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  • JPanel superclass doesn't add the components of its subclasses..

    - by Acryl
    Well, I use a JFrame that adds two JPanels. Those JPanels are superclasses, because I find it easier to separate different areas of the GUI into different classes. But here's the problem: I add the (superclass) JPanel to the JFrame I set the layout of the superclass JPanel to new BorderLayout(); I add components in the subclasses, like this: JPanel panel = new JPanel(); panel.setLayout(new GridLayout(2,1)); panel.add(new JLabel("Label:"); panel.add(new JTextField(); add(panel, BorderLayout.NORTH); But it doesn't show. What do I do wrong? I've tried it without an additional JPanel in the subclasses, but it doesn't work either. I use jdk 1.6

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  • How to see full compile path in Eclipse?

    - by alleywayjack
    I have looked for an answer for this nearly every where that I can think of, but there doesn't seem to be any way to actually SEE what Eclipse "runs" to compile the projects (as it does need the JDK installed and visible to actually build). I ask because I imported a few jars into my project, and even though I've looked through all the javac documentation, I can't seem to figure out how to mimic it quite like Eclipse does. I really, really need to be able to compile on the command line in this case - Eclipse or any other IDE just isn't what is needed. I started to look through the Eclipse source, and although this sounds lazy, I just became overwhelmed and figured I would ask here first, hoping someone else had the same question at one point.

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  • JAXM soap message parsing

    - by Dean
    I am getting the following XML back from a .net service: <?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <soap:Body> <validateCredentialsResponse xmlns="http://www.paragon.com/positionmonitor/PositionMonitor"> <validateCredentialsResult> <ResultData xsi:type="ValidateCredentialsResultData"> <validated>true</validated> <alreadyLoggedIn>false</alreadyLoggedIn> </ResultData> <Status> <Condition xmlns="">SUCCESS</Condition> <ErrorCode xmlns="">BO.00000</ErrorCode> <ErrorDesc xmlns="">OK</ErrorDesc> </Status> </validateCredentialsResult> </validateCredentialsResponse> </soap:Body> </soap:Envelope> ...and I'm trying to parse it using JAXM, however the following always evaluates to null: SOAPEnvelope env = reply.getSOAPPart().getEnvelope(); Can anyone help me out here?

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  • how to run TimerTask off main UI thread?

    - by huskyd97
    I am having trouble with a TimerTask Interfering with In App Purchasing (Async Tasks). I am weak with Threads, so I believe it is running on the main UI thread, eating up resources. How can I run this outside the UI thread? I have searched, and tried some suggestions using handlers. but seems like I get the same result, app gets really laggy. when I don't run this task (refreshes every 500mS), the activity runs smoothly, and there are no hangs during In app purchases. Your help is appreciated, code snippet below: public class DummyButtonClickerActivity extends Activity { protected Timer timeTicker = new Timer("Ticker"); private Handler timerHandler = new Handler(); protected int timeTickDown = 20; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.mainhd); // start money earned timer handler TimerTask tick = new TimerTask() { public void run() { myTickTask(); } }; timeTicker.scheduleAtFixedRate(tick, 0, 500); // 500 ms each } // End OnCreate protected void myTickTask() { if (timeTickDown == 0) { /// run my code here //total = total + _Rate; timerHandler.post(doUpdateTimeout); } else if(timeTickDown < 0) { // do nothing } timeTickDown--; } private Runnable doUpdateTimeout = new Runnable() { public void run() { updateTimeout(); } }; private void updateTimeout() { // reset tick timeTickDown = 2; // 2* 500ms == once a second } }

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  • pass Value from class to JFrame

    - by MYE
    Hello everybody! i have problem between pass value from Class to another JFrame my code write follow MVC Model. Therefore i have 1 class is controller , one jframe is view and 1 class is model. i have some handle process on controller to get value on it and i want this value to jframe but not pass by constructor . How can i pass value from class to jframe and when value be pass jframe will use it to handle. Ex: public class A{ private String str; public A(){ } public void handle(){ ViewFrame v = new ViewFrame(); v.setVisible(true); v.pack(). v.setSize(330,600); str = "Hello World"; //init value here v.getString(str);// pass value to jframe here. } } ======================= public class ViewFrame extends JFrame{ private String str; public ViewFrame (){ System.out.println(str); } public String getString(String str){ return this.str = str; } } but it return null??

