Search Results

Search found 8303 results on 333 pages for 'color picker'.

Page 98/333 | < Previous Page | 94 95 96 97 98 99 100 101 102 103 104 105  | Next Page >

  • Help for CSS Menu Dropdown, FF OK and IE6 Problem

    - by Taruhku
    IE Problem, FF OK. Please help..???? Screen Shoot problem click here This is my CSS dolphincontainer { position:relative; height:56px; color:#E0E0E0; background:#143D55; width:100%; font-family:Tahoma; left: 0px; } dolphinnav {position:absolute;;height:33px;font-size:12px;font-weight:bold;background:#fff url(images/dolphin_bg.gif) repeat-x bottom left;padding:0 0 0 10px;width:975px;} dolphinnav ul {margin:0;padding:0;list-style-type:none;width:auto;float:left;} dolphinnav ul li {display:block;float:left;margin:0 1px;} dolphinnav ul li a {display:block;float:left;color:#001b2c;text-decoration:none;padding:0 0 0 10px;height:33px;} dolphinnav ul li a span {padding:12px 20px 0 0;height:21px;float:left;font-weight:bold;} dolphinnav ul li a:hover {color:#fff;background:transparent url(images/dolphin_bg-OVER.gif) repeat-x bottom left;} dolphinnav ul li a:hover span {display:block;width:auto;cursor:pointer;} dolphinnav ul li a.current,#dolphinnav ul li a.current:hover {color:#fff;background:#00517e url(images/dolphin_left-ON.gif) no-repeat top left;line-height:275%;} dolphinnav ul li a.current span {display:block;padding:0 20px 0 0;width:auto;background:#00517e url(images/dolphin_right-ON.gif) no-repeat top right;height:33px;} .tuckUp { display:block; width:90px; height:30px; overflow:hidden; cursor:pointer; } .pullDown { width:90px; height:56px; } .item a:link, .item a:visited { display:inline; float:left; background:#fff url(images/dolphin_bg.gif) repeat-x top left;padding:0 0 0 10px; text-align:left; color:#444; font-size:11px; font-weight:bold; text-decoration:none; line-height:25px; margin:0 5px 0px 0px; width:80px; } .item a:hover { display:inline; float:left; background:#39c; color:#FFF; text-decoration:none; text-align:left; font-size:11px; font-weight:700; font-weight:bold; line-height:25px; padding:0 0 0 10px; margin:0 5px 0px 0px; width:80px; } HTML: <div id="dolphincontainer"> <div id="dolphinnav"> <ul> <li><a href="index.php"><span>Home</span></a></li> <li><a href="chooseus.php"><span>Why Choose Us</span></a></li> <li><a href="peraturan.php"><span>Rules</span></a></li> <li class="tuckUp" onmousemove="this.className='pullDown'" onmouseout="this.className='tuckUp'"><a href="#"><span>Transaction</span></a> <div class="item"> <a href="drop1.php">Drop Down 1</a><br /> <a href="drop2.php">Drop Down 2</a></a><br /> <a href="drop3.php">Drop Down 3</a><br /> </div> </li> <li><a href="download.php"><span>Download</span></a></li> <li><a href="aboutus.php"><span>About Us</span></a></li> <li><a href="help.php" class="current"><span>Support</span></a></li> <li><a href="promo.php"><span><font color="#FF0000"><blink>PROMO</blink> </font></span></a></li> </ul> </div> </div>

    Read the article

  • Easiest way to submit data via PHP?

    - by Abijah
    I'm new to PHP, and have spent 10 hours trying to figure this problem out. The goal is to take all data entered into this order form, and send it to my email via PHP. I have 2 questions: 1. I can get PHP to send data from a single menu item (example: Mexican Tortas), but how do I get PHP to send data from multiple items (example: Mexican Tortas, Fish Sandwich and Hamburger)? 2. How do I tell PHP to not send data from menu items that don't have the "How Many?" or "Customize It?" text fields filled out? If you could provide a super simple example (or a link to a learning resource) I would really appreciate it. Thank you, Abijah PHP <?php if(isset($_POST['submit'])) { $to = "[email protected]"; $subject = "New Order"; $name_field = $_POST['name']; $phone_field = $_POST['phone']; $item = $_POST['item']; $quantity = $_POST['quantity']; $customize = $_POST['customize']; } $body = "Name: $name_field\nPhone: $phone_field\n\nItem: $item\nQuantity: $quantity\nCustomize: $customize"; echo "Data has been submitted to $to!"; mail($to, $subject, $body); ?> HTML <form action="neworder.php" method="POST"> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/mexicantortas.jpg"> <h1>Mexican Torta - $8.50</h1> <input name="item" type="hidden" value="Mexican Torta"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/fishsandwich.jpg"> <h1>Fish Sandwich - $8.50</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class ="item"> <img style="float:left; margin-right:15px; border:1px Solid #000; width:200px; height:155px;" src="images/hamburgers.jpg"> <h1>Hamburger w/ Fries - $7.00</h1> <input name="item" type="hidden" value="Fish Sandwich"/> <h2>How Many? <font color="#999999">Ex: 1, 2, 3...?</font></h2> <input name="quantity" type="text"/> <h3>Customize It? <font color="#999999">Ex: No Lettuce, Extra Cheese...</font></h3> <textarea name="customize"/></textarea> </div><!-- ITEM_LEFT --> <div class="horizontal_form"> <div class="form"> <h2>Place Your Order Now: <font size="3"><font color="#037B41">Fill in the form below, and we'll call you when your food is ready to be picked up...</font></font></h2> <p class="name"> <input type="text" name="name" id="name" style="text-align:center;" onClick="this.value='';" value="Enter your name"/> </p> <p class="phone"> <input type="text" name="phone" id="phone" style="text-align:center;" onClick="this.value='';" value="Enter your phone #"/> </p> <p class="submit"> <input type="submit" value="Place Order" name="submit"/> </p> </div><!-- FORM --> </div><!-- HORIZONTAL_FORM --> </form>

    Read the article

  • How can I make a table move in JavaScript?

    - by Michal Skrzypek
    My problem is that I was creating a simple website the other day and I needed the content to move according to the button pressed. I managed to do so in CSS3, but the solution did not work for IE whatsoever. Therefore I would like to ask if there is a simple solution for that in js? I don't know js at all but I heard what I need is much easier in js than in css. Details: http://i42.tinypic.com/6yl4ia.png I need the table in the picture to move according to the buttons (which are labels to be exact). The visible area is a div. Here's the relevant code (without animation as I was not satisfied with it): body { background-color: #fff; color: #fff; padding:0px; } #bodywrapperfixed { width: 1248px; margin: 0px auto; position: relative; overflow: hidden; height: 730px; } #bodywrapper { display:block; background-color: #fff; width: 1248px; color: #59595B; padding-top:50px; font-family: 'Roboto', sans-serif; position: absolute; top:0px; left:0px; z-index:1; font-size: 60px; height:730px; } #bodywrapper img { width:400px; padding:15px 0px 20px 0px; } #texten { font-family: 'Roboto', sans-serif; font-size: 35px; padding:5px; } #textpl { font-family: 'Roboto', sans-serif; font-size: 25px; padding:5px; } table#linki { width: 110px; border: none; margin-top:15px; } label { display: block; height: 54px; width: 54px; color:#fff; font-family: 'Roboto', sans-serif; font-weight: 300; font-size: 35px; background-color: #117D10; text-align: center; padding:23px; } label:hover { background-color: #004F00; cursor: pointer; } input#pl { position: absolute; top: -9999px; left: -9999px; } input#en { position: absolute; top: -9999px; left: -9999px; } and the relevant HTML: <div id="bodywrapperfixed"> <div id="bodywrapperfloat"> <table id="ramka"> <tr> <td>random text</td> <td><div id="bodywrapper"> <center> <div id="texten"><div style="font-weight:300; display:inline-block;">Introducing the all-in-one entertainment system.</div><div style="font-weight:500; display:inline-block;">&nbsp;For everyone.</div></div> <div id="textpl"><div style="font-weight:300; display:inline-block;">Przedstawiamy zintegrowany system rozrywki.</div><div style="font-weight:500; display:inline-block;">&nbsp;&nbsp;Dla wszystkich.</div></div> <img src="imgs/xboxone.png"> <div id="texten"><div style="font-weight:300; display:inline-block;">Choose your version of the story:</div></div> <div id="textpl"><div style="font-weight:300; display:inline-block;">Wybierz swoja wersja opowiesci:</div></div> <table id="linki"> <tr> <td><label for="en">en</label><input id="en" type="checkbox"></td> <td><label for="pl">pl</label><input id="pl" type="checkbox"></td> </tr></table> </center> </div></td> <td>random text</td> </tr> </table> </div> </div> Here's what it looks like: http://ingame.lh.pl/thinkone/ Please help me.

