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  • Printing background colours in Chrome

    - by Mick
    Hi, I'm trying to print a php generated document in Chrome. On the browser it looks fine, but my printer will not print any coloured backgrounds. I know that IE has an option to print background but Chrome does not. As the end user will print this off, I do not want to find alternatives like a screen grab or save file etc. I want to find a real solution to this. Here is the page i want to print, for information Can anyone offer a suggestion please?

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  • How views are changing in future versions of SQL

    - by Rob Farley
    April is here, and this weekend, SQL v11.0 (previous known as Denali, now known as SQL Server 2012) reaches general availability. And so I thought I’d share some news about what’s coming next. I didn’t hear this at the MVP Summit earlier this year (where there was lots of NDA information given, but I didn’t go), so I think I’m free to share it. I’ve written before about CTEs being query-scoped views. Well, the actual story goes a bit further, and will continue to develop in future versions. A CTE is a like a “temporary temporary view”, scoped to a single query. Due to globally-scoped temporary objects using a two-hashes naming style, and session-scoped (or ‘local’) temporary objects a one-hash naming style, this query-scoped temporary object uses a cunning zero-hash naming style. We see this implied in Books Online in the CREATE TABLE page, but as we know, temporary views are not yet supported in the SQL Server. However, in a breakaway from ANSI-SQL, Microsoft is moving towards consistency with their naming. We know that a CTE is a “common table expression” – this is proving to be a more strategic than you may have appreciated. Within the Microsoft product group, the term “Table Expression” is far more widely used than just CTEs. Anything that can be used in a FROM clause is referred to as a Table Expression, so long as it doesn’t actually store data (which would make it a Table, rather than a Table Expression). You can see this is not just restricted to the product group by doing an internet search for how the term is used without ‘common’. In the past, Books Online has referred to a view as a “virtual table” (but notice that there is no SQL 2012 version of this page). However, it was generally decided that “virtual table” was a poor name because it wasn’t completely accurate, and it’s typically accepted that virtualisation and SQL is frowned upon. That page I linked to says “or stored query”, which is slightly better, but when the SQL 2012 version of that page is actually published, the line will be changed to read: “A view is a stored table expression (STE)”. This change will be the first of many. During the SQL 2012 R2 release, the keyword VIEW will become deprecated (this will be SQL v11 SP1.5). Three versions later, in SQL 14.5, you will need to be in compatibility mode 140 to allow “CREATE VIEW” to work. Also consistent with Microsoft’s deprecation policy, the execution of any query that refers to an object created as a view (rather than the new “CREATE STE”), will cause a Deprecation Event to fire. This will all be in preparation for the introduction of Single-Column Table Expressions (to be introduced in SQL 17.3 SP6) which will finally shut up those people waiting for a decent implementation of Inline Scalar Functions. And of course, CTEs are “Common” because the Table Expression definition needs to be repeated over and over throughout a stored procedure. ...or so I think I heard at some point. Oh, and congratulations to all the new MVPs on this April 1st. @rob_farley

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  • Result class dependency

    - by Stefano Borini
    I have an object containing the results of a computation. This computation is performed in a function which accepts an input object and returns the result object. The result object has a print method. This print method must print out the results, but in order to perform this operation I need the original input object. I cannot pass the input object at printing because it would violate the signature of the print function. One solution I am using right now is to have the result object hold a pointer to the original input object, but I don't like this dependency between the two, because the input object is mutable. How would you design for such case ?

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  • Perl syntax error [closed]

