Search Results

Search found 11227 results on 450 pages for 'login attempts'.

Page 112/450 | < Previous Page | 108 109 110 111 112 113 114 115 116 117 118 119  | Next Page >

• Submit form with POST data in Android app

  - by datguywhowanders

  I've been searching the web for a way to do this for about a week now, and I just can't seem to figure it out. I'm trying to implement an app that my college can use to allow users to log in to various services on the campus with ease. The way it works currently is they go to an online portal, select which service they want, fill in their user name and pwd, and click login. The form data is sent via post (it includes several hidden values as well as just the user name and pwd) to the corresponding login script which then signs them in and loads the service. I've been trying to come at the problem in two ways. I first tried a WebView, but it doesn't seem to want to support all of the html that normally makes this form work. I get all of the elements I need, fields for user and pwd as well as a login button, but clicking the button doesn't do anything. I wondered if I needed to add an onclick handler for it, but I can't see how as the button is implemented in the html of the webview not using a separate android element. The other possibility was using the xml widgets to create the form in a nice relative layout, which seems to load faster and looks better on the android screen. I used EditText fields for the input, a spinner widget for the service select, and the button widget for the login. I know how to make the onclick and item select handlers for the button and spinner, respectively, but I can't figure out how to send that data via POST in an intent that would then launch a browser. I can do an intent with the action url, but can't get the POST data to feed into it. Anyone have any suggestions?

  Read the article

• How to process XML sernt via POST?

  - by John Conde

  I'm receiving XML sent via POST. Naturally I need to parse this XML to get at the goodies it holds for me. However, when I receive the XML is seems that PHP is parsing it like a query string. For example, this xml: <?xml version="1.0" encoding="utf-8"?> <ForgotPassword> <version>1.0</version> <authentication> <login>myresllerid</login> <apikey>1234567890abcdef</apikey> </authentication> <parameters> <emailAddress>[email protected]</emailAddress> </parameters> </ForgotPassword> Becomes this (from print_r($_REQUEST)): Array ( [ <?xml_version] => "1.0" encoding="utf-8"?> <IDCForgotPassword> <version>1.0</version> <authentication> <login>myresllerid</login> <apikey>1234567890abcdef</apikey> </authentication> <parameters> <emailAddress>[email protected]</emailAddress> </parameters> </IDCForgotPassword> ) You can see the XML is being broken up at the first equals sign (=) in the XML into a key/value pair. How do I avoid this?

  Read the article

• Http authentication with apache httpcomponents

  - by matdan

  Hi, I am trying to develop a java http client with apache httpcomponents 4.0.1. This client calls the page "https://myHost/myPage". This page is protected on the server by a JNDIRealm with a login form authentication, so when I try to get https://myHost/myPage I get a login page. I tried to bypass it unsuccessfully with the following code : //I set my proxy HttpHost proxy = new HttpHost("myProxyHost", myProxyPort); //I add supported schemes SchemeRegistry supportedSchemes = new SchemeRegistry(); supportedSchemes.register(new Scheme("http", PlainSocketFactory .getSocketFactory(), 80)); supportedSchemes.register(new Scheme("https", SSLSocketFactory .getSocketFactory(), 443)); // prepare parameters HttpParams params = new BasicHttpParams(); HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1); HttpProtocolParams.setContentCharset(params, "UTF-8"); HttpProtocolParams.setUseExpectContinue(params, true); ClientConnectionManager ccm = new ThreadSafeClientConnManager(params, supportedSchemes); DefaultHttpClient httpclient = new DefaultHttpClient(ccm, params); httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY, proxy); //I add my authentication information httpclient.getCredentialsProvider().setCredentials( new AuthScope("myHost/myPage", 443), new UsernamePasswordCredentials("username", "password")); HttpHost host = new HttpHost("myHost", 443, "https"); HttpGet req = new HttpGet("/myPage"); //show the page ResponseHandler<String> responseHandler = new BasicResponseHandler(); String rsp = httpClient.execute(host, req, responseHandler); System.out.println(rsp); When I run this code, I always get the login page, not myPage. How can I apply my credential parameters to avoid this login form? Any help would be fantastic

