EventArgs e) { //initializing the hidden field //create a hidden field with a ID HiddenField hdnGuid = new HiddenField(); hdnGuid.ID = "hdnGuid"; //if it is the first time the page is loaded, create a new guid and assign it as the hidden field value if (!Page.IsPostBack) hdnGuid.Value = Guid.NewGuid().ToString(); //add the hidden field to the page Page.Form.Controls.Add(hdnGuid); } //In the 'page_Load' event we check if the hidden field value is same as the old value. In case the value is not same that means it's a 'postback' //and if the value is same then its 'refresh'. As per situation we set the 'httpContent.Items["Refresh"]' value. protected void Page_Load(object sender, EventArgs e) { if(p_tempQue != null) sTemp = p_tempQue; else sTemp = new Queue<string>(); //The hdnGuid will be set the first time page is loaded, else the hdnGuid //will be set after each time the form is submitted using javascript. //assign the hidden field currently on the page for manipulation HiddenField h1 = (HiddenField)(Page.Form.FindControl("hdnGuid")); //create an instance of the GuidClass GuidClass currentGuid = new GuidClass(); //set the GuidClass Guid property to the value of the hidden field currentGuid.Guid = h1.Value; //check to see if the Queue of strings contains the string which is the current Guid property of the GuidClass //if the are equal, then the page was refreshed if (sTemp.Contains<string>(currentGuid.Guid)) { //adds item as key/value pair to share data between an System.Web.IHttpModule interface and an System.Web.IHttpHandler interface during an HTTP request. System.Web.HttpContext.Current.Items.Add("IsRefresh", true); } //if they are not requal, the page is not refreshed else { //if the current Guid property in the GuidClass is not null or not an empty string //add the new Guid to the Queue if (!(currentGuid.Guid.Equals(null) || currentGuid.Guid.Equals(""))) sTemp.Enqueue(currentGuid.Guid); System.Web.HttpContext.Current.Items.Add("IsRefresh", false); } p_tempQue = sTemp; }

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  • Set a specific stylesheet based on session variable in javascript

    - by user2371301
    I have an option for a user to select his/her own theme while logged into the system and this theme is set in a MYSQL Database and called each time the user logs in, this is called by: <?php $_SESSION['SESS_THEME_NAME']; ?> Now, I had this working in a PHP file but I need it to work in Javascript instead unfortunately. And I need some help. I looked at the code using the developers tools on Google Chrome and looks like the above code is not resolving within the javascript file. Which makes sense because you can't access session variables within a javascript file (as I found by searching Google.) The code is basically supposed to set the specific stylesheet based on the value extracted from the MYSQL database. So if the database says Default the script needs to tell the webpage to use the default.css file. And so on and so forth. My attempt at writing this is as follows: var themName="<?php $_SESSION['SESS_THEME_NAME']; ?>"; if (themeName == "Default") { document.write("<link re='stylesheet' type='text/css' href='css/mws-theme.css'>"); }; if (themeName == "Army") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-army.css'>"); }; if (themeName == "Rocky Mountains") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-rocky.css'>"); }; if (themeName == "Chinese Temple") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-chinese.css'>"); }; if (themeName == "Boutique") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-boutique.css'>"); }; if (themeName == "Toxic") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-toxic.css'>"); }; if (themeName == "Aquamarine") { document.write("<link rel='stylesheet' type='text/css' href='css/mws-theme-aquamarine.css'>"); }; Any help once so ever would be awesome and much much appreciated! I am reaching a deadline :/

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  • how to fetch & store any column from coredata to array

    - by user440485
    Hi All, I am working on page(Lesson) has button called "AddToFavorite". when i click on this button lessonID,lessonHeading is added in the Coredata. - (NSFetchedResultsController *)fetchedResultsController { // Set up the fetched results controller if needed. if (fetchedResultsController != nil) { return fetchedResultsController; } // Create the fetch request for the entity. NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; // Edit the entity name as appropriate. NSEntityDescription *entity = [NSEntityDescription entityForName:@"Favorites" inManagedObjectContext:managedObjectContext]; [fetchRequest setEntity:entity]; // Edit the sort key as appropriate. NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"lessonHeading" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [fetchRequest setSortDescriptors:sortDescriptors]; NSFetchedResultsController *aFetchedResultsController = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:managedObjectContext sectionNameKeyPath:@"lessonHeading" cacheName:@"Root"]; self.fetchedResultsController = aFetchedResultsController; self.fetchedResultsController.delegate = self; [aFetchedResultsController release]; [fetchRequest release]; [sortDescriptor release]; [sortDescriptors release]; return fetchedResultsController; } -(void)addToFavorites { UIAlertView *alert=[[UIAlertView alloc]initWithTitle:nil message:@"Lesson has been added successfully to your Favorite List" delegate:nil cancelButtonTitle:@"OK" otherButtonTitles:nil]; [alert show]; [alert release]; //Create a new managed object context for the new book -- set its persistent store coordinator to the same as that from the fetched results controller's context. NSManagedObjectContext *addingContext = [[NSManagedObjectContext alloc] init]; self.addingManagedObjectContext = addingContext; [addingManagedObjectContext setPersistentStoreCoordinator:[[fetchedResultsController managedObjectContext] persistentStoreCoordinator]]; Favorites *fav = [NSEntityDescription insertNewObjectForEntityForName:@"Favorites" inManagedObjectContext:addingContext]; fav.lessonID=[[data objectAtIndex:count]objectForKey:@"LessonID"]; fav.lessonTitle=[[data objectAtIndex:count]objectForKey:@"LessonTitle"]; [self didFinishWithSave:YES]; [addingContext release]; } My problem is that i want to show an alert if this lessonID is already existing in the coreData. show guide me how i can match the current page lessonID with the existing lessonID's in the CoreData. I am using CoreData 1st time.so sory for any mistake ...& thanks for ypur help frnds.