    - by Linny
    I am a beginner taking a Perl programming course. We are trying to write a basic program for counting nucleotides in a DNA string. I'm getting syntax errors on the lines that have a single bracket on lines 28 & 70 and don't know why. It also reads that I have compilation errors. I have no idea where to start figuring that out. # The purpose of this program is to count the number of nucleotides in a strand. Each protein is counted separately # print "/n NOTE: Nucleotide counting /n"; # use strict; # enforce variable declarations use warnings; # enable compiler warnings # Display number of A,a,T,t,G,g,C,c, nucleotides in a word or sequence of letters. # my ($base) = ''; # an extracted letter from a string my ($nuceotide_count) = 0 ; # the current position within the word my ($position) = 0 ; # number of vowels in user-supplied word my ($word) = ''; # word to be processed my ($A_count) = 0 ; # of A nucleotides in the user-supplied sequence my ($a_count) = 0 ; # of A nucleotides in the user-supplied sequence my ($C_count) = 0 ; # of C nucleotides in the user-supplied sequence my ($c_count) = 0 ; # of C nucleotides in the user-supplied sequence my ($G_count) = 0 ; # of G nucleotides in the user-supplied sequence my ($g_count) = 0 ; # of G nucleotides in the user-supplied sequence my ($T_count) = 0 ; # of T nucleotides in the user-supplied sequence my ($t_count) = 0 ; # of T nucleotides in the user-supplied sequence word = (STDIN) for ($position = 0);($position if (($base eq 'a') or ($base eq 'A')) { ++$A_count; } # end if ++$position; if (($base eq 'T') or ($base eq 't')) { ++$T_count; } end if ++$position; if (($base eq 'G') or ($base eq 'g')) { ++$G_count; } # end if ++$position; if (($base eq 'C') or ($base eq 'c')) { ++$C_count; } # end if ++$position; } # end for # Display final results. # print " \n The number of A or a neucleotides is: $A_count"; print " \n The number of T or t neucleotides is: $T_count"; print " \n The number of G or g neucleotides is: $G_count"; print " \n The number of C or c neucleotides is: $C_count"; print " \n\n Program completed successfully. \n" ; exit ;

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  • Will the Canon Pixma MX882 Wireless Multifunction Printer allow you to keep printing once one ink cartridge has run out?

    - by braveterry
    My wife's Epson Workforce 600 has died, and I'm thinking of replacing it with a Canon Pixma MX882 printer/scanner/copier/fax. One of the most annoying things about the Epson is that once it has decided that one of the ink cartridges is empty, it will not let you print anything until the empty cartridge is replaced. I have a Canon IP1800 that will let you print until a cartridge actually runs out of ink, and even when a cartridge is depleted, I can continue to print using the other colors. (The driver allows you to print using only the color cartridges or using only the black cartridge.) Questions: Will the Canon Pixma MX882 allow me to print until the ink runs out or will it declare the cartridge empty while ink is still left? Will the Canon Pixma MX882 allow me to keep printing even after one of the cartridges has been used up?

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  • Printing to a printer connected to a wireless router

    - by mspencer
    I have a Netgear WNDR4500 wireless router which allows me to print wirelessly to a printer connected to it via a USB cable. However, the software used to print to it only works for Windows and OS X. I've seen the question Printing to a printer attached to a network USB hub, and tried the instructions it gave using my router's IP address, but when I print a test page it says copying data then says printer is in use. In the printer queue window it says not connected. How can I print to the printer using Ubuntu? Thanks.

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  • Indefinite loops where the first time is different

    - by George T
    This isn't a serious problem or anything someone has asked me to do, just a seemingly simple thing that I came up with as a mental exercise but has stumped me and which I feel that I should know the answer to already. There may be a duplicate but I didn't manage to find one. Suppose that someone asked you to write a piece of code that asks the user to enter a number and, every time the number they entered is not zero, says "Error" and asks again. When they enter zero it stops. In other words, the code keeps asking for a number and repeats until zero is entered. In each iteration except the first one it also prints "Error". The simplest way I can think of to do that would be something like the folloing pseudocode: int number = 0; do { if(number != 0) { print("Error"); } print("Enter number"); number = getInput(); }while(number != 0); While that does what it's supposed to, I personally don't like that there's repeating code (you test number != 0 twice) -something that should generally be avoided. One way to avoid this would be something like this: int number = 0; while(true) { print("Enter number"); number = getInput(); if(number == 0) { break; } else { print("Error"); } } But what I don't like in this one is "while(true)", another thing to avoid. The only other way I can think of includes one more thing to avoid: labels and gotos: int number = 0; goto question; error: print("Error"); question: print("Enter number"); number = getInput(); if(number != 0) { goto error; } Another solution would be to have an extra variable to test whether you should say "Error" or not but this is wasted memory. Is there a way to do this without doing something that's generally thought of as a bad practice (repeating code, a theoretically endless loop or the use of goto)? I understand that something like this would never be complex enough that the first way would be a problem (you'd generally call a function to validate input) but I'm curious to know if there's a way I haven't thought of.

