Search Results

Search found 46894 results on 1876 pages for 'java native interface'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 993/1876 | < Previous Page | 989 990 991 992 993 994 995 996 997 998 999 1000  | Next Page >

  • Is a point inside or outside a polygon which is on the surface of a globe

    - by richard
    How do I determine if a point is inside or outside a polygon that lies on the the surface of the earth? The inside of the polygon can be determined via the right hand rule, ie. the inside of the polygon is on your right hand side when you walk around the polygon. The polygon may Circle either pole Cross the 180 longitude Cover more than 50% of the globe As the globe is a sphere the normal ray crossing algorithms do not work correctly.

    Read the article

  • Blackberry Contacts Photo

    - by Farhan
    Hi, I am currently working on the Application named (Blackberry Contacts Sync) and i am stuck at this point that how i sync Contact's Image. Please tell me how to store images in Database(MySQL) and how to retrieve it.

    Read the article

  • form inside tabview doesn't work

    - by user3536737
    i am working with jsf and primefaces , and here is what 've tried well i want to creat a tabview that get data from an arraylist in my bean i get for exemple 4 tabs , and inside each one i've created a hidden panel where i have a form with 2 input text to update informations , do i display the panel when i click on the second button Update , after that my panel is not hidden anymore , and i set the new values and click on the second button to update the informations , the problem is that the updating and the execution is working only for the first tab , it means when i try to update the new informations it works for the first one and for the other tabs it doesn't here is the code <p:tab title="#{rr.nom_ressource}"> <h:panelGrid> <h:graphicImage value="Ressources/images/emp.jpg" style="vertical-align:middle" /> <span style="font-size:15px; width:170px; display:inline-block;"> Nom : #{rr.nom_ressource} Type: #{rr.type_ressource} Specification: #{rr.experience} </span> <h:commandButton image="Ressources/images/delete.jpg" actionListener="#{SelectBean.act}" update=":form" style="vertical-align:middle" > Update </h:commandButton> <h:commandButton update=":outPanel" actionListener="#{SelectBean.mod1()}" image="Ressources/images/update.png" style="vertical-align:middle" > Modifier </h:commandButton> <h:form id="form111"> <p:growl id="growl" showDetail="true" sticky="true" /> <p:panel rendered ="#{SelectBean.bol}" closable="true" toggleable="true" id="outPanel" styleClass="outPanel" widgetVar="outpanel"> <h:outputLabel value="Nom " /> <h:inputText value="#{SelectBean.nom}" /> <br/> <h:outputLabel value="Experience " /> <h:inputText value="#{SelectBean.exp}" /> <br/> <h:commandButton value="Update" action="#{SelectBean.done}"/> </p:panel> </h:form> </h:panelGrid> </p:tab> for my managedbean the code is correct i think the problem is here

    Read the article

  • Can't add libraries to Eclipse Android project

    - by neuromancer
    I'm trying to get the Hackbook for Android project to work in Eclipse. One of the things I need to do is remove that invalid reference and include that project I made. I did this before, but then I started over and now it doesn't work. Here is where I add the project. If I click "Apply" and then "OK" everything seems to be fine, but it isn't, because when I go back to this screen, none of the changes I made are there. Why isn't it saving my changes? How am I supposed to do this?

    Read the article

  • How to clean up my code

    - by simion
    Being new to this i realy am trying to learn how to keep code as simple as possible, whilst doing the job its supposed to. The question i have done is from project eulur, it says Each new term in the Fibonacci sequence is generated by adding the previous two terms. By starting with 1 and 2, the first 10 terms will be: 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, ... Find the sum of all the even-valued terms in the sequence which do not exceed four million. Here is my code below, i was wondering what the best way of simplifying this would be, for a start removing all of the .get(list.length()-1 )..... stuff would be a good start if possible but i dont really no how to? Thanks public long fibb() { ArrayList<Integer> list = new ArrayList<Integer>(); list.add(1); list.add(2); while((list.get(list.size() - 1) + (list.get(list.size() - 2)) < 4000000)){ list.add((list.get(list.size()-1)) + (list.get(list.size() - 2))); } long value = 0; for(int i = 0; i < list.size(); i++){ if(list.get(i) % 2 == 0){ value += list.get(i); } } return value; }

