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Search found 841 results on 34 pages for 'angle'.

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  • Inner angle between two lines

    - by ocell
    Hi folks, I have two lines: Line1 and Line2. Each line is defined by two points (P1L1(x1, y1), P2L1(x2, y2) and P1L1(x1, y1), P2L3(x2, y3)). I want to know the inner angle defined by these two lines. For do it I calculate the angle of each line with the abscissa: double theta1 = atan(m1) * (180.0 / PI); double theta2 = atan(m2) * (180.0 / PI); After to know the angle I calculate the following: double angle = abs(theta2 - theta1); The problem or doubt that I have is: sometimes I get the correct angle but sometimes I get the complementary angle (for me outer). How can I know when subtract 180º to know the inner angle? There is any algorithm better to do that? Because I tried some methods: dot product, following formula: result = (m1 - m2) / (1.0 + (m1 * m2)); But always I have the same problem; I never known when I have the outer angle or the inner angle! Thanks in advance for reading my trouble and for your time! Oscar.

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  • Calculating the correct particle angle in an outwards explosion

    - by Sun
    I'm creating a simple particle explosion but am stuck in finding the correct angle to rotate my particle. The effect I'm going for is similar to this: Where each particle is going outwards from the point of origin and at the correct angle. This is what I currently have: As you can see, each particle is facing the same angle, but I'm having a little difficulty figuring out the correct angle. I have the vector for the point of emission and the new vector for each particle, how can I use this to calculate the angle? Some code for reference: private Particle CreateParticle() { ... Vector2 velocity = new Vector2(2.0f * (float)(random.NextDouble() * 2 - 1), 2.0f * (float)(random.NextDouble() * 2 - 1)); direction = velocity - ParticleLocation; float angle = (float)Math.Atan2(direction.Y, direction.X); ... return new Particle(texture, position, velocity, angle, angularVelocity, color, size, ttl, EmitterLocation); } I am then using the angle created as so in my particles Draw method: spriteBatch.Draw(Texture, Position, null, Color, Angle, origin, Size, SpriteEffects.None, 0f);

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  • Specifying force and angle in ApplyImpulse in box2d

    - by Deepak Mahalingam
    I need to apply an impulse on a object with a particular force and at a particular angle in Box2d. If I am right the syntax would be the following: body.GetBody().ApplyImpulse(new b2Vec2(direction, power),body.GetBody().GetWorldCenter()); The problem is my direction is in angles. I found a discussion where it was said that the way we can convert an angle into a vector would be as: new b2Vec2(Math.cos(angle*Math.PI/180),Math.sin(angle*Math.PI/180)); Now I am not sure how to combine these two. In other words, if I wish to apply a force of 30 units at an angle of 30 degrees at the center of the object, how should I do it?

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  • How to change the view angle and label value of a chart .NET C#

    - by George
    Short Description I am using charts for a specific application where i need to change the view angle of the rendered 3D Pie chart and value of automatic labels from pie label names to corresponding pie values. This how the chart looks: Initialization This is how i initialize it: Dictionary<string, decimal> secondPersonsWithValues = HistoryModel.getSecondPersonWithValues(); decimal[] yValues = new decimal[secondPersonsWithValues.Values.Count]; //VALUES string[] xValues = new string[secondPersonsWithValues.Keys.Count]; //LABELS secondPersonsWithValues.Keys.CopyTo(xValues, 0); secondPersonsWithValues.Values.CopyTo(yValues, 0); incomeExpenseChart.Series["Default"].ChartType = System.Windows.Forms.DataVisualization.Charting.SeriesChartType.Pie; incomeExpenseChart.Series["Default"].Points.DataBindXY(xValues, yValues); incomeExpenseChart.ChartAreas["Default"].Area3DStyle.Enable3D = true; incomeExpenseChart.Series["Default"].CustomProperties = "PieLabelStyle=Outside"; incomeExpenseChart.Legends["Default"].Enabled = true; incomeExpenseChart.ChartAreas["Default"].Area3DStyle.LightStyle = System.Windows.Forms.DataVisualization.Charting.LightStyle.Realistic; incomeExpenseChart.Series["Default"]["PieDrawingStyle"] = "SoftEdge"; Basically i am querying data from database using the HistoryModel.getSecondPersonWithValues(); to get pairs as Dictionary<string, decimal> where key is the person and value is ammount. Problem #1 What i need is to be able to change the marked labels from person names to the ammounts or add another label of ammounts with the same colors (See Image). Problem #2 Another problem is that i need to change the view angle of 3D Pie chart. Maybe it's very simple and I just don't know the needed property or maybe i need to override some paint event. Either ways any kind of ways would be appriciated. Thanks in advance George.