    Read the article

  • Configure Forms based authentication in SharePoint 2010

    - by sreejukg
      Configuring form authentication is a straight forward task in SharePoint. Mostly public facing websites built on SharePoint requires form based authentication. Recently, one of the WCM implementation where I was included in the project team required registration system. Any internet user can register to the site and the site offering them some membership specific functionalities once the user logged in. Since the registration open for all, I don’t want to store all those users in Active Directory. I have decided to use Forms based authentication for those users. This is a typical scenario of form authentication in SharePoint implementation. To implement form authentication you require the following A data store where you are storing the users – technically this can be active directory, SQL server database, LDAP etc. Form authentication will redirect the user to the login page, if the request is not authenticated. In the login page, there will be controls that validate the user inputs against the configured data store. In this article, I am going to use SQL server database with ASP.Net membership API’s to configure form based authentication in SharePoint 2010. This article assumes that you have SQL membership database available. I already configured the membership and roles database using aspnet_regsql command. If you want to know how to configure membership database using aspnet_regsql command, read the below blog post. http://weblogs.asp.net/sreejukg/archive/2011/06/16/usage-of-aspnet-regsql-exe-in-asp-net-4.aspx The snapshot of the database after implementing membership and role manager is as follows. I have used the database name “aspnetdb_claim”. Make sure you have created the database and make sure your database contains tables and stored procedures for membership. Create a web application with claims based authentication. This article assumes you already created a web application using claims based authentication. If you want to enable forms based authentication in SharePoint 2010, you must enable claims based authentication. Read this post for creating a web application using claims based authentication. http://weblogs.asp.net/sreejukg/archive/2011/06/15/create-a-web-application-in-sharepoint-2010-using-claims-based-authentication.aspx  You make sure, you have selected enable form authentication, and then selected Membership provider and Role manager name. To make sure you are done with the configuration, navigate to central administration website, from central administration, navigate to the Web Applications page, select the web application and click on icon, you will see the authentication providers for the current web application. Go to the section Claims authentication types, and make sure you have enabled forms based authentication. As mentioned in the snapshot, I have named the membership provider as SPFormAuthMembership and role manager as SPFormAuthRoleManager. You can choose your own names as you need. Modify the configuration files(Web.Config) to enable form authentication There are three applications that needs to be configured to support form authentication. The following are those applications. Central Administration If you want to assign permissions to web application using the credentials from form authentication, you need to update Central Administration configuration. If you do not want to access form authentication credentials from Central Administration, just leave this step.  STS service application Security Token service is the service application that issues security token when users are logging in. You need to modify the configuration of STS application to make sure users are able to login. To find the STS application, follow the following steps Go to the IIS Manager Expand the sites Node, you will see SharePoint Web Services Expand SharePoint Web Services, you can see SecurityTokenServiceApplication Right click SecuritytokenServiceApplication and click explore, it will open the corresponding file system. By default, the path for STS is C:\Program Files\Common Files\Microsoft Shared\Web Server Extensions\14\WebServices\SecurityToken You need to modify the configuration file available in the mentioned location. The web application that needs to be enabled with form authentication. You need to modify the configuration of your web application to make sure your web application identifies users from the form authentication.   Based on the above, I am going to modify the web configuration. At end of each step, I have mentioned the expected output. I recommend you to go step by step and after each step, make sure the configuration changes are working as expected. If you do everything all together, and test your application at the end, you may face difficulties in troubleshooting the configuration errors. Modifications for Central Administration Web.Config Open the web.config for the Central administration in a text editor. I always prefer Visual Studio, for editing web.config. In most cases, the path of the web.config for the central administration website is as follows C:\inetpub\wwwroot\wss\VirtualDirectories\<port number> Make sure you keep a backup copy of the web.config, before editing it. Let me summarize what we are going to do with Central Administration web.config. First I am going to add a connection string that points to the form authentication database, that I created as mentioned in previous steps. Then I need to add a membership provider and a role manager with the corresponding connectionstring. Then I need to update the peoplepickerwildcards section to make sure the users are appearing in search results. By default there is no connection string available in the web.config of Central Administration. Add a connection string just after the configsections element. The below is the connection string I have used all over the article. <add name="FormAuthConnString" connectionString="Initial Catalog=yourdatabasename;data source=databaseservername;Integrated Security=SSPI;" /> Once you added the connection string, the web.config look similar to Now add membership provider to the code. In web.config for CA, there will be <membership> tag, search for it. You will find membership and role manager under the <system.web> element. Under the membership providers section add the below code… <add name="SPFormAuthMembership" type="System.Web.Security.SqlMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> After adding memberhip element, see the snapshot of the web.config. Now you need to add role manager element to the web.config. Insider providers element under rolemanager, add the below code. <add name="SPFormAuthRoleManager" type="System.Web.Security.SqlRoleProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> After adding, your role manager will look similar to the following. As a last step, you need to update the people picker wildcard element in web.config, so that the users from your membership provider are available for browsing in Central Administration. Search for PeoplePickerWildcards in the web.config, add the following inside the <PeoplePickerWildcards> tag. <add key="SPFormAuthMembership" value="%" /> After adding this element, your web.config will look like After completing these steps, you can browse the users available in the SQL server database from central administration website. Go to the site collection administrator’s page from central administration. Select the site collection you have created for form authentication. Click on the people picker icon, choose Forms Auth and click on the search icon, you will see the users listed from the SQL server database. Once you complete these steps, make sure the users are available for browsing from central administration website. If you are unable to find the users, there must be some errors in the configuration, check windows event logs to find related errors and fix them. Change the web.config for STS application Open the web.config for STS application in text editor. By default, STS web.config does not have system.Web or connectionstrings section. Just after the System.Webserver element, add the following code. <connectionStrings> <add name="FormAuthConnString" connectionString="Initial Catalog=aspnetdb_claim;data source=sp2010_db;Integrated Security=SSPI;" /> </connectionStrings> <system.web> <roleManager enabled="true" cacheRolesInCookie="false" cookieName=".ASPXROLES" cookieTimeout="30" cookiePath="/" cookieRequireSSL="false" cookieSlidingExpiration="true" cookieProtection="All" createPersistentCookie="false" maxCachedResults="25"> <providers> <add name="SPFormAuthRoleManager" type="System.Web.Security.SqlRoleProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> </providers> </roleManager> <membership userIsOnlineTimeWindow="15" hashAlgorithmType=""> <providers> <add name="SPFormAuthMembership" type="System.Web.Security.SqlMembershipProvider, System.Web, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a" applicationName="FormAuthApplication" connectionStringName="FormAuthConnString" /> </providers> </membership> </system.web> See the snapshot of the web.config after adding the required elements. After adding this, you should be able to login using the credentials from SQL server. Try assigning a user as primary/secondary administrator for your site collection from Central Administration and login to your site using form authentication. If you made everything correct, you should be able to login. This means you have successfully completed configuration of STS Configuration of Web Application for Form Authentication As a last step, you need to modify the web.config of the form authentication web application. Once you have done this, you should be able to grant permissions to users stored in the membership database. Open the Web.config of the web application you created for form authentication. You can find the web.config for the application under the path C:\inetpub\wwwroot\wss\VirtualDirectories\<port number> Basically you need to add connection string, membership provider, role manager and update the people picker wild card configuration. Add the connection string (same as the one you added to the web.config in Central Administration). See the screenshot after the connection string has added. Search for <membership> in the web.config, you will find this inside system.web element. There will be other providers already available there. You add your form authentication membership provider (similar to the one added to Central Administration web.config) to the provider element under membership. Find the snapshot of membership configuration as follows. Search for <roleManager> element in web.config, add the new provider name under providers section of the roleManager element. See the snapshot of web.config after new provider added. Now you need to configure the peoplepickerwildcard configuration in web.config. As I specified earlier, this is to make sure, you can locate the users by entering a part of their username. Add the following line under the <PeoplePickerWildcards> element in web.config. See the screenshot of the peoplePickerWildcards element after the element has been added. Now you have completed all the setup for form authentication. Navigate to the web application. From the site actions -> site settings -> go to peope and groups Click on new -> add users, it will popup the people picker dialog. Click on the icon, select Form Auth, enter a username in the search textbox, and click on search icon. See the screenshot of admin search when I tried searching the users If it displays the user, it means you are done with the configuration. If you add users to the form authentication database, the users will be able to access SharePoint portal as normal.

