Search Results

Search found 2877 results on 116 pages for 'dollar sign'.

Page 96/116 | < Previous Page | 92 93 94 95 96 97 98 99 100 101 102 103  | Next Page >

  • problem getting info from a cookie with javascript

    - by Jason
    I am having an issue with my cookies and I can't figure it out. Basically I have it set up so it checks for the cookie to see if the user is logged in, and then displays either a welcome message or a login link. It works - except that instead of returning the persons name in the welcome message it just is blank where the name should be. The cookie is there, with all the appropriate info.. not sure what I am doing wrong. var itm = new Array(); itm[0] = findCookie("ui"); if (itm[0] == null) { document.write("<h2><a href='logreg.html'>Log In or Sign Up</a></h2>"); } else { var c1 = itm[0].indexOf(","); var c2 = itm[0].indexOf(",",c1); var c3 = itm[0].indexOf(",",c2); var gname = itm[0].substring(c2,c3); document.write("<h2>Welcome "+gname+"!</h2>"); } The findCookie function is.. function findCookie(val){ var cookie = null; var findVal = val + "="; var dc = document.cookie; if (dc.length > 0) { var start = dc.indexOf(findVal); if (start >= 0) { start += findVal.length; lastVal = dc.indexOf(";", start); if (lastVal == -1) { lastVal = dc.length; } cookie = (dc.substring(start, lastVal)); } else { return cookie; } } return cookie; }

    Read the article

  • Virtual Lan on the Cloud -- Help Confirm my understanding?

    - by marfarma
    [Note: Tried to post this over at ServerFault, but I don't have enough 'points' for more than one link. Powers that be, move this question over there.] Please give this a quick read and let me know if I'm missing something before I start trying to make this work. I'm not a systems admin professional, and I'd hate to end up banging my head into the wall if I can avoid it. Goals: Create a 'road-warrior' capable star shaped virtual LAN for consultants who spend the majority of their time on client sites, and who's firm has no physical network or servers. Enable CIFS access to a cloud-server based installation of Alfresco Allow Eventual implementation of some form of single-sign-on ( OpenLDAP server ) access to Alfresco and other server applications implemented in the future Given: All Servers will live in the public internet cloud (Rackspace Cloud Servers) OpenVPN Server will be a Linux disto, probably Ubuntu 9.x, installed on same server as Alfresco (at least to start) Staff will access server applications and resources from client sites, hotels, trains, planes, coffee shops or their homes over various ISP, using their company laptops or personal home desktops. Based on my Research thus far, to accomplish this, I'll need: OpenVPN with Bridging Enabled to create a star shaped "virtual" LAN http://openvpn.net/index.php/open-source/documentation/miscellaneous/76-ethernet-bridging.html A Road Warrior Network Configuration, as described in this Shorewall article (lower down the page) http://www.shorewall.net/OPENVPN.html Configure bridge addressesing (probably DHCP) http://openvpn.net/index.php/open-source/faq.html#bridge-addressing Configure CIFS / Samba to accept VPN IP address http://serverfault.com/questions/137933/howto-access-samba-share-over-vpn-tunnel Set up Client software, with keys configured for access (potentially through a OpenVPN-Sa client portal) http://www.openvpn.net/index.php/access-server/download-openvpn-as/221-installation-overview.html

    Read the article

  • Problem with authentication from different domains using Django sessions.

    - by Greg
    Hi all, I am developing a bookmarklet which essentially adds a toolbar to a web page user is currently looking at. To use it, user needs to be logged in. To login user clicks on 'Singin' which displays a standard form containing Username, Password etc fields. When user successfully logs in they may chose to navigate to a different web-site. When on another page, they (a) re-load the bookmarklet (b) their session is retrieved from the server (c) user doesn't need to login again. Pretty standard I've would have thought. Using Django sessions and JQuery. I'm having troubles implementing the above usecase. Here are some problems I've encountered: Cross domain POST AJAX requests are disallowed. That was solved with JSONp. I doubt it is a very secure approach but for now it works. My server returns the session id in a cookie, however when the user navigates to a different page I don't really know how to retrieve that session id to send back to my server. Can I even read third party cookies from my JavaScript? I'm looking for some guidelines on implementing the above usecase. Ideally I don't want to redirect user to another page for them to sign in. Any suggestion would be greatly appreciated. Thanks.