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  • Debian: Firefox or Iceweasel default printer for POS station

    - by Bubnoff
    Context Using Debian 6.04 "Squeeze" as POS station. There are two printers installed: Network printer and a receipt printer It absolutely must be able to print by default to the receipt printer on a certain website though the system default is a network printer. In Debian ...it doesn't. Problem I've set up XP, 7, Ubuntu and even Mac OSX this way, so I'm no stranger to setting Firefox up this way ...same Iceweasel/Firefox settings ...complete fail. Always uses system default no matter what the settings, or, which printer you print from. To get this to work on other systems you do this: Print a page in Firefox using desired printer. Ensure print.save_settings is true. Firefox remembers last printer used Set print.always_print_silent = true The end. This works on every OS I've set up ....except Firefox and Iceweasel in Debian. My only recourse seems to be to set the receipt printer as default or go back to bloaty Ubuntu/Mint ...etc.

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  • PDF export printing in Internet Explorer [closed]

    - by user619804
    protected static byte[] exportReportToPdf(JasperPrint jasperPrint) throws JRException { JRPdfExporter exporter = new JRPdfExporter(); ByteArrayOutputStream baos = new ByteArrayOutputStream(); exporter.setParameter(JRExporterParameter.JASPER_PRINT, jasperPrint); exporter.setParameter(JRExporterParameter.OUTPUT_STREAM, baos); exporter.setParameter(JRPdfExporterParameter.PDF_JAVASCRIPT, "this.print({bUI: true,bSilent: false,bShrinkToFit: true});"); exporter.exportReport(); return baos.toByteArray(); } We are using code like this to export a PDF document from a Jasper application. The line exporter.setParameter(JRPdfExporterParameter.PDF_JAVASCRIPT, "this.print({bUI: true,bSilent: false,bShrinkToFit: true});"); adds JavaScript to send the PDF document directly to the printer. The expected behavior is that a print dialog will come up with a preview of the PDF document. This works fine most of the time - except I am having problems about one out of every 5-6 times in Internet Explorer 8 and Firefox. What happens is - the print preview dialog with the PDF document does not appear or it appears with a blank document in the preview window. -I've tried a number of different JavaScripts (different params to this.print() via exporter.setParameter -I've tried setting different response headers such as response.setContentType("application/pdf"); response.setHeader("Content-disposition","inline; filename=\"" + reportName + "\""); response.setContentLength(baos.size()); these did not seem to help This seems to be an IE and FF issue. Has anyone ever dealt with this problem? I need to get it to work across all browsers 100% of the time. Perhaps a different approach to accomplish the goal of sending the PDF document export directly to the printer? or a third party library that will work across browsers?

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  • My Brother printer doesn't accept quality settings anymore - what can I do?

    - by rearlight
    I have a Brother MFC-465CN network printer. It uses the brother-cups-wrapper-bh7 and brother-lpr-drivers-bh7drivers. Now, when I print (which works perfectly fine) I try to print in "fast normal" settings to save some ink. I use LibreOffice and Ubuntus default PDF-viewer to print and set the settings in the print dialog manually. "Fast normal" is the default printing setting (in the Ubuntu GUI printing config). But the printer always prints in "normal" or even "fine" quality settings which takes forever and uses much more ink. So, what can I do about that? Thanks for your help in advance!

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  • Network printer problem with 12.04

    - by G. He
    I had an HP LaserJet 3030 printer connected to an Ubuntu box. It worked fine with 11.10. I was able to print from Ubuntu as well as from Windows and Mac from the home network. About a month or so ago, I upgraded 11.10 to 12.04, then things started to falling apart. My Windows 7 laptop couldn't print to the printer any more. Today, I installed many updates on 12.04, hoping that would fix the printing problem. Unfortunately, it made the situation much worse. Now not only my Windows 7 laptop won't print, my XP desktop won't print either. Every time I print something from the Windows computer, the Ubuntu box logs an error message in /var/log/samba/log.'machineName' as: _spoolss_OpenPrinterEx: Cannot open a printer handle for printer \\server. It is interesting that it uses the server name as the printer, not the \\server\xyzprinter as the printer name. Anyone had a similar problem? Anyway to work around the problem?

