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  • Inheritance question / problem

    - by Itsik
    I'm creating a custom Layout for android. The layout implementation is exactly the same, but once I need to extend from RelativeLayout, and once from LinearLayout. class Layout1 extends LinearLayout { // methods and fields } class Layout2 extends RelativeLayout { // the same EXACT methods and fields } How can I use inheritance to avoid DRY and implement my methods once.

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  • How to execute query with IN clause in spring?

    - by GK
    I have following code : try { MapSqlParameterSource parameters = new MapSqlParameterSource(); parameters.addValue("ids", year); return this.template.getJdbcOperations().query( "SELECT * FROM INCOME WHERE PROVNUM=? AND FISCALDATE IN ( :ids )", this.rowMapper, parameters); }catch (EmptyResultDataAccessException ex) { return null; } But i am not able to send the value for PROVNUM. how to do that? need help, thanks.

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  • program to determine number of duplicates in a sentence

    - by bhavna raghuvanshi
    public class duplicate { public static void main(String[] args)throws IOException { System.out.println("Enter words separated by spaces ('.' to quit):"); Set<String> s = new HashSet<String>(); Scanner input = new Scanner(System.in); while (true) { String token = input.next(); if (".".equals(token)) break; if (!s.add(token)) System.out.println("Duplicate detected: " + token); } System.out.println(s.size() + " distinct words:\n" + s); } } my program detects and prints duplicate words but i need to print the number of duplicate words also. pls help me do it.

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  • HTML/CSS Rendering to Image

    - by Steve
    Is there a library or tool that can take an html page and some css, and then render an image? I would like to define some templates server side using html code snippets, and some CSS to define the layout. Then using the template and CSS, I would like to essentially render an image of how this would display in a browser, and pass the image back to the client. Thanks.

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  • Very Urgent :How to start a new session if a user click on the new tab in IE or mozilla on websphere

    - by ha22109
    Hi, I have one "user search" portlet on the home page of one application running on websphere portal server.Which display the matching user records as per the search criteria filled in the search form.I have requirement to have a "back to search input" link on the results page which onclick should show the filled form on the input jsp. The issue which i am facing is if i open the application in two diff tab of same IE browser and start giving some search criteria and submit and same time search for some other input from other IE tab (in the same browser)and then go back to previous tab and click on "back to search input" link then instead of showing me the first input it will show me the imput which i entered in the next IE tab. I am setting and getting the bean(form bean) through portlet session.but in the two diff tab of same IE it will be the sae user session (and may be the same portlet session..) Please tell me solution for this. The one thing to be notice here is i can access this "user search" application even without doing login also.so it must be taking the default portlet session in this case. what wil happen once i login and then search,will it going to overwrite the portlet session and http session or howz is that?

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  • How to change the way that timer schedules in TimerTask?

    - by Judking
    Here is the code snippet: Timer t = new Timer(); TimerTask task = new TimerTask() { @Override public void run() { //change the timer rate of scheduleAtFixedRate here } }; //every 10 sec t.scheduleAtFixedRate(task, new Date(), 10000); Could anyone tell me how to change the rate of timer to t.scheduleAtFixedRate(task, new Date(), 30000) in method run from TimerTask instance? Thanks a lot!

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  • What is the easiest straightforward way of telling which version performs better?

    - by Peter Perhác
    I have an application, which I have re-factored so that I believe it is now faster. One can't possibly feel the difference, but in theory, the application should run faster. Normally I would not care, but as this is part of my project for my master's degree, I would like to support my claim that the re-factoring did not only lead to improved design and 'higher quality', but also an increase in performance of the application (a small toy-thing - a train set simulation). I have toyed with the latest VisualVM thing today for about four hours but I couldn't get anything helpful out of it. There isn't (or I haven't found it) a way to simply compare the profiling results taken from the two versions (pre- and post- refactoring). What would be the easiest, the most straightforward way of simply telling the slower from the faster version of the application. The difference of the two must have had an impact on the performance. Thank you.

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  • What is wrong in this bit of MyID3 code? (error code is just Exceptions)

    - by user3697621
    Okay, so, this was supposed to get the paths of all mp3 files in a folder, read their metadata and put in an arraylist. public static List<String> OrgMetadata(List<String> rawgenrelist){ File folder = new File("C:\\SOM\\"); File[] listOfFiles = folder.listFiles(); //File path = listOfFiles; for (int i = 0; i < listOfFiles.length; i++) { String pt = listOfFiles[i].getAbsolutePath(); File src = new File(pt); MusicMetadataSet src_set = new MyID3().read(src); if (src_set != null && listOfFiles[i].isFile()) { IMusicMetadata metadata = src_set.getSimplified(); rawgenrelist.add(metadata.getGenreName()); } } List<String> genrelist; genrelist = new ArrayList(new HashSet(rawgenrelist)); return genrelist; }

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  • Getting instance of a class in ArrayList

    - by user1499974
    I have a small problem with ArrayList. You see, I wish to get an instance of RenderNewHUD in my renderer class, which has a list of registered renderers. I did not want to create a variable for this due to limitations and awkwardness. Here is my code. RenderNewHUD hud = renderer.renderList.get(RenderNewHUD()); How exactly can I go along getting the instance of RenderNewHUD without creating a new instance? If you need any more of my code, just ask. Sorry if this is a very dumb question - I have looked EVERYWHERE for an answer.