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  • session variable values are not being passed between pages

    - by ravi nankani
    hi, i am a little new to php and although i have managed to pass values of session variables before this piece of code is leaving me puzzled <form action="team_reg2.php" method="post" name="form1" class="cent" id="form1"> Team Registration "; print "member$i"; print "\n"; print "\n"; print "Please enter only id\n"; } ? now this will pass via post to team_reg2.php echo " please note your team id is 1 "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } else { $str="select * from $query where ("; for($i=1;$i<=$num;$i++) { $name='mem'.$i; $text="p_id='$_POST[$name]'"; if($i==1) $str=$str.$text; else $str=$str.' or '.$text; } $str=$str.')'; $query2=$str; echo "$str"; // echo "$query2"; $que=mysql_query($query2,$con) or die(mysql_error()); $num=mysql_num_rows($que); if($num!=0) { while($result=mysql_fetch_array($que)) { echo "$result[p_id] is already registered in team $result[t_id]"; } //include("reg_team.html"); } else if($num==0) { //echo $query; $query2="select max(t_id) from $query"; $que=mysql_query($query2,$con) or die(mysql_error()); //echo "$que"; $result=mysql_fetch_array($que); $max=$result['max(t_id)']; $max++; $num=$_SESSION['max_team']; for($i=1;$i<=$num;$i++) { $name='mem'.$i; if($_POST[$name]!="") { $query2="insert into $query values($max,'$_POST[$name]')"; $que=mysql_query($query2,$con); } } echo " please note your team id is $max "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } } ? i have done session_start(); at the beginning of the page itself. The problem is that echoing $_SESSION variables in second file is not printing anything. someone please explain me whats going on. thank you

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  • In NHIbernate, why does SaveOrUpdate() update the Version, but SaveOrUpdateCopy() doesn't?

    - by Daniel T.
    I have a versioned entity, and this is what happens when I use SaveOrUpdate() vs. SaveOrUpdateCopy(): // create new entity var entity = new Entity{ Id = Guid.Empty }); Console.WriteLine(entity.Version); // prints out 0 // save the new entity GetNewSession(); entity.SaveOrUpdate(); Console.WriteLine(entity.Version); // prints out 1 GetNewSession(); // loads the persistent entity into the session, so we have to use // SaveOrUpdateCopy() to merge the following transient entity var dbEntity = Database.GetAll<Entity>(); // new, transient entity used to update the persistent entity in the session var newEntity = new Entity{ Id = Guid.Empty }); newEntity.SaveOrUpdateCopy(); Console.WriteLine(entity.Version); // prints out 1, but should be 2 Why is the version number is not updated for SaveOrUpdateCopy()? As I understand it, the transient entity is merged with the persistent entity. The SQL calls confirm that the data is updated. At this point, shouldn't newEntity become persistent, and the version number incremented?

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  • How to avoid an HttpException due to timeout

    - by Dan
    I'm working on a website powered by .NET asp/C# code. The clients require that sessions have a 25 minute timeout. However, sometimes the site is used, and a user stays connected for long periods of time (longer than 25 mins). Session_End is triggered: protected void Session_End(Object sender, EventArgs e) { Hashtable trackingInformaiton = (Hashtable)Application["trackingInformation"]; trackingInformaiton.Remove(Session["trackingID"]); } The user returns some time later, but when they interact with the website, they get an error, and we get this email notification: User: Unauthenticated User Error: System.Web.HttpException Description: Failed to load viewstate. The control tree into which viewstate is being loaded must match the control tree that was used to save viewstate during the previous request... The telling part of the stack trace is System.Web.UI.Control.AddedControl. Apparently, the server has thrown away the session data, and is sending new data, but the client is trying to deal with old data. Hence the error that "the control tree into which viewstate is being loaded [doesn't] match the control tree that was used to save the viewstate during the prevoius request." So here's the question. How can I force instruct the user's browser to redirect to a "you're logged out" screen when the connection times out? (Is it something I should add to the Session_End method?)

