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  • Discard unprintable characters returned in server's XML response

    - by Penang
    While trying to use the Bing API to search, I am getting characters that are not printable and do not seem to hold any extra information. The goal is to save the XML (UTF-8) response as a text file to be parsed later. My code currently looks something like this: URL url = new URL(queryURL); BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream())); BufferedWriter out = new BufferedWriter(new FileWriter(query+"-"+saveResultAs)); String str = in.readLine(); out.write(str); in.close(); out.close(); When I send the contents of 'str' to console it looks something like this: and here's a what the newly created local XML file looks like: What should I be doing to convert the UTF-8 text so that str does not have the extra characters?

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  • Is the Google Annotations Gallery useful in production code?

    - by cafe
    I could actually see a use for the Google Annotations Gallery in real code: Stumble across code that somehow works beyond all reason? Life's short. Mark it with @Magic and move on: @Magic public static int negate(int n) { return new Byte((byte) 0xFF).hashCode() / (int) (short) '\uFFFF' * ~0 * Character.digit ('0', 0) * n * (Integer.MAX_VALUE * 2 + 1) / (Byte.MIN_VALUE >> 7) * (~1 | 1); } This is a serious question. Could this be used in an actual code review?

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  • How to use a photo that has just been uploaded to Tomcat v6?

    - by Zombie_Colonel
    In an android application a user can upload a picture to a Tomcat server v6 in (Projet\WebContent\images) A second user can come at the same time display the picture thing not work it shows me: The requested resource is not available. I did what? I have to reboot the server? refresh? in a PHP page I upload pictures and then they are simply viewed by the user, for cons there I find difficulty with JEE

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  • Figuring out QuadCurveTo's parameters

    - by Fev
    Could you guys help me figuring out QuadCurveTo's 4 parameters , I tried to find information on http://docs.oracle.com/javafx/2/api/javafx/scene/shape/QuadCurveTo.html, but it's hard for me to understand without picture , I search on google about 'Quadratic Bezier' but it shows me more than 2 coordinates, I'm confused and blind now. I know those 4 parameters draw 2 lines to control the path , but how we know/count exactly which coordinates the object will throught by only knowing those 2 path-controller. Are there some formulas? import javafx.animation.PathTransition; import javafx.animation.PathTransition.OrientationType; import javafx.application.Application; import static javafx.application.Application.launch; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.paint.Color; import javafx.scene.shape.MoveTo; import javafx.scene.shape.Path; import javafx.scene.shape.QuadCurveTo; import javafx.scene.shape.Rectangle; import javafx.stage.Stage; import javafx.util.Duration; public class _6 extends Application { public Rectangle r; @Override public void start(final Stage stage) { r = new Rectangle(50, 80, 80, 90); r.setFill(javafx.scene.paint.Color.ORANGE); r.setStrokeWidth(5); r.setStroke(Color.ANTIQUEWHITE); Path path = new Path(); path.getElements().add(new MoveTo(100.0f, 400.0f)); path.getElements().add(new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f)); PathTransition pt = new PathTransition(Duration.millis(1000), path); pt.setDuration(Duration.millis(10000)); pt.setNode(r); pt.setPath(path); pt.setOrientation(OrientationType.ORTHOGONAL_TO_TANGENT); pt.setCycleCount(4000); pt.setAutoReverse(true); pt.play(); stage.setScene(new Scene(new Group(r), 500, 700)); stage.show(); } public static void main(String[] args) { launch(args); } } You can find those coordinates on this new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f) line, and below is the picture of Quadratic Bezier

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  • How to get the type of the class for comparison

    - by Halo
    I have this object which is an instance of a superclass. I want to know which subclass that object really is, so that I can decide what to do with it. There is this getClass() method but it's apparently not used for comparison issues. How can I get the sub-type of my object?

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  • How do I manipulate a tree of immutable objects?