  Read the article

• Django URL Conf Returns Incorrect "Current URL"

  - by natnit

  I have a django app that is mostly done, and the URLs work perfectly when I run it with the manage.py runserver command. However, I've recently tried to get it running via lighttpd, and many links have stopped working. For example: http://mysite.com/races/32 should work, but instead throws this error message. Page not found (404) Request Method: GET Request URL: http://mysite.com/races/32 Using the URLconf defined in racetrack.urls, Django tried these URL patterns, in this order: ^admin/ ^create/$ ^races/$ ^races/(?P<race_id>\d+)/$ ^races/(?P<race_id>\d+)/manage/$ ^races/(?P<text>\w+)/$ ^user/(?P<kol_id>\d+)/$ ^$ ^login/$ ^logout/$ The current URL, 32, didn't match any of these. The request URL is accurate, but the last line (which displays the current URL) is giving 32 instead of races/32 as expected. Here is my urlconf: from django.conf.urls.defaults import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('racetrack.races.views', (r'^admin/', include(admin.site.urls)), (r'^create/$', 'create'), (r'^races/$', 'index'), (r'^races/(?P<race_id>\d+)/$', 'detail'), (r'^races/(?P<race_id>\d+)/manage/$', 'manage'), (r'^races/(?P<text>\w+)/$', 'index'), (r'^user/(?P<kol_id>\d+)/$', 'user'), # temporary for index page replace with welcome page (r'^$', 'index'), ) urlpatterns += patterns('django.contrib.auth.views', (r'^login/$', 'login', {'template_name': 'races/login.html'}), (r'^logout/$', 'logout', {'next_page': '/'}), ) Thank you.

  Read the article

• Accept All Cookies via HttpClient

  - by Vinay

  So this is currently how my app is set up: 1.) Login Activity. 2.) Once logged in, other activities may be fired up that use PHP scripts that require the cookies sent from logging in. I am using one HttpClient across my app to ensure that the same cookies are used, but my problem is that I am getting 2 of the 3 cookies rejected. I do not care about the validity of the cookies, but I do need them to be accepted. I tried setting the CookiePolicy, but that hasn't worked either. This is what logcat is saying: 11-26 10:33:57.613: WARN/ResponseProcessCookies(271): Cookie rejected: "[version: 0] [name: cookie_user_id][value: 1][domain: www.trackallthethings.com][path: trackallthethings][expiry: Sun Nov 25 11:33:00 CST 2012]". Illegal path attribute "trackallthethings". Path of origin: "/mobile-api/login.php" 11-26 10:33:57.593: WARN/ResponseProcessCookies(271): Cookie rejected: "[version: 0][name: cookie_session_id][value: 1985208971][domain: www.trackallthethings.com][path: trackallthethings][expiry: Sun Nov 25 11:33:00 CST 2012]". Illegal path attribute "trackallthethings". Path of origin: "/mobile-api/login.php" I am sure that my actual code is correct (my app still logs in correctly, just doesn't accept the aforementioned cookies), but here it is anyway: HttpGet httpget = new HttpGet(//MY URL); HttpResponse response; response = Main.httpclient.execute(httpget); HttpEntity entity = response.getEntity(); InputStream in = entity.getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader(in)); StringBuilder sb = new StringBuilder(); From here I use the StringBuilder to simply get the String of the response. Nothing fancy. I understand that the reason my cookies are being rejected is because of an "Illegal path attribute" (I am running a script at /mobile-api/login.php whereas the cookie will return with a path of just "/" for trackallthethings), but I would like to accept the cookies anyhow. Is there a way to do this?

