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  • How to crete a Java Iterator that throws IOException

    - by Antonio
    I'd like to implement an iterator that retrieves objects from disk/network. Iterator itr = getRemoteIterator(); while(itr.hasNext()) { Object element = itr.next(); System.out.print(element + " "); } However the problem is that hasNext() and next() methods of the Iterator object does not allow to throw IOException. Is there any other standard interface work around this issue? Desired code is: public interface RemoteIterator<E> { boolean hasNext() throws IOException; E next() throws IOException; void remove(); }

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  • Does close ever throw an IOException?

    - by TofuBeer
    After providing some answers here, and reading some comments, it would seem that, in practice IOException is never thrown on close for file I/O. Are there any cases in which calling close on a Stream/Reader/Writer actually throws an IOException? If an exception is actually thrown, how should it be dealt with?

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  • Android: Nexus One - Geocoder causes IOException - works perfectly with other devices and emulator

    - by Stefan Klumpp
    The code below works perfectly for real devices running on 1.5, 1.6 and 2.0 as well as the emulator running on 2.1. However, executing it on the Nexus One (running 2.1) raises an IOException: java.io.IOException: Unable to parse response from server at android.location.Geocoder.getFromLocation(Geocoder.java:124) That's the code snippet where it happens: Double myLatitude = AppObject.myLocation.getLatitude(); Double myLongitude = AppObject.myLocation.getLongitude(); DEBUG.i(TAG, "My location: " + myLatitude + " | " + myLongitude); Geocoder geocoder = new Geocoder(MainActivity.this); java.util.List<Address> addressList; try { addressList = geocoder.getFromLocation(myLatitude, myLongitude, 5); if(addressList!=null && addressList.size()>0) { currentAddress = new String(); DEBUG.i(TAG,addressList.get(0).toString()); currentAddress = addressList.get(0).getAddressLine(0) + ", " + addressList.get(0).getAddressLine(1) + ", " + addressList.get(0).getAddressLine(2); } return true; } catch (IOException e) { e.printStackTrace(); return false; }

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  • C# StreamReader.EndOfStream produces IOException

    - by Ziplin
    I'm working on an application that accepts TCP connections and reads in data until an </File> marker is read and then writes that data to the filesystem. I don't want to disconnect, I want to let the client sending the data to do that so they can send multiple files in one connection. I'm using the StreamReader.EndOfStream around my outter loop, but it throws an IOException when the client disconnects. Is there a better way to do this? private static void RecieveAsyncStream(IAsyncResult ar) { TcpListener listener = (TcpListener)ar.AsyncState; TcpClient client = listener.EndAcceptTcpClient(ar); // init the streams NetworkStream netStream = client.GetStream(); StreamReader streamReader = new StreamReader(netStream); StreamWriter streamWriter = new StreamWriter(netStream); while (!streamReader.EndOfStream) // throws IOException { string file= ""; while (file!= "</File>" && !streamReader.EndOfStream) { file += streamReader.ReadLine(); } // write file to filesystem } listener.BeginAcceptTcpClient(RecieveAsyncStream, listener); }

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  • StreamReader.EndOfStream produces IOException

    - by Ziplin
    I'm working on an application that accepts TCP connections and reads in data until an </File> marker is read and then writes that data to the filesystem. I don't want to disconnect, I want to let the client sending the data to do that so they can send multiple files in one connection. I'm using the StreamReader.EndOfStream around my outter loop, but it throws an IOException when the client disconnects. Is there a better way to do this? private static void RecieveAsyncStream(IAsyncResult ar) { TcpListener listener = (TcpListener)ar.AsyncState; TcpClient client = listener.EndAcceptTcpClient(ar); // init the streams NetworkStream netStream = client.GetStream(); StreamReader streamReader = new StreamReader(netStream); StreamWriter streamWriter = new StreamWriter(netStream); while (!streamReader.EndOfStream) // throws IOException { string file= ""; while (file!= "</File>" && !streamReader.EndOfStream) { file += streamReader.ReadLine(); } // write file to filesystem } listener.BeginAcceptTcpClient(RecieveAsyncStream, listener); }

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  • java ioexception error=24 too many files open