    Read the article

  • Error mounting CloudDrive snapshot in Azure

    - by Dave
    Hi, I've been running a cloud drive snapshot in dev for a while now with no probs. I'm now trying to get this working in Azure. I can't for the life of me get it to work. This is my latest error: Microsoft.WindowsAzure.Storage.CloudDriveException: Unknown Error HRESULT=D000000D ---> Microsoft.Window.CloudDrive.Interop.InteropCloudDriveException: Exception of type 'Microsoft.WindowsAzure.CloudDrive.Interop.InteropCloudDriveException' was thrown. at ThrowIfFailed(UInt32 hr) at Microsoft.WindowsAzure.CloudDrive.Interop.InteropCloudDrive.Mount(String url, SignatureCallBack sign, String mount, Int32 cacheSize, UInt32 flags) at Microsoft.WindowsAzure.StorageClient.CloudDrive.Mount(Int32 cacheSize, DriveMountOptions options) Any idea what is causing this? I'm running both the WorkerRole and Storage in Azure so it's nothing to do with the dev simulation environment disconnect. This is my code to mount the snapshot: CloudDrive.InitializeCache(localPath.TrimEnd('\\'), size); var container = _blobStorage.GetContainerReference(containerName); var blob = container.GetPageBlobReference(driveName); CloudDrive cloudDrive = _cloudStorageAccount.CreateCloudDrive(blob.Uri.AbsoluteUri); string snapshotUri; try { snapshotUri = cloudDrive.Snapshot().AbsoluteUri; Log.Info("CloudDrive Snapshot = '{0}'", snapshotUri); } catch (Exception ex) { throw new InvalidCloudDriveException(string.Format( "An exception has been thrown trying to create the CloudDrive '{0}'. This may be because it doesn't exist.", cloudDrive.Uri.AbsoluteUri), ex); } cloudDrive = _cloudStorageAccount.CreateCloudDrive(snapshotUri); Log.Info("CloudDrive created: {0}", snapshotUri, cloudDrive); string driveLetter = cloudDrive.Mount(size, DriveMountOptions.None); The .Mount() method at the end is what's now failing. Please help as this has me royally stumped! Thanks in advance. Dave

    Read the article

  • Cross domain login - what to store in the database?

    - by Jenkz
    I'm working on a system which will allow me to login to the same system via various domains. (www.example.com, www.mydomain.com, sub.domain.com etc) The following threads form the basis of my research so far: Single Sign On across multiple domains Cross web domain login with .net membership What I want to happen is that If I am logged in on the master domain and I visit a page on a client domain to be automatically logged in on the client. Obviously If I am not logged in on the master, I will need to enter my username and password. Walkthrough: 1. User logs in on master site 2. User navigates to client site 3. Client site re-directs to master site to see if User is logged in. 4. If User is logged in on master, record a RFC 4122 token ID and send this back to the client site. 5. Client site then looks up the token ID in the central database and logs this user in. This might eventually end up running on more than once instance of PHP and Apache, so I can't just store: token_id, php_session_id, created Is there any problem with me storing and using this: token_id, username, hashed_password, created Which is deleted on use, or automatically after x seconds.

    Read the article

  • Invalid iPhone Application Binary

    - by Kristopher Johnson
    I'm trying to upload an application to the iPhone App Store, but I get this error message from iTunes Connect: The binary you uploaded was invalid. The signature was invalid, or it was not signed with an Apple submission certificate. My guess is that it is not properly signed. I have downloaded my App Store distribution certficate, but I can't figure out how to "sign" my application with it. The SDK's documentation about code signing is not very helpful. (FWIW, I can install the app on my iPhone just fine using the development provisioning profile.) However, it is possible that I screwed things up on a more basic level. Here's what I did to try to prepare it for upload: In Xcode, select the Device|Release target Select the target and click the Info button. Change "Code Signing Identity" to "iPhone Distribution", and change "Code Signing Provisioning Profile" to my App Store distribution profile. Build Go to the directory where the built MyApp.app bundle is, control-click and choose "Compress" to create MyApp.zip Upload MyApp.zip to the App Store via iTunes Connect (which resulted in the above error message). Can anybody give me any hints? Edit: Found someone with the same problem. Unfortunately, he won't tell us how he fixed it. http://www.rhonabwy.com/wp/2008/07/18/seattlebus-diary-ongoing-update-saga/#comments http://www.rhonabwy.com/wp/2008/07/22/seattlebus-diary-update-is-pending-review/ (Note: For general information on submitting iPhone applications to the App Store, see Steps to upload an iPhone application to the AppStore.)