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  • Very basic beginner Ruby question to do with elsif and ranges [migrated]

    - by MattKneale
    I've been trying to get to grasps with Ruby (for all of an hour) and this is my first language. I've got the following code: var_comparison = 5 print "Please enter a number: " my_num = Integer(gets.chomp) if my_num > var_comparison print "You picked a number greater than 5!" elsif my_num < var_comparison print "You picked a number less than 5!" elsif my_num > 99 print "Your number is too large, man." else print "You picked the number 5!" end Clearly the interpreter has no way of distinguishing between accepting the rule 5 or 99. How do I make it so that any number between 6-99 returns "You picked a number greater than 5!", but a number 100 or greater returns "Your number is too large, man!"? Do I need to specifically state a range somehow? How would I best do that? Would it by the normal range methods e.g. if my_num 6..99 or if my_num.between(6..99) ?

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  • Map rendering Libgdx Java

    - by user3165683
    Ok, so I am trying to create a 2D non-movable random tiled map. This is what I have so far: private void generateTile(){ System.out.print("tiletry1"); while(loadedTiles != 8100){ System.out.print("tiletry"); Texture currentTile = null; int tileX = 0; int tileY = 0; if (tileX == 120); tileY = 16; tileX = 0; game.batch.begin(); switch(MathUtils.random(2)){ case 0: //game.batch.draw(tile1, tileX, tileY); System.out.print("tile1"); currentTile = tile1; break; case 1: //game.batch.draw(tile2, tileX, tileY); System.out.print("tile2"); currentTile = tile2; break; case 2: //game.batch.draw(tile3, tileX, tileY); System.out.print("tile3"); currentTile = tile3; break; } tileX+=16; loadedTiles ++; game.batch.draw(currentTile, tileX, tileY); game.batch.end(); } } However, I can't see any of the tiles and the screen just looks green. This method is above my render method which I have: camera.update(); batch.setProjectionMatrix(camera.combined); Gdx.gl.glClear(GL20.GL_COLOR_BUFFER_BIT); game.batch.begin(); //other render stuff Why am I not able to see the tiles?

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  • Generate random number histogram using java

    - by Chewart
    Histogram -------------------------------------------------------- 1 ****(4) 2 ******(6) 3 ***********(11) 4 *****************(17) 5 **************************(26) 6 *************************(25) 7 *******(7) 8 ***(3) 9 (0) 10 *(1) -------------------------------------------------------- basically above is what my prgram needs to do.. im missing something somewhere any help would be great :) import java.util.Random; public class Histogram { /*This is a program to generate random number histogram between 1 and 100 and generate a table */ public static void main(String args[]) { int [] randarray = new int [80]; Random random = new Random(); System.out.println("Histogram"); System.out.println("---------"); int i ; for ( i = 0; i<randarray.length;i++) { int temp = random.nextInt(100); //random numbers up to number value 100 randarray[i] = temp; } int [] histo = new int [10]; for ( i = 0; i<10; i++) { /* %03d\t, this generates the random numbers to three decimal places so the numbers are generated with a full number or number with 00's or one 0*/ if (randarray[i] <= 10) { histo[i] = histo[i] + 1; //System.out.println("*"); } else if ( randarray[i] <= 20){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 30){ histo[i] = histo[i] + 1; } else if ( randarray[i] <= 40){ histo[i] = histo[i] + 1; } else if (randarray[i] <= 50){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=60){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=70){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=80){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=90){ histo[i] = histo[i] + 1; } else if ( randarray[i] <=100){ histo[i] = histo[i] + 1; } switch (randarray[i]) { case 1: System.out.print("0-10 | "); break; case 2: System.out.print("11-20 | "); break; case 3: System.out.print("21-30 | "); break; case 4: System.out.print("31-40 | "); break; case 5: System.out.print("41-50 | "); break; case 6: System.out.print("51-60 | "); break; case 7: System.out.print("61-70 | "); break; case 8: System.out.print("71-80 | "); break; case 9: System.out.print("81-90 | "); break; case 10: System.out.print("91-100 | "); } for (int i = 0; i < 80; i++) { randomNumber = random.nextInt(100) index = (randomNumber - 1) / 2; histo[index]++; } } } }

