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  • phpMyAdmin "No database selected" MySQL

    - by user1751660
    I downloaded a MySQL backup file and promptly imported into MAMP's phpMyAdmin. I got this return: Error SQL query: -- -- Database: `mysql` -- -- -------------------------------------------------------- -- -- Table structure for table `columns_priv` -- CREATE TABLE IF NOT EXISTS `columns_priv` ( `Host` CHAR( 60 ) COLLATE utf8_bin NOT NULL DEFAULT '', `Db` CHAR( 64 ) COLLATE utf8_bin NOT NULL DEFAULT '', `User` CHAR( 16 ) COLLATE utf8_bin NOT NULL DEFAULT '', `Table_name` CHAR( 64 ) COLLATE utf8_bin NOT NULL DEFAULT '', `Column_name` CHAR( 64 ) COLLATE utf8_bin NOT NULL DEFAULT '', `Timestamp` TIMESTAMP NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP , `Column_priv` SET( 'Select', 'Insert', 'Update', 'References' ) CHARACTER SET utf8 NOT NULL DEFAULT '', PRIMARY KEY ( `Host` , `Db` , `User` , `Table_name` , `Column_name` ) ) ENGINE = MYISAM DEFAULT CHARSET = utf8 COLLATE = utf8_bin COMMENT = 'Column privileges'; MySQL said: #1046 - No database selected I did not alter the .sql file at all. Any hints on how i can get this puppy going locally? Thanks!

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  • MySQL: How to copy rows, but change a few fields?

    - by Andrew
    I have a large number of rows that I would like to copy, but I need to change one field. I can select the rows that I want to copy: select * from Table where Event_ID = "120" Now I want to copy all those rows and create new rows while setting the Event_ID to 155. How can I accomplish this?

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  • Replace data in MySQL table with data from another table

    - by Oli
    I am trying to modify an existing MySQL database for use in a new application. I have a table of items (table_items), which has multiple fields, including "ItemID" and "ItemName". I have another table (table_list) which has "ItemName" in it, but no ItemID. I need to either update this table to contain ItemID instead of ItemName, or create a new table which imports ItemIDs from table_items as opposed to the ItemName when table_list.ItemName = table_items.ItemName. I have tried the following: UPDATE table_list A, table_items B SET A.ItemName = B.ItemID WHERE A.ItemName = B.ItemName The current table has over 500,000 rows and every time i try this in PHPMyAdmin i get the error "the MySQl server has gone away". Any help greatly appreciated.

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  • MySQL "IS IN" equivalent?

    - by nute
    A while ago I worked on a MS-SQL project and I remember a "IS IN" thing. I tried it on a MySQL project and it did not work. Is there an equivalent? Workaround? Here is the full query I am trying to run: SELECT * FROM product_product, product_viewhistory, product_xref WHERE ( (product_viewhistory.productId = product_xref.product_id_1 AND product_xref.product_id_2 = product_product.id) OR (product_viewhistory.productId = product_xref.product_id_2 AND product_xref.product_id_1 = product_product.id) ) AND product_product.id IS IN (SELECT DISTINCT pvh.productId FROM product_viewhistory AS pvh WHERE pvh.cookieId = :cookieId ORDER BY pvh.viewTime DESC LIMIT 10) AND product_viewhistory.cookieId = :cookieId AND product_product.outofstock='N' ORDER BY product_xref.hits DESC LIMIT 10 It's pretty big ... but the part I am interested in is: AND product_product.id IS IN (SELECT DISTINCT pvh.productId FROM product_viewhistory AS pvh WHERE pvh.cookieId = :cookieId ORDER BY pvh.viewTime DESC LIMIT 10) Which basically says I want the products to be in the "top 10" of that sub-query. How would you achieve that with MySQL (while trying to be efficient)?

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  • What is corret way to connect to MySQL?