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  • Finding the angle of a fleeing dodo.

    - by donthackmyacc
    I'm coding some critter AI for a game i am working on for my Unity 3D project. I have no programming background and have been stumbling through this using tutorials and other peoples scripts. My problem is that i want my critter to run directly away from the player when the player kicks it. I need the dodo to run directly away from the player when kicked, and i dont know the math nor the syntax to calculate that angle. They are two characters moving independently through worldspace. Here is what i got so far: waypoint = (fleeWP.transform.position); transform.LookAt(Vector3(waypoint.x, transform.position.y, waypoint.z)); transform.Translate (Vector3.forward * speed * Time.deltaTime); This currently makes the critter move towards the waypoint, rather than away. I might be attacking this all wrong. Please chastise me.

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  • determine collision angle on a rotating body

    - by jorb
    update: new diagram and updated description I have a contact listener set up to try and determine the side that a collision happened at relative to the a bodies rotation. One way to solve this is to find the value of the yellow angle between the red and blue vectors drawn above. The angle can be found by taking the arc cosine of the dot product of the two vectors (Evan pointed this out). One of my points of confusion is the difference in domain of the atan2 function html canvas coordinates and the Box2d rotation information. I know I have to account for this somehow... SS below questions: Does Box2D provide these angles more directly in the collision information? Am I even on the right track? If so, any hints? I have the following javascript so far: Ship.prototype.onCollide = function (other_ent,cx,cy) { var pos = this.body.GetPosition(); //collision position relative to body var d_cx = pos.x - cx; var d_cy = pos.y - cy; //length of initial vector var len = Math.sqrt(Math.pow(pos.x -cx,2) + Math.pow(pos.y-cy,2)); //body angle - can over rotate hence mod 2*Pi var ang = this.body.GetAngle() % (Math.PI * 2); //vector representing body's angle - same magnitude as the first var b_vx = len * Math.cos(ang); var b_vy = len * Math.sin(ang); //dot product of the two vectors var dot_prod = d_cx * b_vx + d_cy * b_vy; //new calculation of difference in angle - NOT WORKING! var d_ang = Math.acos(dot_prod); var side; if (Math.abs(d_ang) < Math.PI/2 ) side = "front"; else side = "back"; console.log("length",len); console.log("pos:",pos.x,pos.y); console.log("offs:",d_cx,d_cy); console.log("body vec",b_vx,b_vy); console.log("body angle:",ang); console.log("dot product",dot_prod); console.log("result:",d_ang); console.log("side",side); console.log("------------------------"); }

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  • How to adjust the shooting angle of an object

    - by Blue
    I've been trying to add an angle adjustment feature to a power bar that I got from unity3dStudents. But I can't seem to get the code right. I'm using addforce to rigidbody, it works but the power is too great. I also found that rotating the object it's shooting from changes the angle. But I don't know how to proceed from that. Can somebody show me the problem with the script below, as in how to add height to the addforce without it going to far up or to the side? Or how to change the angle of the object? var theAngle : int; var maxAngle : int = 130; var minAngle : int = 0; var angleIncreasing : boolean = false; var angleDecreasing : boolean = false; var rotationSpeed : float = 10; var ball : Rigidbody; var spawnPos : Transform; var shotForce : float = 25; function Update () { if(Input.GetKeyDown("k")){ angleIncreasing = true; angleDecreasing = false; } if(Input.GetKeyUp("k")){ angleIncreasing = false; } if(Input.GetKeyDown("l")){ angleIncreasing = false; angleDecreasing = true; } if(Input.GetKeyUp("l")){ angleDecreasing = false; } ------- if(angleIncreasing){ theAngle += Time.deltaTime * rotationSpeed; if(theAngle > maxAngle){ theAngle = maxAngle; } } if(angleDecreasing){ theAngle -= Time.deltaTime * rotationSpeed; if(theAngle < minAngle){ theAngle = minAngle; } } } function Shoot(power : float, angle : int){ ---- var forward : Vector3 = spawnPos.forward; var upward : Vector3 = spawnPos.up; pFab.AddForce(forward * power * shotForce); pFab.AddForce(upward * angle * 10); ---- }

