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  • Any way to turn off quips in OOWeb?

    - by Misha Koshelev
    http://ooweb.sourceforge.net/tutorial.html Not really a question, but I can't seem to stop writing stuff like this. Maybe someone will find it useful. I know rewriting an HTTP server is not the way to turn off the quips ;) /* Copyright 2010 Misha Koshelev. All Rights Reserved. */ package com.mksoft.common; import java.io.BufferedReader; import java.io.InputStreamReader; import java.io.IOException; import java.io.PrintWriter; import java.io.UnsupportedEncodingException; import java.net.URLDecoder; import java.text.SimpleDateFormat; import java.util.Date; import java.util.LinkedHashMap; import java.net.ServerSocket; import java.net.Socket; /** * Simple HTTP Server. * * @author Misha Koshelev */ public class HttpServer extends Thread { /* * Constants */ /** * 404 Not Found Result */ protected final static String result404NotFound="<html><head><title>404 Not Found</title></head><body bgcolor='#ffffff'><h1>404 Not Found</h1></body></html>"; /* * Variables */ /** * Port on which HTTP server handles requests. */ protected int port; public int getPort() { return port; } public void setPort(int _port) { port=_port; } /* * Constructors */ public HttpServer(int _port) { setPort(_port); } /* * Helpers */ /** * Errors */ protected void error(String message) { System.err.println(message); System.err.flush(); } /** * Debugging */ protected boolean debugOutput=true; protected void debug(String message) { if (debugOutput) { error(message); } } /** * Lock object */ private Object lock=new Object(); /** * Should we quit? */ protected boolean doQuit=false; /** * Are we done? */ protected boolean areWeDone=false; /** * Process POST request headers */ protected String processPostRequest(String url,LinkedHashMap<String,String> headers,String inputLine) { debug("HttpServer.processPostRequest: url=\""+url); if (debugOutput) { for (String key: headers.keySet()) { debug("HttpServer.processPostRequest: headers."+key+"=\""+headers.get(key)+"\""); } } debug("HttpServer.processPostRequest: inputLine=\""+inputLine+"\""); try { inputLine=new URLDecoder().decode(inputLine,"UTF-8"); } catch (UnsupportedEncodingException uee) { uee.printStackTrace(); } String[] keyValues=inputLine.split("&"); LinkedHashMap<String,String> post=new LinkedHashMap<String,String>(); for (int i=0;i<keyValues.length;i++) { String keyValue=keyValues[i]; int equals=keyValue.indexOf('='); String key=keyValue.substring(0,equals); String value=keyValue.substring(equals+1); post.put(key,value); } return post(url,headers,post); } /** * Server loop (here for exception handling purposes) */ protected void serverLoop() throws IOException { /* Start server socket */ ServerSocket serverSocket=null; try { serverSocket=new ServerSocket(getPort()); } catch (IOException ioe) { ioe.printStackTrace(); System.exit(1); } Socket clientSocket=null; while (true) { /* Quit if necessary */ if (doQuit) { break; } /* Accept incoming connections */ try { clientSocket=serverSocket.accept(); } catch (IOException ioe) { ioe.printStackTrace(); System.exit(1); } /* Read request */ BufferedReader in=null; String inputLine=null; String firstLine=null; String blankLine=null; LinkedHashMap<String,String> headers=new LinkedHashMap<String,String>(); try { in=new BufferedReader(new InputStreamReader(clientSocket.getInputStream())); while (true) { if (blankLine==null) { inputLine=in.readLine(); } else { /* POST request, read Content-length bytes */ int contentLength=new Integer(headers.get("Content-Length")).intValue(); StringBuilder sb=new StringBuilder(contentLength); for (int i=0;i<contentLength;i++) { sb.append((char)in.read()); } inputLine=sb.toString(); break; } if (firstLine==null) { firstLine=inputLine; } else if (blankLine==null) { if (inputLine.equals("")) { if (firstLine.startsWith("GET ")) { break; } blankLine=inputLine; } else { int colon=inputLine.indexOf(": "); String key=inputLine.substring(0,colon); String value=inputLine.substring(colon+2); headers.put(key,value); } } } } catch (IOException ioe) { ioe.printStackTrace(); } /* Process request */ String result=null; firstLine=firstLine.replaceAll(" HTTP/.