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  • Is there a limit for the number of files in a directory on an SD card?

    - by jamesh
    I have a project written for Android devices. It generates a large number of files, each day. These are all text files and images. The app uses a database to reference these files. The app is supposed to clear up these files after a little use (perhaps after a few days), but this process may or may not be working. This is not the subject of this question. Due to a historic accident, the organization of the files are somewhat naive: everything is in the same directory; a .hidden directory which contains a zero byte .nomedia file to prevent the MediaScanner indexing it. Today, I am seeing an error reported: java.io.IOException: Cannot create: /sdcard/.hidden/file-4200.html at java.io.File.createNewFile(File.java:1263) Regarding the sdcard, I see it has plenty of storage left, but counting $ cd /Volumes/NO_NAME/.hidden $ ls | wc -w 9058 Deleting a number of files seems to have allowed the file creation for today to proceed. Regrettably, I did not try touching a new file to try and reproduce the error on a commandline; I also deleted several hundred files rather than a handful. However, my question is: are there hard limits on filesize or number of files in a directory? am I even on the right track here? Nota Bene: The SD card is as-is - i.e. I haven't formatted it, so I would guess it would be a FAT-* format. The FAT-32 format has hard limits of filesize of 2GB (well above the filesizes I am dealing with) and a limit of number of files in the root directory. I am definitely not writing files in the root directory.

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  • Submit form using javascript, work in FF but not in IE

    - by Permana
    I have this code. The code below is working in Firefox, but it is not in IE <body> <?php $data = getLoginData($_SESSION['whoyouare']); ?> <form name="frm_redirect_dfr" action="<?php echo $data['url']; ?>" method="POST" id="frm_redirect_dfr" style="display: none;"> <input name="DFRNet_User" value="<?php echo $data['username']; ?>" type="hidden" /> <input name="DFRNet_Pass" value="<?php echo $data['password']; ?>" type="hidden" /> <input name="tbllogin" value="login" type="hidden" /> <input type="submit" value="submit" /> </form> <script language="javascript" type="text/javascript"> document.forms["frm_redirect_dfr"].submit(); </script> </body> What I want to do is, when user access the page, it first will try to get login data, echo it in the form, and submit the form automatically using javascript

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  • Click outside menu to close in jquery

    - by George
    So I have a drop-down menu that shows on a click, as per business requirements. The menu becomes hidden again after you mouse away from it. But now I am being asked to have it stay in place until user clicks anywhere on the document. How can this be accomplished? This is a simplified version of what I have now: $(document).ready(function() { $("ul.opMenu li").click(function(){ $('#MainOptSubMenu',this).css('visibility', 'visible'); }); $("ul.opMenu li").mouseleave(function(){ $('#MainOptSubMenu',this).css('visibility', 'hidden'); }); }); <ul class="opMenu"> <li id="footwo" class=""> <span id="optImg" style="display: inline-block;"> <img src="http://localhost.vmsinfo.com:8002/insight/images/options-hover2.gif"/> </span> <ul id="MainOptSubMenu" style="visibility: hidden; top: 25px; border-top: 0px solid rgb(217, 228, 250); background-color: rgb(217, 228, 250); padding-bottom: 15px;"> <li>some</li> <li>nav</li> <li>links</li> </ul> </li> </ul> I tried something like this $('document[id!=MainOptSubMenu]').click(function() thinking it would trigger on anything that wasnt the menu, but it didnt work.

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  • rails named_scope issue with eager loading

    - by Craig
    Two models (Rails 2.3.8): User; username & disabled properties; User has_one :profile Profile; full_name & hidden properties I am trying to create a named_scope that eliminate the disabled=1 and hidden=1 User-Profiles. Moreover, while the User model is usually used in conjunction with the Profile model, I would like the flexibility to be able specify this using the :include = :profile syntax. I have the following User named_scope: named_scope :visible, { :joins => "INNER JOIN profiles ON users.id=profiles.user_id", :conditions => ["users.disabled = ? AND profiles.hidden = ?", false, false] } This works as expected when just reference the User model: >> User.visible.map(&:username).flatten => ["user a", "user b", "user c", "user d"] However, when I attempt to include the Profile model: User.visible(:include=> :profiles).profile.map(&:full_name).flatten I get an error that reads: NoMethodError: undefined method `profile' for #<User:0x1030bc828> Am I able to cross model-collection boundaries in this manner?