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  • C# Collision test of a ship and asteriod, angle confusion

    - by Cherry
    We are trying to to do a collision detection for the ship and asteroid. If success than it should detect the collision before N turns. However it is confused between angle 350 and 15 and it is not really working. Sometimes it is moving but sometime it is not moving at all. On the other hand, it is not shooting at the right time as well. I just want to ask how to make the collision detection working??? And how to solve the angle confusion problem? // Get velocities of asteroid Console.WriteLine("lol"); // IF equation is between -2 and -3 if (equation1a <= -2) { // Calculate no. turns till asteroid hits float turns_till_hit = dx / vx; // Calculate angle of asteroid float asteroid_angle_rad = (float)Math.Atan(Math.Abs(dy / dx)); float asteroid_angle_deg = (float)(asteroid_angle_rad * 180 / Math.PI); float asteroid_angle = 0; // Calculate angle if asteroid is in certain positions if (asteroid.Y > ship.Y && asteroid.X > ship.X) { asteroid_angle = asteroid_angle_deg; } else if (asteroid.Y < ship.Y && asteroid.X > ship.X) { asteroid_angle = (360 - asteroid_angle_deg); } else if (asteroid.Y < ship.Y && asteroid.X < ship.X) { asteroid_angle = (180 + asteroid_angle_deg); } else if (asteroid.Y > ship.Y && asteroid.X < ship.X) { asteroid_angle = (180 - asteroid_angle_deg); } // IF turns till asteroid hits are less than 35 if (turns_till_hit < 50) { float angle_between = 0; // Calculate angle between if asteroid is in certain positions if (asteroid.Y > ship.Y && asteroid.X > ship.X) { angle_between = ship_angle - asteroid_angle; } else if (asteroid.Y < ship.Y && asteroid.X > ship.X) { angle_between = (360 - Math.Abs(ship_angle - asteroid_angle)); } else if (asteroid.Y < ship.Y && asteroid.X < ship.X) { angle_between = ship_angle - asteroid_angle; } else if (asteroid.Y > ship.Y && asteroid.X < ship.X) { angle_between = ship_angle - asteroid_angle; } // If angle less than 0, add 360 if (angle_between < 0) { //angle_between %= 360; angle_between = Math.Abs(angle_between); } // Calculate no. of turns to face asteroid float turns_to_face = angle_between / 25; if (turns_to_face < turns_till_hit) { float ship_angle_left = ShipAngle(ship_angle, "leftKey", 1); float ship_angle_right = ShipAngle(ship_angle, "rightKey", 1); float angle_between_left = Math.Abs(ship_angle_left - asteroid_angle); float angle_between_right = Math.Abs(ship_angle_right - asteroid_angle); if (angle_between_left < angle_between_right) { leftKey = true; } else if (angle_between_right < angle_between_left) { rightKey = true; } } if (angle_between > 0 && angle_between < 25) { spaceKey = true; } } }

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  • Find the new coordinates using a starting point, a distance, and an angle

    - by dqhendricks
    Okay, say I have a point coordinate. var coordinate = { x: 10, y: 20 }; Now I also have a distance and an angle. var distance = 20; var angle = 72; The problem I am trying to solve is, if I want to travel 20 points in the direction of angle from the starting coordinate, how can I find what my new coordinates will be? I know the answer involves things like sin/cosin, because I used to know how to do this, but I have since forgotten the formula. Can anyone help?