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  • find substring and indices in mips

    - by ccc
    im trying find out substring and first occurrence indices. but something wrong. im comparing each element of pattern array and each element of string array until pointer reach to '\0'. and if any characater found it keep in temp array. and increasing pointers +1. whats the problem. algorithm is totaly wrong ? #Note: $v0 is a symbolic name used by the assember for $2. # $a0 is a symbolic name used by the assember for $4. .data prompt_str: .asciiz "Please type a text string: " prompt_ptr: .asciiz "Please type a pattern string: " print_yes: .asciiz "Yes, there is a match." print_no: .asciiz "No, there is no match." text_str: .asciiz "Text string : " pattern_str: .asciiz "Pattern string : " print_out: .asciiz "Output to be produced :" print_dash: .asciiz "----------------------" print_index: .asciiz "Starting index :" print_msg : .asciiz "Length of longest partial match = " nl: .asciiz "\n" str : .space 81 ptr : .space 81 tmp : .space 81 .text main: la $a0, prompt_str li $v0, 4 #print_string command. syscall la $a0,str #read string li $a1,81 li $v0,8 syscall la $t0,str #move string to $t0 la $a0,prompt_ptr li $v0,4 #print pattern command syscall la $a0,ptr #read pattern li $a1,81 li $v0,8 syscall la $t1,ptr #move pattern to $t1 la $t5,tmp #move temp to $t5 lb $t2,0($t0) #pointer first element array of string lb $t3,0($t1) #pointer first element array of pattern lb $t6,0($t5) #pointer first element array of temp loop : beq $t3,$0,end_loop beq $t2,$t3,match addiu $t0,$t0,1 j loop match : move $t6,$t2 addiu $t5,$t5,1 addiu $t0,$t0,1 addiu $t1,$t1,1 j print_match print_match : la $a0,text_str #print string li $v0,4 syscall move $a0,$t0 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,pattern_str #print pattern string li $v0,4 syscall move $a0,$t1 li $v0,4 syscall la $a0,nl #print newline character li $v0,4 syscall la $a0,print_out #print output line and newline character li $v0,4 syscall la $a0,nl li $v0,4 syscall la $a0,print_dash li $v0,4 syscall la $a0,print_yes li $v0,4 syscall la $a0,print_index #print starting index li $v0,4 syscall li $v0,10 syscall end_loop : li $v0,10 syscall

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  • Make a Perl-style regex interpreter behave like a basic or extended regex interpreter

    - by Barry Brown
    I am writing a tool to help students learn regular expressions. I will probably be writing it in Java. The idea is this: the student types in a regular expression and the tool shows which parts of a text will get matched by the regex. Simple enough. But I want to support several different regex "flavors" such as: Basic regular expressions (think: grep) Extended regular expressions (think: egrep) A subset of Perl regular expressions, including the character classes \w, \s, etc. Sed-style regular expressions Java has the java.util.Regex class, but it supports only Perl-style regular expressions, which is a superset of the basic and extended REs. What I think I need is a way to take any given regular expression and escape the meta-characters that aren't part of a given flavor. Then I could give it to the Regex object and it would behave as if it was written for the selected RE interpreter. For example, given the following regex: ^\w+[0-9]{5}-(\d{4})?$ As a basic regular expression, it would be interpreted as: ^\\w\+[0-9]\{5\}-\(\\d\{4\}\)\?$ As an extended regular expression, it would be: ^\\w+[0-9]{5}-(\\d{4})?$ And as a Perl-style regex, it would be the same as the original expression. Is there a "regular expression for regular expressions" than I could run through a regex search-and-replace to quote the non-meta characters? What else could I do? Are there alternative Java classes I could use?

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  • How do you unit test a LINQ query using Moq and Machine.Specifications?