    Read the article

  • Firefox drags div like it was an image, javascript event handlers possibly to blame

    - by user281434
    Hi, I'm using this HTML,CSS and Javascript code (in one document together if you want to test it out): <style type="text/css"> #slider_container { width: 200px; height: 30px; background-color: red; display:block; } #slider { width: 20px; height: 30px; background-color: blue; display:block; position:absolute; left:0; } </style> <script type="text/javascript" src="../../js/libs/jquery-1.4.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#slider").mousedown(function() { $(document).mousemove(function(evnt) { $("#test").html("sliding"); }).mouseup(function() { $("#test").html("not sliding"); $(document).unbind("mousemove mouseup"); });}); }); </script> <div id="test">a</div> <div id="slider_container"> <div id="slider"></div> </div> Everything (surprisingly) works fine in IE, but firefox seems to totally clusterf*ck when this javascript is used. The first "slide" is okay, you drag, it says "sliding", you drop, it says "not sliding". On the second "slide" (or mousedown if you will), firefox suddenly thinks the div is an image or link and wants to drag it around. Screenshot of the dragging: http://i.imgur.com/nPJxZ.jpg Obviously the blue div half-positioned in the red div is the one being dragged. Windows does not capture the cursor when you take a screenshot, but it's a stop sign. Is there someway to prevent this default behaviour?

    Read the article

  • C# .NET: Descending comparison of a SortedDictionary?

    - by Rosarch
    I'm want a IDictionary<float, foo> that returns the larges values of the key first. private IDictionary<float, foo> layers = new SortedDictionary<float, foo>(new DescendingComparer<float>()); class DescendingComparer<T> : IComparer<T> where T : IComparable<T> { public int Compare(T x, T y) { return -y.CompareTo(x); } } However, this returns values in order of the smallest first. I feel like I'm making a stupid mistake here. Just to see what would happen, I removed the - sign from the comparator: public int Compare(T x, T y) { return y.CompareTo(x); } But I got the same result. This reinforces my intuition that I'm making a stupid error. This is the code that accesses the dictionary: foreach (KeyValuePair<float, foo> kv in sortedLayers) { // ... } UPDATE: This works, but is too slow to call as frequently as I need to call this method: IOrderedEnumerable<KeyValuePair<float, foo>> sortedLayers = layers.OrderByDescending(kv => kv.Key); foreach (KeyValuePair<float, ICollection<IGameObjectController>> kv in sortedLayers) { // ... } UPDATE: I put a break point in the comparator that never gets hit as I add and remove kv pairs from the dictionary. What could this mean?

    Read the article

  • Using stdint.h and ANSI printf?

    - by nn
    Hi, I'm writing a bignum library, and I want to use efficient data types to represent the digits. Particularly integer for the digit, and long (if strictly double the size of the integer) for intermediate representations when adding and multiplying. I will be using some C99 functionality, but trying to conform to ANSI C. Currently I have the following in my bignum library: #include <stdint.h> #if defined(__LP64__) || defined(__amd64) || defined(__x86_64) || defined(__amd64__) || defined(__amd64__) || defined(_LP64) typedef uint64_t u_w; typedef uint32_t u_hw; #define BIGNUM_DIGITS 2048 #define U_HW_BITS 16 #define U_W_BITS 32 #define U_HW_MAX UINT32_MAX #define U_HW_MIN UINT32_MIN #define U_W_MAX UINT64_MAX #define U_W_MIN UINT64_MIN #else typedef uint32_t u_w; typedef uint16_t u_hw; #define BIGNUM_DIGITS 4096 #define U_HW_BITS 16 #define U_W_BITS 32 #define U_HW_MAX UINT16_MAX #define U_HW_MIN UINT16_MIN #define U_W_MAX UINT32_MAX #define U_W_MIN UINT32_MIN #endif typedef struct bn { int sign; int n_digits; // #digits should exclude carry (digits = limbs) int carry; u_hw tab[BIGNUM_DIGITS]; } bn; As I haven't written a procedure to write the bignum in decimal, I have to analyze the intermediate array and printf the values of each digit. However I don't know which conversion specifier to use with printf. Preferably I would like to write to the terminal the digit encoded in hexadecimal. The underlying issue is, that I want two data types, one that is twice as long as the other, and further use them with printf using standard conversion specifiers. It would be ideal if int is 32bits and long is 64bits but I don't know how to guarantee this using a preprocessor, and when it comes time to use functions such as printf that solely rely on the standard types I no longer know what to use.

    Read the article

  • VS 2008 designer and usercontrol.

