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  • Downloading a Directory Tree with FTPLIB

    - by Anthony Lemmer
    I'd like to download a directory and all of its contents to the local HD. Here's the code I have thus far (crashes if there's a sub-directory, else grabs all the files): import ftplib import configparser import os def runBackups(): #Load INI filename = 'connections.ini' config = configparser.SafeConfigParser() config.read(filename) connections = config.sections() i = 0 while i < len(connections): #Load Settings uri = config.get(connections[i], "uri") username = config.get(connections[i], "username") password = config.get(connections[i], "password") backupPath = config.get(connections[i], "backuppath") archiveTo = config.get(connections[i], "archiveto") #Start Back-ups ftp = ftplib.FTP(uri) ftp.login(username, password) ftp.set_debuglevel(2) ftp.cwd(backupPath) files = ftp.nlst() for filename in files: ftp.retrbinary('RETR %s' % filename, open(os.path.join(archiveTo, filename), 'wb').write) ftp.quit() i += 1 print() print("Back-ups complete.") print()

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  • Localizing concatenated or dynamic strings

    - by SooDesuNe
    I'm familiar with using NSLocalizedString() to localize strings, but the problem I have today requires a little more finesse. My situation is like this: NSString *userName; //the users name, entered by the user. Does not need localized NSString *favoriteFood; //the users favorite food, also entered by user, and not needing localized NSString *summary = [NSString stringWithFormat:@"%@'s favorite food is %@", userName, favoriteFood]; This works fine for english, but not every language uses the same word ordering as English, for example, a word-by-word translation of the same sentance from Japanese into English would read: UserName's favorite food pizza is Not to mention that 's is doesn't make a possessive in every language. What techniques are available for localizing this type of concatenated sentence?

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  • PHP Error - Login Script

    - by gamerzfuse
    I am creating a new login script/members directory. I am creating it from scratch without any frameworks (advice on this matter would also be appreciated). The situation: // Look up the username and password in the database $query = "SELECT admin_id, username FROM admin WHERE adminname = '$admin_user' AND password = SHA1('$admin_pass')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { This bit of code keeps giving me an error (the last line in particular): Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in /home8/craighoo/public_html/employees/security/dir_admin.php on line 20 When echoing the query I get: SELECT admin_id, username FROM admin WHERE adminname = 'admin' AND password = SHA1('tera#byte') Thanks in advance!

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  • MySQL query cache and PHP variables

    - by Saif Bechan
    I have seen the following statement made about the query cache: // query cache does NOT work $r = mysql_query("SELECT username FROM user WHERE signup_date >= CURDATE()"); // query cache works! $today = date("Y-m-d"); $r = mysql_query("SELECT username FROM user WHERE signup_date >= '$today'"); So the query cache only works on the second query. I was wondering if the query cache will also work on this: define('__TODAY',date("Y-m-d")); $r = mysql_query("SELECT username FROM user WHERE signup_date >= '".__TODAY."'");

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  • How to access web server of any machine of my network from the outside

    - by Luc
    Hello, I have an ip like username.dyndns.org, this is the external IP of my router. On my lan, I have several machine (m1, m2, ...) , each running a dedicated web server. Is it possible to reach each machine from the outside with something like: http://m1.username.dyndns.org http://m2.username.dyndns.org ? Do you know what needs to be configured in my router for NAT ? Also, is there a special directive in Apache to do so ? Thanks a lot, Regards, Luc

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  • using joins or multiple queries in php/mysql

    - by askkirati
    Here i need help with joins. I have two tables say articles and users. while displaying articles i need to display also the user info like username, etc. So will it be better if i just use joins to join the articles and user tables to fetch the user info while displaying articles like below. SELECT a.*,u.username,u.id FROM articles a JOIN users u ON u.id=a.user_id OR can this one in php. First i get the articles with below sql SELECT * FROM articles Then after i get the articles array i loop though it and get the user info inside each loop like below SELECT username, id FROM users WHERE id='".$articles->user_id."'; Which is better can i have explanation on why too. Thank you for any reply or views

