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• OPN Diamond Level Criteria Update

  - by Cinzia Mascanzoni

  On June 1, 2013, the criteria for Oracle PartnerNetwork members to attain the prestigious Diamond level will change and all members at the Diamond level at that point will be required to meet the new criteria. This change underscores the requirement for these elite partners to engage across Oracle’s broad product portfolio. Refer to the Diamond Level Requirements on the OPN Portal here for more detail.

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• Detect if square in grid is within a diamond shape

  - by myrkos

  So I have a game in which basically everything is a square inside a big grid. It's easy to check if a square is inside a box whose center is another square: *** x *o* --> x is not in o's square *** **x *o* --> x IS in o's square *** This can be done by simply subtracting the coordinates of o and x, then taking the largest coordinate of that and comparing it with the half side length. Now I want to do the same thing but check if x is in o's diamond, like so: * **x **o** --> x IS in o's diamond *** * What would be the best way to check if a square is in another square's surrounding diamond-shaped area, given the diamond's half width/height?

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• Why is there ambiguity in this diamond pattern?

  - by cambr

  #include <iostream> using namespace std; class A { public: void eat(){ cout<<"A";} }; class B: public A { public: void eat(){ cout<<"B";} }; class C: public A { public: void eat(){ cout<<"C";} }; class D: public B,C { public: void eat(){ cout<<"D";} }; int main(){ A *a = new D(); a->eat(); } I am not sure this is called diamond problem or not, but why doesn't this work? When I said, a->eat() (remember eat() is not virtual), there is only one possible eat() to call, that of A. Why then, do I get this error: 'A' is an ambiguous base of 'D'

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• How does virtual inheritance solve the diamond problem?

  - by cambr

  class A { public: void eat(){ cout<<"A";} }; class B: virtual public A { public: void eat(){ cout<<"B";} }; class C: virtual public A { public: void eat(){ cout<<"C";} }; class D: public B,C { public: void eat(){ cout<<"D";} }; int main(){ A *a = new D(); a->eat(); } I understand the diamond problem, and above piece of code does not have that problem. How exatly does virtual inheritance solve the problem? What I understand: When I say A *a = new D();, the compiler wants to know if an object of type D can be assigned to a pointer of type A, but it has two paths that it can follow, but cannot decide by itself. So, how does virtual inheritance resolve the issue (help compiler take the decision)?

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• Control diamond square algorithm to generate islands/pangea.

  - by Gabriel A. Zorrilla

  I generated a height map with the diamond square algorithm. The thing is i do not manage to create islands, this is, restrict the height other than water level range to a certain value in the center of the map. I manualy seeded a circle in the middle of the map but the rest of the map still receives heights over the water level. I dont fully understand the Perlin noise algorithm so i'd like to work with my current implementation of the diamond square algorithm which took me 3 days to interpret and code in PHP. :P

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• Diamond-square terrain generation problem

  - by kafka

  I've implemented a diamond-square algorithm according to this article: http://www.lighthouse3d.com/opengl/terrain/index.php?mpd2 The problem is that I get these steep cliffs all over the map. It happens on the edges, when the terrain is recursively subdivided: Here is the source: void DiamondSquare(unsigned x1,unsigned y1,unsigned x2,unsigned y2,float range) { int c1 = (int)x2 - (int)x1; int c2 = (int)y2 - (int)y1; unsigned hx = (x2 - x1)/2; unsigned hy = (y2 - y1)/2; if((c1 <= 1) || (c2 <= 1)) return; // Diamond stage float a = m_heightmap[x1][y1]; float b = m_heightmap[x2][y1]; float c = m_heightmap[x1][y2]; float d = m_heightmap[x2][y2]; float e = (a+b+c+d) / 4 + GetRnd() * range; m_heightmap[x1 + hx][y1 + hy] = e; // Square stage float f = (a + c + e + e) / 4 + GetRnd() * range; m_heightmap[x1][y1+hy] = f; float g = (a + b + e + e) / 4 + GetRnd() * range; m_heightmap[x1+hx][y1] = g; float h = (b + d + e + e) / 4 + GetRnd() * range; m_heightmap[x2][y1+hy] = h; float i = (c + d + e + e) / 4 + GetRnd() * range; m_heightmap[x1+hx][y2] = i; DiamondSquare(x1, y1, x1+hx, y1+hy, range / 2.0); // Upper left DiamondSquare(x1+hx, y1, x2, y1+hy, range / 2.0); // Upper right DiamondSquare(x1, y1+hy, x1+hx, y2, range / 2.0); // Lower left DiamondSquare(x1+hx, y1+hy, x2, y2, range / 2.0); // Lower right } Parameters: (x1,y1),(x2,y2) - coordinates that define a region on a heightmap (default (0,0)(128,128)). range - basically max. height. (default 32) Help would be greatly appreciated.