  Read the article

• DotNetOpeId - Using OpenIdButton for Google Apps

  - by JediPotPie

  I am an ASP.NET newbie and I am trying to design an OpenID/SSO system for an internal web application. The web application is pretty simple and the authentication is currently being managed by a database with usernames and passwords. I want to replace the existing accounts stored in the database with Google Apps accounts. I have downloaded the latest DotNetOpenAuth-3.4.3.10103 package and got the OpenIdRelyingPartyWebForms sample up and running on IIS. I have built my own login page using just a OpenIdButton object that points to a development Google domain. The button seems to work fine in FireFox, at least it is forwarding me to the Google Apps login, but nothing happens when I load the same page in IE. When I click the Google button, nothing happens, zip. The same is true for the Yahoo button in the login.aspx page given in the sample. Here is the .aspx code I am using... <rp:OpenIdButton runat="server" ImageUrl="http://www.google.com/accounts/google_transparent.gif" Text="Login with Google!" ID="googleLoginButton" Identifier="https://www.google.com/accounts/o8/site-xrds?hd=dev.connexcloud.com" />

  Read the article

• Kohana Auth Library Deployment

  - by Steve

  My Kohana app runs perfectly on my local machine. When I deployed my app to a server (and adjust the config files appropriately), I can no longer log into the app. I've traced through the app login routine on both my local version and the server version and they both agree with each other all the way through until you get to the auth.php controller logged_in() routine where suddenly, at line 140 - the is_object($this-user) test - the $user object no longer exists!?!?!? The login() function call that calls the logged_in() function successfully passes the following test, which causes a redirect to the logged_in() function. if(Auth::instance()->login($user, $post['password'])) Yes, the password and hash, etc all work perfectly. Here is the offending code: public function logged_in() { if ( ! is_object($this->user)) { // No user is currently logged in url::redirect('auth/login'); } etc... } As the code is the same between my local installation and the server, I reckon it must be some server setting that is messing with me. FYI: All the rest of the code works because I have a temporary backdoor available that allows me to use the application (view pages of tables, etc) without being logged in. Any ideas?

  Read the article

• The post->success->data variable is empty..

  - by Asaf

  Hello, I tried sending some data like so: <form action="http://www.someurl.com/something.php" id="login"> <input type="textbox" id="UserName" value="user"> <input type="textbox" id="Password" value="password"> <input type="submit" value="submit"> </form> <div id="result"></div> <script type="text/javascript"> $('form#login').submit(function() { $.post($('form#login').attr('action'), $('form#login').serialize(), function(data) { $('#result').html(data+'222') }); return false; }); </script> Now, the value of #result div change to 222... that is: the post was successful but for some reason there is no data, and when I go directly to something.php and post manually, it does bring back data (am I mistaken or does the post(success(data)) variable returns the whole page returned after you post something? if so, how could it be?) Thank you very much for your help

  Read the article

• Tomcat does not pick up the class file - the JSP file is not displayed

  - by blueSky

  I have a Java code which is a controller for a jsp page, called: HomeController.java. Code is as follows: @Controller public class HomeController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/mypage") public String home() { System.out.println("HomeController: Passing through..."); return "home"; } } There is nothing especial in the jsp page: home.jsp. If I go to this url: http://localhost:8080/adcopyqueue/mypage I can view mypage and everything works fine. Also in the tomcat Dos page I can see the comment: HomeController: Passing through... As expected. Now under the same directory that I have HomeController.java, I've created another file called: LoginController.java. Following is the code: @Controller public class LoginController { protected final transient Log log = LogFactory.getLog(getClass()); @RequestMapping(value = "/loginpage") public String login() { System.out.println("LoginController: Passing through..."); return "login"; } } And under the same place which I have home.jsp, I've created login.jsp. Also under tomcat folders, LoginController.class exists under the same folder that HomeController.class exists and login.jsp exists under the same folder which home.jsp exists. But when I go to this url: http://localhost:8080/adcopyqueue/loginpage Nothing is displayed! I think tomcat does not pick up LoginController.class b/c on the tomcat Dos window, I do NOT see this comment: LoginController: Passing through... Instead I see following which I do not know what do they mean? [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:34) got manifest [ INFO] [http-8080-1 01:43:45] (AppInfo.java:populateAppInfo:36) manifest entrie s 8 The structure and the code for HomeController.java and LoginController.java plus the jsp files match. I have no idea why tomcat sees one of the files and not the other? Clean build did not help. Does anybody have any idea? Any help is greatly appraciated.

