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  • How do I cast a void pointer to a struct in C?

    - by Rowhawn
    In a project I'm writing code for, I have a void pointer, "implementation", which is a member of a "Hash_map" struct, and points to an "Array_hash_map" struct. The concepts behind this project are not very realistic, but bear with me. The specifications of the project ask that I cast the void pointer "implementation" to an "Array_hash_map" before I can use it in any functions. My question, specifically is, what do I do in the functions to cast the void pointers to the desired struct? Is there one statement at the top of each function that casts them or do I make the cast every time I use "implementation"? Here are the typedefs the structs of a Hash_map and Array_hash_map as well as a couple functions making use of them. typedef struct { Key_compare_fn key_compare_fn; Key_delete_fn key_delete_fn; Data_compare_fn data_compare_fn; Data_delete_fn data_delete_fn; void *implementation; } Hash_map; typedef struct Array_hash_map{ struct Unit *array; int size; int capacity; } Array_hash_map; typedef struct Unit{ Key key; Data data; } Unit; functions: /* Sets the value parameter to the value associated with the key parameter in the Hash_map. */ int get(Hash_map *map, Key key, Data *value){ int i; if (map == NULL || value == NULL) return 0; for (i = 0; i < map->implementation->size; i++){ if (map->key_compare_fn(map->implementation->array[i].key, key) == 0){ *value = map->implementation->array[i].data; return 1; } } return 0; } /* Returns the number of values that can be stored in the Hash_map, since it is represented by an array. */ int current_capacity(Hash_map map){ return map.implementation->capacity; }

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  • Why is an anonymous inner class containing nothing generated from this code?

    - by Andrew Westberg
    When run through javac on the cmd line Sun JVM 1.6.0_20, this code produces 6 .class files OuterClass.class OuterClass$1.class OuterClass$InnerClass.class OuterClass$InnerClass2.class OuterClass$InnerClass$InnerInnerClass.class OuterClass$PrivateInnerClass.class When run through JDT in eclipse, it produces only 5 classes. OuterClass.class OuterClass$1.class OuterClass$InnerClass.class OuterClass$InnerClass2.class OuterClass$InnerClass$InnerInnerClass.class OuterClass$PrivateInnerClass.class When decompiled, OuterClass$1.class contains nothing. Where is this extra class coming from and why is it created? package com.test; public class OuterClass { public class InnerClass { public class InnerInnerClass { } } public class InnerClass2 { } //this class should not exist in OuterClass after dummifying private class PrivateInnerClass { private String getString() { return "hello PrivateInnerClass"; } } public String getStringFromPrivateInner() { return new PrivateInnerClass().getString(); } }

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  • C struct memory layout?

    - by Eonil
    I have C# background. Very newbie to low level language like C. In C#, memory layout by compiler by default, and I have to specify some special attribute to override this behavior for exact layout. As I know, C does not re-align by default. But I heard there's a little re-aligning behavior which very hard to find. Can I know about C's memory layout behavior? (what should be re-aligned and not)

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  • Types in a struct in C

    - by drigoSkalWalker
    In this article : http://publib.boulder.ibm.com/infocenter/macxhelp/v6v81/index.jsp?topic=/com.ibm.vacpp6m.doc/language/ref/clrc03defst.htm What's means the sentence "In C, a structure member may be of any type except "function returning T" (for some type T)" Thanks for all the answers!

