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  • How to write a regular expression for "everything between X and Y" for use with preg_replace

    - by pg
    I want to take a variable called $encoded_str and and remove cd1, CD1 and anything between the first 'l' and the last blank space. So for example "lp6 id4 STRINGcd1" would return "STRING". I'm using PHP 4 for now so I can't use str_ireplace, I have this: $encoded_str=str_replace('CD1','',$encoded_str); $encoded_str=str_replace('cd1','',$encoded_str); $encoded_str=preg_replace('X','',$encoded_str); I've RTFM for preg_replace but am a bit confused. What should I replace the X with and can you suggest a decent introductory primer for writing regular expressions?

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  • Split a string by comma, quote and full-stop.. with a few exceptions

    - by dunc
    I've got a lot of text, similar to the following paragraph, which I'd like to split into words without punctuation (', ", ,, ., newline etc).. with a few exceptions. Initially considered endemic to the Chalakudy River system in Kerala state, southern India, but now recognised to have a wider distribution in surrounding drainages including the Periyar, Manimala, and Pamba river though the Manimala data may be questionable given it seems to be the type locality of P. denisonii. In the Achankovil River basin it occurs sympatrically, and sometimes syntopically, with P. denisonii. Wild stocks may have dwindled by as much as 50% in the last 15 years or so with collection for the aquarium trade largely held responsible although habitats are also being degraded by pollution from agricultural and domestic sources, plus destructive fishing methods involving explosives or organic toxins. The text refers to P. denisonii which is a species of fish. It's an abbreviation of Genus species. I would like this reference to be one word. So, for instance, this is the kind of array I'd like to see: Array ( ... [44] given [45] it [46] seems [47] to [48] be [49] the [50] type [51] locality [52] of [53] P. denisonii [54] In [55] the ... ) The only things that distinguish these species references such as P. denisonii from a new sentence like end. New are: The P (for Puntius, as in the P. in the aforementioned example) is only ever one letter, always a capital the d (as in . denisonii) is always either a lower case letter or an apostrophe (') What regexp can I use with preg_split to give me such an array? I've tried a simple explode( " ", $array ) but it doesn't do the job at all. Thanks in advance,

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  • Find Javascript Code inside String

    - by Ph.E
    Greetings friends, I am developing a web application that will allow the customer to enter a personalized message, which will then be converted to HTML. Well, the problem is that I can not allow the insertion of Javascript code. So I need a method that filters the text, searching for and remove it. I think the regular expressions to solve my problem, but I'm having difficulty building. Some of his friends could help me, or has already developed something for this. Thank you.

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  • How to match parameter names in an expression?

    - by burak ozdogan
    Hi, I have a set of expressions representing some formula with some parameters inside. Like: [parameter1] * [parameter2] * [multiplier] And many others like this. I want to use a regular expression so that I can get a list of strings (List<string>) which will have the following inside: [paramter1] [paramter2] [multiplier] I am not using regular expressions so often; if you have already used something like this I would appreciate if you can share. Thanks!

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  • PHP : Pattern Replacement Query.

    - by Rachel
    Currently I have ‘customer_id’ . ‘+’ . ‘operator_domain’ pattern, e.g., '123456789'.'+'.'987654321' Desired Pattern: ‘customer_id.operator_domain’ pattern, e.g., '123456789987654321' How can I achieve this using in php ?

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  • Regular Expression - Block Spam

    - by Immanuel
    Could someone lead me on finding a regular expression that blocks a comma separated list of Spam words I already have? The regular expression needs to match a string with the spam word list I already have. Not that it matters, but I am using PHP.

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  • Regular Expression

    - by TiagoDias
    Hi all, I cannot manage to get a working regular expression (for use in ASP.NEt Validataor) for the following criteria: - I want all chars from A-Z a-z 0-9 - I don't want the Enter key I have the expression: [\w\s,.-/]*[^\n] but that don't works. Please give-me a hint, Thanks.

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  • Replace strings differently depending if is enclosed in braces or not.

    - by peroyomas
    I want to replace all instances of an specific words between braces with something else, unless it is written between double braces, while it should show as is it was written with single braces without the filter. I have tried a code but only works for the first match. The rest are shown depending of the first one: $foo = 'a {bar} b {{bar}} c {bar} d'; $baz = 'Chile'; preg_match_all( '/(\{?)\{(tin)\}(\}?)/i', $foo, $matches, PREG_SET_ORDER ); if ( !empty($matches) ) { foreach ( (array) $matches as $match ) { if( empty($match[1]) && empty($match[3])) { $tull = str_replace( $match[0], $baz, $foo ); } else { $tull = str_replace( $match[0], substr($match[0], 1, -1), $foo ) ; } } } echo $tull;

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  • (.*) instead of (.*?)