  Read the article

• Create Session Variable from different datasources?

  - by Szafranamn

  Currently I am developing a dynamic website using Dreamweaver cs5 with ColdFusion 9 and using Access to create my databases along with QuickBooks and QODBC to create database. I have established a login session variable stemming from the login page. This session variable is being drawn from one Datasource "Access" Table "Logininfo" Field "FullName" but I wanted to create another session variable either at this point or further into the member's page to use in a query sequence. This session variable would stem from another Datasoucre "QBs" Table "Invoice" Field "CustomerRefFullName" which is generated through Quickbooks and QODBC. I am not sure if this is possible but if it is how do I do it. I want to do this so I can query the Invoice database to upload the customer's Invoices unique to them onto their page. So it would have to be related to their login credentials. If there is another better route to take I would greatly appreciate the advice. Below is the login code if there is additional information needed let me know. This is my current thinking/plan to do what I wish to intend hence the need to create the session variable: I have another Datasource "QBs" with a Table "Invoice" when I create another webpage for the customer to see their invoice I need to create a recordset that accesses that Table. In order to do so I think the best way would some home convert the session.FullName (which came from Access Datasource, Logininfor Table) into a session.CustomerRefFullName (which would have to come from (Datasource: QBs Table: Invoice Field: CustomerRefFullName) that way I could set the query WHERE CustomerRefFullName and have each logged in user see their specific Invoices. So is there a way to turn the session variable off one datasource/table into a different sessionvariable off a new datasource/table even if it is unique just to that page??? <cfif IsDefined("FORM.username")> SELECT FullName, Username,Password,AccessLevels FROM Logininfo WHERE Username= AND Password=

  Read the article

• How can I debug PEAR auth?

  - by croceldon

  I have a directory on my site that I've implemented PEAR's Auth to run my authentication. It is working great. However, I've tried to make a copy of my site (it's going to be translated to a different language), and on this new site, the Auth process doesn't seem to be working correctly. I can login properly, but every time I try to go to a different page in the same directory, and use Auth to authorize, it forces me to login again. Here's my logic: $auth_options = array( 'dsn' => mysql://user:password@server/db', 'table' => 'users', 'usernamecol' => 'username', 'passwordcol' => 'password', 'db_fields' => '*' ); $auth = new Auth("DB", $auth_options, "login_function"); $auth->setFailedLoginCallback('bad_login'); $auth->start(); if (!$auth->checkAuth()) { die('cannot succeed in checkAuth') exit; } else { include("nocache.php"); } This is part of a file that's included in every php page I that I desire to require authentication. I can login properly once, but whenever I then try to go to a different page that requires authentication, it makes me login again (and I see the 'cannot succeed' die message at the bottom of the page). Again, this solution works fine on my original site, I copied all the files, and only changed the db server/password - it still doesn't work. And I'm using the same webhost for both. What am I doing wrong here? Or how can I debug this further?