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  • jquery pass value class

    - by mckenzie
    $(".hidee2").click(function() { var type = $(".st").val(); } <form action="" method="POST"><input type="hidden" class="st" value="st"><div class="button">Room Status : Accepting Reservation <br /><span><span><a class="hidee2">Book Now!</a></span></span></div></form> <form action="" method="POST"><input type="hidden" class="st" value="st2"><div class="button">Room Status : Accepting Reservation <br /><span><span><a class="hidee2">Book Now!</a></span></span></div></form> <form action="" method="POST"><input type="hidden" class="st" value="st3"><div class="button">Room Status : Accepting Reservation <br /><span><span><a class="hidee2">Book Now!</a></span></span></div></form> How do i get which book now! link user click? because i need to pass over the st value? is there any way to achieve this using jquery? currently, only st value is passed over

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  • .each or search function, how can I make use of those?

    - by Noor
    I have a ul list, with 10 items, and I have a label that displays the selected li text. When I click a button, I need to check the label, versus all the list items to find the matching one, when it finds that I need to assign the corresponding number. I.e. list: Messi Cristiano Zlatan hidden values of list items: www.messi.com www.cronaldo.com www.ibra.com label: Zlatan script (thought)procces: get label text, search list for matching string, get the value of that string. (and if someone could point me in a direction to learn these basic(?) stuff. tried to be as specific as possible, thanks guys! edit: really sorry for not being clear. the li's are all getting a class dynamically (.listitem). the links can be stored in an array or in a hidden field (or other ul thats hidden) it doesn't really matter where the links are.. $('.listitem').click(function() { $("#elname").text($(this).text()); $("#such").attr("href", $(this).attr('value')); }); I was trying that with the li's having values but I realized that li's can't have values.. thanks again!

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  • jQuery: Show and hide child div when hovering

    - by Björn
    Hi there, I've got a set of items. Each item has two images and some text. For the images I've created a parent div which has an overflow:hidden CSS value. I want to achieve an mouseover effect. As soon as you hover over the images I want to hide the current div and show the second div. Here's a small snippet: <div class="product-images"> <div class="product-image-1"><img src="image1.gif>" /></div> <div class="product-image-2"><img src="images2.gif" /></div> </div> I've created a small jQuery snippet: jQuery(document).ready(function() { jQuery('.product-images').mouseover(function() { jQuery('.product-image-1').hide(); }).mouseout(function() { jQuery('.product-image-1').show(); }); }); Now the problem is that not only the currently hovered child is hidden. Instead all other existing childs are hidden as well. I need something like "this" or "current" but I don't know which jQuery function is the right one. Any idea? Thanks, BJ

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  • Javascript to PHP, mysql uploading, one button pressing solution