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• Moving in a diamond - enemy gets stuck

  - by Fibericon

  I have an enemy that I would like to move as follows: Start at (0, 200, 0) Move to (200, 0, 0) Move to (0, -200, 0) Move to (-200, 0, 0) Move to start point, repeat as long as it remains active. This is what I've done to achieve that: if (position.X < 200 && position.Y > 0) { Velocity = new Vector3(1, -1, 0) * speed; } else if (position.X >= 200 && position.Y <= 0 && position.Y > -200) { Velocity = new Vector3(-1, -1, 0) * speed; } else if (position.X <= 0 && position.Y <= -200) { Velocity = new Vector3(-1, 1, 0) * speed; } else { Velocity = new Vector3(1, 1, 0) * speed; } It moves to the second point, but then gets stuck and appears to vibrate in place. How should I be doing this?

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• Can the Diamond Problem be really solved?

  - by Mecki

  A typical problem in OO programming is the diamond problem. I have parent class A with two sub-classes B and C. A has an abstract method, B and C implement it. Now I have a sub-class D, that inherits of B and C. The diamond problem is now, what implementation shall D use, the one of B or the one of C? People claim Java knows no diamond problem. I can only have multiple inheritance with interfaces and since they have no implementation, I have no diamond problem. Is this really true? I don't think so. See below: [removed vehicle example] Is a diamond problem always the cause of bad class design and something neither programmer nor compiler needs to solve, because it shouldn't exist in the first place? Update: Maybe my example was poorly chosen. See this image Of course you can make Person virtual in C++ and thus you will only have one instance of person in memory, but the real problem persists IMHO. How would you implement getDepartment() for GradTeachingFellow? Consider, he might be student in one department and teach in another one. So you can either return one department or the other one; there is no perfect solution to the problem and the fact that no implementation might be inherited (e.g. Student and Teacher could both be interfaces) doesn't seem to solve the problem to me.

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• Code Golf: Diamond Pattern

  - by LiraNuna

  The challenge The shortest code by character count to output a a pattern of diamonds according to the input. The input is composed of 3 positive numbers representing the size of the diamond and the size of the grid. A diamond is made from the ASCII characters / and \ with spaces. A diamond of size 1 is: /\ \/ The size of the grid consists from width and height of number of diamonds. Test cases Input: 1 6 2 Output: /\/\/\/\/\/\ \/\/\/\/\/\/ /\/\/\/\/\/\ \/\/\/\/\/\/ Input: 2 2 2 Output: /\ /\ / \/ \ \ /\ / \/ \/ /\ /\ / \/ \ \ /\ / \/ \/ Input 4 1 3 Output: /\ /\ /\ / \ / \ / \ / \ / \ / \ / \/ \/ \ \ /\ /\ / \ / \ / \ / \ / \ / \ / \/ \/ \/ Code count includes input/output (i.e full program).

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• Driver issue for 7850 HD Diamond Windows 7

  - by Mr.Student

  I have an issue with windows 7 implementing the drivers ati provides for my 7850 HD Diamond video card. The video card is plugged in correctly to the PCIE 2.0 slots of my motherboard (p6t asus) with more then enough power. Fortunately the card works as I have my monitor plugged into the card itself and I can see just fine. However windows 7 does not replace the standard vga default microsoft driver with catalyst drivers that I've tried installing from online as well as the CD. Every time I install the drivers using Catalyst Install manager it always finishes with "Install complete(Warnings occured)". I then see the warnings it has which it instead reports that it successfully installed the SDK, Catalyst Install Manager, and HDMI/AUDIO packages. When I check my device manager after that, the display adapter still shows as standard vga and that its still using microsoft default display adapter. Now this current card is replacing an old card of mine which is the ATI 4890 HD which works beautifully. In fact for the old card to work, all I need to do is go to device manager and right click on standard vga - click update driver and windows 7 magically finds the correct driver to install and everything is good. Not so with the new card. I've even went into my regedits and uninstalled every bit of ati driver software before reinstalling my new card. Nothing's worked thus far. I've already exchanged my card out once and talked to customer support from my motherboard, microsoft, and ati all blaming the other. Please help me out!!