  Read the article

• javax.xml.bind.MarshalException

  - by sandeep

  Hi, I am getting javax.xml.bind.MarshalException error. I am sending List from my webservice to the backingbean and I have this error. Here is my code: Backing bean @WebServiceRef(wsdlLocation = "http://localhost:26565/Login_webserviceService/Login_webservice?WSDL") public String login() { System.out.println("Login Phase entered"); int result = 0; List list; List finalList = null; try { Weblogin.LoginWebserviceService service = new Weblogin.LoginWebserviceService(); Weblogin.LoginWebservice port = service.getLoginWebservicePort(); result = port.login(voterID, password); Weblogin.LoginWebservice port1 = service.getLoginWebservicePort(); list = port1.candDetails(1); finalList = list; this.setList(finalList); } catch (Exception e) { e.printStackTrace(); } if (result == 1) return "polling"; else return "login"; } Webservice public List candDetails(int pollEvent) { List resultList = null; List finalList = null; try { if (pollEvent == 1) { resultList = em.createNamedQuery("Cantable.findAll").getResultList(); finalList = resultList; } } catch (Exception e) { e.printStackTrace(); } return resultList; }

  Read the article

• Sharing same properties of ViewController for iPhone Stroryboard and iPad Story Board

  - by Ruhul Amin

  I'm developing a universal application. in the first view, I have the login screen for the user. In iPhone storyBoard, I have added 2 text field and one button( login check). I have added properties in ViewController.h file by dragging those objects(Ctrl key + Dragg) to .h file. I have added code for login check and it is working fine for iPhone. This is the code in ViewController.h @property (strong, nonatomic) IBOutlet UITextField *txtUserId; @property (strong, nonatomic) IBOutlet UITextField *txtUserPwd; @property (strong, nonatomic) IBOutlet UIButton *btnLogin; In the iPad storyBoard, I have added 2 text field( userid and password) and i button for login. So now, I want to bind those objects with the veriable which I declared already in ViewController.h file in case of iPhone. My questions: 1. What is the right way to bind properties for both storyboard? 2. Am I on the right direction or should I think in a different way to do it? I am new with iPhone development. Please help. Thanks. --Amin

  Read the article

• What would be a better implementation of shared variable among subclass

  - by Churk

  So currently I have a spring unit testing application. And it requires me to get a session cookie from a foreign authentication source. Problem what that is, this authentication process is fairly expensive and time consuming, and I am trying to create a structure where I am authenticate once, by any subclass, and any subsequent subclass is created, it will reuse this session cookie without hitting the authentication process again. My problem right now is, the static cookie is null each time another subclass is created. And I been reading that using static as a global variable is a bad idea, but I couldn't think of another way to do this because of Spring framework setting things during run time and how I would set the cookie so that all other classes can use it. Another piece of information. The variable is being use, but is change able during run time. It is not a single user being signed in and used across the board. But more like a Sub1 would call login, and we have a cookie. Then multiple test will be using that login until SubX will come in and say, I am using different credential, so I need to login as something else. And repeats. Here is a outline of my code: public class Parent implements InitializingBean { protected static String BASE_URL; public static Cookie cookie; ... All default InitializingBean methods ... afterPropertiesSet() { cookie = // login process returns a cookie } } public class Sub1 extends Parent { @resource public String baseURL; @PostConstruct public void init() { // set parents with my baseURL; BASE_URL = baseURL; } public void doSomething() { // Do something with cookie, because it should have been set by parent class } } public class Sub2 extends Parent { @resource public String baseURL; @PostConstruct public void init() { // set parents with my baseURL; BASE_URL = baseURL; } public void doSomethingElse() { // Do something with cookie, because it should have been set by parent class } }

  Read the article

• Codeigniter Inputting session data from model for a simple authentication system

  - by user1616244

  Trying to put together a simple login authentication. Been at this for quite sometime, and I can't find where I'm going wrong. Pretty new to Codeigniter and OOP PHP. I know there are authentication libraries out there, but I'm not interested in using those. Model: function login($username, $password){ if ($this->db->table_exists($username)){ $this->db->where('username', $username); $this->db->where('password', $password); $query = $this->db->get($username); if($query->num_rows >= 1) { return true; $data = array( 'username' => $this->input->post('username'), 'login' => true ); $this->session->set_userdata($data); } } } Controller function __construct(){ parent::__construct(); $this->logincheck(); } public function logincheck(){ if ($this->session->userdata('login')){ redirect('/members'); } } If I just echo from the controller: $this-session-all_userdata(); I get an empty array. So the problem seems to be that the $data array in the model isn't being stored in the session.