    - by user2897858
    my program is generating buttons from a mysql database.When one of the button is pressed, it would uplod the current time and the gps coordinate. Sadly, it only works if the same button is pressed twice, but its not an option, because the button has to dissappear. I would like to have some help in coding how to make that possible the user only need to press the button once for the correct upload.Thanks in advance Here is the full code of my my file: <?php session_start(); ?> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>title</title> </head> <?php $maidatum=date("Ymj"); echo "<script>getLocation();</script>"; //Az adatbázishoz való csatlakozás $conn = mysql_connect("localhost","root","asd"); if(!($conn))die("Nincs conn a kiszolgálóval!".mysql_error()); $adatbazisneve="schtrans"; mysql_select_db($adatbazisneve,$conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); //Combobox $sql = "SELECT Jaratszam,Vezeto FROM user"; $rs = mysql_query($sql) or die(mysql_error()); echo "<form action=\"\" method=\"post\">"; echo<<<nev <select name='Lista'> nev; while($row = mysql_fetch_array($rs)){ echo "<option value='".$row["Jaratszam"]."'>".$row["Vezeto"]."</option>"; }mysql_free_result($rs); echo "</select>"; ///Combox vége echo<<<lekerd <form action="" method="post"> <input type="submit" name="bekuldes" value="Lekérdez" /> </form> </form> lekerd; echo<<<gps <form action="" method="post"> <input type="hidden" name= "longitude" id="longitude"> <input type= "hidden" name ="latitude" id="latitude"> </form> gps; if(isset($_POST["bekuldes"])) { $jaratszam = $_POST['Lista']; $_SESSION['jaratsz']=$jaratszam; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } if(isset($_POST["ido"])) { $hanyadik=$_POST["ido"]; $longitudee="longitude$hanyadik"; $latitudee="latitude$hanyadik"; ?> <script> var x=document.getElementById("log"); function getLocation() { if (navigator.geolocation) { navigator.geolocation.getCurrentPosition(showPosition); } else{x.innerHTML="GPS szolgáltatás nem müködik ezen a böngészon, kérlek értesítsd a rendszergazdát!";} } function showPosition(position) { var latitude = position.coords.latitude; var longitude = position.coords.longitude; document.getElementById("<?php echo $longitudee;?>").value = longitude; document.getElementById("<?php echo $latitudee;?>").value = latitude; } </script> <?php echo "<script>getLocation();</script>"; $latitude=$_POST["latitude"]; $longitude=$_POST["longitude"]; print_r($_POST); $currentime=date("H:i:s"); $acim=$_SESSION['adatok0'][$hanyadik]; $idofeltolt_parancs="UPDATE cim_$maidatum SET ido='$currentime',lat='$latitude',longi='$longitude' WHERE cimid='$acim';"; $feltoltes=mysql_query($idofeltolt_parancs, $conn) or die(mysql_error()); //tryy $jaratszam=$_SESSION['jaratsz']; $lekerdez_parancs="SELECT * FROM cim_$maidatum WHERE jarat=$jaratszam;"; $lekerdez=mysql_query($lekerdez_parancs, $conn); mysql_query("set names 'utf8'"); mysql_query("set character set 'utf8'"); echo "<table border=\"1\">"; echo "<td>Utánvétel</td> <td>Megrendelés összege</td> <td>ISZ</td> <td>Város</td> <td>Utca</td> <td>Megjegyzés</td> <td>Csomagok</td> <td>Raklaphely</td> <td>Súly</td><td>Térfogat</td><td>Latitude</td><td>Longitude</td><td>Ido</td>"; $g=1; //cimszámláló while ($adatok=mysql_fetch_array($lekerdez)) { echo "<tr>"; $_SESSION['adatok0'][$g]=$adatok[0]; echo "<td>$adatok[2]</td> <td>$adatok[3]</td> <td>$adatok[4]</td> <td>$adatok[5]</td> <td>$adatok[6]</td> <td>$adatok[7]</td> <td>$adatok[8]</td> <td>$adatok[9]</td> <td>$adatok[10]</td><td>$adatok[11]</td><td>$adatok[13]</td><td>$adatok[14]</td>"; if ($adatok[12]==null) { echo<<<gomb <form action="" method="post"> <td> <input type="hidden" name= "longitude" id="longitude$g"> <input type= "hidden" name ="latitude" id="latitude$g"> <input type="submit" name="ido" value="$g" /></td> </form> gomb; } else {echo "<td>$adatok[12]</td>";} $g++; } echo "</table>"; } mysql_close($conn); ?> </html>

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  • What is the best way to identify which form has been submitted?

