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  • Android ArrayList Calendar add and get is different

    - by Raku ShinShou
    I put increment date of the calendar and add into arraylist, but when i loop them out, the date is all same. Calendar a = Calendar.getInstance(); ArrayList<Calendar> b = new ArrayList<Calendar>(); for (int i=0; i<3; i++) { a.add(Calendar.DATE, i>0 ? 1 : 0); b.add(a); } for (int i=0; i<b.size(); i++){ Log.d("xxx", "test=" + b.get(i)); } suppose i wan 10/11/2012, 11/11/2012, 12/11/2012 but it come out like 12/11/2012, 12/11/2012, 12/11/2012 Anyone know how to solve this?

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  • Why I see only part of the image in the button?

    - by Roman
    I add an image to the button in the following way: ImageIcon icon = new ImageIcon("images/col.jpg"); tmp = new JButton(icon); My image is a red sphere but in my button I see only read color. I assume that I see just a small part of the sphere. How can I see the whole image in the button?

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  • trying to switch beginning of an array with another

    - by user1874574
    I have a problem where i am trying to swap two arrays so that they switch beginnings. example: array 1 = (1,2,3,4,5,6,7,8) and array 2 = (11,12,13,14,15,16,17,18) i want to end up with the first array being (11,12,13,14,5,6,7,8) and i want the second array to be (1,2,3,4,15,16,17,18) but for some reason i end up with 1=(11,12,13,14,5,6,7,8) and 2=(11,12,13,14,15,16,17,18) my code is provided below, what am i doing wrong? public static void Mutate(Genetic lowest, Genetic secondLowest) { int halfway = (lowest.getPopulation().length)/2; int[] one = lowest.getPopulation(); int[] two = secondLowest.getPopulation(); int[] temp = secondLowest.getPopulation(); int[] temp2 = lowest.getPopulation(); for(int i = 0; i < halfway; i++){ temp[i] = one[i]; } lowest.setPopulation(temp); for(int i = 0; i < lowest.getPopulation().length; i++){ System.out.print(temp[i]); } System.out.println(); for(int i = 0; i < halfway; i++){ temp2[i] = two[i]; } for(int i = 0; i < lowest.getPopulation().length; i++){ System.out.print(temp2[i]); } }

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  • Are Interfaces "Object"?

    - by PrashantGupta
    package inheritance; class A{ public String display(){ return "This is A!"; } } interface Workable{ public String work(); } class B extends A implements Workable{ public String work(){ return "B is working!"; } } public class TestInterfaceObject{ public static void main(String... args){ B obj=new B(); Workable w=obj; //System.out.println(w.work()); //invoking work method on Workable type reference System.out.println(w.display()); //invoking display method on Workable type reference //System.out.println(w.hashCode()); // invoking Object's hashCode method on Workable type reference } } As we know that methods which can be invoked depend upon the type of the reference variable on which we are going to invoke. Here, in the code, work() method was invoked on "w" reference (which is Workable type) so method invoking will compile successfully. Then, display() method is invoked on "w" which yields a compilation error which says display method was not found, quite obvious as Workable doesn't know about it. Then we try to invoke the Object class's method i.e. hashCode() which yields a successful compilation and execution. How is it possible? Any logical explanation?

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  • Arrays (toString) not output correctly

    - by DiscoDude
    Hello, Actually this tread is continuing from the other one. There wasn't enough characters to continue there. Anyway. the problem is that the output is "1(10) 2(23) 3(29)". Even though I could return string for the array values (10,23,29) and used string reference as 1, 2 and 3. My question is it possible to return index values 1,2,3 and as well as array values. Am I making an sense. Here is what I have done... // int[] groups = {10, 23, 29}; in the constructor String tempA = ""; String tempB = " "; int[] temp = new int[4]; int length = groups.length; for (int j = 0; j < length; j++) { temp[j] = groups[j]; tempB = tempB + "("+goups+")"; } groups = temp; Arrays.sort(coingroups); for(int i = 1; i < groups.length;i++) { tempA = tempA+" "+(i)+ "("+groups[i]+")"; } return tempA;

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  • how to create a logo and graphical images [closed]

    - by priya
    hi Can you tell me how to create code for this? Insert a new logo of the company Use layout manager to place the components on the applet Insert graphical images The details of the music CDs should be stored category-wise in seperate text files. For example, classic.txt file stores the music titles of classic tracks, western.txt file stores the music title of western tracks. Display the list of the title available with the music store depending upon the category selected. The images should also change according to the selection.