    - by MattS
    I'm writing a genetic algorithm that needs to read/write lots of files. The fitness test for the GA is invoking a program called gradif, which takes a file as input and produces a file as output. Everything is working except when I make the population size and/or the total number of generations of the genetic algorithm too large. Then, after so many generations, I start getting this: java.io.FileNotFoundException: testfiles/GradifOut29 (Too many open files). (I get it repeatedly for many different files, the index 29 was just the one that came up first last time I ran it). It's strange because I'm not getting the error after the first or second generation, but after a significant amount of generations, which would suggest that each generation opens up more files that it doesn't close. But as far as I can tell I'm closing all of the files. The way the code is set up is the main() function is in the Population class, and the Population class contains an array of Individuals. Here's my code: Initial creation of input files (they're random access so that I could reuse the same file across multiple generations) files = new RandomAccessFile[popSize]; for(int i=0; i<popSize; i++){ files[i] = new RandomAccessFile("testfiles/GradifIn"+i, "rw"); } At the end of the entire program: for(int i=0; i<individuals.length; i++){ files[i].close(); } Inside the Individual's fitness test: FileInputStream fin = new FileInputStream("testfiles/GradifIn"+index); FileOutputStream fout = new FileOutputStream("testfiles/GradifOut"+index); Process process = Runtime.getRuntime().exec ("./gradif"); OutputStream stdin = process.getOutputStream(); InputStream stdout = process.getInputStream(); Then, later.... try{ fin.close(); fout.close(); stdin.close(); stdout.close(); process.getErrorStream().close(); }catch (IOException ioe){ ioe.printStackTrace(); } Then, afterwards, I append an 'END' to the files to make parsing them easier. FileWriter writer = new FileWriter("testfiles/GradifOut"+index, true); writer.write("END"); try{ writer.close(); }catch(IOException ioe){ ioe.printStackTrace(); } My redirection of stdin and stdout for gradif are from this answer. I tried using the try{close()}catch{} syntax to see if there was a problem with closing any of the files (there wasn't), and I got that from this answer. It should also be noted that the Individuals' fitness tests run concurrently. UPDATE: I've actually been able to narrow it down to the exec() call. In my most recent run, I first ran in to trouble at generation 733 (with a population size of 100). Why are the earlier generations fine? I don't understand why, if there's no leaking, the algorithm should be able to pass earlier generations but fail on later generations. And if there is leaking, then where is it coming from? UPDATE2: In trying to figure out what's going on here, I would like to be able to see (preferably in real-time) how many files the JVM has open at any given point. Is there an easy way to do that?

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  • threaded serial port IOException when writing

    - by John McDonald
    Hi, I'm trying to write a small application that simply reads data from a socket, extracts some information (two integers) from the data and sends the extracted information off on a serial port. The idea is that it should start and just keep going. In short, it works, but not for long. After a consistently short period I start to receive IOExceptions and socket receive buffer is swamped. The thread framework has been taken from the MSDN serial port example. The delay in send(), readThread.Join(), is an effort to delay read() in order to allow serial port interrupt processing a chance to occur, but I think I've misinterpreted the join function. I either need to sync the processes more effectively or throw some data away as it comes in off the socket, which would be fine. The integer data is controlling a pan tilt unit and I'm sure four times a second would be acceptable, but not sure on how to best acheive either, any ideas would be greatly appreciated, cheers. using System; using System.Collections.Generic; using System.Text; using System.IO.Ports; using System.Threading; using System.Net; using System.Net.Sockets; using System.IO; namespace ConsoleApplication1 { class Program { static bool _continue; static SerialPort _serialPort; static Thread readThread; static Thread sendThread; static String sendString; static Socket s; static int byteCount; static Byte[] bytesReceived; // synchronise send and receive threads static bool dataReceived; const int FIONREAD = 0x4004667F; static void Main(string[] args) { dataReceived = false; readThread = new Thread(Read); sendThread = new Thread(Send); bytesReceived = new Byte[16384]; // Create a new SerialPort object with default settings. _serialPort = new SerialPort("COM4", 38400, Parity.None, 8, StopBits.One); // Set the read/write timeouts _serialPort.WriteTimeout = 500; _serialPort.Open(); string moveMode = "CV "; _serialPort.WriteLine(moveMode); s = null; IPHostEntry hostEntry = Dns.GetHostEntry("localhost"); foreach (IPAddress address in hostEntry.AddressList) { IPEndPoint ipe = new IPEndPoint(address, 10001); Socket tempSocket = new Socket(ipe.AddressFamily, SocketType.Stream, ProtocolType.Tcp); tempSocket.Connect(ipe); if (tempSocket.Connected) { s = tempSocket; s.ReceiveBufferSize = 16384; break; } else { continue; } } readThread.Start(); sendThread.Start(); while (_continue) { Thread.Sleep(10); ;// Console.WriteLine("main..."); } readThread.Join(); _serialPort.Close(); s.Close(); } public static void Read() { while (_continue) { try { //Console.WriteLine("Read"); if (!dataReceived) { byte[] outValue = BitConverter.GetBytes(0); // Check how many bytes have been received. s.IOControl(FIONREAD, null, outValue); uint bytesAvailable = BitConverter.ToUInt32(outValue, 0); if (bytesAvailable > 0) { Console.WriteLine("Read thread..." + bytesAvailable); byteCount = s.Receive(bytesReceived); string str = Encoding.ASCII.GetString(bytesReceived); //str = Encoding::UTF8->GetString( bytesReceived ); string[] split = str.Split(new Char[] { '\t', '\r', '\n' }); string filteredX = (split.GetValue(7)).ToString(); string filteredY = (split.GetValue(8)).ToString(); string[] AzSplit = filteredX.Split(new Char[] { '.' }); filteredX = (AzSplit.GetValue(0)).ToString(); string[] ElSplit = filteredY.Split(new Char[] { '.' }); filteredY = (ElSplit.GetValue(0)).ToString(); // scale values int x = (int)(Convert.ToInt32(filteredX) * 1.9); string scaledAz = x.ToString(); int y = (int)(Convert.ToInt32(filteredY) * 1.9); string scaledEl = y.ToString(); String moveAz = "PS" + scaledAz + " "; String moveEl = "TS" + scaledEl + " "; sendString = moveAz + moveEl; dataReceived = true; } } } catch (TimeoutException) {Console.WriteLine("timeout exception");} catch (NullReferenceException) {Console.WriteLine("Read NULL reference exception");} } } public static void Send() { while (_continue) { try { if (dataReceived) { // sleep Read() thread to allow serial port interrupt processing readThread.Join(100); // send command to PTU dataReceived = false; Console.WriteLine(sendString); _serialPort.WriteLine(sendString); } } catch (TimeoutException) { Console.WriteLine("Timeout exception"); } catch (IOException) { Console.WriteLine("IOException exception"); } catch (NullReferenceException) { Console.WriteLine("Send NULL reference exception"); } } } } }