    - by Ram
    Hello, I have created a custom data grid control. I dragged it on windows form and set its properties like column and all & ran the project. It built successfully and I am able to view the grid control on the form. Now if i try to view that form in designer, I am getting following error.. Object reference not set to an instance of an object. Instances of this error (1) 1. Hide Call Stack at Microsoft.VisualStudio.Design.Serialization.CodeDom.XML.CodeDomXmlProcessor.GetMemberTargetObject(XmlElementData xmlElementData, String& member) at Microsoft.VisualStudio.Design.Serialization.CodeDom.XML.CodeDomXmlProcessor.CreateAssignStatement(XmlElementData xmlElement) at Microsoft.VisualStudio.Design.Serialization.CodeDom.XML.CodeDomXmlProcessor.XmlElementData.get_CodeDomElement() at Microsoft.VisualStudio.Design.Serialization.CodeDom.XML.CodeDomXmlProcessor.EndElement(String prefix, String name, String urn) at Microsoft.VisualStudio.Design.Serialization.CodeDom.XML.CodeDomXmlProcessor.Parse(XmlReader reader) at Microsoft.VisualStudio.Design.Serialization.CodeDom.XML.CodeDomXmlProcessor.ParseXml(String xmlStream, CodeStatementCollection statementCollection, String fileName, String methodName) at Microsoft.VisualStudio.Design.Serialization.CodeDom.VSCodeDomParser.OnMethodPopulateStatements(Object sender, EventArgs e) at System.CodeDom.CodeMemberMethod.get_Statements() at System.ComponentModel.Design.Serialization.TypeCodeDomSerializer.Deserialize(IDesignerSerializationManager manager, CodeTypeDeclaration declaration) at System.ComponentModel.Design.Serialization.CodeDomDesignerLoader.PerformLoad(IDesignerSerializationManager manager) at Microsoft.VisualStudio.Design.Serialization.CodeDom.VSCodeDomDesignerLoader.PerformLoad(IDesignerSerializationManager serializationManager) at Microsoft.VisualStudio.Design.Serialization.CodeDom.VSCodeDomDesignerLoader.DeferredLoadHandler.Microsoft.VisualStudio.TextManager.Interop.IVsTextBufferDataEvents.OnLoadCompleted(Int32 fReload) If I ignore the exception, form appears blank with no sign of grid control on it. However I can see the code for the grid in the designer file. Any pointer on this would be a great help. I have customized grid for my custom requirements like I have added custom text box n all. I have defined 3 constructors public GridControl() public GridControl(IContainer container) protected GridControl(SerializationInfo info, StreamingContext context)

    Read the article

  • problem with ajax on the hosting server

    - by nelly
    when I Implemented chatting Function , I use Ajax to send messages between file to another . so , it is working well on local host . but , when I upload it in to remote server it doesn't work. can U tell me ,why ? is an Ajax need Special configuration ? there is my files that I used : Ajax .js file witch has "ajax_send" function that i used in chatbox.js file chatbox.js file wich consest of functions i used it to send data from php file to another one and it display the state (any user sign in or new sending message and so on ..) user.php file whitch responseble to write user name in the text file usersonline.txt and then display the online users in the online users column. send.php file that write on room1.text recive.php file that read room1.txt and then write the content into the chat box I beleve that the problem comes from the ajax code in Ajax.js File so please help me find out the problem and how to solve it. is ajax needs special server settings ? because it was working at the local host !

    Read the article

  • Programmatically talking to a Serial Port in OS X or Linux

    - by deadprogrammer
    I have a Prolite LED sign that I like to set up to show scrolling search queries from a apache logs and other fun statistics. The problem is, my G5 does not have a serial port, so I have to use a usb to serial dongle. It shows up as /dev/cu.usbserial and /dev/tty.usbserial . When i do this everything seems to be hunky-dory: stty -f /dev/cu.usbserial speed 9600 baud; lflags: -icanon -isig -iexten -echo iflags: -icrnl -ixon -ixany -imaxbel -brkint oflags: -opost -onlcr -oxtabs cflags: cs8 -parenb Everything also works when I use the serial port tool to talk to it. If I run this piece of code while the above mentioned serial port tool, everthing also works. But as soon as I disconnect the tool the connection gets lost. #!/usr/bin/python import serial ser = serial.Serial('/dev/cu.usbserial', 9600, timeout=10) ser.write("<ID01><PA> \r\n") read_chars = ser.read(20) print read_chars ser.close() So the question is, what magicks do I need to perform to start talking to the serial port without the serial port tool? Is that a permissions problem? Also, what's the difference between /dev/cu.usbserial and /dev/tty.usbserial?