    - by Frederik
    I'm building an entire application out of immutable objects so that multi-threading and undo become easier to implement. I'm using the Google Collections Library which provides immutable versions of Map, List, and Set. My application model looks like a tree: Scene is a top-level object that contains a reference to a root Node. Each Node can contain child Nodes and Ports. An object graph might look like this: Scene | +-- Node | +-- Node | +- Port +-- Node | +- Port +- Port If all of these objects are immutable, controlled by a top-level SceneController object: What is the best way to construct this hierarchy? How would I replace an object that is arbitrarily deep in the object tree? Is there a way to support back-links, e.g. a Node having a "parent" attribute?

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  • OutOfMemoryError creating a tree recursively?

    - by Alexander Khaos Greenstein
    root = new TreeNode(N); constructTree(N, root); private void constructTree(int N, TreeNode node) { if (N > 0) { node.setLeft(new TreeNode(N-1)); constructTree(N-1, node.getLeft()); } if (N > 1) { node.setMiddle(new TreeNode(N-2)); constructTree(N-2, node.getMiddle()); } if (N > 2) { node.setRight(new TreeNode(N-3)); constructTree(N-3, node.getRight()); } Assume N is the root number, and the three will create a left middle right node of N-1, N-2, N-3. EX: 5 / | \ 4 3 2 /|\ 3 2 1 etc. My GameNode class has the following variables: private int number; private GameNode left, middle, right; Whenever I construct a tree with an integer greater than 28, I get a OutOfMemoryError. Is my recursive method just incredibly inefficient or is this natural? Thanks!

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  • JPA polymorphic oneToMany

    - by bob
    I couldn't figure out how to cleanly do a tag cloud with JPA where each db entity can have many tags. E.g Post can have 0 or more Tags User can have 0 or more Tags Is there a better way in JPA than having to make all the entities subclass something like Taggable abstract class? Where a a Tag entity would reference many Taggables. thank you

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  • Hibernate Criteria API: get n random rows

    - by hadrien
    I can't figure out how to fetch n random rows from a criteria instance: Criteria criteria = session.createCriteria(Table.class); criteria.add(Restrictions.eq('fieldVariable', anyValue)); ... Then what? I can't find any doc with Criteria API Does it mean I should use HQL instead? Thanx! EDIT: I get the number of rows by: int max = criteria.setProjecxtion(Projections.rowCount()).uniqueResult(); How do I fetch n random rows with indexes between 0 and max? Thx again!

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  • Sending an HTTP POST request through the android emulator doesn't work

    - by Sotirios Delimanolis
    I'm running a tomcat servlet on my local machine and an Android emulator with an app that makes a post request to the servlet. The code for the POST is below (without exceptions and the like): String strUrl = "http://10.0.2.2:8080/DeviceDiscoveryServer/server/devices/"; Device device = Device.getUniqueInstance(); urlParameters += URLEncoder.encode("user", "UTF-8") + "=" + URLEncoder.encode(device.getUser(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("port", "UTF-8") + "=" + URLEncoder.encode(new Integer(Device.PORT).toString(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("address", "UTF-8") + "=" + URLEncoder.encode(device.getAddress().getHostAddress(), "UTF-8"); URL url = new URL(strUrl); HttpURLConnection connection = (HttpURLConnection) url.openConnection(); connection.setDoOutput(true); connection.setRequestMethod("POST"); OutputStreamWriter wr = new OutputStreamWriter(connection.getOutputStream()); wr.write(urlParameters); wr.flush(); wr.close(); Whenever this code is executed, the servlet isn't called. However if I change the type of the request to 'GET' and don't write anything to the outputstream, the servlet gets called and everything works fine. Am I just not making the POST correctly or is there some other error?

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  • What is the easiest straightforward way of telling which version performs better?

    - by Peter Perhác
    I have an application, which I have re-factored so that I believe it is now faster. One can't possibly feel the difference, but in theory, the application should run faster. Normally I would not care, but as this is part of my project for my master's degree, I would like to support my claim that the re-factoring did not only lead to improved design and 'higher quality', but also an increase in performance of the application (a small toy-thing - a train set simulation). I have toyed with the latest VisualVM thing today for about four hours but I couldn't get anything helpful out of it. There isn't (or I haven't found it) a way to simply compare the profiling results taken from the two versions (pre- and post- refactoring). What would be the easiest, the most straightforward way of simply telling the slower from the faster version of the application. The difference of the two must have had an impact on the performance. Thank you.