    - by Rupert
    Currently, when I design my forms, I like to keep the name of the submit button equal to the id of the form. Then, in my php, I just do if(isset($_POST['submitName'])) in order to check if a form has been submitted and which form has been submitted. Firstly, are there any security problems or design flaws with this method? One problem I have encountered is when I wish to overlay my forms with javascript in order to provide faster validation to the user. For example, whilst I obviously need to retain server side validation, it is more convenient for the user if an error message is displayed inline, upon blurring an input. Additionally, it would be good to provide entire form validation, upon clicking the submit button. Therefore, when the user clicks on the form's submit button, I am stopping the default action, doing my validation, and then attempting to renable the traditional submit functionality, if the validation passes. In order to do this, I am using the form.submit() method but, unfortunately, this doesn't send the submit button variable (as it should be as form.submit() can be called without any button being clicked). This means my PHP script fails to detect that the form has been submitted. What is the correct way to work around this? It seems like the standard solution is to add a hidden field into the form, upon passing validation, which has the name of form's id. Then when form.submit() is called, this is passed along in place of the submit button. However, this solution seems very ungraceful to me and so I am wondering whether I should: a) Use an alternative method to detect which form has been submitted which doesn't rely rely on passing the submit button. If so what alternative is there? Obviously, just having an extra hidden field from the start isn't any better. b) Use an alternative Javascript solution which allows me to retain my non-Javascript design. For example, is there an alternative to form.submit() which allows me to pass in extra data? c) Suck it up and just insert a hidden field using Javascript.

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  • How to check whether a CGPoint is inside a UIImageView?

    - by Horace Ho
    In touchesBegan: CGPoint touch_point = [[touches anyObject] locationInView:self.view]; There are tens of UIImageView around, stored in a NSMutableArray images. I'd like to know is there a built-in function to check if a CGPoint (touch_point) is inside one of the images, e.g.: for (UIImageView *image in images) { // how to test if touch_point is tapped on a image? } Thanks Follow up: For unknown reason, pointInside never returns true. Here is the full code. - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { UITouch *touch = [touches anyObject]; touch_point = [touch locationInView:self.view]; for (UIImageView *image in piece_images) { if ([image pointInside:touch_point withEvent:event]) { image.hidden = YES; } else { image.hidden = NO; } NSLog(@"image %.0f %.0f touch %.0f %.0f", image.center.x, image.center.y, touch_point.x, touch_point.y); } } although I can the two points are sometimes identical in the NSLog output ... I also tried: if ([image pointInside:touch_point withEvent:nil]) the result is the same. never returns a true. To eliminate the chance of anything goes with with the images. I tried the following: if (YES or [image pointInside:touch_point withEvent:event]) all images are hidden ater the first click on screen.

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  • Easyslider content loading sooner than I would like.

    - by Jason
    I am using a jquery easyslider on a page and also pulling some rss feeds using php. Pulling the feeds is taking a long time and as a result delaying the load of the easy slider until after the feeds have been pulled in. This can be seen here: http://perksconsulting.com/dev/ I am looking for a way to display a loader image in the space where the easy slider is so the images do not appear stacked vertically for a few seconds while the php is interpreted by the server, but I have never used a loader image and am not sure how I would do that. I am currently using this script to hide the page contents until everything is loaded, but the one thing it is not hiding is the images from the easy slider: <SCRIPT TYPE="text/javascript" LANGUAGE="javascript"> function waitPreloadPage() { //DOM if (document.getElementById){ document.getElementById('prepage').style.visibility='hidden'; }else{ if (document.layers){ //NS4 document.prepage.visibility = 'hidden'; } else { //IE4 document.all.prepage.style.visibility = 'hidden'; } } } // End --> </SCRIPT> Ideally I would like to be able to display a loading image in place of the slider in the middle of the page until everything loads. Could anyone tell me how to do this? Thank you.

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  • Image jQuery scroller in a container. (like facebook cropper) can't get values of position.