    Read the article

  • How do I create Twitter style URLs for my app - Using existing application or app redesign - Ruby on

    - by bgadoci
    I have developed a blog application of sorts that I am trying to allow other users to take advantage of (for free and mostly for family). I wondering if the authentication I have set up will allow for such a thing. Here is the scenario. Currently the application allows for users to sign up for an account and when they do so they can create blog posts and organize those posts via tags. The application displays no data publicly (another words, you have to login to see anything). To gain access you have to create an account and even after you do, you cannot see anyone else's information as the applications filters using the current_user method and displays in the /posts/index.html.erb page. This would be great if a user only wanted to blog and share it with themselves, not really what I am looking for. My question has two parts (hopefully I won't make anyone mad by not putting these into two questions) Is it possible for a particular users data to live at www.myapplication.com/user without moving everything to the /user/show.html.erb file? Is it possible to make some of that information (living at the URL) public but still require login for create and destroy actions. Essentially, exactly like twitter. I am just curious if I can get from where I am (using the current_user methods across controllers to display in /posts/index.html.erb) to where I want to be. My fear is that I have to redesign the app such that the user data lives in the /user/show.html.erb page. Thoughts? UPDATE: I am using Clearance for authentication by Thoughtbot. I wonder if there is something I can set in the vendored gem path to represent the /posts/index.html.erb code as the /user/id code and replace id with the user name.

    Read the article

  • How do I create Twitter style URL's for my app - Using existing application or app redesign - Ruby o

    - by bgadoci
    I have developed a blog application of sorts that I am trying to allow other users to take advantage of (for free and mostly for family). I wondering if the authentication I have set up will allow for such a thing. Here is the scenario. Currently the application allows for users to sign up for an account and when they do so they can create blog posts and organize those posts via tags. The application displays no data publicly (another words, you have to login to see anything). To gain access you have to create an account and even after you do, you cannot see anyone else's information as the applications filters using the current_user method and displays in the /posts/index.html.erb page. This would be great if a user only wanted to blog and share it with themselves, not really what I am looking for. My question has two parts (hopefully I won't make anyone mad by not putting these into two questions) Is it possible for a particular users data to live at www.myapplication.com/user without moving everything to the /user/show.html.erb file? Is it possible to make some of that information (living at the URL) public but still require login for create and destroy actions. Essentially, exactly like twitter. I am just curious if I can get from where I am (using the current_user methods across controllers to display in /posts/index.html.erb) to where I want to be. My fear is that I have to redesign the app such that the user data lives in the /user/show.html.erb page. Thoughts?

    Read the article

  • java - BigDecimal

    - by Mk12
    I was trying to make my own class for currencies using longs, but Apparently I should use BigDecimal (and then whenever I print it just add the $ sign before it). Could someone please get me started? What would be the best way to use BigDecimals for Dollar currencies, like making it at least but no more than 2 decimal places for the cents, etc. The api for BigDecimal is huge, and I don't know which methods to use. Also, BigDecimal has better precision, but isn't that all lost if it passes through a double? if I do new BigDecimal(24.99), how will it be different than using a double? Or should I use the constructor that uses a String instead? EDIT: I decided to use BigDecimals, and then use: private static final java.text.NumberFormat moneyt = java.text.NumberFormat.getCurrencyInstance(); { money.setRoundingMode(RoundingMode.HALF_EVEN); } and then whenever I display the BigDecimals, to use money.format(theBigDecimal). Is this alright? Should I have the BigDecimal rounding it too? Because then it doesn't get rounded before it does another operation.. if so, could you show me how? And how should I create the BigDecimals? new BigDecimal("24.99") ? Well, after many comments to Vineet Reynolds (thanks for keeping coming back and answering), this is what I have decided. I use BigDecimals and a NumberFormat. Here is where I create the NumberFormat instance. private static final NumberFormat money; static { money = NumberFormat.getCurrencyInstance(Locale.CANADA); money.setRoundingMode(RoundingMode.HALF_EVEN); } Here is my BigDecimal: private final BigDecimal price; Whenever I want to display the price, or another BigDecimal that I got through calculations of price, I use: money.format(price) to get the String. Whenever I want to store the price, or a calculation from price, in a database or in a field or anywhere, I use (for a field): myCalculatedResult = price.add(new BigDecimal("34.58")).setScale(2, RoundingMode.HALF_EVEN); .. but I'm thinking now maybe I should not have the NumberFormat round, but when I want to display do this: System.out.print(money.format(price.setScale(2, RoundingMode.HALF_EVEN); That way to ensure the model and things displayed in the view are the same. I don't do: price = price.setScale(2, RoundingMode.HALF_EVEN); Because then it would always round to 2 decimal places and wouldn't be as precise in calculations. So its all solved now, I guess. But is there any shortcut to typing calculatedResult.setScale(2, RoundingMode.HALF_EVEN) all the time? All I can think of is static importing HALF_EVEN... EDIT: I've changed my mind a bit, I think if I store a value, I won't round it unless I have no more operations to do with it, e.g. if it was the final total that will be charged to someone. I will only round things at the end, or whenever necessary, and I will still use NumberFormat for the currency formatting, but since I always want rounding for display, I made a static method for display: public static String moneyFormat(BigDecimal price) { return money.format(price.setScale(2, RoundingMode.HALF_EVEN)); } So values stored in variables won't be rounded, and I'll use that method to display prices.

