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• How do you use grep to find terms that are n characters long?

  - by Brian

  I'm using grep to filter the Mac OS X dictionary words file (by default located at /usr/share/dict/words). I want to use grep to retrieve all words four characters long. How do I do this? My best guess for how to do this was: grep [:alpha:]{4} words But that returns zero results.

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• javascript split string on space or on quotes to array

  - by Boriz

  var str = 'single words "fixed string of words"'; var astr = str.split(" "); // need fix i want the array to be like: single, words, fixed string of words.

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• How can I test if an input field contains foreign characters?

  - by zeckdude

  I have an input field in a form. Upon pushing submit, I want to validate to make sure the user entered non-latin characters only, so any foreign language characters, like Chinese among many others. Or at the very least test to make sure it does not contain any latin characters. Could I use a regular expression for this? What would be the best approach for this? I am validating in both javaScript and in PHP. What solutions can I use to check for foreign characters in the input field in both programming languages?

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• what is the regular expression for this

  - by bn

  I want to parse this (adv) much (thanks) I want to eliminate the words and the bracket (adv) but not (thanks) the condition is: inside bracket, and word length inside bracket is 1-5 characters I am using preg_match in PHP Thank You

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• Regular expression alphanumerics with space

  - by Surya sasidhar

  I write regular expression for alphanumerics, but it is not taking space. I want space (whitespace between characters). I write like this: ^[a-zA-Z0-9_]*$

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• How to strip away letters from string?

  - by Jaffa

  I want to strip away all letters in a string, which are not numeric. Preferably a solution made with Regular Expressions or something. And in C#. How to do that?

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• Need to add specific characters to regular expression

  - by lordryan

  i'm using the following regular expression to form a basic email validation. var emailRegEx = /^([a-zA-Z0-9])(([a-zA-Z0-9])*([\._\+-])*([a-zA-Z0-9]))*@(([a-zA-Z0-9\-])+(\.))+([a-zA-Z]{2,4})+$/; this works pretty well for what i need but i also need to exclude these specific characters for reasons i won't go into. !,#,$,%,^,&,*,(,),-,+,|,{,},[,],:,>,<,?,/,\,= - (the characters between the "," if that isn't clear) could someone help me with adding the second group to the first? I know the pro's and cons of using javascript to validate email addresses - i have to do it this way. thanks.

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• Finding C#-style unescaped strings using regular expressions

  - by possan

  I'm trying to write a regular expression that finds C#-style unescaped strings, such as string x = @"hello world"; The problem I'm having is how to write a rule that handles double quotes within the string correctly, like in this example string x = @"before quote ""junk"" after quote"; This should be an easy one, right?

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• JavaScript: add or subtract from number in string

  - by yoavf

  I have a string that looks like "(3) New stuff" where 3 can be any number. I would like to add or subtract to this number. I figured out the following way: var thenumber = string.match((/\d+/)); thenumber++; string = string.replace(/\(\d+\)/ ,'('+ thenumber +')'); Is there a more elegant way to do it?

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• How do I .MatchCase and .WholeWord?

  - by Tanner

  Hello, Ive been making a find, find next function for my richtextbox, so I have these check boxes to let the user search by whole word or case sensitive or both, and I got the first two, to work but I can't get it to work with both case a whole word checked, here's my code: if (isWhole == true && isCase == true) { string searchText = Form2.text; this.Focus(); richTextBox1.Focus(); findPos = richTextBox1.Find(searchText,findPos,richTextBox1.Text.Length, RichTextBoxFinds.WhatGoesHere?); richTextBox1.Select(findPos, searchText.Length); findPos += searchText.Length; } But there's no option for wholeword and matchcase so is there any way to do this with .Find()?

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• Next line matching the regex in bash

  - by Lin_freak

  I have a file in the format: Port Number IP address Port Number IP address (Not sure how the output will be displayed here but let me tell you they are on separate lines) and so on.... I use the command grep -C 1 'port number' file.txt i.e. I want all IP addresses corresponding to a particular port. Making it simple, I want the next line matching a regular expression. Like if my regular expression matches line 2,4 and 6 then I want lines 3, 5 and 7 to be printed. How to do that?