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  • Class Loading Deadlocks

    - by tomas.nilsson
    Mattis follows up on his previous post with one more expose on Class Loading Deadlocks As I wrote in a previous post, the class loading mechanism in Java is very powerful. There are many advanced techniques you can use, and when used wrongly you can get into all sorts of trouble. But one of the sneakiest deadlocks you can run into when it comes to class loading doesn't require any home made class loaders or anything. All you need is classes depending on each other, and some bad luck. First of all, here are some basic facts about class loading: 1) If a thread needs to use a class that is not yet loaded, it will try to load that class 2) If another thread is already loading the class, the first thread will wait for the other thread to finish the loading 3) During the loading of a class, one thing that happens is that the <clinit method of a class is being run 4) The <clinit method initializes all static fields, and runs any static blocks in the class. Take the following class for example: class Foo { static Bar bar = new Bar(); static { System.out.println("Loading Foo"); } } The first time a thread needs to use the Foo class, the class will be initialized. The <clinit method will run, creating a new Bar object and printing "Loading Foo" But what happens if the Bar object has never been used before either? Well, then we will need to load that class as well, calling the Bar <clinit method as we go. Can you start to see the potential problem here? A hint is in fact #2 above. What if another thread is currently loading class Bar? The thread loading class Foo will have to wait for that thread to finish loading. But what happens if the <clinit method of class Bar tries to initialize a Foo object? That thread will have to wait for the first thread, and there we have the deadlock. Thread one is waiting for thread two to initialize class Bar, thread two is waiting for thread one to initialize class Foo. All that is needed for a class loading deadlock is static cross dependencies between two classes (and a multi threaded environment): class Foo { static Bar b = new Bar(); } class Bar { static Foo f = new Foo(); } If two threads cause these classes to be loaded at exactly the same time, we will have a deadlock. So, how do you avoid this? Well, one way is of course to not have these circular (static) dependencies. On the other hand, it can be very hard to detect these, and sometimes your design may depend on it. What you can do in that case is to make sure that the classes are first loaded single threadedly, for example during an initialization phase of your application. The following program shows this kind of deadlock. To help bad luck on the way, I added a one second sleep in the static block of the classes to trigger the unlucky timing. Notice that if you uncomment the "//Foo f = new Foo();" line in the main method, the class will be loaded single threadedly, and the program will terminate as it should. public class ClassLoadingDeadlock { // Start two threads. The first will instansiate a Foo object, // the second one will instansiate a Bar object. public static void main(String[] arg) { // Uncomment next line to stop the deadlock // Foo f = new Foo(); new Thread(new FooUser()).start(); new Thread(new BarUser()).start(); } } class FooUser implements Runnable { public void run() { System.out.println("FooUser causing class Foo to be loaded"); Foo f = new Foo(); System.out.println("FooUser done"); } } class BarUser implements Runnable { public void run() { System.out.println("BarUser causing class Bar to be loaded"); Bar b = new Bar(); System.out.println("BarUser done"); } } class Foo { static { // We are deadlock prone even without this sleep... // The sleep just makes us more deterministic try { Thread.sleep(1000); } catch(InterruptedException e) {} } static Bar b = new Bar(); } class Bar { static { try { Thread.sleep(1000); } catch(InterruptedException e) {} } static Foo f = new Foo(); }

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  • should I extend or create instance of the class

    - by meWantToLearn
    I have two classes Class A and Class B in Class A, i have three methods that perform the save, delete and select operation based upon the object I pass them. in Class B I perform the logic operations, such as modification to the property of the object before being passed to the methods of Class A, My problem is in Class B, should it extend Class A, and call the methods of class A , by parent::methodName or create instance of class A and then call Class A does not includes any property just methods. class A{ public function save($obj){ //code here } public function delete($obj){ //code here } public function select($obj){ //code here } } //Should I extend class A, and call the method by parent::methodName($obj) or create an instance of class A, call the method $instanceOfA-methodName($obj); class B extends A{ public function checkIfHasSaved($obj){ if($obj->saved == 'Yes'){ parent::save($obj); //**should I call the method like this** $instanceOFA = new A(); //**or create instance of class A and call without extending class A** instanceOFA->save($obj); } //other logic operations here } }

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  • Changing multiple objects with a new class name using Jquery