    - by EBAGHAKI
    Suppose we have this html content, and we are willing to get Content1, Content2,.. with regular expression. <li>Content1</li> <li>Content2</li> <li>Content3</li> <li>Content4</li> If I use the line below preg_match_all('/<li>(.*)<\/li>/', $text, $result); i will get an array with a single row containing: Content1</li> <li>Content2</li> <li>Content3</li> <li>Content4 And by using this code: preg_match_all('/<li>(.*?)<\/li>/', $text, $result); i will get an array with 4 row containing Content1, Content2, ... Why (.*) is not working since it means match any character zero or more times

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  • How do we match any single character including line feed in Perl regular expression?

    - by bobo
    I would like to use UltraEdit regular expression (perl) to replace the following text with some other text in a bunch of html files: <style type="text/css"> #some-id{} .some-class{} //many other css styles follow </style> I tried to use <style type="text/css">.*</style> but of course it wouldn't match anything because the dot matches any character except line feed. I would like to match line feed as well and the line feed maybe either \r\n or \n. How should the regular expression look like? Many thanks to you all.

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  • What does this statement mean ? printf("[%.*s] ", (int) lengths[i],

    - by Vivek Goel
    I was reading this page http://dev.mysql.com/doc/refman/5.0/en/mysql-fetch-row.html there is one line printf("[%.*s] ", (int) lengths[i], row[i] ? row[i] : "NULL"); from code MYSQL_ROW row; unsigned int num_fields; unsigned int i; num_fields = mysql_num_fields(result); while ((row = mysql_fetch_row(result))) { unsigned long *lengths; lengths = mysql_fetch_lengths(result); for(i = 0; i < num_fields; i++) { printf("[%.*s] ", (int) lengths[i], row[i] ? row[i] : "NULL"); } printf("\n"); } what does [%.*s] mean in that code ?

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  • Using RE to retrive an ID

    - by chrissygormley
    Hello, I am trying to use RE to match a changing ID and extract it. I am having some bother getting it working. The String is: m = 'Some Text That exists version 1.0.41.476 Fri Jun 4 16:50:56 EDT 2010' The code I have tried so far is: r = re.compile(r'(s*\s*)(\S+)') m = m.match(r) Can anyone help extract this string. Thanks

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  • Regular expression matching in php

    - by user1836428
    I have this regexp: /(.*)(([0-9]([^a-zA-Z])*){7,}[0-9])(.*)/. Given the following values 0654535263 065453-.-5263 065asd4535263 Expected Results 06**** 06**** 06**** Actual Results 0654535263 06**** 065asd4535263 It does not match the last row because of the letters (I want to match from 0-3 letters) and it matches only last occurence (in the second row in example, it skips first row).

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  • Problem with re.findall (duplicates)

    - by user559385
    Hello, I tried to fetch source of 4chan site, and get links to threads. I have problem with regexp (isn't working). Source: import urllib2, re req = urllib2.Request('http://boards.4chan.org/wg/') resp = urllib2.urlopen(req) html = resp.read() print re.findall("res/[0-9]+", html) #print re.findall("^res/[0-9]+$", html) The problem is that: print re.findall("res/[0-9]+", html) is giving duplicates. I can't use: print re.findall("^res/[0-9]+$", html) I have read python docs but they didn't help.

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  • SED whitespace removal within a string

    - by blazeprogrammer
    I'm trying to use sed to replace whitespace within a string. For example, given the line: var test = 'Some test text here.'; I want to get: var test = 'Sometesttexthere.'; I've tried using (\x27 matches the '): sed 's|\x27\([^x27[:space:]]*\)[[:space:]]|\x27\1|g but that just gives var test = 'Sometest text here.'; Any ideas?

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  • Validate a string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

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  • document.URL Matching in Javascript

    - by streetparade
    I have a url which looks like this https://test.high.com/people/11111111-name-firstname-_custa/deals/new Now i need to match document.URL if im on that Page if so i will alert a message. The important part is /deals/new How can i match that in Javascript?

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