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  • ANGLE wined3d in reverse

    <b>Wine-Reviews:</b> "Were happy to announce a new open source project called Almost Native Graphics Layer Engine, or ANGLE for short. The goal of ANGLE is to layer WebGLs subset of the OpenGL ES 2.0 API over DirectX 9.0c API calls."

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  • Calculating angle a segment forms with a ray

    - by kr1zz
    I am given a point C and a ray r starting there. I know the coordinates (xc, yc) of the point C and the angle theta the ray r forms with the horizontal, theta in (-pi, pi]. I am also given another point P of which I know the coordinates (xp, yp): how do I calculate the angle alpha that the segment CP forms with the ray r, alpha in (-pi, pi]? Some examples follow: I can use the the atan2 function.

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  • (Libgdx) Move Vector2 along angle?

    - by gemurdock
    I have seen several answers on here about moving along angle, but I can't seem to get this to work properly for me and I am new to LibGDX... just trying to learn. These are my Vector2's that I am using for this function. public Vector2 position = new Vector2(); public Vector2 velocity = new Vector2(); public Vector2 movement = new Vector2(); public Vector2 direction = new Vector2(); Here is the function that I use to move the position vector along an angle. setLocation() just sets the new location of the image. public void move(float delta, float degrees) { position.set(image.getX() + image.getWidth() / 2, image.getY() + image.getHeight() / 2); direction.set((float) Math.cos(degrees), (float) Math.sin(degrees)).nor(); velocity.set(direction).scl(speed); movement.set(velocity).scl(delta); position.add(movement); setLocation(position.x, position.y); // Sets location of image } I get a lot of different angles with this, just not the correct angles. How should I change this function to move a Vector2 along an angle using the Vector2 class from com.badlogic.gdx.math.Vector2 within the LibGDX library? I found this answer, but not sure how to implement it. Update: I figured out part of the issue. Should convert degrees to radians. However, the angle of 0 degrees is towards the right. Is there any way to fix this? As I shouldn't have to add 90 to degrees in order to have correct heading. New code is below public void move(float delta, float degrees) { degrees += 90; // Set degrees to correct heading, shouldn't have to do this position.set(image.getX() + image.getWidth() / 2, image.getY() + image.getHeight() / 2); direction.set(MathUtils.cos(degrees * MathUtils.degreesToRadians), MathUtils.sin(degrees * MathUtils.degreesToRadians)).nor(); velocity.set(direction).scl(speed); movement.set(velocity).scl(delta); position.add(movement); setLocation(position.x, position.y); }

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  • Stop a rotating object at a specified angle?

    - by Krummelz
    I'm working in JavaScript with HTML5 and the canvas. I have an object which is rotating at a certain speed, and I need the object's rotation to slow down gradually and the front of the object to stop at a specified angle. (I'm using radians, not degrees.) I have a variable to keep track of the angle which the object is facing, as it rotates. How would I go about getting the object to come to rest, facing the direction I want it to?

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  • How do you calculate the reflex angle given to vectors in 3D space?

    - by Reimund
    I want to calculate the angle between two vectors a and b. Lets assume these are at the origin. This can be done with theta = arccos(a . b / |a| * |b|) However arccos gives you the angle in [0, pi], i.e. it will never give you an angle greater than 180 degrees, which is what I want. So how do you find out when the vectors have gone past the 180 degree mark? In 2D I would simply let the sign of the y-component on one of the vectors determine what quadrant the vector is in. But what is the easiest way to do it in 3D?

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  • Surface normal to screen angle

    - by Tannz0rz
    I've been struggling to get this working. I simply wish to take a surface normal and convert it to a screen angle. As an example, assuming we're working with the highlighted surface on the sphere below, where the arrow is the normal, the 2D angle would obviously be PI/4 radians. Here's one of the many things I've tried to no avail: float4 A = v.vertex; float4 B = v.vertex + float4(v.normal, 0.0); A = mul(VP, A); B = mul(VP, B); A.xy = (0.5 * (A.xy / A.w)) + 0.5; B.xy = (0.5 * (B.xy / B.w)) + 0.5; o.theta = atan2(B.y - A.y, B.x - A.x); I'm finally at my wit's end. Thanks for any and all help.