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  • How do I manipulate a tree of immutable objects?

    - by Frederik
    I'm building an entire application out of immutable objects so that multi-threading and undo become easier to implement. I'm using the Google Collections Library which provides immutable versions of Map, List, and Set. My application model looks like a tree: Scene is a top-level object that contains a reference to a root Node. Each Node can contain child Nodes and Ports. An object graph might look like this: Scene | +-- Node | +-- Node | +- Port +-- Node | +- Port +- Port If all of these objects are immutable, controlled by a top-level SceneController object: What is the best way to construct this hierarchy? How would I replace an object that is arbitrarily deep in the object tree? Is there a way to support back-links, e.g. a Node having a "parent" attribute?

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  • Hibernate Criteria API: get n random rows

    - by hadrien
    I can't figure out how to fetch n random rows from a criteria instance: Criteria criteria = session.createCriteria(Table.class); criteria.add(Restrictions.eq('fieldVariable', anyValue)); ... Then what? I can't find any doc with Criteria API Does it mean I should use HQL instead? Thanx! EDIT: I get the number of rows by: int max = criteria.setProjecxtion(Projections.rowCount()).uniqueResult(); How do I fetch n random rows with indexes between 0 and max? Thx again!

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  • Sorting an ArrayList of Contacts

    - by Sameera0
    Ok so I have a been making an addressbook application and have pretty much finished all the key features but I am looking to implement a sort feature in the program. I want to sort an Arraylist which is of a type called Contact (contactArray) which is a separate class which contains four fields; name, home number, mobile number and address. So I was looking into using the collection sort yet am not sure how i'd implement this. Is this the right sort I should be using / is it possible to use or should I look into making a custom sort?

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  • Discard unprintable characters returned in server's XML response

    - by Penang
    While trying to use the Bing API to search, I am getting characters that are not printable and do not seem to hold any extra information. The goal is to save the XML (UTF-8) response as a text file to be parsed later. My code currently looks something like this: URL url = new URL(queryURL); BufferedReader in = new BufferedReader(new InputStreamReader(url.openStream())); BufferedWriter out = new BufferedWriter(new FileWriter(query+"-"+saveResultAs)); String str = in.readLine(); out.write(str); in.close(); out.close(); When I send the contents of 'str' to console it looks something like this: and here's a what the newly created local XML file looks like: What should I be doing to convert the UTF-8 text so that str does not have the extra characters?

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  • Figuring out QuadCurveTo's parameters

    - by Fev
    Could you guys help me figuring out QuadCurveTo's 4 parameters , I tried to find information on http://docs.oracle.com/javafx/2/api/javafx/scene/shape/QuadCurveTo.html, but it's hard for me to understand without picture , I search on google about 'Quadratic Bezier' but it shows me more than 2 coordinates, I'm confused and blind now. I know those 4 parameters draw 2 lines to control the path , but how we know/count exactly which coordinates the object will throught by only knowing those 2 path-controller. Are there some formulas? import javafx.animation.PathTransition; import javafx.animation.PathTransition.OrientationType; import javafx.application.Application; import static javafx.application.Application.launch; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.paint.Color; import javafx.scene.shape.MoveTo; import javafx.scene.shape.Path; import javafx.scene.shape.QuadCurveTo; import javafx.scene.shape.Rectangle; import javafx.stage.Stage; import javafx.util.Duration; public class _6 extends Application { public Rectangle r; @Override public void start(final Stage stage) { r = new Rectangle(50, 80, 80, 90); r.setFill(javafx.scene.paint.Color.ORANGE); r.setStrokeWidth(5); r.setStroke(Color.ANTIQUEWHITE); Path path = new Path(); path.getElements().add(new MoveTo(100.0f, 400.0f)); path.getElements().add(new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f)); PathTransition pt = new PathTransition(Duration.millis(1000), path); pt.setDuration(Duration.millis(10000)); pt.setNode(r); pt.setPath(path); pt.setOrientation(OrientationType.ORTHOGONAL_TO_TANGENT); pt.setCycleCount(4000); pt.setAutoReverse(true); pt.play(); stage.setScene(new Scene(new Group(r), 500, 700)); stage.show(); } public static void main(String[] args) { launch(args); } } You can find those coordinates on this new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f) line, and below is the picture of Quadratic Bezier

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  • Explicit constructor still has default values even though a default constructor is not invoked.