*",""); if (firstLine.startsWith("GET ")) { result=get(firstLine.replaceFirst("GET ",""),headers); } else if (firstLine.startsWith("POST ")) { result=processPostRequest(firstLine.replaceFirst("POST ",""),headers,inputLine); } else { error("HttpServer.ServerLoop: Unhandled request \""+firstLine+"\""); } debug("HttpServer.ServerLoop: result=\""+result+"\""); /* Send response */ PrintWriter out=null; try { out=new PrintWriter(clientSocket.getOutputStream(),true); } catch (IOException ioe) { ioe.printStackTrace(); } if (result!=null) { out.println("HTTP/1.1 200 OK"); } else { out.println("HTTP/1.0 404 Not Found"); result=result404NotFound; } Date now=new Date(); out.println("Date: "+new SimpleDateFormat("EEE, d MMM yyyy HH:mm:ss z").format(now)); out.println("Content-Type: text/html; charset=UTF-8"); out.println("Content-Length: "+result.length()); out.println(""); out.print(result); /* Clean up */ out.close(); if (in!=null) { in.close(); } clientSocket.close(); } serverSocket.close(); areWeDone=true; synchronized(lock) { lock.notifyAll(); } } /* * Methods */ /** * Run server on port specified in constructor. */ public void run() { try { serverLoop(); } catch (IOException ioe) { ioe.printStackTrace(); System.exit(1); } } /** * Process GET request (should be overwritten). */ public String get(String url,LinkedHashMap<String,String> headers) { debug("HttpServer.get: url=\""+url+"\""); if (debugOutput) { for (String key: headers.keySet()) { debug("HttpServer.get: headers."+key+"=\""+headers.get(key)+"\""); } } if (url.equals("/")) { return "<html><head><title>HttpServer GET Test Page</title></head>\r\n"+ "<body bgcolor='#ffffff'>\r\n"+ "<center><h1>HttpServer GET Test Page</h1></center>\r\n"+ "<hr />\r\n"+ "<center><table>\r\n"+ "<form method='post' action='/'>\r\n"+ "<tr><td align=right>Test 1:</td>\r\n"+ " <td><input type='text' name='text 1' value='test me !!! !@#$'></td></tr>\r\n"+ "<tr><td align=right>Test 2:</td>\r\n"+ " <td><input type='text' name='text 2' value='type smthng'></td></tr>\r\n"+ "<tr><td>&nbsp;</td>\r\n"+ " <td align=right><input type='submit' value='Submit'></td></tr>\r\n"+ "</form>\r\n"+ "</table></center>\r\n"+ "<hr />\r\n"+ "<center><a href='/quit'>Shutdown Server</a></center>\r\n"+ "</html>"; } else if (url.equals("/quit")) { quit(); return ""; } else { return null; } } /** * Process POST request (should be overwritten). */ public String post(String url,LinkedHashMap<String,String> headers,LinkedHashMap<String,String> post) { debug("HttpServer.post: url=\""+url+"\""); if (debugOutput) { for (String key: headers.keySet()) { debug("HttpServer.post: headers."+key+"=\""+headers.get(key)+"\""); } } if (url.equals("/")) { String result="<html><head><title>HttpServer Post Test Page</title></head>\r\n"+ "<body bgcolor='#ffffff'>\r\n"+ "<center><h1>HttpServer Post Test Page</h1></center>\r\n"+ "<hr />\r\n"+ "<center><table>\r\n"+ "<tr><th>Key</th><th>Value</th></tr>\r\n"; for (String key: post.keySet()) { result+="<tr><td align=right>"+key+"</td><td align=left>"+post.get(key)+"</td></tr>\r\n"; } result+="</table></center>\r\n"+ "</html>"; return result; } else { return null; } } /** * Wait for server to quit. */ public void waitForCompletion() { while (areWeDone==false) { synchronized(lock) { try { lock.wait(); } catch (InterruptedException ie) { } } } } /** * Shutdown server. */ public void quit() { doQuit=true; } }