    - by liquilife
    I'd like to click on a trigger and show a specific image. There are multiple triggers which would show a specific image related to it within a set. There are 4 sets The challenge for me is toggling the other images to hide only in this 'set' when one of these triggers are clicked, as there can only be one image showing at a time in each set. Here is the HTML I've put together thus far: <!-- Thumbnails which can be clicked on to toggle the larger preview image --> <div class="materials"> <a href="javascript:;" id="shirtgrey"><img src="/grey_shirt.png" height="122" width="122" /></a> <a href="javascript:;" id="shirtred"><img src="red_shirt.png" height="122" width="122" /></a> <a href="javascript:;" id="shirtblue"><img src="hblue_shirt.png" height="122" width="122" /></a> <a href="javascript:;" id="shirtgreen"><img src="green_shirt.png" height="122" width="122" /></a> </div> <div class="collars"> <a href="javascript:;" id="collargrey"><img src="grey_collar.png" height="122" width="122" /></a> <a href="javascript:;" id="collarred"><img src="red_collar.png" height="122" width="122" /></a> <a href="javascript:;" id="collarblue"><img src="blue_collar.png" height="122" width="122" /></a> <a href="javascript:;" id="collargreen"><img src="green_collar.png" height="122" width="122" /></a> </div> <div class="cuffs"> <a href="javascript:;" id="cuffgrey"><img src="grey_cuff.png" height="122" width="122" /></a> <a href="javascript:;" id="cuffred"><img src="red_cuff.png" height="122" width="122" /></a> <a href="javascript:;" id="cuffblue"><img src="blue_cuff.png" height="122" width="122" /></a> <a href="javascript:;" id="cuffgreen"><img src="/green_cuff.png" height="122" width="122" /></a> </div> <div class="pockets"> <a href="javascript:;" id="pocketgrey"><img src="grey_pocket.png" height="122" width="122" /></a> <a href="javascript:;" id="pocketred"><img src=".png" height="122" width="122" /></a> <a href="javascript:;" id="pocketblue"><img src="blue_pocket.png" height="122" width="122" /></a> <a href="javascript:;" id="pocketgreen"><img src="green_pocket.png" height="122" width="122" /></a> </div> <!-- The larger images where one from each set should be viewable at one time, triggered by the thumb clicked above --> <div class="selectionimg"> <div class="selectShirt"> <img src="grey_shirt.png" height="250" width="250" class="selectShirtGrey show" /> <img src="red_shirt.png" height="250" width="250" class="selectShirtRed hide" /> <img src="blue_shirt.png" height="250" width="250" class="selectShirtBlue hide" /> <img src="green_shirt.png" height="250" width="250" class="selectShirtGreen hide" /> </div> <div class="selectCollar"> <img src="grey_collar.png" height="250" width="250" class="selectCollarGrey show" /> <img src="red_collar.png" height="250" width="250" class="selectCollarRed hide" /> <img src="blue_collar.png" height="250" width="250" class="selectCollarBlue hide" /> <img src="green_collar.png" height="250" width="250" class="selectCollarGreen hide" /> </div> <div class="selectCuff"> <img src="grey_cuff.png" height="250" width="250" class="selectCuffGrey show" /> <img src="red_cuff.png" height="250" width="250" class="selectCuffRed hide" /> <img src="blue_cuff.png" height="250" width="250" class="selectCuffBlue hide" /> <img src="green_cuff.png" height="250" width="250" class="selectCuffGreen hide" /> </div> <div class="selectPocket"> <img src="grey_pocket.png" height="250" width="250" class="selectPocketGrey show" /> <img src="hred_pocket.png" height="250" width="250" class="selectPocketRed hide" /> <img src="blue_pocket.png" height="250" width="250" class="selectPocketBlue hide" /> <img src="green_pocket.png" height="250" width="250" class="selectPocketGreen hide" /> </div> </div> How can jQuery be used to change a class of an image to "show" and ensure that all other images in that same div are set to a class of "hide"? First time posting here. I'm very efficient with HTML and CSS and have a basic understanding of jQuery. I'm learning and this just seems a little bit beyond my abilities at the moment. I hope this all makes sense. Thanks for any help.