    Read the article

  • problem with "select new Object ... join ... where"

    - by jacob
    Hi, I'm having a problem with an HQL query Three classes ClassOne is my BusinessObject public class ClassOne { private int id; private int status; private Set<ClassTwo> classTwos; + other fields/getters/setters/constructor etc } ClassTwo is referenced in a set of ClassOne and is kind of the history of an object of ClassOne public class ClassTwo { private int id; private int oldStatus; private int newStatus; private String message; //+ getters/setters/constructor etc } ClassThree is my DTO/VO with just one classTwo (not the whole history) public class ClassThree { private int id; private int status; private ClassTwo classTwo; public ClassThree(int pId, int pStatus, ClassTwo pClassTwo) { id=pId; status=pStatus; classTwo=pClassTwo; } //+ getters/setters etc } Now I'd like to create an HQL query like this: I'd like to get all objects of ClassThree with a certain status and if it exists the newest ClassTwo with a certain newStatus. For example: I'd like to get all the DTOs (ClassThree) of ClassOne whose status is now 1, but earlier in their history it has been 2 and I'd like to have the latest ClassTwo object which has 2 as newStatus. SELECT new ClassThree(c1.id, c1.status, c2) FROM ClassOne c1 LEFT JOIN c1.classtwos c2 (...) and (...) is where I don't know what to do, I'm not even sure if it's a join / join fetch Looked around and tried quite a lot already, but no clue. Especially with the join fetch I get some Hibernate errors like org.hibernate.QueryException: query specified join fetching, but the owner of the fetched association was not present in the select list. Fetching the BusinessObject like that is no problem SELECT distinct(c1) FROM ClassOne c1 LEFT OUTER JOIN FETCH c1.classtwos c2 and I get the ClassTwos as my field. Thanks in advance, Jacob P.S.: One thing might be important, ClassTwo has no reference to ClassOne!!

    Read the article

  • how to get email id from google api response

    - by user1726508
    i am able to get user information from Google API response using oath2 . But i do't know how to get those responses individually . Response i am getting from Google Api: * Access token: ya29.AHES6ZQ3QxKxnfAzpZasdfd23423NuxJs29gMa39MXV551yMmyM5IgA { "id": "112361893525676437860", "name": "Ansuman Singh", "given_name": "Ansuman", "family_name": "Singh", "link": "https://plus.google.com/112361893525676437860", "gender": "male", "birthday": "0000-03-18", "locale": "en" } Original Token: ya29.AHES6ZQ3QxKxnfAzpZu0lYHYu8sdfsdafdgMa39MXV551yMmyM5IgA New Token: ya29.AHES6ZQ3QxKxnfdsfsdaYHYu8TNuxJs29gMa39MXV551yMmyM5IgA But i want only "id" & "name" indiviually to save in my Database table. How can i do this? I got those above response/output By using the below code. public static void main(String[] args) throws IOException { ------------------------- ------------------------- ------------------------- String accessToken = authResponse.accessToken; GoogleAccessProtectedResource access = new GoogleAccessProtectedResource(accessToken, TRANSPORT, JSON_FACTORY, CLIENT_ID, CLIENT_SECRET, authResponse.refreshToken); HttpRequestFactory rf = TRANSPORT.createRequestFactory(access); System.out.println("Access token: " + authResponse.accessToken); String url = "https://www.googleapis.com/oauth2/v1/userinfo?alt=json&access_token=" + authResponse.accessToken; final StringBuffer r = new StringBuffer(); final URL u = new URL(url); final URLConnection uc = u.openConnection(); final int end = 1000; InputStreamReader isr = null; BufferedReader br = null; isr = new InputStreamReader(uc.getInputStream()); br = new BufferedReader(isr); final int chk = 0; while ((url = br.readLine()) != null) { if ((chk >= 0) && ((chk < end))) { r.append(url).append('\n'); } } System.out.print(""); System.out.println(); System.out.print(" "+ r ); //this is printing at once but i want them individually access.refreshToken(); System.out.println("Original Token: " + accessToken + " New Token: " + access.getAccessToken()); }