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  • Accessing variablss through a different class within the constructor of latter classes of an object

    - by Haxed
    In the code below, I've added two lines that print output. The first line prints junk as usual, but surprisingly the second one gives me a compilation error. Why? class Student { private String name; public Student(String name){ this.name = name; } public String getName(){ return name; } } class StudentServer { public StudentServer(){ Student[] s = new Student[30]; s[0] = new Student("Nick"); // LINE 01: This compiles, although prints junk System.out.println(s[0]); // LINE 02: I get a error called cannot find symbol System.out.println(s[0].getName()); } public static void main(){ new StudentServer(); } } Many Thanks

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  • disable the Home Button and Back Button"

    - by michael
    i want way to disable the Home Button & Back Button when click on checkbox in application , my application on version 4.2.2 i have code but not work when click on checkbox work stop to application public void HardButtonOnClick(View v) { boolean checked1 = ((CheckBox) v).isChecked(); if(checked1) { SQLiteDatabase db; db = openOrCreateDatabase("Saftey.db", SQLiteDatabase.CREATE_IF_NECESSARY, null); db.setVersion(1); db.setLocale(Locale.getDefault()); db.setLockingEnabled(true); ContentValues values = new ContentValues(); values.put("hardBtn", "YES"); db.update("Setting", values, "id = ?", new String[] { "1" }); Toast.makeText(this, "Hard Button Locked", Toast.LENGTH_LONG).show(); //SharedPreferences pref = getSharedPreferences("pref",0); //SharedPreferences.Editor edit = pref.edit(); //edit.putString("hard","yes"); //edit.commit(); /* String Lock="yes" ; Bundle bundle = new Bundle(); bundle.putString("key", Lock); Intent a = new Intent(Change_setting.this, ChildMode.class); a.putExtras(bundle); startActivity(a);*/ super.onAttachedToWindow(); this.getWindow().setType(WindowManager.LayoutParams.TYPE_KEYGUARD); isLock = true; } else { SQLiteDatabase db; db = openOrCreateDatabase("Saftey.db", SQLiteDatabase.CREATE_IF_NECESSARY, null); db.setVersion(1); db.setLocale(Locale.getDefault()); db.setLockingEnabled(true); ContentValues values = new ContentValues(); values.put("hardBtn", "NO"); db.update("Setting", values, "id = ?", new String[] { "1" }); //SharedPreferences pref = getSharedPreferences("pref",0); //SharedPreferences.Editor edit = pref.edit(); //edit.putString("hard","no"); //edit.commit(); Toast.makeText(this, "Hard Button Un-Locked", Toast.LENGTH_LONG).show(); isLock = false; } } how can work it??

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  • servlet connection to DB

    - by underW
    Initially, after reading books on the subject, I firmly believed that the algorithm for working with a database from a servlet is as follows: create a connection - connect to the database - form a request - send the request to the database - get the query results - process them - close connection - OK. Now, with a better understanding of the practical side, I realized that nobody does it that way, and everything happens through a connection pool according to the following algorithm: initialize the servlet - create a connection pool - a request comes from a user - take a free connection from the pool - form a request - send the request to the database - get the query results - process them - return the connection back to the pool - ok. Now I have this problem: We have 100 users, they are divided into 10 groups, each group has it's own username and password to connect to the database. Moreover, each group may have different rights to the database. How am I supposed to use a connection pool in this situation? If I understand correctly, a pool is nothing more than just a group of similar connections with a single login and password. And here I have 10 pairs of username / password. It looks like I cannot use the pool in this situation. What should I do?

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  • Android: how to get the walking distance between two geo coordinats?

    - by wei
    I used this query URL http://maps.google.com/maps?q=from+A+to+B&output=kml ,which is given in the answer to this question. But after I tried it, it doesn't work with coordinates. It works with address names tho. I guess I could use google's geocoding to get the addresses first. But I wonder if there is another way to get the walking distance between two coordinates?

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  • How to dynamicly build up a gui

    - by InsertNickHere
    Hi there, for the app i am creating i need a lot "option menus". E.g. for the sound file trimming part it would be something like "leadingSilence" / Integer "trailingSilence" / Integer "hold" / Integer. Overall, there are a lot of options of different types (int, float, string), and im thinking about if it is a better way to manualy create a window for each option set, or to dynamicly create them. last one would be quite easy if all types were similar (so i would just add eg spinButtons) I guess but its not. At this time i mange the options with the standard .properties of jave, and there is no need to change. My question is: is there a lib which provides such functionality, or is there a "standard way" to do this? How much work would it be? How to dynamicly create the selection listeners? In could i'd love to have something like: OptionWindow trimmingOptionWindow = createWindowFromOptionSet(OptionManager.getOptions("trimming") ); trimmingOptionWindow.open(); I hope its clear what I mean :)

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  • Launch Activity with Intent Filter on Right Time

    - by user511853
    Hi. I want to launch my own media player application when I want to watch a video from Youtube. When I write android:scheme="http" and android:host="m.youtube.com" it is OK. But, it asks everywhere in m.youtube.com to open my app. So, it gets annoying. I tried to use pathPattern, pathPrefix and path to solve this but I didn't get ahead. All I want is clearly this: When the link is like "http://m.youtube.com/index?desktop_uri=%2F%gl=US#" the intent filter shouldn't launch my app. When the link is like "http://m.youtube.com/index?desktop_uri=%2F&gl=US#/watch?xl=xl_blazer&v=k3Cdqx1qFX8" my application should be launched. Is there anyone that can help me?