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• HTC Diamond Touch sync problem

  - by Anders

  I have a HTC Diamond Touch with all my contacts etc. on it. Did however not use it for 6mo while being abroad. When I start the phone now I realize that the touch screen has stopped working. I have tried restarting, soft resetting, shutting it off etc but the touch just wont follow commands. However, I can manage the phone by buttons so it's not frozen. Hence I can get into the phone and watch contacts but not use it to call etc. The problem is, how do I get my 300 contacts out of the thing!? When I'm plugging in the phone, it lets me choose between "Sync with Outlook" and "Use as storage device". It automatically selects "Use as storage device". Now, I cannot choose to sync it with the buttons. I can not change this option afterwards either. In short, I have a phone with all of my contact data and am completely unable to get that out of it. Any tips/help/suggestions? If possible, preferably one that does not including sending the phone to a hardware workshop for three weeks in order to get it fixed:)

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• Why am I getting a closed filehandle error when using the diamond operator in list context in Perl?

  - by gvkv

  This code: foreach my $file (@data_files) { open my $fh, ',', $file || croak "Could not open file $file!\n"; my @records = <$fh>; close $fh; .... } produces this error: readline() on closed filehandle $fh at nut_init_insert.pl line 29. and I have no idea why.

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• A Big Congrats to Hitachi- Now a Diamond Level Partner!

  - by Kristin Rose

  Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} We’ve said this before and we’ll say it again, nothing sparkles quite like a diamond. Being named Diamond level partner is the highest ranking available in the Oracle PartnerNetwork Specialized program, and we could not be more excited to congratulate Hitachi, Ltd on their new glistening title! Hitachi has helped clients maximize the business benefits of their Oracle Applications for more than two decades, while also helping them bring their business visions to life through industry led services and solutions. Not only has Hitachi achieved Diamond level status, they also have 29 additional Oracle Specializations! Here at OPN we know that it all starts with equipping our partners with the proper tools to help their end customers succeed, and we truly believe that diamonds partners are forever! So here’s to you Hitachi, our diamond in the ruff! Shine On, The OPN Communications Team

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• Diamond square algorithm.

  - by Gabriel A. Zorrilla

  I'm trying to write the Diamond-Square algorithm in Java to generate a random map but can't figure out the implementation... Anyone with some Java code (or other language) so i can check how the loop is made would be greatly appreciated! Thanks!

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• Can we move shape (Diamond) in C#

  - by Ani

  I want to move a Diamond Shape in the form(for example 2 pixels every 200ms) horizantally. I used the following code in From_Paint Event. private void Form1_Paint(object sender, PaintEventArgs e) { Graphics g = e.Graphics; Point p1 = new Point(5,0); Point p2 = new Point(10, 5); Point p3 = new Point(5, 10); Point p4 = new Point(0, 5); Point[] ps = { p1, p2, p3, p4, p1 }; g.DrawLines(Pens.Black, ps);} I know how to move a picturebox but how to do with shape. Thanks, Ani

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• Diamond problem in C++

  - by Jack

  I know the diamond problem. I am using gcc compiler. I have some scenarios I need explanation about. 1) class A{ public: virtual void eat(){cout<<"A eat\n";} }; class B:public A{ public: void eat(){ cout<<"B eat\n";}}; class C:public A{ public: void eat(){ cout<<"C eat\n";}}; class D:public B,C{ public: void eat(){ cout<<"D eat\n";}}; int main() { A * a = new D(); a->eat(); getch(); return 0; } Why doesn't this work? 2) class A{ public: void eat(){cout<<"A eat\n";} }; class B:virtual public A{ public: void eat(){ cout<<"B eat\n";}}; class C:virtual public A{ public: void eat(){ cout<<"C eat\n";}}; class D: public B,C{ public: void eat(){ cout<<"D eat\n";}}; int main() { A * a = new D(); a->eat(); getch(); return 0; } When I do this what happens in the background. How does the ambiguity get removed. Is the concept of vtables involved here?