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  • java.io.IOException: Invalid argument

    - by Luixv
    Hi I have a web application running in cluster mode with a load balancer. It consists in two tomcats (T1, and T2) addressing only one DB. T2 is nfs mounted to T1. This is the only dofference between both nodes. I have a java method generating some files. If the request runs on T1 there is no problem but if the request is running on node 2 I get an exception as follows: java.io.IOException: Invalid argument at java.io.FileOutputStream.close0(Native Method) at java.io.FileOutputStream.close(FileOutputStream.java:279) The corresponding code is as follows: for (int i = 0; i < dataFileList.size(); i++) { outputFileName = outputFolder + fileNameList.get(i); FileOutputStream fileOut = new FileOutputStream(outputFileName); fileOut.write(dataFileList.get(i), 0, dataFileList.get(i).length); fileOut.flush(); fileOut.close(); } The exception appears at the fileOut.close() Any hint? Luis

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  • File.Replace throwing IOException

    - by WebDevHobo
    I have an app that can make modify images. In some cases, this makes the filesize smaller, in some cases bigger. The program doesn't have an option to "not replace the file if result has a bigger filesize". So I wrote a little C# app to try and solve this. Instead of overwriting the files, I make the app write the result to a folder under the current one and name that folder Test. The C# app I wrote compares grabs the contents of both folders and puts the full path to the file(s) in two List objects. I then compare and replace. The replacing isn't working however. I get the following IOException: Unable to remove the file to be replaced The location is on an external hard-drive, on which I have full rights. Now, I know I can just do File.Delete and File.Move in that order, but this exception has gotten me interested in why this particular setup wont work. Here's the source code: http://pastebin.com/4Vq82Umu And yes, the file specified as last argument of the Replace function does exist.

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  • System.IO.IOException: file used by another process

    - by Srodriguez
    Dear all, I've been working in this small piece of code that seems trivial but still i cannot really see where is the problem. My functions does a pretty simple thing. Opens a file, copy its contents, replace a string inside and copy it back to the original file (a simple search and replace inside a text file then). I didn't really know how to do that as I'm adding lines to the original file, so i just create a copy of the file, (file.temp) copy also a backup (file.temp) then delete the original file(file) and copy the file.temp to file. I get an exception while doing the delete of the file. Here is the sample code: private static bool modifyFile(FileInfo file, string extractedMethod, string modifiedMethod) { Boolean result = false; FileStream fs = new FileStream(file.FullName + ".tmp", FileMode.Create, FileAccess.Write); StreamWriter sw = new StreamWriter(fs); StreamReader streamreader = file.OpenText(); String originalPath = file.FullName; string input = streamreader.ReadToEnd(); Console.WriteLine("input : {0}", input); String tempString = input.Replace(extractedMethod, modifiedMethod); Console.WriteLine("replaced String {0}", tempString); try { sw.Write(tempString); sw.Flush(); sw.Close(); sw.Dispose(); fs.Close(); fs.Dispose(); streamreader.Close(); streamreader.Dispose(); File.Copy(originalPath, originalPath + ".old", true); FileInfo newFile = new FileInfo(originalPath + ".tmp"); File.Delete(originalPath); File.Copy(fs., originalPath, true); result = true; } catch (Exception ex) { Console.WriteLine(ex); } return result; }` And the related exception System.IO.IOException: The process cannot access the file 'E:\mypath\myFile.cs' because it is being used by another process. at System.IO.__Error.WinIOError(Int32 errorCode, String maybeFullPath) at System.IO.File.Delete(String path) at callingMethod.modifyFile(FileInfo file, String extractedMethod, String modifiedMethod) Normally these errors come from unclosed file streams, but I've taken care of that. I guess I've forgotten an important step but cannot figure out where. Thank you very much for your help,