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  • Sorting an ArrayList of Contacts

    - by Sameera0
    Ok so I have a been making an addressbook application and have pretty much finished all the key features but I am looking to implement a sort feature in the program. I want to sort an Arraylist which is of a type called Contact (contactArray) which is a separate class which contains four fields; name, home number, mobile number and address. So I was looking into using the collection sort yet am not sure how i'd implement this. Is this the right sort I should be using / is it possible to use or should I look into making a custom sort?

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  • How to start an activity that is defined in other Android projects?

    - by qichuan
    I have defined some common Activities in a library project and want to reuse these activity in my working project. I declared my library project as Android library, use the fully-qualified name of the Activities and declare them in the AndroidManifest.xml of the new project. However, I get 'Unable to find explicit activity class' error when launching the application. Any other configurations shall I do in order to start the Activities?

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  • How can I calculate the age at death?

    - by user521180
    SimpleDateFormat formatter = new SimpleDateFormat("dd-MM-yyyy"); if(petDetails.getDateOfDeath() != null){ String formatedDateOfDeath = formatter.format(petDetails.getDateOfDeath()); String formateDateOfBirth = formatter.format(petDetails.getDateOfBirth()); } How can i calculate the age of death from the above. I dont want to use any externallibraries EDIT: please look at what I've got so far.none of the other threads are like mine. most of them are about date from DOB to today and not in the format im using.

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  • 2 compareTo method overriden in the same class definition, how could I force to use the second?

    - by jayjaypg22
    I want to sort a list List<Blabla> donnees by a criterion on one of its field. My problem is that compareTo is already overriden for this Class. So I've got something like : Blabla { public int compareTo(Object other) { ... } public int compareTo(Blabla other) { ... } } In a business layer class I call : Business { method (){ Collections.sort(List<Blabla > donnees); } } But this call N°1 compareTo method with object parameter. How could I sort my list with the N°2 method?

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  • JComboBox to string

    - by gabrielle fregil
    I have a String array of names, and then I added it into an editable JComboBox. The user can either pick his/her name from the choices or just input his/her name if not in the choices. How do I put the user input into a new string variable? String [] chooseName = { Mark, John, Allison, Jessica }; JComboBox combo = new JComboBox (chooseName); combo.setEditable(true); String chosenName = /* how do i place what the user inputed here? */

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  • Inheritance question / problem

    - by Itsik
    I'm creating a custom Layout for android. The layout implementation is exactly the same, but once I need to extend from RelativeLayout, and once from LinearLayout. class Layout1 extends LinearLayout { // methods and fields } class Layout2 extends RelativeLayout { // the same EXACT methods and fields } How can I use inheritance to avoid DRY and implement my methods once.

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  • value from resource bundle as pattern in formatDate

    - by binary_runner
    I want to read pattern for JST formatDate also from resource bundle but this naive approach does not working, what I'm doing wrong ? in com/company/MyPortlet.properties is this key: company.date.format = yyyy-MM-dd HH:mm:ss In page I have: <fmt:setBundle basename="com.company.MyPortlet"/> <fmt:formatDate value="${date}" pattern="${company.date.format}" />

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  • Spring OpenSessionInViewFilter with @Transactional annotation