    - by Stefan
    Hey all. Having a reallllll mind pain. I have a php image uploader which is all good and sotring the file and the jquery ajax is returning the image in an ammended html div with a div set up like this: #crop-holder { width:80px; height:80px; margin:10px 10px 20px 10px; border:1px #c0c0c0 solid; overflow:hidden; cursor:move; } The image is viewing fine and I am using the jquery scrollview plugin: http://code.google.com/p/jquery-scrollview/ I have tried adding a few lines to the plugin to store variables of scrollTop and Left and then replacing two hidden input values with x and y in my page. And then on the returned ajax html in the div I am trying to on a button click (for example) retrieve the values of the two hidden inputs.... Heres what i added to the plugin (i'm no js expert!): .mouseout(function(){ var _m = this.m; var lasty = _m.scrollTop(); getElementById("ycord").value = lasty; var lastx = _m.scrollLeft(); getElementById("xcord").value = lastx; self.stopgrab(); }) Still no luck!! How can I get the scrollTop and scrollLeft and successfully prepare them for sending onto another php script!? Thanks:) stefpretty

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  • Passing a variable from beggining to end - Paypal

    - by Phil Jackson
    Hi all, I'be been at this for days and i cant seem to figure it out. All i want to do is when subscribe button is pushed, a variable is send ( post get i dont care ) payment is completed and landed on the success page, with my variable! From what i can gather this should be able to do it: <form action="https://www.sandbox.paypal.com/cgi-bin/webscr" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="hidden" name="hosted_button_id" value="0000000"> <Input type="hidden" name="custom" value="<?php md5($code.microtime()); ?>"/> <input type="image" src="https://www.sandbox.paypal.com/en_US/i/btn/btn_subscribeCC_LG.gif" border="0" name="submit" alt="PayPal - The safer, easier way to pay online!"> <img alt="" border="0" src="https://www.sandbox.paypal.com/en_US/i/scr/pixel.gif" width="1" height="1"> </form> Any help much appreciated ( and yes I've read paypal and sandbox documentation, just not that good at reading. )

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  • MVC Html.ActionLink with post funtionality?

    - by Levitikon
    I'm checking to see if anyone has written an MVC extension for Html.ActionLink that you can pass in Post parameters like such: <% Html.ActionLink("Click me", "Index", "Home", new { MyRouteValue = "123" }, null, new { postParam1 = "a", postParam2 = "b" }); %> That would render the link like normal but having an onClick event that submits an also rendered form with an Action url for the Action, Controller, and Route Values with additional hidden inputs from the Post Parameters like such: <a href="#" onClick="$('#theform').submit(); return false;">Click me</a> <form id="theform" action="/Home/Index/123" method="post"> <input type="hidden" name="postParam1" value="a"> <input type="hidden" name="postParam2" value="b"> </form> I'm looking to redirect users to various pages with potentially a lot of data. Not only from page to page, but from email to page also. This would be highly reusable and I think would clean up a lot of code, and would save a bunch of time writing this if its already floating around out there. I hate recreating the wheel when I don't have to. Thanks!

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  • How do I keep users from spoofing data through a form?

    - by Jonathan
    I have a site which has been running for some time now that uses a great deal of user input to build the site. Naturally there are dozens of forms on the site. When building the site, I often used hidden form fields to pass data back to the server so that I know which record to update. an example might be: <input type="hidden" name="id" value="132" /> <input type="text" name="total_price" value="15.02" /> When the form is submitted, these values get passed to the server and I update the records based on the data passed (i.e. the price of record 132 would get changed to 15.02). I recently found out that you can change the attributes and values via something as simple as firebug. So...I open firebug and change the id value to "155" and the price value to "0.00" and then submit the form. Viola! I view product number 155 on the site and it now says that it's $0.00. This concerns me. How can I know which record to update without either a query string (easily modified) or a hidden input element passing the id to the server? And if there's no better way (I've seen literally thousands of websites that pass the data this way), then how would I make it so that if a user changes these values, the data on the server side is not executed (or something similar to solve the issue)? I've thought about encrypting the id and then decrypting it on the other side, but that still doesn't protect me from someone changing it and just happening to get something that matches another id in the database. I've also thought about cookies, but I've heard that those can be manipulated as well. Any ideas? This seems like a HUGE security risk to me.