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  • IOException: Unable To Delete Images Due To File Lock

    - by Arslan Pervaiz
    I am Unable To Delete Image File From My Server Path It Gaves Error That The Process Cannot Access The File "FileName" Because it is being Used By Another Process. I Tried Many Methods But Still All In Vain. Please Help me Out in This Issue. Here is My Code Snippet. using System; using System.Data; using System.Web; using System.Data.SqlClient; using System.Web.UI; using System.Web.UI.HtmlControls; using System.Globalization; using System.Web.Security; using System.Text; using System.DirectoryServices; using System.Collections; using System.IO; using System.Drawing; using System.Drawing.Imaging; using System.Drawing.Drawing2D; //============ Main Block ================= byte[] data = (byte[])ds.Tables[0].Rows[0][0]; MemoryStream ms = new MemoryStream(data); Image returnImage = Image.FromStream(ms); returnImage.Save(Server.MapPath(".\\TmpImages\\SavedImage.jpg"), System.Drawing.Imaging.ImageFormat.Jpeg); returnImage.Dispose(); \\ I Tried this Dispose Method To Unlock The File But Nothing Done. ms.Close(); \\ I Tried The Memory Stream Close Method Also But Its Also Not Worked For Me. watermark(); \\ Here is My Water Mark Method That Print Water Mark Image on My Saved Image (Image That is Converted From Byte Array) DeleteImages(); \\ Here is My Delete Method That I Call To Delete The Images //===== ==== My Delete Method To Delete Files================== public void DeleteImages() { try { File.Delete(Server.MapPath(".\\TmpImages\\WaterMark.jpg")); \\This Image Deleted Fine. File.Delete(Server.MapPath(".\\TmpImages\\SavedImage.jpg")); \\ Exception Thrown On Deleting of This Image. } catch (Exception ex) { LogManager.LogException(ex, "Error in Deleting Images."); Master.ShowMessage(ex.Message, true); } } \ ==== Method Declartion That Make Watermark of One Image On Another Image.======= public void watermark() { //create a image object containing the photograph to watermark Image imgPhoto = Image.FromFile(Server.MapPath(".\\TmpImages\\SavedImage.jpg")); int phWidth = imgPhoto.Width; int phHeight = imgPhoto.Height; //create a Bitmap the Size of the original photograph Bitmap bmPhoto = new Bitmap(phWidth, phHeight, PixelFormat.Format24bppRgb); bmPhoto.SetResolution(imgPhoto.HorizontalResolution, imgPhoto.VerticalResolution); //load the Bitmap into a Graphics object Graphics grPhoto = Graphics.FromImage(bmPhoto); //create a image object containing the watermark Image imgWatermark = new Bitmap(Server.MapPath(".\\TmpImages\\PrintasWatermark.jpg")); int wmWidth = imgWatermark.Width; int wmHeight = imgWatermark.Height; //Set the rendering quality for this Graphics object grPhoto.SmoothingMode = SmoothingMode.AntiAlias; //Draws the photo Image object at original size to the graphics object. grPhoto.DrawImage( imgPhoto, // Photo Image object new Rectangle(0, 0, phWidth, phHeight), // Rectangle structure 0, // x-coordinate of the portion of the source image to draw. 0, // y-coordinate of the portion of the source image to draw. phWidth, // Width of the portion of the source image to draw. phHeight, // Height of the portion of the source image to draw. GraphicsUnit.Pixel); // Units of measure //------------------------------------------------------- //to maximize the size of the Copyright message we will //test multiple Font sizes to determine the largest posible //font we can use for the width of the Photograph //define an array of point sizes you would like to consider as possiblities //------------------------------------------------------- //Define the text layout by setting the text alignment to centered StringFormat StrFormat = new StringFormat(); StrFormat.Alignment = StringAlignment.Center; //define a Brush which is semi trasparent black (Alpha set to 153) SolidBrush semiTransBrush2 = new SolidBrush(Color.FromArgb(153, 0, 0, 0)); //define a Brush which is semi trasparent white (Alpha set to 153) SolidBrush semiTransBrush = new SolidBrush(Color.FromArgb(153, 255, 255, 255)); //------------------------------------------------------------ //Step #2 - Insert Watermark image //------------------------------------------------------------ //Create a Bitmap based on the previously modified photograph Bitmap Bitmap bmWatermark = new Bitmap(bmPhoto); bmWatermark.SetResolution(imgPhoto.HorizontalResolution, imgPhoto.VerticalResolution); //Load this Bitmap into a new Graphic Object Graphics grWatermark = Graphics.FromImage(bmWatermark); //To achieve a transulcent watermark we will apply (2) color //manipulations by defineing a ImageAttributes object and //seting (2) of its properties. ImageAttributes imageAttributes = new ImageAttributes(); //The first step in manipulating the watermark image is to replace //the background color with one that is trasparent (Alpha=0, R=0, G=0, B=0) //to do this we will use a Colormap and use this to define a RemapTable ColorMap colorMap = new ColorMap(); //My watermark was defined with a background of 100% Green this will //be the color we search for and replace with transparency colorMap.OldColor = Color.FromArgb(255, 0, 255, 0); colorMap.NewColor = Color.FromArgb(0, 0, 0, 0); ColorMap[] remapTable = { colorMap }; imageAttributes.SetRemapTable(remapTable, ColorAdjustType.Bitmap); //The second color manipulation is used to change the opacity of the //watermark. This is done by applying a 5x5 matrix that contains the //coordinates for the RGBA space. By setting the 3rd row and 3rd column //to 0.3f we achive a level of opacity float[][] colorMatrixElements = { new float[] {1.0f, 0.0f, 0.0f, 0.0f, 0.0f}, new float[] {0.0f, 1.0f, 0.0f, 0.0f, 0.0f}, new float[] {0.0f, 0.0f, 1.0f, 0.0f, 0.0f}, new float[] {0.0f, 0.0f, 0.0f, 0.3f, 0.0f}, new float[] {0.0f, 0.0f, 0.0f, 0.0f, 1.0f}}; ColorMatrix wmColorMatrix = new ColorMatrix(colorMatrixElements); imageAttributes.SetColorMatrix(wmColorMatrix, ColorMatrixFlag.Default, ColorAdjustType.Bitmap); //For this example we will place the watermark in the upper right //hand corner of the photograph. offset down 10 pixels and to the //left 10 pixles int xPosOfWm = ((phWidth - wmWidth) - 10); int yPosOfWm = 10; grWatermark.DrawImage(imgWatermark, new Rectangle(xPosOfWm, yPosOfWm, wmWidth, wmHeight), //Set the detination Position 0, // x-coordinate of the portion of the source image to draw. 0, // y-coordinate of the portion of the source image to draw. wmWidth, // Watermark Width wmHeight, // Watermark Height GraphicsUnit.Pixel, // Unit of measurment imageAttributes); //ImageAttributes Object //Replace the original photgraphs bitmap with the new Bitmap imgPhoto = bmWatermark; grPhoto.Dispose(); grWatermark.Dispose(); //save new image to file system. imgPhoto.Save(Server.MapPath(".\\TmpImages\\WaterMark.jpg"), ImageFormat.Jpeg); imgPhoto.Dispose(); imgWatermark.Dispose(); }