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  • Find angle for projectile to meet target in parabolic arc

    - by TheBroodian
    I'm making a thing that launches projectiles in 2D. Its projectiles are fired with a set initial velocity, and are only affected by gravity. Assuming that its target is within range, and that there aren't any obstacles, how would my thing find the appropriate angle at which to launch its projectile (in radians)? The equation for this is found here: Wikipedia: Angle Required to Hit Coordinate Sadly, I'm not a physicist (a.k.a. can't read smart people math) and am having a hard time reading its breakdown. If not only for the sake of anybody else that might read this other than myself, would anybody be kind enough to break the equation down into baby words please?

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  • Rotation angle based on touch move

    - by Siddharth
    I want to rotate my stick based on the movement of the touch on the screen. From my calculation I did not able to find correct angle in degree. So please provide guidance, my code snippet for that are below. if (pSceneTouchEvent.isActionMove()) { pValueX = pSceneTouchEvent.getX(); pValueY = CAMERA_HEIGHT - pSceneTouchEvent.getY(); rotationAngle = (float) Math.atan2(pValueX, pValueY); stick.setRotation((float) MathUtils.radToDeg(rotationAngle)); }

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  • Java :moving ball with angle ?

    - by Meko
    Hi all.I am started to learn game physics and I am trying to move ball with an angle.But it does not change its angle .Java coordinate sydstem is a little different and i think my problem is there.Here my codes this is for calculating x and y speed scale_X= Math.sin(angle); scale_Y=Math.cos(angle); velosity_X=(speed*scale_X); velosity_Y=(speed*scale_Y); This is for moving ball in run() function ball.posX =ball.posX+(int)velosity_X; ball.posY=ball.posY+(int)velosity_Y; I used (int)velosity_X and (int)velosity_Y because in ball class I draw object g.drawOval(posX, posX, width, height); and here g.drawOval requares int.I dont know is it problem or not. Also if I use angle 30 it goes +X and +Y but if I use angle 35 it goes -X and -Y. I didnot figure out how work coordinate system on java.

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  • Ease Rotate RigidBody2D toward arbitrary angle

    - by Plastic Sturgeon
    I'm trying to make a rigidbody2D circle return to an orientation after a collision. But there is a weird behavior I do not expect - it always orients to the same direction. This is what I call in FixedUpdate(): rotationdifference = -halfPI + rigidbody2D.rotation; rigidbody2D.AddTorque (rotationdifference * ease); I would expect this would rotate 90 degrees (1/2 Pi Radians) off of the neutral axis. But it does not. In fact it performs exactly the same as: rotationdifference = rigidbody2D.rotation; rigidbody2D.AddTorque (rotationdifference * ease); What is going on? How would I be able to set an angle I want it to ease towards, and then have it ease towards it when its not colliding with some other force?

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  • Bridge made out of blocks at an angle

    - by Pozzuh
    I'm having a bit of trouble with the math behind my project. I want the player to be able to select 2 points (vectors). With these 2 points a floor should be created. When these points are parallel to the x-axis it's easy, just calculate the amount of blocks needed by a simple division, loop through that amount (in x and y) and keep increasing the coordinate by the size of that block. The trouble starts when the 2 vectors aren't parallel to an axis, for example at an angle of 45 degrees. How do I handle the math behind this? If I wasn't completely clear, I made this awesome drawing in paint to demonstrate what I want to achieve. The 2 red dots would be the player selected locations. (The blocks indeed aren't square.) http://i.imgur.com/pzhFMEs.png.

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  • Calculating angle between 2 vectors

    - by Error 454
    I am working on some movement AI where there are no obstacles and movement is restricted to the XY plane. I am calculating 2 vectors: v - the direction of ship 1 w - the vector pointing from the position of ship 1 to ship 2 I am then calculating the angle between these two vectors using the standard formula: arccos( v . w / ( |v| |w| ) ) The problem I'm having is the nature of arccos only returning values between 0 and 180. This makes it impossible to determine whether I should turn left or right to face the other ship. Is there a better way to do this?

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