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  • Quartz: triggering multiple jobs

    - by Phanindra
    In Quarts, can I use a single trigger to schedule multiple jobs, so that all the jobs gets executed in parallel. What is the best way to do this. Example, every hour execute Jobs j1, j2, ..., jn in parallel. Assuming that there is no dependency between the jobs.

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  • Android - Fill Layout with Buttons

    - by GuyNoir
    Just a quick question about how you would go about implementing this. I want there to be buttons at the bottom of the screen, but if the screen size is larger, more buttons would be added. For example, at a small screen size, there might be 4-5 buttons at the bottom, but if you ran it on a tablet or something similar, there would be maybe 20 buttons. Any suggestions? It can't scroll either, it just has to dynamically fill the layout with buttons. Thanks.

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  • How to use a photo that has just been uploaded to Tomcat v6?

    - by Zombie_Colonel
    In an android application a user can upload a picture to a Tomcat server v6 in (Projet\WebContent\images) A second user can come at the same time display the picture thing not work it shows me: The requested resource is not available. I did what? I have to reboot the server? refresh? in a PHP page I upload pictures and then they are simply viewed by the user, for cons there I find difficulty with JEE

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  • JDBC with JSP fails to insert

    - by StrykeR
    I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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  • What does the exception "javax.servlet.jsp.JspException: Broken pipe" signify?

    - by Ruepen
    I'm getting the following error: javax.servlet.jsp.JspException: Broken pipe Now I have seen questions/answers with respects to the socket exception, but this error is coming from a different package. Any help is greatly appreciated. BTW, I am seeing quite a lot of these errors in a struts web app Weblogic Node logs and I am thinking that it has to do with end users closing their web browser before the page reloads/executes the next step (database transaction which takes quite a bit of time to execute, anywhere from 30 seconds to 4 mins).

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  • OPENGL Android getting the coordinates of my image

    - by Debopam
    I used the codes from the following the website. And it helped a lot to draw the required object on my screen. But the problem I am facing is getting the coordinates of my object. Let me explain. According to the code. You just need to add your graphic images in PNG format and refer it to the class here. What I am trying to achieve is a simple collision detection mechanism. I have added a maze (as PNG). And have a object (as PNG) to go through the blank path within the maze. In order to do this I need to know the blank spaces within the coordinates through which my object will move. Can any one tell me how to get the blank spaces as (x,y) coordinates through which I can take my object?

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  • How to add clear option to this whiteboard?

    - by swift
    i have to add clear screen option to my whiteboard application, usual procedure is to draw a fill rect to the sizeof the image. But in my app i have transparent panels added one above the other i.e as layers, if i follow the usual procedure the drawing from the underlying panel wont be visible. please tell me any logic to do this. public void createFrame() { JFrame frame = new JFrame(); JLayeredPane layerpane=frame.getLayeredPane(); board= new Whiteboard(client); //board is a transparent panel // tranparent image: board.image = new BufferedImage(590,690, BufferedImage.TYPE_INT_ARGB); board.setBounds(74,23,590,690); board.setImage(image); virtualboard.setImage(image); //virtualboardboard is a transparent panel virtualboard.setBounds(74,23,590,690); JPanel background=new JPanel(); background.setBackground(Color.white); background.setBounds(74,25,590,685); layerpane.add(board,new Integer(5)); layerpane.add(virtualboard,new Integer(4));//Panel where remote user draws layerpane.add(background,new Integer(3)); layerpane.add(board.colourButtons(),new Integer(2)); layerpane.add(board.shapeButtons(),new Integer(1)); layerpane.add(board.createEmptyPanel(),new Integer(0)); }

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  • why isn't the input text file being read into the ArrayList<String>, diary?

    - by hmg
    Here's my code: public void readFile() throws IOException { System.out.println("Input file name: "); Scanner in = new Scanner(System.in); String readName = in.nextLine(); Scanner reader = new Scanner(new File(readName)); System.out.println("Reading file..."); while (reader.hasNextLine()) { System.out.println(reader.nextLine()); } System.out.println("File read."); Scanner inAgain = new Scanner(System.in); System.out.println("Would you like to read this into the current Diary?"); System.out.println("Warning: This will overwrite your current Diary!"); String readFileConfirm = inAgain.nextLine(); ArrayList<String> readData = new ArrayList<String>(); if (readFileConfirm.equalsIgnoreCase("yes")) { for (int i = 0; i < readData.size(); i++) { readData.add(reader.nextLine()); } System.out.println("Data added to extra array..."); System.out.println("Here are the contents."); for (int i = 0; i < readData.size(); i++) { System.out.println(readData.get(i)); } System.out.println("Contents read."); System.out.println("Now overwriting current Diary with read file..."); diary.clear(); for (int i = 0; i < diary.size(); i++) { diary.add(readData.get(i)); } System.out.println("New Diary created!"); System.out.println("Use 'recall' to see your new Diary!"); } else { System.out.println("Very well, returning to first command entry."); } } Thanks in advance! -h

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