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• Extracting numbers from a url using javascript?

  - by stormist

  var exampleURL = '/example/url/345234/test/'; var numbersOnly = [?] The /url/ and /test portions of the path will always be the same. Note that I need the numbers between /url/ and /test. In the example URL above, the placeholder word example might be numbers too from time to time but in that case it shouldn't be matched. Only the numbers between /url/ and /test. Thanks!

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• How to determine that there is date in the string or not with different date format ?

  - by Harikrishna

  I have a need of checking whether there is the date in the string or not. FUTIDX 26FEB2009 NIFTY 0 -- There is date in the string. FUTIDX MINIFTY 30 Jul 2009 -- There is date in the string. FUTSTK ONGC 27 Mar 2008 -- There is date in the string. How can I do that ?

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• Censoring selected words (replacing them with ****) using a single replaceAll?

  - by aioobe

  I'd like to censor some words in a string by replacing each character in the word with a "*". Basically I would want to do String s = "lorem ipsum dolor sit"; s = s.replaceAll("ipsum|sit", $0.length() number of *)); so that the resulting s equals "lorem ***** dolor ***". I know how to do this with repeated replaceAll invokations, but I'm wondering, is this possible to do with a single replaceAll?

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• RegExp that matches any String containing "0-9" and "." and "-" and " "

  - by tzippy

  I need t check every line of a file for the following pattern: - 14 Values seperated by an irregular number of spaces. - Values may be negative (-), decimal seperator is a dot followed by maximum one digit - The line ends with several spaces here is an example line: 10015 20100501 1 4.6 6.4 8.4 10.5 86.6 4.0 13.0 0.9 6.4 0.0 1007.2 Thanks!

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• Can I make a SQL Server 2005 Table Column accept only letters and numbers ?

  - by Space Cracker

  When we have a column that will store a username that will only accept letters and numbers we always do validation on this input field using javascript or even server validation from code .. but i want to know if is there any way that can allow me make this validation on the Table column itself even some one try to enter data from any place it don't accept and throw exception ?

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• Regular expression - starting and ending with a letter, accepting only letters, numbers and _

  - by jreid9001

  I'm trying to write a regular expression which specifies that text should start with a letter, every character should be a letter, number or underscore, there should not be 2 underscores in a row and it should end with a letter or number. At the moment, the only thing I have is ^[a-zA-Z]\w[a-zA-Z1-9_] but this doesn't seem to work properly since it only ever matches 3 characters, and allows repeated underscores. I also don't know how to specify requirements for the last character.

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• In Perl, how to match several prefixes

  - by xorsyst

  I have 2 input files. One is a list of prefix and lengths, like this: 101xxx 102xxx 30xx 31xx (where x is any number) And another is a list of numbers. I want to iterate through the second file, matching each number against any of the prefix/lengths. This is fairly easy. I build a list of regexps: my @regexps = ('101...', '102...', '30..', '31..'); Then: foreach my $regexp (@regexps) { if (/$regexp/) { # do something But, as you can guess, this is slow for a long list. I could convert this to a single regexp: my $super_regexp = '101...|102...|30..|31..'; ...but, what I need is to know which regexp matched the item, and what the ..s matched. I tried this: my $catching_regexp = '(101)(...)|(102)(...)|(30)(..)|(31)(..)'; but then I don't know whether to look in $1, $3, %5 or $7. Any ideas? How can I match against any of these prefix/lengths and know which prefix, and what the remaining digits where?

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• groovy or java: how can replace '\' with '\\' 'C:\www\web-app\StudyReports\test.bat'

  - by john

  hi, this might be trivial (please forgive me for that) but my eventual goal is to have a string like def newline= 'C:\\www\web-app\StudyReports\\test.bat' but my old line only have one '\', i tried different ways of using the following def newline=oldline.replaceAll(/\\/,'//') but did not work at ... could someone help me out.

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• Regular expression to match text that doesn't start with substring?