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• C#- move a shape to a point which is half way from the top of the form

  - by hello-all

  Hello all, Here I have to create a diamond using drawlines method and make it move horizontally along a path that is half way from the top of the form. I created a diamond and it is moving horizontally, but i want it to start moving from a position which is half way from the top of the form. This is the code to create a diamond, private void Form1_Paint(object sender, PaintEventArgs e) { Graphics g = e.Graphics; Point p1 = new Point(5+x, 0); Point p2 = new Point(10+x, 5); Point p3 = new Point(5+x, 10); Point p4 = new Point(0+x, 5); Point[] ps = { p1, p2, p3, p4, p1 }; Pen p_yellow = new Pen(Color.Yellow, 5); g.DrawLines(p_yellow, ps); this.BackColor = System.Drawing.Color.DarkBlue; } I can make it move using the timer and following is the code, private void timer1_Tick(object sender, EventArgs e) { if (x < 500) x += 2; else timer1.Enabled = false; this.Invalidate(); } please tell me how to bring the diamond to a point which is half way from the top of the form?

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• Boost.Python wrapping hierarchies avoiding diamond inheritance

  - by stbuton

  I'm having some trouble seeing what the best way to wrap a series of classes with Boost.Python while avoiding messy inheritance problems. Say I have the classes A, B, and C with the following structure: struct A { virtual void foo(); virtual void bar(); virtual void baz(); }; struct B : public A { virtual void quux(); }; struct C : public A { virtual void foobar(); }; I want to wrap all classes A, B, and C such that they are extendable from Python. The normal method for accomplishing this would be along the lines of: struct A_Wrapper : public A, boost::python::wrapper<A> { //dispatch logic for virtual functions }; Now for classes B and C which extend from A I would like to be able to inherit and share the wrapping implementation for A. So I'd like to be able to do something along the lines of: struct B_Wrapper : public B, public A_Wrapper, public boost::python::wrapper<B> { //dispatch logic specific for B }; struct C_Wrapper : public C, public A_Wrapper, public boost::python::wrapper<C> { //dispatch logic specific for C } However, it seems like that would introduce all manner of nastiness with the double inheritance of the boost wrapper base and the double inheritance of A in the B_Wrapper and C_Wrapper objects. Is there a common way that this instance is solved that I'm missing? thanks.

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• Dynamic programming: Largest diamond(rhombus) block

  - by Darksody

  I have a small program to do in Java. I have a 2D array filled with 0 and 1, and I must find the largest rhombus (as in square rotated by 90 degrees) and their numbers. Example: 0 1 0 0 0 1 1 0 1 1 1 0 1 0 1 1 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1 1 1 1 1 1 Result: 1 1 1 1 1 1 1 1 1 1 1 1 1 The problem is similar to this SO question. If you have any idea, post it here.

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• Dynamic programming: Find largest diamond (rhombus)

  - by Darksody

  I have a small program to do in Java. I have a 2D array filled with 0 and 1, and I must find the largest rhombus (as in square rotated by 90 degrees) and their numbers. Example: 0 1 0 0 0 1 1 0 1 1 1 0 1 0 1 1 1 1 0 1 1 1 1 1 0 0 1 1 1 1 1 1 1 1 1 1 Result: 1 1 1 1 1 1 1 1 1 1 1 1 1 The problem is similar to this SO question. If you have any idea, post it here.

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• How to shortcut diamond character in vim

  - by temujin.ya.ru

  In the dictionary file, which I am editing I often need to insert character "?" on place of <. Is there a way to map "?" to some key so that I press "r" for replace and then my_shortcut to have < replaced by "?"? I found a way to make imap mapping in .vimrc: :imap <> ? But changing to inset mode is sub-optimal, would that be possible to make it all in replace mode and what should I write in .vimrc for that?

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• How can I direct edge to get out of the diamond on the right?

  - by Didier Trosset

  I have a simple dot diagram to show how to perform tests. PerformTests; PerformTests<---+ PerformTests -> TestsPassed; | | TestsPassed [shape="diamond"]; v | TestsPassed -> Release [label="Yes"]; TestsPassed | TestsPassed -> FixErrors [label="No"]; Y| N\ | FixErrors -> PerformTests; v FixErrors Release The diagram shows square boxes for all nodes, except TestPassed that has a diamond shape. My issue is here. I'd like the edge that goes outside of the diamond for No to be getting out of the diamond at the right (east) instead of oblique down-right (south-east). What I have What I want ^ ^ / \ / \ < > < >---> \ /\ \ / v \ v I've seen such compass_pt in the dot grammar, but cannot figure out how to use it. I what I want possible, and how to do it?

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• What is the ambiguity in this piece of code?