    - by Phil.Wheeler
    I'm struggling to get my head around how to accommodate a mocked repository's method that only accepts a Linq expression as its argument. Specifically, the repository has a First() method that looks like this: public T First(Expression<Func<T, bool>> expression) { return All().Where(expression).FirstOrDefault(); } The difficulty I'm encountering is with my MSpec tests, where I'm (probably incorrectly) trying to mock that call: public abstract class with_userprofile_repository { protected static Mock<IRepository<UserProfile>> repository; Establish context = () => { repository = new Mock<IRepository<UserProfile>>(); repository.Setup<UserProfile>(x => x.First(up => up.OpenID == @"http://testuser.myopenid.com")).Returns(GetDummyUser()); }; protected static UserProfile GetDummyUser() { UserProfile p = new UserProfile(); p.OpenID = @"http://testuser.myopenid.com"; p.FirstName = "Joe"; p.LastLogin = DateTime.Now.Date.AddDays(-7); p.LastName = "Bloggs"; p.Email = "[email protected]"; return p; } } I run into trouble because it's not enjoying the Linq expression: System.NotSupportedException: Expression up = (up.OpenID = "http://testuser.myopenid.com") is not supported. So how does one test these sorts of scenarios?

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  • Make Python Socket Server More Efficient

    - by BenMills
    I have very little experience working with sockets and multithreaded programming so to learn more I decided to see if I could hack together a little python socket server to power a chat room. I ended up getting it working pretty well but then I noticed my server's CPU usage spiked up over 100% when I had it running in the background. Here is my code in full: http://gist.github.com/332132 I know this is a pretty open ended question so besides just helping with my code are there any good articles I could read that could help me learn more about this? My full code: import select import socket import sys import threading from daemon import Daemon class Server: def __init__(self): self.host = '' self.port = 9998 self.backlog = 5 self.size = 1024 self.server = None self.threads = [] self.send_count = 0 def open_socket(self): try: self.server = socket.socket(socket.AF_INET6, socket.SOCK_STREAM) self.server.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1) self.server.bind((self.host,self.port)) self.server.listen(5) print "Server Started..." except socket.error, (value,message): if self.server: self.server.close() print "Could not open socket: " + message sys.exit(1) def remove_thread(self, t): t.join() def send_to_children(self, msg): self.send_count = 0 for t in self.threads: t.send_msg(msg) print 'Sent to '+str(self.send_count)+" of "+str(len(self.threads)) def run(self): self.open_socket() input = [self.server,sys.stdin] running = 1 while running: inputready,outputready,exceptready = select.select(input,[],[]) for s in inputready: if s == self.server: # handle the server socket c = Client(self.server.accept(), self) c.start() self.threads.append(c) print "Num of clients: "+str(len(self.threads)) self.server.close() for c in self.threads: c.join() class Client(threading.Thread): def __init__(self,(client,address), server): threading.Thread.__init__(self) self.client = client self.address = address self.size = 1024 self.server = server self.running = True def send_msg(self, msg): if self.running: self.client.send(msg) self.server.send_count += 1 def run(self): while self.running: data = self.client.recv(self.size) if data: print data self.server.send_to_children(data) else: self.running = False self.server.threads.remove(self) self.client.close() """ Run Server """ class DaemonServer(Daemon): def run(self): s = Server() s.run() if __name__ == "__main__": d = DaemonServer('/var/servers/fserver.pid') if len(sys.argv) == 2: if 'start' == sys.argv[1]: d.start() elif 'stop' == sys.argv[1]: d.stop() elif 'restart' == sys.argv[1]: d.restart() else: print "Unknown command" sys.exit(2) sys.exit(0) else: print "usage: %s start|stop|restart" % sys.argv[0] sys.exit(2)

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  • Simple way to decrease values without making a new attribute?

    - by Jam
    I'm making a program where you're firing a 'blaster', and I have 5 ammo. I'm blasting an alien who has 5 health. At the end I instantiate the player and make him blast 6 times to check that the program works correctly. But the way I've done it makes it so that the amount won't decrease. Is there an easy fix to this, or do I just have to make a new attribute for ammo and health? Here's what I have: class Player(object): """ A player in a shooter game. """ def blast(self, enemy, ammo=5): if ammo>=1: ammo-=1 print "You have blasted the alien." print "You have", ammo, "ammunition left." enemy.die(5) else: print "You are out of ammunition!" class Alien(object): """ An alien in a shooter game. """ def die(self, health=5): if health>=1: health-=1 print "The alien is wounded. He now has", health, "health left." elif health==0: health-=1 print "The alien gasps and says, 'Oh, this is it. This is the big one. \n" \ "Yes, it's getting dark now. Tell my 1.6 million larvae that I loved them... \n" \ "Good-bye, cruel universe.'" else: print "The alien's corpse sits up momentarily and says, 'No need to blast me, I'm dead already!" # main print "\t\tDeath of an Alien\n" hero = Player() invader = Alien() hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) hero.blast(invader) raw_input("\n\nPress the enter key to exit.")