  Read the article

• How to avoid notice in php when one of the conditions is not true

  - by user225269

  I've notice that when one of the two conditions in a php if statement is not true. You get an undefined index notice for the statement that is not true. And the result in my case is a distorted web page. For example, this code: <?php session_start(); if (!isset($_SESSION['loginAdmin']) && ($_SESSION['loginAdmin'] != '')) { header ("Location: loginam.php"); } else { include('head2.php'); } if (!isset($_SESSION['login']) && ($_SESSION['login'] != '')) { header ("Location: login.php"); } else { include('head3.php'); } ?> If one of the if statements is not true. The one that is not true will give you a notice that it is undefined. In my case it says that the session 'login' is not defined. If session 'LoginAdmin' is used. What can you recommend that I would do in order to avoid these undefined index notice.

  Read the article

• $_SERVER['HTTP_REFERER'] not working with Header

  - by EmmyS

  I have a site that allows public access to some pages, but requires a login for others. I have a link to the login from all pages, and what I'd like to do after a successful login is send the user back to the page they were on when they clicked the login link. I know the HTTP_REFERER can be spoofed, and sometimes stripped out by certain hosts and proxies, but since it's strictly within my own site, and only a convenience for users, I'm not too worried about it. I am curious about why it isn't working in conjunction with a redirect, though. I've set a visible field to contain the value of the http referer, and it displays correctly. So the page is getting the value of the referrer variable. But when I try this: $home_url = $_SERVER['HTTP_REFERER']; header('Location: ' . $home_url); it doesn't work. This, on the other hand, does: $home_url = 'http://' . $_SERVER['HTTP_HOST'].dirname($_SERVER['PHP_SELF']).'/discussions.php'; header('Location: ' . $home_url); So I know the header location part works. Any idea why it doesn't want to work in conjunction with the http_referer variable? (Also, does it drive anyone else nuts that referer is spelled incorrectly? I keep mistyping it using the OED spelling, silly me...)

  Read the article

• jquery an div tags used in a ordered list

  - by shan2on

  hello everyone, i'm not sure where my errors are lying but here is my scenario... i have an un-ordered list in html that handles my main link bar... <ul id="navlist"> <li><a href="/" id="current">home</a></li> <li><a href="#" id="search">search</a></li> <li><a href="#" id="users">login</a></li> </ul> and what i want done is to call each id and have jQuery handle each and dislpay it where specified in my css file... for now, lets just ignore my "home" link... here is a snippet of my inline jquery $(document).ready(function() { $("a").click(function () { $("div#login").slideToggle("fast"); }); }) Now, whichever div i specify, it calls that ... however it will only call one div, using either from the un-orderd list, as mentioned above in the html. My Goal is to call a search bar when search is clicked, and to call a login box when login is clicked. to my knowledge (noob), i believe use an as a class, however that is what brings me here. i believe my error is in my jquery and not my css, as stated above, either instance will be displayed when the jquery function calls either tag. any help is greatly appreciated. thanks in advance shan2on

  Read the article

• php session_start() error

  - by tooepic

  Hi, i've used a sample found on online and applied it to my code: <?php session_start(); if (isset($_REQUEST["email"])) { $_SESSION["name"] = true; $host = $_SERVER["HTTP_HOST"]; $path = dirname($_SERVER["PHP_SELF"]); $sid = session_name() . "=" . session_id(); header("Location: index.php?$sid"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> ... ... and rest of the html code When I open this page, I got an error: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 I looked around to resolve this issue and saw few posts about this in this site also, but I just can't get a good grip on this...can't find the answer. Please help. Thanks.