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  • JPA optimistic lock - setting @Version to entity class cause query to include VERSION as column

    - by masato-san
    I'm using JPA Toplink Essential, Netbean6.8, GlassFish v3 In my Entity class I added @Version annotation to enable optimistic locking at transaction commit however after I added the annotation, my query started including VERSION as column thus throwing SQL exception. None of this is mentioned in any tutorial I've seen so far. What could be wrong? Snippet public class MasatosanTest2 implements Serializable { private static final long serialVersionUID = 1L; @Id @Basic(optional = false) @Column(name = "id") private Integer id; @Column(name = "username") private String username; @Column(name = "note") private String note; //here adding Version @Version int version; query used: SELECT m FROM MasatosanTest2 m Internal Exception: com.microsoft.sqlserver.jdbc.SQLServerException Call: SELECT id, username, note, VERSION FROM MasatosanTest2

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  • Is it possible to scan Entities in jar files using JPA and hibernate

    - by user1260109
    I have the following situation : Project A - Contains a few entities and is independent Project B - Contains a few entities and is independent Project C - Contains few entities and is dependent on Project A & Project B. I am using Maven to manage dependencies and builds. When I try to test Project A and project B it goes through fine. Each of them has a persistence.xml and a separate persistent context. When I run Project C , It does map any of the entities. I have tried to use the auto-detect, specified the jar file attribute ... but nothing seems to work. It gives me a Mapping Exception saying unknown entity and wont persist or read the Entities from Projects A or B. I have posted the 3 persistence.xml files here. Also, I tried using the class attribute and using the same persistent context but it just wont find the files. Any help is really appreciated. Thanks in advance ! <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="A" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/> <property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.connection.username" value="username"/> <property name="hibernate.connection.password" value="password"/> <property name="hibernate.connection.url" value="jdbc:oracle:thin:@webdev.epi.web:1521/webdev.world"/> <property name="hibernate.max_fetch_depth" value="3"/> <property name="hibernate.archive.autodetection" value="class"/> </properties> </persistence-unit> </persistence> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="B" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/> <property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.connection.username" value="username"/> <property name="hibernate.connection.password" value="password"/> <property name="hibernate.connection.url" value="jdbc:oracle:thin:@webdev.epi.web:1521/webdev.world"/> <property name="hibernate.max_fetch_depth" value="3"/> <property name="hibernate.archive.autodetection" value="class"/> </properties> </persistence-unit> </persistence> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="C" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <jar-file>A-0.0.1-SNAPSHOT.jar</jar-file> <jar-file>B-0.0.1-SNAPSHOT.jar</jar-file> <properties> <property name="hibernate.dialect" value="org.hibernate.dialect.Oracle9Dialect"/> <property name="hibernate.connection.driver_class" value="oracle.jdbc.OracleDriver"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.connection.username" value="username"/> <property name="hibernate.connection.password" value="password"/> <property name="hibernate.connection.url" value="jdbc:oracle:thin:@webdev.epi.web:1521/webdev.world"/> <property name="hibernate.max_fetch_depth" value="3"/> <property name="hibernate.archive.autodetection" value="class"/> </properties> </persistence-unit> </persistence>

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  • PHP: form action on same page, still show same until refresh

    - by Karem
    Yes, Im having a little edit profile page, index.php?mode=profile. Lets take the username in the editprofile form as example. The username is already in the username-field. So i changed from "Peter" to "Tom" and press save. The action is ?mode=profile&edit=true. So now when i have pressed save it has updated the column in the db from Peter to Tom. But this field keeps having the value "Peter" until if i do press refresh (or f5), then "Tom" will appear. Like it hasnt updated in the database anything, although it did but it still shows Peter until next refresh.. like it caches, but it shouldnt cache nothing? Any help on this? Is it because its on the same "page" / file? what can i do