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  • How can I programmatically tell if a caught IOException is because the file is being used by another

    - by Paul K
    When I open a file, I want to know if it is being used by another process so I can perform special handling; any other IOException I will bubble up. An IOException's Message property contains "The process cannot access the file 'foo' because it is being used by another process.", but this is unsuitable for programmatic detection. What is the safest, most robust way to detect a file being used by another process?

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  • How do I close a file after catching an IOException in java?

    - by DimDom
    All, I am trying to ensure that a file I have open with BufferedReader is closed when I catch an IOException, but it appears as if my BufferedReader object is out of scope in the catch block. public static ArrayList readFiletoArrayList(String fileName, ArrayList fileArrayList) { fileArrayList.removeAll(fileArrayList); try { //open the file for reading BufferedReader fileIn = new BufferedReader(new FileReader(fileName)); // add line by line to array list, until end of file is reached // when buffered reader returns null (todo). while(true){ fileArrayList.add(fileIn.readLine()); } }catch(IOException e){ fileArrayList.removeAll(fileArrayList); fileIn.close(); return fileArrayList; //returned empty. Dealt with in calling code. } } Netbeans complains that it "cannot find symbol fileIn" in the catch block, but I want to ensure that in the case of an IOException that the Reader gets closed. How can I do that without the ugliness of a second try/catch construct around the first? Any tips or pointers as to best practise in this situation is appreciated,

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  • when does java.util.zip.ZipFile.close() throw IOException?

    - by sk
    Under what circumstances would java.util.zip.ZipFile.close() throw an IOException? Its method signature indicates that it can be thrown, but from the source code there doesn't seem to be any place where this could happen, unless it's in native code. What corrective action, if any, could be taken at the point where that exception is caught?