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  • Getting an object from a 2d array inside of a class

    - by user36324
    I am have a class file that contains two classes, platform and platforms. platform holds the single platform information, and platforms has an 2d array of platforms. Im trying to render all of them in a for loop but it is not working. If you could kindly help me i would greatly appreciate. void Platforms::setUp() { for(int x = 0; x < tilesW; x++){ for(int y = 0; y < tilesH; y++){ Platform tempPlat(x,y,true,renderer,filename,tileSize/scaleW,tileSize/scaleH); platArray[x][y] = tempPlat; } } } void Platforms::show() { for(int x = 0; x < tilesW; x++){ for(int y = 0; y < tilesH; y++){ platArray[x][y].show(renderer,scaleW,scaleH); } } }

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  • Atomikos vs JOTM vs Bitronix vs ????

    - by HDave
    I am new to JTA and it's underlying transaction managers. Can anyone explain the pros/cons of each of these? Feel free to add others I didn't list in title. Also, don't the major applications servers (WebSphere, JBoss, Glassfish) have their own JTA compliant transaction manager? In those environments, would you still use these third party implementations?

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  • Rank Source Control Optionsl-VSS vs CVS vs none vs your own hell

    - by Roman A. Taycher
    It seems like a lit of people here and on many programmer wikis/blogs/ect. elsewhere really dislike VSS. A lot of people also have a serious dislike for cvs. In many places I have heard a lot of differing opinions on whether or not using vss or cvs is better or worse then using no source control, please rate the worst and explain why!!!!! you rated them this way. Feel free to throw in your own horrible system in the rankings. If you feel it depends on the circumstances try to explain the some of the different scenarios which lead to different rankings. (note:I see a lot of discussion of what is better but little of what is worse.) second note: while both answers are nice I'm looking less for good replacements and more for a comparison of which is worse and more importantly why!!!!!

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  • Rank Source Control Options-VSS vs CVS vs none vs your own hell

    - by Roman A. Taycher
    It seems like a lot of people here and on many programmer wikis/blogs/ect. elsewhere really dislike VSS. A lot of people also have a serious dislike for cvs. In many places I have heard a lot of differing opinions on whether or not using VSS or cvs is better or worse then using no source control, please rate the worst and explain why!!!!! you rated them this way. Feel free to throw in your own horrible system in the rankings. If you feel it depends on the circumstances try to explain the some of the different scenarios which lead to different rankings. (note:I see a lot of discussion of what is better but little of what is worse.) second note: while both answers are nice I'm looking less for good replacements and more for a comparison of which is worse and more importantly why!

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  • C# new class with only single property : derive from base or encapsulate into new ?

    - by Gobol
    I've tried to be descriptive :) It's rather programming-style problem than coding problem in itself. Let's suppose we have : A: public class MyDict { public Dictionary<int,string> dict; // do custom-serialization of "dict" public void SaveToFile(...); // customized deserialization of "dict" public void LoadFromFile(...); } B: public class MyDict : Dictionary<int,string> { } Which option would be better in the matter of programming style ? class B: is to be de/serialized externally. Main problem is : is it better to create new class (which would have only one property - like opt A:) or to create a new class derived - like opt B: ? I don't want any other data processing than adding/removing and de/serializing to stream. Thanks in advance!

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  • Static class vs Singleton class in C# [closed]

    - by Floradu88
    Possible Duplicate: What is the difference between all-static-methods and applying a singleton pattern? I need to make a decision for a project I'm working of whether to use static or singleton. After reading an article like this I am inclined to use singleton. What is better to use static class or singleton? Edit 1 : Client Server Desktop Application. Please provide code oriented solutions.

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  • In C, when do structure names have to be included in structure initializations and definitions?

    - by Tyler
    I'm reading The C Programming Language by K&R and in the section on structures I came across these code snippets: struct maxpt = { 320, 200 }; and /* addpoints: add two points */ struct addpoint(struct point p1, struct point p2) { p1.x += p2.x; p1.y += p2.y; return p1; } In the first case, it looks like it's assigning the values 320 and 200 to the members of the variable maxpt. But I noticed the name of the struct type is missing (shouldn't it be "struct struct_name maxpt = {320, 200}"? In the second case, the function return type is just "struct" and not "struct name_of_struct". I don't get why they don't include the struct names - how does it know what particular type of structure it's dealing with? My confusion is compounded by the fact that in previous snippets they do include the structure name, such as in the return type for the following function, where it's "struct point" and not just "struct". Why do they include the name in some cases and not in others? /* makepoint: make a point from x and y components */ struct point makepoint(int x, int y) { struct point temp; temp.x = x; temp.y = y; return temp; }

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  • polymorphism, inheritance in c# - base class calling overridden method?