    Read the article

  • Bash on Snow Leopard doesn't obey terminal colours

    - by karbassi
    With the new version of Snow Leopard, OSX upgraded the bash version to GNU bash, version 3.2.48(1)-release (x86_64-apple-darwin10.0). Now, my .bashrc sets the following settings: # Colors export TERM=xterm-color export GREP_OPTIONS='--color=auto' GREP_COLOR='1;32' export CLICOLOR=1 export LSCOLORS=ExGxFxDxCxHxHxCbCeEbEb # Setup some colors to use later in interactive shell or scripts export COLOR_NC='\e[0m' # No Color export COLOR_WHITE='\e[1;37m' export COLOR_BLACK='\e[0;30m' export COLOR_BLUE='\e[0;34m' export COLOR_LIGHT_BLUE='\e[1;34m' export COLOR_GREEN='\e[0;32m' export COLOR_LIGHT_GREEN='\e[1;32m' export COLOR_CYAN='\e[0;36m' export COLOR_LIGHT_CYAN='\e[1;36m' export COLOR_RED='\e[0;31m' export COLOR_LIGHT_RED='\e[1;31m' export COLOR_PURPLE='\e[0;35m' export COLOR_LIGHT_PURPLE='\e[1;35m' export COLOR_BROWN='\e[0;33m' export COLOR_YELLOW='\e[1;33m' export COLOR_GRAY='\e[1;30m' export COLOR_LIGHT_GRAY='\e[0;37m' The colours are used later on for output. This used to work in previous version of OSX but not my output is as such: Some ideas that have not worked. Switching Terminal.app from 64-bit to 32-bit.

    Read the article

  • Dichroic Glass in Blender

    - by KalAurum
    I am trying to use blender to simulate the Lycurgus Cup. The cup is an example of dichroic (two-color) glass, and appears green when a light source is on the outside of the cup, and appears red when a light source is inside the cup. Here is an image of when light is outside and it appears green: Here is an image of when light is inside and it appears red: I have created a glass cup in blender. I have made the glass a red color, and then used the colorbands under the Object-Material/Shading-Ramps tab to add green specular and diffuse color. However, this makes the glass appear the same mix of red and green whether I put the light source on the inside or outside the cup. An example can be seen here: According to the second post here, someone was able to to fake the effect of a dichroic glass in blender rather easily through the use of a magic procedural texture but they provide no clues on how to do this (in blender). Does anyone know how to achieve this effect in blender?

    Read the article

  • Excel 2007 Conditional Formatting is not properly using custom formula provided

    - by Charles
    In Excel 2007, I want to conditionally color a row if it is odd numbered and then vary the coloring depending on if a specific cell (in column E) in that row contains a number (green) or empty(red). E.g. if E15 has a value of 2 and E13 has no entry, I would expect row 15 to be green and row 13 to be red. My two formulas are: To color red: =IF((MOD(ROW(),2) = 1),NOT(ISNUMBER(INDIRECT("$E$"&ROW()))), FALSE) To color green: =IF((MOD(ROW(),2) = 1),ISNUMBER(INDIRECT("E"&ROW())), FALSE) If I paste these formulas into cells on the worksheet I get the expected values. For row 15 the "red" equation is false and the "green" equation is true. For Row 13 the "red" equation is true and the "green equation is false. However if I use these formulas in the conditional formating use formula feature, all of my rows are red, any thoughts?

    Read the article

  • How to retain background colors when pasting between documents in Excel

    - by Iain Fraser
    I have a script that programatically generates excel spreadsheets - cleaning up ugly reports that are given to us from another organisation. For interests sake; I'm using PHPExcel to generate the "clean" reports. We get these reports every week for an event that happens every couple of months. The reports contain a list of attendees along with a group id that allows us to know that some attendees belong together. To help the event organisers out, I've taken the event ID and generated a unqiue color code (based on the hash of the event ID - truncated to 6 characters). This unique colour code is set as the background color of a cell in each row. This helps organisers quickly visually identify group members. Trouble is, when the organisers copy the rows from the weeks report into the master report (which contains all attendees, not just the ones that signed up this week) - all the colour-codes snap to the master template's color pallette. Thank you very much for your time All the best Iain

    Read the article

  • Limited RGB range due to HDMI cable?

    - by Cedric Reichenbach
    I have a NVidia GeForce GTX 660, connected to a Samsung SyncMaster S24B350 through a HDMI cable. On my computer, I'm running both, Windows 8 and Linux Mint. I think that something might prevent my system from using the whole RGB spectrum, since bright colors seem to vanish into white under standard settings. However, under Linux I could switch to a limited color range mode (16-235) and suddenly, the image looked much better. Is it possible that the HDMI cable limits color range (since it was originally inteded for TVs)? Is there a way of switching to limited color range mode in Windows 8 as well?

    Read the article

  • How can I get black window borders in Windows 8?

    - by sean e
    In Windows 8, when I go into Control Panel\Appearance and Personalization\Personalization\Window Color and Appearance the amount of control over window colors is greatly reduced as compared to Windows 7. The color controls do not allow you to make Window borders display in black. Is there some other way to set the window border color in Windows 8? Edit 1: Clearly the standard way does not work in Windows 8. The question is, is there another way? Perhaps through the registry for example? Edit 2: I tried copying the values in HKEY_CURRENT_USER\Software\Microsoft\Windows\DWM from my Win7 system to the Win8 system without success (killing the 2 DWM processes after each change - they are automatically restarted and do use the new values).

    Read the article

  • Changing ati graphics setting into a batch file

    - by FrozenKing
    I want to change my saturation level to zero and again to default but I can do it manually by going to ati catalyst center. Since, I want to do it regularly I need some batch file code or program to alter this settings in a click or using shortcut keys. The reason I am doing this because I want to change my screen to black and white from color since b/w will make my eyes less tired then a colored display. I came to know about this saturation from my previously asked question : Changing display color from B/W to color (vice-versa)using a program.

    Read the article

  • No colors when running native windows shell application from mintty

    - by Pete
    Hi. I have installed cygwin (i'm not very experienced with it), and try to run a native windows shell application from it, (msbuild.exe which is the build tool for the .NET framework, to be exact). When I run the application from the normal cygwin bash shell, the output of the application appear as it should with the text colors that I would normally see in the windows command line. But when I execute the program from a mintty terminal, there is no coloring of the output, all text is in the default foreground color. I'm puzzled, because I would have expected the color coding to be the standard ANSI color code escape characters... Can this be fixed?