    Read the article

  • Finding all CLASSPATH resources matching a pattern

    - by binil
    I want to read a bunch of text files, by loading them as resources using the context classloader. URL url = Thread.currentThread() .getContextClassloader() .getResource("folder/foo.txt"); Is there some way to get a list of resources whose names match a given pattern? For eg: URL[] matchingUrls = someLibrary.getMatchingResources("folder/*.txt"); Libraries like Spring can scan the classpath to find classes with a given annotation, so I am wondering if there something similar to load a bunch of resources.

    Read the article

  • Full and Partial Matching of Sets

    - by jeffrey
    I have several sets of the same type [Y, M, D] and am trying to write a function to search these sets and return an array of the available sets that fit my parameters. ReturnedSets = return_matches(Y,M,D); I want the three parameters of the function return_matches to be optional. Which means any combination of values can be used to return the sets. For example, one could write - return_matches(13,null,2); - and the function would look for all sets that contain [13, anyValue, 2]; I'm writing this in PHP, to allow users to manage dated files on my website, but I'd like to be able to use this function again for other uses. Thanks! edit: (This, or variations of this, is all I can come up with so far... There is something extra that I don't understand, because this function ends up / would not work to return sets that contain y and d, but leaving m arbitrary. if(y == s[0]){ if(m == s[1]){ if(d == s[2]){ print "day match"; } } else {print "month match";} } else {print "year match";} } else {print "no match";}

    Read the article

  • Is my way of doing threads in Android correct?

    - by Charlie
    Hi, I'm writing a live wallpaper, and I'm forking off two separate threads in my main wallpaper service. One updates, and the other draws. I was under the impression that once you call thread.start(), it took care of everything for you, but after some trial and error, it seems that if I want my update and draw threads to keep running, I have to manually keep calling their run() methods? In other words, instead of calling start() on both threads and forgetting, I have to manually set up a delayed handler event that calls thread.run() on both the update and draw threads every 16 milliseconds. Is this the correct way of having a long running thread? Also, to kill threads, I'm just setting them to be daemons, then nulling them out. Is this method ok? Most examples I see use some sort of join() / interrupt() in a while loop...I don't understand that one...

    Read the article

  • Help choosing the right data structure

    - by devoured elysium
    I need a data structure with the following requirements: Needs to be able to get elements by index (like a List). I will always just add / remove elements from the end of the structure. I am inclined to use an ArrayList. In this situation, it seems to be O(1) both to read elements (they always are?), remove elements (I only need to remove them at the end of the list) and to add(I only add to the end of the list). There is only the problem that time to time the ArrayList will have a performance penalty when it's completly full and I need to add more elements to it. Is there any other better idea? I don't think of a data structure that'd beat the ArrayList here. Thanks

    Read the article

  • create an hotspot and set an image without background (like earth icon) to my panel

    - by sirvan
    Hi I try to create an hotspot by Extends of canvas and I try to add it on a panel witch painted by images , so I must to draw an icon (image) instead of clear rectangle of the screen, to do that I override the paint method to draw the icon I want to use, so far there is no problem, the hotspot work true and the icon painted in true size I want(32,24 pixel) I try to add this hotspot after painting image on the my panel in mypanel.paint(g) that override too. The problem , I use an car icon that have no background !!(I hope you can understand me) just car icon must be show on the panel that painted with my images; But an unwanted rectangle created around the icon and made bad view, How I can paint may icon on panel without that background? Please help me.