  Read the article

• Redirection Still not working (updated on earlier question)

  - by NoviceCoding

  So earlier I asked this question: JQuery Login Redirect. Code Included The php file is sending the following: $return['error'] = false; $return['msg'] = 'You have successfully logged in!!'; I've tried all the suggestions, quoting the error on php and ajax end, 2 equals instead of 3, I've also tried DNE true which should be the same as an else statement: $(document).ready(function(){ $('#submit').click(function() { $('#waiting').show(500); $('#empty').show(500); $('#reg').hide(0); $('#message').hide(0); $.ajax({ type : 'POST', url : 'logina.php', dataType : 'json', data: { type : $('#typeof').val(), login : $('#login').val(), pass : $('#pass').val(), }, success : function(data){ $('#waiting').hide(500); $('#empty').show(500); $('#message').removeClass().addClass((data.error === true) ? 'error' : 'success') .text(data.msg).show(500) if(data.error != true) window.location.replace("http://blahblah.com/usercp.php"); if (data.error === true) $('#reg').show(500); $('#empty').hide() }, error : function(XMLHttpRequest, textStatus, errorThrown) { $('#waiting').hide(500); $('#message').removeClass().addClass('error') .text("There was an Error. Please try again.").show(500); $('#reg').show(500); $('#empty').hide(); Recaptcha.reload(); } }); return false; }); And it still wont work. Any ideas on how to make a redirection work if login is successful and error returns false? Also while I am asking, can I put a .delay(3000) 3s at the end of window.location.replace("http://blahblah.com/usercp.php")?

  Read the article

• Is OpenID too complicated?

  - by John Leidegren

  I'm beginning to seriously doubt the OpenID community despite that fact that it works. I'm in the process of currently evaluating OpenID as an authentication service for 'this' site and while the promises are great, I just can't get it to work. And I'm really lost. I ask of the SO community to help me out here. Give me answers and show me examples so I can leverage this in the way it was meant to be. My scenario is very typical. I want to authenticate users through a specific Google Apps domain. If you have access to this Google Apps domain, then you have access to my web application. Where I get lost, is all the prerequisites and dependencies involved. What is XRD? What is Yadis? Why do I need XRD and Yadis? What do I need to do to deploy OpenID authentication on my website? Also, this is really important to me. When I login to SO, I use my Google Account. When I click the login button I'm presented with this confirmation page. Where I'm granting SO the right to use my Google Account credentials. Somehow, Google knows that it's "Stackoverflow.com" that's asking me if it's okay to login. And I wish to know what manner of control I have over this little text. I intend to deploy OpenID on several different domains but I would prefer if they would all work without having to be individually configured with special parameters, such as secret API keys and what not. However, I don't know for sure if this is a prerequisite of OpenID, that or the Federated Login API that Google provides.

  Read the article

• PHP checking/refreashing functions

  - by user1284360

  ok i have a main document that displays a chatbox, what i want is for the chatbox to refreash on everyone who is logged in's screen whenever someone posts a new message... ive tried many methods including sleep timers and new functions that call then sleep and get recalled but this just generates an endless line of the same or little diffrent data making the form unusable until error... this is my code <?php // set error reporting level if (version_compare(phpversion(), "5.3.0", ">=") == 1) error_reporting(E_ALL & ~E_NOTICE & ~E_DEPRECATED); else error_reporting(E_ALL & ~E_NOTICE); require_once('inc/login.inc.php'); require_once('inc/chat.inc.php'); // initialization of login system and generation code $oSimpleLoginSystem = new SimpleLoginSystem(); $oSimpleChat = new SimpleChat(); // draw login box echo $oSimpleLoginSystem->getLoginBox(); // draw chat application $sChatResult = '<font color="0x99000"> <a href="Register_form.html">New Account</a><br> login to send a message<br> or register for a new account</font>'; if ($_COOKIE['member_name'] && $_COOKIE['member_pass']) { if ($oSimpleLoginSystem->check_login($_COOKIE['member_name'], $_COOKIE['member_pass'])) { $sChatResult = ""; if($oSimpleLoginSystem->check_privledges($_COOKIE['member_name']) >= 2) { $sChatResult .= "<br>privledge check Working<br>"; } $sChatResult .= "<form action=$_SERVER[PHP_SELF] method='post'> <input type='hidden' name='foo' value='<?= $foo ?>' /> <input type='submit' name='submit' value='Refresh Messages' /> </form>"; $sChatResult .= $oSimpleChat->acceptMessages(); $sChatResult .= "<br><br>"; $sChatResult .= $oSimpleChat->getMessages(); } } echo $sChatResult; ?>