    Read the article

  • WPF Templates error - "Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw

    - by jasonk
    I've just started experimenting with WPF templates vs. styles and I'm not sure what I'm doing wrong. The goal below is to alternate the colors of the options in the menu. The code works fine with just the , but when I copy and paste/rename it for the second segment of "MenuChoiceOdd" I get the following error: Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw an exception. Sample of the code: <Window x:Class="WpfApplication1.Template_Testing" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="Template_Testing" Height="300" Width="300"> <Grid> <Grid.Resources> <ControlTemplate x:Key="MenuChoiceEven"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="#FFC2CCDB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> <ControlTemplate x:Key="MenuChoiceOdd"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="##FFCBCBCB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> </Grid.Resources> <Border BorderBrush="SlateGray" BorderThickness="2" Margin="10" CornerRadius="10" Background="LightSteelBlue" Width="200"> <StackPanel Margin="4"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="2,2,2,0" Name="MenuHeaderTextBlock" Text="TextBlock" Width="Auto" FontSize="16" Foreground="PaleGoldenrod" TextAlignment="Left" Padding="10" FontWeight="Bold"><TextBlock.Background><LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"><GradientStop Color="LightSlateGray" Offset="0" /><GradientStop Color="DarkSlateGray" Offset="1" /></LinearGradientBrush></TextBlock.Background></TextBlock> <StackPanel Height="Auto" HorizontalAlignment="Stretch" Margin="2,0,2,0" Name="MenuChoicesStackPanel" VerticalAlignment="Top" Width="Auto"> <Button Template="{StaticResource MenuChoiceEven}" Content="Test Even menu element" /> <Button Template="{StaticResource MenuChoiceOdd}" Content="Test odd menu element" /> </StackPanel> </StackPanel> </Border> </Grid> </Window> What am I doing wrong?

    Read the article

  • Using AChartEngine library for graphs, not able to get value for diffrent x-axis value

    - by kundan Chaudhary
    public static ArrayList<double[]> Value = new ArrayList<double[]>(); private double[] x = new double[10]; private double[] y = new double[10]; int counter = -1; add.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { counter++; x[counter] = Double.parseDouble(income_1.getText().toString()); y[counter] = Double.parseDouble(income_2.getText().toString()); income_1.setText(""); income_2.setText(""); } }); publish.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { if (Value != null) { Value.add(x); Value.add(y); Intent intent = salesStackedBarChart.execute(BarChart.this, Value, counter); startActivity(intent); } } }); //and in SalesStackedBarChart.java class public Intent execute(Context context, ArrayList<double[]> values ,int counter) { int count = counter + 1; double fcount = counter + 1.5; String[] titles = new String[] { "Android", "iPhone" }; int[] colors = new int[] { Color.GREEN, Color.CYAN }; XYMultipleSeriesRenderer renderer = buildBarRenderer(colors); setChartSettings(renderer, "Yearly revenue in the last "+count+" years", "Years", "revenue in $", 0.5, fcount, 0, 24000, Color.GRAY, Color.LTGRAY); renderer.setXLabels(count); renderer.setYLabels(10); renderer.setDisplayChartValues(true); renderer.setXLabelsAlign(Align.LEFT); renderer.setYLabelsAlign(Align.LEFT); renderer.setZoomRate(1.1f); renderer.setBarSpacing(0.5); return ChartFactory.getBarChartIntent(context, buildBarDataset(titles, values), renderer, Type.DEFAULT); } // in AbstractDemoChart.java class protected XYMultipleSeriesDataset buildBarDataset(String[] titles, List<double[]> values) { XYMultipleSeriesDataset dataset = new XYMultipleSeriesDataset(); int length = titles.length; for (int i = 0; i < length; i++) { CategorySeries series = new CategorySeries(titles[i]); double[] v = values.get(i); int seriesLength = v.length; for (int k = 0; k < seriesLength; k++) { series.add(v[k]); } dataset.addSeries(series.toXYSeries()); } return dataset; } Run this project i get graph with x- axis value: 1,2,3,4,5.... But I want to print value: 2005,2006,2007,2008..... I changed in some code like: setChartSettings(renderer, "Yearly revenue in the last "+count+" years", "Years", "revenue in $", 2005, 2010, 0, 24000, Color.GRAY, Color.LTGRAY); and run project i get value of x-axis like: 2005,2006,2007.... but not get graph bar value. Values of all x-axis are null. How can I make this work?

    Read the article

  • JPanel paint method is not being called, why?

    - by swift
    When i run this code the paintComponent method is not being called It may be very simple error but i dont know why this, plz. package test; import java.awt.Color; import java.awt.Graphics; import java.awt.Graphics2D; import java.awt.Point; import java.awt.image.BufferedImage; import javax.swing.BorderFactory; import javax.swing.JPanel; class Userboard extends JPanel { static BufferedImage image; String shape; Point start; Point end; Point mp; String selected; int ex,ey;//eraser int w,h; public Userboard() { setOpaque(false); System.out.println("paper"); setBackground(Color.white); setBorder(BorderFactory.createLineBorder(Color.black)); } public void paintComponent(Graphics g) { System.out.println("userboard-paint"); try { //g.drawImage(image, 0, 0, this); Graphics2D g2 = (Graphics2D)g; g2.setPaint(Color.black); if(start!=null && end!=null) { if(selected==("elipse")) { System.out.println("userboard-elipse"); g2.drawOval(start.x, start.y,(end.x-start.x),(end.y-start.y)); System.out.println("userboard-elipse drawn"); } else if(selected==("rect")) g2.drawRect(start.x, start.y, (end.x-start.x),(end.y-start.y)); else if(selected==("line")) g2.drawLine(start.x,start.y,end.x,end.y); } } catch(Exception e) {} } //Function to draw the shape on image public void draw() { System.out.println("Userboard-draw"); System.out.println(selected); System.out.println(start); System.out.println(end); Graphics2D g2 = image.createGraphics(); g2.setPaint(Color.black); if(start!=null && end!=null) { if(selected=="line") g2.drawLine(start.x, start.y, end.x, end.y); else if(selected=="elipse") { System.out.println("userboard-elipse"); g2.drawOval(start.x, start.y, (end.x-start.x),(end.y-start.y)); System.out.println("userboard-elipse drawn"); } else if(selected=="rect") g2.drawRect(start.x, start.y, (end.x-start.x),(end.y-start.y)); } start=null; repaint(); g2.dispose(); } //To add the point to the board which is broadcasted by the server public void addPoint(Point ps,String varname,String shape,String event) { try { if(end==null) end = new Point(); if(start==null) start = new Point(); if(shape.equals("elipse")) this.selected="elipse"; else if(shape.equals("line")) this.selected="line"; else if(shape.equals("rect")) this.selected="rect"; else if(shape.equals("erase")) erase(); if(end!=null && start!=null) { if(varname.equals("end")) end=ps; else if(varname.equals("mp")) mp=ps; else if(varname.equals("start")) start=ps; if(event.equals("drag")) repaint(); else if(event.equals("release")) draw(); } repaint(); } catch(Exception e) { e.printStackTrace(); } } //Function which provides the erase functionality public void erase() { Graphics2D pic=(Graphics2D) image.getGraphics(); pic.setPaint(Color.white); if(start!=null) pic.fillRect(start.x, start.y, 10, 10); } //To set the size of the image public void setWidth(int x,int y) { System.out.println("("+x+","+y+")"); w=x; h=y; image = new BufferedImage(w, h, BufferedImage.TYPE_INT_ARGB); } //Function to add buttons into the panel, calling this function returns a panel }

    Read the article

  • Feedback on iterating over type-safe enums

    - by Sumant
    In response to the earlier SO question "Enumerate over an enum in C++", I came up with the following reusable solution that uses type-safe enum idiom. I'm just curious to see the community feedback on my solution. This solution makes use of a static array, which is populated using type-safe enum objects before first use. Iteration over enums is then simply reduced to iteration over the array. I'm aware of the fact that this solution won't work if the enumerators are not strictly increasing. template<typename def, typename inner = typename def::type> class safe_enum : public def { typedef typename def::type type; inner val; static safe_enum array[def::end - def::begin]; static bool init; static void initialize() { if(!init) // use double checked locking in case of multi-threading. { unsigned int size = def::end - def::begin; for(unsigned int i = 0, j = def::begin; i < size; ++i, ++j) array[i] = static_cast<typename def::type>(j); init = true; } } public: safe_enum(type v = def::begin) : val(v) {} inner underlying() const { return val; } static safe_enum * begin() { initialize(); return array; } static safe_enum * end() { initialize(); return array + (def::end - def::begin); } bool operator == (const safe_enum & s) const { return this->val == s.val; } bool operator != (const safe_enum & s) const { return this->val != s.val; } bool operator < (const safe_enum & s) const { return this->val < s.val; } bool operator <= (const safe_enum & s) const { return this->val <= s.val; } bool operator > (const safe_enum & s) const { return this->val > s.val; } bool operator >= (const safe_enum & s) const { return this->val >= s.val; } }; template <typename def, typename inner> safe_enum<def, inner> safe_enum<def, inner>::array[def::end - def::begin]; template <typename def, typename inner> bool safe_enum<def, inner>::init = false; struct color_def { enum type { begin, red = begin, green, blue, end }; }; typedef safe_enum<color_def> color; template <class Enum> void f(Enum e) { std::cout << static_cast<unsigned>(e.underlying()) << std::endl; } int main() { std::for_each(color::begin(), color::end(), &f<color>); color c = color::red; }

