Search Results

Search found 46894 results on 1876 pages for 'java native interface'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 994/1876 | < Previous Page | 990 991 992 993 994 995 996 997 998 999 1000 1001  | Next Page >

  • How do I change the build's SDK version in Xcode?

    - by Kavon Farvardin
    I'm using Xcode 2.5 on Mac 10.4.11 PPC. javac -version returns 1.5.x yet when I imported my source code and tried to build it in Xcode, I get errors all over because generics, annotations, and for-each loops are not supported in -source 1.3. I thought I found the setting to change the source version in Xcode in the above but it doesn't work. Any ideas?

    Read the article

  • How to find out efficiently the auto-generated id for a new object when using JPA?

    - by webstarg
    Hello, I have an attribute which is annotated with @Id. The ID is going to be generated automatically when persisting the object. That means that the ID-value is not defined before I persist the object. After persisting it, it has an ID (in the database), but unfortunately the field still remains null as long as I don't reload it from the DB. is there any easy way to find out the generated id? Or better: To configure that it will be written into the field? Thanks in advance

    Read the article

  • Does a servlet knows the encoding of the sent form that specified using http-equiv?

    - by Daziplqa
    Does a servlet knows the encoding of the sent form that specified using http-equiv? When I specify an encoding of a POSTed form using http-equiv like that: <HTML> <head> <meta http-equiv='Content-Type' content='text/html; charset=gb2312'/> </head> <BODY > <form name="form" method="post" > <input type="text" name="v_rcvname" value="????"> </form> </BODY> </HTML> And then at the servlet I use the method, request.getCharacterEncoding() I got null ! So, Is there a way that I can tell the server that I am encoding the data in some char encoding??

    Read the article

  • Why does this compile?

    - by akf
    I was taken aback earlier today when debugging some code to find that something like the following does not throw a compile-time exception: public Test () { HashMap map = (HashMap) getList(); } private List getList(){ return new ArrayList(); } As you can imagine, a ClassCastException is thrown at runtime, but can someone explain why the casting of a List to a HashMap is considered legal at compile time?

    Read the article

  • Quartz: triggering multiple jobs

    - by Phanindra
    In Quarts, can I use a single trigger to schedule multiple jobs, so that all the jobs gets executed in parallel. What is the best way to do this. Example, every hour execute Jobs j1, j2, ..., jn in parallel. Assuming that there is no dependency between the jobs.

    Read the article

  • Is there a file diff tool that allows for exceptions?

    - by Kevin
    We currently use Beyond Compare 3.0 and I am quite pleased with it. However, it would be great if I could easily specify an exclusion for a specific one-time case. This is needed when I am doing a code review of some refactoring. For instance: Old code doSomething(ConstantsInterface.FOOBAR); New code: doSomething(BetterEnumeration.FOOBAR); In this case, I have hundreds of changes that I am reviewing that are essentially all the same exact change and I just want to see the exceptions. It would be great if I could easily specify an exception that indicates these two cases are equal. I know of a way to do it in the grammar, but it is tedious and cumbersome in the case where there are ten or so exceptions. Any other tips?

    Read the article

  • JPanel superclass doesn't add the components of its subclasses..

    - by Acryl
    Well, I use a JFrame that adds two JPanels. Those JPanels are superclasses, because I find it easier to separate different areas of the GUI into different classes. But here's the problem: I add the (superclass) JPanel to the JFrame I set the layout of the superclass JPanel to new BorderLayout(); I add components in the subclasses, like this: JPanel panel = new JPanel(); panel.setLayout(new GridLayout(2,1)); panel.add(new JLabel("Label:"); panel.add(new JTextField(); add(panel, BorderLayout.NORTH); But it doesn't show. What do I do wrong? I've tried it without an additional JPanel in the subclasses, but it doesn't work either. I use jdk 1.6

    Read the article

  • Validation - Data Integrity

    - by Thomas
    A table can only store 10 records in a particular state, 10 users over 30 years for example, the others must be less than 30 years. It is a business rule and as such should be respected. How to ensure that state? Think: multiple users accessing this table.

    Read the article

  • Reading http file on url

    - by Nkunzis
    I am trying to read an xml file on an http url. "Unexpected end of file from server" keeps on coming . the page is password protected, I would like to know if I am properly giving in my url authentication details. I tried with non protected pages and I can read them properly. Here is my code: URL url = new URL("http://username:[email protected]:0000/test.xml"); URLConnection yc = url.openConnection(); BufferedReader in = new BufferedReader(new InputStreamReader(yc.getInputStream())); String inputLine; while ((inputLine = in.readLine()) != null) System.out.println(inputLine); in.close();

    Read the article

  • Finding occurrences of element before and after the element in Array

    - by user3718040
    I am writing a algorithm, if an array contain 3 does not contain between two 1s. like this int array={5, 2, 10, 3, 15, 1, 2, 2} the above array contain 3, before 3 there is no 1 and after 3 is one 1 it should return True. int array={3,2,18,1,0,3,-11,1,3} in this array after first element of 3 there is two 1 it should return False. I have try following code public class Third { public static void main(String[] args){ int[] array = {1,2,4,3, 1}; for(int i=0;i<array.length;i++) { if(array[i]==3) { for(int j=0;j<array[i];j++) { if(array[j]==1) { System.out.println("I foud One before "+array[j]); }else { break; } System.out.println("yes i found the array:"+array[i]); } for(int z=0;z>array[i];z++) { if(array[z]==1) { System.out.println("I found after 3 is :"+array[z]); } break; } } } } } I am not getting exact result from my above code which i want.