  - by Steven

  I have text with file names scattered throughout. The filenames appear in the text like this: |test.txt| |usr01.txt| |usr02.txt| |foo.txt| I want to match the filenames that don't start with usr. I came up with (?<=\|).*\.txt(?=\|) to match the filenames, but it doesn't exclude the ones starting with usr. Is this possible with regular expressions?

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• Notepad++ regular expression find and replace $_REQUEST with $_GET but a more secure

  - by David

  What I am doing is replacing, in a large program, all $_REQUEST['var'] and mysql_escape_string($_REQUEST['var']) with either the 1st or 2nd line below the dotted line. Now, I have figured out this much of the regular expression but I would like to make it simpler. Instead of having to run the top one first then the 2nd one I would like to just run one all together. I tried this but it did not work. (mysql_escape_string\()*$_REQUEST\[\'([^']*)\'\]\)(\)*) So below is what works but again have to do it twice. $_REQUEST\[\'([^']*)\'\] mysql_escape_string\($_REQUEST\[\'([^']*)\'\]\) (isset($_GET['\1'])?mysql_real_escape_string($_GET['\1']):false) (isset($_POST['\1'])?mysql_real_escape_string($_POST['\1']):false) ============================ Update: Yeah, after some research I figured out that Notepad++ does not support most regular expressions. I guess one additional step can not hurt a person. It's just laziness. *NOTE: BUT if anyone wants to try feel free to comment. At least it is just 2 steps and not 20.

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• Regular Expression

  - by equilibrium

  Ohh! this regular expression thing is eating my brain up. I have been reading it from Introduction to Automata Theory, Languages and Computer by Hopcroft, Motwani and Ullman. I have solved a few exercises too but could not solve the following even after trying for almost one hr. The problem is to write a regular expression that defines a language consisting of all strings of 0s and 1s except the substring 011. Is the answer (0+1)* - 011 correct ? If not what should be the correct answer for this?

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• Sed: regular expression match lines without <!--

  - by sixtyfootersdude

  I have a sed command to comment out xml commands sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml Takes: <a> <!-- Comment --> <b> bla </b> </a> Produces: <!-- Security: <a> --> <!-- Security: <!-- Comment --> --> // NOTE: there are two end comments. <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> Ideally I would like to not use my sed script to comment things that are already commented. Ie: <!-- Security: <a> --> <!-- Comment --> <!-- Security: <b> --> <!-- Security: bla --> <!-- Security: </b> --> <!-- Security: </a> --> I could do something like this: sed 's/^\([ \t]*\)\(.*[0-9a-zA-Z<].*\)$/\1<!-- Security: \2 -->/' web.xml sed 's/^[ \t]*<!-- Security: \(<!--.*-->\) -->/\1/' web.xml but I think a one liner is cleaner (?) This is pretty similar: http://stackoverflow.com/questions/436850/matching-a-line-that-doesnt-contain-specific-text-with-regular-expressions

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• Regular Expression repetition of class

  - by codersarepeople

  I am trying to figure out a regular expression for the following: <tr class="A">.*</tr><tr class="(B|C)">.*</tr> Now The second tr class will repeat an unknown number of times, with something unknown in between repetitions, but simply putting it in parentheses and added a plus doesn't work. Here's the PHP code that didn't work: $pattern = '/<tr\ class=\"A\">.*(<tr\ class=\"(B|C)\">.*<\/tr>.*)+/'; preg_match_all($pattern,$playerHtml,$scores); But it only returns the first Here's an example of something that should match: <tr class="A">blah</tr>blah <tr class="B">blah</tr>blah <tr class="B">blah</tr>blah <tr class="C">blah</tr> This only matches blahblahblah

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• I need a way to implement the function matches() from XPath 2.0 with functions from XPath 1.0

  - by Jenny Smith

  I have the following piece of code: root="//valueExpression[matches(self::*,'pattern')]/.." But I can only use XPath 1.0 and I get an exception for the function matches(). Can you please help me with a solution using only functions from XPath 1.0 ?

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