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  • Should Java IOException have been an unchecked RuntimeException?

    - by Derek Mahar
    Do you agree that the designers of Java class java.io.IOException should have made it an unchecked run-time exception derived from java.lang.RuntimeException instead of a checked exception derived only from java.lang.Exception? I think that class IOException should have been an unchecked exception because there is little that an application can do to resolve problems like file system errors. However, in When You Can't Throw An Exception, Elliotte Rusty Harold claims that most I/O errors are transient and so you can retry an I/O operation several times before giving up: For instance, an IOComparator might not take an I/O error lying down, but — because many I/O problems are transient — you can retry a few times, as shown in Listing 7: Is this generally the case? Can a Java application correct I/O errors or wait for the system to recover? If so, then it is reasonable for IOException to be checked, but if it is not the case, then IOException should be unchecked so that business logic can delegate handling this exception to a separate system error handler.

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  • What to do when ServerSocket throws IOException and keeping server running

    - by s5804
    Basically I want to create a rock solid server. while (keepRunning.get()) { try { Socket clientSocket = serverSocket.accept(); ... spawn a new thread to handle the client ... } catch (IOException e) { e.printStackTrace(); // NOW WHAT? } } In the IOException block, what to do? Is the Server socket at fault so it need to be recreated? For example wait a few seconds and then serverSocket = ServerSocketFactory.getDefault().createServerSocket(MY_PORT); However if the server socket is still OK, then it is a pity to close it and kill all previously accepted connections that are still communicating. EDIT: After some answers, here my attempt to deal with the IOException. Would the implementation be guaranteeing keeping the server up and only re-create server socket when only necessary? while (keepRunning.get()) { try { Socket clientSocket = serverSocket.accept(); ... spawn a new thread to handle the client ... bindExceptionCounter = 0; } catch (IOException e) { e.printStackTrace(); recreateServerSocket(); } } private void recreateServerSocket() { while (keepRunning) { try { logger.info("Try to re-create Server Socket"); ServerSocket socket = ServerSocketFactory.getDefault().createServerSocket(RateTableServer.RATE_EVENT_SERVER_PORT); // No exception thrown, then use the new socket. serverSocket = socket; break; } catch (BindException e) { logger.info("BindException indicates that the server socket is still good.", e); bindExceptionCounter++; if (bindExceptionCounter < 5) { break; } } catch (IOException e) { logger.warn("Problem to re-create Server Socket", e); e.printStackTrace(); try { Thread.sleep(30000); } catch (InterruptedException ie) { logger.warn(ie); } } } }

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  • IOException during blocking network NIO in JDK 1.7

    - by Bass
    I'm just learning NIO, and here's the short example I've written to test how a blocking NIO can be interrupted: class TestBlockingNio { private static final boolean INTERRUPT_VIA_THREAD_INTERRUPT = true; /** * Prevent the socket from being GC'ed */ static Socket socket; private static SocketChannel connect(final int port) { while (true) { try { final SocketChannel channel = SocketChannel.open(new InetSocketAddress(port)); channel.configureBlocking(true); return channel; } catch (final IOException ioe) { try { Thread.sleep(1000); } catch (final InterruptedException ie) { } continue; } } } private static byte[] newBuffer(final int length) { final byte buffer[] = new byte[length]; for (int i = 0; i < length; i++) { buffer[i] = (byte) 'A'; } return buffer; } public static void main(final String args[]) throws IOException, InterruptedException { final int portNumber = 10000; new Thread("Reader") { public void run() { try { final ServerSocket serverSocket = new ServerSocket(portNumber); socket = serverSocket.accept(); /* * Fully ignore any input from the socket */ } catch (final IOException ioe) { ioe.printStackTrace(); } } }.start(); final SocketChannel channel = connect(portNumber); final Thread main = Thread.currentThread(); final Thread interruptor = new Thread("Inerruptor") { public void run() { System.out.println("Press Enter to interrupt I/O "); while (true) { try { System.in.read(); } catch (final IOException ioe) { ioe.printStackTrace(); } System.out.println("Interrupting..."); if (INTERRUPT_VIA_THREAD_INTERRUPT) { main.interrupt(); } else { try { channel.close(); } catch (final IOException ioe) { System.out.println(ioe.getMessage()); } } } } }; interruptor.setDaemon(true); interruptor.start(); final ByteBuffer buffer = ByteBuffer.allocate(32768); int i = 0; try { while (true) { buffer.clear(); buffer.put(newBuffer(buffer.capacity())); buffer.flip(); channel.write(buffer); System.out.print('X'); if (++i % 80 == 0) { System.out.println(); Thread.sleep(100); } } } catch (final ClosedByInterruptException cbie) { System.out.println("Closed via Thread.interrupt()"); } catch (final AsynchronousCloseException ace) { System.out.println("Closed via Channel.close()"); } } } In the above example, I'm writing to a SocketChannel, but noone is reading from the other side, so eventually the write operation hangs. This example works great when run by JDK-1.6, with the following output: Press Enter to interrupt I/O XXXX Interrupting... Closed via Thread.interrupt() — meaning that only 128k of data was written to the TCP socket's buffer. When run by JDK-1.7 (1.7.0_25-b15 and 1.7.0-u40-b37), however, the very same code bails out with an IOException: Press Enter to interrupt I/O XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX XXXXXXXXXXX Exception in thread "main" java.io.IOException: Broken pipe at sun.nio.ch.FileDispatcherImpl.write0(Native Method) at sun.nio.ch.SocketDispatcher.write(SocketDispatcher.java:47) at sun.nio.ch.IOUtil.writeFromNativeBuffer(IOUtil.java:93) at sun.nio.ch.IOUtil.write(IOUtil.java:65) at sun.nio.ch.SocketChannelImpl.write(SocketChannelImpl.java:487) at com.example.TestBlockingNio.main(TestBlockingNio.java:109) Can anyone explain this different behaviour?