    - by Phoenix
    According to my understanding a default constructor initializes the state of the object to default values, so if i provide an explicit no-arg public constructor like this then how are the values of d and e still getting initialized to zero because in this case the default constructor is not invoked. public class B extends A{ private int d; private int e; public B() { System.out.println(d); System.out.println(e); } } EDIT:: The only thing default constructor does is call to super() then how come if i have a explicitly mentioned a constructor here and A has a protected variable say c which is initialized to 17 in its constructor. Should I not be explicitly calling super() to be able to see that change since I'm using my own constructor ? Why is B still getting the value of 17 through inheritance ?

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  • How to start an activity that is defined in other Android projects?

    - by qichuan
    I have defined some common Activities in a library project and want to reuse these activity in my working project. I declared my library project as Android library, use the fully-qualified name of the Activities and declare them in the AndroidManifest.xml of the new project. However, I get 'Unable to find explicit activity class' error when launching the application. Any other configurations shall I do in order to start the Activities?

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  • JPA polymorphic oneToMany

    - by bob
    I couldn't figure out how to cleanly do a tag cloud with JPA where each db entity can have many tags. E.g Post can have 0 or more Tags User can have 0 or more Tags Is there a better way in JPA than having to make all the entities subclass something like Taggable abstract class? Where a a Tag entity would reference many Taggables. thank you

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  • Sending an HTTP POST request through the android emulator doesn't work

    - by Sotirios Delimanolis
    I'm running a tomcat servlet on my local machine and an Android emulator with an app that makes a post request to the servlet. The code for the POST is below (without exceptions and the like): String strUrl = "http://10.0.2.2:8080/DeviceDiscoveryServer/server/devices/"; Device device = Device.getUniqueInstance(); urlParameters += URLEncoder.encode("user", "UTF-8") + "=" + URLEncoder.encode(device.getUser(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("port", "UTF-8") + "=" + URLEncoder.encode(new Integer(Device.PORT).toString(), "UTF-8"); urlParameters += "&" + URLEncoder.encode("address", "UTF-8") + "=" + URLEncoder.encode(device.getAddress().getHostAddress(), "UTF-8"); URL url = new URL(strUrl); HttpURLConnection connection = (HttpURLConnection) url.openConnection(); connection.setDoOutput(true); connection.setRequestMethod("POST"); OutputStreamWriter wr = new OutputStreamWriter(connection.getOutputStream()); wr.write(urlParameters); wr.flush(); wr.close(); Whenever this code is executed, the servlet isn't called. However if I change the type of the request to 'GET' and don't write anything to the outputstream, the servlet gets called and everything works fine. Am I just not making the POST correctly or is there some other error?

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  • How to use a photo that has just been uploaded to Tomcat v6?

    - by Zombie_Colonel
    In an android application a user can upload a picture to a Tomcat server v6 in (Projet\WebContent\images) A second user can come at the same time display the picture thing not work it shows me: The requested resource is not available. I did what? I have to reboot the server? refresh? in a PHP page I upload pictures and then they are simply viewed by the user, for cons there I find difficulty with JEE

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  • Is the Google Annotations Gallery useful in production code?

    - by cafe
    I could actually see a use for the Google Annotations Gallery in real code: Stumble across code that somehow works beyond all reason? Life's short. Mark it with @Magic and move on: @Magic public static int negate(int n) { return new Byte((byte) 0xFF).hashCode() / (int) (short) '\uFFFF' * ~0 * Character.digit ('0', 0) * n * (Integer.MAX_VALUE * 2 + 1) / (Byte.MIN_VALUE >> 7) * (~1 | 1); } This is a serious question. Could this be used in an actual code review?

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  • Can I include both Apache Axis 1 and 2 libraries in the same project?

    - by ian_scho_es
    If it sounds like a ridiculous idea then it is. The client only wants to have to install one project on their server. Our web service will be bridging between mobile phones and various SOAP services made in .NET, Apache Axis 1 and 2, which rely on standards to transfer files such as MTOM and DIME. I am looking for an 'architecture' trick, such as develop the Axis 1 calls in a separate project and compile as a jar, to then pass it into the Axis 2 project.... Hmmm. Anything rather than having to download the source code for Axis 1 & 2 and compile them using the same xml libraries, etc. "It can't be done" is an acceptable answer. Thanks!

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  • value from resource bundle as pattern in formatDate

    - by binary_runner
    I want to read pattern for JST formatDate also from resource bundle but this naive approach does not working, what I'm doing wrong ? in com/company/MyPortlet.properties is this key: company.date.format = yyyy-MM-dd HH:mm:ss In page I have: <fmt:setBundle basename="com.company.MyPortlet"/> <fmt:formatDate value="${date}" pattern="${company.date.format}" />

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