    Read the article

  • How to remove accidental branch in TortoiseHg?

    - by msorens
    (I am a relative newcomer to TortoiseHg, so bear with me :-) I use TortoiseHg on two machines to talk to my remote source repository. I made changes on one machine, committed them, and attempted to push them to the remote repository BUT I forgot to first do a pull to get the latest code first. The push gave me a few lines of output, suggesting I may have forgotten to pull first (true!) and mentioned something like "abort: push creates new remote branches...". So I did a pull, which added several nodes to the head of my graph in the repository explorer. The problem is that the push I tried to do is now showing as a branch in the repository explorer. Looking from the server side (codeplex), it shows no sign of my attempted push, indicating this accidental branch is still local on my machine. How could I remove this accidental branch? I tried selecting that node in the graph then doing "revert" but it did not seem to do anything. I am wondering if it would be simplest to just discard my directory tree on my local machine and do a completely new, clean pull from the server...?

    Read the article

  • Rails 2.3 session

    - by Sam Kong
    Hi, I am developing a rails 2.3.2 app. I need to keep session_id for an order record, retrieve it and finally delete the session_id when the order is completed. It worked when I used cookies as session store but it doesn't for active_record store. (I restarted my browser, so no cache issue.) I know rails 2.3 implements lazy session load. I read some info about it but am still confused. Can somebody clarify how I use session_id for such a case? What I am doing is... A user make an order going through several pages. There is no sign-up, neither login. So I keep session_id in the order record so that no other user can access the order. @order = Order.last :conditions = {:id = params[:id], :session_id = session[:session_id] } When the order is finished, I set nil to session_id column. How would you implement such a case in lazy session(and active_record store) environment? Thanks. Sam

    Read the article

  • Logout exception flooding elmah

    - by durilai
    I am using ASP.NET membership, and in particular a copy of the membership code included in the MVC project. I am also using elmah to log exceptions. I am getting flooded with the following when people sign out. System.Web.HttpException: Server cannot set status after HTTP headers have been sent. Here is the stack trace sent System.Web.HttpException: Server cannot set status after HTTP headers have been sent. at System.Web.HttpResponse.set_StatusCode(Int32 value) at System.Web.HttpResponseWrapper.set_StatusCode(Int32 value) at System.Web.Mvc.HandleErrorAttribute.OnException(ExceptionContext filterContext) at System.Web.Mvc.ControllerActionInvoker.InvokeExceptionFilters(ControllerContext controllerContext, IList`1 filters, Exception exception) at System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName) at System.Web.Mvc.Controller.ExecuteCore() at System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext) at System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext) at System.Web.Mvc.MvcHandler.<>c__DisplayClass8.<BeginProcessRequest>b__4() at System.Web.Mvc.Async.AsyncResultWrapper.<>c__DisplayClass1.<MakeVoidDelegate>b__0() at System.Web.Mvc.Async.AsyncResultWrapper.<>c__DisplayClass8`1.<BeginSynchronous>b__7(IAsyncResult _) at System.Web.Mvc.Async.AsyncResultWrapper.WrappedAsyncResult`1.End() at System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult) at System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result) at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) I cannot seem to find any reason for this. It is not causing an issue for end users, but would still like to resolve/learn about it. Thanks for any help or guidance.

    Read the article

  • Automatically install and launch a code-signed application from Safari

    - by Thomas Jung
    Is it possible and if so what are the steps necessary to package (or build) a Mac OS X application and code-sign it so that it can be downloaded with Safari and automatically launch? ... possibly after the user responds to some sort of dialog explaining that it is a signed application and the publisher has been verified. An example of the user experience I am trying to create is "installing Google Chrome for the first time on Windows", which is a 3-click, less-than-a-minute process. For the concerned among you: I am not trying to create a drive-by download. I am fine with some sort of intermittent user step approving the download. I just want to make the installation as quick and painless as possible and not require the user drag the app from a mounted DMG into the application folder. This may not 100% jibe with established Mac OS X user interaction guidelines, but it would work better for the not-power users. I only need the high-level steps or pointers to resources ... my google-fu was weak on this one.

    Read the article

  • Sharepoint isn't accepting new Credentials initially when switching users.