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  • Servlet IOException when streaming a Byte Array

    - by MontyBongo
    I occasionally get an IOException from a Servlet I have that writes a byte array to the outputstream in order to provide a file download capability. This download servlet has a reasonable amount of traffic (100k hits a month) and this exception occurs rarely, around 1-2 times a month. I have tried recreating the exception by using the exact same Base64 String and no exception is raised and the Servlet behaves as designed. Is this IO Exception being caused by something outside my applications control? For example a network issue or the user resetting the connection? I have tried to google the cause of an IOException at this point in the stack but to no avail. The environment is running Tomcat 5.5 on CentOS 5.3 with an Apache HTTP Server acting as a proxy using proxy_ajp. ClientAbortException: java.io.IOException at org.apache.catalina.connector.OutputBuffer.realWriteBytes(OutputBufferjava:366) at org.apache.tomcat.util.buf.ByteChunk.append(ByteChunk.java:352) at org.apache.catalina.connector.OutputBuffer.writeBytes(OutputBuffer.java:392) at org.apache.catalina.connector.OutputBuffer.write(OutputBuffer.java:381) at org.apache.catalina.connector.CoyoteOutputStream.write(CoyoteOutputStream.java:89) at org.apache.catalina.connector.CoyoteOutputStream.write(CoyoteOutputStream.java:83) at com.myApp.Download.doPost(Download.java:34) at javax.servlet.http.HttpServlet.service(HttpServlet.java:710) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:691) at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:469) at org.apache.catalina.core.ApplicationDispatcher.doForward(ApplicationDispatcher.java:403) at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:301) at com.myApp.EntryServlet.service(EntryServlet.java:278) at javax.servlet.http.HttpServlet.service(HttpServlet.java:803) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at com.myApp.filters.RequestFilter.doFilter(RequestFilter.java:16) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:210) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:151) at org.apache.coyote.ajp.AjpAprProcessor.process(AjpAprProcessor.java:444) at org.apache.coyote.ajp.AjpAprProtocol$AjpConnectionHandler.process(AjpAprProtocol.java:472) at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1286) at java.lang.Thread.run(Thread.java:636) Caused by: java.io.IOException at org.apache.coyote.ajp.AjpAprProcessor.flush(AjpAprProcessor.java:1200) at org.apache.coyote.ajp.AjpAprProcessor$SocketOutputBuffer.doWrite(AjpAprProcessor.java:1285) at org.apache.coyote.Response.doWrite(Response.java:560) at org.apache.catalina.connector.OutputBuffer.realWriteBytes(OutputBufferjava:361) And the code in the Download Servlet: @Override protected void doPost (HttpServletRequest request, HttpServletResponse response) throws ServletException, java.io.IOException { try { response.setContentType("application/pdf"); response.setHeader("Pragma", ""); response.setHeader("Cache-Control", ""); response.setHeader("Content-Disposition", "Inline; Filename=myPDFFile..pdf"); ServletOutputStream out = response.getOutputStream(); byte[] downloadBytes = Base64.decode((String)request.getAttribute("fileToDownloadBase64")); out.write(downloadBytes); } catch (Base64DecodingException e) { e.printStackTrace(); response.getOutputStream().print("An error occurred"); } }

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  • Force IOException during file reading