    Read the article

  • pass Value from class to JFrame

    - by MYE
    Hello everybody! i have problem between pass value from Class to another JFrame my code write follow MVC Model. Therefore i have 1 class is controller , one jframe is view and 1 class is model. i have some handle process on controller to get value on it and i want this value to jframe but not pass by constructor . How can i pass value from class to jframe and when value be pass jframe will use it to handle. Ex: public class A{ private String str; public A(){ } public void handle(){ ViewFrame v = new ViewFrame(); v.setVisible(true); v.pack(). v.setSize(330,600); str = "Hello World"; //init value here v.getString(str);// pass value to jframe here. } } ======================= public class ViewFrame extends JFrame{ private String str; public ViewFrame (){ System.out.println(str); } public String getString(String str){ return this.str = str; } } but it return null??

    Read the article

  • Print unique ascii characters in eclipse console

    - by Shaded
    Hey guys, Kind of a strange question but... here it goes. Recently my application threw an IOException that the text only had a clubs symbol in it (like the suit in cards) I know this is probably because there was a number in there that was cast to a char and printed to the screen, and I've found where that might have happened. The only problem is, I can't recreate it in eclipse because the eclipse console doesn't want to print those characters for me. All I get are boxes. I figure this is an encoding issue or something but I need eclipse to print out those characters just like the windows console would. Is there a setting I can change to do this?

    Read the article

  • Help for creating a random String

    - by Max
    I need to create a random string which should be between the length of 6 to 10 but it sometimes generates only about the length of 3 to 5. Here's my code. Can anyone would be able to find out the problem? :( int lengthOfName = (int)(Math.random() * 4) + 6; String name = ""; /* randomly choosing a name*/ for (int j = 0; j <= lengthOfName; j++) { int freq = (int)(Math.random() * 100) + 1; if(freq <= 6){ name += "a"; }if(freq == 7 && freq == 8){ name += "b"; }if(freq >= 9 && freq <= 11){ name += "c"; }if(freq >= 12 && freq <= 15){ name += "d"; }if(freq >= 16 && freq <= 25){ name += "e"; }if(freq == 26 && freq == 27){ name += "f"; }if(freq == 28 && freq == 29){ name += "g"; }if(freq >= 30 && freq <= 33){ name += "h"; }if(freq >= 34 && freq <= 48){ name += "i"; }if(freq == 49 && freq == 50){ name += "j"; }if(freq >= 51 && freq <= 55){ name += "k"; }if(freq >= 56 && freq <= 60){ name += "l"; }if(freq == 61 && freq == 62){ name += "m"; }if(freq >= 63 && freq <= 70){ name += "n"; }if(freq >= 71 && freq <= 75){ name += "o"; }if(freq == 76 && freq == 77){ name += "p"; }if(freq == 78){ name += "q"; }if(freq >= 79 && freq <= 84){ name += "r"; }if(freq == 85 && freq == 86){ name += "s"; }if(freq == 87 && freq == 88){ name += "t"; }if(freq >= 89 && freq <= 93){ name += "u"; }if(freq == 94){ name += "v"; }if(freq == 95 && freq == 96){ name += "w"; }if(freq == 97){ name += "x"; }if(freq == 98 && freq == 99){ name += "y"; }if(freq == 100){ name += "z"; } }

    Read the article

  • Speed/expensive of SQLite query vs. List.contains() for "in-set" icon on list rows

    - by kpdvx
    An application I'm developing requires that the app main a local list of things, let's say books, in a local "library." Users can access their local library of books and search for books using a remote web service. The app will be aware of other users of the app through this web service, and users can browse other users' lists of books in their library. Each book is identified by a unique bookId (represented as an int). When viewing books returned through a search result or when viewing another user's book library, the individual list row cells need to visually represent if the book is in the user's local library or not. A user can have at most 5,000 books in the library, stored in SQLite on the device (and synchronized with the remote web service). My question is, to determine if the book shown in the list row is in the user's library, would it be better to directly ask SQLite (via SELECT COUNT(*)...) or to maintain, in-memory, a List or int[] array of some sort containing the unique bookIds. So, on each row display do I query SQLite or check if the List or int[] array contains the unique bookId? Because the user can have at most 5,000 books, each bookId occupies 4 bytes so at most this would use ~ 20kB. In thinking about this, and in typing this out, it seems obvious to me that it would be far better for performance if I maintained a list or int[] array of in-library bookIds vs. querying SQLite (the only caveat to maintaining an int[] array is that if books are added or removed I'll need to grow or shrink the array by hand, so with this option I'll most likely use an ArrayList or Vector, though I'm not sure of the additional memory overhead of using Integer objects as opposed to primitives). Opinions, thoughts, suggestions?

    Read the article

  • How do you search through a map?

    - by Jack Null
    I have a map: Map<String, String> ht = new HashMap(); and I would like to know how to search through it and find anything matching a particular string. And if it is a match store it into an arraylist. The map contains strings like this: 1,2,3,4,5,5,5 and the matching string would be 5. So for I have this: String match = "5"; ArrayList<String> result = new ArrayList<String>(); Enumeration num= ht.keys(); while (num.hasMoreElements()) { String number = (String) num.nextElement(); if(number.equals(match)) { result.add(number); } }

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 990 991 992 993 994 995 996 997 998 999 1000 1001  | Next Page >