    - by Tiziani
    Hi all, I have a standard website (one webapplication and one site collection) with some custom pages and webparts. The issue I'm having is that when I try to switch users, using the "Sign In As a Different User" and entering new credentials (even for another site collection admin account), IE tries the account three times, and then it presents a 401 Access Denied screen. After that, if I erase all the stuff of access denied page from the browser's url, I'm logged as the new account I just had entered and was not accepted. After researching for a while on google, I found a KB ( http://support.microsoft.com/kb/970814 ) that might relate, but just tested here and it didn't work at all. The modified method suggested by the KB is the following: function LoginAsAnother(url, bUseSource) { document.cookie="loginAsDifferentAttemptCount=0"; if (bUseSource=="1") { GoToPage(url); } else { //var ch=url.indexOf("?") =0 ? "&" : "?"; //url+=ch+"Source="+escapeProperly(window.location.href); //STSNavigate(url); document.execCommand("ClearAuthenticationCache"); } } But after making this change, it no longer asks for a new credential. Any ideas?

    Read the article

  • How to create a view to manage associations between HABTM models? (Rails)

    - by Chris Hart
    Hello, I am using Ruby on Rails and need to create a view that allows the creation of records through a HABTM relationship to another model. Specifically, I have the following models: Customer and ServiceOverride, and a join table customers_serviceoverrides. Using the customer view for create/update, I need to be able to create, update and delete ServiceOverrides and manage the attributes of the associated model(s) from the same view. Visually I'd prefer to have something like a plus/minus sign to add/delete service overrides, and each serviceoverride record has two string entities which need to be displayed and editable as well. However, if I could just get the code (a kind of nested form, I'm assuming?) working, I could work out the UI aspects. The models are pretty simple: class ServiceOverride < ActiveRecord::Base has_and_belongs_to_many :customers end class Customer < ActiveRecord::Base has_and_belongs_to_many :serviceoverrides end The closest thing I've found explaining this online is on this blog but it doesn't really address what I'm trying to do (both manage the linkages to the other model, and edit attributes of that model. Any help is appreciated. Thanks in advance. Chris

    Read the article

  • Python: Networked IDLE/Redo IDLE front-end while using the same back-end?

    - by Rosarch
    Is there any existing web app that lets multiple users work with an interactive IDLE type session at once? Something like: IDLE 2.6.4 Morgan: >>> letters = list("abcdefg") Morgan: >>> # now, how would you iterate over letters? Jack: >>> for char in letters: print "char %s" % char char a char b char c char d char e char f char g Morgan: >>> # nice nice If not, I would like to create one. Is there some module I can use that simulates an interactive session? I'd want an interface like this: def class InteractiveSession(): ''' An interactive Python session ''' def putLine(line): ''' Evaluates line ''' pass def outputLines(): ''' A list of all lines that have been output by the session ''' pass def currentVars(): ''' A dictionary of currently defined variables and their values ''' pass (Although that last function would be more of an extra feature.) To formulate my problem another way: I'd like to create a new front end for IDLE. How can I do this? UPDATE: Or maybe I can simulate IDLE through eval()? UPDATE 2: What if I did something like this: I already have a simple GAE Python chat app set up, that allows users to sign in, make chat rooms, and chat with each other. Instead of just saving incoming messages to the datastore, I could do something like this: def putLine(line, user, chat_room): ''' Evaluates line for the session used by chat_room ''' # get the interactive session for this chat room curr_vars = InteractiveSession.objects.where("chatRoom = %s" % chat_room).get() result = eval(prepared_line, curr_vars.state, {}) curr_vars.state = curr_globals curr_vars.lines.append((user, line)) if result: curr_vars.lines.append(('SELF', result.__str__())) curr_vars.put() The InteractiveSession model: def class InteractiveSession(db.Model): # a dictionary mapping variables to values # it looks like GAE doesn't actually have a dictionary field, so what would be best to use here? state = db.DictionaryProperty() # a transcript of the session # # a list of tuples of the form (user, line_entered) # # looks something like: # # [('Morgan', '# hello'), # ('Jack', 'x = []'), # ('Morgan', 'x.append(1)'), # ('Jack', 'x'), # ('SELF', '[1]')] lines = db.ListProperty() Could this work, or am I way off/this approach is infeasible/I'm duplicating work when I should use something already built?