    - by Andrew Johns
    This code doesn't work, but hopefully you'll get what I'm trying to achieve here. I've got a Money class, which I've taken from http://www.noticeablydifferent.com/CodeSamples/Money.aspx, and extended it a little to include currency conversion. The implementation for the actual conversion rate could be different in each project, so I decided to move the actual method for retrieving a conversion rate (GetCurrencyConversionRate) into a derived class, but the ConvertTo method contains code that would work for any implementation assuming the derived class has overriden GetCurrencyConversionRate so it made sense to me to keep it in the parent class? So what I'm trying to do is get an instance of SubMoney, and be able to call the .ConvertTo() method, which would in turn use the overriden GetCurrencyConversionRate, and return a new instance of SubMoney. The problem is, I'm not really understanding some concepts of polymorphism and inheritance yet, so not quite sure what I'm trying to do is even possible in the way I think it is, as what is currently happening is that I end up with an Exception where it has used the base GetCurrencyConversionRate method instead of the derived one. Something tells me I need to move the ConvertTo method down to the derived class, but this seems like I'll be duplicating code in multiple implementations, so surely there's a better way? public class Money { public CurrencyConversionRate { get { return GetCurrencyConversionRate(_regionInfo.ISOCurrencySymbol); } } public static decimal GetCurrencyConversionRate(string isoCurrencySymbol) { throw new Exception("Must override this method if you wish to use it."); } public Money ConvertTo(string cultureName) { // convert to base USD first by dividing current amount by it's exchange rate. Money someMoney = this; decimal conversionRate = this.CurrencyConversionRate; decimal convertedUSDAmount = Money.Divide(someMoney, conversionRate).Amount; // now convert to new currency CultureInfo cultureInfo = new CultureInfo(cultureName); RegionInfo regionInfo = new RegionInfo(cultureInfo.LCID); conversionRate = GetCurrencyConversionRate(regionInfo.ISOCurrencySymbol); decimal convertedAmount = convertedUSDAmount * conversionRate; Money convertedMoney = new Money(convertedAmount, cultureName); return convertedMoney; } } public class SubMoney { public SubMoney(decimal amount, string cultureName) : base(amount, cultureName) {} public static new decimal GetCurrencyConversionRate(string isoCurrencySymbol) { // This would get the conversion rate from some web or database source decimal result = new Decimal(2); return result; } }

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  • jQuery only firing last class in multiple-class click

    - by user1134644
    I have a set of links like so: <a href="#internalLink1" class="classA">This has Class A</a> <a href="#internalLink2" class="classB">This has Class B</a> <a href="#internalLink3" class="classA classB">This has Class A and Class B</a> And here's the corresponding jQuery: $('.classA').click(function(){ // do class A stuff }); $('.classB').click(function(){ // do class B stuff }); Currently, when I click on the first link with Class A, it does the Class A stuff like it's supposed to. Similarly, when I click on the second link with Class B, it does the Class B stuff like it's supposed to. No worries there. My issue is, when I click on the third link with BOTH classes, it only fires the function for whichever class comes last (in this case, class B. If I put class A at the end instead, it performs class A's function). I want it to fire both. What am I doing wrong? Thanks in advance. EDIT: To those posting fiddles, nearly all of them work, so as many have said, it's most likely not my code, but the way it displays in my file. For a little more clarification, I was teaching myself some jQuery and decided to try making a (very) simple "Choose Your Own Adventure" type game. Here's a jsfiddle containing the opening of my bare-bones-please-don't-laugh game. Click on "Hide in the bushes", then "Examine the victim", then "Take any valuables and leave, he's dead already" <-- THIS is where the issue is. It's supposed to add 98 gold ("hawks") to your inventory, AND tell you that your alignment has shifted 1 point towards Chaotic. At the moment, it only does the chaotic alert, and no gold gets added to your inventory. The other option (refresh the fiddle to restart) that adds money to your inventory, but DOES NOT make you chaotic, works just fine (if you select "Search him for identification" instead of "take the money and run") Sorry this is so long!