    Read the article

  • im writing this code so the user would enter his/her name and followed by his/her marks to get the a

    - by WM
    What if the user wanted to enter his/her grades in the following way: Will 23, 34, 45, 45 how would i get rid of the commas public class StudentAverage { public static void main(String[] args) { int markSum = 0; double average = 0; Scanner input1 = new Scanner(System.in); System.out.print("Enter student record : "); String name = input1.next(); Scanner input2 = new Scanner(input1.nextLine()); int countTotal = 0; while (input2.hasNextInt()) { countTotal++; markSum += input2.nextInt(); } average = markSum / countTotal; // to calculate the total average System.out.print( name + " " + average ); } }

    Read the article

  • "Change" panel on jframe

    - by bog
    I have 2 panels, the first one is the menu, and the second is the application main panel. Firstly the menu panel shows up, than i need to switch to the other panel if a specific button is pressed on the menu (the menu is hidden but the app returns to it after running is completed). && i need to resize the frame too if it's possible. can i do this somehow?

    Read the article

  • How to trigger an application in mobile automatically

    - by san6086
    My idea is to make an application start automatically when a message from a specific user reaches the inbox of the mobile . For example if my friend sends some numbers to my mobile, the sms has to be read and validated first and then calculator ( inbuilt mobile application) has to be triggered and process the numbers from the message. Please help me with the above query.

    Read the article

  • replace capturing group

    - by Don
    Hi, If I have a regex with a capturing group, e.g. foo(_+f). If I match this against a string and want to replace the first capturing group in all matches with baz so that foo___f blah foo________f is converted to: foobaz blah foobaz There doesn't appear to be any easy way to do this using the standard libraries. If I use Matcher.replaceAll() this will replace all matches of the entire pattern and convert the string to baz blah baz Obviously I can just iterate through the matches, store the start and end index of each capturing group, then go back and replace them, but is there an easier way? Thanks, Don

    Read the article

  • Hibernate - One design problem

    - by Yatendra Goel
    I am learning Hibernate from the tutorial on JBoss website. I have a confusion in a code example located here. There is a Cat class code at 4.1. A simple POJO example. This Cat class has a reference to his mother as private Cat mother; Q1. If the class has an identifier property as id, then wouldn't it be better to store the cat's mother's id instead of cat's mother object. means instead of private Cat mother; wouldn't it be better to have private long motherId; `

    Read the article

  • Find messages from certain key till certain key while being able to remove stale keys.

    - by Alfred
    My problem Let's say I add messages to some sort of datastructure: 1. "dude" 2. "where" 3. "is" 4. "my" 5. "car" Asking for messages from index[4,5] should return: "my","car". Next let's assume that after a while I would like to purge old messages because they aren't useful anymore and I want to save memory. Let's say at time x messages[1-3] became stale. I assume that it would be most efficient to just do the deletion once every x seconds. Next my datastructure should contain: 4. "my" 5. "car" My solution? I was thinking of using a concurrentskiplistset or concurrentskiplist map. Also I was thinking of deleting the old messages from inside a newSingleThreadScheduledExecutor. I would like to know how you would implement(efficiently/thread-safe) this or maybe use a library?

    Read the article

  • How to create an ARGB_8888 pixel value?

    - by vidstige
    Say I want to create an array of pixel values to pass into the createBitmap method described here. I have three int values r, g, b in the range 0 - 0xff. How do I transform those into a opaque pixel p? Does the alpha channel go in the high byte or the low byte? I googled up the documentation but it only states that: Each pixel is stored on 4 bytes. Each channel (RGB and alpha for translucency) is stored with 8 bits of precision (256 possible values.) This configuration is very flexible and offers the best quality. It should be used whenever possible. So, how to write this method? int createPixel(int r, int g, int b) { retrurn ? }

    Read the article

  • Question on XJB

    - by Hima
    I have two tables -- INSTALL_BUILD_RESULTS and BUILD_RESULTS. IBR has a primary key called Install_Build_Id and BR has a primary key called Build_Id. Both are numbers A third table, LINK_BUILD_TO_INSTALL_BUILD is a table simply consisting of the two columns mentioned above, used together as a composite key. How can I write an xjb for these 3 tables.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 989 990 991 992 993 994 995 996 997 998 999 1000  | Next Page >