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  • multiple login pages in ASP.NET forms authentication

    - by Brad
    My bank's website has 2 login pages for online banking. On the first page, I enter my username. If I don't enter a valid username, I get an error message, and do not get to the 2nd page. The 2nd page displays a picture based on my user name, and has me enter my password. If I manually type a URL to a page inside the site after entering my username but before entering my password, I am redirected back to the first login page. Is there a good way to implement this in ASP.NET with Forms Authentication? I only get 1 loginUrl in my web.config. I am fairly certain my bank uses Java.

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  • checkUnique function?

    - by Chris Leah
    Hey, so I have created a function to check the DB for unique entries, but when I call the function it doesn't seem to work and gives me a fatal error any ideas from the function or do you wish to see the sign up page calling it. Thanks :) //Check for unique entries function checkUnique($table, $field, $compared) { $query = $mysqli->query('SELECT '.$mysqli->real_escape_string($field).' FROM '.$mysqli->real_escape_string($table).' WHERE "'.$mysqli->real_escape_string($field).'" = "'.$mysqli->real_escape_string($compared).'"'); if(!$query){ return TRUE; } else { return FALSE; } } The page calling it..... if (!empty($_POST['username']) && !empty($_POST['password']) && $_POST['password']==$_POST['password_confirm'] && !empty($_POST['email']) && validateEmail($_POST['email']) == TRUE && checkUnqiue('users', 'email', $_POST['email']) == TRUE && checkUnique('users', 'username', $_POST['username']) == TRUE)

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  • Quick MySQLi security question

    - by Benjamin Falk
    I have a quick MySQLi security related question... For example, take a look at this code (gets in put from the user, checks it against the database to see if the username/password combination exist): $input['user'] = htmlentities($_POST['username'], ENT_QUOTES); $input['pass'] = htmlentities($_POST['password'], ENT_QUOTES); // query db if ($stmt = $mysqli->prepare("SELECT * FROM members WHERE username=? AND password = ?")) { $stmt->bind_param("ss", $input['user'], md5($input['pass'] . $config['salt'])); $stmt->execute(); $stmt->store_result(); // check if there is a match in the database for the user/password combination if ($stmt->num_rows > 0) {} } In this case, I am using htmlentities() on the form data, and using a MySQLi prepared statement. Do I still need to be using mysql_real_escape_string()?

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  • How do you update the aspnetdb membership IsApproved value?

    - by Matt
    I need to update existing users IsApproved status in the aspnet_Membership table. I have the code below that does not seem to be working. The user.IsApproved property is updated but it is not saving it to the database table. Are there any additional calls I need to make? Any suggestions? Thanks. /// <summary> /// Updates a users approval status to the specified value /// </summary> /// <param name="userName">The user to update</param> /// <param name="isApproved">The updated approval status</param> public static void UpdateApprovalStatus(string userName, bool isApproved) { MembershipUser user = Membership.GetUser(userName); if (user != null) user.IsApproved = isApproved; }

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  • XSS to change ASP.NET session state

    - by Juri Bogdanov
    Hello! I am developing the application that stores current user and user's role to session state (System.Web.SessionState.HttpSessionState Page.Session). if (Session["username"] == null) Session.Add("username", User.Identity.Name); if (Session["isAdministrator"] == null) Session.Add("isAdministrator", User.IsInRole(domain + "\\Domain Admins")); After I check these session states in code behind for granting permissions to some excecution: if ((bool)Session["isAdministrator"] || computer.Administrators.Contains(Session["username"].ToString())) My question is next: how safe that mechanism is? Is it possible to change the session states using some JavaScript for example or some how else? Thanks :)

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  • Can't append space at end of UITextView

    - by Sam V
    I have a UITextView in which I want the initial value to be "@username " (notice the space after the username). This way the user can start typing right away without having to tap space. So I do: textView.text = [NSString stringWithFormat:@"@%@ ", username]; But it seems like it's impossible to have the UITextView text property ending with a space (it always gets stripped out). Am I correct? Is there any workaround for this? I tried using the \s char and no success.