  - by cambr

  #include <iostream> using namespace std; class A { public: void eat(){ cout<<"A";} }; class B: public A { public: void eat(){ cout<<"B";} }; class C: public A { public: void eat(){ cout<<"C";} }; class D: public B,C { public: void eat(){ cout<<"D";} }; int main(){ A *a = new D(); a->eat(); } I am not sure this is called diamond problem or not, but why doesn't this work? When I said, a->eat() (remember eat() is not virtual), there is only one possible eat() to call, that of A. Why then, do I get this error: 'A' is an ambiguous base of 'D'

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• Any good utilities to manage an old Diamond Rio 500 on a Mac?

  - by robot

  Gave my son an old Rio 500, and I'd like him to be able to manage the songs on it with his Mac. Any utilities to do that?

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• Bind can only work for the DNS server inside zone

  - by Bob

  I got a big problem when I added a new zone to my current Bind configuration. ===============/etc/named.conf=============== include "/etc/rndc.key"; controls { inet 127.0.0.1 port 953 allow { 127.0.0.1; } keys { "rndckey"; }; }; acl "trusted" { 127.0.0.1; 208.43.81.157; 69.4.236.88; }; options { directory "/var/named"; allow-query { any; }; recursion yes; allow-recursion { trusted; }; }; zone "." { type hint; file "root.hints"; }; zone "2comu.com" { type master; file "2comu.com.db"; allow-update { none; }; }; zone "usa-diamond.com" { type master; file "usa-diamond.com.db"; allow-update { none; }; }; ===============/var/named/2comu.com.db=============== $TTL 86400 @ IN SOA ns1.2comu.com. root.2comu.com. ( 2011011101 3600 300 3600000 3600 ) IN NS ns1.2comu.com. IN NS ns2.2comu.com. IN MX 10 email.2comu.com. ns1.2comu.com. IN A 208.43.81.157 ns2.2comu.com. IN A 69.4.236.88 www.2comu.com. IN A 208.43.81.157 ftp.2comu.com. IN A 208.43.81.157 email.2comu.com. IN A 208.43.81.157 ===============/var/named/usa-diamond.com=============== $TTL 86400 @ IN SOA ns1.2comu.com. root.usa-diamond.com. ( 2011011115 3600 300 3600000 3600 ) IN NS ns1.2comu.com. IN NS ns2.2comu.com. www.usa-diamond.com. IN A 208.43.81.157 ================================================================ All of the configurations inside domain 2comu.com work well. But when www.usa-diamond.com doesn't work at all. When I tried "dig +trace www.usa-diamond.com", I got the following message ================================================================ ; <<>> DiG 9.3.6-P1-RedHat-9.3.6-4.P1.el5_4.2 <<>> +trace usa-diamond.com ;; global options: printcmd . 517603 IN NS c.root-servers.net. . 517603 IN NS d.root-servers.net. . 517603 IN NS e.root-servers.net. . 517603 IN NS f.root-servers.net. . 517603 IN NS g.root-servers.net. . 517603 IN NS h.root-servers.net. . 517603 IN NS i.root-servers.net. . 517603 IN NS j.root-servers.net. . 517603 IN NS k.root-servers.net. . 517603 IN NS l.root-servers.net. . 517603 IN NS m.root-servers.net. . 517603 IN NS a.root-servers.net. . 517603 IN NS b.root-servers.net. ;; Received 500 bytes from 208.43.81.157#53(208.43.81.157) in 0 ms com. 172800 IN NS j.gtld-servers.net. com. 172800 IN NS d.gtld-servers.net. com. 172800 IN NS e.gtld-servers.net. com. 172800 IN NS i.gtld-servers.net. com. 172800 IN NS f.gtld-servers.net. com. 172800 IN NS m.gtld-servers.net. com. 172800 IN NS b.gtld-servers.net. com. 172800 IN NS k.gtld-servers.net. com. 172800 IN NS l.gtld-servers.net. com. 172800 IN NS c.gtld-servers.net. com. 172800 IN NS h.gtld-servers.net. com. 172800 IN NS a.gtld-servers.net. com. 172800 IN NS g.gtld-servers.net. ;; Received 505 bytes from 192.33.4.12#53(c.root-servers.net) in 3 ms usa-diamond.com. 172800 IN NS ns1.2comu.com. usa-diamond.com. 172800 IN NS ns2.2comu.com. ;; Received 107 bytes from 192.48.79.30#53(j.gtld-servers.net) in 177 ms ;; Received 33 bytes from 208.43.81.157#53(ns1.2comu.com) in 0 ms ========================================================================= It seems I can't get any answer from ns1.2comu.com. Can anyone give some suggestions? Thanks a lot. Bob

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