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  • Hints to properly design UML class diagram

    - by mic4ael
    Here is the problem. I have just started learning UML and that is why I would like to ask for a few cues from experienced users how I could improve my diagram because I do know it lacks a lot of details, it has mistakes for sure etc. Renovation company hires workers. Each employee has some kind of profession, which is required to work on a particular position. Workers work in groups consisting of at most 15 members - so called production units, which specializes in a specified kind of work. Each production unit is managed by a foreman. Every worker in order to be able to perform job tasks needs proper accessories. There are two kind of tools - light and heavy. To use heavy tools, a worker must have proper privileges. A worker can have at most 3 light tools taken from the warehouse.

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  • Isn't class scope purely for organization?

    - by Di-0xide
    Isn't scope just a way to organize classes, preventing outside code from accessing certain things you don't want accessed? More specifically, is there any functional gain to having public, protected, or private-scoped methods? Is there any advantage to classifying method/property scope rather than to, say, just public-ize everything? My presumption says no simply because, in binary code, there is no sense of scope (other than r/w/e, which isn't really scope at all, but rather global permissions for a block of memory). Is this correct? What about in languages like Java and C#[.NET]?

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  • What class structure allows for a base class and mix/match of subclasses? (Similar to Users w/ roles)

    - by cdeszaq
    I have a set of base characteristics, and then a number of sub-types. Each instance must be one of the sub-types, but can be multiple sub-types at once. The sub-types of each thing can change. In general, I don't care what subtype I have, but sometimes I do care. This is much like a Users-Roles sort of relationship where a User having a particular Role gives the user additional characteristics. Sort of like duck-typing (ie. If my Foo has a Bar, I can treat it like a ThingWithABar.) Straight inheritance doesn't work, since that doesn't allow mix/match of sub-types. (ie. no multi-inheritance). Straight composition doesn't work because I can't switch that up at runtime. How can I model this?

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  • Adobe Photoshop Vs Lightroom Vs Aperture