    Read the article

  • Prevent Navigation to CreateUserWizardStep in the Postback event of nextbutton

    - by Aparna
    I am working with CreateUserWizard tool for creating a registration page. This is the first time and I am encountering problem with the following: I defined two steps in WizardSteps in the page: <WizardSteps> <asp:WizardStep ID="CreateUserWizardStep0" runat="server" Title="Sign Up for your new Account !!"> <asp:TextBox ID="Email" runat="server"> In the first wizard step, the user provides email, and we need to check if this email meets certain criteria (if he exists in our internal database, country is US etc) and if he/she is eligible navigate to CreateUserWizardStep1. I have a StartNextButton in the Start Navigation template for the WizardStep0. <StartNavigationTemplate> <br /> <asp:Button ID="StartNextButton" runat="server" CommandName="MoveNext" OnClick="StartNextButton_Click" Text="Check My Eligibility" /> </StartNavigationTemplate> I do all the logic of checking eligibility in the post-back event OnClick="StartNextButton_Click . If he is not eligible, I should display the error message in the step0 textbox and prevent navigation to CreateUserWizardStep1. I tried the following: if(noteligible) { lblError1.Visible = true; lblError1.Text = this.hfUserAlreadyRegistered.Value.ToString(); this.CreateUserWizard1.ActiveStepIndex = this.CreateUserWizard1.WizardSteps.IndexOf(this.CreateUserWizardStep0); this.CreateUserWizard1.Controls.Remove(CreateUserWizardStep1); this.CreateUserWizard1.ActiveStepIndex = 0; break; } But this is not working. I am taken out of step0 and step1 is coming irrespective of this. How can I just remain in Step0 and display the error message when the user is not eligible and navigate to Step1 only when he is eligible to register ? Thank you very much.

    Read the article

  • php curl login problem

    - by user331329
    <?php // create a new CURL resource $file_path = '/mail'; define("COOKIE_FILE", "c:\cookie.txt"); $ch = curl_init(); // set URL and other appropriate options curl_setopt($ch, CURLOPT_URL, "https://mail.gov.in/iwc/signin"); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, FALSE); curl_setopt ($ch, CURLOPT_USERAGENT, "Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.6) Gecko/20070725 Firefox/2.0.0.6"); curl_setopt ($ch, CURLOPT_TIMEOUT, 60); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 1); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt ($ch, CURLOPT_COOKIESESSION, TRUE); session_write_close(); $strCookie = 'PHPSESSID=d095af0e30afc021dd3652734009' . $_COOKIE['PHPSESSID'] . '; path=/mail'; curl_setopt( $ch, CURLOPT_COOKIE, $strCookie ); curl_setopt ($ch, CURLOPT_COOKIEJAR, COOKIE_FILE); curl_setopt($ch, CURLOPT_COOKIEFILE, COOKIE_FILE); curl_setopt ($ch, CURLOPT_POST, 1); curl_setopt ($ch, CURLOPT_POSTFIELDS,'fromLogin=true&domainName=nic.in&username=&password=&button=Sign%20In'); $url = curl_getinfo($ch); // grab URL and pass it to the browser $data = curl_exec($ch); echo $data."<pre>"; echo "<pre>"; print_r($url); // close CURL resource, and free up system resources curl_close($ch); ?> whats wrong with my code why i am not able to login directly in their mail

    Read the article

  • Workaround for basic syntax not being parsed.

    - by Mark Tomlin
    I want to have a class property that allow for an expression to take place on the right side of the equals sign. All versions of PHP choke on the following code, but it is written in this way to allow for easier extendibility in the future. /* Example SDK Class */ class SDK { /* Runtime Option Flags */ // Strings # 0: Makes no change to the strings. var $STRING_NONE = (1 << 0); # 1: Removes color codes from the string. var $STRING_STRIP_COLOR = (1 << 1); # 2: Removes language codes from the string. var $STRING_STRIP_LANG = (1 << 2); # 3: Removes all formatting from the string. var $STRING_STRIP = SELF::STRING_STRIP_COLOR & SELF::STRING_STRIP_LANG; # 4: Converts color codes to HTML & UTF-8. var $STRING_HTML = (1 << 3); # 8: Converts color codes to ECMA-48 escape color codes & UTF-8. var $STRING_CONSOLE = (1 << 4); # 16: Changes player names only. var $STRING_NAMES = (1 << 5); # 32: Changes host names only. var $STRING_HOSTS = (1 << 6); function SDK($fString = SELF::STRING_HTML & SELF::STRING_NAMES & SELF_HOST) { // constructor code. } } $SDK &= new SDK(SDK::STRING_NONE); (1 << 0) seems like very basic syntax to me, and is not fathomable why PHP would not allow for such a thing. Can anyone think of a work around that would maintain readability and future expandability of the following code?

    Read the article

< Previous Page | 92 93 94 95 96 97 98 99 100 101 102 103  | Next Page >