    - by sky
    what is the correct way to connect to MySQL database without the mysql_fetch_assoc() error? Getting [Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource] with mysql_connect('localhost', 'name', 'pass'); mysql_select_db('dbname'); getting mysql_fetch_assoc() error without mysql_select_db any suggest? CODE are: $result= mysql_query('SELECT DISTINCT username FROM users'); $somethings= array(); while ($row= mysql_fetch_assoc($results)) { $somethings[]= $row['something']; } ? var somethings= ;

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  • Create table with PHP and populate from MySQL

    - by typoknig
    Hi all, I am creating a table to display on a web page and that table is populated from data in a MySQL database. I am trying to do a couple of things that are making it difficult for me. First I am trying to have call the PHP code that exists in a separate file in HTML via JavaScript. I think I have that working right but I am not 100% sure (because the table will not display). I think it is working right because some of the code for the table (which is in the PHP file) displays in FireBug. Second I am trying to make it so the rows alternate colors for easy viewing too. My PHP code so far is below. The table does not display at all in any browser. $query = "SELECT * FROM employees"; $result = mysql_query($query); $num = mysql_num_rows($result); echo '<table>'; for ($i = 0; $i < $num; $i++){ $row = mysql_fetch_array($result); $id = $row['id']; $l_name = $row['l_name']; $f_name = $row['f_name']; $ssn = $row['ssn']; $class = (($i % 2) == 0) ? "table_odd_row" : "table_even_row"; echo "<tr>"; echo "<td class=" . $class . ">$wrap_id</td>"; echo "<td class=" . $class . ">$wrap_l_name</td>"; echo "<td class=" . $class . ">$wrap_f_name</td>"; echo "<td class=" . $class . ">$wrap_ssn</td>"; echo "</tr>"; } echo '</table>'; mysql_close($link); }

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  • Connecting Android app to MySQL database

    - by opuhliyvladyslav
    Can somebody help me with question related with MySQL database using? Yesterday i was making app for getting some text data and sending them to database located on remote server! I was making POST request to database and sent few text fields to one table in database. So MY QUESTION IS: "Can I use MySQL directly (not though POST method )? and how to use it ?" (will be so glad to see url to solutions or examples) P.S. when i was sending data to server i have some errors in database fields when sending russian characters (what type of encoding sending from my app to server????)

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  • Problem connecting to remote mysql database

    - by user361024
    I am trying to connect to a mysql db on a shared server. I am using a java application to make the connection. Problem doesn't happen when I connect to localhost db. URL = "jdbc:mysql://SHARED HOST IP:3306/DBNAME"; USER = "dbUSER"; PASS = "dbPASS"; Connection conn = DriverManager.getConnection(URL, USER, PASS); java.sql.SQLException: Access denied for user 'DBUSER'@'mycomputersIP???' (using password: YES) It is strange that it says denied for dbuser@ mycomputersip instead of dbuser@sharedhostIP Is there a setting on my wireless router that is screwing things up?

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  • Error when creating database in MySQL using Netbeans 6.8

    - by nix
    I am trying to create a database using MySQL statements in NetBeans 6.8. However, I keep getting Error code 1064. I don't know what the problem is really since the same statements work in NetBeans 6.0. Here is the error: Error code 1064, SQL state 42000: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '; /*!40000 ALTER TABLE students ENABLE KEYS */; -- -- Definition of table `w' at line 1016 Line 46, column 1

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  • accessing external mysql server through "ssh tunnel" - any drawbacks?

    - by Max
    In an upcoming project I have a two server setup: one is the application server and another, already existing runs the mysql server with databases I need to access. I contacted the server admin of the mysql server and the only way I can access the remote mysql databases is via "SSH tunnel". I have never done this before and never heard of it so far, so my question, are there any drawbacks, e. g. performance wise? Isnt it rather slow compared to directly accessing the mysql server on its default port?

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  • MySQL GROUP BY with three tables

    - by Psaniko
    I have the following tables: posts (post_id, content, etc) comments (comment_id, post_id, content, etc) posts_categories (post_category_id, post_id, category_id) and this query: SELECT `p`.*, COUNT(comments.comment_id) AS cmts, posts_categories.*,comments.* FROM `posts` AS `p` LEFT JOIN `posts_categories` ON `p`.post_id = `posts_categories`.post_id LEFT JOIN `comments` ON `p`.post_id = `comments`.post_id GROUP BY `p`.`post_id` There are three comments on post_id=1 and four in total. In posts_categories there are two rows, both assigned to post_id=1. I have four rows in posts. But if I query the statement above I get a result of 6 for COUNT(comments.comment_id) at post_id=1. How is this possible? I guess the mistake is somewhere in the GROUP BY clause but I can't figure out where. Any suggestions?