    - by Aditi
    Adobe Photoshop is the standard choice for photographers, graphic artists and Web designers. Adobe Photoshop Lightroom  & Apple’s Aperture are also in the same league but the usage is vastly different. Although Photoshop is most popular & widely used by photographers, but in many ways it’s less relevant to photographers than ever before. As Lightroom & Aperture is aimed squarely at photographers for photo-processing. With this write up we are going to help you choose what is right for you and why. Adobe Photoshop Adobe Photoshop is the most liked tool for the detailed photo editing & designing work. Photoshop provides great features for rollover and Image slicing. Adobe Photoshop includes comprehensive optimization features for producing the highest quality Web graphics with the smallest possible file sizes. You can also create startling animations with it. Designers & Editors know how important precise masking is, PhotoShop lets you do that with various detailing tools. Art history brush, contact sheets, and history palette are some of the smart features, which add to its viability. Download Whether you’re producing printed pages or moving images, you can work more efficiently and produce better results because of its smooth integration across other adobe applications. Buy supporting layer effects, it allows you to quickly add drop shadows, inner and outer glows, bevels, and embossing to layers. It also provides Seamless Web Graphics Workflow. Photoshop is hands-down the BEST for editing. Photoshop Cons: • Slower, less precise editing features in Bridge • Processing lots of images requires actions and can be slower than exporting images from Lightroom • Much slower with editing and processing a large number of images Aperture Apple Aperture is aimed at the professional photographer who shoots predominantly raw files. It helps them to manage their workflow and perform their initial Raw conversion in a better way. Aperture provides adjustment tools such as Histogram to modify color and white balance, but most of the editing of photos is left for Photoshop. It gives users the option of seeing their photographs laid out like slides or negatives on a light table. It boasts of – stars, color-coding and easy techniques for filtering and picking images. Aperture has moved forward few steps than Photoshop, but most of the editing work has been left for Photoshop as it features seamless Photoshop integration. Aperture Pros: Aperture is a step up from the iPhoto software that comes with every Mac, and fairly easy to learn. Adjustments are made in a logical order from top to bottom of the menu. You can store the images in a library or any folder you choose. Aperture also works really well with direct Canon files. It is just $79 if you buy it through Apple’s App Store Moving forward, it will run on the iPad, and possibly the iPhone – Adobe products like Lightroom and Photoshop may never offer these options It is much nicer and simpler user interface. Lightroom Lightroom does a smashing job of basic fixing and editing. It is more advanced tool for photographers. They can use it to have a startling photography effect. Light room has many advanced features, which makes it one of the best tools for photographers and far ahead of the other two. They are Nondestructive editing. Nothing is actually changed in an image until the photo is exported. Better controls over organizing your photos. Lightroom helps to gather a group of photos to use in a slideshow. Lightroom has larger Compare and Survey views of images. Quickly customizable interface. Simple keystrokes allow you to perform different All Lightroom controls are kept available in panels right next to the photos. Always-available History palette, it doesn’t go when you close lightroom. You gain more colors to work with compared to Photoshop and with more precise control. Local control, or adjusting small parts of a photo without affecting anything else, has long been an important part of photography. In Lightroom 2, you can darken, lighten, and affect color and change sharpness and other aspects of specific areas in the photo simply by brushing your cursor across the areas. Photoshop has far more power in its Cloning and Healing Brush tools than Lightroom, but Lightroom offers simple cloning and healing that’s nondestructive. Lightroom supports the RAW formats of more cameras than Aperture. Lightroom provides the option of storing images outside the application in the file system. It costs less than photoshop. Download Why PhotoShop is advanced than Lightroom? There are countless image processing plug-ins on the market for doing specialized processing in Photoshop. For example, if your image needs sophisticated noise reduction, you can use the Noiseware plug-in with Photoshop to do a much better job or noise removal than Lightroom can do. Lightroom’s advantages over Aperture 3 Will always have better integration with Photoshop. Lightroom is backed by bigger and more active user community (So abundant availability for tutorials, etc.) Better noise reduction tool. Especially for photographers the Lens-distortion correction tool  is perfect Lightroom Cons: • Have to Import images to work on them • Slows down with over 10,000 images in the catalog • For processing just one or two images this is a slower workflow Photoshop Pros: • ACR has the same RAW processing controls as Lightroom • ACR Histogram is specialized to the chosen color space (Lightroom is locked into ProPhoto RGB color space with an sRGB tone curve) • Don’t have to Import images to open in Bridge or ACR • Ability to customize processing of RAW images with Photoshop Actions Pricing and Availability Get LightRoomGet PhotoShop Latest version Of Photoshop can be purchased from Adobe store and Adobe authorized reseller and it costs US$999. Latest version of Aperture can be bought for US$199 from Apple Online store or Mac App Store. You can buy latest version of LightRoom from Adobe Store or Adobe Authorized reseller for US$299. Related posts:Adobe Photoshop CS5 vs Photoshop CS5 extended Web based Alternatives to Photoshop 10 Free Alternatives for Adobe Photoshop Software

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  • how can i select first second or third element with given class name using CSS?

    - by Tumharyyaaden
    ie. i have the following: <div class="myclass">my text1</div> some other code+containers... <div class="myclass">my text2</div> some other code+containers... <div class="myclass">my text3</div> some other code+containers... i have the css class div.myclass {doing things} that applies to all obviously but i also wanted to be able to select the first, second or third like this: div.myclass:first {color:#000;} div.myclass:second {color:#FFF;} div.myclass:third {color:#006;} almost like the jQuery index selection .eq( index ) which is what i am using currently but need a noscript alternative. Thanks in advance!

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