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  • Toshiba Laptop Problem - Black Screen on Startup [using Win Vista]

    - by BubblySue
    Hi guys, can anyone help me on my problem? I only see black screen after the startup.. It just shows the logo and the status bar upon start, then it goes black screen with moveable cursor. I tried alt+ctrl+del, but it doesn't work. I pressed shift 5 times and it makes a sound. I already removed battery and restarted it, but still the same. I can go to safe mode and scanned thru there. Still, desktop won't show up. Don't know what else to check? Been searching the net for solutions. Please help? :(

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  • Making a window pop in and out of the edge of the screen

    - by Brad
    I'm trying to re-write an application I have for Windows in Objective-C for my Mac, and I want to be able to do something like Mac's hot corners. If I move my mouse to the left side of the screen it will make a window visible, if I move it outside of the window location the window will hide again. (window would be pushed up to the left side of screen). Does anyone know where I can find some demo code (or reference) on how to do this, or at least how to tell where the mouse is at, even if the current application is not on top. (not sure how to word this, too used to Windows world). Thank you -Brad

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  • Evenly distribute items on the screen

    - by abolotnov
    I am trying to solve this little puzzle (the algorithm): I have N image icons and I want to distribute them evenly on users screen. Say, I put them in a table. If there is one image, there will be one cell in a table. If two - one row with two columns, if three - one row and three columns, if four - two rows, two columns... and so on until row space is gone and since then the table should only grow in columns without adding extra rows. I'm trying to figure an algorithm for this and perhaps this is something that has a solution already somewhere? My attempt is so far something like this: obtain_max_rows() obtain_visible_columns() if (number_of_pictures > max_rows*max_columns) { columns = roundup(number_of_pictures/max_rows) for(max_rows){generate row;for columns{generate column}} } else { **here comes to trouble...** } This logic is bit silly though - it somehow needs to think cases where there are 12 pictures on first screen and 2 on the other trying to balance it say 8/6 or somehow like that.

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  • popup panel that docks to the bottom of the screen

    - by Michael Wiles
    How do I create a pop panel that docks to the bottom of the screen... The way that I'm doing this is by setting the styling as such: bottom: 10px; position: absolute; This will always set the panel to 10 px from the bottom of the browser window. The problem is that gwt (or gwtp for that matter) is insisting on setting the right and the top of the panel and thus overriding my styling. If I use chrome's element explorer and disable the right and top style rules I get the correct behaviour so one way of doing it is somehow disabling gwt setting of the location of the panel on the screen...?

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  • drawRect is not refreshing the screen

    - by coure06
    I have this code in my drawRect method float aValue = .0167f; float fValue = 20; for(int i=1; i<=6; i++) { CGContextSelectFont(context, "Arial", fValue, kCGEncodingMacRoman); CGContextSetCharacterSpacing(context, 0); CGContextSetTextDrawingMode(context, kCGTextFill); NSString *hString = [[NSString alloc] initWithFormat:@"%i",i]; CGContextSetRGBFillColor(context, 1, 1, 1, aValue); CGContextShowTextAtPoint(context, i*25, i*16, [hString UTF8String], [hString length]); aValue += 0.167; fValue += 1; } I am calling a method using NSTimer like this staticTimer = [NSTimer scheduledTimerWithTimeInterval:1.0 target:self selector:@selector(refreshUIView) userInfo:nil repeats:YES]; here is the refreshUIView -(void)refreshUIView { [self setNeedsDisplay]; } Problem is that drawRect is not clearing the screen, its just over writing what have been written last time on screen.

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  • android:black screen switching between activity

    - by 100rabh
    Hi, I am using below code from one of my activity to start another Intent viewIntent = new Intent (getApplicationContext (), landingPage.class); Bundle b = new Bundle (); b.putString ("ApplicationName", a_Bean.getApplicationName ()); if (landingPage.getInstanceCount () < 1) bp.landingPage_ProgressDialog = ProgressDialog.show (ViewAllApp.this, "Please wait...", "Retrieving data...", true, false); viewIntent.putExtras (b); viewIntent.addFlags (Intent.FLAG_ACTIVITY_CLEAR_TOP); startActivityForResult (viewIntent,10); Thread background=new Thread(new Runnable() { public void run() { Progresshandler.sendMessage(handler.obtainMessage());//finishes progressDialog }}); background.start (); but after startactivity it shows a black screen & then displays new activity. Can I make progressdialog to be shown while the black screen is displayed??

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  • Creating a loading screen in HTML5

    - by espais
    I am having some issues finding a decent tutorial for generating a loading style screen with regards to HTML5. To be quite honest I'm not sure exactly where to begin... My project is essentially a simple HTML5 game, where I'll be loading in various sprite sheets and tilesets. They'll be reasonably small, but I'd like to show a little loading spinner instead of a blank screen while all the resources are loaded. Much appreciated if somebody could point me in the right direction, be it decent links or code samples to get me going...my Google-fu is lacking today! For clarification, I need to figure out how to load the resources themselves, as opposed to finding a spinner. For instance, how to calculate that X% has loaded.

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  • Android: How to invalidate multiple parts of screen

    - by user342731
    I need to be able to selectively invalidate multiple (about 20) rectangles on the screen for performance reasons, so tried the following: Vector<Rect> myRects = new Vector<Rect>(); // ... add some Rects to myRects for (Rect r : myRects) { invalidate(r); } However this seems to invalidates a union of all the Rect's, forming one large rectangle which covers all of small ones I'm trying to invalidate. How can one invalidate multiple areas on the screen, and only those areas?