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  • MySQL SELECT where if stores have X, show me everything that they have

    - by tnt0932
    I have a MYSQL table like this: STORES (SPID, StoreID, ProductID); And data like this: { 1 | s1 | p2 } { 2 | s1 | p7 } { 3 | s1 | p8 } { 4 | s2 | p1 } { 5 | s2 | p3 } { 6 | s2 | p6 } { 7 | s2 | p9 } { 8 | s3 | p2 } { 9 | s3 | p5 } And I would like to: Use a MYSQL SELECT query to get results, where if a store has a certain product, then a list of all of the products at that store will be returned. For example, if I were looking for "p2", then I would like to know that "s1" has "p2, p7, p8" and "s3" has "p2, p5". Please let me know if you require any more information. I'm not sure what is required to solve this issue (Which is probably why I can't search and find the answer!) Thank you.

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  • Ensuring uniqueness on a varchar greater than 255 in MYSQL/InnoDB

    - by Vijay Boyapati
    I have a table which contains HTML entries for news pages. When I initially designed it I used URL as the primary key. I've learned the error of my ways because left-joining is super slow. So I want to redesign the table with an integer (id) primary key, but still keep the rows unique based on the URL. The problem is that I've found URLs longer than 255 characters, and MySQL isn't letting my create a key on the URL. I'm using an InnoDB/UTF8 table. From what I understand it's using multiple bytes per character with a limit of 766 bytes for the key (in InnoDB). I would really love suggestions on an elegant way of keeping the rows unique based on URL, while using an integer primary key. Thanks!

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  • jQuery Load MySQL Fetch Array

    - by Robert Hanson
    I'm a beginner in jQuery area and I have simple question like this : I want to load (AJAX) MySQL result in array, let's say : $row[0] = first name $row[1] = last name $row[2] = phone number I have no problem with PHP part, but I have difficulties to display each of that array content on different id. because syntax I found loads everything processed by PHP : <script type="text/javascript"> $(document).ready(function(){ $('#mysql-result').load('ajax.php'); }); </script> how to get 'First Name', 'Last Name' and 'Phone Number' from PHP with only one time load and still I can put the result in different . thank you.

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  • Search for string within text column in MySQL

    - by user94154
    I have mysql table that has a column that stores xml as a string. I need to find all tuples where the xml column contains a given string of 6 characters. Nothing else matters--all I need to know is if this 6 character string is there or not. So it probably doesn't matter that the text is formatted as xml. Question: how can I search within mysql? ie SELECT * FROM items WHERE items.xml [contains the text '123456'] Is there a way I can use the LIKE operator to do this? Thanks

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  • MSYQL ~ Why does this query only select a single row?

    - by Joe
    SELECT * FROM tbl_houses WHERE (SELECT HousesList FROM tbl_lists WHERE tbl_lists.ID = '123') LIKE CONCAT('% ', tbl_houses.ID, '#') ^ It only selects the row from tbl_houses of the last occuring "tbl_houses.ID" inside tbl_lists.HousesList I need it to select ALL the rows where any ID from tbl_houses exists within tbl_lists.HousesList

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  • MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

    - by Paul Norman
    Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

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  • password limitations in SQL Server and MySql

    - by asteroid
    Does MySql 5.1 and SQL Server 2008 (Web edition, Standard) have any functional password limitations other than length limits? Are metacharacters in any form a bad idea to use, like bang, pipe, hash, any slash, carrot, and so on? I know that MySql 5.1 has a password length limitation of 16 characters that is hardcoded, but I was wondering, are any metacharacters (i.e. non alphanumerics) a bad idea to use? And is this true in SQL Server 2008 Web edition, Standard? So specifically: can symbols like: /`~:}{[]^ be used successfully? I would hope it doesn't matter to the database, but I don't understand enough about password storage in enterprise database systems yet to know for sure, and I was looking for confirmation or an explanation.

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  • How Export Result of MySQL Query on PHPMyAdmin 3.4.3?

    - by grape
    1) I've got a 30K row table. 2) When I run a long, 50-line query on that table, a GROUP function reduces the number of rows to 7K. 3) I want to export the grouped 7K rows as a new table, or save them as a CSV. When I attempt to export, instead of getting the grouped 7K rows, I get the old, pre-query 30K rows. What am I doing wrong, and what should I be doing? NOTE: I'm not a coder, so I'd really appreciate a solution that just used the PHPMyAdmin GUI. Thanks!

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