    - by Gautam
    This is regarding Spring OpenSessionInViewFilter using with @Transactional annotation at service layer. i went through so many stack overflow post on this but still confused about whether i should use OpenSessionInViewFilter or not to avoid LazyInitializationException It would be great help if somebody help me find out answer to below queries. Is it bad practice to use OpenSessionInViewFilter in application having complex schema. using this filter can cause N+1 problem if we are using OpenSessionInViewFilter does it mean @Transactional not required? Below is my Spring config file <context:component-scan base-package="com.test"/> <context:annotation-config/> <bean id="messageSource" class="org.springframework.context.support.ReloadableResourceBundleMessageSource"> <property name="basename" value="resources/messages" /> <property name="defaultEncoding" value="UTF-8" /> </bean> <bean id="propertyConfigurer" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer" p:location="/WEB-INF/jdbc.properties" /> <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${jdbc.driverClassName}" p:url="${jdbc.databaseurl}" p:username="${jdbc.username}" p:password="${jdbc.password}" /> <bean id="sessionFactory" class="org.springframework.orm.hibernate3.LocalSessionFactoryBean"> <property name="dataSource" ref="dataSource" /> <property name="configLocation"> <value>classpath:hibernate.cfg.xml</value> </property> <property name="configurationClass"> <value>org.hibernate.cfg.AnnotationConfiguration</value> </property> <property name="hibernateProperties"> <props> <prop key="hibernate.dialect">${jdbc.dialect}</prop> <prop key="hibernate.show_sql">true</prop> <!-- <prop key="hibernate.hbm2ddl.auto">create</prop> --> </props> </property> </bean> <tx:annotation-driven /> <bean id="transactionManager" class="org.springframework.orm.hibernate3.HibernateTransactionManager"> <property name="sessionFactory" ref="sessionFactory" /> </bean>

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  • Can't referr to my get method

    - by chility
    I have this amazing and good looking class: public class SayingsHolder extends Application{ ArrayList<String> SayingsList = new ArrayList<String>(){{ SayingsList.add("1"); SayingsList.add("2"); }}; public ArrayList<String> getSayingsList() { return SayingsList; } } Now I'm trying to call the getSayingsList method inside of my activity's FragmentStatePagerAdapter by: private class ScreenSlidePagerAdapter extends FragmentStatePagerAdapter { final SayingsHolder holder = (SayingsHolder).getApplication(); } Everything fine for now, but when I make my code like this: private class ScreenSlidePagerAdapter extends FragmentStatePagerAdapter { final SayingsHolder holder = (SayingsHolder).getApplication(); holder.getSayingsList(); } it says: Syntax error on token "getSayingsList", Identifier expected after this token The problem is that holder is not functional at all. What I mean is that when i type the this holder. the getSayingsList is not showing at all. What am I missing here? I know that it is an extremely small issue, but it seems that I can't spot it. My activity extends FragmentActivity if it's important It seems that I'm missing something here. I can't call my method anywhere in my activity. I'm starting a bounty, because I need an example.

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  • What is wrong in this bit of MyID3 code? (error code is just Exceptions)

    - by user3697621
    Okay, so, this was supposed to get the paths of all mp3 files in a folder, read their metadata and put in an arraylist. public static List<String> OrgMetadata(List<String> rawgenrelist){ File folder = new File("C:\\SOM\\"); File[] listOfFiles = folder.listFiles(); //File path = listOfFiles; for (int i = 0; i < listOfFiles.length; i++) { String pt = listOfFiles[i].getAbsolutePath(); File src = new File(pt); MusicMetadataSet src_set = new MyID3().read(src); if (src_set != null && listOfFiles[i].isFile()) { IMusicMetadata metadata = src_set.getSimplified(); rawgenrelist.add(metadata.getGenreName()); } } List<String> genrelist; genrelist = new ArrayList(new HashSet(rawgenrelist)); return genrelist; }

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  • Interrupt a thread in DatagramSocket.receive

    - by SEK
    I'm building an application that listens on both TCP and UDP, and I've run into some trouble with my shutdown mechanism. When I call Thread.interrupt() on each of the listening threads, the TCP thread is interrupted from listening, whereas the UDP listener isn't. To be specific, the TCP thread uses Socket.accept(), which simply returns (without actually connecting). Whereas the UDP thread uses DatagramSocket.receive, and doesn't exit that method. Is this an issue in my JRE, my OS, or should I just switch to (Datagram)Socket.close()?

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