    Read the article

  • Increase RGB components every Hour (r), Minute (g), Second (b) for digital clock

    - by TJ Fertterer
    So I am taking my first javascript class (total noob) and one of the assignments is to modify a digital clock by assigning the color red to hours, green minutes, blue to seconds, then increase the respective color component when it changes. I have successfully assigned a decimal color value (ex. "#850000" to each element (hours, minutes, seconds), but my brain is fried trying to figure out how to increase the brightness when hours, minutes, seconds change, i.e. red goes up to "#870000" changing from 1:00:00 pm to 2:00:00 pm. I've searched everywhere with no help on how to successfully do this. Here is what I have so far and any help on this would be greatly appreciated. TJ <script type="text/javascript"> <!-- function updateClock() { var currentTime = new Date(); var currentHours = currentTime.getHours(); var currentMinutes = currentTime.getMinutes(); var currentSeconds = currentTime.getSeconds(); // Pad the minutes with leading zeros, if required currentMinutes = ( currentMinutes < 10 ? "0" : "" ) + currentMinutes; // Pad the seconds with leading zeros, if required currentSeconds = ( currentSeconds < 10 ? "0" : "" ) + currentSeconds; // Choose either "AM" or "PM" as appropriate var timeOfDay = ( currentHours < 12 ) ? "AM" : "PM"; // Convert the hours component to 12-hour format currentHours = ( currentHours > 12 ) ? currentHours - 12 : currentHours; // Convert an hours component if "0" to "12" currentHours = ( currentHours == 0 ) ? 12 : currentHours; // Get hold of the html elements by their ids var hoursElement = document.getElementById("hours"); document.getElementById("hours").style.color = "#850000"; var minutesElement = document.getElementById("minutes"); document.getElementById("minutes").style.color = "#008500"; var secondsElement = document.getElementById("seconds"); document.getElementById("seconds").style.color = "#000085"; var am_pmElement = document.getElementById("am_pm"); // Put the clock sections text into the elements' innerHTML hoursElement.innerHTML = currentHours; minutesElement.innerHTML = currentMinutes; secondsElement.innerHTML = currentSeconds; am_pmElement.innerHTML = timeOfDay; } // --> </script> </head> <body onload="updateClock(); setInterval( 'updateClock()', 1000 )"> <h1 align="center">The JavaScript digital clock</h1> <h2 align="center">Thomas Fertterer - Lab 2</h2> <div id='clock' style="text-align: center"> <span id="hours"></span>: <span id='minutes'></span>: <span id='seconds'></span> <span id='am_pm'></span> </div> </body> </html>

    Read the article

  • Change the content of a <style> element through JavaScript

    - by paercebal
    The Problem I have the following code: <html> <head> <style id="ID_Style"> .myStyle { color : #FF0000 ; } </style> </head> <body> <p class="myStyle"> Hello World ! </p> </body> </html> And I want to modify the contents of <style> through JavaScript. The Expected Solution The first solution was to use the innerHTML property of the style element (retrieved through its id), but while it works on Firefox, it fails on Internet Explorer 7. So, I used pure DOM methods, that is, creating an element called style, a text node with the desired content, and append the text node as a child of the style node, etc. It fails, too. According to MSDN, the <style> element has an innerHTML property, and according to W3C, the <style> element is a HTMLStyleElement, which derives from HTMLElement, deriving from Element deriving from Node, which has the appendChild method. It seems to behave as if the content of a <style> element was readonly on Internet Explorer. The Question So the question is: Is there a way to modify the content of a <style> element on Internet Explorer? While the current problem is with IE7, a cross-browser solution would be cool, if possible. Appendix Sources: Style Element (MSDN): http://msdn.microsoft.com/en-us/library/ms535898.aspx HTMLStyleElement (W3C): http://www.w3.org/TR/2003/REC-DOM-Level-2-HTML-20030109/html.html#ID-16428977 Complete Test Code You can use this test code if you want to reproduce your problem: <html> <head> <style id="ID_Style"> .myStyle { color : #FF0000 ; } </style> <script> function replaceStyleViaDOM(p_strContent) { var oOld = document.getElementById("ID_Style") ; var oParent = oOld.parentNode ; oParent.removeChild(oOld) ; var oNew = document.createElement("style") ; oParent.appendChild(oNew) ; oNew.setAttribute("id", "ID_Style") ; var oText = document.createTextNode(p_strContent) ; oNew.appendChild(oText) ; } function replaceStyleViaInnerHTML(p_strContent) { document.getElementById("ID_Style").innerHTML = p_strContent ; } </script> <script> function setRedViaDOM() { replaceStyleViaDOM("\n.myStyle { color : #FF0000 ; }\n") } function setRedViaInnerHTML() { replaceStyleViaInnerHTML("\n.myStyle { color : #FF0000 ; }\n") } function setBlueViaDOM() { replaceStyleViaDOM("\n.myStyle { color : #0000FF ; }\n") } function setBlueViaInnerHTML() { replaceStyleViaInnerHTML("\n.myStyle { color : #0000FF ; }\n") } function alertStyle() { alert("*******************\n" + document.getElementById("ID_Style").innerHTML + "\n*******************") ; } </script> </head> <body> <div> <button type="button" onclick="alertStyle()">alert Style</button> <br /> <button type="button" onclick="setRedViaDOM()">set Red via DOM</button> <button type="button" onclick="setRedViaDOM()">set Red via InnerHTML</button> <br /> <button type="button" onclick="setBlueViaDOM()">set Blue via DOM</button> <button type="button" onclick="setBlueViaInnerHTML()">set Blue via InnerHTML</button> </div> <p class="myStyle"> Hello World ! </p> </body> </html> Thanks !

    Read the article

  • Styling an Input Field

    - by John
    Hello When I try to alter the CSS for the input field named "title" below, which is classed by "submissionfield", the position changes, but the height, length, and font of the field do not change. How could I make the height of the input field "title" 22 px, the length 550 px, and the font Times New Roman? The CSS below does not do it. Thanks in advance, John echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; The CSS: .submissiontitle { position:absolute; width:100px; left:30px; top:200px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .submissionfield { position:absolute; width:550px; left:50px; top:230px; text-align: left; margin-bottom:3px; padding:0px; font-family: "Times New Roman", Times, serif; font-size: 22px; color:#000000; } .urltitle { position:absolute; width:250px; left:30px; top:300px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .urlfield { position:absolute; width:550px; left:30px; top:330px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submissionbutton { position:absolute; width:250px; left:30px; top:380px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submittitle { position:absolute; width:250px; left:30px; top:150px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; }