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  • Athentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "string0826" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • Validation with State Pattern for Multi-Page Forms in ASP.NET

    - by philrabin
    I'm trying to implement the state pattern for a multi-page registration form. The data on each page will be accumulated and stored in a session object. Should validation (including service layer calls to the DB) occur on the page level or inside each state class? In other words, should the concrete implementation of IState be concerned with the validation or should it be given a fully populated and valid object? See "EmptyFormState" class below: namespace Example { public class Registrar { private readonly IState formEmptyState; private readonly IState baseInformationComplete; public RegistrarSessionData RegistrarSessionData { get; set;} public Registrar() { RegistrarSessionData = new RegistrarSessionData(); formEmptyState = new EmptyFormState(this); baseInformationComplete = new BasicInfoCompleteState(this); State = formEmptyState; } public IState State { get; set; } public void SubmitData(RegistrarSessionData data) { State.SubmitData(data); } public void ProceedToNextStep() { State.ProceedToNextStep(); } } //actual data stored in the session //to be populated by page public class RegistrarSessionData { public string FirstName { get; set; } public string LastName { get; set; } //will include values of all 4 forms } //State Interface public interface IState { void SubmitData(RegistrarSessionData data); void ProceedToNextStep(); } //Concrete implementation of IState //Beginning state - no data public class EmptyFormState : IState { private readonly Registrar registrar; public EmptyFormState(Registrar registrar) { this.registrar = registrar; } public void SubmitData(RegistrarSessionData data) { //Should Validation occur here? //Should each state object contain a validation class? (IValidator ?) //Should this throw an exception? } public void ProceedToNextStep() { registrar.State = new BasicInfoCompleteState(registrar); } } //Next step, will have 4 in total public class BasicInfoCompleteState : IState { private readonly Registrar registrar; public BasicInfoCompleteState(Registrar registrar) { this.registrar = registrar; } public void SubmitData(RegistrarSessionData data) { //etc } public void ProceedToNextStep() { //etc } } }

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  • Authentication Problem - not recognizing 'else' - Ruby on rails...

    - by bgadoci
    I can't seem to figure out what I am doing wrong here. I have implemented the Super Simple Authentication from Ryan Bates tutorial and while the login portion is functioning correctly, I can't get an error message and redirect to happen correctly for a bad login. Ryan Bates admits in his comments he left this out but can't seem to implement his recommendation. Basically what is happening is that when someone logs in correctly it works. When a bad password is entered it does the same redirect and flashes 'successfully logged in' thought they are not. The admin links do not show (which is correct and are the links protected by the <% if admin? %) but I need it to say 'failed login' and redirect to login path. Here is my code: SessionsController class SessionsController < ApplicationController def create if session[:password] = params[:password] flash[:notice] = 'Successfully logged in' redirect_to posts_path else flash[:notice] = "whoops" redirect_to login_path end end def destroy reset_session flash[:notice] = 'Successfully logged out' redirect_to posts_path end end ApplicationController class ApplicationController < ActionController::Base helper_method :admin? protected def authorize unless admin? flash[:error] = "unauthorized request" redirect_to posts_path false end end def admin? session[:password] == "123456" end helper :all # include all helpers, all the time protect_from_forgery # See ActionController::RequestForgeryProtection for details # end

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  • How to use sessions in PDO?

    - by Byakugan
    I am still redoing and getting rid of old mysql_* commands in my code. I tried to transfer my session login form old code and this is what I got so far: public function login($user, $password) { if (!empty($user) && !empty($password)) { $password = $web->doHash($user, $password); // in this function is (return sha1(strtoupper($user).':'.strtoupper($password)) $stmt = $db_login->prepare("SELECT * FROM account WHERE username=:user AND pass_hash=:password"); $stmt->bindValue(':user', $user, PDO::PARAM_STR); $stmt->bindValue(':password', $password, PDO::PARAM_STR); $stmt->execute(); $rows = $stmt->rowCount(); if ($rows > 0) { $results_login = $stmt->fetch(PDO::FETCH_ASSOC); $_SESSION['user_name'] = $results_login['username']; $_SESSION['user_id'] = $results_login['id']; return true; } else { return false; } } else { return false; } } After that I am using checks if user logged on site: public function isLogged() { return (!empty($_SESSION['user_id']) && !empty($_SESSION['user_name'])); } But it seems - this function returns always empty because $_SESSION does not exists in PDO? And of course logout is used in this form on my sites: public function logout() { unset($_SESSION['user_id']); unset($_SESSION['user_name']); } But I think PDO has different way of handling session? I did not find any so what is it can i somehow add $_SESSION in PDO withou changing code much? I am using variables $_SESSION['user_name'] and $_SESSION['user_id'] in all over my web project. Summary: 1) How to use sessions in PDO correctly? 2) What is difference between using $stmt->fetch(PDO::FETCH_ASSOC); and $stmt->fetchAll(); Thank you.

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