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  • Screen capture during testing

    - by Edwward
    This is an application for reviewing performance tests. Simple in concept, tricky to describe. Picture: 1) Recording interactions with a WPF program so the inputs can be played back. 2) Playing the inputs back while doing a continuous screen capture. 3) Capturing wall time as well as continuous CPU percentages during playback. 4) Repeating steps (2) and (3) lots of times. 5) Writing the relevant stuff out to files/db. 6) Reading it and putting it all in a fancy UI for easy review/analysis. The killer for me is (2). I could use some guidance on a good, possibly commercial, screen capture SDK. I would also welcome the news that my whole problem already has a solution. And of course any thoughts on the overall idea would also be great. Thanks. Ed

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  • UIView Horizontal scroll for a part of a screen

    - by Futur
    Hi Friends, I have a requirement for scrolling a part of a view horizontally. there are 2 views, mainView(0,70,320*2,400) and a horizontalView(0,0,320*2,160)[this horizontalView has an internal UIScrollView with the same frame] So the horizontal view will occupy the first section of the screen and it should only be scrollable horizontally (and the other part of the mainView - the other part of the screen should be static). how to achieve this? i am getting a general scroll for the whole page not for the first section alone. am i in the right direction for this problem? please advice Thank you

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  • [C++]Two windows fullscreen on two different screen.

    - by sirithang
    Hi! I'm actually working on an app to display an image onto a Dome. The dome projection system is constitued of two projector and a pc running a GentoO Linux and KDE, with nvidia TwinView system. Since here i've used SDL to display a fullscreen windows, and it display my app onto the two screen. But i just figured that i need to project two different images, one on each projector. That's why i search for a solution to display a fullscreen window on the first screen (projector) and another on the second. But SDL fullscreen just extend the window to the two screens. I can use any librairie (since it light and free, as i will wrap it into my small "API"), or change display setting. BTW it would be nice to have openGL support, since SDL manage only one window ^^"

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  • android: how to create multiply views screen?

    - by avi cohen
    hello, i'm beginner at android development. i want to create an activity, which shows a question with 4 answers, and at the bottom of the screen i want to place a timer. i have already found timer example, and i created a question with the answers. the problem that they are 2 different projects and activities, and i am looking for the best way to implement it. i think i can't show 2 activities on one screen, but i can show 2 views or shell i use the ViewGroup, or maybe to copy-paste one of the activities code to another ( its the easiest way but probably the most ugliest way to implement it). please tell me what is the best way, that i will study and not to waste time to study all the ways and only then to choose one of them. thanks!

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  • Removing a UIView from its superView and expanding its frame to full screen

    - by Magic Bullet Dave
    I have an object that is a subclass of UIView that can be added to a view hierarchy as a subView. I want to be able to remove the UIView from its superView and add it as a subView of the main window and then expand to full screen. Something along the lines of: // Remove from superView and add to mainWindow [self retain]; [self removeFromSuperView]; [self addSubView:mainWindow]; // Animate to full screen [UIView beginAnimations:@"expandToFullScreen" context:nil]; [UIView setAnimationDuration:1.0]; self.frame = [[UIScreen mainScreen] applicationFrame]; [UIView commitAnimations]; [self release]; Firstly am I on the right lines? Secondly, is there an easily way for the object to get a pointer to the mainWindow? Thanks Dave

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  • Display CFUserNotification on iPhone lock screen

    - by user1768826
    I am developing an iPhone app that need to display some message on lock screen. I have tried to use local notification or CFUserNotification but neither of them can display the message on top of the lock screen. For CFUserNotification I have tried kCFUserNotificationAlertTopMostKey (refer this similar question) but it still not work. I am not going to hook springboard since my phone is not jailbreak. I have found an app do implement it and I have tested on my none-jailbreak iPhone iOS 6.0, don't know how to implement this. Any help much appreciated.

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  • CSS Ease-in-out to full screen