    Read the article

  • convert pixels into image

    - by Zeta Op
    what i am trying to do is to convert a pixel from a video cam, into an image to expalin it better imagine a 3d model so.. the pixels would be each polying, and i want to do is to conver each polyigon into an image. what i have so far is this ** import processing.video.*; PImage hoja; Capture cam; boolean uno, dos, tres, cuatro; import ddf.minim.*; Minim minim; AudioPlayer audio; float set; void setup() { //audio minim = new Minim(this); // audio = minim.loadFile("audio"); // audio.loop(); // uno=false; dos=false; tres=false; cuatro=true; size(640, 480); hoja=loadImage("hoja.gif"); cam = new Capture(this, width, height); cam.start(); } void draw() { if (cam.available() == true) { cam.read(); if (uno==true) { filtroUno(); image(cam, 0, 0, 640, 480); } if (dos==true) { filtroDos(); } if(tres==true){ filtroTres(); } if(cuatro==true){ filtroCuatro(); image(cam, set, 0,640,480); } } // The following does the same, and is faster when just drawing the image // without any additional resizing, transformations, or tint. //set(0, 0, cam); } void filtroUno() { cam.loadPixels(); hoja.loadPixels(); for (int i=0;i<cam.pixels.length;i++) { if (brightness(cam.pixels[i])>110) { cam.pixels[i]=color(0, 255, 255); } else { cam.pixels[i]=color(255, 0, 0); } } for (int i=0;i<cam.width;i+=10) { for (int j=0;j<cam.height;j+=10) { int loc=i+(j*cam.width); if (cam.pixels[loc]==color(255, 0, 0)) { for (int x=i;x<i+10;x++) { for (int y=j;y<j+10;y++) { // println("bla"); int locDos=i+(j*cam.width); cam.pixels[locDos]=hoja.get(x, y); } } } } } cam.updatePixels(); } ** the broblem is that each pixel is creating me a matrix, so.. is not recreating what id that to do. i had the method filtroUno but it wasn't showing ok.. and was the result void filtroUno() { cam.loadPixels(); hoja.loadPixels(); for (int i=0;i<cam.pixels.length;i++) { if (brightness(cam.pixels[i])>110) { cam.pixels[i]=color(0, 255, 255); } else { cam.pixels[i]=color(255, 0, 0); } } for (int i=0;i<cam.width;i+=10) { for (int j=0;j<cam.height;j+=10) { int loc=i+j*hoja.width*10; if (cam.pixels[loc]==color(255, 0, 0)) { for (int x=i;x<i+10;x++) { for (int y=j;y<j+10;y++) { // println("bla"); int locDos=x+y*hoja.height*10; cam.pixels[locDos]=hoja.get(x, y); } } } } } cam.updatePixels(); } i hope you can help me thanks note: each red pixel should be the gif image the imge size is 10x10

    Read the article

  • WCF service is not getting called

    - by Cheranga
    I have a web solution and I have a WCF service project inside it. We need to support "cookieless". so in the web.config, it's set as <sessionState mode="SQLServer" sqlConnectionString="Data Source=ds;Initial Catalog=db;User Id=uid;Password=pwd" allowCustomSqlDatabase="true" cookieless="true" timeout="720" regenerateExpiredSessionId="false"/> The WCF service will be supporting sessions, so we have also set "aspNetCompatibilityEnabled" to true in web.config. <serviceHostingEnvironment aspNetCompatibilityEnabled="true" multipleSiteBindingsEnabled="true"/> The service and interfaces are as follows, [ServiceContract(SessionMode=SessionMode.Allowed)] public interface ICDOCService { } [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class CDOCService : ICDOCService { } The problem we are facing is we cannot access the service from any client application. (web app, WCF test client) The following error is showing, when we access it via WCF Test client, Failed to invoke the service. Possible causes: The service is offline or inaccessible; the client-side configuration does not match the proxy; the existing proxy is invalid. Refer to the stack trace for more detail. You can try to recover by starting a new proxy, restoring to default configuration, or refreshing the service. The content type text/html; charset=UTF-8 of the response message does not match the content type of the binding (multipart/related; type="application/xop+xml"). If using a custom encoder, be sure that the IsContentTypeSupported method is implemented properly. The first 1024 bytes of the response were: <HTML> <HEAD> <link rel="alternate" type="text/xml" href="http://localhost:53721/Services/CDOCService.svc?disco"/> <STYLE type="text/css">#content{ FONT-SIZE: 0.7em; PADDING-BOTTOM: 2em; MARGIN-LEFT: 30px}BODY{MARGIN-TOP: 0px; MARGIN-LEFT: 0px; COLOR: #000000; FONT-FAMILY: Verdana; BACKGROUND-COLOR: white}P{MARGIN-TOP: 0px; MARGIN-BOTTOM: 12px; COLOR: #000000; FONT-FAMILY: Verdana}PRE{BORDER-RIGHT: #f0f0e0 1px solid; PADDING-RIGHT: 5px; BORDER-TOP: #f0f0e0 1px solid; MARGIN-TOP: -5px; PADDING-LEFT: 5px; FONT-SIZE: 1.2em; PADDING-BOTTOM: 5px; BORDER-LEFT: #f0f0e0 1px solid; PADDING-TOP: 5px; BORDER-BOTTOM: #f0f0e0 1px solid; FONT-FAMILY: Courier New; BACKGROUND-COLOR: #e5e5cc}.heading1{MARGIN-TOP: 0px; PADDING-LEFT: 15px; FONT-WEIGHT: normal; FONT-SIZE: 26px; MARGIN-BOTTOM: 0px; PADDING-BOTTOM: 3px; MARGIN-LEFT: -30px; WIDTH: 100%; COLOR: #ffffff; PADDING-TOP: 10px; FONT-FAMILY: Tahoma; BACKGROUND-COLOR: #003366}.intro{MARGIN-LEFT: -15px} </STYLE> <TITLE>CDOCService Service</TITLE></HEAD><BODY><DIV id="content"><P '. Server stack trace: at System.ServiceModel.Channels.HttpChannelUtilities.ValidateRequestReplyResponse(HttpWebRequest request, HttpWebResponse response, HttpChannelFactory factory, WebException responseException, ChannelBinding channelBinding) at System.ServiceModel.Channels.HttpChannelFactory.HttpRequestChannel.HttpChannelRequest.WaitForReply(TimeSpan timeout) at System.ServiceModel.Channels.RequestChannel.Request(Message message, TimeSpan timeout) at System.ServiceModel.Dispatcher.RequestChannelBinder.Request(Message message, TimeSpan timeout) at System.ServiceModel.Channels.ServiceChannel.Call(String action, Boolean oneway, ProxyOperationRuntime operation, Object[] ins, Object[] outs, TimeSpan timeout) at System.ServiceModel.Channels.ServiceChannel.Call(String action, Boolean oneway, ProxyOperationRuntime operation, Object[] ins, Object[] outs) at System.ServiceModel.Channels.ServiceChannelProxy.InvokeService(IMethodCallMessage methodCall, ProxyOperationRuntime operation) at System.ServiceModel.Channels.ServiceChannelProxy.Invoke(IMessage message) Exception rethrown at [0]: at System.Runtime.Remoting.Proxies.RealProxy.HandleReturnMessage(IMessage reqMsg, IMessage retMsg) at System.Runtime.Remoting.Proxies.RealProxy.PrivateInvoke(MessageData& msgData, Int32 type) at ICDOCService.GetCDOCCount(String institutionID, String mrnID, String userID, String callingSystemID, String securityToken) at CDOCServiceClient.GetCDOCCount(String institutionID, String mrnID, String userID, String callingSystemID, String securityToken)

    Read the article

  • multi divs centered

    - by user1319385
    I have 2 divs with 3 divs inside them, all 2 wrapped around one big div. I try and center it and its not working. Here is my code: <div stye="margin-left:auto; margin-right:auto; width: 1210px;"> <div id="left" style=" float:left; width: 606px; height: 506px;"> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; height:502px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A picture of a cool guy wearing our shirt will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; border-left:0px; height:200px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A product image will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0;border-top:0px; border-left:0px; height:300px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A tight product image will go in here.</h1></div> </div> <div id="left" style="float:left; width: 604px; height: 506px;"> <div style="top:0px; float:right; width:300px; border: 2px solid #FF0; border-left:0px; height:502px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A picture of a cool guy wearing our shirt will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0; border-left:0px; height:200px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A product image will go in here.</h1></div> <div style="top:0px; float:left; width:300px; border: 2px solid #FF0;border-top:0px; border-left:0px; height:300px; text-align:center; font-family: Myriad Pro, Arial, sans-serif; color:#FFF;"><h1>A tight product image will go in here.</h1></div> </div> </div>