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  • SIFR, JAVASCRIPT & PHP - How to apply SIFR to dynamically loaded content.

    - by user311039
    Well here's the problem: I have a PHP index page which uses show/hide layers javascript. I am using the on menu.click function to show and hide content relevant to each menu. On.click all divs are hidden except the content for that menu item , which fades in. The content relating to each menu item are displayed within separate DIVS. The property is applied to all the text within all the divs. See: http://jobe-group.com/jobeco/uk/2010live/dynamic/content/index.php# The trouble is that SIFR only appears to be applied to the displayed on.load when the page is first loaded. When this is hidden and the other s shown through the "show" function they load in classic CSS fonts without the SIFR applied. Is this unavoidable with the SIFR setup. Or am I not calling the divs properly. I have set the SIFR to apply to the selector and indeed it works fine on the for the displayed on load. It doesn't work for the within other . In theory I would think its possible to load the SIFR on all divs on page.load even if those divs are presently visibility:hidden. What's the verdict on this? Hope someone can help. Cheers, John

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  • XML configuration of Zend_Form: child nodes and attributes not always equal?

    - by Cez
    A set of forms (using Zend_Form) that I have been working on were causing me some headaches trying to figure out what was wrong with my XML configuration, as I kept getting unexpected HTML output for a particular INPUT element. It was supposed to be getting a default value, but nothing appeared. It appears that the following 2 pieces of XML are not equal when used to instantiate Zend_Form: Snippet #1: <form> <elements> <test type="hidden"> <options ignore="true" value="foo"/> </test> </elements> </form> Snippet #2: <form> <elements> <test type="hidden"> <options ignore="true"> <value>foo</value> </options> </test> </elements> </form> The type of the element doesn't appear to make a difference, so it doesn't appear to be related to hidden fields. Is this expected or not?

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  • Making a button click and process using javascript with Asp.Net

    - by user944919
    I'm having two buttons and one button is hidden. Now when I click the visible button I need to do two things 1.Open Iframe. 2.Automatically make the 2nd Button(Hidden)to be clicked. When the second button is clicked I need to display the message on top of the IFrame which I have mentioned as function showStickySuccessToast() Now I am able to open IFrame but I'm unable to make the Hidden button clicked automatically. This is what I'm having: <script type="text/javascript"> $(document).ready(function(){ $("#<%=Button1.ClientID%>").click(function(event){ $('#<%=TextBox1.ClientID%>').change(function () { $('#various3').attr('href', $(this).val()); }); }); function showStickySuccessToast() { $().toastmessage('showToast', { text: 'Finished Processing!', sticky: false, position: 'middle-center', type: 'success', closeText: '', close: function () { } }); } }) </script> Here are my two buttons how I'm working with: <a id="various3" href="#"><asp:Button ID="Button1" runat="server" Text="Button" OnClientClick="Button2_Click"/></a> <asp:Button ID="Button2" runat="server" Text="Button" Visible="False" OnClick="Button2_Click"/> And in the button2_Click event: Protected Sub Button2_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles Button2.Click System.Web.UI.ScriptManager.RegisterClientScriptBlock(Page, GetType(Page), "Script", "showStickySuccessToast();", True) End Sub

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  • Prototype: Form.serialize missing some inputs (due to table?)