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  • A controller problem using a base CRUD model

    - by rkj
    In CodeIgniter I'm using a base CRUD My_model, but I have this small problem in my browse-controller.. My $data['posts'] gets all posts from the table called "posts". Though the author in that table is just a user_id, which is why I need to use my "getusername" function (gets the username from a ID - the ID) to grab the username from the users table. Though I don't know how to proceed from here, since it is not just one post. Therefore I need the username to either be a part of the $data['posts'] array or some other smart solution. Anyone who can help me out? function index() { $this->load->model('browse_model'); $data['posts'] = $this->browse_model->get_all(); $data['user'] = $this->browse_model->getusername(XX); $this->load->view('header'); $this->load->view('browse/index', $data); $this->load->view('footer'); }

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  • FTP to SFTP in shell scripting

    - by Kimi
    This script is to connect to different servers and copy a file from a loaction defined. It is mandatory to use sftp and not ftp. #!/usr/bin/ksh -xvf Detail="jyotibo|snv4915|/tlmusr1/tlm/rt/jyotibo/JyotiBo/ jyotibo|snv4915|/tlmusr1/tlm/rt/jyotibo/JyotiBo/" password=Unix11! c_filename=import.log localpath1=`pwd` for i in $Detail do echo $i UserName=`echo $i | cut -d'|' -f1` echo $UserName remotehost=`echo $i | cut -d'|' -f2` echo $remotehost remote_path=`echo $i | cut -d'|' -f3` echo $remote_path { echo "open $remotehost user $UserName $password lcd $localpath1 cd $remote_path bi prompt mget $c_filename prompt " } |ftp -i -n -v 2>&1 done I want to do the similar thing using sftp instead of ftp.

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  • What is the best way to marshal a char array function argument?

    - by Seh Hui 'Felix' Leong
    Let say that given the following signature in LegacyLib.dll: int Login(SysInst *inst, char username[8], char password[6]); The simple way to marshal this function in C# would be: [DllImport("LegacyLib.dll", CharSet=CharSet.Ansi)] public static extern int Login(ref SysInst inst, string username, string password); The problem of doing it in a such a naive way is that the managed string we passed into the username or password parameter could be longer than the array bounds and this could potentially cause a buffer overrun in LegacyLib.dll. Is there a better way which overcomes this problem? i.e. is there any quick [MarshalAs(…)] magic that I could use to counter that?

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  • How to get login password in servlets

    - by Dusk
    I've successfully implemented form based authentication, and now I want to get the username and password to initialize session object in javamail from servlets. How can I do that? I can getlogin username by using method request.getRemoteUser(), but I don't know how to get the password. If I create any session object like: authentication = new PasswordAuthentication(user,password); Properties props = new Properties(); props.put("mail.host", "localhost"); props.put("mail.debug",true); props.put("mail.store.protocol", "pop3"); props.put("mail.transport.protocol", "smtp"); Session session = Session.getInstance(props, this); then how can I get inbox messages from mail server based upon particular username and password, if I don't pass any password from servlets to PasswordAuthentication object?

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  • How do I make an HTTP Post with HTTP Basic Authentication, using POCO?

    - by Alyoshak
    I'm trying to make an HTTP Post with HTTP Basic Authentication (cleartext username and password), using POCO. I found an example of a Get and have tried to modify it, but being a rookie I think I've mangled it beyond usefulness. Anyone know how to do this? Yes, I've already seen the other SO question on this: POCO C++ - NET SSL - how to POST HTTPS request, but I can't make sense of how it is trying to implement the username and password part. I also don't understand the use of "x-www-form-urlencoded". Is this required for a Post? I don't have a form. Just want to POST to the server with username and password parameters.