    Read the article

  • DisplayObject not being displayed in AS3

    - by MarkSteve
    I have this class: public class IskwabolText extends Sprite { private var _tf:TextField; private var _tfmt:TextFormat; private var _size:Number; private var _text:String; public function IskwabolText(params:Object) { var defaultParams:Object = { color: 0x000000, background: false, backgroundColor: 0xFFFFFF, width: 0, height: 0, multiline: false, wordWrap: false }; // textfield _tf = new TextField(); _tf.antiAliasType = 'advanced'; _tf.embedFonts = true; _tf.type = 'dynamic'; _tf.selectable = false; // textformat _tfmt = new TextFormat(); set(defaultParams); set(params); } public function get(param:String):Object { switch (param) { case 'size': return _tfmt.size; case 'text': return _tf.text; case 'font': return _tfmt.font; case 'color': return _tfmt.color; case 'background': return _tf.background; case 'backgroundColor': return _tf.backgroundColor; case 'width': return _tf.width; case 'height': return _tf.height; case 'multiline': return _tf.multiline; case 'wordWrap': return _tf.multiline; default: return this[param]; } return null; } public function set(params:Object):Object { for (var i:String in params) { setParam(i, params[i]); } redraw(); return this; } private function setParam(param:String, value:Object):Object { switch (param) { case 'size': _tfmt.size = new String(value); break; case 'text': _tf.text = new String(value); break; case 'font': _tfmt.font = new String(value); break; case 'color': _tfmt.color = new uint(value); break; case 'background': _tf.background = new Boolean(value); break; case 'backgroundColor': _tf.backgroundColor = new uint(value); break; case 'width': _tf.width = new Number(value); break; case 'height': _tf.height = new Number(value); break; case 'multiline': _tf.multiline = new Boolean(value); break; case 'wordWrap': _tf.multiline = new Boolean(value); break; default: this[param] = value; break; } return this; } private function redraw():void { _tf.setTextFormat(_tfmt); if (contains(_tf)) removeChild(_tf); if (_tf.width == 0) _tf.width= _tf.textWidth+5; _tf.height = _tf.textHeight; addChild(_tf); } } But when I do this: public class Main extends Sprite { public function Main() { addChild(new IskwabolText({ size: 100, text: 'iskwabol', font: 'Default', // this is properly embedded color: 0x000000, x: stage.stageWidth / 2 - this.width / 2, y: 140 })); } } The child IskwabolText doesn't get displayed. What happening?

    Read the article

  • May 2011 Release of the Ajax Control Toolkit

    - by Stephen Walther
    I’m happy to announce that the Superexpert team has published the May 2011 release of the Ajax Control Toolkit at CodePlex. You can download the new release at the following URL: http://ajaxcontroltoolkit.codeplex.com/releases/view/65800 This release focused on improving the ModalPopup and AsyncFileUpload controls. Our team closed a total of 34 bugs related to the ModalPopup and AsyncFileUpload controls. Enhanced ModalPopup Control You can take advantage of the Ajax Control Toolkit ModalPopup control to easily create popup dialogs in your ASP.NET Web Forms applications. When the dialog appears, you cannot interact with any page content which appears behind the modal dialog. For example, the following page contains a standard ASP.NET Button and Panel. When you click the Button, the Panel appears as a popup dialog: <%@ Page Language="vb" AutoEventWireup="false" CodeBehind="Simple.aspx.vb" Inherits="ACTSamples.Simple" %> <%@ Register TagPrefix="act" Namespace="AjaxControlToolkit" Assembly="AjaxControlToolkit" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title>Simple Modal Popup Sample</title> <style type="text/css"> html { background-color: blue; } #dialog { border: 2px solid black; width: 500px; background-color: White; } #dialogContents { padding: 10px; } .modalBackground { background-color:Gray; filter:alpha(opacity=70); opacity:0.7; } </style> </head> <body> <form id="form1" runat="server"> <div> <act:ToolkitScriptManager ID="tsm" runat="server" /> <asp:Panel ID="dialog" runat="server"> <div id="dialogContents"> Here are the contents of the dialog. <br /> <asp:Button ID="btnOK" Text="OK" runat="server" /> </div> </asp:Panel> <asp:Button ID="btnShow" Text="Open Dialog" runat="server" /> <act:ModalPopupExtender TargetControlID="btnShow" PopupControlID="dialog" OkControlID="btnOK" DropShadow="true" BackgroundCssClass="modalBackground" runat="server" /> </div> </form> </body> </html>     Notice that the page includes two controls from the Ajax Control Toolkit: the ToolkitScriptManager and the ModalPopupExtender control. Any page which uses any of the controls from the Ajax Control Toolkit must include a ToolkitScriptManager. The ModalPopupExtender is used to create the popup. The following properties are set: · TargetControlID – This is the ID of the Button or LinkButton control which causes the modal popup to be displayed. · PopupControlID – This is the ID of the Panel control which contains the content displayed in the modal popup. · OKControlID – This is the ID of a Button or LinkButton which causes the modal popup to close. · DropShadow – Displays a drop shadow behind the modal popup. · BackgroundCSSClass – The name of a Cascading Style Sheet class which is used to gray out the background of the page when the modal popup is displayed. The ModalPopup is completely cross-browser compatible. For example, the following screenshots show the same page displayed in Firefox 4, Internet Explorer 9, and Chrome 11: The ModalPopup control has lots of nice properties. For example, you can make the ModalPopup draggable. You also can programmatically hide and show a modal popup from either server-side or client-side code. To learn more about the properties of the ModalPopup control, see the following website: http://www.asp.net/ajax/ajaxcontroltoolkit/Samples/ModalPopup/ModalPopup.aspx Animated ModalPopup Control In the May 2011 release of the Ajax Control Toolkit, we enhanced the Modal Popup control so that it supports animations. We made this modification in response to a feature request posted at CodePlex which got 65 votes (plenty of people wanted this feature): http://ajaxcontroltoolkit.codeplex.com/workitem/6944 I want to thank Dani Kenan for posting a patch to this issue which we used as the basis for adding animation support for the modal popup. Thanks Dani! The enhanced ModalPopup in the May 2011 release of the Ajax Control Toolkit supports the following animations: OnShowing – Called before the modal popup is shown. OnShown – Called after the modal popup is shown. OnHiding – Called before the modal popup is hidden. OnHidden – Called after the modal popup is hidden. You can use these animations, for example, to fade-in a modal popup when it is displayed and fade-out the popup when it is hidden. Here’s the code: <act:ModalPopupExtender ID="ModalPopupExtender1" TargetControlID="btnShow" PopupControlID="dialog" OkControlID="btnOK" DropShadow="true" BackgroundCssClass="modalBackground" runat="server"> <Animations> <OnShown> <Fadein /> </OnShown> <OnHiding> <Fadeout /> </OnHiding> </Animations> </act:ModalPopupExtender>     So that you can experience the full joy of this animated modal popup, I recorded the following video: Of course, you can use any of the animations supported by the Ajax Control Toolkit with the modal popup. The animation reference is located here: http://www.asp.net/ajax/ajaxcontroltoolkit/Samples/Walkthrough/AnimationReference.aspx Fixes to the AsyncFileUpload In the May 2011 release, we also focused our energies on performing bug fixes for the AsyncFileUpload control. We fixed several major issues with the AsyncFileUpload including: It did not work in master pages It did not work when ClientIDMode=”Static” It did not work with Firefox 4 It did not work when multiple AsyncFileUploads were included in the same page It generated markup which was not HTML5 compatible The AsyncFileUpload control is a super useful control. It enables you to upload files in a form without performing a postback. Here’s some sample code which demonstrates how you can use the AsyncFileUpload: <%@ Page Language="vb" AutoEventWireup="false" CodeBehind="Simple.aspx.vb" Inherits="ACTSamples.Simple1" %> <%@ Register TagPrefix="act" Namespace="AjaxControlToolkit" Assembly="AjaxControlToolkit" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head id="Head1" runat="server"> <title>Simple AsyncFileUpload</title> </head> <body> <form id="form1" runat="server"> <div> <act:ToolkitScriptManager ID="tsm" runat="server" /> User Name: <br /> <asp:TextBox ID="txtUserName" runat="server" /> <asp:RequiredFieldValidator EnableClientScript="false" ErrorMessage="Required" ControlToValidate="txtUserName" runat="server" /> <br /><br /> Avatar: <act:AsyncFileUpload ID="async1" ThrobberID="throbber" UploadingBackColor="yellow" ErrorBackColor="red" CompleteBackColor="green" UploaderStyle="Modern" PersistFile="true" runat="server" /> <asp:Image ID="throbber" ImageUrl="uploading.gif" style="display:none" runat="server" /> <br /><br /> <asp:Button ID="btnSubmit" Text="Submit" runat="server" /> </div> </form> </body> </html> And here’s the code-behind for the page above: Public Class Simple1 Inherits System.Web.UI.Page Private Sub btnSubmit_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles btnSubmit.Click If Page.IsValid Then ' Get Form Fields Dim userName As String Dim file As Byte() userName = txtUserName.Text If async1.HasFile Then file = async1.FileBytes End If ' Save userName, file to database ' Redirect to success page Response.Redirect("SimpleDone.aspx") End If End Sub End Class   The form above contains an AsyncFileUpload which has values for the following properties: ThrobberID – The ID of an element in the page to display while a file is being uploaded. UploadingBackColor – The color to display in the upload field while a file is being uploaded. ErrorBackColor – The color to display in the upload field when there is an error uploading a file. CompleteBackColor – The color to display in the upload field when the upload is complete. UploaderStyle – The user interface style: Traditional or Modern. PersistFile – When true, the uploaded file is persisted in Session state. The last property PersistFile, causes the uploaded file to be stored in Session state. That way, if completing a form requires multiple postbacks, then the user needs to upload the file only once. For example, if there is a server validation error, then the user is not required to re-upload the file after fixing the validation issue. In the sample code above, this condition is simulated by disabling client-side validation for the RequiredFieldValidator control. The RequiredFieldValidator EnableClientScript property has the value false. The following video demonstrates how the AsyncFileUpload control works: You can learn more about the properties and methods of the AsyncFileUpload control by visiting the following page: http://www.asp.net/ajax/ajaxcontroltoolkit/Samples/AsyncFileUpload/AsyncFileUpload.aspx Conclusion In the May 2011 release of the Ajax Control Toolkit, we addressed over 30 bugs related to the ModalPopup and AsyncFileUpload controls. Furthermore, by building on code submitted by the community, we enhanced the ModalPopup control so that it supports animation (Thanks Dani). In our next sprint for the June release of the Ajax Control Toolkit, we plan to focus on the HTML Editor control. Subscribe to this blog to keep updated.