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  • Modify static variables while debugging in Eclipse

    - by sleske
    As an extension the the question "Modify/view static variables while debugging in Eclipse", I'd like to be able to modify static variables while debugging in Eclipse. For instance and local variables, I can just choose the variable in the "Variables" view of Eclipse, and use the context menu "Change value..." to change the value. This is not possible for arbitrary static variables, because they do not appear in the "Variables" view. What I tried: If you choose "Java / Show static variables" from the triangle menu in the "Variables" view, you can see and modify static member variables of the variables listed in the "Variables view". However, I did not find how to access a static member of a class whose instance does not appear in the "Variables view". You can of course enter a static member as an expression into the "Expression view" (using fully qualified name). Then you can see the value, but the "Expression view" does not have an option to modify the value (it does allow to modify members of an expression, but not the expression itself, even if the expression is a field). So, if I have a static variable like a boolean MyClass.disableAllBugs, is there a way to change MyClass.disableAllBugs during debugging? As an aside: I realize that even having public mutable static fields (i.e. mutable global variables) is very bad style. But some codebases have it, and then it's sometimes useful to modify it while debugging.

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  • Problem running a Python program, error: Name 's' is not defined.

    - by Sergio Tapia
    Here's my code: #This is a game to guess a random number. import random guessTaken = 0 print("Hello! What's your name kid") myName = input() number = random.randint(1,20) print("Well, " + myName + ", I'm thinking of a number between 1 and 20.") while guessTaken < 6: print("Take a guess.") guess = input() guess = int(guess) guessTaken = guessTaken + 1 if guess < number: print("You guessed a little bit too low.") if guess > number: print("You guessed a little too high.") if guess == number: break if guess == number: guessTaken = str(guessTaken) print("Well done " + myName + "! You guessed the number in " + guessTaken + " guesses!") if guess != number: number = str(number) print("No dice kid. I was thinking of this number: " + number) This is the error I get: Name error: Name 's' is not defined. I think the problem may be that I have Python 3 installed, but the program is being interpreted by Python 2.6. I'm using Linux Mint if that can help you guys help me. Using Geany as the IDE and pressing F5 to test it. It may be loading 2.6 by default, but I don't really know. :( Edit: Error 1 is: File "GuessingGame.py", line 8, in <Module> myName = input() Error 2 is: File <string>, line 1, in <Module>

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  • Python Twisted Client Connection Lost

    - by MovieYoda
    I have this twisted client, which connects with a twisted server having an index. I ran this client from command-line. It worked fine. Now I modified it to run in loop (see main()) so that I can keep querying. But the client runs only once. Next time it simply says connection lost \n Connection lost - goodbye!. What am i doing wrong? In the loop I am reconnecting to the server, it that wrong? from twisted.internet import reactor from twisted.internet import protocol from settings import AS_SERVER_HOST, AS_SERVER_PORT # a client protocol class Spell_client(protocol.Protocol): """Once connected, send a message, then print the result.""" def connectionMade(self): self.transport.write(self.factory.query) def dataReceived(self, data): "As soon as any data is received, write it back." if data == '!': self.factory.results = '' else: self.factory.results = data self.transport.loseConnection() def connectionLost(self, reason): print "\tconnection lost" class Spell_Factory(protocol.ClientFactory): protocol = Spell_client def __init__(self, query): self.query = query self.results = '' def clientConnectionFailed(self, connector, reason): print "\tConnection failed - goodbye!" reactor.stop() def clientConnectionLost(self, connector, reason): print "\tConnection lost - goodbye!" reactor.stop() # this connects the protocol to a server runing on port 8090 def main(): print 'Connecting to %s:%d' % (AS_SERVER_HOST, AS_SERVER_PORT) while True: print query = raw_input("Query:") if query == '': return f = Spell_Factory(query) reactor.connectTCP(AS_SERVER_HOST, AS_SERVER_PORT, f) reactor.run() print f.results return if __name__ == '__main__': main()

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