  Read the article

• Need for J2me source code

  - by tikamchandrakar

  For J2me It strikes me as odd that you need an extra "api key" and so on. But actually, what I really want is NOT create an extra facebook application that needs to be registered on Facebook. I don't want to create any extra configuration effords necessary for the user of my application to undergo. All my user should need is his well-known login data for facebook. Everything else should be completely transparent to him. So, I thought maybe would u can do the login process, creating a request to the REST server via http. I know this would provide me with an XML. I hope that the this API will somehow automatically transform that XML into an intuitive object model that represents the facebook user data of the respective user. So, I would expect something like userData = new FacebookData(new FacebookConnection("user_name", "password")). Done. If you get, what I mean. No api key. No secret key. Just the well-known login data. Practically, the equivalent to thunderbird webmail, which allows you to access your MSN hotmail account via Thunderbird. Thunderbird webmail will automatically converts the htmls obtained from a hotmail browser login into the data structure usually passed on to a mail client. Hope you get what I mean. I was expecting the equilalent for the your API.

  Read the article

• PHP session corrupt

  - by Baversjo

  Using symfony framework 1.4 I have created a website. I'm using sfguard for authentication. Now, this is working great on WAMP (windows). I can login to several accounts on different browsers and use the website. I have ubuntu server 9.10 running apache (everything up to date and default configuration). On my server, when I login to the website in one browser it works great. When I on my other computer login with another user account on the public website, the login is successful. But when I refresh/go to another page the first user is shown as logged in instead! Also, when I press logout, It's not showing that I'm logged out after page load. When I press f5 again I'm logged out. As mentioned, all this works as expected on my local installation. I'm thinking there something wrong with my PHP session configuration on my ubuntu server, but I've never touched it.. Please help me. This is a school project and I'm presenting it today :(

  Read the article

• How can I automate new system provisioning with scripts under Mac OS X 10.6?

  - by deeviate

  I've been working on this for days but simply cannot find the correct references to make it work. The idea is to have a script that will baseline newly purchased Macs that comes into the company with basic stuffs like set autologin to off, create a new admin user (for remote admins to access for support, set password to unlock screensaver and etc) . Sample list for baseline that admins have to do on each new machine: Click the Login Options button Set Automatic Login: OFF Check: Show the Restart, Sleep, and Shutdown buttons Uncheck: Show input menu in login window Uncheck: Show password hints Uncheck: Use voice over in the login window Check: Show fast user switching menu as Short Name (note: this is only part of a long list to do on each machine) I've managed to find some references to make some parts work. Like autologin can be unset with: defaults write /Library/Preferences/.GlobalPreferences com.apple.userspref.DisableAutoLogin -bool TRUE and I've kinda found ways to muscle in a new user creation (including prompts) with AppleScript and shell commands. But generally its tough finding ways to do somewhat simple things like turn on password to get out of screensaver or to allow fast user switching. References are either too limited or just no where to be seen (e.g. I can unset autologin via cli but the very next setting on the system preference "show restart, sleep and shutdown buttons" is somewhere else and I can't find any command line to make it set) Does anyone have any ideas on a list, document, reference or anything of where each setting on the system resides so that I can be pointed to make it work? or maybe sample scripts for the above example... My thanks for reading thus far—a huge thank you for whoever that has any info on the above.

  Read the article

< Previous Page | 108 109 110 111 112 113 114 115 116 117 118 119  | Next Page >