    Read the article

  • Create nice animation on your ASP.NET Menu control using jQuery

    - by hajan
    In this blog post, I will show how you can apply some nice animation effects on your ASP.NET Menu control. ASP.NET Menu control offers many possibilities, but together with jQuery, you can make very rich, interactive menu accompanied with animations and effects. Lets start with an example: - Create new ASP.NET Web Application and give it a name - Open your Default.aspx page (or any other .aspx page where you will create the menu) - Our page ASPX code is: <form id="form1" runat="server"> <div id="menu">     <asp:Menu ID="Menu1" runat="server" Orientation="Horizontal" RenderingMode="List">                     <Items>             <asp:MenuItem NavigateUrl="~/Default.aspx" ImageUrl="~/Images/Home.png" Text="Home" Value="Home"  />             <asp:MenuItem NavigateUrl="~/About.aspx" ImageUrl="~/Images/Friends.png" Text="About Us" Value="AboutUs" />             <asp:MenuItem NavigateUrl="~/Products.aspx" ImageUrl="~/Images/Box.png" Text="Products" Value="Products" />             <asp:MenuItem NavigateUrl="~/Contact.aspx" ImageUrl="~/Images/Chat.png" Text="Contact Us" Value="ContactUs" />         </Items>     </asp:Menu> </div> </form> As you can see, we have ASP.NET Menu with Horizontal orientation and RenderMode=”List”. It has four Menu Items where for each I have specified NavigateUrl, ImageUrl, Text and Value properties. All images are in Images folder in the root directory of this web application. The images I’m using for this demo are from Free Web Icons. - Next, lets create CSS for the LI and A tags (place this code inside head tag) <style type="text/css">     li     {         border:1px solid black;         padding:20px 20px 20px 20px;         width:110px;         background-color:Gray;         color:White;         cursor:pointer;     }     a { color:White; font-family:Tahoma; } </style> This is nothing very important and you can change the style as you want. - Now, lets reference the jQuery core library directly from Microsoft CDN. <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.4.4.min.js"></script> - And we get to the most interesting part, applying the animations with jQuery Before we move on writing jQuery code, lets see what is the HTML code that our ASP.NET Menu control generates in the client browser.   <ul class="level1">     <li><a class="level1" href="Default.aspx"><img src="Images/Home.png" alt="" title="" class="icon" />Home</a></li>     <li><a class="level1" href="About.aspx"><img src="Images/Friends.png" alt="" title="" class="icon" />About Us</a></li>     <li><a class="level1" href="Products.aspx"><img src="Images/Box.png" alt="" title="" class="icon" />Products</a></li>     <li><a class="level1" href="Contact.aspx"><img src="Images/Chat.png" alt="" title="" class="icon" />Contact Us</a></li> </ul>   So, it generates unordered list which has class level1 and for each item creates li element with an anchor with image + menu text inside it. If we want to access the list element only from our menu (not other list element sin the page), we need to use the following jQuery selector: “ul.level1 li”, which will find all li elements which have parent element ul with class level1. Hence, the jQuery code is:   <script type="text/javascript">     $(function () {         $("ul.level1 li").hover(function () {             $(this).stop().animate({ opacity: 0.7, width: "170px" }, "slow");         }, function () {             $(this).stop().animate({ opacity: 1, width: "110px" }, "slow");         });     }); </script>   I’m using hover, so that the animation will occur once we go over the menu item. The two different functions are one for the over, the other for the out effect. The following line $(this).stop().animate({ opacity: 0.7, width: "170px" }, "slow");     does the real job. So, this will first stop any previous animations (if any) that are in progress and will animate the menu item by giving to it opacity of 0.7 and changing the width to 170px (the default width is 110px as in the defined CSS style for li tag). This happens on mouse over. The second function on mouse out reverts the opacity and width properties to the default ones. The last parameter “slow” is the speed of the animation. The end result is:   The complete ASPX code: <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server">     <title>ASP.NET Menu + jQuery</title>     <style type="text/css">         li         {             border:1px solid black;             padding:20px 20px 20px 20px;             width:110px;             background-color:Gray;             color:White;             cursor:pointer;         }         a { color:White; font-family:Tahoma; }     </style>     <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.4.4.min.js"></script>     <script type="text/javascript">         $(function () {             $("ul.level1 li").hover(function () {                 $(this).stop().animate({ opacity: 0.7, width: "170px" }, "slow");             }, function () {                 $(this).stop().animate({ opacity: 1, width: "110px" }, "slow");             });         });     </script> </head> <body>     <form id="form1" runat="server">     <div id="menu">         <asp:Menu ID="Menu1" runat="server" Orientation="Horizontal" RenderingMode="List">                         <Items>                 <asp:MenuItem NavigateUrl="~/Default.aspx" ImageUrl="~/Images/Home.png" Text="Home" Value="Home"  />                 <asp:MenuItem NavigateUrl="~/About.aspx" ImageUrl="~/Images/Friends.png" Text="About Us" Value="AboutUs" />                 <asp:MenuItem NavigateUrl="~/Products.aspx" ImageUrl="~/Images/Box.png" Text="Products" Value="Products" />                 <asp:MenuItem NavigateUrl="~/Contact.aspx" ImageUrl="~/Images/Chat.png" Text="Contact Us" Value="ContactUs" />             </Items>         </asp:Menu>     </div>     </form> </body> </html> Hope this was useful. Regards, Hajan

    Read the article

< Previous Page | 94 95 96 97 98 99 100 101 102 103 104 105  | Next Page >