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  • not getting output from parmiko/ssh command

    - by Matt
    I am using paramiko/ssh/python to attempt to run a command on a remote server. When I ssh manually and run the command in question, I get the results I want. But if I use the python (co-opted from another thread on this site) below, there is no returned data. If I modify the command to be something more basic like 'pwd' or 'ls' I can then get the output. Any help is appreciated. Thanks, Matt import paramiko import time import sys, os, select import select username='medelman' password='Ru5h21iz' hostname='10.15.27.166' hostport=22 cmd='tail -f /x/web/mlog.txt' #works cmd='' #doesn't work client = paramiko.SSHClient() client.load_system_host_keys() client.connect(hostname=hostname, username=username, password=password) transport = client.get_transport() channel = transport.open_session() channel.exec_command(cmd) while True: rl, wl, xl = select.select([channel],[],[],0.0) if len(rl) 0: # Must be stdout print channel.recv(1024) time.sleep(1)

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  • codeigniter: how to redirect after login to current controller (php_self in regular php)

    - by krike
    Well it's not really a problem but I check if the user exist and log them in and redirect to site/members_area, but I don't want to send the user to a specific page but i want to reload the current controller. So if I login in index/home I would like to be redirected at index/home, how should I proceed? in regular php I would put in the action to redirect to current page <?php echo $_SERVER['PHP_SELF']; ?> This is the code in the framework function validate_credentials() { $this->load->model('membership_model'); $query = $this->membership_model->validate(); if($query) // if the user's credentials validated... { $data = array( 'username' => $this->input->post('username'), 'is_logged_in' => true ); $this->session->set_userdata($data); redirect('site/members_area'); //<-- this line here should be dynamic } else // incorrect username or password { $this->index(); } }

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  • PHP MYSQL Endless Loop

    - by Neb
    Hi, I have a problem with my php/mysql script. It should only output the while loop once but I am getting unlimited loops and an endless page. $query = mysql_query("SELECT * FROM users WHERE username ='".base64_encode($_SESSION['username'])."' LIMIT 1"); $result = mysql_fetch_array($query); if(empty($result)){ echo "No user... Error"; }else{ while($row = $result){ ?> <a href="index.php?user=<?=$row['id']?>"><?=base64_decode($row['username'])?></a> | <a href="javascript:void(0);" id="logout">Logout</a> <?php } } I have tried a similar script with these same lines and it works perfectly $result = mysql_fetch_array($query); if(empty($result)){ echo "No user... Error"; }else{ while($row = $result){ //Something } }

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  • Push origin master error on new repository.

    - by thaiyoshi
    I just started using git with github. I followed their instructions and ran into errors on the last step. I'm checking in an existing directory that isn't currently source-controlled (project about a week old). Other than that, my use case should be pretty run of the mill. Here's what's happening: $ git push origin master error: src refspec master does not match any. fatal: The remote end hung up unexpectedly error: failed to push some refs to '[email protected]:{username}/{projectname}.git' Github's instructions: Global setup: Download and install Git git config --global user.name "Your Name" git config --global user.email {username}@gmail.com Next steps: mkdir projectname cd projectname git init touch README git add README git commit -m 'first commit' git remote add origin [email protected]:{username}/{projectname}.git git push origin master

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  • Using JSON, passing variable from php to javascript

    - by Ryan Fung
    I wonder why it is not working? check_login.php <?php session_start(); $data = array("username" => "true"); echo json_encode($data); ?> my js file var linkName; $.ajax({ type: "POST", url: "check_login.php", dataType: "json", success: function(json){ if(json.username != "true") { //do something } } }); I am trying to get the username after checking whether or not the user has signed in yet in the php file, something like passing a session variable. But currently passing a string seems to already have a problem. Any know what I did wrong here? Still not working the code above. Anyone want to help me out here?

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