    - by Aditya Singh
    I have a black background div of a size which contains an image. <div id="Banner"> <img onclick="expand();" src="hola.jpg"> </div> #Banner { position:relative; height:50px; width:50px; margin:0 auto; background-color:#000000; -webkit-transition: all 0.5s ease-in-out 0.5s; -moz-transition: all 0.5s ease-in-out 0.5s; -o-transition: all 0.5s ease-in-out 0.5s; transition: all 0.5s ease-in-out 0.5s; } <script type="text/javascript"> function expand(){ document.getElementById('Banner').style['height'] = '250'; document.getElementById('Banner').style['width'] = '250'; } </script> So when the user clicks on the image, the div transitions to 250, 250. My problem is that, i want it to to transition to full screen. The following javascript function does expand to fullscreen but the transition effect doesn't come. I need to do it from a javascript code without jquery. function expand(){ document.getElementById('Banner').style['position'] = 'absolute'; document.getElementById('Banner').style['height'] = '100%'; document.getElementById('Banner').style['width'] = '100%'; document.getElementById('Banner').style['top'] = '0'; document.getElementById('Banner').style['left'] = '0'; } Please advice. Update : Solution Roger below has provided with an alternative solution. This takes care if the document has already been scrolled and is another place. Will expand the div to full browser screen. sz=getSize(); //function returns screen width and height in pixels currentWidth=200; currentHeight=200; scalex=sz.W/currentWidth; scaley=sz.H/currentHeight; transx=0-((expandingDiv.offsetLeft+(currentWidth/2))-(sz.W/2))+document.body.scrollLeft; transy=0-((expandingDiv.offsetTop+(cuttentHeight/2))-(sz.H/2))+document.body.scrollTop; transx = transx.toString(); transy = transy.toString(); document.getElementById("Banner").style['-webkit-transform'] = 'translate('+transx+'px,'+transy+'px) scale('+scalex+','+scaley+')';

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  • Android: Get the screen resolution / pixels as integer values

    - by poeschlorn
    Hi guys, this is a really simple question on which I've found no answer :/ How can I quickly access the screen resolution (width, height) as integer values? I've tried this one, but it always shows zero on my emulator: DisplayMetrics dm = new DisplayMetrics(); int width = dm.widthPixels / 2; In my case I want to dynamically create a table with tableRows, each containing two cols. This cols all shall fill half of the screen in width. Can someone give me a hint?

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  • MFMessageComposeViewControllerDelegate error - black screen

    - by user1053839
    I'm using the following code to show in-app sms. My app don't have a status bar. (I'm using 320x480 pixels screen in portrait view). the problem is that when I load the controller, the screen becomes black as you can see from the image... http://desmond.imageshack.us/Himg211/scaled.php?server=211&filename=schermata092456187alle1.png&res=landing this is the code: MFMessageComposeViewController *picker = [[MFMessageComposeViewController alloc] init]; picker.messageComposeDelegate = self; picker.recipients = [NSArray arrayWithObject:@"123456789"]; // your recipient number or self for testing picker.body = @"test"; [self presentModalViewController:picker animated:YES];

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  • Why does the last row of my tableview not align to the bottom of the screen

    - by Liam
    I have a view which consists of a tableview and a navigation bar. For my tableview I have implemented a 'Load more' row which will load current + pagesize every time it is clicked The way the loading works is very simple, every time it is clicked I just request the amount of rows I want to display e.g. 5, 10, 15 and so on. This request populates an array and I call [self.tableView reloadData] The issue I am experiencing is that when I go to the tableview the first time, it correctly loads and displays the tableview. However, if I 'Load more' it returns the correct amount and displays the correct number of cells but the last cell will not fit properly at the bottom of the screen, about 1/2 of it (or roughly the size of the navigation bar of the cell) appears below the bottom of the screen. I thought it was sufficient to just tell the tableview to reload itself. Do I need to use [self.tableView insertRowsAtIndexPaths ...] to do this.

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  • matlab: how to transform screen pixels into specific coordinates

    - by user3137385
    I have to draw a curve captured on a image using screen pixels (mouse clicks) into a coordinate system. E.g.: Pixels on the screen, from left to right (130 px to 970 px) correspond to the x-axis of my coordinate system (1000 to 6000). Pixels from bottom to top (670 to 99) correspond to the y-axis of coordinate system (0 to 1.2). How can this be done? Maybe there's a function in matlab doing something like that? Some more explanation: I have a jpg image of a curve on a coordinate system. I've got pixel positions (x,y) of several points on that curve. Now I want to plot same curve into a matlab figure with same x and y axis as on the jpg image.

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  • Screen orientation change forces data re-entry

    - by Timbermar
    I'm developing a simple app, only a handful of activities and nothing to complicated. The issue I'm having is that in a few of my activities I have EditText widgets, and when the screen is rotated, these widgets loose their values. They still visually, that is, on the handset screen, report their values from before the rotation, but to the code report their default values. An example, I have an activity with an EditText, I enter a number, 15, the calculator starts calculating, displays a result. If at this point I rotate to a different orientation, as expected the activity dies, reloads, shows the new orientation, my value of 15 is still in the EditText, however the calculator (the code) calculates as if it was 0, which is the initial value. I have not tried changing the initial value to see if it is really pulling from the default value, or just setting itself to 0 when I cast it as an int. If I didn't explain this well enough, let me know, I can add source code if I need to. Thanks.

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