    - by DixonD
    I have the piece of code that reads data from file. I want to force IOException in this code for testing purpose (I want to check if code throws correct custom exception in this case). Is there a some way to create a file which is protected from being read, for example? Maybe dealing with some security checks can help? Please, note that passing name to not-existent file cannot help, because FileNotFoundException has separate catch clause. Here peace of code for better undestanding of question: BufferedReader reader = null; try { reader = new BufferedReader(new FileReader(csvFile)); String rawLine; while ((rawLine = reader.readLine()) != null) { // some work is done here } } catch (FileNotFoundException e) { throw new SomeCustomException(); } catch (IOException e) { throw new SomeCustomException(); } finally { // close the input stream if (reader != null) { try { reader.close(); } catch (IOException e) { // ignore } } }

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  • IOException opening RFCOMM on openSUSE

    - by Chief A-G
    I have a permissions problem on openSUSE with Bluetooth /dev/rfcomm0. I've written a small test application which opens /dev/rfcomm0 and sends a request message and retrieves a response message. At first my problem was a permission denied error on /dev/rfcomm0 until I added the user account to the dialup users group. Now I get a System.IO.IOException Interrupted system call error whenever I run the app. I can sudo my application and it runs fine. I'm not sure how and which permissions to set to get this work work under my normal user account.

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  • java.io.IOException: Premature EOF

    - by jouzef19
    Hi: I am trying to download an xml file using Stream and things was fine , until the xml size became bigger than 9 MB , so i've got this error java.io.IOException: Premature EOF this is the code BufferedInputStream bfi = null; try { bfi = new BufferedInputStream(new URL("The URL").openStream()); String name = "name.xml"; FileOutputStream fb = new FileOutputStream(name); BufferedOutputStream bout = new BufferedOutputStream(fb, 1024); byte[] data = new byte[1024]; int x = 0; while ((x = bfi.read(data, 0, 1024)) >= 0) { bout.write(data, 0, x); } this.deletePhishTankDatabase(this.recreateFileName()); ptda.insertDownloadTime(hour, day, month, year); bout.close(); bfi.close(); } catch (IOException ex) { Logger.getLogger(PhishTankDataBase.class.getName()).log(Level.SEVERE, null, ex); } finally { try { bfi.close(); } catch (IOException ex) { Logger.getLogger(PhishTankDataBase.class.getName()).log(Level.SEVERE, null, ex); } } } else { System.out.println("You can't do anything"); return; } thanks in advanced

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  • What to do when ServerSocket throws IOException

    - by s5804
    Basically I want to create a rock solid server. while (keepRunning.get()) { try { Socket clientSocket = serverSocket.accept(); ... spawn a new thread to handle the client ... } catch (IOException e) { e.printStackTrace(); // NOW WHAT? } } In the IOException block, what to do? Is the Server socket at fault so it need to be recreated? For example wait a few seconds and then serverSocket = ServerSocketFactory.getDefault().createServerSocket(MY_PORT); However if the server socket is still OK, then it is a pity to close it and kill all previously accepted connections that are still communicating.

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  • Java: dangerous self-returning-recursive function by IOException?

    - by HH
    I had very errorsome Exception handling with if-clauses. An exception occurs if not found path. An exception returns the function again. The function is recursive. Safe? $ javac SubDirs.java $ java SubDirs Give me an path. . HELLO com TOASHEOU google common annotations base collect internal Give me an path. IT WON'T FIND ME, SO IT RETURNS ITSELF due to Exception caught Give me an path. $ cat SubDirs.java import java.io.*; import java.util.*; public class SubDirs { private List<File> getSubdirs(File file) throws IOException { List<File> subdirs = Arrays.asList(file.listFiles(new FileFilter() { public boolean accept(File f) { return f.isDirectory(); } })); subdirs = new ArrayList<File>(subdirs); List<File> deepSubdirs = new ArrayList<File>(); for(File subdir : subdirs) { deepSubdirs.addAll(getSubdirs(subdir)); } subdirs.addAll(deepSubdirs); return subdirs; } public static void search() { try{ BufferedReader in = new BufferedReader(new InputStreamReader(System.in)); String s; System.out.println("Give me an path."); while ((s = in.readLine()) != null && s.length() != 0){ SubDirs dirs = new SubDirs(); List<File> subDirs = dirs.getSubdirs(new File(s)); for ( File f : subDirs ) { System.out.println(f.getName()); } System.out.println("Give me an path."); } }catch(Exception e){ // Simple but is it safe? search(); } } public static void main(String[] args) throws IOException { search(); } }

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  • java.io.IOException: Bad DNS address - in opening a HttpConnection

    - by Shreyas
    Hi, I m opening a HttpConnection to a URL. Its working in simulator but when i try it in device, it gives "java.io.IOException: Bad DNS address" while opening the HttpConnection. I serached the forums but havent got the solution yet. That URL is opening in Blackberry device Internet Browser but not getting the HttpConnection (HttpConnection is coming NULL) when i try through my code.

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