    - by Chris
    I'm using JavaScript Prototype (through Ruby on Rails) to handle some Ajax calls; but in one particular case I'm missing a field from the form. I have a layout like this: +---------+---------+ | Thing 1 | Thing 2 | +---------+---------+-----------+ | o Opt 1 | o Opt 1 | <Confirm> | | o Opt 2 | o Opt 2 | | +---------+---------+-----------+ Opt 1 and 2 are Radio buttons, Confirm is a button. The entire table is wrapped in a form, with code like: <form action="javascript:void(0)"> <input type="hidden" name="context" value="foo" /> <input type="hidden" name="subcontext" value="bar" /> <table> <tr><td>Thing 1</td><td>Thing2</td></tr> <tr><td> <input type="radio" name="choice" value="1.1" />Opt 1<br /> <input type="radio" name="choice" value="1.2" />Opt 2<br /> </td><td> <input type="radio" name="choice" value="2.1" />Opt 1<br /> <input type="radio" name="choice" value="2.2" />Opt 2<br /> </td><td> <input name="choice_btn" type="button" value="Confirm" onclick="new AJAX.Updater('my_form', '/process_form', {asynchronous:true, evalScripts:true, parameters:Form.serialize(this.form)}); return false;" /> </td></tr> </table> </form> But I can see that the POST generated by clicking the Confirm button contains the foo and bar values for the hidden fields, but not the choice of the radio buttons. Is this because I've got a table inside my form? How can I get around this?

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  • DRY jQuery for RESTful PUT/DELETE links

    - by Aupajo
    I'm putting together PUT/DELETE links, a la Rails, which when clicked create a POST form with an hidden input labelled _method that sends the intended request type. I want to make it DRYer, but my jQuery knowledge isn't up to it. HTML: <a href="/articles/1" class="delete">Destroy Article 1</a> <a href="/articles/1/publish" class="put">Publish Article 1</a> jQuery: $(document).ready(function() { $('.delete').click(function() { if(confirm('Are you sure?')) { var f = document.createElement('form'); $(this).after($(f).attr({ method: 'post', action: $(this).attr('href') }).append('<input type="hidden" name="_method" value="DELETE" />')); $(f).submit(); } return false; }); $('.put').click(function() { var f = document.createElement('form'); $(this).after($(f).attr({ method: 'post', action: $(this).attr('href') }).append('<input type="hidden" name="_method" value="PUT" />')); $(f).submit(); return false; }); });

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  • Fragments keep going back to the default position when MapView is Zoomed In/Out

    - by hectichavana
    I have an activity with 3 fragments displayed, a MapActivity, a ListActivity, and a (normal) DetailsActivity. The ListActivity and DetailsActivity is placed over the MapActivity. There's a function to hide both ListActivity and DetailsActivity with an Animation, and onAnimationEnd() I set a new layout for the hidden Activity. The problem I'm facing is, everytime one of the ListActivity or DetailsActivity hidden (picture State 2), and then I pinch the screen on the MapActivity to zoom the map, it always goes back to the default view (picture State 1). The closed Activities are automatically opened again. Does anybody know how to prevent the hidden fragments from going to the first state again when I pinch the MapActivity? this is an example of the function how I hide the DetailsActivity(): public void hideDetailview() { final Animation close = AnimationUtils.loadAnimation(this, R.anim.close); close.setFillEnabled(true); close.setAnimationListener(closeDetailAnimationListener); fragment_detail.startAnimation(close); Toast.makeText(MainFragmentActivity.this,WWHApplication.getDrawer(), Toast.LENGTH_SHORT).show(); } private AnimationListener closeDetailAnimationListener = new AnimationListener() { @Override public void onAnimationStart(Animation animation) { } @Override public void onAnimationRepeat(Animation animation) { } @Override public void onAnimationEnd(Animation animation) { int newLeft = -330; fragment_detail.layout(newLeft, fragment_detail.getTop(), newLeft + fragment_detail.getMeasuredWidth(), fragment_detail.getTop() + fragment_detail.getMeasuredHeight()); } };

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  • jQuery API counter++ pause on hover and then resume