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  • priority queue implementation

    - by davit-datuashvili
    i have implemented priority queue and i am interested if it is correct public class priqueue { private int n,maxsize; int x[]; void swap(int i,int j){ int t=x[i]; x[i]=x[j]; x[j]=t; } public priqueue(int m){ maxsize=m; x=new int [maxsize+1]; n=0; } void insert(int t){ int i,p; x[++n]=t; for (i=n;i>1 && x[p=i/2] >x[i];i=p) swap(p,i); } public int extramin(){ int i,c; int t=x[1]; x[1]=x[n--]; for (i=1;(c=2*i)<=n;i=c){ if (c+1<=n && x[c+1]<x[c]) c++; if (x[i]<=x[c]) break; swap(c,i); } return t; } public void display(){ for (int j=0;j<x.length;j++){ System.out.println(x[j]); } } } public class priorityqueue { public static void main(String[] args) { priqueue pr=new priqueue(12); pr.insert(20); pr.insert(12); pr.insert(22); pr.insert(15); pr.insert(35); pr.insert(17); pr.insert(40); pr.insert(51); pr.insert(26); pr.insert(19); pr.insert(29); pr.insert(23); pr.extramin(); pr.display(); } } //result: 0 12 15 17 20 19 22 40 51 26 35 29 23

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  • Why do I get a Null Pointer Exception?

    - by Roman
    I have this code: Manager manager = new Manager("Name"); MyWindowListener windowListener = new MyWindowListener(); manager.addWindowListener(windowListener); Eclipse writes that I have a NullPointerException in the last line. What can be the reason for that. I do have constructors in the Manager and MyWindowListener. If it's important MyWindowListener implements WindowListener.

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  • Pass reference to ArrayLists to a method.

    - by bhavna raghuvanshi
    here is the whole program: public class ListMerge { public static void main( String[] args) { Scanner input = new Scanner(System.in); System.out.println ("Input length of arraylist 1:"); int n = input.nextInt(); ArrayList x = new ArrayList(); ArrayList y = new ArrayList(); for (int i = 0; i < n; i++) { System.out.println ("Input x[ " + i +"] :" ); x.add(new Integer(i)); } System.out.println ("Input length of arraylist 2:"); int m = input.nextInt(); for (int i = 0; i < m; i++) { System.out.println ("Input y[ " + i +"] :" ); y.add(new Integer(i)); } } list int merge(ArrayList x, ArrayList y) { List all = new ArrayList(); all.addAll(x); all.addAll(y); System.out.println(all); return all; } } also tell me how do i call the function merge?

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  • Alert Box Methods

    - by Vecta
    I just need a little advice on what may be the best method for handling my situation. I'm in need of placing three buttons in the sidebar of the website I maintain. The website is massive and hard to handle. Currently, it's all HTML files (there are over 10,000 of them believe it or not). We're transitioning to a database website so I don't want to make any sweeping changes that are site-wide, as they may just be scrapped in our re-design process in coming months. However, these buttons are for an application process. When you click on them, an alert box will need to pop up to give you a bit of information and they either allow you to cancel the action or proceed. The buttons are currently located in the left nav which is included on every page of the website. Would it be possible to accomplish this using JS or jQuery? I'd be unable to easily add scripts into the tags on all of the applicable pages, but I'd like to avoid the browser driven "http://www...Says: blah blah" message if possible. Any insight is greatly appreciated! Thank you!

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  • the variable only have it value inside while loop?

    - by user1834467
    static void parse(String fileName) throws IOException{ FileReader fileReader=new FileReader((fileName)); BufferedReader bufferedReader = new BufferedReader(fileReader); StringBuilder stringBuilder=new StringBuilder(); String string; StringBuilder myString = null; while((string = bufferedReader.readLine()) != null) { myString =stringBuilder.append(string); String h=myString.toString(); **System.out.println(h);** } } static void parse(String fileName) throws IOException{ FileReader fileReader=new FileReader((fileName)); BufferedReader bufferedReader = new BufferedReader(fileReader); StringBuilder stringBuilder=new StringBuilder(); String string; StringBuilder myString = null; while((string = bufferedReader.readLine()) != null) { myString =stringBuilder.append(string); String h=myString.toString(); } **System.out.println(h);** } when I try the second part of the code, it print out nothing. how can I get the whole h String outside of the while loop? Is it I have to declare the variable h as instance variable instead of local variable?

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  • JVM memory management & garbage collection book?

    - by Max
    Hi. Could anyone advice a book (or any other source) that would thoroughly reveal internals of JVM memory management & garbage collection (optimization, work, circular references, pecularities, discussions for various JVM impls...)? [What I've found so far are separate articles devoted to various aspects but no weighty tome :). Some good materials for Hotspot implementation are here. ] Thanks a lot for any advice you give.

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  • OnLowMemory getting called

    - by Sam97305421562
    Hi, I am doing an App which access the gprs .I am facing problem when the user starts another application who uses gprs also like google maps .It takes it own heap memory ,after doing some operation on Maps app it calls OnLowMemory of my service .and my ui is also killed in background. I am not getting any proper tutorial haw can i start my app when it is getting killed during onLowMemory ,or is there any other way to handle it . Thanks in advance.

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