    - by Rory
    I need to have this counter pause {stay on current div) while mouseover or hover and resume counter when mouseout. I have tried many ways but still new to jQuery API. <div id="slide_holder"> <div id="slide1" class="hidden"> <img src="images/crane2.jpg" class="fill"> </div> <div id="slide2" class="hidden"> <img src="images/extend_boom.png" class="fill"> </div> <div id="slide3" class="hidden"> <img src="images/Transformers-Bumblebee.jpg" class="fill"> </div> <script> $(function () { var counter = 0, divs = $('#slide1, #slide2, #slide3'); function showDiv () { divs.hide() // hide all divs .filter(function (index) { return index == counter % 3; }) // figure out correct div to show .fadeIn('slow'); // and show it counter++; }; // function to loop through divs and show correct div showDiv(); // show first div setInterval(function () { showDiv(); // show next div }, 3 * 1000); // do this every 10 seconds }); </script>

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  • Bootstrap stop Modal showing on page load

    - by Subby
    I only want the Modal to show when I click on a certain button. At the moment, the Modal shows itself whenever I load the page. Can someone please tell me where I am going horribly wrong? <a href="#myModal" role="button" class="btn" data-toggle="modal">Launch demo modal</a> <div class="modal" id="myModal" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true"> <div class="modal-header"> <button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button> <h3 id="myModalLabel">Modal header</h3> </div> <div class="modal-body"> <p>One fine body…</p> </div> <div class="modal-footer"> <button class="btn" data-dismiss="modal" aria-hidden="true">Close</button> <button class="btn btn-primary">Save changes</button> </div> </div> I am using ASP.NET MVC 3 EDIT: I am NOT using any Javascript at the moment.

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  • Upload to a PHP Server, using Ajax ( XMLHttp POST)

    - by Krishnanunni
    Right now i'm using the below method to Upload a file to PHP <form enctype="multipart/form-data" action="http://sserver.com/fileupload.php" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="30000000" /> <input type="hidden" name="filename" value="file_uploaded.gif" /> <input type="hidden" name="username" value="foobar"/> Please choose a file: <input name="uploaded" type="file" /><br /> <input type="submit" value="Upload" /> </form> I read the $_POST and $_FILE in php to complete upload like this. $target = $_SERVER['DOCUMENT_ROOT']."/test/upload/"; $target = $target . basename( $_FILES['uploaded']['name']) ; echo $target; $ok=1; if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)) { echo "The file ". basename( $_FILES['uploaded']['name']). " has been uploaded"; } else { echo "Sorry, there was a problem uploading your file."; } My questions is , can i change the above said code (HTML) to an Ajax XMLHttpRequest without changes in PHP.

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  • CSS/IE7: The Case of the Extending Background-Image

    - by dmr
    The situation: There a collapsible advanced search box. It is made up of a search box div that contains a boxhead div and a boxbody div. Inside the boxbody div, there is a searchToggle div. When the user clicks "Show/Hide", the display style property of the searchToggle div is toggled between block and none. (The search fields are hidden and the search boxbody gets much smaller). The 2 background-images for the body of the search box are set via the css of the searchBox div and the boxbody div. In IE7, when the searchToggle div is hidden, the background-image from the searchBox div extends on the left more than it should (see Here). It shows up correctly when the display of the searchToggle div is block (see Here). Everything show up correctly, in both cases, in IE8 and FF. The relevant HTML: <div class="searchBox"> <div class="boxhead"> <h2></h2> </div> <div class="boxbody"> <div id="searchToggle" name="searchToggle"> </div> </div> </div> The relevant CSS: .searchBox { margin: 0 auto; width: 700px; background: url(/images/myImageRight-r.gif) no-repeat bottom right; font-size: 100%; text-align: left; overflow: hidden; } .boxbody { margin: 0; padding: 5px 30px 31px; background-image: url(/images/myImageLeft.gif); background-repeat: no-repeat; background-position: left bottom; }

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